This molecule undergoes an E1 mechanism when stirred in water.

This Molecule Undergoes An E1 Mechanism When Stirred In Water.

Answers

Answer 1

All the 3 chemical species are drawn in the images below/

What is E1 mechanism when stirred in water

The E1 reaction mechanism instigates a variant of elimination reactions. It materializes in the vicinity of strong acids or bases and it initiates by eliminating a leaving group from the substrate, consequently creating an intermediate carbocation. Once completed, the mechanism eliminates a proton from a neighborly carbon, initiating the construction process of a double bond.

However, performing an E1 reaction in water may yield unexpected results due to water's nucleophilic nature, catalyzing sneaky attacks on the carbocation intermediates, leading to dissimilar products than initially intended. Furthermore, reactions performed with aqueous media cause other side-products thanks to hydrolysis mechanisms that emerge, making them undesirable.


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This Molecule Undergoes An E1 Mechanism When Stirred In Water.

Related Questions

a 40 ml solution containing .30 M Ti+3 was titrated with 0.75 M Sn+2. what potential at the equivalence point if the resulting solution is
measured against a reference electrode

Answers

In this redox reaction, Ti+3 is oxidized to Ti+4, and Sn+2 is reduced to Sn+4:

Ti+3 + Sn+2 → Ti+4 + Sn+4

The balanced equation shows that one mole of Ti+3 reacts with one mole of Sn+2. We can use this to calculate the number of moles of Sn+2 required to react completely with the Ti+3 in the solution:

n(Sn+2) = (0.30 mol/L) x (0.040 L) = 0.012 mol

The volume of Sn+2 required to react with the Ti+3 can be calculated using the molarity and the number of moles:

V(Sn+2) = n(Sn+2) / [Sn+2] = 0.012 mol / 0.75 mol/L = 0.016 L = 16 mL

At the equivalence point, all of the Ti+3 has reacted with the Sn+2, so the resulting solution contains only Ti+4 and Sn+4. The potential at the equivalence point can be calculated using the Nernst equation:

E = E° - (RT/nF) x ln(Q)

where E° is the standard cell potential, R is the gas constant, T is the temperature in Kelvin, n is the number of electrons transferred in the reaction, F is the Faraday constant, and Q is the reaction quotient.

The standard cell potential can be calculated using the reduction potentials for the half-reactions:

Ti+4 + 2 e- → Ti+3 E° = -0.15 V
Sn+4 + 2 e- → Sn+2 E° = 0.15 V

The overall cell potential is the sum of the reduction potentials:

E°cell = E°reduction (cathode) - E°reduction (anode) = 0.15 V + 0.15 V = 0.30 V

At the equivalence point, the reaction quotient Q is equal to the equilibrium constant K:

K = [Ti+4] / [Sn+4]

The concentrations of Ti+4 and Sn+4 can be calculated from the number of moles and the total volume of the solution:

n(Ti+4) = n(Sn+2) = 0.012 mol
V(total) = 0.040 L + 0.016 L = 0.056

pls tysm it is due today

Answers

The reaction that is shown by the option D is a balanced reaction equation.

What is a balanced reaction equation?

We can say that a reaction equation as we have it balanced number of each of the atoms that we have on the left hand side of the reaction equation is the same as the number of the atoms of the elements that we have on the right hand side of the reaction equation.

A reaction equation is a representation of a chemical reaction using chemical formulas and symbols. It shows the reactants on the left-hand side and the products on the right-hand side of the equation, separated by an arrow.

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)A mixture of 0.220 molesCO, 0.350 molesF2and 0.640 molesHehas a total pressure of 2.95 atm.What is the partial pressure ofCO?

Answers

The partial pressure of a component gas in a mixture is the pressure that gas would exert if present alone in the vessel at the same temperature as that of the mixture. Here the partial pressure of CO is

The pressure exerted by a mixture of two or more non-reacting gases enclosed in a definite volume is equal to the sum of the partial pressures of the component gases. This is sated by Dalton.

