A), Multiply the length of the vibrating string (60.0 cm) by the ratio to find the distance x. B)No, it's impossible to play a G4 note (392 Hz) on this string without retuning, C) not possible without retuning.
Part A) To find the distance x from the bridge to play a D5 note (587 Hz), follow these steps:
1. Calculate the speed of the wave on the string using the formula: v = √(T/μ), where T is tension and μ is linear mass density.
2. Calculate the wavelength of the A4 note using the formula: λ = v/f, where f is the frequency of the A4 note (440 Hz).
3. Calculate the wavelength of the D5 note using the formula: λ = v/f, where f is the frequency of the D5 note (587 Hz).
4. Find the ratio between the A4 and D5 wavelengths: λ_A4 / λ_D5.
5. Multiply the length of the vibrating string (60.0 cm) by the ratio to find the distance x.
Part B) No, it's impossible to play a G4 note (392 Hz) on this string without retuning.
Part C) The reason why it's impossible to play a G4 note (392 Hz) without retuning is because the frequencies of the fundamental modes are fixed and cannot be changed unless the tension, mass, or length of the string is altered. To play a G4 note, the string would need to be adjusted so that its fundamental frequency is 392 Hz, which is not possible without retuning.
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we want to lift a load of 200 lb with an overhead system using pulleys that have an efficiency of 0.9. if we can provide a maximum input force of 103 lb, what is the minimum number of pulleys that we need?
We need at least one pulley to lift the load of 200 lb with an overhead system using pulleys that have an efficiency of 0.9, given that we can provide a maximum input force of 103 lb.
Assuming that the weight of the pulleys and the rope is negligible, we can use the formula,
Load = (Input Force / Efficiencies) ^ Number of Pulleys
where Load is the weight of the load we want to lift, Input Force is the force we apply to the system, Efficiency is the efficiency of each pulley, and Number of Pulleys is the number of pulleys we need.
Plugging in the given values,
200 lb = (103 lb / 0.9) ^ Number of Pulleys
Simplifying the equation,
Number of Pulleys = log (base 2) (200 / (103/0.9))
Number of Pulleys = log (base 2) (200 x 0.9 / 103)
Number of Pulleys = log (base 2) 1.983495
Number of Pulleys = 1
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compare violet and red light from the visible spectrum. you are currently in a labeling module. turn off browse mode or quick nav, tab to items, space or enter to pick up, tab to move, space or enter to drop. which has the longer wavelength? which has the greater frequency? which has the greater energy? answer bank
In the following question, among the various parts to solve on visible spectrum.- A. Red light has a longer wavelength than violet light. B. Violet light has a higher frequency than red light. C. Violet light has greater energy than red light.
Violet and red light from the visible spectrum can be compared based on their wavelengths, frequencies, and energies. Violet light has a shorter wavelength, higher frequency, and greater energy than red light. The answers to the specific questions are: Which has the longer wavelength? Red light has a longer wavelength than violet light. Which has the greater frequency? Violet light has a higher frequency than red light. Which has the greater energy? Violet light has greater energy than red light. An HTML-formatted answer would look like this:
Violet and red light from the visible spectrum can be compared based on their wavelengths, frequencies, and energies. Violet light has a shorter wavelength, higher frequency, and greater energy than red light. The answers to the specific questions are:
Which has the longer wavelength? Red light has a longer wavelength than violet light.Which has the greater frequency? Violet light has a higher frequency than red light.Which has the greater energy? Violet light has greater energy than red light.For more such questions on visible spectrum.
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a ball is dropped from a distance 5 m above the ground, and it hits the ground with a certain speed. if the same ball is dropped from a distance 10 m above the ground, its final speed will be
The final speed of the ball dropped from a distance of 10 meters will be 49 m/s.
The final speed of the ball dropped from a distance of 10 meters will be higher than the final speed of the ball dropped from a distance of 5 meters. This is because of the effect of gravity on the ball.
As the ball falls, gravity will pull it toward the ground, giving it a greater speed as it falls further. This increase in speed is known as the "acceleration due to gravity."
