NEED HELP ASAP PLS AND THX PIC IS ATTACHED

Answer:b

Explanation:i just did it

Answer: Solubility increases so more solute dissolves

Explanation:

The solubility is a measure of the concentration of the dissolved gas particles in the liquid and is a function of the gas pressure. As you increase the pressure of a gas, the collision frequency increases and thus the solubility goes up, as you decrease the pressure, the solubility goes down.

40.5%

Explanation:

Ca×1 = 40

C×4 = 48

H×6 = 6

O×4 = 64

64÷158×100% = 40.5%

The mole fraction of HCl in the given solution is 0.051.

To calculate the mole fraction of HCl in the given solution, we need to first find the mass of HCl and water present in the solution.

Let's assume we have 100 g of the solution, so 9.8 g of it is HCl, and 90.2 g is water.

Next, we need to find the moles of HCl present in the solution.

To do this, we divide the mass of HCl by its molar mass.

The molar mass of HCl is 36.46 g/mol (1.01 g/mol for hydrogen + 35.45 g/mol for chlorine).

moles of HCl = 9.8 g / 36.46 g/mol = 0.269 mol

The moles of water can be calculated using its molar mass which is 18.015 g/mol.

moles of water = 90.2 g / 18.015 g/mol = 5.005 mol

The total number of moles in the solution is the sum of the moles of HCl and water.

total moles = 0.269 mol + 5.005 mol = 5.274 mol

The mole fraction of HCl can now be calculated by dividing the moles of HCl by the total number of moles.

mole fraction of HCl = 0.269 mol / 5.274 mol = 0.051

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answer: 3057.44 m^3

Explanation:

This is Charles Law which is V1/T1=V2/T2  and temp must be in kelvin

So v2=V1 x T2/T1

v2= 3100 X 359.15 / 364.15  = 3057.44 m^3

t1= 91 +273.15 = 364.15

t2=86+273.15 =359.15

The decrease in temperature is 147.075 K. The SI unit for temperature is the kelvin (K), but it can also be measured in degrees Celsius (°C) or Fahrenheit (°F).

What is Temperature?

Temperature is a physical property that measures the degree of hotness or coldness of an object or system, as compared to a standard reference point. It is a measure of the average kinetic energy of the particles (atoms or molecules) in a substance or system.

To solve this problem, we need to use the Charles's law equation which states:

V1/T1 = V2/T2

where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.

We can rearrange the equation to solve for T2:

T2 = (V2/T2) x T1

First, we need to convert the initial temperature from Celsius to Kelvin by adding 273.15:

T1 = 21.0°C + 273.15 = 294.15 K

The initial volume (V1) is 6.0 L, and the final volume (V2) is 3.0 L. Substituting these values into the equation, we get:

(6.0 L/294.15 K) = (3.0 L/T2)

Solving for T2, we get:

T2 = (3.0 L x 294.15 K) / 6.0 L

T2 = 147.075 K

Finally, we can find the decrease in temperature by subtracting the final temperature (T2) from the initial temperature (T1):

ΔT = T1 - T2

ΔT = 294.15 K - 147.075 K

ΔT = 147.075 K

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To solve for Δ2, we need to reverse the reaction and change the sign of Δ1:

2Al2O3(s)⟶4Al(s)+3O2(g)Δ2 = -Δ1

Therefore, Δ2 = -Δ1.

To solve for Δ3, we need to add the reactions for the formation of two moles of Al2O3 from aluminum and oxygen:

4Al(s)+3O2(g)⟶2Al2O3(s)Δ1

2Al2O3(s)⟶4Al(s)+3O2(g)Δ3

Adding these equations gives:

12Al(s)+9O2(g)⟶6Al2O3(s)Δ3

Therefore, Δ3 = 2Δ1.