Here partial pressure is:

partial pressure = Mole fraction × Total pressure

Mole fraction of CO = Number of moles of CO / Total moles

n(CO) = 0.220 / 1.21 = 0.181 moles

partial pressure = 2.95 × 0.181  = 0.533 atm

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How many years passed between the first man on the Moon and the first US woman in space?

Answers

It took 14 years between the first man on the Moon and the first US woman in space.

What is space exploration?

The use of astronomy and space technology to explore outer space is known as space exploration. While astronomers use telescopes to explore space, physical exploration is carried out by both uncrewed robotic space probes and human spaceflight.

Understanding gravity, the magnetosphere, the atmosphere, fluid dynamics, and the geological evolution of other planets, for example, has come from studying the solar system.

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Question 10 (1 point)
What mass of iron (III) nitrate, Fe (NO3)3, is needed to prepare a 125 mL solution of
0.250 M?
7.56 grams
60.5 grams
2.68 grams
30.2 grams

Answers

The mass of iron (III) nitrate needed to prepare a 125 mL solution of 0.250 M is approximately 7.56 grams.

To calculate the mass of iron (III) nitrate needed to prepare a 125 mL solution of 0.250 M, we can use the formula:

mass (in grams) = volume (in liters) x concentration (in moles/liter) x molar mass (in grams/mole)

First, let's convert the volume from milliliters (mL) to liters (L):

125 mL = 0.125 L

Next, we can use the given concentration of 0.250 M to calculate the number of moles of Fe(NO3)3 needed:

moles = concentration x volume

moles = 0.250 mol/L x 0.125 L

moles = 0.03125 mol

Finally, we can use the molar mass of Fe(NO3)3 to convert from moles to grams:

mass = moles x molar mass

mass = 0.03125 mol x 241.86 g/mol

mass ≈ 7.56 g

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CO, (9) +2NH_(9) - CO(NH,) (s) +H, O(1)
a. What is the maximum mass of urea, CO(NH), that can be manufactured from the reaction of 2.20 moles of CO2 with sufficient amount of ammonia.

Answers

The mass of the ammonia that is required is  258 g.

What is the stoichiometry of the reaction?

The quantitative correlations between the reactants and products in a chemical reaction are the focus of the chemistry subfield known as stoichiometry.

We have to know that;

1 mole of CO2 produces 1 mole of urea

2.2 moles of CO2 produces 2.2 urea

Given that the number of moles of urea = 455 g/60 g/mol

= 7.58 moles

Now;

2 moles of NH3 produces 1 mole of urea

x moles of NH3 produces 7.58 moles of urea

x = 7.58 * 2/1

= 15.16 moles

Mass of the ammonia =  15.16 moles * 17 g/mol

= 258 g

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Determine the mass of carbon dioxide that should be produced in the reaction between 3.74g of carbon and excess oxygen what is the maximum recent yield if 11.34g of CO2 is recovers

Answers

13.71g is the mass of carbon dioxide that should be produced in the reaction between 3.74g of carbon and excess oxygen. 83% is the percent yield.

Percent yield in chemistry is the percentage of the product's weight to its theoretical yield. In order to quantify the outcome in percent, we divide the experimental yield with the theoretical yield then multiply the result by 100. Chemists employ an equation called percent yield after a reaction to determine how much material they should have theoretically extracted against how much they actually acquired.

C+ O[tex]_2[/tex] → CO[tex]_2[/tex]

moles of carbon =  3.74/ 12=0.31moles

mass of CO[tex]_2[/tex] =0.31×44=13.71g

% yield =  (11.34/13.71)×  100=83%

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Determine the number of moles in 100,0 g S

Answers

The number of moles in 100g of Sulphur is 3.13 moles.

How to calculate number of moles?

The number of moles in a substance can be calculated by dividing the mass of the substance by its molar mass as follows:

moles = mass ÷ molar mass

According to this question, there are 100g of Sulphur. Sulphur has an atomic mass of 32g/mol. The moles of this element can be calculated as follows;

moles = 100g ÷ 32g/mol

moles = 3.13moles

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Physicians tend to use units of calories ,in part because that is what their patients use and understand .Food “Calories “ are actually calories. How many calories are in a calorie?
A.10,000
B.1,000
C.100
D.10
E.1

Please help me what is the answer.

