If the balls have a head-on, inelastic collision and the 2.0-kg ball recoils with a speed of 3.2 m/s, the kinetic energy lost in the collision is 364.6 J.
Using conservation of momentum, we can find the final velocity:
m1 * v1 + m2 * v2 = (m1 + m2) * vf
Solving for vf, we get:
vf = (m1 * v1 + m2 * v2) / (m1 + m2)
= (2.0 kg * 14 m/s + 6.3 kg * 4.0 m/s) / (2.0 kg + 6.3 kg)
= 6.0 m/s
The final total kinetic energy of the system is:
KEf = (1/2) * (m1 + m2) * vf^2
= (1/2) * 8.3 kg * (6.0 m/s)^2
= 112.2 J
The kinetic energy lost in the collision is the difference between the initial and final kinetic energies:
KE lost = KEi - KEf
= 476.8 J - 112.2 J
= 364.6 J
An inelastic collision is a type of collision between two or more objects in which the total kinetic energy of the system is not conserved. In an inelastic collision, some or all of the kinetic energy of the colliding objects is converted into other forms of energy such as heat, sound, or deformation of the objects.
In an inelastic collision, the colliding objects stick together after the collision and move with a common velocity. This is in contrast to an elastic collision, in which the colliding objects bounce off each other and the total kinetic energy of the system is conserved. Inelastic collisions can occur in many different situations, such as in car crashes, when two objects collide and stick together, or when a ball hits a wall and loses some of its kinetic energy due to deformation.
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Complete Question: -
Two balls with masses of 2.0 kg and 6.3 kg travel toward each other at speeds of 14 m/s and 4.0 m/s, respectively. If the balls have a head-on, inelastic collision and the 2.0-kg ball recoils with a speed of 3.2 m/s, how much kinetic energy is lost in the collision?
if one object has twice as much mass as another object, it also has twice as much inertia. volume. acceleration due to gravity. velocity. all of these
If one object has twice as much mass as another object, it also has twice as much inertia. The correct answer is "inertia".
What is inertia?Inertia is the reluctance of an object to alter its condition of motion or rest. The more massive an object is, the more difficult it is to move. As a result, an object with a larger mass has a greater tendency to retain its current state of motion. This trait of an object is referred to as inertia.
The mass of an object has an impact on its inertia. The more mass an object has, the greater its inertia is. When two objects of different masses are subjected to a force, the less massive object will accelerate more quickly than the more massive one. This is the result of the inertia of the more massive object.
Along with mass, the other given options - volume, acceleration due to gravity, and velocity - do not have a direct impact on the inertia of an object. Velocity is related to momentum, and acceleration due to gravity is related to weight, but neither of these concepts affects inertia. Hence, the correct option is inertia.
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an isotonic contraction is one that involves a change in length but not a change in tension. true or false
The given statement is false. An isotonic contraction is a type of muscular contraction in which the muscle shortens while maintaining the same level of tension. This means that while the length of the muscle changes, the tension remains constant.
What are isotonic contractions?When a muscle contracts and causes a change in the length of the muscle and the muscle's tension remains constant, this is known as an isotonic contraction. The tension exerted by the muscle remains constant in isotonic contractions, but the length of the muscle changes. Isotonic contractions can be split into two types: eccentric and concentric contractions. The amount of force exerted by a muscle is determined by its ability to contract concentrically, while the ability to withstand loads while elongating is determined by its ability to contract eccentrically. Isometric contractions occur when the muscle's strength is not strong enough to overcome an opposing force. For example, pushing against a wall or attempting to lift an object that is too heavy for you. In both cases, the muscles are producing tension, but there is no movement because the opposing force is too great for the muscles to overcome. Therefore, the given statement is false.
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a bicycle wheel has a radius of 0.304 m and a rim whose mass is 2.50 kg. the wheel has 50 spokes, each with a mass of 0.0100 kg. (a) calculate the moment of inertia of the rim about the axle. (b) determine the moment of inertia of any one spoke, assuming it to be a long, thin rod that can rotate about one end. (c) find the total moment of inertia of wheel, including the rim and all 50 spokes.