To solve for Δ4, we need to divide the reaction for the formation of two moles of Al2O3 by two:

2Al(s)+3O2(g)⟶Al2O3(s)Δ1/2

Multiplying this equation by 16 gives:

32Al(s)+48O2(g)⟶16Al2O3(s)8Δ1/2

We can then cancel out the formation of 14 moles of Al2O3:

2Al(s)+32O2(g)⟶Al2O3(s)Δ4 = 8Δ1/2 - 7Δ1

Therefore, Δ4 = 8Δ1/2 - 7Δ1.

The types of chemical reaction for the reactions given are.

Synthesis: H₂O + SO3 → H₂SO4

Decomposition: PbSO4 → PbSO3 + O2

Single- Replacement: Mg + Fe2O3 → Fe + MgO

Double- Replacement: NaBr + H3PO4 → Na3PO4 + HBr

Combustion: C2H4 + O2 → CO2 + H2O

Therefore, A chemical reaction is a process that leads to the transformation of one set of chemical substances to another set. In other words, it is the process by which atoms are rearranged to create new chemical compounds.

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The value of the property at the end of the given time period is determined as $410,000.

The value of the property is the sum of the purchase price of the lot and the cost of building the home, which is:

$30,500 (purchase price of the lot) + $375,000 (cost of building the home) = $405,500

However, the bank has appraised the home at $410,000, which means that the value of the property has increased by $4,500.

Therefore, the value of the property is:

$405,500 (original value) + $4,500 (increase in value) = $410,000.

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Answer:

Absolute zero is the theoretical temperature at which all matter would have zero thermal energy and all molecular motion would stop. This temperature is equal to -273.15 degrees Celsius or -459.67 degrees Fahrenheit. It is the lowest possible temperature in the universe and cannot be reached in practice, as it is impossible to completely eliminate all thermal energy from matter.

Answer:

C. pesticides

Explanation:

hope it helps :)

Answer:

The final volume of gas in the balloon is 40.0 L (nearest tenth).

Explanation:

To solve this problem we can use the Combined Gas Law.

[tex]\boxed{\sf \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}}[/tex]

where:

Convert the temperatures given in Celsius to kelvin by adding 273.15:

[tex]\implies \sf 28^{\circ}C=28+273.15=301.15\;K[/tex]

[tex]\implies \sf -8^{\circ}C=-8+273.15=265.15\;K[/tex]

Therefore, the values to substitute into the formula are:

Substitute the values into the formula and solve for V₂:

[tex]\implies \sf \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}[/tex]

[tex]\implies \sf \dfrac{745 \cdot 30.2}{301.15}=\dfrac{495 \cdot V_2}{265.15}[/tex]

[tex]\implies \sf V_2=\dfrac{745 \cdot 30.2 \cdot 265.15}{301.15 \cdot 495}[/tex]

[tex]\implies \sf V_2=40.01905...[/tex]

[tex]\implies \sf V_2=40.0\;L\;(nearest\;tenth)[/tex]

Therefore, the final volume of gas in the balloon is 40.0 L (nearest tenth).

Answer:

The density of a substance is given by dividing the mass by the volume.

The S.I units of density are kg/m³, but can be measured by other units such as g/cm³

The mass of the iron is 29 kg or 29000 g

Therefore; Density = 29000 g/ 3680 cm³

                              = 7.880 g/cm³

Hence, the density of the iron plate is 7.880 g/cm³

Explanation:

Answer:

D

Explanation:

because replusive force is much more

Answer:

many milliliters of 1.50 M HCl(aq) are required to react with 5.05 g Zn(s)?

volume: 16 mL

First, we need to calculate the number of moles of Zn:

m(Zn) = 5.05 g

M(Zn) = 65.38 g/mol (molar mass of Zn)

n(Zn) = m(Zn) / M(Zn) = 5.05 g / 65.38 g/mol = 0.0773 mol

According to the balanced chemical equation, 1 mole of Zn reacts with 2 moles of HCl. Therefore, the number of moles of HCl needed is:

n(HCl) = 2 × n(Zn) = 2 × 0.0773 mol = 0.1546 mol

Now we can use the molarity of the HCl solution to calculate the volume needed:

M(HCl) = 1.50 mol/L

n(HCl) = V(HCl) × M(HCl)

V(HCl) = n(HCl) / M(HCl) = 0.1546 mol / 1.50 mol/L = 0.103 L = 103 mL

Therefore, we need 103 mL of 1.50 M HCl(aq) to react with 5.05 g Zn(s).

