solids, liquids, and gases all have kinetic energy due to motion of their atoms or molecules. which form of molecular motion do liquids experience? select all that apply. a. translational b. vibrational c. rotational d. transitional

Answers

Answer 1

Translational, rotational and transitional are the form of molecular motion that liquids experience. Therefore, the correct options are option A, C and D.

The only thing that constitutes molecular motion is the movement of its component parts in a certain plane. Temperature has an impact on how much the constituent particles move. The average kinetic energy of the molecules is also measured by the temperature. Heat is another factor that affects molecular mobility since it gives molecules more kinetic energy. Molecules in a liquid are continually moving. When the container is tilted, particles travel to the left and downward due to the pull of gravity, and the gaps are filled by numerous more molecules. The result is a general outflow of liquid from the vessel. Translational, rotational and transitional are the form of molecular motion that liquids experience.

Therefore, the correct options are option A, C and D.

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Related Questions

is it possible to use the same colored central atom to make a model for all of these molecules? why?

Answers

Yes, it is possible to use the same colored central atom to make a model for all of these molecules. This is because the central atom in all of these molecules is the same, so it does not matter what color it is. The other atoms attached to the central atom will determine the shape of the molecule.

All the molecules have the same central atom because they are all hydrocarbons with the general formula CnH2n+2. The only difference between them is the number of carbon atoms that are present.For example, methane (CH4), ethane (C2H6), propane (C3H8), and butane (C4H10) are all hydrocarbons, and they all have Carbon as their central atom. The number of hydrogen atoms in each molecule varies based on the number of carbon atoms present.For instance, Methane (CH4) has one carbon atom and four hydrogen atoms, Ethane (C2H6) has two carbon atoms and six hydrogen atoms, Propane (C3H8) has three carbon atoms and eight hydrogen atoms, and Butane (C4H10) has four carbon atoms and ten hydrogen atoms. Therefore, you can use the same central atom, Carbon (C), to create a model for all of these molecules.

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if you wanted to go into the lab and emulate the buffer solution that exists in your blood which combination of compounds would you mix together to create your buffer? explain your choice.

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A combination of sodium chloride and bicarbonate in a 1:1 ratio is the best choice for creating an approximate buffer solution that mimics the one found in the human bloodstream. This solution helps to maintain the ideal pH balance in the body and ensures optimal functioning.


The bicarbonate acts as a buffer by quickly neutralizing any acidity or alkalinity in the bloodstream, while the sodium chloride acts to further stabilize the pH levels. The buffer solution helps to maintain the optimal pH level of 7.4 in the bloodstream, and keeps the body functioning optimally.

It is important to note that the exact ratio of compounds in the buffer system will vary depending on the individual. For example, the ratio of NaCl to HCO3- may be slightly different from one person to the next. In addition, other compounds such as proteins, amino acids, and phosphates may also be present in small amounts.

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what's a simple definition of what equilibrium is???​

Answers

Answer:

Equilibrium is basically the balance between two opposing forces.  

write down a reaction scheme for polymerization of styrene initiated by thermolysis of azobisisobutyronitrile, including both combination and disproportionation as possible modes of termination.

Answers

The reaction scheme is as follows:

Styrene (monomer) + Azobisisobutyronitrile (initiator) →  Radical polymers + Nitrile groups

Radical polymers then undergo combination or disproportionation as the possible modes of termination:

Combination:

Radical polymers + Radical polymers → Polystyrene (end product)

Disproportionation:

Radical polymers → Polystyrene + Styrene (monomer)

Polymerization of styrene is a chain-growth process initiated by thermolysis of azobisisobutyronitrile, which is a free radical initiator.

During the reaction, styrene molecules act as the monomers, while azobisisobutyronitrile molecules provide the initiating radicals, which combine to form a growing polymer chain.

These polymer chains can either terminate through combination, where two growing chains react with each other and form a new polymer chain, or through disproportionation,

where a growing polymer chain reacts with a styrene molecule to form a new polymer chain and a styrene molecule.

Thermolysis, which is the decomposition of molecules due to high temperature, is the mechanism of initiation of the polymerization of styrene.

This process breaks down the azobisisobutyronitrile molecules into the two radicals, which act as the initiators for the polymerization.

The two possible modes of termination, combination and disproportionation, then occur, resulting in the formation of polystyrene as the end product.

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describe or determine the effect of temperature of temperature on reaction rate and activation energy for a reaction using the arrhenius equation

Answers

The Arrhenius equation shows that the activation energy is directly proportional to the logarithm of the rate constant and inversely proportional to the temperature.

