The airplane flew 4,848 miles in 8 hours. How many miles per hour did it fly?

Step-by-step explanation:

the average change rate of a function f(x) in an interval [x1 .. x2] is

(f(x2) - f(x1)) / (x2 - x1)

in our case that is

(7000 - 2500) / (20 - 0) = 4500 / 20 = 225

the population changed in average by 225 people per year from 1900 to 1920.

Answer:

Sammis work is correct

Step-by-step explanation:

when handling equations such as 107d= 1,733.4

you see that d is being multiplied to 107 to equal the total,

so to find the answer to d you would divide 107 by the total to get your value of d

Answer:the last one

Step-by-step explanation:

Answer:

$10.10

Step-by-step explanation:

Answer:

$10.10

Step-by-step explanation:

please rate and mark as brainlest.

The main idea of the essay is her migration process to the United States and their interaction with Americans.

Julia Alvarez's essay "names" refers to her and her family's migration process from her country of origin to the United States.

Once living in the United States, Julia identifies that American citizens do not know how to pronounce their names correctly due to the language difference between the two societies.

This problem is reinforced by these arguments:

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[tex]\\ \rm\rightarrowtail 11y^2+7y+12[/tex]

Un factorable

let's see why?

There are no factors which gives sum +7 and product 132.

Answer:

Answer: 1.4

Step-by-step explanation:

P(Northern pike) = 0.7

P(walleye) = 0.3

If 2 fishes are caught :

Number of northern pike (x) :

X = 0

P(walleye 1 st) * p(walleye 2nd) = (0.3 * 0.3) = 0.09

X = 1

P(walleye 1st)*P(Northern pike 2nd) OR P(Northern pike 1st)*P(Walleye 2nd)

= (0.3 * 0.7) + (0.7 * 0.3)

= 0.21 + 0.21

= 0.42

P(x = 2)

P(northern pike 1st) * P(northen pike 2nd)

0.7 *0.7 = 0.49

X: _ 0 _ 1 __ 2

P(x): ___ 0.09 ___ 0.42 ____ 0.49

Expected value of northern pikes :

(0* 0.09) + (1 * 0.42) + (2 * 0.49)

0 + 0.42 + 0.98

= 1.4

Expected value of the number of walleye is 0.5.

The expected value exists as a long-run average value of random variables. It also demonstrates the probability-weighted average of all possible values. Expected value exists as a generally utilized financial concept.

W = # of walleye 0, 1, 2

P(W) 0. 49, 0. 42, 0. 09

To estimate the expected value of the number of walleye.

E(X) =  number of walleye

E(X) = (0 [tex]\times[/tex] 0.49) + (1 [tex]\times[/tex] 0.42) + (2 [tex]\times[/tex] 0.09)

E(X) = 0 + 0.42 + 0.08

E(X) = 0.5

Therefore, the number of walleye expected value = 0.5.

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Answer:

It is 25.13 (simplified)

Step-by-step explanation:

3.14(pi) x 8 is 25.14

Answer:

To find each length in the new scale drawing, you can multiply each length in the original scale drawing by this scale factor between the two scale drawings. ▫.

fdddkgStep-by-step explanation:

Answer:

760

Step-by-step explanation:

Answer:

760 of course

Step-by-step explanation:

3 is below 5 so its 760

If the last digit was a 5 or higher,it'll be 770

Answer:

p(b|a) =5/7

Step-by-step explanation:

hello :

note : p(b|a) = p(a and b)/p(a)

p(b|a) = 25/35 =5/7

The value of the probability of the event B given A, symbolically P(B|A), when it is known that P(A) = 0.35, P(B) = 0.45 and P(A∩ B) =0.25 is found as: P(B|A) = 5/7

For two events A and B, by chain rule, we have:

[tex]P(A \cap B) = P(B)P(A|B) = P(A)P(B|A)[/tex]

where P(A|B) is probability of occurrence of A given that B already occurred.