The moment of inertia of the bicycle wheel with radius of 0.304m and 50 spoke, rim with mass 2.50 kg for rim about the axle is 0.229 kg·m² , moment of inertia of any one spoke is 0.00186 kg·m² and moment of inertia of the wheel, including the rim and all 50 spokes is 0.592 kg·m².
(a) The moment of inertia of the rim about the axle, we use the formula for the moment of inertia of a thin hoop.
We substitute the mass of the rim and the radius of the wheel into the formula and get the moment of inertia of the rim
The moment of inertia of the rim about the axle:
[tex]I_{rim} = MR^2[/tex]
where M is the mass of the rim and
R is the radius of the wheel.
Substituting the given values, we get:
[tex]I_{rim} = (2.50 kg) *(0.304 m)^2 = 0.229 kg*m^2[/tex]
Therefore, the moment of inertia of the rim about the axle is 0.229 kg·m².
(b) The moment of inertia of any one spoke, we use the formula for the moment of inertia of a long, thin rod rotating about one end.
We substitute the mass of the spoke and its length into the formula and get the moment of inertia of one spoke.
[tex]I_{spoke} = (1/3)ML^2[/tex]
where M is the mass of the spoke and
L is its length.
Substituting the given values, we get:
[tex]I_{spoke} = (1/3) *(0.0100 kg)*(2 * 0.304 m)^2= 0.00186 kg*m^2[/tex]
Therefore, the moment of inertia of any one spoke is 0.00186 kg·m².
(c) The total moment of inertia of the wheel, we use the parallel axis theorem.
The moment of inertia of the wheel about the center of mass is given by:
[tex]I_{center} = I_{rim} + 50*I_{spoke}[/tex]
Substituting the values we found in parts (a) and (b), we get:
[tex]I_{center} = 0.229 kg*m^2 + 50 * 0.00186 kg*m^2 = 0.324 kg*m^2[/tex]
The distance between the center of mass and the axle is equal to the radius of the wheel, so we can use the parallel axis theorem to find the total moment of inertia:
[tex]I_{total} = I_{center} + Md^2[/tex]
where M is the total mass of the wheel (rim plus spokes) and
d is the distance between the center of mass and the axle.
Substituting the given values, we get:
M = 2.50 kg + 50 × 0.0100 kg = 3.00 kg
d = 0.304 m
[tex]I_{total} = 0.324 kg*m^2 + (3.00 kg) *(0.304 m)^2= 0.592 kg*m^2[/tex]
Therefore, the total moment of inertia of the wheel, including the rim and all 50 spokes, is 0.592 kg·m².
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given two identical iron bars, one of which is a permanent magnet and the other unmagnetized, how could you tell which is which by using only the two bars?
There are two identical iron bars, one of which is a permanent magnet and the other unmagnetized. We can identify that: when the magnetized bar is brought near the other bar, it will stick to it, indicating that it is magnetized. The bar that does not stick is unmagnetized.
Iron bars are used to make permanent magnets by a process called magnetization. Permanent magnets are composed of atoms and aligned electrons that have magnetic properties. The other bar that is not magnetized does not have aligned electrons, so it will not attract other magnets as a magnetized bar would.
The direction of a magnetic field will change when a magnet is brought near it. The North Pole will attract the South Pole, and they will come together. The North Pole will repel the North Pole, and the South Pole will repel the South Pole. The magnetized bar will be attracted to the unmagnetized bar, and the unmagnetized bar will not be attracted to the magnetized bar.
As a result, when the magnetized bar is brought near the other bar, it will stick to it, indicating that it is magnetized. The bar that does not stick is unmagnetized. Thus, with the aid of two bars, one magnetized and the other unmagnetized, we can determine which is which.
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what is the general process by which a large diffuse cloud of gas turns into a star and surrounding planets?
The general process by which a large diffuse cloud of gas turns into a star and surrounding planets are known as: star formation.
The Star Formation process starts with a giant molecular cloud of gas and dust, where the gravitational forces act on the cloud and it collapses under its own gravity. This collapse results in a disc-like structure, which is also known as a protoplanetary disc, and has the potential to form planets.