The Arrhenius equation is

[tex]k = A e^{-\frac{E_a}{RT}}[/tex]

where:

k is the rate constant is the pre-exponential factor

Ea is the activation energy

R is the gas constant

T is the temperature in Kelvin

According to the Arrhenius equation, as temperature increases, the rate constant, and thus the reaction rate increases exponentially. This is because as temperature increases, the average kinetic energy of the molecules in the reaction mixture increases, leading to a greater proportion of molecules with sufficient energy to react.

The activation energy of a reaction, Ea, is the minimum energy required for reactant molecules to react and form products. The Arrhenius equation shows that the activation energy is inversely proportional to the rate constant, and thus the reaction rate. As temperature increases, the proportion of reactant molecules with sufficient energy to overcome the activation energy barrier increases, reducing the activation energy and increasing the reaction rate.

Overall, the Arrhenius equation demonstrates that increasing temperature increases the reaction rate and decreases the activation energy.

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calculate the number of moles of sodium hydroxide present in a 26.80 ml sample of a 0.315 m solution.

Answers

The number of moles of sodium hydroxide present in the sample, is 0.00839 moles.

To calculate the number of moles of sodium hydroxide present in a 26.80 ml sample of a 0.315 m solution, use the following equation:

Moles = concentration (M) x volume (L)

Moles = 0.315 M x 0.02680 L

Moles = 0.00839 moles of sodium hydroxide present in a 26.80 ml sample of a 0.315 m solution.

To explain this in further detail, moles are a unit of measurement for an amount of substance and are typically expressed as mol. A mole is equal to 6.02 x 10^23 atoms or molecules, and is represented by the letter 'n' or 'N'.

The concentration of a solution is a measure of the amount of solute dissolved in a given volume of solvent and is expressed in molarity (M). Volume is expressed in litres (L).


By multiplying the concentration of a solution (0.315 M) by the volume of the sample (0.02680 L).


Sodium hydroxide, also known as lye, is a highly reactive and caustic inorganic compound. It is commonly used in soap and detergent production, as well as in the paper and textile industries.

It is also used in the production of a variety of other chemicals, including pharmaceuticals and food additives.

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what is the ph of a 0.20 m acetic acid solution? hint: the ka of acetic acid, ch3cooh, is 1.8 x 10-5.

Answers

The pH of a 0.20 M acetic acid solution is 2.72.

The pH of a 0.20 M acetic acid solution can be calculated using the Ka of acetic acid, CH3COOH, which is 1.8 x 10-5.

We will use the equation for the dissociation of acetic acid to calculate the pH of the solution.

CH3COOH(aq) + H2O(l) ⇌ H3O+(aq) + CH3COO-(aq)

The equilibrium constant expression for the dissociation of acetic acid is given by

Ka = [H3O+][CH3COO-] / [CH3COOH].

Since we know the value of Ka and the initial concentration of acetic acid, we can solve for

the concentration of H3O+.Ka = [H3O+][CH3COO-] / [CH3COOH]

1.8 x 10-5 = [H3O+]2 / 0.20[H3O+]2 = 3.6 x 10-6[H3O+] = 1.9 x 10-3 M

The pH of the solution can then be calculated as:

pH = -log[H3O+]pH = -log(1.9 x 10-3)

pH = 2.72

Therefore, the pH of a 0.20 M acetic acid solution is 2.72.

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the number of neutrons in the nucleus of a given element is the atomic number. group of answer choices true false

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The statement "the number of neutrons in the nucleus of a given element is the atomic number" is false.

The number of protons in the nucleus of an atom is known as the atomic number of that element. The atomic number is used to determine the arrangement of electrons in a neutral atom's electron cloud. As a result, each element has a unique atomic number, which ranges from 1 to 118.In a neutral atom, the number of protons equals the number of electrons. The number of neutrons, on the other hand, is not directly related to the atomic number. The number of neutrons in the nucleus is determined by subtracting the atomic number from the mass number of an atom.

The charge number of an atomic nucleus is the chemical element's atomic number, also known as nuclear charge number (symbol Z). This is equivalent to the proton number (np), or the number of protons present in the nucleus of each atom of that element, for conventional nuclei. Ordinary chemical elements can be uniquely identified by their atomic number. The atomic number and the number of electrons are both equal in a regular, uncharged atom.

The atomic mass number A of a regular atom is calculated by adding its neutron number N and neutron number Z. The relative isotopic mass of any atom, when expressed in unified atomic mass units (making a quantity known as the "relative isotopic mass"), is within 1% of the whole number A because protons and neutrons have roughly the same mass (and the mass of the electrons is negligible for many purposes) and the mass defect of the nucleon binding is always small in comparison to the nucleon mass.

