Seismic waves do not travel along the Earth’s surface. The statement is false.
what are seismic waves?
The seismic waves can be defined as the waves full of energy that travel through the Earth's layer, these waves are the result of earthquake.
They can further be divided into two types body wave and surface waves. The body waves travel in the interior of the Earth and the surface waves travel at the surface of the Earth.
The seismic waves can have an amplitude of few centimeters in large earthquake. They travel slower as compared to the body waves.
Hence Seismic waves do not travel along the Earth’s surface. The statement is false.
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Answer:
False
Explanation:
Ed 2022
Explain why electromagnetic forces are essential to forming compounds.
Explanation:
formation of compounds because the electric forces compel the atoms to attract each other and formed bonds which leads to the formation of chemical compounds. The attractive or repulsive interaction between any two charged bodies is known as an electric force so the attraction between two opposite charged atoms causes the formation of compounds so we can conclude that electric forces are important for the formation of compounds.
My Noacid performs a physics lab to determine the speed of sound inside a tube. She blocks off one end of the 120. 0 cm tube with a book and places a microphone at the other end. When she snaps her finger she determines the time for the sound to get back to the microphone is. 00695 s. What was the speed of sound that day
The speed of sound inside a tube when she snapped her finger is determined as 345.32 m/s.
Speed of the sound
The speed of the sound wave can be determined by applying echo formula as shown below;
v = 2d/t
where;
d is the distance traveled by the sound wave = 120 cm = 1.2 mt is the time when the sound wave was heard = 0.00695 sSubstitute the given parameters and solve for speed.
v = (2 x 1.2)/(0.00695
v = 345.32 m/s
Thus, the speed of sound inside a tube when she snapped her finger is determined as 345.32 m/s.
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The rotational inertia of a sphere of mass m and radius r about a diameter is 25mr2. The rotational inertia about an axis tangent to the sphere is
The rotational inertia about an axis tangent to the sphere of the given mass and radius is ⁷/₅MR².
Parallel axis theoremAccording to parallel axis theorem, the moment of inertia of a body about any axis is equal to the sum of the product of its mass and the square of the distance between the two parallel axis and the moment of inertia of the body about a parallel axis passing through its centre of mass.
The moment of inertia of the sphere about its parallel axis passing through its centre of mass = ²/₅MR²
The product of its mass and the square of the distance between the two parallel axis = MR²
Rotational inertia about an axis tangent to the sphereMoment of inertia about an axis tangent to the sphere = MR² + ²/₅MR²
= ⁷/₅MR²
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The rotational inertia of a sphere of given mass and radius along a tangent axis is [tex]\rm \frac{7}{5} MR^2[/tex].
What is a moment of inertia?The sum of the products of the mass of each particle in the body with the square of its distance from the axis of rotation expresses a body's tendency to resist angular acceleration.
The given data in the problem is;
M is the sphere's mass.
R is the radius of a sphere
According to the parallel axis theorem,The rotational inertia of a sphere of given mass and radius along a tangent axis is found as;
[tex]\rm I=MR^2+\frac{2}{5} MR^2 \\\\ I=\frac{7}{5} MR^2[/tex]
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why is the freezing compartment kept at top in a refrigerator?
Answer:
Because Geography says the higher one goes the colder it gets
Answer:
The nature of convection.
Explanation:
Warm air rises; cold air falls, so the freezer at the top provides cold air for the other compartments at the bottom.
A 120 N accelerates an object 1. 2 m/s? What is the mass of the object?
Answer:
m = 100 kg
Explanation:
F = ma
120 = m × 1.2
m = 120 ÷ 1.2
m = 100 kg
A hot tungsten filament emit electromagnetic radiation within
A hot tungsten filament emit electromagnetic radiation within the bulb because the tungsten is present within the bulb.
What temperature does a tungsten filament glow at?Due to its high melting point, tungsten can be heated to 3000°C where it glows white hot providing very good brightness due to the presence of argon.
So we can conclude that a hot tungsten filament emit electromagnetic radiation within the bulb.
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Electromagnetic radiation is made up of electromagnetic field waves. A hot tungsten filament emits electromagnetic radiation in the presence of Argon.
What is electromagnetic radiation?Electromagnetic radiation is made up of electromagnetic field waves that travel through space carrying electromagnetic radiant energy. Radio waves, microwaves, infrared, light, ultraviolet, X-rays, and gamma rays are all examples of electromagnetic waves.