The center of the disc gets hotter and denser, and eventually, nuclear fusion begins, resulting in the formation of a star. The protoplanetary disc contains a lot of dust and gas, and as the temperature increases, some of the minerals and elements present in the dust start to melt and then solidify, eventually forming small planetesimals, which aggregate to form the larger planets.
As the planets move around in the disc, they can migrate inward and outward, and some can collide and merge with others, thus forming even larger planets.
The remaining gas and dust in the disc are eventually swept up by the planets or blown away by the star's radiation, and the planets settle into stable orbits. This is the general process by which a large diffuse cloud of gas turns into a star and surrounding planets.
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what was the peak vertical ground reaction force (not resultant force) from the beginning of the measurement through leaving the ground in your spreadsheet?
In the following question, among the conditions given, The peak vertical ground reaction force (not resultant force) from the beginning of the measurement through leaving the ground in your spreadsheet is the highest vertical force.
Hence The peak vertical ground reaction force (not resultant force) from the beginning of the measurement through leaving the ground in your spreadsheet is the highest vertical force that the ground exerts on your body during the time period in question. so then, in order To calculate this, you need to examine your spreadsheet and look for the highest vertical force value present in the data.
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how fast (in rpm) must a centrifuge rotate if a particle 8.50 cm from the axis of rotation is to experience an acceleration of 115000 g's? if the answer has 4 digits or more, enter it without commas, e.g. 13500.
The centrifuge must rotate at approximately 54959 rpm to produce an acceleration of 115000 g's at a distance of 8.50 cm from the axis of rotation.
To solve this problem, we can use the formula for centrifugal acceleration:
a = (r * w^2) / g
where a is the desired acceleration in units of g's, r is the distance of the particle from the axis of rotation, w is the angular velocity of the centrifuge in radians per second, and g is the acceleration due to gravity (approximately 9.81 m/s^2).
First, we need to convert the distance from centimeters to meters:
r = 8.50 cm = 0.085 m
Next, we can rearrange the formula to solve for the angular velocity w:
w = sqrt((a * g) / r)
Substituting the given values, we get:
w = sqrt((115000 * 9.81) / 0.085)
w = 5758.6 radians per second
Finally, we can convert the angular velocity from radians per second to revolutions per minute (rpm):
1 revolution = 2π radians
1 minute = 60 seconds
w (in rpm) = (w / 2π) * 60
w (in rpm) = (5758.6 / (2π)) * 60
w (in rpm) ≈ 54959
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the intensity of a sound wave at a fixed distance from a speaker vibrating at 1.4 khz is 0.683 w/m 2 . determine the intensity if the frequency is increased to 2.57 khz while a constant displacement amplitude is maintained. answer in units of w/m 2 .
The intensity of the sound wave at a fixed distance from the speaker vibrating at 2.57 kHz and maintaining a constant displacement amplitude is 2.25 W/m².
The intensity of a sound wave is directly proportional to the square of its frequency. Therefore, if the frequency of the speaker increases from 1.4 kHz to 2.57 kHz while maintaining a constant displacement amplitude, the intensity of the sound wave will increase by a factor of (2.57 kHz / 1.4 kHz)² = 3.29.
Thus, the new intensity of the sound wave will be 3.29 times the original intensity of 0.683 W/m², which gives us:
New intensity = 3.29 x 0.683 W/m² = 2.25 W/m²
Therefore, the intensity of the sound wave at a fixed distance from the speaker vibrating at 2.57 kHz and maintaining a constant displacement amplitude is 2.25 W/m².
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bohr developed an equation for calculating the energy levels of a hydrogen atom. which of the following can be determined using this equation? select all that apply.
Bohr developed an equation for calculating the energy levels of a hydrogen atom. Using this equation, the following can be determined:
The energy level of an electron
The angular momentum of an electron
The radius of the hydrogen atom's orbit
Around the nucleus of the hydrogen atom, the electrons move in circular orbits. Each of these orbits corresponds to a particular energy level.
Bohr's equation calculates these energy levels based on the electron's distance from the nucleus and its angular momentum.
Thus, by using Bohr's equation, we can determine the energy level of an electron, its angular momentum, and the radius of the hydrogen atom's orbit.