Answer:

24.31 g/mol.

Explanation:

moles =mass/molar mass

n=w/m

Answer: 3.96 moles of CO2 are required in the photosynthesis reaction.

Explanation: The balanced equation for photosynthesis tells us that for every mole of glucose produced, 6 moles of CO2 are required. Therefore, to determine how many moles of CO2 are required for 0.66 moles of glucose, we can set up a proportion:

6 moles CO2 / 1 mole glucose = x moles CO2 / 0.66 moles glucose

Solving for x, we get:

x = (6 moles CO2 / 1 mole glucose) x (0.66 moles glucose / 1) = 3.96 moles CO2

Therefore, to produce 0.66 moles of glucose, 3.96 moles of CO2 are required in the photosynthesis reaction.

Answer:

To solve this problem, we can use the Boyle's Law equation, which states that the pressure and volume of a gas are inversely proportional at constant temperature.

Boyle's Law: P1V1 = P2V2

where P1 and V1 are the initial pressure and volume, and P2 and V2 are the new pressure and volume.

Using the given values:

P1 = 30.0 atm

V1 = 2 L

P2 = 10.0 atm

Substituting these values into the Boyle's Law equation, we get:

30.0 atm x 2 L = 10.0 atm x V2

Simplifying and solving for V2, we get:

V2 = (30.0 atm x 2 L) / 10.0 atm

V2 = 6 L

Therefore, the new volume of the gas will be 6 L if the pressure is reduced to 10.0 atm, assuming the temperature remains constant.

I Hope This Helps!

Answer:

4 millllllermeeters jb

Answer: The amount of heat absorbed for the reaction of 25 mL of 1.0 M H₂SO4 and 50 mL of 1.0 M NaOH, resulting in a temperature increase from 25°C to 33.9°C, is 10.14 kJ.

Explanation:

Hydrogen bonding, which is unquestionably what we have, will occur from the intermolecular force between the molecules of H2O and CH3OH. Atoms trade or exchange valence electrons to create bonds.

Trust and self-esteem are developed in children and adolescents through strong emotional ties. After that, they can leave the family and establish wholesome friendships and other types of social ties. Healthy relationships consequently lower a child's chances of emotional discomfort or antisocial behaviour.

The government of a country issues government bonds, a sort of fixed-interest bond. These bonds are thought of as low-risk investments. Examples of different kinds of government bonds include T - bills, Municipality Bond, Zero-Coupon Bonds, and others.

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Explanation:

I don't have a personal opinion, but I can say that there is no single research method that is effective in all situations.

Different research methods are appropriate for different types of research questions and situations. For example, if the research question is focused on understanding the relationship between two variables, a correlational research method may be appropriate. However, if the research question is focused on understanding the cause-and-effect relationship between variables, an experimental research method may be necessary.

In addition, some research methods may be more appropriate for certain types of data or populations, such as qualitative research methods for exploring subjective experiences or quantitative research methods for analyzing numerical data.

Therefore, researchers need to carefully consider their research question and choose the research method that is most appropriate for their specific situation.

The most standard and widely used research methods

Survey research

This method involves collecting data from a sample of individuals through questionnaires, interviews, or online surveys.

Experimental research

This method involves manipulating one variable (the independent variable) to observe its effect on another variable (the dependent variable) while controlling for other variables.

Observational research

This method involves observing and recording behavior in natural settings without any intervention or manipulation of variables.

Case study research

This method involves in-depth examination and analysis of a single case or a small group of cases to understand a particular phenomenon or situation.

Content analysis

This method involves analyzing and interpreting the content of documents, media, or other communication sources to identify patterns, themes, and trends.