When the ball is dropped from 10 meters, the ball will fall faster because of the increased distance it has to travel, allowing gravity to pull it down more quickly.
By the time it reaches the ground, it will have reached a higher velocity.
The equation for this acceleration due to gravity is:
Vf = Vi + g × t
Where Vf is the final speed, Vi is the initial speed, g is the acceleration due to gravity and t is the time.
Therefore, in order to calculate the final speed of the ball dropped from 10 meters, we can use this equation. Assuming the initial speed of the ball is zero and the acceleration due to gravity is 9.8 m/s2, we get:
Vf = 0 + 9.8 × (10/2)
Vf = 49 m/s
So, the final speed of the ball dropped from a distance of 10 meters will be 49 m/s.
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when einstein's theory of gravity (general relativity) gained acceptance, it demonstrated that newton's theory had been?a. wrongb. incompletec. really only guess
When Einstein's theory of gravity (general relativity) gained acceptance, it demonstrated that Newton's theory had been (b) incomplete.
Newton's theory of gravity is a law that governs the behavior of objects. The formula [tex]F = \frac {G m_1 m_2}{ d^2}[/tex] explains the force of gravity between two objects, where F is the force of gravity, G is the universal gravitational constant, m1 is the mass of one object, m2 is the mass of another object, and d is the distance between the centers of the two objects. This formula shows that gravity decreases as distance increases.
Einstein's theory of gravity (general relativity): It is a theoretical framework proposed by Albert Einstein in 1915. It combines special relativity and Newton's law of universal gravitation. General relativity is based on the notion that gravitation is not a force acting between two masses but rather a curvature of spacetime created by the presence of massive objects. It differs from Newton's law of universal gravitation, which states that gravitation is caused by an attractive force acting between two masses.
When Einstein's theory of gravity (general relativity) gained acceptance, it demonstrated that Newton's theory had been incomplete. Therefore the correct answer is b.
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a rising parcel of unstable air a rising parcel of unstable air can rise well into the mesosphere. cannot rise very far above the tropopause. can eventually escape into space. will not be slowed by entrainment.
A rising parcel of unstable air is an air mass that is warmer than the surrounding air and is therefore buoyant. It can rise until it reaches an area where its temperature is the same as the surrounding air, the tropopause.
The tropopause is the boundary between the troposphere (the lowest part of the atmosphere) and the stratosphere (the next layer of the atmosphere).
At this level, the air is very stable and so the air parcel cannot rise any further.
The air parcel may eventually escape into space, however it will not be slowed by entrainment, the process by which the parcel loses energy and slows down due to friction.
As the parcel rises, the atmospheric pressure decreases and the temperature increases due to the decrease in air density.
As it rises further, the air pressure decreases until it reaches the tropopause, where it then plateaus.
Once the air reaches the tropopause, it has reached a level of equilibrium and can no longer rise further as the temperature and pressure remain constant.
The tropopause also acts as a barrier to air moving from the stratosphere to the troposphere.
This is due to the temperature inversion that occurs when the temperature in the troposphere decreases with altitude while the temperature in the stratosphere increases with altitude.
This inversion creates a strong stratospheric temperature gradient, making it difficult for air to move between the two layers.
A rising parcel of unstable air can rise well into the mesosphere but cannot rise very far above the tropopause.
The tropopause acts as a barrier to air moving between the troposphere and the stratosphere due to its temperature inversion, and the air parcel may eventually escape into space without being slowed by entrainment.
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when a toolbox weighing 5 newtons is resting on the ground next to a sawhorse, how much potential energy does it have?
The potential energy of a toolbox weighing 5 newtons is zero.
The potential energy of a toolbox weighing 5 newtons depends on its height relative to the ground.
Potential energy (PE) is equal to the mass of the object (m) multiplied by the acceleration due to gravity (g) multiplied by its height (h): PE = mgh.
Therefore, the potential energy of the toolbox is equal to 5*9.8*h (where h is the height of the toolbox above the ground).
Assuming that the toolbox is resting on the ground, it has zero potential energy since its height is zero. If the toolbox is lifted above the ground, however, then it will have a greater potential energy.
