Stephanie dilated the rectangle below and dimensions of the image were 24 ft by 6ft. What was the scale of the factor used?

Stephanie Dilated The Rectangle Below And Dimensions Of The Image Were 24 Ft By 6ft. What Was The Scale

Answers

Answer 1

In order to determne the scale factor, calculate the quotient in between the lengths of the sides of the rectangles, as follow:

32 ft/24 ft = 4/3

8 ft/ 6 ft = 4/3

Hence, the scale factor is 4/3


Related Questions

The function c = 100+.30m represents the cost c (in dollars) of renting a car afterdriving m miles.How many miles would a customer have to drive for the cost to be $149.50?

Answers

149.5 = 100 + .30m

149.5 - 100 = .30m

49.5 = .30m

Divide both sides by 0.30

m = 49.5/0.3

m =165

Option D

Finding a polynomial of a given degree with given zeros: Complex zeros

Answers

Given:

• Degree of polynomial = 3

,

• Zeros of the polynomial: 2, 3 - 2i

Let's find the polynomial.

Since the polynomail is of degree 3, it's highest exponent will be 3.

Equate the zeros to zero:

x = 2

Subtract 2 from both sides:

x - 2 = 2 - 2

x - 2 = 0

x = (3 - 2i)

Since this root is a complex conjugate, we have the other complex root: (3 + 2i)

Hence, we have:

(x - (3 - 2i)) and (x - (3 + 2i)).

Therefore, to write the function, we have:

[tex]f(x)=(x-2)(x-(3-2i))(x-(3+2i))[/tex]

Now, simplify the expression:

[tex]\begin{gathered} f(x)=(x-2)(x-3+2i)(x-3-2i) \\ \\ f(x)=x(x-3+2i)-2(x-3+2i)(x-3-2i) \\ \\ f(x)=x^2-3x+2ix-2x+6-4i(x-3-2i) \\ \\ f(x)=x^2-5x+2ix-4i+6(x-3-2i) \end{gathered}[/tex]

Solving further:

[tex]\begin{gathered} f(x)=x(x^2-5x+2ix-4i+6)-3(x^2-5x+2ix-4i+6)-2i(x^2-5x+2ix-4i+6) \\ \\ f(x)=x^3-5x^2+2ix^2-4ix+6x-3x^2+15x-6ix+12i-18-2ix^2+10ix-4i^2x-8-12i^{} \end{gathered}[/tex]

Combine like terms:

[tex]\begin{gathered} f(x)=x^3-5x^2-3x^2-4ix-6ix+10ix+2ix^2-2ix^2+6x+15x+12i-12i-8-16 \\ \\ f(x)=x^3-8x^2+25x-26 \end{gathered}[/tex]

ANSWER:

[tex]f(x)=x^3-8x^2+25x-26[/tex]

Question 8 of 10If f(x) = - VX-3, complete the following statement (round your answerto the nearest hundredth):3x + 2f(7) = —Answer hereSUBMITplease help

Answers

To find f(7) substitute x by 7 in the function

Given the median QR and trapezoid MNOP, what is the value of X?M3.8033Rکد 73PA. 6B. 19(C. 2D, 5E 7F. Cannot be determined

Answers

SOLUTION

Consider the diagram below

Applying the rule in the diagram above, we have

[tex]|QR|=\frac{1}{2}(|ON|+|PM|)[/tex]

Recall from the questions

[tex]\begin{gathered} |QR|=33 \\ |ON|=3x-8 \\ |PM|=7x+4 \end{gathered}[/tex]

Then we substitute the parameters above into the expression above

[tex]\begin{gathered} 33=\frac{1}{2}(3x-8+7x+4) \\ \text{ Multiply both sides by 2} \\ 66=3x-8+7x+4 \\ \text{rerrange the terms and simplify } \\ 66=10x-4 \\ \text{collect like terms } \\ 66+4=10x \end{gathered}[/tex]

simplify further

[tex]\begin{gathered} 70=10x \\ \text{divide both sides by 10} \\ x=\frac{70}{10} \\ \text{then} \\ x=7 \end{gathered}[/tex]

Therefore the value of x is 7

Therefore the right option is E

Describe the complement of the given event. 73% of nineteen year old males are at least 166 pounds

Answers

Solution

- The event is "73% of nineteen year old males are at least 166 pounds"

- The complement of this event is the set of all 19 year old males not in the event described above.

- These set of 19 year olds, must represent the remaining 27% of the population.

- Also, they would weigh less than 166 pounds.