Answers

The answer is E. 1.

How many liters of a 3.4 m isopropanol solution can be made with 78 g of isopropanol

Answers

Answer:

You can make 2.29 L of 3.4 M isopropanol solution with 78 g of isopropanol.

Explanation:

PLEASE HELP WITH CONVERSIONS

Answers

The grams of pigment needed is 9.20 grams

The grams of water needed is 0.199 grams.

The final molarity of the binder in the paint mixture is 20.04 M.

What are the masses of substances required?

The masses of substances required are reived from the mole ratios given.

The grams of pigment needed:

mole ratios of CaCO3 and Cr2O3 is 1 : 1.52

Using the conversion factors:

molar mass of CaCO3 = 100.1 g

molar mass of Cr2O3 = 151.99 g

grams of pigment needed = (0.400 g CaCO3 x 1 mol CaCO3/100.1 g CaCO3) x (1.52 mol Cr2O3/1 mol CaCO3) x (151.99 g Cr2O3/1 mol Cr2O3) grams of pigment needed = 9.20 g Cr2O3

the grams of water needed:

mole ratio of CaCO3 and H2O is 1 : 27.5

molar mass of H2O = 18.0 g

the grams of water needed = 0.400 g CaCO3 x (1 mol CaCO3/100.1 g CaCO3) x (27.5 mol H2O/1 mol CaCO3) x (18.0 g H2O/1 mol H2O)

the grams of water needed = 0.199 g H2O

From the density of water, the volume of water needed is 0.199 mL of water.

Molarity = moles of solute/volume of solution in liters

Volume of solution = 0.000199 L

Number of moles of CaCO3 = 0.400/100.1 g

Number of moles of CaCO3 = 0.003998 mol

Molarity = 0.003998/0.000199

Molarity = 20.04 M

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at 300K, a sample of gas occupies 1.5 dm3.
Assuming the pressure remains constant, the volume of this gas at 600K would be?

Answers

If the pressure remains constant, the volume of the gas is directly proportional to the absolute temperature. The absolute temperature is the temperature in Kelvin (K) and is equal to the Celsius temperature (°C) plus 273.15.

So, to find the volume of the gas at 600K, we can use the formula:

(Volume at 600K) = (Volume at 300K) x (Temperature at 600K / Temperature at 300K)

(Temperature at 600K) = (600°C + 273.15) = 873.15K

(Temperature at 300K) = (300°C + 273.15) = 573.15K

So, the volume of the gas at 600K would be:

(Volume at 600K) = (1.5 dm³) x (873.15K / 573.15K) = 2.28 dm³

Therefore, the volume of the gas at 600K would be 2.28 dm³.

Write short note on the
-physical and chemical methods
of monitoring the rate of
chemical reaction

Answers

Answer:

Physical and chemical methods can be used to monitor the rate of a chemical reaction. Physical methods measure changes in properties like temperature, pressure, or volume. Chemical methods track reactant consumption or product formation using techniques like titration or spectrophotometry. The choice of method depends on the reaction being studied, and scientists use these methods to gain insight into reaction kinetics and optimize conditions for better efficiency and selectivity.

Given the reaction:


If there are initially 14.2 moles of iron (III) nitrate nonahydrate, how many moles of steam (water vapor) will be produced?

Answer in mol.

Answers

Total, 127.8 moles of the steam (water vapor) will be produced.

Iron(III) nitrate nonahydrate, or Fe(NO₃)₃·9H₂O, is a compound that contains iron (III) cations (Fe³⁺) and nitrate anions (NO₃⁻) combined with nine water molecules (H₂O) per formula unit. The nine water molecules are referred to as "nonahydrate," which indicates that there are nine water molecules associated with each formula unit of Fe(NO₃)₃. This compound is also commonly known as ferric nitrate nonahydrate.