When tungsten is heated to a temperature of around 3000 °C, the tungsten starts to emit lights. Tungsten when used in a bulb as a filament then because of its high melting point when electricity is passed through it, it starts to shine white-hot and provides extremely good brightness due to the presence of argon.
Hence, A hot tungsten filament emits electromagnetic radiation in the presence of Argon.
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What is the frequency of a photon with an energy of 4. 56 x 10^-19 j
Answer:
ν = E/h = 4.56x10-19 J / 6.626x10-34 Jsec-1
ν = 6.88x1014 s-1
Explanation:
The frequency of a photon with an energy of 4.56 x 10⁻¹⁹ J is 6.88×10¹⁴ s⁻¹.
What is a frequency?The number of waves that travel through a particular point in a given length of time is described by frequency. So, if a wave takes half a second to pass, the frequency is 2 per second.
Given that the energy of the photon is 4.56 x 10⁻¹⁹ J. Therefore, the frequency of the photon can be written as,
[tex]\rm \gamma = \dfrac{E}{h} = \dfrac{4.56x10^{-19} J}{6.626 \times 10^{-34}\ Jsec^{-1}}\\\\\\\gamma = 6.88 \times 10^{14}\ s^{-1}[/tex]
Hence, the frequency of a photon with an energy of 4.56 x 10⁻¹⁹ J is 6.88×10¹⁴ s⁻¹.
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Find the kinetic energy k of the block at the moment labeled b. express your answer in terms of k and a.
The position of the object can be used to find the kinetic energy in terms of k and a.
What is kinetic energy?The term kinetic energy refers to the energy of an object that is in motion. The question is incomplete hence the syetem is not shown and the value of the kinetic energy can not be found in terms of k and a.
Hence, when the system is shown, we can look at the position of the system and use it to obtain the value of the kinetic energy in terms of k and a.
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Answer:
K = 3/8k(A)^2
Explanation: Potential Energy --> Conservation of Energy
Because block B is at A/2, U = 1/2k(A/2)^2 which equals U = 1/8k(A)^2.
Now that you have the equation for potential energy, you can find kinetic energy in terms of the spring constant (k) and amplitude (A).
K = 3/8 k A^2
Question 1(Multiple Choice Worth 2 points)
(04.05 LC)
The number of protons plus the number of neutrons in an atom is equal to its
O atomic number
O mass number
O nuclear model
O energy level
Question 2 Multiple Choice Worth 2 points)
Answer: Mass Number
Explanation:
Atomic number is the number of just protons;
Nuclear Model is a theoretical description of what an atom looks like;
Energy levels are the energy states that electrons are in;
However, mass number is by definition the number of protons + number of neutrons. :)
Brody drives 180 km in two hours. How fast is he travelling?
should be in km/hour)
Answer:
90 km/h
Explanation:
we just divide the distance by the time to get the speed.
A flat coil of wire has an inductance of 40. 0 mh and a resistance of 6. 00 ω. It is connected to a 21. 2-v battery at the instant t = 0. Consider the moment when the current is 2. 50 a
For a flat coil of wire has an inductance of 40. 0 mh and a resistance of 6. 00 ω, the rate of energy being delivered is mathematically given as
P= 53 W
What rate is energy being delivered by the battery?Generally, the equation for the Battery power is mathematically given as
P = I (dt)V
Therefore
P= 2.50 A * 21.2V
P= 53 W
In conclusion, rate of energy being delivered
P= 53 W
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A flat coil of wire has an inductance of 40. 0 mh and a resistance of 6. 00 ω. It is connected to a 21. 2-v battery at the instant t = 0.The power developed will be 53 Watt.
What is electric power?Electric power is the product of the voltage and current. Its unit is the watt. It is the rate of the electric work done.
The given data in the problem is;
V is the voltage = 21.2 volt (V)
I is the electric current = 2.50 ampere (A)
The formula for the power is given as;
[tex]\rm P= V I \\\\\ P= 2.50 \times 21.2 \\\\ P=53 \ watt[/tex]
Hence electric power developed will be 53 Watts.
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meters/second?
A car accelerates from 4 meters/second to 16 meters/second in 4 seconds. The car's acceleration is what meters/second squared
Answer:
the acceleration of the car is 3 m/s².
Explanation:
Emma wants to drive forward in her car. What does she need to do other than place her vehicle's gear in Drive and accelerate
She need to release the cluch slowly and apply force on the accelator other than place her vehicle's gear in Drive and accelerate
How we drive a car?We drive a car by applying pressure on the accelator, remove foot from the brakes and releasing cluch slowly. When the vehicle get speed, we have to change the gear.