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I need help with this question
Answer:
The is answer C
Explanation:
The electrons are always on the outside and the positive are in the inside the nucleus
and the neutron are in the inside.
Answer:
the correct option is C
Explanation:
in the orbitals that surrounds the nucleus .
thank you.
which choice accurately describes what light is?responsesneither a particle nor a waveneither a particle nor a waveboth a particle and a waveboth a particle and a wave,only a particleonly a particleonly a waveonly a wave
The correct option is C. Both a particle and a wave accurately describe what light is. This is known as the wave-particle duality of light
Wave-particle duality is a fundamental concept in physics that describes the behavior of matter and energy at the atomic and subatomic scale. It states that matter and energy can exhibit both wave-like and particle-like behavior, depending on how they are observed or measured.
For example, light can be observed as both a wave and a particle, depending on the experiment. When it behaves as a wave, it exhibits characteristics such as diffraction, interference, and polarization. When it behaves as a particle, it exhibits characteristics such as energy and momentum. The wave-particle duality has significant implications for our understanding of the nature of reality and the fundamental laws of physics, and it has led to the development of many important technologies, such as lasers, transistors, and semiconductors.
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Complete Question: -
which choice accurately describes what light is? responses neither
A). a particle nor a wave neither
B). a particle nor a wave
C). both a particle and wave both a particle and a wave,
D). only a particle only a particle only a wave only a wave
a mass of 500g ball is kicked at angle of 45 degree to the horizontal the ball reaches 12m height what is the initial velocity
The initial velocity of a 500g ball kicked at a 45-degree angle to the horizontal and reaching a height of 12m can be calculated using the kinematic equation.
What is the kinematic equation?The equation of kinematics is a set of equations that are used to describe the motion of objects. They relate to displacement, velocity, acceleration, and time. Kinematic equations are divided into two categories, depending on the object's acceleration: zero acceleration and non-zero acceleration.
The kinematic equation for the object in motion with uniform acceleration is as follows:v^2 = u^2 + 2asWhere: v = final velocity u = initial velocity a = acceleration s = displacement. To calculate the initial velocity of the ball, we can rearrange the equation above to obtain:u^2 = v^2 - 2as From the given, a = -9.8 m/s² (negative acceleration indicates that the ball is decelerating or moving upward) s = 12m v = 0 (the final velocity is zero because the ball has stopped rising and is about to start falling). We'll use these values to calculate the initial velocity of the ball.u² = (0)² - 2(-9.8)(12)u² = 235.2u = sqrt(235.2)u = 15.33 m/s.
Therefore, the initial velocity of the ball is approximately 15.33 m/s.
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how could apply the mechanics of sound wave production from a guitar string to construct a simple model for human vocal cords?
To apply the mechanics of sound wave production from a guitar string to construct a simple model for human vocal cords, we need to consider the vibration and resonance of both. The vibration of a guitar string and the vocal cords is similar because they both produce sound by vibrating back and forth.
What is the mechanics of sound wave production?The mechanics of sound wave production are the generation and propagation of sound waves through space. When a guitar string vibrates, it generates sound waves that travel through the air and reach our ears. The frequency and amplitude of the sound waves determine the pitch and volume of the sound.
Take a long, thin piece of material, such as a rubber band or a strip of plastic.2. Stretch it taut between two points, such as two pencils or two pegs.3. Pluck the string with your finger and observe the vibration.4. Vary the tension and length of the string to produce different pitches.
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a soccer player kicks a rock horizontally off a 34 m high cliff into a pool of water. if the player hears the sound of the splash 2.78 s later, what was the initial speed given to the rock (in m/s)? assume the speed of sound in air is 343 m/s.
The initial speed given to the rock was approximately 100.96 m/s.
