The histogram shows data collected about the number of passengers using city bus transportation at a specific time of day.

A histogram titled City Bus Transportation. The x-axis is labeled Number Of Passengers and has intervals of 1 to 10, 11 to 20, 21 to 30, 31 to 40, and 41 to 50. The y-axis is labeled Frequency and starts at 0 with tick marks every 1 units up to 9. There is a shaded bar for 1 to 10 that stops at 3, for 11 to 20 that stops at 3, for 21 to 30 that stops at 7, for 31 to 40 that stops at 4, and for 41 to 50 that stops at 3.

Which of the following data sets best represents what is displayed in the histogram?

A: (4, 5, 7, 8, 10, 12, 13, 15, 18, 21, 23, 28, 32, 34, 36, 40, 41, 41, 42, 42)
B: (4, 7, 10, 13, 14, 19, 22, 24, 26, 27, 29, 31, 33, 35, 36, 38, 40, 42, 42, 42)
C: (4, 5, 7, 8, 12, 13, 15, 18, 19, 21, 24, 25, 26, 28, 29, 30, 32, 33, 35, 42)
D: (4, 6, 9, 12, 16, 18, 21, 24, 25, 26, 28, 29, 30, 32, 35, 36, 38, 41, 41, 42)

Answer:

Step-by-step explanation:

the answer is 5/21

Answer: 5/21, I multiplied the two fractions on a piece of paper then simplified the answer.

The equilibrium point is (1600, 80) in the form (x, y).

We need to find the point where the demand function D(x) is equal to the supply function S(x).

The functions are given as follows:
D(x) = 3200/√x
S(x) = 2x√

To find the equilibrium point, we need to set D(x) equal to S(x):

3200/√x = 2x√

Now, let's solve for x:

1. Isolate x by multiplying both sides by √x:
3200 = 2x√ * √x

2. Simplify by squaring both sides:
(3200)^2 = (2x√)^2

3. Perform the squaring:
10,240,000 = 4x^2

4. Divide both sides by 4 to isolate x^2:
2,560,000 = x^2

5. Take the square root of both sides:
x = √2,560,000
x = 1600

Now that we have x, we can find the corresponding price y by plugging x into either D(x) or S(x):

y = D(1600) = 3200/√1600
y = 3200/40
y = 80

So, the equilibrium point is (1600, 80) in the form (x, y).

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y(x) = y_c(x) + y_p(x)

To find the general solution of the given differential equations using the variation of parameters method:

(i) y" - 4y' + 3y = e^x

The complementary solution of the homogeneous equation is found by solving the characteristic equation:

r^2 - 4r + 3 = 0

(r - 1)(r - 3) = 0

The roots are r = 1 and r = 3, so the complementary solution is:

y_c(x) = C1e^x + C2e^(3x)

Now, we need to find the particular solution using the variation of parameters method. Assume the particular solution has the form:

y_p(x) = u1(x)e^x + u2(x)e^(3x)

where u1(x) and u2(x) are functions to be determined.

Differentiating y_p(x), we have:

y_p'(x) = u1'(x)e^x + u1(x)e^x + u2'(x)e^(3x) + 3u2(x)e^(3x)

y_p''(x) = u1''(x)e^x + 2u1'(x)e^x + u1(x)e^x + u2''(x)e^(3x) + 6u2'(x)e^(3x) + 9u2(x)e^(3x)

Substituting y_p(x), y_p'(x), and y_p''(x) back into the original equation, we get:

(u1''(x)e^x + 2u1'(x)e^x + u1(x)e^x + u2''(x)e^(3x) + 6u2'(x)e^(3x) + 9u2(x)e^(3x))

4(u1'(x)e^x + u1(x)e^x + u2'(x)e^(3x) + 3u2(x)e^(3x))