So we can conclude that She need to release the cluch slowly and apply force on the accelator for driving a car.
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Extension Question
If the scale used to measure the mass of the unknown material maxes out at a
lower value than the actual mass of the material, then...
o the measured specific heat will be greater than the actual specific heat.
o the measured specific heat will be less than the actual specific heat.
The measured specific heat will be less than the actual specific heat if a lower value is gotten than the actual mass.
What is Specific heat capacity?This is defined as the quantity of heat needed to raise a substance's temperature by 1 degree Celsius.
If a substance has a low specific heat capacity , it loses water easily which makes the mass when measured to be smaller than the actual value.
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Hydroelectric dams generate electricity by a. water impoundment, in which dam operators control the rate of water flow to turbines. b. converting the kinetic energy of the water impounded behind a dam into potential energy. c. using generators that are placed on the bottom of a river. d. using the energy of the river to produce steam. e. using run-of-the-river systems, in which turbines are placed into the natural water flow.
Hydroelectric dams generate electricity makings use of run-of-the-river systems, in which turbines are placed into the natural water flow.
What are Hydroelectric dams?Generally, Hydroelectric dams produce electricity by making use of turbines and generators, in a process where mechanical energy is produced when moving water turns the rotors of a turbine.
In conclusion, Hydroelectric dams use run-of-the-river systems, in which turbines are placed into the natural water flow.
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You are part of a police unit that has found a powder in a suspect's home. You think it might be a new drug called XYZ. XYZ is an ionic compound that dissolves in water. However, what you think might be a drug may just be salt. Unfortunately there seems to be iron fillings and sand mixed in with the white powder. Your job is to isolate the white powder before sending it to the police lab to be tested to determine if it is salt or XYZ. Give step by step directions on exactly how you will separate your mixture of white powder, iron fillings, and sand.
The steps in the separation include;
Use of magnetaddition of water and filtrationEvaporationSeparation techniquesSeparation techniques has to do with how to obtain a substance in the presence of other substances. In this case, we have the substance XYZ mixed with iron filling and sand.
The separation process begins by using a magnet to remove all the iron fillings. Secondly, water is added and the substance XYZ dissolve in water since it is ionic. The sand can be separated form the solution by filtration.
Lastly, the solution is evaporated and the pure XYZ is obtained and sent to the police lab for analysis.
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The wavelengths of visible light vary from about 300 nm to 700 nm. what is the range of frequencies of visible light in a vacuum?
a) 90 hz to 210 hz
b) 9*10^10 hz to 2.1*10 hz
c) 4.28*10^5 hz to 1*10^6 hz
d) 4.29*10^14 hz to 1*10^15 hz
The range of frequencies of visible light in a vacuum with wavelength between 300 nm to 700 nm is determined as 4.29 x 10¹⁴ Hz to 1 x 10¹⁵ Hz.
Frequency of the visible light
The frequency of the visible light is determined by using the following formulas relating speed of light and frequency of light.
c = fλ
where;
c is speed of lightf is frequency of lightλ is the wavelengthFrequency of light at 300 nm wavelengthf = c/λ
f = (3 x 10⁸) / (300 x 10⁻⁹)
f = 1 x 10¹⁵ Hz
Frequency of light at 700 nm wavelengthf = c/λ
f = (3 x 10⁸) / (700 x 10⁻⁹)
f = 4.29 x 10¹⁴ Hz
Thus, the range of frequencies of visible light in a vacuum with wavelength between 300 nm to 700 nm is determined as 4.29 x 10¹⁴ Hz to 1 x 10¹⁵ Hz.
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10. A ball is attached to a string of length 4 m to make a pendulum. The pendulum is placed at a location that is away from the Earth’s surface by twice the radius of the Earth. What is the acceleration due to gravity at that height and what is the period of the oscillations?
Please show all of your work.
