A browser stores images and page elements in a on your device is cache. Therefore, option A is the correct answer.
Browser cache stores files needed by your browser to display the web sites it visits. This includes elements like the HTML file that describe the site, along with CSS style sheets, Javascripts, cookies, and images.
A browser cache is used to store web page elements such as images, scripts, and HTML files, so that when a user visits the same website again, the browser does not have to re-download all the elements. This helps to speed up page loading time and reduce bandwidth usage.
Therefore, option A is the correct answer.
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Using An assembly code
Read a 3 digit number from one row, then a 1 digit number from the second row. Subtract the 1 digit number from the 3 digit number, and display the result. Make sure you print your name first, then your output.
Sample Input
123
1
Output
Name Last name
122
Sample Input
100
1
Output
Name Last name
099 (or you can display 99 without the 0, either one is fine)
Sample Input
001
1
Output
Name Last name
0 (or you can display 000, either one is fine by me)
An example implementation of the algorithm you described in x86 assembly language using NASM syntax:
The Assembly Language Programsection .data
; Define your data here if needed
section .text
global _start
_start:
; Print your name here
; Read the 3-digit number
mov eax, 3 ; number of characters to read
mov ebx, 0 ; file descriptor (stdin)
mov ecx, buf ; buffer to store the input
mov edx, eax ; maximum number of characters to read
int 0x80 ; invoke the read system call
; Convert the input to a number
mov eax, buf
sub eax, '0' ; convert the hundreds digit
mov ebx, 10
imul ebx
mov ecx, buf+1
sub ecx, '0' ; convert the tens digit
add eax, ecx
imul ebx
mov ecx, buf+2
sub ecx, '0' ; convert the units digit
add eax, ecx
; Read the 1-digit number
mov eax, 1 ; number of characters to read
mov ebx, 0 ; file descriptor (stdin)
mov ecx, buf ; buffer to store the input
mov edx, eax ; maximum number of characters to read
int 0x80 ; invoke the read system call
; Convert the input to a number
mov ebx, 10
mov ecx, buf
sub ecx, '0' ; convert the digit
mul ebx
; Subtract the 1-digit number from the 3-digit number
sub eax, ecx
; Convert the result to a string
mov ebx, 10
div ebx
add edx, '0' ; convert the units digit
mov [result+2], dl
div ebx
add edx, '0' ; convert the tens digit
mov [result+1], dl
add eax, '0' ; convert the hundreds digit
mov [result], al
; Print the result
mov eax, 4 ; system call for write
mov ebx, 1 ; file descriptor (stdout)
mov ecx, result ; address of the string to print
mov edx, 3 ; number of characters to print
int 0x80 ; invoke the write system call
; Exit the program
mov eax, 1 ; system call for exit
xor ebx, ebx ; exit status
int 0x80
section .bss
buf resb 4 ; buffer for input (3 digits + newline)
result resb 4 ; buffer for output (3 digits + null terminator)
Note that this implementation uses system calls for input/output and assumes that the input is terminated by a newline character. You may need to modify it to suit your specific requirements or platform.
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H. W 2: A class includes 20 female students and 30 male students, including 15 female students and 20 male students with black hair. If a person is randomly chosen from the class, what is the probability that the chosen person is a female student with black hair? Hint: (Female student with black hair ) = P(AU B)
Answer:
The probability that the chosen person is a female student with black hair is 15/50, or 3/10.