3(u1(x)e^x + u2(x)e^(3x)) = e^x

Now, we equate the coefficients of like terms on both sides of the equation:

e^x terms:

u1''(x) - 2u1'(x) + u1(x) = 1

e^(3x) terms:

u2''(x) + 6u2'(x) + 9u2(x) = 0

Solve these two differential equations to find u1(x) and u2(x). Once you have u1(x) and u2(x), substitute them back into the particular solution:

y_p(x) = u1(x)e^x + u2(x)e^(3x)

Finally, the general solution is given by:

y(x) = y_c(x) + y_p(x)

(ii) y" - 2y' + y = e^x / (x^2 + 1)

The process is similar to the first equation, but with a slight difference in the particular solution. Assume the particular solution has the form:

y_p(x) = u1(x)e^x + u2(x)e^xln(x^2 + 1)

Differentiate y_p(x) and substitute it back into the original equation to find u1(x) and u2(x). Then the general solution is given by:

y(x) = y_c(x) + y_p(x)

Note: Solving the differential equations for u1(x) and u2(x) in both cases can be quite involved, and the exact form of the particular solution may vary depending on the specific calculations.

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The price that Maura sell each scarf would be =$33. Maura sells each scarf for $33. That is option A.

To calculate the amount of money that Maura spends on each scarf the following is carried out.

The amount of money that she spends on the scarf material = $5.50

The percentage selling price of each scarf = 600% of $5.50

That is ;

= 600/100 × 5.50/1

= 3300/100

= $33.

Therefore, each price that is sold by Maura would probably cost a total of $33.

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After solving by elimination, the value of x and y are -3 and 6 respectively

Elimination refers to the process in which the variables are calculated by eliminating one of the variables.

Given the equations are:

5x + 2y = -3

3x + 3y = 9

For solving by elimination, we multiply the first equation by 3 and the second by 2.

15x + 6y = -9

6x + 6y = 18

Subtract both equations and we get

9x = -27

x = -3

Put the value in one of the given equation

5 (-3) + 2y = -3

-15 + 2y = -3

2y = -3 + 15

2y = 12

y = 6

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The coordinates of the critical point is none and the coordinates of endpoints for the function f(t) = 5t^3 + 5t on the given interval (-2, 2) are (-2, -70) and (2, 70) and the function is increasing in interval (-2,2).

To use the first derivative test to locate the relative extrema of the function f(t) = 5t^3 + 5t with domain (-2, 2), we first need to find the derivative of the function:

f'(t) = 15t^2 + 5

Next, we need to find the critical points by setting the derivative equal to zero and solving for t:

15t^2 + 5 = 0
t^2 = -1/3
t = ± sqrt(-1/3)

Since the square root of a negative number is not a real number, there are no critical points in the given domain (-2, 2).

Therefore, we need to check the endpoints of the domain to determine if they are relative extrema. Plugging in t = -2 and t = 2 into the original function, we get:

f(-2) = -70
f(2) = 70

So the endpoint at t = -2 is a relative minimum and the endpoint at t = 2 is a relative maximum.

To determine the intervals of increase and decrease, we can use the first derivative test. Since the derivative f'(t) = 15t^2 + 5 is positive for all values of t in the domain, the function is increasing on the entire interval (-2, 2).

Therefore, the coordinates of the critical points and endpoints for the function f(t) = 5t^3 + 5t on the given interval (-2, 2) are:

- No critical points in the given domain
- Endpoint at t = -2 is a relative minimum, coordinates: (-2, -70)
- Endpoint at t = 2 is a relative maximum, coordinates: (2, 70)
- The function is increasing on the entire interval (-2, 2)

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The expression that will give the correct lateral surface area of the rectangular prism = (14.5 + 14.5 + 7 + 7)(8.6)

The lateral surface of an object is for all the sides of the object, excluding its base and top (when they exist). The lateral surface area is defined as the area of the lateral surface. This is different from the total surface area, which is the lateral surface area together with the areas of the base and top.

