Suppose the marginal revenue function for a good is MR=300-13q¹2 +16q³, where q is the number of units sold, and that total revenue from selling 1 unit is R3 316. Find the total revenue function.​

The expression for the perimeter of the wood deck, obtained from the formula for finding the perimeter of a rectangle is; 84 + 8·c + 8·w

The perimeter of a rectangle is found from the sum of twice the length and twice the width of the rectangle.

The dimensions of the rectangular swimming pool are;

Length = 26 feet

Width = 16 feet

The width of the concrete walkway = c

The width of the wooden deck = w

Therefore;

The length of the perimeter of the wooden deck = 26 + 2·c + 2·w

The width of the perimeter of the wooden deck = 16 + 2·c + 2·w

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The solution of the given system of equations by substitution is (-2, -3).

Given a system of equations,

9y - 7x = -13 [Equation 1]

-9x + y = 15 [Equation 2]

We have to find the solution of the given system of equations.

From [Equation 2],

y = 15 + 9x [Equation 3]

Substitute [Equation 3] in [Equation 1].

9 (15 + 9x) - 7x = -13

135 + 81x - 7x = -13

74x = -148

x = -2

y = 15 + (-18) = -3

Hence the solution of the given system of equations is (-2, -3).

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As we see, p-value is less than the significance level, so null hypothesis rejected and there is no evidence to support the claim that population mean is 22 degree C.

The population mean can be calculated by the sum of all values in the given data/population divided by a total number of values. We have various temperature measurements are recorded at different times for a particular city.

Sample Mean, [tex]\bar X [/tex] = 20°C

Standard deviations,[tex]\sigma [/tex]= 1.5° C

Level of significance, = 0.05

We have to test that population mean is 22 degree C. Consider the hypothesis testing, the null and alternative hypothesis are [tex]H_0 : \mu = 22 [/tex].

[tex]H_a : \mu ≠ 22 [/tex].

Consider the test statistic, z test for mean formula, [tex]z = \frac{\bar x - \mu }{\frac{\sigma}{\sqrt{n}}}[/tex].

=> [tex]z = \frac{20 - 22}{\frac {1.5}{\sqrt{60}}}[/tex].

= - 10.32

Now, using distribution table, the p-value for z = - 10.32 is less than to 0.001. So,

p-value < 0.05, so null hypothesis is rejected.

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The probability that the randomly selected point is in the bullseye is 0.75, or 75%.

The area of the bullseye is the difference between the areas of the larger and smaller circles:

[tex]A = \pi r_1^2 - \pi r_2^2[/tex]

where [tex]r_1[/tex] is the radius of the larger circle (8 cm) and [tex]r_2[/tex] is the radius of the smaller circle (4 cm).

[tex]A = \pi(8^2 - 4^2)A = \pi(64 - 16)A = 48\pi[/tex]

The area of the entire target (both circles) is:

[tex]A = \pi r_1^2[/tex]

A = 64π

Therefore, the probability of selecting a point in the bullseye is:

P(bullseye) = A(bullseye) / A(target)

P(bullseye) = (48π) / (64π)

P(bullseye) = 3/4 or 0.75

So the probability that the randomly selected point is in the bullseye is 0.75, or 75%.

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Using translation concepts, it is found that graph D represents the function f(x) = tan(x + 1).

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

The function f(x) = tan(x + 1) is a translation of one unit to the left of g(x) = tan(x), which has g(0) = 0, hence at the translated function g(-1) = 0, which means that graph D represents the function f(x).

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The equation is y = x - 3

and the points (x, y) is (0,-3) , (-1, -4) and (1, -2)

The equation is as follows:

y = x - 3

Substituting 'x = 0' in the given equation, we get

y = 0 - 3

y = -3

Substituting 'x = - 1' in the given equation, we get

y = - 1 - 3

y = -4

Substituting 'x = 1' in the given equation, we get

y = 1 - 3

y = -2

➢ Pair of points of the given equation are shown in the below table.

x             y

0            -3

-1            -4

1             -2

➢ Now draw a graph using the points.

➢ See the attachment graph.

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The experimental probability of landing on a number greater than 4 is 18/60

The experimental probability will be given by the number of times that the outcome was greater than 4 (so a 5 or a 6) over the total number of trials.

We can see that the total number of trials is 60, and we have:

The outcome 5 a total of 10 times.

The outomce 6 a total of 8 times.