For example, if the toolbox is lifted to a height of 10 meters above the ground, then it will have a potential energy of 490 joules (5*9.8*10).
The potential energy of the toolbox when it is placed next to the sawhorse, the height of the sawhorse needs to be taken into consideration.
If the sawhorse is higher than the ground, then the toolbox will have a greater potential energy since it will be located at a greater height above the ground.
If the sawhorse is lower than the ground, then the toolbox will have a lesser potential energy than when it is resting on the ground.
The potential energy of a toolbox weighing 5 newtons when placed next to a sawhorse depends on the height of the sawhorse relative to the ground.
If the sawhorse is higher than the ground, then the toolbox will have a greater potential energy, and if it is lower than the ground, then the toolbox will have a lesser potential energy.
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The Force F with rightwards harpoon with barb upwards on top (2,1,−4)N(2,1,−4)N is acting on the body of mass m=3kgm=3kg while causing it to change the postion from point A(2,8,0)mA(2,8,0)m to point B(28,75,68)mB(28,75,68)m.a) Find work done by the force (in one hundredth of Joule) on the distance ABAB.b) Find the total work done by the forces acting on the body over the distance ABAB.c) Find the magnitude of the acceleration of the body (answer to nearest hundredth of m/s2m/s2) as it moves from point AA to point BB.
The work done by the force (in one-hundredth of Joule) on the distance AB is -15300×J/100. The total work done by the forces acting on the body over the distance AB is -153 J. The magnitude of the acceleration of the body is 1.53 m/s².
a) To find the work done by the force on the distance AB, we first need to find the displacement vector from point A to point B:
Displacement vector, AB = B - A
= (28-2, 75-8, 68-0) = (26, 67, 68)
Now, we calculate the dot product of the force vector and the displacement vector:
F • AB = (2,1,-4) • (26,67,68)
= 2(26) + 1(67) - 4(68)
= 52 + 67 - 272
= -153
The work done by the force on the distance AB in one-hundredth of Joule is given by:
Work = F • AB
=-15300×J/100.
b) Since there is only one force acting on the body, the total work done by the forces acting on the body over the distance AB is the same as the work done by the force F:
Total work = -153 J
c) The acceleration of the body is given by Newton's Second Law of Motion:
F = ma
=> a = F/m
where F is the force and m is the mass of the body.
a = F/m
= (2, 1, -4)/3
= (0.67, 0.33, -1.33) m/s²
Therefore, the magnitude of the acceleration of the body is
|a| = √(0.67² + 0.33² + (-1.33)²) ≈ 1.53 m/s² (corrected to the nearest hundredth of m/s²).
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Compared to a landscape that develops in a cool, dry climate, a landscape that develops in a warm, rainy climate will most likely weather and erode a. Slower, so the landforms are more angular b. Slower, so the landforms are more rounded c. Faster, so the landforms are more angular d. Faster, so the landforms are more rounded
A landscape that develops in a warm, rainy climate will most likely weather and erode faster, so the landforms are more rounded.
This is because in a warm, rainy climate, there is more water available to weather and erode the landforms. The water can penetrate cracks and crevices in the rocks, dissolve minerals, and carry away sediments. Over time, this can lead to the rounding of edges and the smoothing of surfaces, resulting in more rounded landforms.
In contrast, in a cool, dry climate, there is less water available to weather and erode the landforms. This can result in slower rates of erosion and less rounding of the landforms.
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a syringe containing an incompressible fluid is oriented vertically and the plunger slowly depressed. at which point is the kinetic energy the lowest?
The point at which the kinetic energy is lowest is 3 in the syringe containing an incompressible fluid that is vertically oriented and the plunger is slowly depressed.
The kinetic energy of an object is the energy it has due to its motion. When an object is in motion, it has kinetic energy. It is a scalar quantity that is proportional to the mass of the object and the square of its velocity. The formula for kinetic energy is given as follows:
KE = 1/2mv²
Where m is the mass of the object and v is its velocity.
Points 1 and 2 have higher kinetic energy because the incompressible fluid is still being compressed in the syringe. Point D is incorrect because the kinetic energy of the incompressible fluid is not the same at all three points. Point E is incorrect because enough information has been provided. Therefore, when a syringe containing an incompressible fluid is vertically oriented and the plunger is slowly depressed, the kinetic energy is lowest at point 3.
