pls help
2.0 mol of Ca(OH)2 are mixed with 2.0 mol of HCl according to the following equation:
Ca(OH)2+2HCl=CaCl2+2H2O
a. Which chemical is in excess and which is limiting reactant?
b. What is the excess in grams?
c.Theoretically,how many moles of H20 will be produced?

When a protonated epoxide is attacked by water, the nucleophile attacks from the "top" or "front" of the epoxide ring in an "S_N2" substitution nucleophilic bimolecular process.

A protonated epoxide is a molecule that contains an epoxide ring (a three-membered ring consisting of two carbon atoms and one oxygen atom) that has been protonated, or had a hydrogen ion (H+) added to it.

The protonation of an epoxide ring can occur in the presence of an acidic medium, such as a strong acid like sulfuric acid (H2SO4) or hydrochloric acid (HCl).

In acidic conditions, the lone pair of electrons on the oxygen atom of the epoxide ring can interact with the positively charged hydrogen ion, resulting in the formation of a protonated epoxide.

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The volume of the gas will be 560 mL when the pressure is reduced to 125.0 kPa, assuming the temperature remains constant.

Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.

Boyle's law is expressed as;

P₁V₁ = P₂V₂

Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.

Substituting the given values, we get:

P₁ = 350.0 kPa (initial pressure)

V₁ = 200 mL (initial volume)

P₂ = 125.0 kPa (final pressure)

V₂ = ?

Solving for V₂, we get:

V₂ = ( P₁ × V₁ ) / P₂

V₂ = (350.0 kPa × 200 mL) / 125.0 kPa

V₂ = 560 mL

Therefore, the final volume of the gas is  560 mL.

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Answer:

They are in high demand.

FOSSIL FUELS, USES, NEGATIVE IMPACTS AND SOLUTIONS;

In order to understand why it is bad to use Fossil Fuels, it is first necessary to understand what they are composed of. There are two main types of Fossil Fuels, namely, Coal and Oil.

The Formation of Coal : -

The multistage process that produces coal.

Many millennia ago, tree trunks fell and were quickly covered in water and mud. The bacteria, respiring anaerobically, due to the lack of Oxygen, produced peat. As is illustrated in stage 3, sediments built up over this peat layer and with time, heat and pressure, certain chemical changes turned the peat into Coal, as shown in stage 4. During the compression process, Sulphur compounds leached into the peat layer and eventually became a components of the final Coal.   In other cases,  Low sulfur coals derive their sulfur mainly from the sulfur components in the coal-forming plants. High-sulfur Coals, however, are now known to derive most of their sulfur from reduction of Sulphate ions to H2S in sea or brackish water in the coal beds by microbial processes.>

The Formation of Oil : -

The multistage process that produces oil.

Oil is essentially the remains of small fossilised sea creatures, that has been compressed and undergone pressures, eventually converted to oil. Oil is commonly accompanied by Natural Gas, which also builds up as a result of the extreme pressures. Sulphur is also found to make a percent of the oil.

The Usage and Combustion of Fossil Fuels : -

Coal and Oil are combusted to convert the chemical energy held to thermal energy, which in turn warms up water so that steam evolves. This team is drafted down a tunnel to turn a turbine, which drives a generator. This is how a power station works.

Upon observing the figure above, if you follow the path of the process, we see that coal enters at number 14 and enters the combuster at number 15. Here, it burns to heat the water at number 19, which is channeled down to drive the generator at number 5, via a series of tubes which converge into one, at number 10.

Coal or Oil or both can be used for this purpose. However the combustion of Coal and Oil releases Sulphur gas, which is dangerous for the Environment, as well as Carbon Dioxide and Carbon Monoxide, as the combustion happens in internal conditions, hence combustion may not occur fully, or in depleted Oxygen.

