The figure below shows a rectangular court. 74 ft (a) Use the calculator to find the area and perimeter of the court. Make sure to include the correct units. Area: 93 ft Perimeter: (b) The court will have a wood floor. Which measure would be used in finding the amount of wood needed? Perimeter O Area (c) A strip of tape will be placed around the court. Which measure would be used in finding the amount of tape needed? Perimeter O Area ft X ft² Ś ft³ ?

The Figure Below Shows A Rectangular Court. 74 Ft (a) Use The Calculator To Find The Area And Perimeter

Answers

Answer 1

Given a rectangle with sides "a" and "b":

The area of the rectangle is:

[tex]A=ab[/tex]

The perimeter of the rectangle is:

[tex]P=2a+2b[/tex]

Given the sides of the rectangle:

a = 74 ft

b = 93 ft

(a)

The area of the rectangle is:

[tex]\begin{gathered} A=74ft*93ft \\ A=6882ft^2 \end{gathered}[/tex]

The perimeter of the rectangle is:

[tex]\begin{gathered} P=2*74ft+2*93ft \\ P=148ft+186 \\ P=334ft \end{gathered}[/tex]

(b) The wood will cover all the area of the court, then the area must the used.

(c) The tape will be placed around the court, then the perimeter must be used.

Answer:

(a)

(b)

(c) Perimeter


Related Questions

Miss Taylor drove 30 miles in March she drove 9 times as many miles in May as she did in March she drove 2 times as many miles in April as she did in May how many miles did Miss Taylor Drive in April.

Answers

then we use the statement to solve

Miss Taylor drove 30 miles in March

[tex]March=30[/tex]

she drove 9 times as many miles in May as she did in March

[tex]\begin{gathered} May=9\text{March} \\ May=9\times30=270 \end{gathered}[/tex]

she drove 2 times as many miles in April as she did in May

[tex]\begin{gathered} April=2May \\ April=2\times270=540 \end{gathered}[/tex]

Taylor Drove 540 Miles in April

Approximate 14 plus cube root of 81 to the nearest tenth.

15.8
17.9
18.0
18.3

Answers

The Approximation of 14 plus cube root of 81 to the nearest tenth is 18.0

How can the terms be simplified?

The concept that will be used to solve this is finding cube root of 81 which same thing as [tex]81^{\frac{1}{3} }[/tex].

Firstly we will need to find the  cube root of 81, which can be expressed as this: [tex]\sqrt[3]{81}[/tex]  and this can be calculated as 4.33.

This implies that the cube root of 81 will now be 4.33.

Then we can proceed to the simplification that was asked from the question which is 14 plus cube root of 81 and this can be expressed as ( 14) + (4.33) = 18.33

Then we were told to express in the the nearest tenth which is 18.0

Therefore, the third option is correct.

Read more about Approximation at:

https://brainly.com/question/24318076

#SPJ1

I need help for problem number 9. On the right side of the paper.

Answers

Constant of variation ( k ):

• y = 2/3

,

• x = 1/4

[tex]k=\frac{y}{x}=\frac{\frac{2}{3}}{\frac{1}{4}}=\frac{8}{3}[/tex]

k = 8/3

Based on k we can find the value of y when x =3/4 as follows:

[tex]\begin{gathered} k=\frac{y}{x} \\ y=k\cdot x \\ y=\frac{8}{3}\cdot\frac{3}{4}=2 \end{gathered}[/tex]

Answer:

• k = 8/3

,

• When ,x, = ,3/4,,, y = 2

Coronado co. sells product p-14 at a price of $52 a unit. the per unit cost data are direct materials $16, direct labour $12, and overhead $12 (75% variable) Coronado has no excess capacity to accept a special order for 38,700 units at a discount of 25% from the regular price. Selling costs associated with this order would be $3 per unit. Indicate the net income/loss

Answers

The net loss from accepting the special order at a discount of 25% from the regular price, without the existence of excess capacity is $38,700.