Let's see
Radius of earth=6371mTwice of it=6371(2)=12742m[tex]\\ \rm\rightarrowtail T=2\pi\sqrt{\dfrac{l}{g}}[/tex]
[tex]\\ \rm\rightarrowtail T=2\pi \sqrt{\dfrac{4}{g}}[/tex]
[tex]\\ \rm\rightarrowtail T=2\pi\dfrac{2}{\sqrt{g}}[/tex]
[tex]\\ \rm\rightarrowtail T=\dfrac{4\pi}{\sqrt{g}}[/tex]
So
[tex]\\ \rm\rightarrowtail g=\dfrac{16\pi ^2}{T^2}[/tex]
Answer:
g' = 1.09 m/s²
T = 12 s
Explanation:
Gravity due to acceleration
Distance from center of Earth = r + 2r = 3rgravity due to acceleration on surface, g = GM/r²Substitute 3r in the denominatorg' = GM/(3r)² = GM/9r²⇒ g' = g/9 = 9.8/9 = 1.09 m/s²
Time period
T = 2π√L/g'T = 2π√4/1.09T ≅ 12 sWhich describes the vector calculation giving the magnetic force on a charged particle moving through a magnetic field?.
Which describes the vector calculation giving the magnetic force on a charged particle moving through a magnetic field? It is the cross product of the velocity vector and the magnetic field vector, which gives a vector perpendicular to those vectors.
An object moving in the xy-plane is subjected to the force f⃗ =(2xyı^ 3yȷ^)n, where x and y are in m
The magnitude of the work done by force experience by the object is (2a²b + 3b²)J.
Work done by the force experienced by the objectThe magnitude of the work done by force experience by the object is calculated as follows;
W = f.d
where;
F is the applied force (2xyi + 3yj), where x and y are in metersd is the displacement of the object = (a, b)The work done by the force is determined from the dot product of the force and the displacement of the object.
F = (2xyi + 3yj).(a + b)
W = (2abi + 3bj).(ai + bj)
W = (2a²b + 3b²)J
Thus, the magnitude of the work done by force experience by the object is (2a²b + 3b²)J.
The complete question is below:
The particle moves from the origin to the point with coordinates (a, b) by moving first along the x-axis to (a, 0), then parallel to the y-axis.
How much work does the force do?
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The total work done for an object moving in the xy-plane is subjected to the force f⃗ =(2xyı^ 3yȷ^)n, where x and y are in m is 3ab N.
What is work done?Work done is the force applied on a body to move it over a distance. Work done for inclined plane can be given as,
[tex]W=F\times d[/tex]
Here (F) is the magnitude of force and (d) is the distance traveled.
An object moving in the xy-plane is subjected to the force
[tex]\vec f =(2xy\hat i +3y\hat j)[/tex]
Here, x and y are in meter.
The particle moves from the origin to the point with coordinates (a, b) by moving first along the x-axis to (a, 0), then parallel to the y-axis.
(a) How much work does the force do?For the first part, the particle moves along x-axis. It moves zero along x-axis. Thus, the force, as y=0.
[tex]W_1=\int\limits^a_0 {2xy\hat i} \, dx =0\\[/tex]
Now, when the object moves along y-axis,
[tex]W_2=\int\limits^a_0 {3y\hat j} \, dx \\W_2=3\int\limits^b_0 {y\hat j} \, dx\\W_2=3y(a-0)\\W_2=3ba\\W_2=3ab[/tex]
Total work done,
[tex]W=0+3ab\\W=3ab\rm\; N[/tex]
Thus, the total work done for an object moving in the xy-plane is subjected to the force f⃗ =(2xyı^ 3yȷ^)n, where x and y are in m is 3ab N.
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Which of the following statements about waves are true? Select all that apply.
O
Sound waves cannot travel through empty space.
Sound waves can travel through liquids.
Light waves are not true waves.
Light waves need matter in order to travel.
Waves can only move matter up and down or from side to side.
Answer:
Sound waves cannot travel through empty space
sound can travel through liqui
Sound waves cannot travel through empty space but can travel through liquids. Waves make the particles of matter up and down but do not along with them. The light waves are not true mechanical waves. Therefore, options (A), (B), (C), and (E) are correct.
What are sound waves?Sound can transmit through liquids, gases, and plasma as longitudinal waves, also known as compression waves. It needs a medium to propagate so it can be propagated through solids as both longitudinal waves and transverse waves.
Longitudinal sound waves contain alternating pressure deviations causing compression and rarefaction, while transverse waves have waves of alternating shear stress perpendicular to the direction of propagation.
Waves can make matter move up and down or from side to side but do not carry along with them. Light waves are not considered true waves because they carry without the involvement of the motion of matter.
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Should the kinetic coefficient of friction and the static coefficient change with a different mass
Explanation:
No. Surface contact area also no. The main issue is the types of materials in contact. Surface roughness somewhat matters. Certain surfaces such as ice are special in that pressure melts the ice.
define one meter lendth
Explanation:
The metre is currently defined as the length of the path travelled by light in a vacuum in 1299 792 458 of a second.