Negative Impacts of Sulphur Gas, Carbon Monoxide and Carbon Dioxide on the Atmosphere and the Environment : -

Prevention and Reduction of These Effects : -

There are numerous methods by which these gases and their effects can be subdued. One notable example for the case of Sulphur Gas, is the “Flue Desulphurisation Method”, which effectively removes the Sulphur and separates it out, hence making it available for use in other Industrial Processes, but in safer compounds, etc.

Replanting of cut down trees can contribute towards of the re-achievement of the equilibrium that has been present in the Atmosphere before Industrial activities led to disequilibrium. Re-planting is a very simple process, but one that can go a long way. In effect, it is a two in one solution, as if we remove Carbon Monoxide emissions by reacting the gas with excess Oxygen, we get Carbon Dioxide. However, the equilibrium in the Biosphere means that is no longer a problem. Thus, replanting of trees is very important.

Answer:

A.

Explanation:

Lithium's electron configuration is 1s^2 and 2s^1 , therefore the orbital diagram would have 2 in 1s box and 1 in 2s box.

Lithium's electron configuration is 1s^2 and 2s^1 , therefore the orbital diagram would have 2 in 1s box and 1 in 2s box. Thus, option A is correct.

An atom in the neutral state has the same number of protons and electrons. Since protons carry the positive charge and electrons carry negative charge of equal magnitude as that of protons, so, in neutral state the overall charge on the atom is zero.

Atomic number of Lithium is 3. Under neutral state it has 3 protons and 3 electrons. So, its overall electric charge is 0.

If an atom of Lithium loses one of its outermost electron, it is left with 2 electrons and 3 protons. Since, number of protons is 1 more than the number of electrons, the electrical charge on Lithium atom would be positive and the magnitude of charge will be equal to the number of electrons lost, which is 1 in this case.

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Answer:

The density of a substance is given by dividing the mass by the volume.

The S.I units of density are kg/m³, but can be measured by other units such as g/cm³

The mass of the iron is 29 kg or 29000 g

Therefore; Density = 29000 g/ 3680 cm³

                              = 7.880 g/cm³

Hence, the density of the iron plate is 7.880 g/cm³

Explanation:

Hydrogen bonding, which is unquestionably what we have, will occur from the intermolecular force between the molecules of H2O and CH3OH. Atoms trade or exchange valence electrons to create bonds.

Trust and self-esteem are developed in children and adolescents through strong emotional ties. After that, they can leave the family and establish wholesome friendships and other types of social ties. Healthy relationships consequently lower a child's chances of emotional discomfort or antisocial behaviour.

The government of a country issues government bonds, a sort of fixed-interest bond. These bonds are thought of as low-risk investments. Examples of different kinds of government bonds include T - bills, Municipality Bond, Zero-Coupon Bonds, and others.

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Answer:

C. pesticides

Explanation:

hope it helps :)

(1) The larger ion is Cr³+

(2) The larger ion is Ca.

In the first pair, we are comparing the cations Cr²⁺ and Cr³⁺. Cations are positively charged ions that form when an atom loses one or more electrons. The charge on a cation tells you how many electrons it has lost. In this case, Cr²⁺ has lost 2 electrons, while Cr³⁺ has lost 3 electrons.

When comparing the sizes of ions, we need to consider the ionic radius. The ionic radius is the distance between the nucleus of an ion and its outermost electron shell.

As we move from left to right across the periodic table, the number of protons in the nucleus increases, which pulls the electrons closer to the nucleus and makes the atoms smaller. As we move down a column in the periodic table, the number of electron shells increases, which makes the atoms larger.

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Answer:2.115 L

Explanation:

4.5 x .47 = 2.115 L

4.5 pints are approximately equal to 2.129292 liters. The answer closes to the result is 2.215 liters.

This question is concerned with conversion between pints and liters. 1 pint is equal to approximately 0.473176 liters. Therefore, to find out how many liters that 4.5 pints is equal to, we multiply 4.5 by 0.473176.

The calculation is as follows: 4.5 pints * 0.473176 liters/pint = 2.129292 liters

Considering the options that was given, the closest answer is 2.215 liters.