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1.
2.
Grams of solute
3.
4.
0600
150
140
130
120
110
100
90
80
70
60
50
40
30
20
10
NH37
Solubility Curve
KCIÓ3
FONX
NHẠC
O
0 10 20 30 40 50
KCI
Naci
Ce2(SO4)3
60 70 80 90 100
Temperature (°C)
How many grams of ammonium chloride (NH4Cl) is dissolved at 50°C?
Which compound is least soluble in water at 10°C?
How many grams of KNO3 can be dissolved at 50°C?
Are the following solutions unsaturated, saturated, or supersaturated?
a.
45g of NaNO3 in 100 g of water at 30°C.
b. 60g of KClO3 in 100 g of water at 60°C.
5. How many grams of NaNO3 are required to saturate 100 grams of water at
75°C?
6. At what temperature would 25g of potassium chlorate (KClO3) dissolve?
7. 89 g NaNO3 is prepared at 30°C.

Answers

From the solubility curve:

37 grams of NH₄Cl can be dissolved at 50°C.Sodium chloride (NaCl) is the least soluble compound40 grams of KNO₃ a. unsaturated, b. supersaturated.100 grams 45°C

How to determine saturation and temperature?

According to the solubility curve for KNO₃, approximately 40 grams of KNO₃ can be dissolved at 50°C.

a. Since 45g of NaNO₃ in 100 g of water at 30°C is below the saturation point, the solution is unsaturated.

b. Since 60g of KClO3 in 100 g of water at 60°C is above the saturation point, the solution is supersaturated.

To determine how many grams of NaNO₃ are required to saturate 100 grams of water at 75°C, we need to look at the solubility curve for NaNO₃. At 75°C, approximately 75 grams of NaNO₃ can be dissolved in 100 grams of water. Therefore, to saturate 100 grams of water, we would need to add 75 grams of NaNO₃.

To find the temperature at which 25g of KClO₃ dissolves, we need to look at the solubility curve for KClO₃. At 25g, the curve intersects the solubility line at approximately 45°C, so 25g of KClO₃ would dissolve at 45°C.

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if you mix 538 grams in water and bring it to a final volume of 647 ml, what will be the concentration of the resulting solution in g/l? answers cannot contain more than one decimal place.

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Answer : When mixing 538 grams of a substance into 647 ml of water, the concentration of the resulting solution in g/L is 0.83.


The concentration of the resulting solution in g/L can be calculated by dividing the mass of the substance (538 g) by the total volume of the solution (647 ml). This gives us a result of 0.83 g/L.

To further explain this calculation, we must first understand the concepts of mass and volume. Mass is a measure of the amount of matter an object contains. Volume, on the other hand, is the amount of space occupied by a given object. When mixing 538 grams of a substance into 647 ml of water, we are creating a solution with a certain concentration of the substance.

To calculate the concentration of the resulting solution, we must divide the mass of the substance (538 g) by the total volume of the solution (647 ml). This gives us a result of 0.83 g/L.

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which type of bond is responsible for holding two water molecules together, creating the properties of water? multiple choice covalent hydrogen double covalent ionic polar

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The type of bond responsible for holding two water molecules together, creating the properties of water, is a polar covalent bond.

Explanation: The type of bond that is responsible for holding two water molecules together, creating the properties of water is hydrogen bond.What is a hydrogen bond?A hydrogen bond is a type of chemical bond that exists between two electrically polar molecules. Hydrogen bonds are much weaker than covalent or ionic bonds, but they do serve a significant purpose in both organic and inorganic chemistry. Example of a hydrogen bond, one example of a hydrogen bond is found in between two water molecules. Each water molecule is composed of two hydrogen atoms and one oxygen atom, and each hydrogen atom is bonded covalently to the oxygen. However, the shared electrons are not distributed evenly between the two atoms. Because oxygen is more electronegative than hydrogen, it pulls electrons away from the hydrogen atoms, resulting in a slight charge imbalance within the molecule. The oxygen atom in one water molecule is therefore attracted to the hydrogen atoms in another water molecule. This attraction produces a hydrogen bond between the two molecules, which helps to hold them together.

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An ester is mixed with LiNHCH3 in order to perform a SNAc mechanism. What is the LUMO in this reaction?
A. N p orbital
B. C-N σ bond
C. C-O σ* bond
D. C-O π* bond

Answers

The LUMO for the reaction when an ester is mixed with [tex]LiNHCH_{3}[/tex] is D. C-O π* bond.

What will be the LUMO in an SNAc mechanism?