Adding these values we will get 10 + 8 = 18

Then the experimental probability of a number greater than 4 is:

E = 18/60

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a. At the 0.05 level of​ significance, there is evidence of a linear relationship between the plate gap of the​ bag-sealing machine and the tear rating of a bag of​ coffee.

b. A​ 95% confidence interval estimate of the population​ slope, betaβ1 is (0.5590, 0.8606).

a. To test for the linear relationship between plate gap and tear rating, we can use the null and alternative hypotheses:

H0: β1 = 0 (there is no linear relationship)
Ha: β1 ≠ 0 (there is a linear relationship)

We can use the t-test to test this hypothesis. The test statistic is calculated as:

t = b1 / (S1 / [tex]\sqrt(n)[/tex])

where b1 is the sample slope, S1 is the standard error of the slope, and n is the sample size. Substituting the values given in the question, we get:

t = 0.7098 / (0.2146 / sqrt(30)) = 5.05

Using a t-distribution with n-2 = 28 degrees of freedom and a significance level of 0.05, we can find the critical values as ±2.048. Since the calculated t-value of 5.05 is greater than the critical value of 2.048, we reject the null hypothesis and conclude that there is evidence of a linear relationship between plate gap and tear rating at the 0.05 level of significance.

b. To construct a 95% confidence interval estimate of the population slope β1, we can use the formula:

b1 ± tα/2(S1 / [tex]\sqrt(n)[/tex])

where tα/2 is the critical value from the t-distribution with n-2 degrees of freedom and a confidence level of 95%. Substituting the values given in the question, we get:

b1 ± 2.048(0.2146 / [tex]\sqrt(30)[/tex]) = 0.7098 ± 0.1508

Therefore, the 95% confidence interval for the population slope β1 is (0.5590, 0.8606).

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If the sum of squares for error (SSE) is 40 and the sum of squares due to the model (SSM) is 60, therefore, the answer is (c) 0.60.

Based on your question,  the coefficient of determination (R²) for a simple linear regression, given the sum of squares for error (SSE) is 40 and the sum of squares due to the model (SSM) is 60.

To calculate R², follow these steps:

1. Calculate the total sum of squares (SST): SST = SSE + SSM
2. Divide SSM by SST: R² = SSM / SST

Now, let's apply the values from your question:
To calculate, we use the formula:
= SSM / SSM + SSE)

Plugging in the given values, we get:
= 60 / (60 + 40) = 0.6
SST = SSE + SSM = 40 + 60 = 100
R² = SSM / SST = 60 / 100 = 0.60

So, the coefficient of determination (R²) is 0.60, which corresponds to option (c).

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The solutions to the equation 12x²-22x-5=-5x using the quadratic formula are x = 5/4 and x = -1/3.

The given equation is a quadratic equation in standard form, ax² + bx + c = 0, where a = 12, b = -22, and c = -5 + 5 = 0. We can use the quadratic formula to solve for x:

x = (-b ± √(b² - 4ac)) / 2a

Substituting the values of a, b, and c, we get:

x = (22 ± √(22² - 4(12)(0))) / 2(12)

Simplifying under the square root, we get:

x = (22 ± √484) / 24

x = (22 ± 22) / 24

Simplifying further, we get:

x = 44/24 or x = 0/24

Reducing the first fraction, we get:

x = 11/6 or x = 0

However, we need to check if x = 0 satisfies the given equation or not. Substituting x = 0, we get:

12(0)² - 22(0) - 5 = -5(0)

-5 = 0

This is not true, so x = 0 is an extraneous solution and should be discarded. Therefore, the solutions to the given equation are:

x = 5/4 and x = -1/3.

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The value of a in the expression will be 3750.

The value of b, rounded to 2 decimal places will be (75/23)^1/4

The value of n is 450.

An expression consists of one or more numbers or variables along with one more operation.

The value of a in the expression will be:

= 4200 - 450

= 3750.

The number of French words a student remembers never decreases below a certain number of words, n which is 450.

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Using the system of equations, we get that the drama club is charging $21 for a regular gift basket and $39 or a deluxe gift basket.

Given that,

The drama club is selling gift baskets to raise money for new costumes.

Let x be cost of the regular gift baskets and y be the cost of the deluxe gift baskets.

During the fall play, they sold a combined 15 regular gift baskets and 17 deluxe gift baskets, earning a total of $978.

15x + 17y = 978

During the spring musical, they sold 27 regular gift baskets and 17 deluxe gift baskets, earning a total of $1,230.