The lateral surface area is given by the formula here as:

(LSA) = 2(l + w)h

Given the following:

l = 14.5

w = 7

h = 8.6

Thus:

Lateral surface area of the prism = 2(l + w)h = 2(14.5 + 7)8.6

Lateral surface area of the prism = (14.5 + 14.5 + 7 + 7)(8.6)

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Use the line segment to determine the average rate of change of the function f(x) on the interval. The function y=f(x) is graphed below. Plot a line segment.:

Step-by-step explanation:

The probability that a randomly selected bolt will have a diameter greater than 0.60 cm is approximately 0.6915.

We know that the diameters of bolts produced on a certain machine are normally distributed with a mean (μ) of 0.62 cm and a standard deviation (σ) of 0.04 cm.

Let X be the diameter of a bolt. Then, X ~ N(μ, σ) = N(0.62, 0.04).

We need to find the probability that a randomly selected bolt will have a diameter greater than 0.60 cm.

P(X > 0.60) = P((X - μ)/σ > (0.60 - 0.62)/0.04) (standardizing X)

= P(Z > -0.5) (where Z ~ N(0,1) is the standard normal distribution)

Using the standard normal distribution table or calculator, we can find that P(Z > -0.5) is approximately 0.6915.

Therefore, the probability that a randomly selected bolt will have a diameter greater than 0.60 cm is approximately 0.6915.

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Answer:

a. The point estimate of the population proportion is calculated as the proportion of employees who failed the test in the sample , which is 20/430. Thus, the point estimate is 4.7%.

b. The margin of error for a 95% confidence interval estimate can be calculated using the following formula:

ME = z*sqrt((p*(1-p))/n)

where: ME = margin of error z = z-score for the desired level of confidence (1.96 for 95% confidence) p = point estimate of the population proportion (0.047) n = sample size (430)

Plugging these values into the formula yields:

ME = 1.96*sqrt((0.047*(1-0.047))/430) = 0.038

Rounding this to 3 decimal places gives the margin of error as 0.038.

c. To compute the 95% confidence interval for the population proportion , you start by finding the bounds of the interval:

Lower bound = point estimate - margin of error

Upper bound = point estimate + margin of error

Plugging in the values gives:

Lower bound = 0.047 - 0.038 = 0.009

Upper bound = 0.047 + 0.038 = 0.085

Rounding these values to 3 decimal places, the 95% confidence interval is between 0.009 and 0.085.

d. No, it is not reasonable to conclude that 4% of the employees cannot pass the company policy test, because the 95% confidence interval for the population proportion includes values below 4%. We can only conclude that it is plausible that less than 4% of the employees cannot pass the test, but we cannot reject the possibility that the proportion is actually higher than 4%.

Step-by-step explanation:

We cannot reject the null hypothesis that the proportion of employees who cannot pass the test is equal to 4%.

a. The point estimate of the population proportion is the sample proportion, which is calculated as the number of employees who failed the test divided by the total number of tests conducted:

point estimate of population proportion = 20/430 = 0.0465 or 4.65%

Therefore, the point estimate of the population proportion is 4.65%.

b. To find the margin of error for a 95% confidence interval estimate, we need to first calculate the standard error of the proportion:

standard error of proportion = sqrt[(point estimate of population proportion) * (1 - point estimate of population proportion) / sample size]

standard error of proportion = sqrt[(0.0465) * (1 - 0.0465) / 430] = 0.020

Then, we can find the margin of error using the z-table for a 95% confidence level:

margin of error = z * (standard error of proportion)

For a 95% confidence level, the z-value is 1.96.

margin of error = 1.96 * 0.020 = 0.039

Therefore, the margin of error for a 95% confidence interval estimate is 0.039.

c. To compute the 95% confidence interval for the population proportion, we use the formula:

point estimate of population proportion ± margin of error

Substituting the values we obtained in parts a and b, we get:

95% confidence interval = 0.0465 ± 0.039

95% confidence interval = (0.008, 0.085)

Therefore, the 95% confidence interval for the population proportion is between 0.008 and 0.085.

d. It is not reasonable to conclude that 4% of the employees cannot pass the company policy test because the lower bound of the confidence interval is 0.008, which is significantly lower than 4%. The confidence interval suggests that the true proportion of employees who cannot pass the test could be as low as 0.8%. Additionally, the point estimate of the population proportion is 4.65%, which is higher than the hypothesized 4%. Therefore, we cannot reject the null hypothesis that the proportion of employees who cannot pass the test is equal to 4%.