Hope it helps
Have a great day
TC
:DD
Which terrestrial planet exhibits retrograde rotation?.
Answer:
Planets that are farther from the sun than the earth (all but Mercury and Venus) will exhibit retrograde motion.
If the position of the planet is observed relative to the background stars, the planet will appear to move backward relative to the stars when the earth is moving in an Eastward direction faster than the planet, and the planet appears to move backwards relative to the stars
(The planet will be on the side of the earth that is opposite that of the sun)
A wave oscillates 4.0 times a second and has a wavelength of 3.0 m.
What are the (a) frequency, (b) period, and (c) speed of this wave?
a) The frequency of the wave is 4.0 Hz
b) The period T of the wave is 0.25s
c) The speed of the wave is 12m/s
Given the data in the question;
Number of oscillation per seconds = 4.0Wavelength; [tex]\lambda = 3.0m[/tex]Frequency; [tex]f = \ ?[/tex]Period; [tex]T = \ ?[/tex]Speed of the wave; [tex]v = \ ?[/tex]Frequency, Period and speed.Frequency is simply the number of occurrences of a repeating phenomenon per unit time.
Period is the time needed for a complete cycle of vibration to pass a given point.
It is expressed as;
[tex]T = \frac{1}{f}[/tex]
Where f is the frequency
Speed is simply the distance traveled in a given interval of time or time ratio.
It is expressed as;
[tex]v = \lambda * f[/tex]
Where [tex]\lambda[/tex] is wavelength and f is frequency
a) Frequency
We said frequency is the number of occurrences of a repeating phenomenon per unit time.
Since the wave oscillates 4.0 times a second
Hence, the frequency of the wave is 4.0 Hz
b) Period
[tex]Period\ T = \frac{1}{f} \\\\Period\ T = \frac{1}{4.0Hz}\\\\Period\ T = \frac{1}{4.0s^{-1}}\\\\Period\ T = 0.25s[/tex]
Therefore, the period T of the wave is 0.25s
c) Speed
[tex]v = \lambda * f\\\\v = 3.0m * 4.0Hz\\\\v = 3.0m * 4.0s^{-1}\\\\v = 12ms^{-1}\\\\v = 12m/s[/tex]
Therefore the speed of the wave is 12m/s.
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A laser beam is used to levitate a metal disk against the force of earth's gravity.
(a) derive an equation giving the required intensity of light, i, in terms of the mass m of the disk, the gravitational acceleration g, the speed of light c, and the cross-sectional area of the disk a. assume the disk is perfectly reflecting and the beam is directed perpendicular to the disk. (do not substitute numerical values; use variables only.)
i =
(b) if the disk has mass 3.89 g and radius 2.40 cm, find the necessary light intensity.
(c) give two reasons why using light pressure as propulsion near earth's surface is impractical.
The necessary light intensity of the disk if the disk has mass 3.89 g and radius 2.40 cm is 6.483 x 10^12cd.
Calculations and Parameters:a. Given that:
i= intensity of light m= mass of disk g= gravitational acceleration c= speed of light a= cross-sectional area of the diskI = P/A
= Force x Speed/Area
Gravitational force, F= GM1M2/r^2
F= ma, F= mg
I= mg x c/q
That is,
i= mass x gravitational acceleration x speed/area
b.
Mass= 3.89g
Radius, r= 2.40cm
i=?
i= mg x c/a
Speed of light= 3.0 x 10^8 m/s
Area, a= /pi r^2
= 3.142 x (0.024)^2
= 3.142 x 0.000576
= 0.0018m^2.
i= 3.89 x 10 x 3.0 x 10^8/0.0018
i= 6.483 x 10^12cd.
c. Light has no mass, therefore, it lacks momentum and cannot exert pressure for propulsion of materials.
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Part B
At your sink, turn on your faucet slowly, until you have achieved a steady drip, drip, drip of lukewarm water. Make sure you can visually see and count the drips. Align the center of the bar of soap with the dripping water and set it down. Make sure the soap is in a sturdy location and does not move during the experiment. The soap represents a rock, and the dripping faucet represents precipitation.
While the soap is being weathered, calculate the number of drips that hit it in a minute. Do this by using your stopwatch to count the number of drips that occur in 10 seconds, and then multiply that number by 6 (because there are 60 seconds in a minute, 6 × 10 = 60). What is the number of drips hitting your bar of soap per minute?