In the SNAc (nucleophilic acyl substitution) mechanism, the nucleophile (LiNHCH_{3}) attacks the carbonyl carbon of the ester, and the LUMO in this reaction is the lowest unoccupied molecular orbital, which is the C-O π* bond.

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what are the oxidation numbers for zn in the reaction represented by the equation: zn hcl zncl h ?

Answers

The oxidation number of Zn in the reaction represented by the equation: Zn + HCl → ZnCl2 + H is +2.

When a metal reacts with a non-metal, the metal takes on a positive charge, making its oxidation number positive. This is because the non-metal takes electrons from the metal, making the metal's charge positive.
In this reaction, the Zn atom is oxidized by the HCl molecule. Oxidation is defined as the loss of electrons. Zn is being oxidized because it is losing electrons to the HCl molecule. Since HCl is a non-metal, it is gaining electrons from Zn, thus making the oxidation number of Zn positive. The oxidation number of Zn is +2.

To sum up, the oxidation number of Zn in the reaction represented by the equation: Zn + HCl → ZnCl2 + H is +2. This is because when a metal reacts with a non-metal, the metal takes on a positive charge, making its oxidation number positive. In this reaction, the Zn atom is being oxidized by the HCl molecule, which is gaining electrons from Zn, thus making the oxidation number of Zn positive and equal to +2.

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How many moles are in 8.52 x 10^33 molecules of Carbonic Acid (23)?

Answers

Answer: There are approximately 141.7 moles

Explanation:

To convert the number of molecules of a substance to the number of moles, we need to divide the number of molecules by Avogadro's Number, which is approximately 6.022 x 10^23 molecules per mole.

Therefore, to calculate the number of moles in 8.52 x 10^33 molecules of carbonic acid (H2CO3), we can use the following formula:

Number of moles = Number of molecules / Avogadro's Number

Number of moles = 8.52 x 10^33 / 6.022 x 10^23

Number of moles = 141.7 mol

Therefore, there are approximately 141.7 moles of carbonic acid in 8.52 x 10^33 molecules of carbonic acid.

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fluorine gas and water vapor react to form hydrogen fluoride gas and oxygen. what volume of hydrogen fluoride would be produced by this reaction if of fluorine were consumed?

Answers

A volume of 2.28 liters of hydrogen fluoride would be produced by this reaction if 1 gram of fluorine was consumed.

The balanced chemical equation for the reaction:

F₂(g) + H₂O(g) → 2HF(g) + O₂(g)

From this equation, we see that 1 mole of fluorine reacts to form 2 moles of hydrogen fluoride.

The given mass of fluorine is not provided in the question. Let's suppose the mass of fluorine is 1 gram.

To convert 1 gram of fluorine to moles, we will use its molar mass. The molar mass of fluorine is 18.998 g/mol.

Hence,1 g F₂ × (1 mol F2/18.998 g F₂) = 0.0526 mol F₂

Since 1 mole of F2 reacts to form 2 moles of HF, the number of moles of HF produced will be:

0.0526 mol F₂ × (2 mol HF/1 mol F₂) = 0.1052 mol HF

We need to assume some values for pressure and temperature. Let's assume that the pressure is 1 atm and the temperature is 273 K.

We will also need to know the volume of water vapor involved in the reaction.

Let's suppose that the volume of water vapor is 1 L.

Using these assumptions, we can calculate the volume of hydrogen fluoride as follows:

PV = nRT

Where P = 1 atm, V is the volume of HF, n = 0.1052 mol, R = 0.0821 L atm/mol K, and T = 273 K.

Substituting these values, we get:

V = (nRT)/P = (0.1052 mol × 0.0821 L atm/mol K × 273 K)/1 atm = 2.28 L

Therefore, 2.28 liters of hydrogen fluoride would be produced by this reaction if 1 gram of fluorine was consumed.

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sodium hydroxide is used to clear clogged drains. a solution of NaOH has a pH of 9.52 at 258C. what are its [H3O^+] and [OH^-]?

Answers

1. The concentration of the hydronium ion, [H₃O⁺] is 3.02×10⁻¹⁰ M

2. The concentration of the hydroxide ion, [OH⁻] is 3.31×10⁻⁵ M

1. How do i determine the hydronium ion, [H₃O⁺]?

The concentration of the hydronium ion, [H₃O⁺], can be obtained as follow:

pH of solution = 9.52Concentration of hydronium, ion [H₃O⁺] = ?

pH of a solution is given by the following formula:

pH = -Log [H₃O⁺]

Inputting the various parameters, we have

9.52 = -Log [H₃O⁺]

Multiply through by -1

-9.52 = Log [H₃O⁺]

Take the anti-log of -9.52

[H₃O⁺] = Anti-log -9.52

[H₃O⁺] = 3.02×10⁻¹⁰ M

2. How do I determine the value of [OH⁻]?

The value of the the hydroxide ion, [OH⁻], can be obtained as follow:

Concentration of hydronium, ion [H₃O⁺] = 3.02×10⁻¹⁰ MConcentrationhydroxide ion, [OH⁻] =?