The time it takes for the rock to fall from the cliff to the water can be found using the kinematic equation,
h = 1/2gt^2
where h is the height of the cliff (34 m), g is the acceleration due to gravity (-9.81 m/s^2), and t is the time it takes for the rock to fall. Solving for t,
t = sqrt(2h/g) = sqrt(2 * 34 / 9.81) = 2.15 s
The horizontal velocity of the rock can be found using the equation,
v = d/t
where d is the horizontal distance the rock travels (unknown) and t is the time it takes for the rock to hit the water (2.78 s). We can use the speed of sound in air (343 m/s) to find the distance d, since the time it takes for the sound of the splash to reach the player is equal to the time it takes for the rock to travel that distance plus the time it takes for the sound to travel that same distance,
2.78 s = t + d/343
Solving for d,
d = (2.78 - t) * 343 = (2.78 - 2.15) * 343 = 217.11 m
Now that we know the horizontal distance the rock travels, we can find its initial velocity using the equation,
v = d/t = 217.11/2.15 = 100.96 m/s
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T or F: Surface currents flow vertically in the uppermost 400 meters of the water column. False (horizontally).
The given statement, "surface currents flow vertically in the uppermost 400 meters of the water column," is false because surface currents flow horizontally in the uppermost 400 meters of the water column. They move water parallel to the surface, driven by factors such as wind and temperature differences.
Surface currents are driven by the wind, and they are characterized by movement across the surface of the water. The direction and intensity of surface currents are influenced by a variety of factors, including wind speed and direction, the shape of the coastline, and the rotation of the Earth. These currents are an essential component of the ocean circulation system and can have a significant impact on the climate and the distribution of marine life. They flow parallel to the water columns in the uppermost parts.
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6. A pulley, of radius R and moment of inertia 1 = 2 MR2, is mounted on an axle with
negligible friction. Block A with a mass M and Block B with a mass 3M are attached to a
light string that passes over the pulley. Assuming that the string doesn't slip on the
pulley, answer the following questions in terms of M, R, and fundamental constants.
Expres
angular
a.
What is the acceleration of the two blocks?
b. What is the tension force in the left section of the string?
c. What is the tension force in the right section of the string?
d. What is the angular acceleration of the pulley?
The acceleration of the two blocks is g/4.
Tension force in the left section of the string is 5/4 Mg
Tension force in the right section of the string is 3/4 Mg
Angular acceleration of the pulley is 0.
How to calculate acceleration, tension force and angular acceleration?a. The acceleration of the two blocks can be found by applying Newton's second law to each block. For Block A, the force equation is:
T - Mg = Ma
where T is the tension force in the string, M is the mass of Block A, g is the acceleration due to gravity, and a is the acceleration of Block A. For Block B, the force equation is:
3Mg - T = 3Ma
where T is the tension force in the string and a is the acceleration of Block B. Since the string is assumed to be light and inextensible, the tension force in both sections of the string is the same.
The two equations can be solved simultaneously to obtain the acceleration: a = g/4
b. To find the tension force in the left section of the string, we can use the force equation for Block A:
T - Mg = Ma
Substituting the value of acceleration we obtained in part a:
T = 5/4 Mg
c. To find the tension force in the right section of the string, we can use the force equation for Block B:
3Mg - T = 3Ma
Substituting the value of acceleration we obtained in part a, and the value of T we obtained in part bt:
T = 3/4 Mg
d. To find the angular acceleration of the pulley, we can use the torque equation:
Iα = Στ
where I is the moment of inertia of the pulley, α is the angular acceleration, and Στ is the net torque acting on the pulley.
The tension force in the string exerts a torque on the pulley, given by:
τ = TR
where R is the radius of the pulley. Since the tension force is the same on both sides of the pulley, the net torque is zero. Thus, we have:
Iα = 0 which implies that the angular acceleration of the pulley is zero.
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Which label identifies a rarefaction?
O A
Ов
O C
OD
In the longitudinal wave ,B represents the phenomenon of rarefaction. Rarefaction refers to the region of a sound wave where the pressure of the medium is lower than its normal value.
What is rarefaction?Rarefaction is a term used to describe a decrease in the density or pressure of a substance, such as a gas or liquid. In the context of sound waves, rarefaction refers to the region of a sound wave where the pressure of the medium is lower than its normal value, causing the particles of the medium to be spread further apart than usual.
Sound waves are composed of regions of compression and rarefaction that alternate in a regular pattern as the wave travels through a medium. In a compressional (longitudinal) sound wave, the particles of the medium are pushed together in regions of compression, while they are spread apart in regions of rarefaction. These changes in pressure and density cause the wave to propagate through the medium.