How is the net loss determined?

Since Coronado Co. lacks the excess capacity for special orders, it implies that it will incur fixed costs per unit of the special order in addition to the variable costs.

Therefore, the company will incur a per unit cost of $40 ($16 + $12 + $9 + $3) while generating a revenue of $39 per unit.

This results in a loss of $1 per unit.

Selling price per unit = $52

Unit Costs:

Direct Materials = $16

Direct Labor = $12

Variable Overhead = $9 (75% of $12)

Total variable cost per unit = $37

Fixed Overhead = $3 (25% of $12)

Special order price per unit = $39 ($52 x 1 - 75%)

Contribution margin per unit = $2 ($39 - $37)

Total contribution margin = $77,400 ($2 x 38,700)

Fixed Overhead without excess capacity = $116,100 ($3 x 38,700)

Net loss = $38,700 ($77,400 - $116,100)

Thus, without excess capacity, it is inadvisable for Coronado to accept the special order at a total loss of $38,700.

Learn more about accepting special orders at https://brainly.com/question/28124882

#SPJ1

What is the image point of (1,−3) after a translation right 2 units and up 2 units?

Answers

For this problem we have the following point given:

[tex]P=(1,-3)[/tex]

And we want to determine the image point after a translation of 2 units to the right and upward. So then we just need to do the following:

[tex]I=(1+2,-3+2)[/tex]

And after do the math we got:

[tex]I=(3,-1)[/tex]

And the final answer for this case would be I=(3,-1)

a blu ray player costs $80.99 in the store. what would your total cost be if the sales tax is 5.5%

Answers

ANSWER:

$ 85.44

STEP-BY-STEP EXPLANATION:

We have the value after tax, we must calculate the sum between the original value and the value equivalent to the established percentage, therefore, we calculate it like this:

[tex]\begin{gathered} p=80.99+80.99\cdot\frac{5.5}{100} \\ p=80.99+4.45 \\ p=\text{ \$85.44} \end{gathered}[/tex]

The final price is $ 85.44

Which statement is true about the relation shown on the graph below?

Answers

We know that a function has a unique value of y for each value in x so the correct statement is:

c. it is not a function because there are multiple y values for a given x value

The side of a square lot is (5×-3) meters. How many meters of fencing materials are needed to enclose the square lot?

Answers

The length of the fencing will be the perimeter of the given square with side (5x - 3) thus (20x - 12) meters will be the fencing length.

What is a square?

A square is a geometrical figure in which we have four sides each side must be equal and the angle between two adjacent sides must be 90 degrees.

As per the given,

Side of square = 5x - 3

The fencing around the square will cover the complete perimeter of the square.

Since the perimeter of the square = 4 × side

Therefore,

Length of fencing = 4 × (5x - 3)

Length of fencing = 20x - 12

Hence "The length of the fencing will be the perimeter of the given square with side (5x - 3) thus (20x - 12) meters will be the fencing length".

For more about a square,

https://brainly.com/question/2189895

#SPJ1

Find the median and mean of the data set below: 3, 8, 44, 50, 12, 44, 14 Median Mean =

Answers

the median is 25, because:

[tex]=\frac{3+8+44+50+12+44+14}{7}=\frac{175}{7}=25[/tex]

the mean value is :

[tex]14[/tex]

Which expression would be easier to simplify if you used the associativeproperty to change the grouping?

Answers

In option A, if expression is simplify with out using associative property then addition of 4/9 and -2/9 is easy, as compare to addition 6 and 4/9. So no need to apply associateive property to option A.

In option B, 60 and 40 can be easily add as compare to 40 and -27 so this expression do not need to apply associative property.

In option C, the expression is easier to simplify if 5/2 and -1/2 is added, which is possible if associative is apply to the expression.

