Suppose m is the line with equation y = −4 and ΔA'B'C is mapped to ΔA"B"C" by applying the glide reflection T3, 0 Rm.
What are the coordinates of ΔA″B″C″?

Suppose M Is The Line With Equation Y = 4 And A'B'C Is Mapped To A"B"C" By Applying The Glide Reflection

Answers

Answer 1

Answer:

The coordinates of ΔA''B''C'' are;

A''(-1, -3), B''(-2, -6), C''(1 , -7)

Step-by-step explanation:

A glide reflection involves the reflection of the preimage over a given line, followed by the translation of the resulting image along the given line

Given that the coordinates of the triangle ΔA'B'C' are;

A'(-4, -5), B'(-5, -2), C'(-2, -1), we have by reflection across the line y = -4

A''(-4, -4 + 1) = A''(-4, -3)

B''(-5, -4 - 2) = B''(-5, -6)

C''(-2, -4-3) = C''(-2, -7)

Translation of A''B''C'' by T 3, 0, we have;

A''(-4, -3)  → T₃, ₀ → A''(-4 + 3, -3) = A''(-1, -3)

B''(-5, -6)  → T₃, ₀ → B''(-5 + 3, -6) = B''(-2, -6)

C''(-2, -7) → T₃, ₀ → C''(-2 + 3, -7) = C''(1 , -7)

The coordinates of ΔA''B''C'' are therefore;

A''(-1, -3), B''(-2, -6), C''(1 , -7).

Answer 2

Answer:

A″(−1, −3), B″(−2, −6), C″(1, −7)

option A


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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

See the attached above.

Hope it helps :)

The slope of line passing through M (-3,5) & N (1,8) will be 3/4.

We have been given a line passing through points M (-3,5) & N (1,8) .

We have to find out what will be the slope of the line ?

What is the formula for slope of a line ?

Slope of line is given by , m = (y2-y1) / (x2-x1).

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Answers

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Answers

Answer:

Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

i am not 100% sure

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:hope that helps :)))

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

 [tex]\bold{Hello!}\\\bold{Your~Answer~Is~Below!}[/tex]

______________________________

 [tex]\bold{Solution~Steps:}[/tex]

[tex]1.)~54+3(1-1):[/tex]

[tex]\bold{Subtract~1~from~1~to~get~0.}[/tex][tex]\bold{Multiply~3~and~0~to~get~0.}[/tex][tex]\bold{Add~54~and~0~to~get~54.}[/tex]

[tex]2.)~54+3(2-1):[/tex]

[tex]\bold{Subtract~1~from~2~to~get~1.}[/tex][tex]\bold{Multiply~3~and~1~to~get~3.}[/tex][tex]\bold{Add~54~and~3~to~get~57.}[/tex]

[tex]3.)~54+3(3-1):[/tex]

[tex]\bold{Subtract~1~from~3~to~get~2.}[/tex][tex]\bold{Multiply~3~and~2~to~get~6.}[/tex][tex]\bold{Add~54~and~6~to~get~60.}[/tex]

[tex]4.)~54+3(4-1):[/tex]

[tex]\bold{Subtract~1~from~4~to~get~3.}[/tex][tex]\bold{Multiply~3~and~3~to~get~9.}[/tex][tex]\bold{Add~54~and~9~to~get~63.}[/tex]

______________________________

 [tex]\bold{Answers:}[/tex]

[tex]\bold{Term~1=\boxed{54}}[/tex][tex]\bold{Term~2=\boxed{57}}[/tex][tex]\bold{Term~3=\boxed{60}}[/tex][tex]\bold{Term~4=\boxed{63}}[/tex]

______________________________

 [tex]\bold{Hope~this~helps,}\\\bold{And~best~of~luck!}\\\\\bold{~~~~~~~-TotallyNotTrillex}[/tex]

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Answers

Answer:

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Step-by-step explanation:

Equations

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Step-by-step explanation:

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Answer

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Step-by-step explanation:

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