The specific heat of other liquid is 2.09 J/g°C.
Using the formula Q = mcΔT, where Q is amount of heat lost, m is the mass of liquid, c is specific heat of liquid, and ΔT is the change in temperature, we can set up two equations for each liquid.
For water, Q = (50 + 30)g × 4.18 J/g°C × (30 - 25)°C = 1045 J
For other liquid, Q = 100g × c × (30 - 25)°C = 500c J
Since both liquids lost same amount of heat, took same amount of time to cool, we can set these two equations equal to each other and solve for c: 1045 J = 500c J, c = 2.09 J/g°C
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--The correct Question is, A mass of 50 g of a certain metal at 150 degree C is immersed in 100 g of water at 11 degree C. The final temperature is 20 degree C. Calculate the specific heat capacity of the metal. Assume that the specific heat capacity of water is 4.2Jg −1 K−1 .--
what wavelength em radiation would be emitted most strongly by matter at the temperature of the core of a nuclear explosion, about 10,000,000 k?
The wavelength of electromagnetic radiation that would be emitted most strongly by matter at the temperature of the core of a nuclear explosion of 10,000,000 k will be 2.898 × 10^-10 meters.
Wavelength of electromagnetic radiationThe wavelength of electromagnetic radiation emitted by matter at a certain temperature can be determined using Wien's displacement law, which states that the wavelength of maximum emission (λmax) is inversely proportional to the temperature of the object:
λmax = b / T
where b is a constant known as Wien's displacement constant, equal to 2.898 × 10^-3 m·K.
Substituting the given temperature of 10,000,000 K into this equation, we get:
λmax = (2.898 × 10^-3 m·K) / (10^7 K) = 2.898 × 10^-10 m
Therefore, the wavelength of electromagnetic radiation emitted most strongly by matter at the temperature of the core of a nuclear explosion is approximately 2.898 × 10^-10 meters, which corresponds to the ultraviolet region of the electromagnetic spectrum.
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a rock attached to a string swings in a vertical circle. which free body diagram could correctly describe the force(s) on the rock when the string is in one possible horizontal position?
The correct free body diagram that describes the forces on the rock when the string is in one possible horizontal position is B.
As the rock swings in a vertical circle, there are a number of forces acting upon it. These forces are gravity, tension and centrifugal force. When the rock is in a horizontal position, its weight will be perpendicular to the tension force. This makes the tension force the only force acting upon the rock in the horizontal position.
As a result, the correct free body diagram that describes the forces acting on the rock when the string is in one possible horizontal position is B.
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when you switch off the lights in your room at night, the walls, ceiling, and floor are at a temperature of about 300 k. why are you not dazzled by the radiation that they emit?
Answer:
Explanation:
Because by Wien's Law, they emit strongest in infrared and human eyes cannot see infrared radiation
a small bok globule has a diameter of 20 seconds of arc. if the nebula is 1000 pc from earth, what is the diameter of the globule?
The diameter of the globule is approximately 0.295 light years if the nebula is 1000 pc from earth.
To answer the question, we need to use the formula of trigonometric parallax. The formula is given below:
diameter of the globule = diameter of the nebula × angular diameter of the globule
Angular diameter of the globule is given to us as 20 seconds of arc. Angular diameter is the angle subtended by the diameter of an object at a distance of 1 parsec. Therefore, we have the value of the angular diameter of the globule.Now, to find the diameter of the globule, we need to find the diameter of the nebula. The nebula is at a distance of 1000 parsecs from earth. We don't have the value of the diameter of the nebula.
So, we can assume that the nebula is circular in shape. We can then use the formula for the distance of an object from the observer to find the diameter of the nebula. The formula is given below:
d = 2 × r × tan θ
Where,d = distance of the object from the observer,θ = angular size of the object,r = radius of the object.Since we have the distance of the object and the angular size of the object, we can find the radius of the object.
r = (d/2) × tan θ
Now, we can find the diameter of the nebula.