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There are 55,440 different ways for the coach to select and order the 5 players for penalty kicks.

A soccer team has 11 players on the field at the end of a scoreless game. According to league rules, the coach must select 5 of the players and designate an order in which they will take penalty kicks. To determine the number of different ways the coach can do this, you need to calculate the number of permutations of 11 players taken 5 at a time. This can be calculated using the formula:

P(n, r) = n! / (n-r)!

Where n = 11 (total players) and r = 5 (players to be selected).

P(11, 5) = 11! / (11-5)!

P(11, 5) = 11! / 6!

P(11, 5) = 39,916,800 / 720

P(11, 5) = 55,440

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Using the derivative, the expression for f(x) = 8x - 16

Since the graph of the derivative of f is shown,  The domain of f is the set of all x such that 0 < x < 4. Given that f(2) = 0, write an expression for f(x) in terms of x.

To do this , we proceed as follows.

Now, the f(x) is the area under the curve of f'(x)

So, f(x) = ∫f'(x)dx

So, f'(x) = ∫₀⁴f''(x)dx

Now,  ∫₀⁴f''(x)dx = area under the curve of f'(x)

= 1/2 × 4 × 4

= 2 × 4

= 8

So, f'(x) = 8

Now, f(x) = ∫f'(x)dx

f(x) = ∫8dx

f(x) = 8x + c

Now, we have that f(2) = 0

So, substituting this into the equation, we have that

f(2) = 8x + c

0 = 8(2) + c

0 = 16 + c

c = - 16

So, substituting c into f(x), we have that

f(x) = 8x - 16

So, f(x) = 8x - 16

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Max(A) exists and is equal to 2.

To prove that 2 is the least upper bound for A, we will assume the opposite, i.e., there exists a smaller upper bound for A, say c < 2. Then, by definition of an upper bound, we have x ≤ c for all x ∈ A. In particular, we can choose x = 1 + (c - 1)/2, which satisfies (x - 1) < 1 and x > c, contradicting the assumption that c is an upper bound for A. Therefore, 2 is the least upper bound for A.

To prove that 2 is an upper bound for A, we need to show that x ≤ 2 for all x ∈ A. By definition of A, we have (x - 1) < 1, which implies x < 2. Therefore, 2 is an upper bound for A.

Since 2 is the least upper bound for A and 2 is in A, we have max(A) = 2. This follows from the fact that max(A) is the smallest number that is an upper bound for A, and we have already shown that 2 is the least upper bound for A. Therefore, max(A) exists and is equal to 2.

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Answer:

True

Step-by-step explanation:

If you graph the two equations, you'll notice that they are reflections about the line [tex]y =x[/tex]

The z-score for a patient who takes ten days to recover is 2.24, which is closest to option c. 2.2.

To find the z-score for a patient who takes ten days to recover from a surgical procedure with a mean recovery time of 5.3 days and a standard deviation of 2.1 days, you can use the following formula:

Z-score = (X - μ) / σ

where X is the patient's recovery time (10 days), μ is the mean recovery time (5.3 days), and σ is the standard deviation (2.1 days).

1. Subtract the mean from the patient's recovery time: 10 - 5.3 = 4.7
2. Divide the result by the standard deviation: [tex]\frac{4.7}{2.1} = 2.24[/tex]

The z-score for a patient who takes ten days to recover is approximately 2.24. None of the given options match this value, so the correct answer is not listed.