We're given that:

Using the chain rule of probability, we get:

[tex]P(A \cap B) = P(A)P(B|A) \\\\P(B|A) = \dfrac{P(A \cap B)}{P(A)} = \dfrac{0.25}{0.35} = \dfrac{5}{7}[/tex]

Thus, the value of the probability of the event B given A, symbolically P(B|A), when it is known that P(A) = 0.35, P(B) = 0.45 and P(A∩ B) =0.25 is found as: P(B|A) = 5/7

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Let's take 1 of x axis from plot (It has three values in y so much useful)

#A

#B

#C

#D

A and D are out of radar .Now we need to find most approx between B and C

Go to 2 now.(Same 3 values)

#B

#C

65 lies between 60 and 70 ,most approximately equal .

Option C is correct

Answer:

C [tex]y=10x+45[/tex]

Step-by-step explanation:

Line of best fit (trendline) : a line through a scatter plot of data points that best expresses the relationship between those points.

All the given options for the line of best fit are linear equations.

Therefore, we can add the line of best fit to the graph (see attached), remembering to have roughly the same number of points above and below the line.

Linear equation:  [tex]y=mx+b[/tex]

(where [tex]m[/tex] is the slope and [tex]b[/tex] is the y-intercept)

From inspection of the line of best fit, we can see that the y-intercept (where x = 0) is approximately 45.  So this suggests that option C is the solution.

We can also see that the line of best fit appears to be the same distance from points (3, 75) and (4, 85).  So we can use the slope formula with these points to give a rough estimate of the slope of the line of best fit:

[tex]\sf{slope=\dfrac{y_2-y_1}{x_2-x_1}}=\dfrac{85-75}{4-3}=10[/tex]

Therefore, this concurs that C is the solution and that the closet approximation to the line of best fit is [tex]y=10x+45[/tex]

Answer:

A: (x-4) squared

B: x+2

C: 9

D: 14

E: 7

F: 2

Step-by-step explanation:

A: This is because x^2 - 8x + 16 factored is (x-4) squared

B: Square root of something squared will remove the square root

C: Minus the variable x and 2 from the right side

D: Factor

E/F: These numbers make the right side become zero

Step-by-step explanation:

1 ounce = 28grams

x grams = 392

x = 392/28

x = 14.oo ounces

Answer:

25 jeans

Step-by-step explanation:

take your total, and divide it by the number of items to get the price of a single item. then, once you have the price of the single item, you take the other price, and divide it by the single price of the jeans, to get the total amount of jeans you can buy.

Answer:

A = bh

A = 45 x 46

A = 2070 inches

Answer:

2070 squre in

Step-by-step explanation:

because the base is 46 and the height is 45 then we just multiply the two together to find the area.

so we solve it and we get

45*46=2070

Answer

One case of sprite costs 3 dollars, All four cases are $12. You can buy 16 cases of sprite with 48 dollars.

Step-by-step explanation:

How to get the cost for 1 case:

You have 4 cases of sprite which all four combined costs $12. You divide 12 by 4 and get 3.

How to get the amount of cases of sprite you can buy with $48:

divide 48 by 3 and you get 16. Why 3? Because 3 is the amount per case and 16 x 3 is 48. Thank me later!

Answer:

It costs $3 per case of Sprite

With 48 dollars, you could buy 16 cases.

Step-by-step explanation:

12/4 = 3    12 dollars divided buy 4 dollars each equals 3 dollars per case

48/3 = 16  48 dollars divided by 3 dollars per case equals 16 cases of sprite

Answer:

25% chance

Step-by-step explanation:

Because a penny has two sides that is 50 percent and a cube 6 sides that's 16 percent. then you subtract 16 from 50 to get a 34 percent chance of probably.

Answer:

Step-by-step explanation:

Easy just divide this into 2 shapes.

The area of a rectangle is lenght Times Width.

2 Rectangles. So the One on the left would be

5X12=60 is the area of the first one.