[tex]\begin{gathered} (2+\frac{5}{2})+(-\frac{1}{2})=2+(\frac{5}{2}-\frac{1}{2}) \\ =2+(\frac{5-1}{2}) \\ =2+2 \\ =4 \end{gathered}[/tex]

Thus option C use associative property to make the simplification easier.

Answer: Option C.

Correctz is jointly proportional to x and y. If z = 115 when x = 8 and y = 3, find z when x = 5 and y = 2. (Round off your answer to the nearest hundredth.)

Answers

When we have a number that is jointly proportional to two other numebrs, the formula is:

[tex]a=kcb[/tex]

This means "a is jointly proportional to c and b with a factor of k"

Then, we need to find the factor k.

In this case z is jointly proportional to x² and y³

This is:

[tex]z=kx^2y^3[/tex]

Then, we know that z = 115 when x = 8 and y = 3. We can write:

[tex]115=k\cdot8^2\cdot3^3[/tex]

And solve:

[tex]\begin{gathered} 115=k\cdot64\cdot27 \\ 115=k\cdot1728 \\ k=\frac{115}{1728} \end{gathered}[/tex]

NOw we can use k to find the value of z when x = 5 and y = 2

[tex]z=\frac{115}{1728}\cdot5^2\cdot2^3=\frac{115}{1728}\cdot25\cdot8=\frac{2875}{216}\approx13.31[/tex]

To the nearest hundreth, the value of z when x = 5 and y = 2 is 13.31

How to find postulate

Answers

Note that if plane N and plane M intersects each other in two points (say A and B) it follows that they intersects each other in the line that contains A and B. So they cannot intersect exactly in only two points. Postulate number 10

8.
What is the measure of angle x in the figure?
40°
A 69°
B 71°
C 109°
D 111°

Answers

Answer:

C 109

Step-by-step explanation:

First add all the known angles inside the triangle first to get 109°

Then since all angles in a triangle add to 180°

you take away 109 from 180 so

180-109 which equals 71

Then since all angles on a straight line add up to 180°

you take 71 from 180 so

180-71 = 109

so x = 109°

Please help meSolve using A=PertThe half life gets me each time.

Answers

[tex]\begin{gathered} Given \\ r=0.028 \\ \end{gathered}[/tex]

In the lab, Deandre has two solutions that contain alcohol and is mixing them with each other. Solution A is 10% alcohol and Solution B is 60% alcohol. He uses200 milliliters of Solution A. How many milliliters of Solution B does he use, if the resulting mixture is a 40% alcohol solution?

Answers

The percentage of alcohol of a solution i is given by the quotient:

[tex]p_i=\frac{v_i}{V_i},_{}[/tex]

where v_i is the volume of alcohol in the solution i and V_i is the volume of the solution i.

From the statement of the problem we know that:

1) Solution A has 10% of alcohol, i.e.

[tex]p_A=\frac{v_A_{}}{V_A}=0.1.\Rightarrow v_A=0.1\cdot V_A.[/tex]

2) Solution B has 60% of alcohol, i.e.

[tex]p_B=\frac{v_B}{V_B}=0.6\Rightarrow v_B=0.6\cdot V_B.[/tex]

3) The volume of solution A is V_A = 200ml.

4) The resulting mixture must have a percentage of 40% of alcohol, so we have that:

[tex]p_M=\frac{v_M}{V_M}=0.4.[/tex]

5) The volume of the mixture v_M is equal to the sum of the volumes of alcohol in each solution:

[tex]v_M=v_A+v_{B\text{.}}_{}[/tex]

6) The volume of the mixtureVv_M is equal to the sum of the volumes of each solution:

[tex]V_M=V_A+V_B\text{.}[/tex]

7) Replacing 5) and 6) in 4) we have:

[tex]\frac{v_A+v_B}{V_A+V_B_{}}=0.4_{}\text{.}[/tex]

8) Replacing 1) and 2) in 7) we have:

[tex]\frac{0.1\cdot V_B+0.6\cdot V_B}{V_A+V_B}=0.4_{}\text{.}[/tex]