In general, rarefaction can occur in any medium, not just in sound waves. For example, in a gas, rarefaction can be caused by a decrease in pressure, temperature or density. In a liquid, rarefaction can be caused by a decrease in pressure or density. Rarefaction waves can be observed in many natural phenomena, such as atmospheric pressure waves, seismic waves, and waves on the surface of water.
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how close would the masses 0.510 kg and 0.108 kg have to be in order for the gravitational force between them to have a magnitude of 1.03 n?
The gravitational force between two masses is inversely proportional to the square of the distance between them. This means that the two masses must be much closer together for the force to be 1.03 N. The masses 0.510 kg and 0.108 kg have to be 0.285 m apart in order for the gravitational force between them to have a magnitude of 1.03 N.
The equation for gravitational force is F=G*m1*m2/d^2, where G is the gravitational constant, m1 and m2 are the two masses, and d is the distance between them.
Assuming G=6.67*10^(-11) Nm^2/kg^2, m1=0.510 kg, and m2=0.108 kg, then d=0.285 m. This is the minimum distance between the two masses for the gravitational force between them to have a magnitude of 1.03 N.
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a tow rope is being used to tow 10 skiers up a ski hill at a constant speed. the average mass of the skiers is 66.0 kg. the hill is inclined at 8.5 degrees. the power output of the motor is 4.70 kw. with what maximum speed can the skiers be towed? assume that there is negligible friction.
The average mass of the skiers is 66.0 kg. The power output of the motor is 4.70 kw. The maximum speed at which the skiers can be towed is 4.21 m/s.
Since there are 10 skiers, the total mass is:
M = 10m = 10(66.0 kg) = 660.0 kg
The force exerted by the tow rope is:
F = Mg sin([tex]\theta[/tex])
F = (660.0 kg)(9.81 m/s^2) sin(8.5 degrees)
F = 1117.9 N
Now, we can use the equation P = Fv to solve for the maximum speed at which the skiers can be towed:
v = P/F
v = (4.70 kW)/(1117.9 N)
v = 4.21 m/s
Speed is a fundamental concept in physics and is used to describe the motion of objects. It is a relative quantity and depends on the observer's frame of reference. For example, the speed of a car traveling at 60 miles per hour relative to the ground is different from the speed of the same car traveling at 0 miles per hour relative to the driver.
Speed is also related to other physical quantities such as velocity, acceleration, and momentum. Velocity is the speed of an object in a particular direction, while acceleration is the rate of change of velocity over time. Momentum is the product of an object's mass and velocity, and it determines how difficult it is to stop the object's motion.
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the star sirius is 8.6 light-years from earth (in our earth-based reference frame). suppose you traveled from earth to sirius at 0.92 c . during your trip, how far would you measure the distance from earth to sirius to be?
Answer:
L = L0 (1 - v^2 / c^2)^1/2
L0 is the proper length and L the distance measured by the space traveler
L = L0 (1 - .92^2)^1/2
L = L0 * .39 = 8.6 L-y * .39 = 3.4 L-y as measured by space traveler
suppose that you are standing on a surface that is so slick that you can get no traction at all in order to begin moving across the surface. fortunately you are carrying a bag of oranges. how can you get yourself moving to the right?
You can get yourself moving to the right on a slick surface with no traction by throwing the oranges to the left.
Actions and reactionsOne possible way to get moving to the right on a slick surface with no traction is to throw the oranges to the left in a series of quick and forceful motions.
According to Newton's third law of motion, every action has an equal and opposite reaction. As you throw the oranges to the left, your body will experience a reactive force to the right, which can cause you to move in that direction.
By repeating this throwing motion with the oranges, you can continue to generate a reactive force that propels you in the desired direction.
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6. a 21.00-kg child initially at rest slides down a playground slide from a height of 3.40 m above the bottom of the slide. if her speed at the bottom is 2.30 m/s, how much energy is lost due to friction?
If a 21.00-kg child slide from a height of 3.40 m above the bottom of the slide and her speed at the bottom is 2.30 m/s, the amount of energy lost due to friction is 644.18 J.