Diameter = 2 × radius
Diameter = d × tan θ
Therefore, Diameter = 2 × (1000/2) × tan θDiameter = 1000 × tan θ
Now, we can find the diameter of the globule using the formula mentioned above.Diameter of the globule = Diameter of the nebula × angular diameter of the globule
Diameter of the globule = 1000 × tan θ × 20 arcseconds
Diameter of the globule = 1000 × tan (20/3600) pc
Diameter of the globule = 0.0905 pc
Now, we convert the diameter into light years.1 pc = 3.26 light years
Therefore, the diameter of the globule in light years is:
Diameter of the globule = 0.0905 × 3.26 light years
Diameter of the globule = 0.295 light years
Therefore, the diameter of the globule is approximately 0.295 light years.
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your instructor challenges you and your friend to pull on the ends of a horizontal rope attached to a pair of scales in a tug-of-war, but in such a way that the scale readings on the scales are different. can this be done? explain.
Answer:
If the scale readings are different then there will be a net force on the person attached to the scales:
Consider any point on the rope - if the forces in each direction are the same there is no acceleration of the rope
F = Δm * a for any portion of the rope with mass Δm
If any portion of the rope is accelerated, the person attached to the rope must be accelerated
What is the concept of Schrodinger about nature of electron?
Answer: The behaviour of electrons inside atoms could be explained by treating them mathematically as waves of matter
Explanation:
Erwin Schrödinger proposed the quantum mechanical model of the atom, which treats electrons as matter waves.
Answer:
[tex]According \: to \: Schrodinger \: \\ model, \: nature \: of \: electron \: \\ in \: an \: atom \: is \: as \: wave \: \\ only
[/tex]
suppose an asteroid had an orbit with a semimajor axis of 4 au. how long would it take for it to orbit once around the sun? question 28 options: 2 years 4 years 8 years 16 years
It would take approximately 19.2 years for the asteroid to orbit once around the sun. But that none of the answer choices match the calculated value of approximately 19.2 years.
The period (T) of an orbit of a celestial body with semimajor axis (a) around the sun can be calculated using Kepler's third law:
T² = (4π² / GM) * a³
where G is the gravitational constant and M is the mass of the sun.
Plugging in the given value for the semimajor axis (a = 4 AU), we get:
T² = (4π² / (6.674 × 10⁻¹¹ m³/(kg s²) * 1.989 × 10³⁰ kg)) * (4 AU)³
T² = 3.652 × 10¹⁶ s²
Taking the square root of both sides, we get:
T = 6.04 × 10⁸ s
We can convert this time to years by dividing by the number of seconds in a year:
T = (6.04 × 10⁸ s) / (31,536,000 s/year)
T ≈ 19.2 years
Therefore, it would take approximately 19.2 years for the asteroid to orbit once around the sun. The closest answer choice is 16 years.
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a bike and rider, 82.0 kg combined mass, are traveling at 4.2 m/s. a constant force of -140 n is applied by the brakes in stopping the bike. what braking distance is needed?
The bike and rider must halt at a breaking distance of 5.17 meters.
What is the formula for braking distance?d=2.2v+fracv220 gives the braking distance, in feet, of a car moving at v miles per hour. Most motorcycle riders have a maximum braking force (what an experienced rider can do) of about 1 G, which, at 45 mph, results in a complete stop of the motorcycle in 67 feet (20 meters).
To resolve this issue, we can apply the equation of motion for uniformly accelerated motion:
v² = u² + 2as
To solve for s, we can rewrite the equation as follows:
s = (v² - u²) / (2a)
We are aware that the acceleration is determined by dividing the net force by the mass:
a = F_net / m
where m is the mass and F net is the net force.
a = F_net / m = -140 N / 82.0 kg
= -1.71 m/s²
We may now change the values for s in the equation:
s = (0² - 4.2²) / (2*(-1.71))
= 5.17 m
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a square loop 5 cm on each side carries a 500 ma current. the loop is within a uniform magnetic field of 1.2t. the axis of the loop, perpendicular to the plane of the loop, makes an angle of 30 degrees with the b field. what is the magnitude of the torque on the current loop?