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Answer: Solubility increases so more solute dissolves

Explanation:

The solubility is a measure of the concentration of the dissolved gas particles in the liquid and is a function of the gas pressure. As you increase the pressure of a gas, the collision frequency increases and thus the solubility goes up, as you decrease the pressure, the solubility goes down.

Answer:

The nuclide formed by the β decay of 26Al is 26Mg.


Mark my answer as brainliest! this was a difficult one

Answer:

The density of an object is constant.

Density is a derived unit of measure.

The density of an object determines whether it will sink or float.

Answer: 2.31 mole H2O

Explanation: blance the equation first

4 NH3 +   5O2   --> 4 NO + 6 H20

1.54 moles NH3 x ( 6 mole H20/ 4 moles NH3) X (18 g H20/1mole H20)

2.31 mole H20

Answer:

D

Explanation:

because replusive force is much more

These substances C6H1203 don't already exist in their empirical formula.

The empirical formula is CH for both C2H2 and C2H6, as it represents the simplest whole number ratio of the various atoms in a molecule. The compound's molar mass is 314 g/mol, and the empirical formula mass is (2 X 12) + 1 + 80 = 105g. Hence, C6H3Br3 is the molecular formula.

Glucose has the chemical formula C6H12O6 = 6 x CH2O c.The molecular weight of glucose is 180 g/mol.. The empirical and molecular formulas are identical because it equals 6 x 30 g/mol.

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Answer:

To solve this problem, we can use the Boyle's Law equation, which states that the pressure and volume of a gas are inversely proportional at constant temperature.

Boyle's Law: P1V1 = P2V2

where P1 and V1 are the initial pressure and volume, and P2 and V2 are the new pressure and volume.

Using the given values:

P1 = 30.0 atm

V1 = 2 L

P2 = 10.0 atm

Substituting these values into the Boyle's Law equation, we get:

30.0 atm x 2 L = 10.0 atm x V2

Simplifying and solving for V2, we get:

V2 = (30.0 atm x 2 L) / 10.0 atm

V2 = 6 L

Therefore, the new volume of the gas will be 6 L if the pressure is reduced to 10.0 atm, assuming the temperature remains constant.

I Hope This Helps!

The volume of the nitrogen oxide gas is 35.2 L

Stoichiometry is the quantitative study of reactants and products in a chemical reaction. It is used to determine the amount of reactants needed to produce a certain amount of product, or to determine the amount of product that will be produced from a given amount of reactant.

To apply stoichiometry;

We know that;

Number of moles of Cu = 150/ 63.5g/mol = 2.36 moles

If 3 moles of Cu produced 2 moles of NO

2.36 moles of Cu will produce 2.36 * 2/3

= 1.57 moles

If 1 moles of NO occupies 22.4 L

1.57 moles of NO will occupy 1.57 * 22.4/1

= 35.2 L

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Answer: C - The amount of gas

Explanation:

Regardless of the reactant B concentration, the reactant rate remains constant. As a result, the response rate is unaffected by increasing B's concentration by a factor of four.

The amount of a substance's solute in a specific amount of solution is how concentrated it is. Molarity, or the amount of molecules of solute in one liter of solution, is a common unit of measurement for concentrations.

Focusing for an extended amount of time on one thing without interruption is meditation. Concentrating the mind on a specific object is the basic exercise of concentration that all meditations begin with. After some practice, concentration can eventually turn into meditation when the mind is calm and not easily diverted by other thoughts.

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Explanation:

First, we need to write a balanced chemical equation for the neutralization reaction:

2 HNO3(aq) + Ba(OH)2(aq) → 2 H2O(l) + Ba(NO3)2(aq)

From the balanced equation, we can see that the stoichiometric ratio of HNO3 to Ba(OH)2 is 2:1. This means that 2 moles of HNO3 react with 1 mole of Ba(OH)2.