[H₃O⁺] × [OH⁻] = 10¯¹⁴

3.02×10⁻¹⁰ × [OH⁻] = 10¯¹⁴

Divide both side by 3.02×10⁻¹⁰

[OH⁻] = 10¯¹⁴ / 3.02×10⁻¹⁰

[OH⁻] = 3.31×10⁻⁵ M

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the electrolyte in automobile lead storage batteries is a 3.75 m sulfuric acid solution that has a density of 1.230 g/ml. calculate the mass percent, molality, and normality of the sulfuric acid.

Answers

In summary, the mass percent of the sulfuric acid solution is 29.89%, the molality is 4.35 mol/kg, and the normality is 7.5 N.

To calculate the mass percent, molality, and normality of the 3.75 M sulfuric acid solution, follow these steps:
First let's calculate the mass of 1 liter of the solution:
We know, Density = mass/volume. So, mass = density × volume = 1.230 g/mL × 1000 mL = 1230 g
Now, calculating the mass of sulfuric acid (H2SO4) in 1 liter of the solution:
Molarity = moles of solute/volume of solution. So moles of solute = molarity × volume = 3.75 mol/L × 1 L = 3.75 mol
The molar mass of H2SO4 = (2 × 1.01) + (32.07) + (4 × 16) = 98.08 g/mol
Mass of H2SO4 = moles × molar mass = 3.75 mol × 98.08 g/mol = 367.8 g
To Calculate the mass percent of H2SO4:
Mass percent = (mass of solute / mass of solution) × 100
= (367.8 g / 1230 g) × 100 = 29.89%
To Calculate the molality of H2SO4:
Molality = moles of solute / mass of solvent (in kg)
Mass of solvent = mass of solution - mass of solute = 1230 g - 367.8 g = 862.2 g = 0.8622 kg
Molality = 3.75 mol / 0.8622 kg = 4.35 mol/kg
To Calculate the normality of H2SO4:
Normality = molarity × number of equivalents per mole
For H2SO4, there are 2 acidic hydrogens (protons) that can be released, so the number of equivalents per mole = 2.
Normality = 3.75 M × 2 = 7.5 N
In summary, the mass percent of the sulfuric acid solution is 29.89%, the molality is 4.35 mol/kg, and the normality is 7.5 N.

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angela has an unknown quantity of gas held at a temperature of 2300 K in a container with a volume of 19 L and a pressure of 6.00 atm. How many moles of gas does angela have? a. what equation will you use? b. show all your work.

Answers

The equation you should use is the ideal gas law: PV=nRT

Where P= pressure in atm (atmospheres)
V= Volume in liters
n= Moles of particles
R= Gas constant=0.08206
T= Temperature in Kelvin (degrees Celsius+273)

We are given everything except the amount of moles of the gas, but we want to find it. We can do this by plugging in everything we know into the equation and solving for n. Which would look like this:

(6)(19)=n(0.08206)(2300)

114=n(188.738)

Now divide both sides by 188.738 to get n by itself

0.7629=n

This means that there are 0.7629 moles of the gas!

If you have any additional questions feel free to ask!
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a chemist mixes of water with of methanol and of 2-methylpyrazine. calculate the percent by mass of each component of this solution. be sure each of your answer entries has the correct number of significant digits.

Answers

The percent by mass of each component of the solution is water: 35.5%, 2-methylpyrazine: 32.73%, and methanol: 31.82%, rounded to 2 significant digits.


The percentage by mass of each component of a solution containing 39. g of water, 36. g of 2-methylpyrazine, and 35. g of methanol can be calculated as follows:

Mass of water = 39. g

Mass of 2-methylpyrazine = 36. g

Mass of methanol = 35. g

Total mass of solution = (39. g + 36. g + 35. g) = 110. g

Percentage by mass of water = (Mass of water/Total mass of solution) × 100= (39. g/110. g) × 100= 35.45% (rounded to 2 significant digits)

Percentage by mass of 2-methylpyrazine = (Mass of 2-methylpyrazine/Total mass of solution) × 100= (36. g/110. g) × 100= 32.73% (rounded to 2 significant digits)

Percentage by mass of methanol = (Mass of methanol/Total mass of solution) × 100= (35. g/110. g) × 100 = 31.82% (rounded to 2 significant digits)

Therefore, the percentage by mass of water is 35.45%, the percentage by mass of 2-methylpyrazine is 32.73%, and the percentage by mass of methanol is 31.82%.