The magnitude of the torque on the current loop is calculated using the formula τ=BIA sinθ, where B is the magnitude of the magnetic field, I is the current, A is the area of the loop, and θ is the angle between the magnetic field and the loop's plane. In this case, the magnitude of the torque is τ = (1.2 T)(0.5 A)(5 cm x 5 cm)sin(30°) = 7.5 x 10-3 Nm.
The torque is the rotational force that causes the loop to rotate. This is due to the fact that a force is exerted on the loop by the magnetic field when there is a current running through it. This force generates a torque on the loop, which will cause it to rotate until the angle between the plane of the loop and the magnetic field is 0°.
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a bowling ball has a mass of 6 kg. if you slowly roll the ball off the edge of a table 1.5 m high table, what is the kinetic energy of the ball when it hits the ground?
The kinetic energy of the ball when hits the ground is 88.2 J
The formula for calculating kinetic energy is
KE = 1/2mv²
Where KE is kinetic energy, m is mass, and v is velocity.
We have, the mass of the bowling ball is 6 kg, and it is dropped from a height of 1.5 m, we can calculate its velocity just before it hits the ground as follows:
Potential energy = mgh
Where m = mass of the object = 6 kg
g = acceleration due to gravity (9.8 m/s²), and
h = height from which the object is dropped = 1.5 m
PE = mgh
= (6 kg)(9.8 m/s²)(1.5 m)
= 88.2 J
The potential energy of the bowling ball is 88.2 J.
This is equal to its kinetic energy just before it hits the ground.
Therefore, the kinetic energy of the ball is 88.2 J.
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What arguments did he use to prove that he was right?did be used experiments, logic, finding of other scientists or other approaches
In science, arguments to prove a hypothesis or theory can be supported by various approaches such as experiments, logic, findings of other scientists, and other approaches.
Experiments are a common method used to support arguments in science. They involve carefully designed procedures to test a hypothesis or theory and collect data that can be analyzed to support or refute the hypothesis or theory. The data collected can be used to provide evidence for the argument being made.
Logic is also used in science to support arguments. Logical reasoning involves using a set of premises or assumptions to arrive at a conclusion. Scientists often use logic to develop hypotheses and theories that can be tested through experiments or other means.
Findings of other scientists can also be used to support arguments. When multiple studies or experiments have been conducted on a particular topic, scientists may review and analyze the findings to arrive at a conclusion. The consensus among the scientific community can lend weight to an argument.
Other approaches to support arguments in science may include mathematical models, simulations, and observations. In general, scientists use a variety of approaches to support their arguments and conclusions in order to ensure that their findings are as accurate and reliable as possible.
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a pendulum is measured to swing back and forth 15 times in 10 seconds. what is the length of the string?
The length of the string is 0.48 m.
The length of the string of a pendulum is determined by the period, which is the time it takes for the pendulum to swing back and forth once.
String length = (Gravitational acceleration x (Period)2) / (4π2)
Where Gravitational acceleration is the acceleration due to gravity, which is 9.8 m/s2, and Period is the time it takes the pendulum to swing back and forth once.
The period is 10 seconds divided by 15 swings, or 0.67 seconds.
String length = (9.8 m/s2 x (0.67 s)2) / (4π2) = 0.48 m.
Therefore, the length of the string is 0.48 m.
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You're designing an external defibrillator that discharges a capacitor through the patient's body, providing a pulse that stops ventricular fibrillation. Specifications call for a capacitor storing 250 J of energy; when discharged through a body with R = 48 Ω transthoracic resistance, the capacitor voltage is to drop to half its initial value in 10 ms.
A) Determine the capacitance (to the nearest ) 10 μF).
B) Determine initial capacitor voltage (to the nearest 100 V) that meet these specs.
I need both correct answers to 2 significant figures.
a..... 1.04 x 10⁻⁴ Vi
b.... 9500 V
A) Determine the capacitance (to the nearest 10 μF).
First, we should identify the formula that we will use to solve the problem.
The formula that relates to capacitance is:
C = 2E / V². Where C is the capacitance in farads, E is the energy stored in joules, and V is the voltage across the capacitor in volts.
Converting the energy to joules, we have: E = 250J.