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Answer:

69

Step-by-step explanation:

first you need to know that median is middle of the data set so put the numbers in order from lowest to highest.

60, 62, 65, 69, 70, 70, 72 now find the number in the middle which is 69. and if there is ever 2 numbers in the middle find the number in between them.

Hope this helps!! Good luck

Step-by-step explanation:

Let's find out:

ax - bx + y = z        subtract 'y' from both sides of the equation

ax-bx = z-y             reduce L side

x ( a-b)  = z-y           divide both sides by (a-b)

x = (z-y) / (a-b)         Done.

To address the girl's allergies and alleviate her problems, it may be best to relocate to a less polluted area with cleaner air.

The sentence is talking about a girl who is facing allergy problems while living in a big city. The word "relocate" means to move from one place to another, which is a suitable option for the girl to avoid the allergy problems caused by living in the big city. Therefore, "relocate" is the correct word that fits in the sentence

Relocating may involve allocating resources and funds to find a suitable new home, and possibly even recreating a new lifestyle in a different environment. Ultimately, the goal is to collocate the girl in a location that is better suited to her health needs.

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The bent rod is supported by a smooth surface at B and by a collar at A, which is fixed to the rod and is free to slide over the fixed inclined rod, Then the magnitude of the reaction force on the rod at B is 160 lb,  the magnitude of the reaction force on the rod at B is 161.11 lb, the moment of reaction on the rod at A -400 lb.

a). To decide the size of the response drive on the pole at B, ready to consider the strengths acting on the pole. Since the bar is in static balance, the net drive acting on the bar within the vertical course must be zero. Subsequently, ready to compose:

B_y - F =

B_y = F = 160 lb

Therefore, the greatness of the response drive on the bar at B is 160 lb.

b). To decide the size of the response constraint on the bar at A, able to consider the powers acting on the collar at A. Since the collar is free to slide over the settled slanted bar, the response drive at A must be opposite the pole. In this manner, ready to compose: A_x + Fsin(30°) =

A_y - Fcos(30°) =

A_x = -Fsin(30°) = -80 lb

A_y = Fcos(30°) = 138.56 lb

In this manner, the size of the response drive on the bar at A is:

|A| = sqrt(A_x2 + A_y2) = sqrt((-80)2 + (138.56)2) ≈ 161.11 lb

c). To decide the minute of response on the bar at A, ready to consider the minutes acting on the collar at A. Since the collar is settled to the pole, the minute of the response constrain at A must balance the minute of the outside drive M. Subsequently, we will type in:

M + A_y*d =

|Ma| = A_y*d = -M = -400 lb.ft

Therefore, the minute of response on the bar at A is -400 lb. ft (counterclockwise). 

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False. Cross-sectional designs do not show how causal processes occur over time, as they only provide a snapshot of a particular moment in time. Longitudinal designs are better suited for studying causal processes over time

Longitudinal designs are better suited for studying causal processes over time. However, cross-sectional designs can still have a high degree of internal validity, which refers to the extent to which a study accurately measures what it intends to measure.

False. Cross-sectional designs do not show how causal processes occur over time, as they only provide a snapshot of a particular moment in time.

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When applying the integral test for the convergence of a series, we can use differential calculus to check if the function being integrated is decreasing. The integral test is a method for determining the convergence or divergence of a series by comparing it to an integral of a related function. If the integral of the function converges, then the series also converges, and if the integral diverges, then the series also diverges.

To apply the integral test, we need to first identify a function that is continuous, positive, and decreasing on the interval of interest. We then integrate this function from the starting point of the series to infinity. If the integral converges, then the series also converges, and if the integral diverges, then the series also diverges.

Differential calculus can be used to check that the function being integrated is decreasing. Specifically, we can use the first derivative of the function to determine if it is decreasing on the interval. If the derivative is negative, then the function is decreasing, and if the derivative is positive, then the function is increasing. If the derivative is zero, then the function may or may not be decreasing, depending on its behavior at that point.