The question you wrote is incomplete, maybe the complete question is:

chemist mixes 39. g of water with 36. g of 2-methylpyrazine and 35. g of methanol. Calculate the percent by mass of each component of this solution. Round each of your answers to 2 significant digits component mass percent.

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the solubility of sodium chloride at room room temperature is 35.8g of nacl per 135.8 g of solution and the density of this solution is 1.20g/ml. calculate the molarity of a saturated solution of nacl

Answers

Answer:

5.41 M

Explanation:

To calculate the molarity of a saturated solution of NaCl, we first need to calculate the amount of NaCl in the solution:

35.8 g of NaCl per 135.8 g of solution means that the mass of NaCl in the solution is:

mass of NaCl = 35.8 g

The density of the solution is 1.20 g/mL, so the volume of the solution can be calculated as:

volume of solution = mass of solution / density of solution

volume of solution = 135.8 g / 1.20 g/mL

volume of solution = 113.17 mL

Now we need to convert the volume of the solution to liters:

volume of solution = 113.17 mL = 0.11317 L

To calculate the molarity of the solution, we need to know the number of moles of NaCl in the solution. We can calculate this using the formula:

moles of solute = mass of solute / molar mass of solute

The molar mass of NaCl is 58.44 g/mol, so:

moles of NaCl = 35.8 g / 58.44 g/mol

moles of NaCl = 0.612 mol

Now we can calculate the molarity of the solution using the formula:

molarity = moles of solute / liters of solution

molarity = 0.612 mol / 0.11317 L

molarity ≈ 5.41 M

What happens to molecules once they are eaten by animals

Answers

When animals consume food containing large polymeric molecules, such as proteins, carbohydrates, and nucleic acids, their digestive system breaks down these molecules into smaller components that can be absorbed and utilized by the body.

Mechanical digestion occurs in the mouth and stomach, where food is broken down into smaller pieces through chewing and mixing with digestive enzymes and acids. Chemical digestion occurs primarily in the small intestine, where enzymes and other compounds break down complex molecules into smaller components.

Proteins, for example, are broken down into their constituent amino acids by proteases, while carbohydrates are broken down into simple sugars like glucose and fructose by amylases. Nucleic acids are broken down into nucleotides by nucleases.

Once these molecules are broken down, they are absorbed into the bloodstream through the walls of the small intestine and transported to the liver, where they are further metabolized and distributed to other parts of the body as needed. The body then uses these molecules to build new proteins, carbohydrates, and nucleic acids or to generate energy through cellular respiration. Any excess molecules are typically stored for later use or eliminated from the body as waste.

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which separation technique would be the best method to separate a 1:1 mixture of aniline and ethylbenzene?

Answers

The best method to separate a 1:1 mixture of aniline and ethylbenzene is through

distillation

.

Distillation is a process that involves heating the mixture to its boiling point, which causes the components to vaporize. As the vapors cool and condense, the liquid components will separate into their pure forms.

Since the boiling points of aniline and

ethylbenzene

differ significantly Aniline boiling point: 184°C; Ethylbenzene boiling point: 135°C.

The process of distillation involves heating the mixture in a distillation apparatus.

As the temperature increases, the vaporized components of the mixture will travel up a condenser and then be collected separately in two separate flasks.

During this process,

aniline

will be the first component to vaporize and travel up the condenser, while ethylbenzene will follow suit.

The two components will condense in their respective flasks and can then be collected and isolated.

In conclusion,

Distillation is the best method to separate a 1:1 mixture of aniline and ethylbenzene due to the fact that it utilizes their differences in boiling points to allow for the collection of the two components in their pure forms.

This is achieved by heating the mixture in a distillation apparatus and condensing the vapors in two separate flasks.

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distillation

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a sample of n2o effuses from a container in 49 s . part a how long would it take the same amount of gaseous i2 to effuse from the same container under identical conditions?

Answers

Under identical conditions, it would take the same amount of gaseous I2 to effuse from the same container as it did for N2O, but it would take longer.

This is because I2 is a larger molecule than N2O, so it has greater difficulty passing through the small spaces in the container. The larger the molecule, the slower the effusion rate.