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a 2.0 m tall man is 10 m in front of a camera with a 25 mm focal length lens. how tall is his image on the detector?
A 2.0 m tall man is 10 m in front of a camera with a 25 mm focal length lens, the height of the image on the detector is approximately 5.01 mm.
To determine the height of the image of a 2.0 m tall man who is 10 m in front of a camera with a 25 mm focal length lens, we will use the lens formula and magnification formula.
First, let's use the lens formula: 1/f = 1/u + 1/v
Here, f is the focal length, u is the object distance, and v is the image distance. We have f = 25 mm, and u = 10 m (which we need to convert to millimeters, so u = 10,000 mm).
We can now solve for v: 1/25 = 1/10,000 + 1/v
To isolate v, let's first subtract 1/10,000 from both sides: 1/25 - 1/10,000 = 1/v Now,
find the least common denominator (LCD) and subtract: (400 - 1)/10,000 = 1/v 399/10,000 = 1/v
Now, take the reciprocal of both sides to solve for v: v = 10,000/399
Now that we have the image distance (v), we can use the magnification formula to find the height of the image: magnification (m) = image height (h') / object height (h) = v / u
We want to find h', so we can rearrange the formula: h' = h * (v / u)
Plug in the known values (h = 2.0 m, u = 10,000 mm, and v = 10,000/399 mm), and convert h to mm (2.0 m = 2,000 mm): h' = 2,000 * (10,000 / 399) / 10,000 Simplify the expression: h' = 2,000 / 399
So, the height of the image on the detector when the man is 2.0m tall, 10 m in front of a camera with a 25 mm focal length lens is approximately 5.01 mm.
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most of the mass of the solar system is located in which of the following? responses sun sun jupiter jupiter comets comets earth
Most of the mass of the solar system is located in the Sun. The Sun accounts for over 99% of the total mass of the solar system, with the remaining mass distributed among the planets, asteroids, comets, and other objects.
The solar system is a collection of objects that orbit around the Sun. It consists of the Sun, eight planets and their natural satellites, dwarf planets, asteroids, comets, and other small bodies. The eight planets, listed in order from the Sun, are Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune.
The Sun is at the center of the solar system and contains more than 99% of the mass of the solar system. It is a giant ball of gas, mostly hydrogen, and helium, and is the source of heat and light for the entire solar system.
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if you had a microscope which was capable of doing this, what would the frequency of electromagnetic radiation be, in hertz, that you would have to use?
Answer:
The electric power didn’t last very long. It lasted only as long as the chemical reaction in the battery.
Explanation:
A 750-kg roller coaster car drops from rest at a height of 90.0 m along a frictionless track. If the coefficient of kinetic friction due to braking along a horizontal track at the end of the ride is 0.720, over what distance does the car need to brake to come to a complete stop?
logs sometimes float vertically in a lake because one end has become water-logged and denser than the other. what is the average density of a uniform-diameter log that floats with 20.0% of its length above water?
Uneven-diameter logs that float with 20.0% of their length above water have an average density of 0.8g/cm3. The density is the proportion of weight to capacity.
An item it's far less compact that liquid may be supported up liquid water, and hence it floats. More dense objects can sink when submerged in water. Less dense logs float whereas more thick logs sink. A body can change its condition of rest or motion by the application of force
Instead of obliquely reading from either the side, read the scale stick straight from of the end of both the log. → The diameter of a log is only ever calculated within the bark. Employ a log measuring rod to determine the log's small end's "diameter from within bark," also known as "d.i.b."
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one cycle of the power dissipated by a resistor ( ) is given by this periodic signal repeats in both directions of time. what is the amplitude of the pwm voltage signal applied across the 500- resistor
The maximum amplitude of the PWM voltage signal applied across the 500-ohm resistor is: Vmax=2*I*R=500*I
The power dissipated by a resistor during one cycle is given by the periodic signal. The PWM voltage signal applied across a 500 Ω resistor is analyzed in this question. The amplitude of the signal is determined below.