Balanced equation for the given reaction is;

Fe(NO₃)₃·9H₂O(s) → Fe(NO₃)₃(s) + 9H₂O(g)

According to the equation, one mole of Fe(NO₃)₃·9H₂O produces 9 moles of water vapor (H₂O) when it undergoes the reaction. Therefore, if there are initially 14.2 moles of Fe(NO₃)₃·9H₂O, the number of moles of water vapor (H₂O) produced will be;

14.2 moles of Fe(NO₃)₃·9H₂O × 9 moles of H₂O per 1 mole of Fe(NO₃)₃·9H₂O = 127.8 moles of H₂O

Therefore, 127.8 moles of water vapor will be produced.

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What is hydrogen fuel cell technology

Answers

Answer:

By combining hydrogen and air in the presence of a catalyst, a fuel cell generates electricity to drive an electric motor, with water vapor as the only by-product. So, compared to a battery, a fuel cell is an energy converter rather than a storage device.

Explanation:

The heat of fusion of water is 79.9 cal/g. If a 7.2 g piece of ice melts in 105 g of water at 34.3 deg C in an insulated bottle, what is the final temperature of the water?

The heat of fusion of water is 79.9 cal/g. If a 7.2 g piece of ice melts in 105 g of water at 34.3 deg C in an insulated bottle, what is the final temperature of the water?

Type your answer...

Answers

The heat of fusion of water is 79.9 cal/g. If a 7.2 g piece of ice melts in 105 g of water at 34.3 deg C in an insulated bottle, 35071.6 °C is the  final temperature of the water.

The physical concept of temperature indicates in numerical form how hot or cold something is. A thermometer is used to determine temperature. Thermometers are calibrated using a variety of temperature scales, which historically defined distinct reference points or thermometric substances.

The most popular scales were the Celsius scale, sometimes known as centigrade, with the unit symbol °C, the scale of Fahrenheit (°F), or the Kelvin scale (K), with the latter being mostly used for scientific purposes.

Δ T = T(initial) - T(final)

T(final)= m × c × q - T(initial)

T(final)= 79.9 x 4.184 x 105 - 30.0

T(final)= 35071.6 °C

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6. Calculate the pH of a buffer prepared by mixing 0.10 mol-L-' acetic acid (CH;COOH, HAc) and
0.10 mol L NaOH solution with the volume ratio of 3:1. (Answer pH = 4.45

Answers

When acetic acid (HAc) reacts with sodium hydroxide (NaOH), it forms sodium acetate (NaAc) and water (H2O):

CH3COOH + NaOH → CH3COONa + H2O

The resulting solution will contain both the weak acid (HAc) and its conjugate base (Ac-). The pH of the buffer can be calculated using the Henderson-Hasselbalch equation:

pH = pKa + log([Ac-]/[HAc])

where pKa is the dissociation constant of HAc, [Ac-] is the concentration of the acetate ion, and [HAc] is the concentration of acetic acid.

The pKa of acetic acid is 4.76.

To calculate the concentrations of HAc and Ac-, we can use the volume ratio of 3:1 to find the total volume of the solution:

Total volume = 0.10 L HAc + 0.03 L NaOH = 0.13 L

The concentration of HAc is:

[HAc] = 0.10 mol / 0.13 L = 0.769 mol/L

The concentration of Ac- is:

[Ac-] = 0.03 mol / 0.13 L = 0.231 mol/L

Now we can substitute these values into the Henderson-Hasselbalch equation:

pH = 4.76 + log([0.231]/[0.769]) = 4.45

Therefore, the pH of the buffer is 4.45.
The pKa of acetic acid is 4.76. Therefore, the pH of the buffer can be calculated using the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA])

where [A-]/[HA] is the ratio of the concentration of the conjugate base to the concentration of the weak acid. In this case, acetic acid is the weak acid and its conjugate base is acetate (CH3COO-).

The volume ratio of the acetic acid and NaOH solutions is 3:1. Therefore, we can assume that we have 0.075 L of acetic acid solution and 0.025 L of NaOH solution.