The potentiаl energy of аn object depends on the locаtion of the object from the bottom reference floor аnd the mаss of the object. The аmount of energy contаins by the object аt аny height is known аs the potentiаl energy of thаt object.
We are given:
The energy of the child at the upper end of the slide is,
[tex]E_{u}[/tex] = mgh
Substitute the values in the above equation
[tex]E_{u}[/tex] = 21 kg × 9.8 m/s2 × 3.40 m
= 699.72 J
The energy at the bottom of the slide is,
[tex]E_{b}[/tex] = [tex]\frac{1}{2}(mv^{2})[/tex]
Substitute the values in the above equation.
[tex]E_{b}[/tex] = [tex]\frac{1}{2}(21.2.30^{2})[/tex]
[tex]E_{b}[/tex] = 55.54 J
The energy lost due to friction is,
[tex]E_{f}[/tex] = [tex]E_{u}[/tex] - [tex]E_{b}[/tex]
Substitute the values in the above equation
[tex]E_{f}[/tex] = 699.72 - 55.54
[tex]E_{f}[/tex] = 644.18 J
Thus, the energy lost due to friction is 644.18 J.
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x < If a heater is used for 2 hours and an electric motor for 4 hours, they consume 25 kJ of energy. If the heater is used for 3 hours and the electric motor for 2 hours, they consume 18 kJ of energy. Calculate the energy consumption per hour of the heater and of the electric motor
The energy consumption per hour of the heater is 9 kJ/hour and the energy consumption per hour of the electric motor is 3 kJ/hour.
What is the energy consumption rate?Let's denote the energy consumption per hour of the heater as "h" and the energy consumption per hour of the electric motor as "m".
From the first piece of information, we can set up the equation:
2h + 4m = 25 (equation 1)
Similarly, from the second piece of information, we can set up another equation:
3h + 2m = 18 (equation 2)
We now have two equations with two unknowns, which we can solve using algebraic methods. Multiplying equation 2 by 2 and subtracting it from equation 1 multiplied by 3, we get:
(3h + 6m) - 2(3h + 2m) = 25(3) - 18(2)
Simplifying this expression, we get:
h = 9
Substituting this value of h into equation 2, we get:
3(9) + 2m = 18
Simplifying this expression, we get:
m = 3
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the grand coulee dam is 1270. m long and 170. m high. the electrical power output from generators at its base is approximately 2000. mw. how many cubic meters of water must flow from the top of the dam per second to produce this amount of power if 92% of the work done on the water by gravity is converted to electrical energy? (each cubic meter of water has a mass of 1000. kg .)
Hence, 127.2 m3/s per second is the required water flow rate from the dam's crest.
What is a second?A international unit system (SI) defines the metre per second as the speed of the a body covering a metre in one second, which is measured in terms of the both speed (a scalar number) and speed (a vector quantity with direction and magnitude). m/s, m/s1, m/s, or ms are the SI unit symbols.
How do you calculate a second?Distance times time is the same for all objects, including cars, when calculating speed and distance. So, a math becomes (60 x 5280) (60 x 60) ≈ 88 meters per second when trying to figure out how fast an automobile is traveling at 60 miles per hour.
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what are the major factors in explaining why some jovian moons are more geologically active than terrestrial worlds of similar or larger sizes?
The major factors in explaining why some Jovian moons are more geologically active than terrestrial worlds of similar or larger sizes are the effects of tidal heating and the presence of a large planetary body providing gravitational forces.
The main factors geologically active than terrestrial worlds are also because:
The effects of Tidal heating is caused by the gravitational force of the large planetary body the moon orbits, which cause the moon to flex and deform internally, releasing energy as heat. This process is more pronounced in moons of Jovian planets due to the stronger gravitational pull of these much larger bodies. This heat is then released through the moon’s surface, causing geological activity. Terrestrial worlds do not experience such a strong gravitational pull and therefore do not experience this form of tidal heating.Overall the combination of tidal forces, volatile materials, lack of atmospheric erosion, and different composition can all contribute to the greater geological activity seen in some Jovian moons compared to terrestrial worlds
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g which of the following statements is correct about this circuit? the equivalent resistance of the circuit is the algebraic sum of all resistors. all of these options are true. total voltage on this combination is an algebraic sum of voltages on each resistor. currents through all resistors are the same.