9) Replacing 3) in 8) we have:

[tex]\frac{0.1\cdot200ml_{}+0.6\cdot V_B}{200ml_{}+V_B}=0.4_{}\text{.}[/tex]

Now we solve the last equation for V_B:

[tex]\begin{gathered} \frac{0.1\cdot200ml+0.6\cdot V_B}{200ml_{}+V_B}=0.4_{}, \\ \frac{20ml+0.6\cdot V_B}{200ml_{}+V_B}=0.4_{}, \\ 20ml+0.6\cdot V_B=0.4_{}\cdot(200ml+V_B), \\ 20ml+0.6\cdot V_B=80ml+0.4\cdot V_B, \\ 0.6\cdot V_B-0.4\cdot V_B=80ml-20ml, \\ 0.2\cdot V_B=60ml, \\ V_B=\frac{60}{0.2}\cdot ml=300ml. \end{gathered}[/tex]

We must use 300ml of Solution B to have a 40% alcohol solution as the resulting mixture.

Answer: 300ml of Solution B.

May I please get help with this. I need help with finding the original and final points on the figure and also finding out where I should put my reflection?

Answers

Answer:

Step-by-step explanation:

The rule for a reflection over the y-axis is represented by the following equation:

[tex](x,y)\rightarrow(-x,y)_{}[/tex]

Therefore, for the given figure and given point:

15. (09.03) Jim picked a card from a standard deck. What is the probability that Ilm picked a heart or an ace? (1 point) OI 52 O 2 52 O 16 52 O 17 52

Answers

The probability of picking a heart or an ace is 17/52

Here, we want to get the probability

The number of cards in a standard deck is 52 cards

Now, we need to know the number of hearts and the number of ace

There are 13 hearts, and 4 aces

The probability of picking a heart is;

[tex]\frac{13}{52}[/tex]

The probability of picking an ace is;

[tex]\frac{4}{52}[/tex]

The probability of picking an ace or a heart is the sum of both which is;

[tex]\frac{4}{52}+\frac{13}{52}\text{ = }\frac{17}{52}[/tex]

Solve the following system of equations using the elimination method. Give the final answer in (x,y) form.

Answers

Anisha used the substitution method to solve the system of equations.

She is missing the value of y.

To find it we plut the value of x in the first equation, then:

[tex]y=4-5=-1[/tex]

Therefore the solution is (4,-1)

A company needs to take 10 sample sensor readings if the sensor collects data at 1/3 of a sample per second how long will it take the company to take all 10 samples

Answers

Given:

Sample space = 10

Rate = 1/3 per second

which of the following is an integer ) 58/81) π) -11) 27.4444....

Answers

-11 is an integer number

Could you help me with this problem?There are 7 acts in a talent show.A comedian, a guitarist, a magician, a pianist, a singer, a violinist, and a whistler.A talent show host randomly schedules the 7 acts.Compute the probability of each of the following events.Event A: The magician is first, the comedian is second, and the whistler is third.Event B: The first three acts are the guitarist, the pianist, and the singer, in any order.Write your answers as fractions in simplest form.

Answers

EXPLANATION

For the event B, the order of the first 3 acts doesn't matter.

So, the number of acts taken from the seven acts when the order doesn't matter is calculated using combinations.

[tex]C(m,n)=\frac{m!}{n!(m-n)!}[/tex][tex]C(7,3)=\frac{7!}{3!(7-3)!}=\frac{7!}{3!4!}[/tex]

Computing the factorials:

[tex]C(7,3)=\frac{5040}{6\cdot24}=\frac{5040}{144}=35[/tex]

Hence, the number of ways the three acts could be given are 1:C(7,3)

Therefore, the probability of the event B is:

[tex]P(B)=\frac{1}{35}[/tex]

For the event A, the order matters, so the difference between combinations and permutations is ordering. When the order matters we need to use permutations.