In general, effusion rates are inversely proportional to the square root of the molecular weight of a gas. This means that the molecular weight of I2 is four times larger than that of N2O, so it would take approximately twice as long for I2 to effuse from the container. In this case, it would take approximately 98 seconds for the same amount of gaseous I2 to effuse from the container under identical conditions.

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A gas sample in a cylinder has a pressure of 0.75 atm at 15.00°C. What will
be the pressure of the gas be if the temperature increases to 50.00°C?
Ans:
atm

Answers

To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas:

[tex]\dfrac{(P_1V_1)}{T_1} = \dfrac{(P_2V_2)}{T_2}[/tex]

where:

[tex]P_1[/tex] and [tex]T_1[/tex] are the initial pressure and temperature,[tex]P_2[/tex] is the final pressure,[tex]T_2[/tex] is the final temperature, and[tex]V_1[/tex] and [tex]V_2[/tex] are the initial and final volumes (which we can assume to be constant in this case).

We can rearrange this equation to solve for [tex]P_2[/tex]:

[tex]P_2 = \dfrac{(P_1 \times T_2 \times V_1)}{(T_1 \times V_2)}[/tex]

Since [tex]V_1[/tex] and [tex]V_2[/tex] are constant in this case, we can simplify this to:

[tex]P_2 = \dfrac{(P_1 \times T_2)}{(T1)}[/tex]

Substituting the given values, we get:

[tex]P_2 = \dfrac{(0.75 \: atm \times 323.15 \: K)}{(288.15 \: K)}[/tex]

where:

we have converted the temperatures to Kelvin by adding 273.15.

Simplifying, we get:

[tex]P_2 = 0.84 \: atm[/tex]

Therefore, the pressure of the gas will be 0.84 atm if the temperature increases to 50.00°C.

[tex]\rule{200pt}{5pt}[/tex]

Answer:

The final pressure is 0.841 atm (to three significant figures).

Explanation:

Since the volume is unchanged, we can use Gay-Lussac's Law to find the pressure of the gas if the temperature increases to 50.00°C.

Gay-Lussac's Law

[tex]\boxed{\sf \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}}[/tex]

where:

P₁ is the initial pressure.T₁ is the initial temperature (measured in kelvin).P₂ is the final pressure.T₂ is the final temperature  (measured in kelvin).

Rearrange the equation to solve for P₂:

[tex]\implies \sf P_2=\dfrac{P_1 \cdot T_2}{T_1}[/tex]

Convert Celsius to kelvin by adding 273.15:

[tex]\implies \sf 15.00^{\circ}C=15.00+273.15=288.15\;K[/tex]

[tex]\implies \sf 50.00^{\circ}C=50.00+273.15=323.15\;K[/tex]

Therefore, the values to substitute into the formula are:

P₁ = 0.75 atmT₁ = 288.15 KT₂  = 323.15 K

Substitute the values into the formula and solve for P₂:

[tex]\implies \sf P_2=\dfrac{0.75 \cdot 323.15}{288.15}[/tex]

[tex]\implies \sf P_2=0.841098...[/tex]

[tex]\implies \sf P_2=0.841\;atm\;(3\;s.f.)[/tex]

Therefore, the final pressure is 0.841 atm (to three significant figures).

in a certain molecule, the central atom has one lone pair and five bonds. what will the electron pair geometry and molecular structure be?

Answers

In the certain molecule, the central atom has the one lone pair and five bonds. The electron pair geometry is the square pyramidal and molecular structure is square pyramidal.

The square pyramidal has  the 5 bonds and the 1 lone pair. The 1 lone pair will be sits on the bottom of the molecule and that will causes the repulsion of the rest of  bonds. This will result in that the bond angles are the all slightly lower than the 90°.

The molecule with the five bonding pairs and the one lone pair is designated as the AX5E and it has the total of the six electron pairs. The electron pair geometry is the square pyramidal and molecular geometry is square pyramidal.

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in the combustion analysis of 17.1 g of sugar (c12h 22o 11), what mass, in grams, of o 2 would be consumed?

Answers

In the combustion analysis of 17.1 g of sugar (C12H22O11), the mass of O2 consumed is equal to 8.55 g.

This is due to the fact that the balanced equation for the combustion of sugar is C12H22O11 + 12 O2 --> 12 CO2 + 11 H2O.

This means that for every one mole of sugar that is combusted, 12 moles of O2 are needed.

To calculate the mass of O2 consumed, the number of moles of sugar must first be calculated using the molar mass of sugar, which is 342.3 g/mol.

Therefore, 17.1 g of sugar is equal to 0.05 moles of sugar. Then, using the balanced equation, it can be seen that 0.05 moles of sugar require 0.6 moles of O2.