The concentration of acetic acid is 0.10 mol-L¹. Therefore, the number of moles of acetic acid is:

moles of HAc = concentration × volume = 0.10 mol-L¹ × 0.075 L = 0.0075 mol

Since the volume of the NaOH solution is 0.025 L and its concentration is 0.10 mol-L¹, the number of moles of NaOH is:

moles of NaOH = concentration × volume = 0.10 mol-L¹ × 0.025 L = 0.0025 mol

The NaOH reacts with the HAc to form water and acetate:

NaOH + HAc → NaAc + H2O

Since the number of moles of NaOH is less than the number of moles of HAc, all of the NaOH will react with the HAc. Therefore, the number of moles of acetate formed is:

moles of acetate = moles of NaOH = 0.0025 mol

The number of moles of HAc remaining after the reaction is:

moles of HAc remaining = moles of HAc - moles of acetate = 0.0075 mol - 0.0025 mol = 0.0050 mol

The total volume of the buffer is 0.075 L + 0.025 L = 0.1 L. Therefore, the concentration of acetate is:

concentration of acetate = moles of acetate / volume of buffer = 0.0025 mol / 0.1 L = 0.025 mol-L¹

The concentration of HAc is:

concentration of HAc = moles of HAc remaining / volume of

We would like to find RDS using Tapel slope. Provide Tafel slope when we assume each step is RDS, alpha a=0.5 * Target Reaction : Cu oxidation [mV]

Mechanism1 Cu-> Cu2+ +2e-
Mechanism2 Cu-> Cu+ +e-
Cu+->Cu2+ +e-​

Answers

The Tafel slope for Mechanism 2 is the sum of the slopes of both steps, presuming that each step in Mechanism 2 is RCS::

b2 = b2_1 + b2_2 = 0.1184 + 0.1184 = 0.2368 V

How to solve

To identify the rate-controlling step (RCS) utilizing the Tafel slope, we initially need to calculate the Tafel slope for each suggested mechanism when the electron transfer coefficient (alpha, α) equals 0.5.

The target reaction involves Cu oxidation.

Mechanism 1:

Cu -> Cu²⁺ + 2e⁻

Mechanism 2:

Cu -> Cu⁺ + e⁻

Cu⁺ -> Cu²⁺ + e⁻

The Tafel slope (b) can be computed with the following formula:

b = (2.303 * R * T) / (α * n * F)

Where:

R signifies the gas constant (8.314 J/mol K)

T represents the temperature in Kelvin (let's assume 298 K, standard room temperature)

α denotes the electron transfer coefficient (0.5)

n is the number of electrons exchanged in the RCS

F is the Faraday constant (96,485 C/mol)

For Mechanism 1, n = 2 (since 2 electrons are exchanged in the rate-controlling step):

b1 = (2.303 * 8.314 * 298) / (0.5 * 2 * 96,485) = 0.0592 V

For Mechanism 2, we must examine both steps. Let's initially evaluate the Tafel slope for each step.

Step 1 (n = 1):

b2_1 = (2.303 * 8.314 * 298) / (0.5 * 1 * 96,485) = 0.1184 V

Step 2 (n = 1):

b2_2 = (2.303 * 8.314 * 298) / (0.5 * 1 * 96,485) = 0.1184 V

The Tafel slope for Mechanism 2 is the sum of the slopes of both steps, presuming that each step in Mechanism 2 is RCS::

b2 = b2_1 + b2_2 = 0.1184 + 0.1184 = 0.2368 V

Having obtained the Tafel slopes for both mechanisms, we can now compare them to the experimental Tafel slope to ascertain which mechanism is more likely the RCS.

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Calculate volume of 0.3 mole of hydrogen chloride

Answers

6.72L is the volume occupied by 0.3 mole of hydrogen chloride. A measurement of three-dimensional space is volume.

A measurement of three-dimensional space is volume. It is frequently expressed quantitatively using SI-derived units, like the cubic foot and litre, or different imperial or US-standard units, including the gallon, quart and cubic inch. Volume and length (cubed) have a symbiotic relationship. A container's capacity is typically thought of as being represented by its volume.