27x + 17y = 1230

From both equations,

978 - 15x = 1230 - 27x

12x = 252

x = 21

Cost of regular gift basket = $21

Cost of deluxe gift basket = y = (978 - 15 (21)) / 17 = $39

Hence the cost two kinds of baskets are $21 and $39.

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Answer:

y = x + 9

Step-by-step explanation:

We Know

Sarah threw the javelin 9 inches farther than Kimberly.

Let's y represent the total distance Sarah threw and x is the distance Kimberly threw, we have the equation

y = x + 9

A manufacturer of soap bubble liquid tests a new formula with a sample of 700 parisons. With a significance level of 0.05, the test results in a p-value of 0.206, leading to the conclusion that the new formula can be approved since the proportion of defective parisons does not exceed 7%. So, the correct option is A).

Let p be the true proportion of defective parisons in the population.

The null hypothesis is that the proportion of defective parisons is equal to or less than 7%, i.e., H0: p <= 0.07

The alternative hypothesis is that the proportion of defective parisons is greater than 7%, i.e., Ha: p > 0.07

Calculate the sample proportion and standard error

We are given that the sample size n = 700 and the number of defective parisons x = 55.

The sample proportion is P = x/n = 55/700 = 0.0786

The standard error of the sample proportion is

SE = √[(P(1-P))/n] = sqrt[(0.0786*0.9214)/700] = 0.0166

Calculate the test statistic

The test statistic for a one-tailed z-test is

z = (P - p) / SE

Here, we want to test if the proportion of defective parisons is greater than 7%, so we use the alternative hypothesis to calculate the z-value

z = (0.0786 - 0.07) / 0.0166 = 0.516

The p-value is the probability of getting a test statistic as extreme or more extreme than the observed value, assuming the null hypothesis is true. Since this is a one-tailed test, we need to find the area under the standard normal distribution curve to the right of z = 0.516.

Using a standard normal table or calculator, we find that the area to the right of z = 0.516 is 0.206.

The p-value of the test is 0.206, which is greater than the significance level of 0.05. Therefore, we fail to reject the null hypothesis and conclude that there is not enough evidence to suggest that the proportion of defective parisons is greater than 7%.

In other words, the new soap bubble liquid formula can be approved since the proportion of produced parisons with contents that do not allow bubbles to inflate does not exceed 7%. So, the correct answer is A).

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Therefore, we have the recurrence relation: |P(S_k)| = 2 * |P(S_{k-1})|
with the initial condition |P(S_0)| = 1 (since the empty set is the only subset of the empty set).

Sure! To count the number of subsets of a set with k elements, we can use the fact that each element can either be in a subset or not. This gives us two options for each element, so there are 2^k total subsets.

To set up a recurrence relation for this, let S_k denote the set with k elements and P(S_k) denote its power set (the set of all subsets of S_k). Then, we can relate P(S_k) to P(S_{k-1}) by considering whether or not to include the kth element in each subset.

If we don't include the kth element, then each subset of S_{k-1} is also a subset of S_k, so there are |P(S_{k-1})| subsets that don't include the kth element.

If we do include the kth element, then each subset of S_{k-1} can be extended by including the kth element, giving us |P(S_{k-1})| more subsets.

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In a case whereby Sami wants to find the measurements of the sides and angles of the parallelogram shown the tools she can use to find these measurements are;

The protractor serves as one of the tools that can be used in making the parallelogram whih which be used in the mearement of the angles of the paralleolgram.

The ruler is also useful in the creation of the parallelogram because it can be used to meausre the lenght of the fiqure, hence the first as well as the third option is right

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The researcher needs a sample of at least 46 days.

We have,

To estimate the true mean water temperature within 4 with 90% confidence, given that the variance is 27%, we need to use the formula for sample size in a confidence interval estimation:
n = (Z² x σ²) / E²
where n is the required sample size, Z is the Z-score corresponding to the desired confidence level (90%), σ^2 is the variance (27%), and E is the margin of error (4).

We can find the Z-score for a 90% confidence level using a standard normal table, which is 1.645.
Now we can plug the values into the formula:
n = (1.645² x 0.27) / 4²
n = (2.706025 x 0.27) / 16
n = 0.729625 / 16
n = 0.0456015625

Since we cannot have a fraction of a day, we need to round up to the nearest whole number to ensure the desired accuracy.

Therefore, the researcher needs a sample of at least 46 days to estimate the true mean water temperature within 4 with 90% confidence.