Overall, the integral test and the use of differential calculus provide powerful tools for determining the convergence or divergence of a series. By identifying a suitable function and checking it's decreasing behavior using the derivative, we can use the integral test to evaluate the convergence of a wide range of series.

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If we can observe this behavior in the data or the context of the problem, we can infer that a is diagonal.

If the matrix a is diagonal, it means that its eigenvectors are orthogonal to each other. Geometrically, this means that the linear transformation t corresponding to a scales the input vector along the direction of the eigenvectors without rotating it.

More specifically, let λ1 and λ2 be the eigenvalues of a, and let v1 and v2 be the corresponding eigenvectors. If a is diagonal, then we have:

a * v1 = λ1 * v1

a * v2 = λ2 * v2

This means that the linear transformation t scales the input vector v1 by a factor of λ1 along the direction of v1, and scales the input vector v2 by a factor of λ2 along the direction of v2. Since v1 and v2 are orthogonal, this scaling does not rotate the input vector.

Geometrically, this means that the linear transformation t corresponding to a stretches or shrinks the input vector along the direction of the eigenvectors without rotating it. If we can observe this behavior in the data or the context of the problem, we can infer that a is diagonal.

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The area of a rectangle is given by multiplying its length by its width. So, we have: Therefore, the area of the rectangle is 256x²m¹⁰.

When calculating a rectangle's area, we multiply the length by the width of the rectangle. The perimeter of a shape is the space surrounding it. Space inside a form is measured by area.  A closed figure's area is the portion of the plane that it occupys, whereas its perimeter is the space around it. The size of a plane or the area it encloses is expressed in square metres.

An example of a quadrilateral with equal and parallel opposite sides is a rectangle. It is a polygon with four sides and four angles that are each 90 degrees. A rectangle is a form with only two dimensions.

Area = length x width

Area = (8m³)² x (4x²m⁴)

Area = 64m⁶ x 4x²m⁴

Area = 256x²m¹⁰

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We have proved that if the sequence (a_n) satisfies lim a_n = L = 0, then (a_n) is unbounded.

To prove that if the sequence (a_n) satisfies lim a_n = L = 0, then (a_n) is unbounded, we will use proof by contradiction.

Assume that (a_n) is bounded. Then, there exists a positive number M such that |a_n| ≤ M for all n in the natural numbers.

Since lim a_n = L = 0, we can choose an ε > 0 such that if n is sufficiently large, then |a_n - L| < ε. In other words, there exists a natural number N such that for all n ≥ N, |a_n - L| < ε.

Consider the case when n ≥ N and a_n > 0 (the case when a_n < 0 is similar). Then, we have:

a_n = L + (a_n - L) > L - ε

Since a_n ≤ M, we have:

0 ≤ a_n < M

Combining these inequalities, we get:

0 ≤ L - ε < a_n < M

This implies that a_n is bounded between two positive numbers, which contradicts the assumption that (a_n) is unbounded. Therefore, our initial assumption that (a_n) is bounded must be false, and hence (a_n) is unbounded when lim a_n = L = 0.

Therefore, we have proved that if the sequence (a_n) satisfies lim a_n = L = 0, then (a_n) is unbounded.

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The meaning of the statement is : Trying to understand the universe is as tempting to human curiosity as it is daunting. Option 2

The use of "so many stars to yearn toward" suggests a multitude of stars existing in the universe, sparking fascination amongst humankind. Herein lies an implication of our innate desire for exploration and comprehension of the cosmos, urging us to seek knowledge about countless celestial bodies.

Yet, the phrase "so many ways to get lost in the dark" hints at the vastness of the universe, teeming with infinite stellar objects that present significant challenges in their study and analysis. It is this immense scope that gives rise to the difficulty of bridging the gaps in our understanding of space.