- Thus, the complement of the event is:

"27% of nineteen year old males weigh less than 166 pounds"

Solve T=C(8+AB) for A

Answers

[tex]\begin{gathered} \text{Given} \\ T=C(8+AB) \end{gathered}[/tex][tex]\begin{gathered} \text{Divide both sides by }C \\ T=C(8+AB) \\ \frac{T}{C}=\frac{C(8+AB)}{C} \\ \frac{T}{C}=\frac{\cancel{C}(8+AB)}{\cancel{C}} \\ \frac{T}{C}=8+AB \\ \\ \text{Subtract both sides by }8 \\ \frac{T}{C}-8=8-8+AB \\ \frac{T}{C}-8=\cancel{8-8}+AB \\ \frac{T}{C}-8=AB \\ \\ \text{Divide both sides by }B \\ \frac{\frac{T}{C}-8}{B}=\frac{AB}{B} \\ \frac{\frac{T}{C}}{B}-\frac{8}{B}=\frac{A\cancel{B}}{\cancel{B}} \\ \frac{T}{CB}-\frac{8}{B}=A \\ \\ \text{By symmetric property of equality, we can swap left and right side of equations} \\ \frac{T}{CB}-\frac{8}{B}=A \\ A=\frac{T}{CB}-\frac{8}{B} \end{gathered}[/tex]

Mary is x years old. How old will she be in 10 years? How old was she 2 years ago?

Answers

We know that Mary is x years old.

The age in 10 years will be x plus 10, as follows:

[tex]M_{\text{age}+10}=x+10[/tex]

And the age she had two years ago was:

[tex]M_{\text{age}-2}=x-2[/tex]

An example of this could be: imagine that Mary is 10 years now. In ten years, she will have:

10 + 10 = 20 years ( we add 10 to the original number). Likewise, 2 years ago, she had 10-2 = 8 years.

Therefore, the answers are two equations:

[tex]M_{age+10}=x+10[/tex][tex]M_{\text{age}-2}=x-2[/tex]

Given that figure ABCD is a dilation of figure KLMN, find the missing values:(note that values are slightly different because of a round-off error)

Answers

• Given the dimensions of ABCD:

m∠A = 71.68 degrees

m∠C = 47.68 degrees

m∠D = 141.87 degrees

CD = 4

AD = 6

BC = 8

• Dimensions of KLMN:

m∠K = 71.52 degrees

m∠L = 98.87 degrees

m∠M = 47.53 degrees

KL = 10

KN = 15

MN = 10

Let's find the missing values.

Given that figure ABCD is a dilation of KLMN, both figures are similar.

• Similar figures have proportional corresponding sides.

,

• Similar figures have equal corresponding angles.

Therefore, we have the corresponding sides:

AB ⇔ KL

BC ⇔ LM

CD ⇔ MN

AD ⇔ KN

The corresponding angles are:

m∠A = m∠K

m∠B = m∠L

m∠C = m∠M

m∠D = m∠N

Thus, to find the missing values, we have:

• X = m∠B = m∠L = 98.87 degrees

X = 98.87 degrees.

• Y = m∠N = m∠D = 141.87 degrees.

Y = 141.87 degrees

• To find the value of ,a,, apply the proportionality equation:

[tex]\frac{AB}{AD}=\frac{KL}{KN}[/tex]

Plug in values and solve for a:

[tex]\begin{gathered} \frac{a}{6}=\frac{10}{15} \\ \\ \text{Cross multiply:} \\ 15a=10\times6 \\ \\ 15a=60 \\ \\ a=\frac{60}{15} \\ \\ a=4 \end{gathered}[/tex]

• To find the value of ,b,, apply the proportionality equation:

[tex]\begin{gathered} \frac{DC}{BC}=\frac{NM}{LM} \\ \\ \frac{4}{8}=\frac{10}{b} \\ \\ \text{Cross multiply:} \\ 4b=10\times8 \\ \\ 4b=80 \\ \\ b=\frac{80}{4} \\ \\ b=20 \end{gathered}[/tex]

ANSWER:

• X = 98.87°

,

• Y = 141.87°

,

• a = 4

,

• b = 20

write the slope-interference form of the equation of each line

Answers

The slope interference form of straight line is given by

[tex]y=mx+c[/tex]

Here is the slope of the line and c is the y-intercept

Now, from the graph, it is seen that the line passes through the points (0,4) and (3,5)

So,

[tex]\begin{gathered} \frac{y-4}{5-4}=\frac{x-0}{3-0} \\ \frac{y-4}{1}=\frac{x}{3} \\ 3(y-4)=x \\ 3y=x+12 \\ y=\frac{x}{3}+4 \end{gathered}[/tex]

So, the required equation is

[tex]y=\frac{x}{3}+4[/tex]

The graph shows the absolute value parent function. 6 Which statement is true? A. (0,1) is the x- and y-intercept of the function. B. (1,1) is the x- and y-intercept of the function. O C. (0,0) is the x- and y-intercept of the function. D. The function has no intercepts.