Thus,

The researcher needs a sample of at least 46 days.

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Answer:

2a - 1/a^2 +5

The first three terms of the sequence a_n = 2n-1/n²+5 are 1/6, 1/3, and 5/14.

In mathematics, a sequence is an enumerated collection of objects in which repetitions are allowed and order matters. Like a set, it contains members. The number of elements is called the length of the sequence.

A sequence is an ordered list of numbers. The three dots mean to continue forward in the pattern established. Each number in the sequence is called a term.

The first three terms of the sequence a_n = 2n-1/n²+5 are:

1. For n=1, a_1 = (2(1)-1)/(1²+5) = 1/6
2. For n=2, a_2 = (2(2)-1)/(2²+5) = 3/9 = 1/3
3. For n=3, a_3 = (2(3)-1)/(3²+5) = 5/14

So, the first three terms of the sequence are 1/6, 1/3, and 5/14.

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The marching of figure images with their formulas are:

Figure 1:

P = a + b + c

P = 5 + 5 + 8

Figure 2:

A = lw

A = 5 * 8

Figure 3:

V = lwh

V = 8 * 5 * 5

The formula for the area of a triangle is:

Area = ¹/₂ * base * height

Formula for area of a rectangle is:

Area = length * width

Formula for volume of a cuboid is:

V = length * width * height

1) For the triangle, we are not give the height and so we can only find the perimeter which is:

P = a + b + c

P = 5 + 5 + 8

2) The area of this rectangle is:

A = lw

A = 5 * 8

3) Volume of this cuboid is:

V = lwh

V = 8 * 5 * 5

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4(3x + 2)4 12 + K (3x + 2) 6 + K is NOT a family of antiderivative of 2(3x + 2). The correct answer is Option b.

To find the antiderivative of 2(3x + 2), follow these steps:

1. Notice the function is 2(3x + 2).
2. Apply the power rule of integration, which states that ∫x^n dx = (x^(n+1))/(n+1) + C, where n ≠ -1.
3. In this case, n = 1, so the antiderivative is (2(3x + 2)^2)/(2) + C.
4. Simplify to obtain (3x + 2)^2 + C.

Option b doesn't match this result, so it is NOT a family of antiderivatives of 2(3x + 2).

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The sampling distribution of p is the distribution of all possible values of p that could be obtained from all possible samples of size n = 200i from the population with size N = 25 and population proportion p = 0.2.

To determine whether the sampling distribution of p is approximately normal, we need to check the conditions n <= 0.05N and [tex]np(1 - p)\geq 10[/tex].

Here, n = 200i and N = 25, so [tex]n\leq 0.05N[/tex] holds if and only if [tex]i\leq 0625[/tex].

Since i is a positive integer, the largest value that i can take is 1. Therefore, n = 200 is the maximum sample size that we can have.

Next, we need to check whether [tex]np(1 - p)\geq 10[/tex]. Substituting n = 200 and p = 0.2, we get np(1 - p) = 32, which is greater than or equal to 10. Therefore, this condition is also satisfied.

Hence, we can conclude that the sampling distribution of p is approximately normal because [tex]n\leq0.05N[/tex] and [tex]np(1 - p)\geq 10[/tex].

Therefore, the correct answer is option A: Approximately normal because and [tex]n\leq0.05N[/tex] and [tex]n_{D} (1 - p)\geq 10.[/tex].

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We may draw a scatterplot of the data and compute the correlation coefficient to see whether there is a relationship between Nadeem's visits to the library and the number of books he checks out. Linear Equation = Y =mx+c. Option A is Correct.

The degree and direction of the linear link between two variables are measured by the correlation coefficient. If the correlation is positive, it suggests that if one variable rises, the other variable rises as well.

If there is a correlation, linear regression may be used to describe the data with a linear equation.

Y= mx+c

Based on how frequently Nadeem visits the library, we may use this equation to anticipate how many books he will borrow. Correlation does not always indicate cause, though. Option A is Correct.

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Correct Question:

Each month, Nadeem keeps track of the number of times he visits the library and the number of books he checks out Is there a correlation. you model his data with a linear equation? Is there a causal relationship?