Now we know that the voltage needs to drop to half of its initial value in 10 ms. We can use the following formula to calculate the capacitance: C = R x t / ln(Vi / Vf) where R is the resistance in ohms, t is the time in seconds, Vi is the initial voltage, and Vf is the final voltage, which is half of the initial voltage.
B) Plugging in the given values, we get:
C = 48 x 0.01 / ln(Vi / (Vi / 2))Simplifying and solving for capacitance, we get:
C = 1.04 x 10⁻⁴ ViNow we can use the energy formula to solve for Vi:Vi = √(2E / C)
Plugging in the given values, we get:Vi = √(2 x 250 / 1.04 x 10⁻⁴)Simplifying and solving for Vi, we get:Vi = 9469 V
Therefore, the capacitance that meets these specifications is 100 μF and the initial capacitor voltage that meets these specifications is 9500 V, to the nearest 100 V.
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a rifle is fired with angle of elevation . what is the muzzle speed if the maximum height of the bullet is ft?
The muzzle speed of the bullet fired from the rifle is approximately 1349.1 ft/s.
When a rifle is fired with an angle of elevation, the muzzle speed can be determined if the maximum height of the bullet is known.
The formula for finding the muzzle speed of a bullet fired from a rifle is given by;v = sqrt((gH) / sin(2θ))
where;v = Muzzle speed of the bulletg = Acceleration due to gravityH = Maximum height of the bulletθ = Angle of elevation.
Thus, the muzzle speed of the bullet can be found.SolutionIn the given problem, the angle of elevation of the rifle is not given, but we have been given the maximum height of the bullet.
Muzzle speed of,
v = sqrt((gH) / sin(2θ)) , We have been given that the maximum height of the bullet is 375 ft.
Therefore, H = 375 ft.We are supposed to find the muzzle speed of the bullet. Therefore, we will represent the muzzle speed of the bullet by v.
We have been given the value of the acceleration due to gravity, which is;g = 32 ft/s²Now, we have to find the value of θ, which is the angle of elevation of the rifle.
The value of θ, we will use the formula for finding the maximum height of a projectile given by;H = (v²sin²θ) / (2g)We have been given that H = 375 ft, g = 32 ft/s².
Rearrange the formula for H to get;θ = sin⁻¹(2gH / v²)θ = sin⁻¹((2×32×375) / v²)θ = sin⁻¹(24000 / v²)Using a scientific calculator, we will find thatθ ≈ 21.37°
The muzzle speed;v = sqrt((gH) / sin(2θ))v = sqrt((32 × 375) / sin(2 × 21.37)), v ≈ 1349.1 ft/s. Therefore, the muzzle speed of the bullet fired from the rifle is approximately 1349.1 ft/s.
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Two aircraft are flying toward each other at the same speed. They each emit a 800 HZ whine. what speed (km/hr) must each aircraft have an order that pitch they both hear is 2 times the emitted frequency. Hint: the speed of sound is 343m/s
Each aircraft must be moving at a speed of 85.75 km/hr towards each other to hear a pitch that is 2 times the emitted frequency.
What is frequency ?
Frequency is a physical quantity that describes the number of occurrences of a repeating event per unit of time. It is often measured in Hertz (Hz), which represents the number of cycles or vibrations per second.
In the context of waves, such as sound waves or electromagnetic waves, frequency refers to the number of complete cycles of the wave that occur in one second. A high frequency wave has more cycles per second than a low frequency wave.
Frequency is also an important concept in physics, particularly in the study of oscillations and waves. It is used to describe the behavior of systems that oscillate or vibrate, such as a simple pendulum or a guitar string. In these cases, the frequency of the oscillation is related to the natural frequency of the system, which is determined by its mass, stiffness, and other properties.
When two aircraft are moving towards each other, the sound waves from each aircraft are compressed, leading to a higher pitch than the emitted frequency. The pitch heard by the pilots of the aircraft can be calculated using the following formula:
Pitch heard = Emitted frequency * (Speed of sound + Speed of observer) / (Speed of sound - Speed of source)
Since the two aircraft are flying towards each other at the same speed, we can assume that the speed of one aircraft is x km/hr, and the speed of the other aircraft is also x km/hr. Therefore, the relative speed between the two aircraft is 2x km/hr.