The experiment was conducted in my toilet wash hand sink with a bar soap 30 centimeter away from the faucet, the number of drips record per minute is 120 drips
Control ExperimentationData
Number of Drips Recorded = 20 drips per 10 secondsIn one minute(60 seconds), the number of drips recorded will beCalculation for the number of drips per minute
= 20*6
= 120 drips
What is Control Experiment
Control experiment are carried out to minimize the effects of variables other than the independent variable
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Given the velocity v= ds dt and the initial position of a body moving along a coordinate line, find the body's position at time t
For the body's position at time t is mathematically given as
s(t)=4.9t^2+5t+16
What is the body's position at time t
Generally, the equation for the velocity is mathematically given as
v=ds/dt
v=9.8t+5 as velocity
s=4.9t^2+5t+c
s(0)=16
16=c
s(t)=4.9t^2+5t+16
In conclusion the body's position at time t
s(t)=4.9t^2+5t+16
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The body position at the given time t is s = 4.9t² + 5t + 16 if the velocity v= ds/dt and the initial position of a body moving along a coordinate line.
What is the distance?A numerical representation of the distance between two items or locations is called distance. A physical length or an approximation based on other considerations in physics or common usage can be referred to as distance.
We have:
[tex]\rm v = \frac{ds}{dt}[/tex]
[tex]\rm v = 9.8t+5[/tex] is the velocity
[tex]\rm s = 4.9t^2+5t+c[/tex] is the speed
At t = 0 s(0) = 16
16 = c
[tex]\rm s = 4.9t^2+5t+16[/tex]
Thus, the body position at the given time t is s = 4.9t² + 5t + 16 if the velocity v= ds/dt and the initial position of a body moving along a coordinate line.
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I have an answer but I'm not it sure about it. I just need someone to help confirm it. Thanks
Answer:
0.40s. He's dead, Jim.
Explanation:
The block accelerates at a rate of [tex]9.81 ms^-^2[/tex]. The moment it's 14 meters from the ground, it has traveled 39 meters, in about [tex]39=\frac12(9.81)t^2 \rightarrow 2.82 s[/tex].
For the man to dodge, the time left is the distance the block takes to go down to 2 meters from ground, or 51 meters from its starting point. Which translates in [tex]51=\frac12(9.81)t^2\rightarrow 3.22s[/tex]
He has thus less than half a second ([tex]0.40s[/tex] to be exact) to dodge.
Gwen runs back and forth along a straight track. During the time interval 0≤t≤45 seconds, gwen’s velocity, in feet per second, is modeled by the function v given by v(t)=250sin(t2120)t 6
Gwen's position is a function of his velocity and time
Gwen's position at 45 seconds is 63.9 feet
How to determine Gwen's position at 45 seconds?The function is given as:
v(t) = 250sin(t^2/120)/(t + 6)
When t = 45, we have:
v(45) = 250sin(45^2/120)/(45 + 6)
Evaluate the sum, the exponent and the quotient
v(45) = 250sin(16.875)/(51)
Evaluate the sine ratio
v(45) = 250 * 0.2903/51
Evaluate the product and quotient
v(45) = 1.42
The position is then calculated as:
S(45) = v(45) * 45
This gives
S(45) = 1.42 * 45
Evaluate the product
S(45) = 63.9
Hence, Gwen's position at 45 seconds is 63.9 feet
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The displacement is the shortest between any two given points. The displacement of Gwen at the time period of 45 seconds is 63.9 feet.
What is displacement?The displacement is the shortest between any two given points. It is the product of velocity and time.
Given that the function of the velocity is [tex]v(t)=\dfrac{250\sin\left(\frac{t^{2}}{120}\right)}{\left(t+6\right)}[/tex]. Therefore, substitute the value of t as 45, to know the velocity of Gwen at 45 seconds,
[tex]v(t)=\dfrac{250\sin\left(\frac{t^{2}}{120}\right)}{\left(t+6\right)}[/tex]
[tex]v(45)=\dfrac{250\sin\left(\frac{45^{2}}{120}\right)}{\left(45+6\right)}\\\\v(45) = 1.42[/tex]
Since displacement is the product of velocity and time, therefore, the displacement is equal to,
[tex]s = v \times t\\\\s = 1.42 \times 45\\\\s = 63.9\rm \ feet[/tex]
Hence, the displacement of Gwen at the time period of 45 seconds is 63.9 feet.
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