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The total surface area of the trapezoidal prism is S = 3,296 inches²

Given data ,

Let the total surface area of the trapezoidal prism is S

Now , the measures of the sides of the prism are

Side a = 10 inches

Side b = 32 inches

Side c = 10 inches

Side d = 20 inches

Length l = 40 inches

Height h = 8 inches

Lateral area of prism L = l ( a + b + c + d )

L = 40 ( 10 + 32 + 10 + 20 )

L = 2,880 inches²

Surface area S = h ( b + d ) + L

On simplifying the equation , we get

S = 2,880 inches² + 8 ( 52 )

S = 3,296 inches²

Hence , the surface area of prism is S = 3,296 inches²

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Answer:

1/2 or 50%

Step-by-step explanation:

To find probability, put the number of biographies (chances the event will happen) over the number of books (sample space).

5/10 reduces to 1/2 or 50%.

Hope this helps!

Answer:

D.) 42

Step-by-step explanation:

7 multiplied by 6 is 42, and since the function rule is to multiply by 6, we multiply the input, 7, by 6, to get the output, 42.

Answer:

the answer is D.42

Step-by-step explanation:

have a nice day.

(a) the rejection region is n overline x > kappa.

(b) kappa = 13/20 = 0.65. Since n overline x = 11 > kappa, we reject the null hypothesis and conclude that there is evidence in favor of the alternative hypothesis that theta > 0.45.

What is hypothesis?

A hypothesis is a proposed explanation or tentative answer to a research question or phenomenon. The null hypothesis is the default position that there is no significant difference between two groups or variables, while the alternative hypothesis proposes that there is a significant difference.

(a) According to Neyman-Pearson's lemma, the likelihood ratio is the most powerful test for a simple vs. a composite hypothesis. The likelihood function for the Bernoulli distribution is:

[tex]L(\theta | x) = \theta^k (1 - \theta)^{(n-k)[/tex]

where k is the number of successes in n trials. The likelihood ratio is:

[tex]\Lambda(x) = L(\theta_A | x) / L(\theta_0 | x)[/tex]

[tex]= (\theta_A^k (1 - \theta_A)^{(n-k)}) / (\theta_0^k (1 - \theta_0)^{(n-k)})[/tex]

Taking the logarithm and simplifying, we get:

[tex]log \Lambda(x) = k log(\theta_A / \theta_0) + (n-k) log((1 - \theta_A) / (1 - \theta_0))[/tex]

To define the rejection region, we need to find the value of kappa such that [tex]P(n overline x > kappa | \theta = \theta_0)[/tex] = alpha, where overline x is the sample mean. Since n overline x sim Bin(n, theta_0), we have:

[tex]P(n overline x > kappa | \theta = \theta_0) = 1 - P(n overline x < = kappa | \theta = \theta_0)\\= 1 - F(n overline x < = kappa | \theta = \theta_0)\\= 1 - sum from i=0 to floor(kappa*n) (n choose i) (\theta_0^i) ((1-\theta_0)^(n-i))[/tex]

where F is the cumulative distribution function of the binomial distribution. We can use a numerical method or a table to find kappa such that [tex]P(n overline x > kappa | \theta = \theta_0) = \alpha.[/tex]

Therefore, the rejection region is n overline x > kappa.

(b) Using the given values, we have k = 11, n = 20, [tex]\theta_0 = 0.45[/tex], and [tex]\theta_A = 0.65[/tex]. The sample mean is overline x = k/n = 0.55. To find kappa, we need to solve:

[tex]P(n overline x > kappa | \theta = \theta_0) = alpha\\1 - F(n overline x < = kappa | \theta = \theta_0) = 0.05\\F(n overline x < = kappa | \theta = \theta_0) = 0.95[/tex]

Using a binomial table, we find that the 0.95th percentile of the binomial distribution with n = 20 and theta = 0.45 is 13. Therefore, kappa = 13/20 = 0.65. Since n overline x = 11 > kappa, we reject the null hypothesis and conclude that there is evidence in favor of the alternative hypothesis that theta > 0.45.

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