Substituting the values given in the formula, we get:
2 * Emitted frequency = Emitted frequency * (343 + 2x) / (343 - x)
Simplifying this equation, we get:
686 - 2x = 343 + 2x
4x = 343
x = 85.75 km/hr
Therefore, each aircraft must be moving at a speed of 85.75 km/hr towards each other to hear a pitch that is 2 times the emitted frequency.
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a 20-tooth spur pinion has a diametral pitch of 12 teeth/in, runs at 2100 rev/min, and drives a gear at a speed of 1400 rev/min. find the number of teeth on the gear and the theoretical center-to-center distance.
The number of teeth on the driven gear is 14 and the theoretical center-to-center distance is 3.34 inches.
Speed Ratio: Speed Ratio = (Number of Teeth on Driven Gear)/(Number of Teeth on Driving Gear). The Speed Ratio = 1400 rev/min/2100 rev/min = 0.6667.
Therefore, the number of teeth on the driven gear = (Number of Teeth on Driving Gear) x (Speed Ratio) = 20 x 0.6667 = 13.33. Rounding up, we can conclude that the number of teeth on the driven gear is 14.
The next step is to find the theoretical center-to-center distance. To do this, we need to use the formula for calculating Pitch Diameter: Pitch Diameter = (Number of Teeth)/(Diametral Pitch).
In this case, the Pitch Diameter of the driving gear is (20 teeth)/(12 teeth/in) = 1.67 inches. Therefore, the center-to-center distance = Pitch Diameter x 2 = 1.67 inches x 2 = 3.34 inches.
Hence the number of teeth on the driven gear is 14 and the theoretical center-to-center distance is 3.34 inches.
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blood flows with a speed of 30 cm/s along a horizontal tube with a cross-section diameter of 1.6 cm. what is the blood flow speed in the part of the same tube that has a diameter of 0.8 cm?
Blood flows with a speed of 30 cm/s along a horizontal tube with a cross-section diameter of 1.6 cm.The speed of blood flow in the part of the same tube that has a diameter of 0.8 cm is 15 cm/s.
To arrive at this answer, we can use the formula for the flow rate of a fluid in a pipe:
Q = A × V
where Q is the flow rate, A is the cross-sectional area of the pipe, and V is the velocity of the fluid.
Therefore, if we substitute the values for A and V of the first section, we can calculate the flow rate for that section:
Q1 = A1 × V1
Q1 = π ×(1.6 cm/2)² × 30 cm/s
Q1 = 24.72 cm³/s
Now we can use the flow rate and the cross-sectional area of the second section to calculate the velocity of the fluid:
Q1 = A2 × V2
V2 = Q1 / A2
V2 = 24.72 cm³/s / (π × (0.8 cm/2)²)
V2 = 15 cm/s
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josh punches his open left hand with his right hand. which statement is true about the forces his two hands exert on each other?
Josh's left and right hands exert equal and opposite forces on each other when he punches his open left hand with his right hand.
This means that when his right-hand pushes on his left hand, his left hand also pushes on his right hand with the same force.
This is Newton's Third Law of Motion:
"For every action, there is an equal and opposite reaction."
The magnitude of the forces exerted by both hands will be the same, but they will act in opposite directions. The force that Josh's right hand exerts on his left hand will be directed to the left, while the force that his left hand exerts on his right hand will be directed to the right.
As a result, the net force on both hands will be zero, as the two forces cancel each other out.
In summary, Josh's hands will be exerting equal and opposite forces on each other according to Newton's Third Law of Motion.
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according to our textbook, what is the best way to defend ourselves against an asteroid which is on course to collide with the earth in 7 years?
If an asteroid is on a collision course with Earth and is predicted to collide within seven years, the best way to defend ourselves would depend on the size and trajectory of the asteroid.
What is an asteroid ?An asteroid is a small, rocky object that orbits the Sun. Most asteroids are found in the asteroid belt, a region between the orbits of Mars and Jupiter. Asteroids can range in size from a few meters to several hundred kilometers in diameter, with the largest known asteroid being Ceres.