Pulse Width Modulation is the PWM. It's a process for varying the pulse width of a square wave, which changes the percentage of time the signal is high to low. The pulse width can be varied to create the desired output signal level. It is frequently utilized in applications where analog signals are required, including control systems, power supplies, and audio systems. The maximum voltage Vm of the PWM voltage signal can be found by calculating the RMS value of the pulse. The root-mean-square value is the square root of the mean of the square of the signal over a given period. If we use a pulse that has a duty cycle of 50%, this formula simplifies to: Vmax=Vm+0.5Vdc where Vdc is the average value of the pulse.
The maximum amplitude can be determined using this formula: Vmax=I*R where I is the current and R is the resistance. The current flowing through the resistor is proportional to the voltage applied to it, and the voltage is proportional to the duty cycle of the PWM signal, which varies from 0 to 1. Thus, the voltage applied to the resistor is proportional to the duty cycle and can be expressed as: V=Vmax*D where D is the duty cycle. Thus, the amplitude of the PWM voltage signal applied across a 500-ohm resistor is: Vmax=2*I*R=500*I. Using this equation, we can determine the maximum amplitude of the PWM voltage signal applied across the 500-ohm resistor.
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while a car travels around a circular track at a constant speed, its a) acceleration is non-zero and along the path b) acceleration is non zero and inward toward the center c) acceleration is zero d) acceleration is non-zero and outward from the center
While a car travels around a circular track at a constant speed, its (d) acceleration is non-zero and outward from the center.
When a car travels around a circular track at a constant speed, it is constantly changing direction, and therefore, constantly accelerating. This acceleration is known as centripetal acceleration and is directed towards the center of the circle.
However, according to Newton's third law, every action has an equal and opposite reaction. In this case, the car also experiences an equal and opposite acceleration, known as the centrifugal acceleration, which is directed outward from the center of the circle.
This is the non-zero acceleration experienced by the car, and it acts to counterbalance the centripetal acceleration, keeping the car moving in a circular path.
Therefore, the correct answer is (d) acceleration is non-zero and outward from the center.
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a value of mass is given as 14.6 g to 15.2 g. a value of volume is given as 2.4 to 2.8 m3. state the density using reasonable outer limits.
The density using reasonable outer limits is the density of an object can be determined by dividing its mass (measured in grams, g) by its volume (measured in cubic metres, m3). To calculate the density using the given values of mass and volume, we can use the following formula: Density = Mass/Volume.
Therefore, the density of the given object can be calculated using the outer limits of mass and volume, which are 14.6 g to 15.2 g and 2.4 m3 to 2.8 m3, respectively. The calculated density of the given object is in the range of 5.75 g/m3 to 5.45 g/m3.
To calculate the density, the mass and volume of the object must be known. Mass is a measure of how much matter an object has, and is calculated in grams (g). Volume, on the other hand, is a measure of the amount of space an object takes up, and is calculated in cubic metres (m3).
When these two values are known, the density can be calculated using the formula: Density = Mass/Volume. In this case, the given values of mass and volume are 14.6 g to 15.2 g and 2.4 m3 to 2.8 m3, respectively. By substituting these values into the formula, the density of the object can be calculated as follows:
Density = Mass/Volume
Density = 14.6 g/2.4 m3 = 5.75 g/m3
Density = 15.2 g/2.8 m3 = 5.45 g/m3
Therefore, the density of the given object is in the range of 5.75 g/m3 to 5.45 g/m3.
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5. does it take the same amount of work to speed your car up from 25 m/s to 30 m/s as it does to speed it up from 30 m/s to 35 m/s? if not, which situation requires more work? why? use the cer framework to answer the question.
The same amount of work to speed up a car from 25 m/s to 30 m/s as it does from 30 m/s to 35 m/s is different because it requires more work to speed up a car from 30 m/s to 35 m/s than it does to speed it up from 25 m/s to 30 m/s.
Thus, the correct answer is "No, it doesn't".
The CER framework is a tool that can be used to answer questions that involve scientific principles. CER stands for Claim, Evidence, and Reasoning.