The number of ways in which four acts can be scheculed when the order matters is:

[tex]P(m,n)=\frac{m!}{(m-n)!}[/tex][tex]P(m,n)=\frac{7!}{(7-3)!}=\frac{5040}{24}=210[/tex]

The number of ways the magician is first, the comedian is second and the whistler is third are 1:P(7,4)

Therefore, the probability of the event A is.

[tex]P(A)=\frac{1}{210}[/tex]

$75 dinner, 6.25% tax, 18% tip please show work.You have to find the total cost

Answers

According the the information given in the exercise, you know that the cost of the dinner was:

[tex]d=_{}$75$[/tex]

Where "d" is the cost of the dinner in dollars.

Convert from percentages to decimal numbers by dividing them by 100:

1. 6.25% tax in decimal for:

[tex]\begin{gathered} tax=\frac{6.25}{100} \\ tax=0.0625 \\ \end{gathered}[/tex]

2. 18% tip in decimal form:

[tex]\begin{gathered} tip=\frac{18}{100} \\ \\ tip=0.18 \end{gathered}[/tex]

To find the amount in dollars of the tax and the the amount in dollars of the tip, multiply "d" by the decimals found above.

Knowing the above, let be "t" the total cost in dollars.

This is:

[tex]\begin{gathered} t=d+0.0625d+0.18d \\ t=75+(0.0625)(75)+(0.18)(75) \\ t=93.1875 \end{gathered}[/tex]

Therefore the answer is: The total cost is $93.1875

5. Helen, Riley, and Derrick are on a running team. Helen ran 15 1/4 kilometers last week. Riley ran 4 1/12 less kilometers than Helen, and Derrick ran 7 3/8 more kilometers than Riley. If their goal is to run 60 kilometers in total, how much further do they need to run to meet their goal? I

Answers

Given in the scenario:

a.) Helen ran 15 1/4 kilometers last week.

b.) Riley ran 4 1/12 less kilometers than Helen.

c.) Derrick ran 7 3/8 more kilometers than Riley.

d.) Their goal is to run 60 kilometers in total.

To be able to determine how much further do they need to run to get 60 kilometers in total, we must first determine how many kilometers did Riley and Derrick run.

We get,

A.)

[tex]\text{Riley: }4\frac{1}{12}\text{ less kilometers than Helen}[/tex][tex]\text{ = 15 }\frac{1}{4}\text{ - 4 }\frac{1}{12}[/tex]

Recall: To be able to subtract mixed numbers, you must first convert them into an improper fraction with a common denominator. The LCM of the two denominators must be their denominator when converted.

The LCM of 4 and 12 is 12. We get,

[tex]\text{ 15 }\frac{1}{4}\text{ = }\frac{1\text{ + (4 x 15)}}{4}\text{ = }\frac{1\text{ + 60}}{4}\text{ = }\frac{61}{4}\text{ = }\frac{(61)(3)}{12}\text{ = }\frac{183}{12}[/tex][tex]4\text{ }\frac{1}{12}\text{ = }\frac{1\text{ + (4 x 12)}}{12}\text{ = }\frac{1\text{ + 48}}{12}\text{ = }\frac{49}{12}[/tex]

Let's now proceed with the subtraction,

[tex]15\frac{1}{4}-4\frac{1}{12}=\frac{183}{12}\text{ - }\frac{49}{12}\text{ = }\frac{183\text{ - 49}}{12}\text{ = }\frac{134}{12}\text{ = }\frac{\frac{134}{2}}{\frac{12}{2}}\text{ = }\frac{67}{6}\text{ or 11}\frac{1}{6}[/tex]

Conclusion: Riley ran 11 1/6 kilometers.

B.)

[tex]\text{Derrick: }7\frac{3}{8}\text{ more kilometers than Riley}[/tex][tex]\text{ = 11}\frac{1}{6}\text{ + 7}\frac{3}{8}[/tex]

Recall: To be able to add mixed numbers, you must first convert them into an improper fraction with a common denominator. The LCM of the two denominators must be their denominator when converted.