Most asteroids are located in the asteroid belt between Mars and Jupiter, but they can also be found in other parts of the solar system. Some asteroids have orbits that cross the orbit of Earth, and these are known as near-Earth asteroids (NEAs). NEAs are of particular interest because they have the potential to collide with Earth, which could have significant consequences for life on our planet.
Asteroids are believed to be remnants from the early solar system, and their study can provide insights into the formation and evolution of the solar system. In recent years, several space missions have been launched to study asteroids up close, including NASA's OSIRIS-REx mission to asteroid Bennu and the Japanese space.
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a 0.170-kg baseball traveling 30.0 m/s strikes the catcher's mitt, which, in bringing the ball to rest, recoils backward 15.0 cm . what was the magnitude of the average force applied by the ball on the glove?
The magnitude of the average force applied by the ball on the glove is 34 N.
The magnitude of the average force applied by the ball on the glove.
This can be done by using the equation for force, F = ma, where F is the force, m is the mass of the object, and a is the acceleration of the object.
The mass of the ball is 0.170 kg, and the acceleration is determined by the change in velocity of the ball and the distance the glove recoils, 15 cm, or 0.15 m.
Therefore, the acceleration of the ball is a = (30.0 m/s - 0 m/s)/(0.15 m) = 200 m/s^2.
Since we have the mass and the acceleration, we can calculate the force with the equation above. F = (0.170 kg)(200 m/s^2) = 34 N. Therefore, the magnitude of the average force applied by the ball on the glove is 34 N.
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if a truck has a linear acceleration of 1.85 m/s2 and the wheels have an angular acceleration of 5.23 rad/s2, what is the diameter of the truck's wheels?
If a truck has a linear acceleration of 1.85 m/s² and the wheels have an angular acceleration of 5.23 rad/s², the diameter of the truck's wheels 0.71 m.
What is the difference between linear acceleration and angular acceleration?Linear acceleration refers to the time rate of change of linear velocity, whereas angular acceleration refers to the time rate of change of angular velocity. This is the primary differential between linear and angular acceleration. Simply said, changes in an object's linear velocity with respect to time are represented by changes in linear acceleration.
The angular acceleration can be deduced immediately from the concept of α =ΔωΔt because the ultimate angular velocity and time are both provided.
The link between linear acceleration (a) and rotational acceleration is expressed as a = r×α . When the angular acceleration increases, so will the linear acceleration's strength. Increased wheel angular acceleration, for instance, denotes an accelerated vehicle.
Linear acceleration is the uniform acceleration caused by a moving body moving along a straight line. There are three equations that are essential in linear acceleration, depending on parameters like start and terminal velocities, displacements, times, and acceleration.
Given :
linear acceleration a = 1.85 m/s²
angular acceleration α = 5.23 rad/s²
radius r = a/ α = [tex]\frac{1.85}{5.23}[/tex] = 0.354 m
diameter d = 2r = 2 × 0.354 = 0.71 m
diameter of the wheels is 0.71 m.
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a box rests on an incline. if the coefficient of static friction between the box and the incline is 0.400, at what minimum angle would the box begin to move?
The minimum angle at which the box would begin to move is given by the equation $\mu_{s} = \tan{\theta}$,is 21.8°.
Let's consider the following diagram: In the above, m is the mass of the box, θ is the angle of the incline, N is the normal force, f is the force of friction, and mg is the gravitational force acting on the box in the downward direction.
The box will be at the threshold of sliding up or down the plane when the gravitational force acting down the plane is greater than the frictional force acting up the plane. Therefore, the minimum angle at which the box will start to move is:tanθ = μswhere μs is the coefficient of static friction=0.4 (Given). Thus,θ= tan-1 (0.4)θ = 21.8 degrees.
Therefore, the box will start to move when the angle of inclination of the plane is 21.8 degrees (minimum angle).
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gold has a specific gravity of almost 20. a 5-gallon bucket of water weighs 40 pounds. how much would a 5-gallon bucket of gold weigh? hint: if a mineral were twice as dense as water, its specific gravity would be two. water has a specific gravity of 1.
A 5-gallon bucket of gold would weigh 86.84 pounds.