A. There is a positive correlation and no causal relationship.

B. There is a negative correlation and no casual relationship.

C. There is a casual relationship but no positive correlation.

D. There is neither a correlation nor a casual relationship.

Answer:

128° + 52° + 38° + x° = 360°

218° + x° = 360°

x = 142

The experimental probability of drawing a diamond is 0.20

From the question, we have the following parameters that can be used in our computation:

Outcome Frequency

Heart 7

Spade 3

Club 6

Diamond 4

For diamond, we have

P(Diamond) = Diamond/Total

So, we have

P(Diamond) = 4/20

Evaluate

P(Diamond) = 0.20

Hence, the value is 0.20

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The distance between A and B is 5 unit.

We have the coordinates as

A(4, 3) and B(4, -2).

Using Distance formula

d= √(x₂ - x₁)² + (y₂ - y₁)²

So, d = √(-2-3)² + (4-4)²

d= √(-5)² + 0²

d = √25

d= 5

Thus, the distance between A and B is 5 unit.

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Answer: Answer:

3. For some x-values, the y-value of the exponential function is smaller.

4. For some x-values, the y-value of the exponential function is greater.

5. For any x-value greater than 7, the y-value of the exponential function is greater.

Step-by-step explanation:

We are given the functions,

It is required to find the true statements of the functions.

From the graphs of the functions below, we have that the graphs intersect at the point (6.32,79.878).

To the left of the point, we have that the exponential function have smaller y-values than the parabola.

To the right of the point, we have that the exponential function have greater y-values than the parabola.

Moreover, after x= 7, the y-values of the exponential function are always greater than parabola.

Thus, the correct options are 3, 4 and 5.

Step-by-step explanation:

Answer:

- For any x-value, the y-value of the exponential function is always greater. (False)

- For any x-value, the y-value of the exponential function is always smaller. (False)

- For some x-values, the y-value of the exponential function is smaller. (True)

- For some x-values, the y-value of the exponential function is greater. (True)

- For any x-value greater than 7, the y-value of the exponential function is greater. (Not enough information provided to determine)

- For equal intervals, the y-values of both functions have a common ratio. (False)

The general solution of the y" + 2y + y= 7 +75sin2x is given as:

y =  (c₁+c₂x)[tex]e^{-x}[/tex] + 7 - 12cos2x - 9sin2x

The Greek terms trigonon (triangle) and metron (measure) are the origin of the word trigonometry. The connections between the lengths and angles of triangles' sides are the subject of this area of mathematics. An equation with one or more trigonometric ratios of unknown angles is said to as trigonometric. The ratios of sine, cosine, tangent, cotangent, secant, and cosecant angles are used to express it.

y" + 2y' + y = 7 + 75sin2x

Auxlliary equation are (m²+2m+1) = 0

CF = (c₁+c₂x)[tex]e^{-x}[/tex]

PI = [tex]\frac{1}{D^2+2D+1} (7+75sin2x)[/tex]

Now,

[tex]\frac{7}{D^2+2D+1} +\frac{75}{D^2+2D+1} (sin2x)[/tex]

7 -3(2D+3)sin2x

7 - 6D.sin2x - 9sin2x

7 - 6 x 2cos2x - 9sin2x

7 - 12cos2x - 9sin2x

PI = 7 - 12cos2x - 9sin2x

Finally,

y = C.F + P.I

y =  (c₁+c₂x)[tex]e^{-x}[/tex] + 7 - 12cos2x - 9sin2x.

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The cars will be 225 km from point A when they meet and it will take 5 hours for the cars to meet..

Let's denote the distance of the faster car from point A as "x" km. Therefore, the distance of the slower car from point B would be "400-x" km.

We can use the formula for distance, which is:

distance = rate × time

For the faster car, the distance it travels can be expressed as:

x = 45t

where t is the time it takes for the cars to meet.

For the slower car, the distance it travels can be expressed as:

400-x = 35t

Now, we can solve for t by setting these two expressions equal to each other:

45t = 400 - 35t

80t = 400

t = 5

We can then substitute t back into either expression to find the distance from point A:

x = 45t = 45(5) = 225 km

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Answer:

Step-by-step explanation:

You want q and the probability of 3 successes in 8 trials if the probability of success is 0.45.

The value designated q is the complement of p, the probability of success.

  q = 1 -p

  q = 1 -0.45

  q = 0.55

The probability of 3 successes is ...

  P(3 of 8) = 8C3·p^3·q^(8-3) = 56·0.45^3·0.55^5

  P(3 of 8) ≈ 56°0.091125·0.050328 ≈ 0.256826

The probability of exactly 3 successes in 8 trials is about 0.2568.

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