Volume = 0.3×22.4

            =6.72L

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Which type of symbiotic relationship best describes the relationship between cotton plants and wasps?

a: parasitic - the cotton plants are helped, but the wasps are harmed
b: commensal - the cotton plants are helped and the wasps are unaffected
c:mutualistic - both the cotton plants and the wasps are helped

Answers

Answer:

The answer is c. ( mutualistic ).

Explanation:

The relationship between cotton plants and wasps is an example of mutualism. The cotton plants provide a food source in the form of nectar for the wasps, and in return, the wasps serve as pollinators for the cotton plants, which helps the plants reproduce. This is a mutually beneficial relationship, as both species benefit from the interaction. Therefore, the answer is (c) mutualistic.

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How many mL of hydrogen chloride gas will be produced from 25.0 g of BaCl2 at STP? BaCl2(s) + H2SO4(aq) → BaSO4(aq) + 2HCl(g)

Answers

5380 mL of hydrogen chloride gas will produce 25.0 g of  BaCl₂ at STP.

To solve this problem, we need to use stoichiometry to determine the amount of hydrogen chloride gas produced from the given amount of BaCl₂.

First, we need to balance the chemical equation:

BaCl₂(s) + H₂SO₄(aq) → BaSO₄(aq) + 2HCl(g)

According to the balanced equation, 1 mole of BaCl₂ produces 2 moles of HCl.

The molar mass of BaCl₂ is 208.23 g/mol.

So, the number of moles of BaCl₂ in 25.0 g is:

n(BaCl₂) = mass ÷ molar mass = 25.0 g ÷ 208.23 g/mol = 0.120 mol

From the balanced equation, 1 mole of BaCl₂ produces 2 moles of HCl. Therefore, the number of moles of HCl produced is:

n(HCl) = 2 × n(BaCl₂) = 2 × 0.120 mol = 0.240 mol

At STP (standard temperature and pressure), 1 mole of any gas occupies 22.4 L.

Therefore, the volume of HCl gas produced at STP is:

V(HCl) = n(HCl) × 22.4 L/mol = 0.240 mol × 22.4 L/mol = 5.38 L

However, the question asks for the volume of hydrogen chloride gas in mL, so we need to convert the answer to mL:

1 L = 1000 mL

Therefore, V(HCl) = 5.38 L × 1000 mL/L = 5380 mL

So, 25.0 g of BaCl₂ at STP will produce 5380 mL of hydrogen chloride gas.

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3. If I have 3 moles of gas in a container with a volume of 60 liters and at a temperature of 400 K, what is the pressure inside the container?​

Answers

Answer:

The pressure would be 1.65 atmospheres.

Hi i need help figuring how many mol… please if you can hurry! Thank you

Answers

The number of moles is 0.001734 moles

The Ideal gas law is the equation of state of a hypothetical ideal gas. It is a good approximation to the behaviour of many gases under many conditions, although it has several limitations. The ideal gas equation can be written as

                                    PV = nRT

where,

P = Pressure

V = Volume

T = Temperature

n = number of moles

Given,

Volume = 3.4L

Pressure = 1.2 atm

Temperature = 283K

PV = nRT

1.2 × 3.4 = n × 8.314 × 283

n = 0.001734 moles

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How many moles of oxygen are in 2.71 x 1025 molecules of carbon dioxide (CO2)?

Answers

Answer:

There are 4.52 moles of oxygen in 2.71 x 10^25 molecules of carbon dioxide (CO2).

Explanation:

A student used 0.17 grams of Alka Seltzer for their experiment. What's the mass of sodium bicarbonate (NaHCO3) in their sample?

Answers

Answer:

To find the mass of sodium bicarbonate (NaHCO3) in a sample of Alka Seltzer that weighs 0.17 grams, we need to know the percentage of NaHCO3 in Alka Seltzer. This information is usually provided on the label of the product. Once we know the percentage of NaHCO3, we can use the following formula to calculate the mass of NaHCO3 in the sample:

mass of NaHCO3 = sample mass (in grams) x % NaHCO3 / 100

For example, if the percentage of NaHCO3 in Alka Seltzer is 50%, then the mass of NaHCO3 in a 0.17 gram sample would be:

mass of NaHCO3 = 0.17 x 50 / 100 = 0.085 grams

Therefore, the mass of sodium bicarbonate in the student's 0.17 gram sample of Alka Seltzer depends on the percentage of NaHCO3 in the Alka Seltzer, which should be provided on the product label.