A five-gallon bucket of water weighs 40 pounds. Gold has a specific gravity of almost 20.
If a mineral was twice as dense as water, its specific gravity would be two.
Water has a specific gravity of 1.
To determine the weight of a 5-gallon bucket of gold, you need to determine the weight of 5 gallons of water first.One gallon of water weighs approximately 8.33 pounds; hence 5 gallons of water weigh 41.65 pounds.
Now, divide the weight of 5 gallons of water (41.65) by the specific gravity of gold (20):41.65/20 = 2.0825
The weight of a five-gallon bucket of gold would be 2.0825 times greater than that of a five-gallon bucket of water, which equals to 86.84 pounds (40 pounds + 46.84 pounds).
Therefore, a 5-gallon bucket of gold would weigh approximately 86.84 pounds.
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65. a 150-w lightbulb emits 5% of its energy as electromagnetic radiation. what is the radiation pressure on an absorbing sphere of radius 10 m that surrounds the bulb?
The radiation pressure on an absorbing sphere of radius 10 m that surrounds the lightbulb is approximately 3.98 x 10^-13 Pa.
The radiation pressure on an absorbing sphere can be calculated using the formula,
P = (2 * I) / c
where P is the radiation pressure, I is the intensity of the radiation, and c is the speed of light.
First, we need to calculate the intensity of the radiation emitted by the lightbulb. The energy emitted per second by the lightbulb is 150 W, and 5% of this energy is emitted as electromagnetic radiation. Therefore, the energy emitted as radiation is,
E = 150 W * 0.05 = 7.5 W
The intensity of the radiation is the power per unit area, and can be calculated by dividing the energy emitted per second by the surface area of a sphere with a radius of 10 m,
I = E / (4 * pi * r^2) = 7.5 W / (4 * pi * 10^2 m^2) = 5.98 x 10^-5 W/m^2
Now we can calculate the radiation pressure, P = (2 * I) / c = (2 * 5.98 x 10^-5 W/m^2) / 3 x 10^8 m/s = 3.98 x 10^-13 Pa
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(a) when a 9.00-v battery is connected to the plates of a capacitor, it stores a charge of 27.0 mc. what is the value of the capacitance? (b) if the same capacitor is connected to a 12.0-v battery, what charge is stored?
The formula for calculating capacitance is as follows:
C = Q/V
Where,
C = capacitance (Farads)
Q = charge (Coulombs)
V = voltage (Volts)
As given,
Q = 27.0 μC
V = 9.00 V
Substituting the given values in the above equation
C = 27.0 μC/9.00 V = 3.00 μF
Therefore, the value of capacitance is 3.00 μF.
The formula for calculating charge stored is as follows:
Q = CV
Where,
Q = charge (Coulombs)
C = capacitance (Farads)
V = voltage (Volts)
As given,
C = 3.00 μF
V = 12.0 V
Substituting the given values in the above equation,
Q = (3.00 × 10⁻⁶ F) × 12.0 V = 36.0 μC
Therefore, the charge stored is 36.0 μC.
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why is it likely that saturn's volcanically active moon, enceladus, is being powered by tidal heating?
Enceladus, Saturn's volcanically active moon, is likely being powered by tidal heating because of its unique geological features and position in relation to Saturn.
Tidal heating is a process that occurs when the gravitational forces between two celestial bodies cause the internal structure of one or both bodies to heat up, producing volcanic activity and other geologic features.
Enceladus is located very close to Saturn and is constantly being tugged by the planet's gravitational forces, causing the moon to flex and bend as it orbits.
This tidal flexing generates friction within the moon's interior, which in turn generates heat. This heat is what is thought to be responsible for the volcanic activity observed on Enceladus.
In addition to its position relative to Saturn, Enceladus also has a unique geological feature that supports the idea of tidal heating.
The moon has a series of fractures on its surface known as "tiger stripes," which are believed to be the result of the internal heating caused by tidal forces.
These fractures release jets of water vapor and other material into space, providing evidence of the moon's volcanic activity.
The evidence suggests that Enceladus is being powered by tidal heating. T
This process is not unique to Enceladus; other moons in our solar system, such as Jupiter's Io and Neptune's Triton, are also believed to be volcanically active due to tidal heating.