1. Claim: It does not take the same amount of work to speed up a car from 25 m/s to 30 m/s as it does to speed it up from 30 m/s to 35 m/s.
2. Evidence: Work is equal to force times distance, which means that the amount of work required to accelerate an object depends on the distance over which the force is applied. If the distance is shorter, less work will be done.
The distance over which the force is applied to speed up a car from 30 m/s to 35 m/s is shorter than the distance over which the force is applied to speed it up from 25 m/s to 30 m/s. This implies that more work is required to speed up a car from 30 m/s to 35 m/s than it does to speed it up from 25 m/s to 30 m/s. The equation for calculating work is W = F x D, where W is work, F is force, and D is distance.
3. Reasoning: Therefore, it requires more work to speed up a car from 30 m/s to 35 m/s than it does to speed it up from 25 m/s to 30 m/s. This is because the distance over which the force is applied to speed up a car from 30 m/s to 35 m/s is shorter than the distance over which the force is applied to speed it up from 25 m/s to 30 m/s. The work done on an object is a measure of the energy transferred to it. When more work is done on an object, more energy is transferred to it.
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Answer: The table that would organize and summarize the class data on pH levels of the different soil types is found in the attachment below.
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a negatively charged point particle is placed initially at rest in a uniform electric field as a result of being placed in the electric field which direction will it move
When a negatively charged point particle is placed initially at rest in a uniform electric field, it will move towards the direction of the electric field.
An electric field is a vector field that represents the force exerted by charged particles over each other. It is generated by charges, and it affects other charged particles that are in the space around it. The direction of the electric field is given by the direction of the force that is experienced by a small positive test charge placed in that field. If the force on the test charge is towards the positive charge that creates the field, the electric field will point towards the positive charge. If the force on the test charge is towards the negative charge that creates the field, the electric field will point towards the negative charge.
When a negatively charged particle is placed in the electric field, it experiences a force in the direction opposite to the direction of the electric field, this is because the negatively charged particle is attracted towards the positively charged particles that generate the field, and so it moves towards them. Therefore, the negatively charged particle moves towards the direction of the electric field. When a positively charged particle is placed in the electric field, it experiences a force in the direction of the electric field. This is because the positively charged particle is attracted towards the negatively charged particles that generate the field, and so it moves towards them. Therefore, the positively charged particle moves towards the direction opposite to the direction of the electric field.
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a 100 kg shot-putter pushes on a 4 kg shot with a force of 500 n forward and a force of 866 n upward. how large is the resultant force acting on the shot?
The magnitude of the resultant force acting on the shot is 1000 N, and its direction is approximately 59.5 degrees above the horizontal.
The resultant force acting on the shot can be found using vector addition of the two forces applied on the shot.
The two forces can be represented as vectors in the xy-plane, with the horizontal force of 500 N pointing in the positive x-direction and the vertical force of 866 N pointing in the positive y-direction. We can use the Pythagorean theorem and trigonometry to find the magnitude and direction of the resultant force vector.
The magnitude of the resultant force vector F is given by:
|F| = [tex]\sqrt{(500 N)^2 + (866 N)^2)}[/tex]
|F| = 1000 N
The direction of the resultant force vector is given by the angle θ it makes with the positive x-axis:
tan θ = (866 N) / (500 N)
θ = tan⁻¹(866/500)
θ ≈ 59.5 degrees
Therefore, the magnitude of the resultant is 1000 N, and its direction is approximately 59.5 degrees.
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a stone and a block are on an incline as shown in figure. the stone is at rest. how many forces act on the stone?
These two forces act on the stone:
Force due to gravityForce of the inclineThe stone in the figure shown is at rest, which means that the net force on the stone is zero. Therefore, there must be two forces acting on the stone, one in the direction of the incline and the other in the opposite direction. These two forces are:
Force due to gravity (weight): This is the force of gravity acting on the stone in the downward direction. This force is equal to the weight of the stone and opposes the force of the incline.The force of the incline: This is the force of the incline acting on the stone in the upward direction. This force is equal to the weight of the stone and is the opposite of the force due to gravity.Learn more about the force of gravity: https://brainly.com/question/29236134
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c. what will be the charges of the spheres in fractions of after connection? how does the total charge of the two spheres after the connection compare to the initial charge of the left sphere?