Answers

From the graph;

(0,0) is the (x, y) intercept of the graph

since the function passes through (0,0)

If the carrier transmits 12 kW, what is the modulated power if modulation index is (1/√2) ?

Answers

The modulated power is 15 kW.

The modulated power is given by the formula P_T= P_C (1+  (m_a^2)/2) and is connected to the total power of the carrier signal and the modulation index.

To obtain the modulated power, substitute the values in the given equation and simplify.

Given,  

Power of carrier signal (P_C) = 12 kW

                                                = 12000 W

Modulation index ( m_a) = 1/√2

Consequently, when we change the variables in the equation, we get

P_T= P_C (1+  (m_a^2)/2)

     =12000 (1+  (1/√2)^2/2)

     = 12000 (1+ 1/4)

     = 12000 * 5/4

     = 3000*5

     = 15000 W

     =  15 kW

Hence, modulated power is 15 kW.

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1/b + 1/9 + = 1/tSolve for t

Answers

The given expression is

[tex]\frac{1}{b}+\frac{1}{9}=\frac{1}{t}[/tex]

First, we multiply the equation by t

[tex]\begin{gathered} (\frac{1}{b}+\frac{1}{9})\cdot t=\frac{1}{t}\cdot t \\ (\frac{1}{b}+\frac{1}{9})\cdot t=1 \end{gathered}[/tex]

Now, we divide the equation by 1/b + 1/9

[tex]\begin{gathered} \frac{(\frac{1}{b}+\frac{1}{9})\cdot t}{(\frac{1}{b}+\frac{1}{9})}=\frac{1}{(\frac{1}{b}+\frac{1}{9})} \\ t=\frac{1}{(\frac{1}{b}+\frac{1}{9})} \end{gathered}[/tex]

Now, we sum fractions

[tex]t=\frac{1}{\frac{9+b}{9b}}[/tex]

Then, we solve this combined fraction

[tex]t=\frac{9b\cdot1}{9+b}=\frac{9b}{9+b}[/tex]

Therefore, the final expression is

[tex]t=\frac{9b}{9+b}[/tex]

I will give brainlist

The Busy Bee store bottles fresh jars of honey at a constant rate. In 2 hours, it bottles 18 jars, and in 6 hours, it bottles 54 jars of honey.

Determine the constant of proportionality.

9
18
0.11
4.5

Answers

The constant of proportionality is A. 9.

What is a constant of proportionality?

The constant of proportionality is simply used to show that the numbers given have a constant value.

From the information, the Busy Bee store bottles fresh jars of honey at a constant rate. In 2 hours, it bottles 18 jars. The constant will be:

= Number of jars / Number of hours

= 18/2

= 9

In 6 hours, it bottles 54 jars of honey. The constant will be:

= 54 / 6

= 9

Therefore, the constant is 9.

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I solved for Part A and the correct graph was answer A I just need Part B to be solved (at the bottom)

Answers

In Part (b) of this problem, we want to determine which function is the bes representation for the graph and table.

We are given:

To determine which function matches best, we can look at the parent function of a linear, logarithmic, and exponential function.

(see comparisons below):

Notice that our graph most closely resembles that of the exponential function. Therefore, the best model for the data would be an exponential function.

1 punto Two distinct coplanar lines that do not intersect are known as lines * A. parallel B. perpendicular C. skew D. Tangent

Answers

Coplanar lines are lines that lies in the same plane.

By definition, two distince lines that lies in the same plane and that do not intersect are said to be parallel

Hence the correct choice is A

i need help please,solve and explain it's 4th grade math.. thank you.

Answers

What you can say about 12th, 18th and the 21st child, depends if these numbers are multiples of 4 (every 4th child is wearing spectacles), 3 (every 3rd child is a girl) and 2 (every 2nd child is wearing a white shirt).

If a numer is multiple of another one, then the quotient between them is an integer number.

for 12th:

12/4 = 3

12/3 = 4

12/2 = 6

12 is multiple of 3, 4 and 6.

Then, 12th child is wearing spectacles, a white shirt and is a girl.

for 18th:

18/4 = 4.5

18/3 = 6

18/2 = 9

18 is multiple of 3 and 2.

Then, 18th child is a girl and is weraing a white shirt

for 21th:

21/4 = 5.25

21/3 = 7

21/2 = 11.5

21 is multiple of 3.

THen, 21st child is a girl.