The LCM of 6 and 8 is 24. We get,

[tex]11\frac{1}{6}\text{ = }\frac{1\text{ + (11 x 6)}}{6}\text{ = }\frac{1\text{ + 66}}{6}\text{ = }\frac{67}{6}\text{ = }\frac{(67)(4)}{24}\text{ = }\frac{268}{24}[/tex][tex]7\frac{3}{8}\text{ = }\frac{3\text{ + (7 x 8)}}{8}=\frac{3\text{ + 56}}{8}=\frac{59}{8}=\frac{(59)(3)}{24}=\frac{177}{24}[/tex]

Let's now proceed with the addition,

[tex]11\frac{1}{6}\text{ + 7}\frac{3}{8}\text{ = }\frac{268}{24}\text{ + }\frac{177}{24}\text{ = }\frac{268\text{ + 177}}{24}\text{ = }\frac{445}{24}\text{ or 18}\frac{13}{24}[/tex]

Conclusion: Derrick ran 18 13/24 kilometers.

C.) To be able to determine how much further do they need to run to get 60 kilometers in total, we subtract 60 by the sum of distance the three people ran.

We get,

[tex]\text{ 60 - (15 }\frac{1}{4}\text{ + 11}\frac{1}{6}\text{ + 18}\frac{13}{24})[/tex]

The same process that we did, convert all numbers into similar fractions.

The LCM of 4, 6 and 24 is 24. We get,

[tex]15\frac{1}{4}\text{ = }\frac{1\text{ + }(15\text{ x 4)}}{4}\text{ = }\frac{1\text{ + 60}}{4}\text{ = }\frac{61}{4}\text{ = }\frac{(61)(6)}{24}\text{ = }\frac{366}{24}[/tex][tex]11\frac{1}{6}\text{ = }\frac{1\text{ + (11 x 6)}}{6}\text{ = }\frac{1\text{ + 66}}{6}\text{ = }\frac{67}{6}\text{ = }\frac{(67)(4)}{24}\text{ = }\frac{268}{24}[/tex][tex]\text{ 18}\frac{13}{24}=\text{ }\frac{13+(18\text{ x 24)}}{24}\text{ = }\frac{13\text{ + 432}}{24}\text{ = }\frac{445}{24}[/tex][tex]60\text{ = }\frac{60\text{ x 24 }}{24}\text{ = }\frac{1440}{24}[/tex]

Let's proceed with the operation,

[tex]\text{ 60 - (15 }\frac{1}{4}\text{ + 11}\frac{1}{6}\text{ + 18}\frac{13}{24})\text{ = }\frac{1440}{24}-(\frac{366}{24}\text{ + }\frac{268}{24}\text{ + }\frac{445}{24})[/tex][tex]\text{ }\frac{1440\text{ - (366 + 268 + 445)}}{24}\text{ = }\frac{1440\text{ - 1079}}{24}[/tex][tex]\text{ = }\frac{361}{24}[/tex]

Therefore, they need to run a total of 361/24 kilometers to be able to meet their goal.

Solve the inequality. Express your answer using set notation or interval notation. Graph the solution set.

Answers

Answer:

(D) {xIx ≥ 5} or [5, ∞)

Explanation:

Given inequality: 5x - 11 ≥ 9 + x

By collecting the like terms, we have

5x - x ≥ 9 + 11

4x ≥ 20

Divide bothsides by 4

4x/4 ≥ 20/4

x ≥ 5

In set notation, we have {5, ∞}

The graph of the solution set is

Write the trig equation needed to solve for X. Then solve for X. Round answers to the nearest tenth.

Answers

In order to solve for x, we need to use the tangent relation of the angle 48°.

The tangent relation is equal to the length of the opposite leg to the angle over the length of the adjacent leg to the angle.