The charges of the spheres after connection will be the same as the charge of the left sphere. The total charge of the two spheres after connection is equal to the initial charge of the left sphere.
To understand this, it is important to know that electric charge is a conserved quantity. This means that the net charge of a system cannot change. Therefore, if two objects with opposite charges (like the two spheres) are connected, the charges of the two objects will become equal and the total charge of the two spheres will remain the same as the initial charge of the left sphere.
To further understand this concept, consider two spheres with opposite charges. If the two spheres are not connected, then the total charge of the two spheres is equal to the sum of the charges of each sphere. However, if the two spheres are connected, the net charge of the system cannot change. Therefore, the charge of each sphere will become equal and the total charge of the two spheres after the connection will remain the same as the initial charge of the left sphere.
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A 23.3 kg boy is moving along a circular path with the constant speed of 2.7 m/s. What is the magnitude of the centripetal force acting on the boy if the radius of the circle is 12.9 m. Note : Calculate the answer to 3 (three) significant figures by presenting it in normal ( decimal) form. Don't forget to include the unit.
The centripetal force for the given question would be 16.3 N.
Explanation:
The magnitude of the centripetal force acting on a 23.3 kg boy moving along a circular path with a constant speed of 2.7 m/s and the radius of the circle is 12.9 m is 16.3 N (newton).
What is centripetal force?
Centripetal force is the net force acting on an object moving in a circular path toward the center of the circle. It always points towards the center of the circle, hence the name "center-seeking force".
What is the formula for centripetal force?
The formula for centripetal force is Fc = (mv²)/r, where Fc is the centripetal force, m is mass, v is velocity or speed and r is the radius of the circular path.
In the given question: Mass, m = 23.3 kgVelocity, v = 2.7 m/s, Radius, r = 12.9. To calculate centripetal force,
F = (m x v^2)/r
Putting the given values in the above formula: F = (23.3 kg x (2.7 m/s)^2)/12.9 m= 16.3 N (newton)
Therefore, the magnitude of the centripetal force acting on the boy is 16.3 N (newton).
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a 5 kg toy train car is connected to a 3 kg toy train car. the 3 kg car is given an external force of 16 n. what is the tension in the rope connecting the cars?
A 5 kg toy train car is connected to a 3 kg toy train car. the 3 kg car is given an external force of 16 n. the tension in the rope connecting the two cars is 29 N.
The tension in the rope connecting two toy train cars A toy train car with a mass of 5 kg is connected to a toy train car with a mass of 3 kg. An external force of 16 N is applied to the 3 kg car.
Tension in the rope between the two toy cars is what we need to calculate. According to Newton’s 2nd law, force equals mass multiplied by acceleration. If the two cars are moving in the same direction with the same acceleration, the tension in the rope can be calculated as follows:
Force acting on the two cars is the external force that is applied on the 3 kg car which is equal to 16 N. In this case, both cars will have the same acceleration.
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engineers at the university of texas at austin are developing an advanced locomotive propulsion system that uses a gas turbine and perhaps the largest highspeed flywheel in the world in terms of the energy it can store. the flywheel can store 4.8 * 108 j of energy when operating at its maximum rotational speed of 15,000 rpm. at that rate, the perimeter of the rotor moves at approximately 1,000 m/s. determine the radius of the flywheel and its rotational inertia.
The radius of the flywheel and its rotational inertia will be 0.64m and 389kgm² respectively.
What is the rotational inertia?Rotational inertia, also known as moment of inertia, is a measure of an object's resistance to rotational motion. It is similar to the concept of mass in linear motion. Just as mass is a measure of an object's resistance to linear motion, the moment of inertia is a measure of an object's resistance to rotational motion.
The moment of inertia of an object depends on its shape and mass distribution. Objects with more mass distributed farther from the axis of rotation have a higher moment of inertia than objects with the same mass but a more compact distribution of mass. The moment of inertia is measured in units of kilograms square meters (kg m²) in the SI system.