The Second rectangle is

6X10=60

Both rectangles have the same area.

Now just add up both areas

60+60= 120 square units

SonicIsCoool, if you need more help I'm at your service

:)

Answer:

C. 120 units² or square units

Step-by-step explanation:

View the attached picture

Hope it helps!

Answer:

6 feet

Step-by-step explanation:

8×8+x×x=10×10

x×x=100-64

x=6

Answer: B

Step-by-step explanation:

Reason:

When two lines cross to form an X shape, the opposite pairs of angles are known as vertical angles. They are always congruent to one another.

They do not have to be vertically aligned (meaning the angles could be sitting side by side). Example: In problem 15, angle 1 and angle 3 are vertical angles that are congruent.

Answer:

[tex]\displaystyle y' = \frac{\big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \tan^2 x + 5x \big) + \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( 2 \sec^2 x \tan x + 5 \big)}{ \big( \csc^2 x + 3 \big) \big( \sin^2 x + 6 \big)} + \frac{2 \cot x \csc^2 x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2 \big( \sin^2x + 6 \big)} - \frac{2 \cos x \sin x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big) \big( \sin^2 x + 6 \big)^2}[/tex]

General Formulas and Concepts:
Calculus

Differentiation

Derivative Property [Multiplied Constant]:
[tex]\displaystyle (cu)' = cu'[/tex]

Derivative Property [Addition/Subtraction]:
[tex]\displaystyle (u + v)' = u' + v'[/tex]

Derivative Rule [Basic Power Rule]:

Derivative Rule [Product Rule]:
[tex]\displaystyle (uv)' = u'v + uv'[/tex]

Derivative Rule [Quotient Rule]:
[tex]\displaystyle \bigg( \frac{u}{v} \bigg)' = \frac{vu' - uv'}{v^2}[/tex]

Derivative Rule [Chain Rule]:
[tex]\displaystyle [u(v)]' = u'(v)v'[/tex]

Step-by-step explanation:

*Note:

Since the answering box is way too small for this problem, there will be limited explanation.

Step 1: Define

Identify.

[tex]\displaystyle y = \frac{\cos^2 x - 3\sqrt{x} +6}{\sin^2 x + 6} \times \frac{\tan^2 x + 5x}{\csc^2 x + 3}[/tex]

Step 2: Differentiate

We can differentiate this function with the use of the given derivative rules and properties.

Applying Product Rule:

[tex]\displaystyle y' = \bigg( \frac{\cos^2 x - 3\sqrt{x} + 6}{\sin^2 x + 6} \bigg)' \frac{\tan^2 x + 5x}{\csc^2 x + 3} + \frac{\cos^2 x - 3\sqrt{x} +6}{\sin^2 x + 6} \bigg( \frac{\tan^2 x + 5x}{\csc^2 x + 3} \bigg) '[/tex]

Differentiating the first portion using Quotient Rule:

[tex]\displaystyle \bigg( \frac{\cos^2 x - 3\sqrt{x} + 6}{\sin^2 x + 6} \bigg)' = \frac{\big( \cos^2 x - 3\sqrt{x} + 6 \big)' \big( \sin^2 x + 6 \big) - \big( \sin^2 x + 6 \big)' \big( \cos^2 x - 3\sqrt{x} + 6 \big)}{\big( \sin^2 x + 6 \big)^2}[/tex]

Apply Derivative Rules and Properties, namely the Chain Rule:

[tex]\displaystyle \bigg( \frac{\cos^2 x - 3\sqrt{x} + 6}{\sin^2 x + 6} \bigg)' = \frac{\big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \sin^2 x + 6 \big) - \big( 2 \sin x \cos x \big) \big( \cos^2 x - 3\sqrt{x} + 6 \big)}{\big( \sin^2 x + 6 \big)^2}[/tex]

Differentiating the second portion using Quotient Rule again:

[tex]\displaystyle \bigg( \frac{\tan^2 x + 5x}{\csc^2 x + 3} \bigg) ' = \frac{\big( \tan^2 x + 5x \big)' \big( \csc^2 x + 3 \big) - \big( \csc^2 x + 3 \big)' \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2}[/tex]

Apply Derivative Rules and Properties, namely the Chain Rule again:
[tex]\displaystyle \bigg( \frac{\tan^2 x + 5x}{\csc^2 x + 3} \bigg) ' = \frac{\big( 2 \tan x \sec^2 x + 5 \big) \big( \csc^2 x + 3 \big) - \big( -2 \csc^2 x \cot x \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2}[/tex]

Substitute in derivatives:

[tex]\displaystyle y' = \frac{\big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \sin^2 x + 6 \big) - \big( 2 \sin x \cos x \big) \big( \cos^2 x - 3\sqrt{x} + 6 \big)}{\big( \sin^2 x + 6 \big)^2} \frac{\tan^2 x + 5x}{\csc^2 x + 3} + \frac{\cos^2 x - 3\sqrt{x} +6}{\sin^2 x + 6} \frac{\big( 2 \tan x \sec^2 x + 5 \big) \big( \csc^2 x + 3 \big) - \big( -2 \csc^2 x \cot x \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2}[/tex]

Simplify:

[tex]\displaystyle y' = \frac{\big( \tan^2 x + 5x \big) \bigg[ \big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \sin^2 x + 6 \big) - 2 \sin x \cos x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \bigg]}{\big( \sin^2 x + 6 \big)^2 \big( \csc^2 x + 3 \big)} + \frac{\big( \cos^2 x - 3\sqrt{x} +6 \big) \bigg[ \big( 2 \tan x \sec^2 x + 5 \big) \big( \csc^2 x + 3 \big) + 2 \csc^2 x \cot x \big( \tan^2 x + 5x \big) \bigg] }{\big( \csc^2 x + 3 \big)^2 \big( \sin^2 x + 6 \big)}[/tex]

We can rewrite the differential by factoring and common mathematical properties to obtain our final answer:

[tex]\displaystyle y' = \frac{\big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \tan^2 x + 5x \big) + \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( 2 \sec^2 x \tan x + 5 \big)}{ \big( \csc^2 x + 3 \big) \big( \sin^2 x + 6 \big)} + \frac{2 \cot x \csc^2 x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2 \big( \sin^2x + 6 \big)} - \frac{2 \cos x \sin x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big) \big( \sin^2 x + 6 \big)^2}[/tex]

∴ we have found our derivative.

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Topic: Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

Answer:

The 6-pack contains 0.130 liters more soda.

Hey there!

A car is purchased for $23,000 . Each year it loses 30% of its value. After how many years will the car be worth $6700 or less? (Use the calculator provided if necessary.) Write the smallest possible whole number answer.

Set up the depreciation equation D(t) where t is the number of years in the life of the car:

D(t) = 23,000/(1.3)^t

The problem asks for D(t)<=6800

23,000/(1.3)^t = 6800

Cross multiply:

7300(1.3)^t = 24,000

Divide each side by 6800

1.3^t = 23000/6800

1.3^t = 3.38

Take the natural log of both sides:

LN(1.3^t) = LN(3.38)

Using the natural log identities, we have:

t * LN(1.3) = 1.22

t * 0.2624 = 1.22

Divide each side by 0.2624

t = 4.6494

Rounding this up, we have t = 5

Answer:

it would be 7647

close enough though

Step-by-step explanation:

Answer:

Step-by-step explanation:

Isolate the term of x and y from one side of the equation.

y=4x+22 and y=-7x

y=-7x=4x+22

Solve.

-7x=4x+22

x=2

Substitute.

y=-7x, x=-2

y=-7(-2)

Solve.

Multiply.

y=14

(-2,14)

Therefore, the final answer is (-2,14).

I hope this helps you! Let me know if my answer is wrong or not.