So we have:

[tex]\begin{gathered} \tan (48\degree)=\frac{x}{17} \\ 1.1106=\frac{x}{17} \\ x=1.1106\cdot17 \\ x=18.88 \end{gathered}[/tex]

Rounding to the nearest tenth, we have x = 18.9.

Determine the solution to the system of equations using substitution. (1 pt)2:+ y=6y = -6(2,6)(2,-6)(4, -2)(-2,4)

Answers

2x + y = 6 (1)

y = x - 6 (2)

Substituting y in equation (1)

2x + x - 6 = 6

3x - 6 = 6 Isolating 3x

3x = 6 + 6

3x = 12 Isolating x

x = 12/3 = 4

If x is 4 , then y is equal to -2 ( from equation (2) y)

Which answer choice shows 3.002 written in expanded form?A) 3 + 0.2B) 3 + 0.02C) 3 + 0.002D) 3+ 0.0002

Answers

SOLUTION

We want to know which answer choice shows 3.002 written in expanded form

To do this let us subtract 3.002 from 3, we have

We got 0.002

So the expanded form is

[tex]3+0.002[/tex]

Hence the correct answer is option C

Problem 14.f(2)(a) Determine the equations of the perpendicular bisectors througheach side of the triangle.C(4,6)B(7,3)A(2,2)I

Answers

The product of the slopes of the perpendicular lines is -1, which means if the slope of one of them is m, then the slope of the perpendicular line is -1/m

In triangle ABC

The perpendicular bisector of the side BC is drawn from the opposite vertex A

Then to find it find the slope of BC and reciprocal it and change its sign to get its slope and find the midpoint of BC to use it in the equation of the perpendicular bisector

Since B = (7, 3) and C = (4, 6)

Let us find the slope of BC, using the rule of the slope

[tex]m=\frac{y2-y1}{x2-x1}[/tex]

Let (x1, y1) = (7, 3) and (x2, y2) = (4, 6)

[tex]\begin{gathered} m_{BC}=\frac{6-3}{4-7} \\ m_{BC}=\frac{3}{-3} \\ m_{BC}=-1 \end{gathered}[/tex]

Now to find the slope of the perpendicular line to BC reciprocal it and change its sign

Since the reciprocal of 1 is 1 and the opposite of negative is positive, then

Then the slope of the perpendicular line is 1

Now, let us find the mid-point of BC

The rule of the midpoint is

[tex]M=(\frac{x1+x2}{2},\frac{y1+y2}{2})[/tex]

Then the mid-point of BC is

[tex]\begin{gathered} M_{BC}=(\frac{7+4}{2},\frac{3+6}{2}) \\ M_{BC}=(\frac{11}{2},\frac{9}{2}) \\ M_{BC}=(5.5,4.5) \end{gathered}[/tex]

Now we can form the equation of the perpendicular bisector of BC using its slope 1 and the point (5.5, 4.5)

The form of the equation using a point and a slope is

[tex]y-y1=m(x-x1)[/tex]

m is the slope and (x1, y1) is a point on the line

Since m = 1 and (x1, y1) = (5.5, 4.5), then

[tex]\begin{gathered} m=1,x1=5.5,y1=4.5 \\ y-4.5=1(x-5.5) \\ y-4.5=x-5.5 \end{gathered}[/tex]

Add 4.5 to both sides

[tex]\begin{gathered} y-4.5+4.5=x-5.5+4.5 \\ y=x-1 \end{gathered}[/tex]

The equation of the perpendicular bisector of BC is

[tex]y=x-1[/tex]

We will do the same to AB and AC

Which of the following is a factor of the polynomial Step By Step Explanation Please

Answers

Use the quadratic formula.

[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]

Where a = 3, b = -31, and c = -60.

[tex]x=\frac{-(-31)\pm\sqrt[]{(-31)^2-4(3)(-60)}}{2(3)}[/tex]

Solve to find both solutions.