These methods are commonly used across various fields of research, including social sciences, psychology, education, business, and healthcare. However, the choice of research method depends on the research question, the type of data needed, and the availability of resources.

These substances C6H1203 don't already exist in their empirical formula.

The empirical formula is CH for both C2H2 and C2H6, as it represents the simplest whole number ratio of the various atoms in a molecule. The compound's molar mass is 314 g/mol, and the empirical formula mass is (2 X 12) + 1 + 80 = 105g. Hence, C6H3Br3 is the molecular formula.

Glucose has the chemical formula C6H12O6 = 6 x CH2O c.The molecular weight of glucose is 180 g/mol.. The empirical and molecular formulas are identical because it equals 6 x 30 g/mol.

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The number or amount of moles of magnesium sulfide in 100g of MgS is 1.774 moles.

The number of moles in a substance can be calculated by dividing the mass of the substance by its molar mass as follows:

Mole is the base unit of amount of substance i.e. the amount of substance of a system which contains exactly 6.02214076 × 10²³ elementary entities.

no of moles = mass ÷ molar mass

According to this question, 100g of magnesium sulfide is given. The molar mass of magnesium sulfide is 56.38 g/mol.

moles = 100g ÷ 56.38g/mol

moles = 1.774 moles

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Answer:

Explanation:

Part A

Density equals mass divided by volume. The units for density are g/cm³ or g/mL. Note that 1 cm³ = 1 mL.

d = m/v

Substitute the mass and the volume into the equation and then divide the bottom number into the top number.

d = 7.9 g/4.3 cm³ = 1.8 g/cm³

Part B

The density of a substance can be used as a conversion factor to find either the mass of the substance or the volume of the substance.

5 cm³ x 8.9 g/cm³ = 45 g

Note that cm³ units cancel and you are left with grams.

Part C

We will use the density of the substance to find the volume of the substance.

150 g x 1 mL/1.25 g = 120 mL

Note that you can invert density so the units of g cancel and you are left with mL.

The infusion will be finished in 114.286 hours.

We need to infuse 100 mg of Drug Z. Since the IV solution contains 0.0175% of Drug Z, we can calculate the amount of IV solution needed for the infusion.

To do this, we need to use the following formula:

Amount of IV solution = [tex]\frac{(Amount of Drug Z * 100) }{ Concentration of Drug Z}[/tex]

Amount of IV solution = [tex]\frac{(100 mg * 100) }{0.0175 \% }[/tex]

Amount of IV solution = 5,714.286 ml

To calculate how long it will take to complete the infusion, we need to use the following formula:

Time to complete infusion =[tex]\frac{Amount of IV solution }{ Rate of infusion }[/tex]

Time to complete infusion =[tex]\frac{ 5,714.286 ml }{ 50 ml/hr }[/tex]

Time to complete infusion = 114.286 hr

Therefore, it will take 114.286 hours to complete the infusion.

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The heat capacity of an object is defined as the amount of heat required to raise its temperature by 1 degree Celsius (or 1 Kelvin). It is denoted by the symbol "C" and has units of J/°C (Joules per degree Celsius) or J/K (Joules per Kelvin).

We can use the formula for heat capacity to calculate its value for the object:

where:

Substituting the given values, we get:

Note that the units of temperature must match (either Celsius or Kelvin) in order for the calculation to be correct. Since the given change in temperature is in Celsius, we can use Celsius for the units of heat capacity as well.

Dividing, we get:

Therefore, the heat capacity of the object is 95.8 J/°C. This means that it requires 95.8 Joules of heat to raise the temperature of the object by 1 degree Celsius (or Kelvin).

[tex]\rule{200pt}{5pt}[/tex]

Answer: 2.31 mole H2O

Explanation: blance the equation first

4 NH3 +   5O2   --> 4 NO + 6 H20

1.54 moles NH3 x ( 6 mole H20/ 4 moles NH3) X (18 g H20/1mole H20)

2.31 mole H20