The radius will be:
= 1000 / 15000(2πrad / 60)
= 0.64m
The inertia will be:
= 2(4.8 × 10^8) / 100 (2π/60)
= 389kgm²
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you are standing on a scale in an elevator. suddenly you notice your weight increases. what do you conclude?
When standing on a scale in an elevator, if one notices an increase in their weight, it means that: the elevator is accelerating upwards.
This is due to the fact that the scale underfoot has to counter the upward acceleration of the elevator, which causes the weight measured on the scale to increase. The scale measures the normal force, which is the weight being exerted on the scale, which is equal to the mass of the individual multiplied by the gravitational acceleration on the surface of the earth.
This can be represented by the formula: W = mg,
where W is the weight, m is the mass of the object and g is the gravitational acceleration.
When the elevator is stationary or moving at a constant velocity, the gravitational acceleration is the same as the normal force and the weight of the individual remains constant. However, when the elevator begins to accelerate upwards, the normal force exerted by the scale must increase to counter the upward acceleration of the elevator.
This causes an increase in weight measured on the scale. Therefore, if one notices an increase in their weight while standing on a scale in an elevator, it indicates that the elevator is accelerating upwards.
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I have no clue what im doing..
If work = 100J and time = 20 seconds, what is power
Answer:
5 J/s or 5 watt
Explanation:
Given,
Work (W) = 100 J
Time (t) = 20 s
To find : Power (P)
Formula :
P = W/t
P = 100/20
P = 5 J/s
P = 5 watt
Note : -
J/s and watt are units are power.
A sound wave has a frequency of 687 Hz in air and a wavelength of 0.49 m. What is the temperature of the air? Relate the speed of sound in air to temperature in units of Kelvin, but answer in units of Celsius. Assume the velocity of sound at 0◦C is 333 m/s.
Answer in units of deg C.
The temperature of the sound air is approximately 17.57°C.
Soundwave calculation.
We can use the formula for the speed of sound in air to relate it to temperature:
v = 331.5 * sqrt(T/273.15)
where v is the velocity of sound in air, T is the temperature in Kelvin, and 273.15 K is the temperature in Kelvin at 0◦C.
We know the frequency and wavelength of the sound wave in air, and we can use the formula for the speed of sound to find the velocity of sound:
v = f * λ
where f is the frequency of the sound wave λ is the wavelength.
Plugging in the given values, we get:
v = 687 Hz * 0.49 m
v = 336.63 m/s
Now we can use the formula for the speed of sound to find the temperature:
336.63 m/s = 331.5 * sqrt(T/273.15)
Solving for T, we get:
T = (336.63/331.5)^2 * 273.15
T = 290.72 K
Converting from Kelvin to Celsius, we get:
T = 290.72 - 273.15
T ≈ 17.57°C
Therefore, the temperature of the air is approximately 17.57°C.
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an object is located in water 30 cm from the vertex of a convex surface made of plexiglas with a radius of curvature of 80 cm. where does the image form by refraction and what is its magnification? nwater
The image formed by refraction is at a distance of 120cm behind the lens and its magnification is 4.
The image formation by refraction and magnification of an object in water 30 cm from the vertex of a convex surface made of plexiglass with a radius of curvature of 80 cm can be calculated using the following steps:
1. Determine the object's distance from the lens. Object distance (u) = -30 cm. (negative sign as per the convention of the mirror)
2. Determine the focal length of the lens using the formula:
f = R/2 where, f = focal length of the lens, R = radius of curvature of the lens.
So, f = 80/2 = 40 cm.
3. Use the mirror formula to determine the image distance from the surface:
1/f = 1/v + 1/u where,v = image distance from the surface.
Substituting the given values (with proper sign convention), we get:
(-1/40) = 1/v + (-1/30)
Solving for v, we get:
v = 120 cm.
5. Use the magnification formula to determine the magnification of the image:
m = -(v/u)
where,m = magnification, v = 120 cm, u = 30 cm
Therefore,m = -(120/-30) = 4
Therefore, the image will form at a distance of 120 cm from the lens on the water side of the lens and is magnified by a factor of 4.
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