Is the prime factor of 121 11x11?

Answers

The prime factor of 121 is simply 11.

11x11 =121, since you can't take 11 two times.

Fill in the blank. In the triangle below, Z = 52° 35

Answers

Solution

Since the diagram given is a Triangle, therefore, the sum of it's interior angles is 180 degrees

However, the Triangle is a right angle Triangle since on of its angles is 90 degrees.

The sum of its Interior angles is given by;

[tex]\begin{gathered} z+52+90=180 \\ \\ \Rightarrow z+142=180 \end{gathered}[/tex]

subtracting 142 from both sides,

[tex]\begin{gathered} \Rightarrow z+142-142=180-142=38 \\ \\ \Rightarrow z=38^0 \end{gathered}[/tex]

Therefore, z = 38

Hello I need help with the following question. 8. Use the given graph of the function f to find the domain and range(−6,6)8 The domain of f is(Type a compound inequality.)The range of f is(Type a compound inequality.)

Answers

We are to use the given graph in the question to find the domain and range

From the graph,

The lowest value of x plotted is x = -14

The highest value of x plotted is x = 12

The loowest value of y is y= -4

The highest value of y is y = 6

Hence, the domain is

[tex]-14\leq x\leq12[/tex]

While the range is

[tex]-4\leq y\leq6[/tex]

In the diagram below of triangle DEF, G is a midpoint of DE and H is a midpoint of EF. IfGH = 50 -- 87, and DF = 9x + 0, what is the measure of GH? E H D F

Answers

Answer:

GH = 18

Explanations:

From the diagram:

DF = 9x + 0

GH = 50 - 8x

Since G is a midpoint of DE and H is a midpoint of EF, using the midpoint theorem:

DF = 2GH

9x + 0 = 2 (50 - 8x)

9x = 100 - 16x

9x + 16x = 100

25x = 100

x = 100/25

x = 4

Substituting the value of x into GH = 50 - 8x

GH = 50 - 8(4)

GH = 50 - 32

GH = 18

write in exponential form5x5x5

Answers

5 x 5 x 5 = 5^3

[tex]\begin{gathered} \\ 5x5x5=5^{3\text{ }}\text{ = 125} \end{gathered}[/tex][tex]=16^{5\text{ }}\text{ = 16 x 16 x 16 x 16 x 16 = 1,048,576}[/tex]

g(x)=2x-2f(x)=4x-1Find (g*f) (-9)

Answers

Given:

[tex]\begin{gathered} g(x)=2x-2 \\ f(x)=4x-1 \end{gathered}[/tex]

The expression for g(f(x)) is,

[tex]\begin{gathered} g(f(x))=2(f(x))-2 \\ =2(4x-1)-2 \\ =8x-2-2 \\ =8x \end{gathered}[/tex]

Substitute x=-9 in the above expression.

[tex]\begin{gathered} g(f(-9))=8\times-9 \\ =-72 \end{gathered}[/tex]

Thus, the final value of the expression is -72.

Which is closest to the circumference of the earth if it's diameter is 7926.41 miles?

Answers

ANSWER

24901.55 miles

EXPLANATION

We have to find the circumference of the earth using the diameter given.

The formula for circumference is:

[tex]C=\pi\cdot D[/tex]

where D = diameter

Therefore, the circumference is:

[tex]\begin{gathered} C=\pi\cdot7926.41 \\ C=24901.55\text{ miles} \end{gathered}[/tex]

18. The table below gives the population of a town (in thousands) from the year 2000 to the year 2008. Year '00 '01 '02 03 04 '05 06 '07 '08 Population 87 84 83 80 77 76 78 81 85 (thousands) What was the average rate of change of population: a. between 2002 and 2004? b. between 2002 and 2006?

Answers

a . Average rate of change between 2002 and 2004 can be calculated below

[tex]\begin{gathered} average\text{ rate of change=}\frac{chang\text{e in y}}{\text{change in x}} \\ average\text{ rate of change = }\frac{77-83}{2004-2002} \\ average\text{ rate of change}=\frac{-6}{2}=-3(thousand) \end{gathered}[/tex]

b. Average rate of change between 2002 and 2006 is

[tex]\begin{gathered} \text{average rate of change = }\frac{78-83}{2006-2002} \\ average\text{ rate of change}=\frac{-5}{4}=-\frac{5}{4}(thousand) \end{gathered}[/tex]

Give the sample space describing all the outcomes. Then give all of the out comes for the event that the number 3 chosen. Use the format H1 to mean that the coin toss is heads and the number chosen is 1. If there is more than one element in the set separate them with commas