[tex]x=\frac{31\pm\sqrt[]{961+720}}{6}=\frac{31\pm\sqrt[]{1681}}{6}=\frac{31\pm41}{6}[/tex]

Rewrite the expression as two.

[tex]\begin{gathered} x_1=\frac{31+41}{6}=\frac{72}{6}=12 \\ x_2=\frac{31-41}{6}=\frac{-10}{6}=-\frac{5}{3} \end{gathered}[/tex]

Once we have the solutions, we express them as factors. To do that, we have to move the constant to the right side of each equation.

[tex]\begin{gathered} x=12\to(x-12) \\ x=-\frac{5}{3}\to(3x+5)_{} \end{gathered}[/tex]

As can observe, the factor of the polynomial is (x-12).

Therefore, the answer is d.

Question is stated in picture. The figure is a triangular piece of cloth

Answers

Answer:

Alternative D - 8 sin(35°)

Step-by-step explanation:

Sin(x) is defined as:

[tex]\begin{gathered} \sin (x)=\frac{\text{Opposite side}}{Hypotenuse\text{ }} \\ \end{gathered}[/tex]

In this exercise,

BC is the opposite side to 35°

AC is the hypotenuse and measures 8 in

Then:

[tex]\begin{gathered} \sin (35\degree)=\frac{BC}{8} \\ \sin (35\degree)\cdot8=BC \\ BC=8\sin (35\degree) \end{gathered}[/tex]

Other Questions
The pull model is also called ________ which means the production process begins with a ________ so that a company only makes the products and quantities that their customers actually want. what is a characteristic of a monopoly's demand curve? it is the same as the marginal revenue curve it is the same as the market demand curve it is the same as the supply curve it is more elastic than the demand curve of a competitive firm g a city has two water towers. one tower holds 8.4 x 103 gallons of water and the other tower holds 9.5 x 104 gallons of water. what is the combined water capacity of the two towers in scientific notation? The monster of kings island paying particular attention to how the author uses language to create a vivid picture What is the missing coefficient of the x-term of the product (x5)^2 after it has been simplified?25101025 What type of organism could have an exoskeleton?A. WormB. InvertebrateC. HumanD. Vertebrate I need help finding the exact perimeter. Special right triangles. In the rhombus m What is troubling about the circumstance when a coil is stationary and a magnet moves as compres to when a magnet is stationary and the coil moves? Whats the correct answer answer asap for brainlist tech a says the best way to ensure the torque converter is engaged fully into the pump is to strike the rear of the torque converter with a a hammer in three places. tech b says that the torque converter requires an alignment tool when installing it in the transmission. who is right? Why does Robert Kennedy bring up John's assassination during his speech about MLK's death? how did the french and indian war in 1763 contribute to the weiting of the declartion of independence a. colonist were angry that they were being taxed by britain as a result of the warb. certain colonies were given privileges by kind george during the warc. colonist were angry that only certain places were being defended by british soildersd. king george did not send enough support to help colonists when fighting the war Why are art critiques important? What benefit can we gain from them? 5. There are 9.75 ounces of Cinnamon Toast Crunch in a bowl. Additional cereal ispoured into the bowl at a rate of 1.5 ounces per second. How many ounces are inthe bowl after 3 seconds? At the airport, the new runway will be parallel to a nearby highway. The equation that represents the highway is 6y = 8x - 11. Which equation could represent the new runway? A. 9y = 12x + 5B. 9x = 12y + 8C. 12y = -9x + 2 D. 12x = -9y + 4 Describe the transformation from the graph of f to the graph of h. Write an equation that represents h in terms of x. Look at image for example. Lets do problem number 11 Solve the inequality X - (5 - 3x) = 2x - 1 Soue se compound inequality and give your answer in intentel notation- 10 AND-80-72-1 Which does not increase the price of certain goods? question 7 options: tariffs sales taxes excise taxes property taxes