Using the given information, we can calculate the number of moles of Ba(OH)2 that reacted:

moles of Ba(OH)2 = Molarity x Volume (in L)

moles of Ba(OH)2 = 0.250 M x (37.9/1000) L

moles of Ba(OH)2 = 0.009475 mol

Since the stoichiometric ratio of HNO3 to Ba(OH)2 is 2:1, the number of moles of HNO3 that reacted is twice the number of moles of Ba(OH)2:

moles of HNO3 = 2 x moles of Ba(OH)2

moles of HNO3 = 2 x 0.009475 mol

moles of HNO3 = 0.01895 mol

Finally, we can calculate the concentration of the HNO3 solution:

concentration of HNO3 = moles of HNO3 / volume of HNO3 solution (in L)

concentration of HNO3 = 0.01895 mol / 0.120 L

concentration of HNO3 = 0.158 mol/L

Therefore, the concentration of the HNO3 solution is 0.158 mol/L.

The number or amount of moles of magnesium sulfide in 100g of MgS is 1.774 moles.

The number of moles in a substance can be calculated by dividing the mass of the substance by its molar mass as follows:

Mole is the base unit of amount of substance i.e. the amount of substance of a system which contains exactly 6.02214076 × 10²³ elementary entities.

no of moles = mass ÷ molar mass

According to this question, 100g of magnesium sulfide is given. The molar mass of magnesium sulfide is 56.38 g/mol.

moles = 100g ÷ 56.38g/mol

moles = 1.774 moles

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Answer:

24.31 g/mol.

Explanation:

moles =mass/molar mass

n=w/m

The value of the property at the end of the given time period is determined as $410,000.

The value of the property is the sum of the purchase price of the lot and the cost of building the home, which is:

$30,500 (purchase price of the lot) + $375,000 (cost of building the home) = $405,500

However, the bank has appraised the home at $410,000, which means that the value of the property has increased by $4,500.

Therefore, the value of the property is:

$405,500 (original value) + $4,500 (increase in value) = $410,000.

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Answer:

2300J

Explanation:

The first law of thermodynamics states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system:

ΔU = Q - W

Where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done by the system.

In this case, ΔU is what we want to find, Q is 700 J, and W is -400 J (note that the work done by the system is negative because it is done on the surroundings). Substituting these values into the equation:

ΔU = Q - W

ΔU = 700 J - (-400 J)

ΔU = 700 J + 400 J

ΔU = 1100 J

The final internal energy of the system is therefore 1100 J + the initial energy of 1200 J, which equals 2300 J.

Answer:

To find the value of y, we need to use the concept of molar ratios and the mole concept.

First, we need to calculate the number of moles of aluminum and oxygen in the given sample of ore. We can do this by dividing the mass of each element by its respective atomic mass:

Number of moles of aluminum = 5.4 kg / 27 g/mol = 200 moles

Number of moles of oxygen = 4.8 kg / 16 g/mol = 300 moles

Next, we can determine the ratio of the number of moles of aluminum to oxygen in the sample. This ratio is:

Aluminum : Oxygen = 200 : 300

Simplifying this ratio by dividing both sides by 100, we get:

Aluminum : Oxygen = 2 : 3

According to the chemical formula of aluminum oxide (Al2O3), it contains 2 atoms of aluminum for every 3 atoms of oxygen. Therefore, the sample of ore must contain a whole number of units of this chemical formula. Let the number of units of Al2O3 be y.

Then, we can set up the following equation to solve for y:

2 moles of aluminum * y = 200 moles of aluminum

3 moles of oxygen * y = 300 moles of oxygen

Simplifying each equation, we get:

y = 100

y = 100

Since both equations give the same value for y, we can conclude that the sample of ore contains 100 units of Al2O3. Therefore, the value of y is 100.

Answer:

Absolute zero is the theoretical temperature at which all matter would have zero thermal energy and all molecular motion would stop. This temperature is equal to -273.15 degrees Celsius or -459.67 degrees Fahrenheit. It is the lowest possible temperature in the universe and cannot be reached in practice, as it is impossible to completely eliminate all thermal energy from matter.