Answers

Explanation

The sample space is composed of all the possible outcomes i.e. of all the possible combinations between the result of tossing the coin and picking the card. There are two possible outcomes for the coin and four for the cards so there will be 8 different combinations in the saple space. These are:

[tex]H1,H2,H3,H4,T1,T2,T3,T4[/tex]

Then we must show all the outcomes where the card with the 3 is picked. This set is composed of all the elements with a 3 in the list above. There are two:

[tex]H3,T3[/tex]Answers

Then the answers are:

Sample space: {H1,H2,H3,H4,T1,T2,T3,T4}

Event that the number chosen is 3: {H3,T3}

An arts academy requires there to be 6 teachers for every 96 students and 3 tutors for every 30 students. How many students does the academy have per teacher? Per tutor? How many tutors does the academy need if it has 100 students?

Answers

If the school requieres 6 teachers for every 96 students then

1 teacher will be required for every

= 96/6

= 16 students

If 3 tutors for every 30 students then 1 tutor is required for

= 30/3

= 10 students

If the academy has 100 students, the number of tutors required would be

= 100/10

= 10 tutors

Hence

The academy requires;

f(x) = x^2 g(x) = x^2 - 8 g(x)= x^2 - 8 We can think of g as a translated (shifted) version of f. Complete the description of the transformation. Use nonnegative numbers. To get the function g, shift f [up/down/left/right] by [ ] units.

Answers

We have that the parent function (the original function is x^2). If we add a number after it as:

[tex]f(x)=x^2_{}+b[/tex]

We affect the function in the y-axis, that is, we move the original function upward or downward.

Therefore, to get the function g, we need to shift the f function down by 8 units, that is

[tex]g(x)=f(x)-8=x^2-8[/tex]

Determine the value of n that makes the polynomial a perfect square trinomial. Then factor as the square of a binomial. Express numbers as integers orsimplified fractions.u^2+20u+n

Answers

SOLUTION

The expression is given as

[tex]u^2+20u+n[/tex]

The value of n makes the expression a perfect square trinomial.

To find the value of n, we have

Identify the coefficient of u and divide by 2

[tex]\begin{gathered} \text{the coefficient of u=20} \\ \text{divide by 2=}\frac{\text{20}}{2}=10 \end{gathered}[/tex]

Then square the result, we have

[tex]\begin{gathered} 10^2=100 \\ \text{hence } \\ n=100 \end{gathered}[/tex]

Then the complete trinomial of the polynomial becomes

[tex]u^2+20u+100[/tex]

To factor as a square of a binomial we use the perfect square trinomial above

[tex]\begin{gathered} u^2+20u+100 \\ u^2+20u+10^2 \\ \text{Then} \\ (u+10)^2 \end{gathered}[/tex]

Therefore

The vaue of n = 100

The factor as the square of a binomial is (u+ 10)²

Given that the height of a trapezoid is 16 m and one base’s length is 25 m. Calculate the dimension of the other base of the trapezoid if its area is 352 m².

Answers

ANSWER:

19 m

STEP-BY-STEP EXPLANATION:

We have that the formula for the area of a trapezoid is the following:

[tex]A=\frac{B+b}{2}\cdot h[/tex]

We substitute each value and calculate the length of the other base, like so:

[tex]\begin{gathered} 352=\frac{25+b}{2}\cdot16 \\ \\ 25+b=352\cdot\frac{2}{16}\frac{}{} \\ \\ b=44-25 \\ \\ b=19 \end{gathered}[/tex]

The dimension of the other base of the trapezoid is 19 m

Tanvir applies the distributive property to the left-hand side of the equation 1/3(3q+15)=101 Which equation shows the correct application of the distributive property?

1: q+15=101
2:3q+5=101
3:3q+15=101
4:q+5=101

Answers

When Tanvir applies the distributive property to the left-hand side of the equation, 1/3(3q+15)=101, the equation that shows the correct application is equation 4: q+5=101.

What is distributive property?

The distributive property applies basic mathematical operations, especially in equations.

This property is that when a value is multiplied or divided by a number to a set that will be added or subtracted, the result is the same, notwithstanding if the operation is done before the addition or subtraction.

1/3(3q+15) = 101

(3q/3+15/3) = 101

= q + 5 = 101

q = 96

Check of Distributive Property:

1/3(3q+15) = 101

1/3(3 x 96+15) = 101

= 1 x 96 + 5 = 101

= 96 + 5 = 101

= 101 = 101

Or: 1/3(3q+15) = 101

1/3(3 x 96+15) = 101

= 1/3(288 + 15) = 101

= 1/3(303) = 101

= 101 = 101

Thus, the equation that correctly applies the distributive property is equation 4: q+5=101.

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