Explanation:

Can anyone name this compound. Only number 4. and i would appreciate if you could explain how you name it.

Answers

The IUPAC name of the compound is 3-chloro-4-ethyl-2,4-dimethyloctane

How do i determine the name for the compound?

The naming of compound follows the IUPAC principles. This is illustrated below:

Locate the longest continuous carbon chain. In this case it is carbon 8. Thus, we can say that the parent name is octaneIdentify the substituent groups attached. In this case the substituent groups attached are: Cl, CH₃ and CH₂CH₃ Give the substituents the lowest count. In this case, Cl is located at carbon 3, CH₂CH₃ is located at carbon 4 and the two CH₃ are located at carbon 2 and 4Combine the above to obtain the IUPAC name for the compound.

Thus, the IUPAC name for the compound is: 3-chloro-4-ethyl-2,4-dimethyloctane

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Determine the pH of a solution that is 0.00501 M HCl and 0.0378 M HClO2. The a of HClO2 is 1.1×10−2
.

Answers

The acidity or alkalinity of a solution depends on the hydronium ion and hydroxide ion concentration. The pH scale is introduced by the scientist Sorensen. The pH of the solution is -1.90.

The pH of a solution is defined as the negative logarithm to the base 10 of the value of the hydronium ion concentration in moles per litre. The pH of the solution is given as:

pH = -log [H₃O⁺]

Dissociation of HCl is:

HCl + H₂O → H₃O⁺ + Cl⁻

Kₐ = [H₃O⁺][Cl⁻] / [HCl]

1.3 × 10⁶ = x × x / 0.00501

x² = 0.00501 × 1.3 × 10⁶ = 6513

x = √6513 = 80.7 M

HClO₂ + H₂O → H₃O⁺ + ClO⁻

Kₐ = [H₃O⁺][ClO⁻] / [HClO₂]

1.1×10⁻² = x² / 0.0378

x² = 0.0378 × 1.1×10⁻² = 0. 00041

x = 0.020 M

Thus the total concentration now is :

x = [H₃O⁺] = 0.020 +  80.7 = 80.72 M

pH = -log [H₃O⁺]

-log[80.72 ] = -1.90

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in general, which of the following statements about electron-pair geometries is true? question 14 options: a) they maximize the space between valence electrons to minimize the repulsion between them. b) they maximize the polarity of valence electrons to minimize the attraction between them. c) they maximize the space between

Answers

They maximise the distance between valence electrons to reduce the repulsion between them, which is option an in the correct response. This is so because the idea behind electron-pair geometries is to reduce valence electron repulsion.

By increasing the distance between them, which decreases the repelling power of the interactions between electrons, this is accomplished.

Because they reduce electron repulsion and enable molecules to adopt their most stable form, electron-pair geometries are used to anticipate the structure of molecules.

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Sometimes a fossil is formed as a result of the movement of an organism in soft sediment. Which of these are two kinds of trace fossils?
*
1 point
shells and bones
tracks and burrows
a bee and a beetle in amber
petrified and mummified fossils

Answers

Answer:The two kinds of trace fossils mentioned in the options are:

tracks

burrowsTracks and burrows are both examples of trace fossils, which are fossils thatprovide evidence of an organism's activity, rather than the organism itself.Tracks are impressions left by an organism's feet or other body parts as itmoved across soft sediment, while burrows are tunnels or other structurescreated by an organism as it burrowed into the sediment. Both types of tracefossils can provide valuable information about an organism's behavior, habitat, and interactions with other organisms.

What happens to a buffered solution
when a small amount of base is
added?

Answers

Answer: When you add small quantities of an acid or alkali (base) to it, its pH does not change significantly. In other words, the buffer solution stops the acid and base from neutralizing each other.

Answer:

 the result is a decrease in the amount of conjugate base present and an increase in the amount of the weak acid.

Explanation:

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