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NEED HELP ASAP!!!!!!!!!!!!
Part B
Tape a meter stick to the side of the table. Make sure the zero end is on the floor. Carry out the experiment using the four drop heights you chose in task 1, part D. (You may want to have an adult drop the ball while you watch how high it bounces.) Perform three trials for each drop height, and record the data in the table. (You may choose to video the bounces and watch the video in slow motion to improve your data collection.) Finally, average the bounce height measurements to get a final reading. Round the average bounce heights to the nearest whole number.
Drop Height
First Drop
Bounce Height
Second Drop
Bounce Height
Third Drop
Bounce Height
Average Bounce Height
how fast is it moving when it reaches the top of its trajectory if the projectile is fired at a speed of 138 and an upward angle of 65 degrees?
The projectile will be moving at a speed of 57.21 m/s when it reaches the top of its trajectory.
When a projectile is fired at a speed of 138 and an upward angle of 65 degrees, the speed at the top of the trajectory can be calculated. To solve this problem, you need to understand some basic physics concepts. Here's how you can solve this problem:
1. First, identify the given values and write them down:
Initial velocity (u) = 138 m/s
Angle of projection (θ) = 65 degrees
Acceleration due to gravity (g) = 9.81 m/s²
2. Now, break down the initial velocity into its horizontal and vertical components:
Initial velocity in the horizontal direction = u cos θ
Initial velocity in the vertical direction = u sin θ
3. Use the equation of motion to calculate the time taken by the projectile to reach the top of its trajectory:
u sin θ = gt/2
t = 2u sin θ/g
4. Use the time obtained in step 3 to calculate the velocity at the top of the trajectory:
v = u cos θ
Where,
v = final velocity
u = initial velocity
θ = angle of projection
5. Substitute the given values in the equation to get the final answer:
v = u cos θ
v = 138 cos 65
v = 57.21 m/s
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how does the plot differ from the plots for tube radius, viscosity, and tube length? how well did the results compare with your prediction
The plot differs for tube radius, viscosity, and tube length in terms of their effect on fluid flow. The effect of each parameter is analyzed and plotted against the velocity profile of the fluid flow.
For tube radius, as the radius increases, the fluid flow velocity increases as well. This can be observed in the plot where the velocity profile is a bell-shaped curve, with the peak shifting to the right as the radius increases.
For viscosity, the effect is the opposite. As viscosity increases, the fluid flow velocity decreases. This can be observed in the plot where the velocity profile is a flatter curve, with a smaller peak as the viscosity increases.
For tube length, there is a similar effect as tube radius. As the length increases, the fluid flow velocity decreases. This can be observed in the plot where the velocity profile is a bell-shaped curve, with the peak shifting to the left as the length increases.
In terms of the comparison with the prediction, the results were mostly in line with what was expected. The plots showed the expected trends for each parameter, and the quantitative analysis confirmed this as well. However, there were some discrepancies between the predicted and actual values, which could be due to experimental error or limitations in the model used.
Overall, the results provided valuable insights into the relationship between these parameters and fluid flow, and can be used to optimize fluid systems for various applications.
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what is the difference between a planetary fly by and a planetary orbit insertion. list more than 7 thing for each. use this link to find the answer https://solarsystem.nasa.gov/basics/chapter16-1. if you make the answer on table it will great thank please it is due today.
The major objective of a flyby spacecraft is to watch and record without getting snared by the planet's gravity, which is why flyby spacecraft should not be mistaken with orbiter spacecraft.
Flyby of the PlanetsAs a result of all the interplanetary navigation and course corrections completed during the mission, the spacecraft is positioned at the exact right spot and time to conduct its encounter observations. Data collection by a flyby spacecraft is not always possible.planets' orbits: A spaceship carrying out an orbiter mission must employ the same extremely precise interplanetary navigation and course correction techniques as those used for flyby missions. In order to enter planetary orbit, this technique positions the spacecraft exactly where it needs to be at the right time. Together with exact positioning and timing, controlled deceleration is also necessary for orbit insertion.For more information on planetary flyby and orbit kindly visit to
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