The following statement is true about this circuit: option (A) The equivalent resistance of the circuit is the algebraic sum of all resistors.
This means that the total resistance of the circuit is equal to the sum of the individual resistances of each resistor. The total voltage on this combination is an algebraic sum of voltages on each resistor. This means that the total voltage of the circuit is equal to the sum of the voltages across each individual resistor.
The currents through all resistors are the same. This means that the total current that flows through the circuit is the same as the current that flows through each individual resistor.
To summarize, in a series circuit the equivalent resistance, total voltage, and current are equal to the algebraic sum of all the individual resistances, voltages, and currents respectively.
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how do the vertical and horizontal components of velocity change for a ball tossed at an upward angle?
When a ball is thrown at an upward angle, the vertical and horizontal components of velocity change in different ways. The vertical component of velocity decreases to a certain point before increasing again due to gravity. However, the horizontal component of velocity remains constant throughout the motion of the ball.
When a ball is tossed at an upward angle, the velocity has two components; vertical and horizontal components. The horizontal component is unaffected since there is no force acting on it.
The vertical component is influenced by the gravitational force acting on the ball. As the ball goes up, the vertical component of velocity decreases to zero. The maximum point is reached when the ball's velocity is zero. At this point, the ball stops going up and starts going down. As the ball falls, the vertical component of velocity increases in the opposite direction to the gravitational force acting on it.
Therefore, the vertical component of velocity changes as the ball is tossed at an upward angle. It increases, then decreases to zero at the top of its trajectory, and then increases again as the ball falls back to the ground. The horizontal component of velocity is constant throughout the motion of the ball because there is no force acting on it.
Hence, when a ball is tossed at an upward angle, the vertical and horizontal components of velocity change in different ways.
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suppose you were dragging a table across a rough floor. in this case, the potential energy for friction depends on which quantity or quantities? (choose all that apply)
In dragging a table across a rough floor, the potential energy for friction depends on the coefficient of friction, normal force, and distance traveled by the table, hence option (a), (b), and (c) are correct.
In this case, the potential energy for friction would depend on the following quantities:
Coefficient of friction: The coefficient of friction between the table and the floor would determine how much force is required to move the table and hence, the potential energy for friction.
Normal force: The normal force acting on the table due to the weight of the table and any objects placed on it would also affect the potential energy for friction.
Distance moved: The distance the table is moved would determine the amount of work done against friction and hence, the potential energy for friction.
Surface area: The surface area in contact between the table and the floor could also affect the potential energy for friction.
Overall, the potential energy for friction depends on a combination of factors, including the properties of the surfaces in contact, the force required to move the object, and the distance moved.
Therefore correct options are (a), (b), and (c).
Suppose you were dragging a table across a rough floor. in this case, the potential energy for friction depends on which quantity or quantities? (choose all that apply)
a. The total distance the table travels.
c. The coefficient of friction between the table and the floor.
d. The normal force that the floor exerts on the table.
e. There is no potential energy for frictional forces.
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Do any of the force pairs suggested in Question 5 not produce an acceleration? If so which one(s).
A. A skier uses her ski poles to start moving downhill
B. A boat propeller spins rapidly in the water
C. A baseball player hits a pitched ball with a bat
D. A party balloon contains rapidly moving helium atoms
All of the given options produce an acceleration that are force pairs suggested in Question 5.
When a skier uses her ski poles to start moving downhill then the ski poles exert a backward force on the ground while the ground exerts a forward force on poles and produces acceleration.
Similarly in case B. when a boat propeller spins rapidly in the water the propeller exert a backward force on the water while the water exerts a forward force on propeller and produces acceleration.
In case C. when a baseball player hits a pitched ball with a bat the bat exert a backward force on the ball while the ball exerts a force away from bat and produces acceleration.
In case D. when a party balloon contains rapidly moving helium atoms the helium atoms exert an outward force on the balloon while the balloon exerts an inward force on helium atoms and produces acceleration.
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What is the kinetic energy of the ball as it is halfway through the fall from a forty foot building? What is the potential energy?
Answer:
The kinetic energy is more than half of its maximum energy