Mathematics Middle School

PLEASE HELP THIS IS URGENT

What is the surface area of the figure below?

A. 12ft
B. 36ft
C. 54ft
D. 90ft

PLEASE HELP THIS IS URGENT What Is The Surface Area Of The Figure Below?A. 12ftB. 36ftC. 54ft D. 90ft

Answers

Answer 1
A 12 bc both front and back are six so 6+6 = 12
Answer 2
the answer is a. i think

Related Questions

PLEASE HURRY IM RUNNING LATE WITH THIS!,

Answers

C. Purple and green

Hope this help!!

Can someone please help me

Answers

Rate of change= (y2-y1)/(x2-x1), in this case the rate of change is 2
2

the formula for rate of change is
(Y2 - Y1)/(X2-X1).

Plug in any 2 random coordinates.

(6-4)/(5-4)

2/1

2

100 POINTS HELP PLEASE IM DESPERATE !!!!!!!!!!!!!!!!!!!!

If AB¯¯¯¯¯¯¯¯
is translated right 5
units and down 2
units, what are the coordinates of A′,
the image of point A?

Line Segment A B with coordinates A negative 5, 2 & B negative 2, 6.

Answers

So basically you gotta go uo down left right up up down agian that ur answer
The coordinates for A’ would be (0,0)

Please help me I want this done today.

Answers

B is correct. B is rights because at the end of the equation you need to divide by 1 so it all equals out.

Answer:

Choose Choice B

Step-by-step explanation:

45-19 is 26.

All of the other equations don't make sense except B

A hollow ball is made of rubber that is 2 centimeters thick. The ball has a radius to the outside surface of 6 centimeters.

What is the approximate volume of rubber used to make the ball?

Use 3.14 for pi.

Responses

33.5 cm³
33.5 cm³

267.9 cm³
267.9 cm³

636.4 cm³
636.4 cm³

904.3 cm³

Answers

Answer:

636.4 cm³

Step-by-step explanation:

636.4 to the third power

Find the volume of the triangular prism; do not round.

Answers

Answer:

[tex]\boxed{\mathtt{Volume=33.55m^{3}}}[/tex]

Step-by-step explanation:

[tex]\textsf{For this problem, we are asked to find the Volume of a Triangular Prism.}[/tex]

[tex]\large\underline{\textsf{What is Volume?}}[/tex]

[tex]\textsf{Volume is the amount of space a figure occupies. Volume is measured in Cubic units.}[/tex]

[tex]\large\underline{\textsf{We are Given;}}[/tex]

[tex]\textsf{The Height is 6.1m. Keep in mind that the Height is the Perpendicular Distance}[/tex]

[tex]\textsf{between 2 bases.}[/tex]

[tex]\textsf{The base is; (4.4 x 2.5).}[/tex]

[tex]\textsf{The Height of the Triangle is 2.5m.}[/tex]

[tex]\large\underline{\textsf{Necessary Formulas;}}[/tex]

[tex]\mathtt{Volume=(Base) \times Height}[/tex]

[tex]\mathtt{Area = \frac{1}{2} (Base \times Height)}[/tex]

[tex]\large\underline{\textsf{For this Problem;}}[/tex]

[tex]\mathtt{Volume=(Triangles' \ Area) \times Height}[/tex]

[tex]\large\underline{\textsf{The area of a Triangle is;}}[/tex]

[tex]\mathtt{Area = \frac{1}{2} (Base \times Height)}[/tex]

[tex]\textsf{Find the area of the base first.}[/tex]

[tex]\large\underline{\textsf{Substitute;}}[/tex]

[tex]\mathtt{Area = \frac{1}{2} (4.4 \times 2.5)}[/tex]

[tex]\boxed{\mathtt{Area = 5.5m^{2}.}}[/tex]

[tex]\textsf{We know the Base, now let's find the volume of the figure.}[/tex]

[tex]\large\underline{\textsf{Substitute;}}[/tex]

[tex]\mathtt{Volume=5.5 \times 6.1}[/tex]

[tex]\boxed{\mathtt{Volume=33.55m^{3}}}[/tex]

[tex]\huge\text{Hey there!}[/tex]


[tex]\huge\textsf{Find the \boxed{\bf volume} of a triangular prism is:}[/tex]

[tex]\mathsf{\dfrac{1}{2}(\boxed{\bf b}ase\times\boxed{\bf h}eight\times\boxed{\bf l}ength) = \boxed{\bf v}olume}[/tex]


[tex]\huge\textsf{Your \boxed{\bf equation} should look like:}[/tex]

[tex]\mathsf{volume = \dfrac{1}{2}(4.4\ m \times 2.5\ m\times 6.1\ m)}[/tex]


[tex]\huge\textsf{\boxed{\bf Step-by-step} explanation can be:}[/tex]

[tex]\mathsf{volume = \dfrac{1}{2}(4.4\ m \times 2.5\ m\times 6.1\ m)}[/tex]

[tex]\mathsf{volume = \dfrac{1}{2}\times 4.4\ m \times 2.5\ m\times 6.1\ m}[/tex]

[tex]\mathsf{volume = 0.5\times 4.4\ m \times 2.5\ m\times 6.1\ m}[/tex]

[tex]\mathsf{volume = 2.2\ m\times 15.25\ m}[/tex]

[tex]\mathsf{volume = 33.55}[/tex]


[tex]\huge\textsf{Therefore your \boxed{\bf answer} should be:}[/tex]

[tex]\huge\boxed{\mathsf{volume = 33.55m^2}}\huge\checkmark[/tex]


[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]



~[tex]\frak{Amphitrite1040:)}[/tex]
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