Finally, the mass of O2 consumed can be determined by multiplying the number of moles of O2 by the molar mass of O2, which is 32 g/mol.

Therefore, 0.6 moles of O2 is equal to 19.2 g, which is equivalent to 8.55 g of O2 consumed.

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what is the ph of a solution if 10 ml of a 1 m hcl solution is added to 10 ml of a 1 m naoh solution?

Answers

The pH of a solution if 10 ml of a 1 M HCl solution is added to 10 ml of a 1 M NaOH solution can be calculated as follows:

First, let's find the number of moles of HCl and NaOH in the solution. Number of moles of HCl = Concentration of HCl x Volume of HClNumber of moles of HCl = 1 M x (10 ml/1000 ml)Number of moles of HCl = 0.01 molesNumber of moles of NaOH = Concentration of NaOH x Volume of NaOHNumber of moles of NaOH = 1 M x (10 ml/1000 ml)Number of moles of NaOH = 0.01 molesNext, let's find the net number of moles of H+ and OH- ions.Number of moles of H+ ions = Number of moles of NaOH - Number of moles of HCl.Number of moles of H+ ions = 0.01 - 0.01Number of moles of H+ ions = 0 molesNumber of moles of OH- ions = Number of moles of HCl - Number of moles of NaOHNumber of moles of OH- ions = 0.01 - 0.01Number of moles of OH- ions = 0 molesSince the net number of moles of H+ ions and OH- ions is zero, the solution is neutral. The pH of a neutral solution is 7. Therefore, the pH of the solution is 7.

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a 0.50 liter sample of CO2 at STP is compressed to a volume of 0.10 litera and pressure of 1.6 atm. What is the temperature of the sample?

Answers

The temperature of the sample of CO² gas is 87.41 Kelvin.

What is the temperature of the sample?

Combined gas law put together both Boyle's Law, Charles's Law, and Gay-Lussac's Law. It states that "the ratio of the product of volume and pressure and the absolute temperature of a gas is equal to a constant.

It is expressed as;

P₁V₁/T₁ = P₂V₂/T₂

At STP (standard temperature and pressure), the temperature is 273.15 K and the pressure is 1 atm.

Therefore, we can use the combined gas law to solve for the final temperature:

P₁V₁/T₁ = P₂V₂/T₂

Where P₁ = 1 atm, V₁ = 0.50 L, T₁ = 273.15 K, P₂ = 1.6 atm, V₂ = 0.10 L, and we are solving for T₂.

Substituting the values and solving for T2, we get:

T₂ = (P₂V₂T₁) / (P₁V₁)

T₂ = ( 1.6 atm × 0.10 L × 273.15 K) / (1 atm × 0.50 L)

T₂ = 87.41 K

Therefore, the temperature of the sample is 87.41 K.

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in all of the reactions you investigated today, did it make any difference in which order you broke bonds or formed bonds?

Answers

Bond breaking is endothermic process as it require energy and Bond forming is an exothermic process as it releases energy.

A reaction is said to be bond breaking where energy is taken in from the surroundings so the temperature of the surroundings decreases. An endothermic process is defined as any thermodynamic process with an increase in the enthalpy H of the system. In this process, a closed system usually absorbs thermal energy from its surroundings which is heat transfer into the system.

An exothermic process is defined as a thermodynamic process or reaction that releases energy from the system to its surroundings usually in the form of heat but also in a form of light, electricity, or sound. In this process energy is transferred into the surroundings rather than taking energy from the surroundings as in an endothermic reaction.

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The complete question is,

What is the difference in bond breaking and bond forming.

Pressure (kg/cm²)
1.15
1.24
1.47
Volume (mL)
44.8
41.5
35.0
A student doing this experiment obtained the data
shown in the table above. The value of the
constant, k, for this data is
A. 0.04
B. 25.7
C. 50.0
D. 51.5

Answers

The value of the constant, k, for this data is 51.5.

option D.

What is the value of the constant K?

To determine the constant k, we can use the formula:

PV = k

where;

P is the pressure in kg/cm², V is the volume in mL, and k is the constant.

We can rearrange the formula to solve for k:

k = PV

Now, we can multiply the pressure and volume values for each data point to get the corresponding value of k:

For the first data point: k = 1.15 kg/cm² x 44.8 mL = 51.52

For the second data point: k = 1.24 kg/cm² x 41.5 mL = 51.40

For the third data point: k = 1.47 kg/cm² x 35.0 mL = 51.45

We can take the average of these values to get an overall value for k:

k = (51.52 + 51.40 + 51.45) / 3 = 51.46 ≈ 51.5

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