8.41 > 8.051
the digit after the decimal point is greater on 8.41 (4) than on 8.051 (0)
Put these numbers in order from least to greatest. -27/36, 6, 18/40, 5/20
We have four numbers. We have to know that negative numbers are "smaller" than positive numbers, and when numbers are far away from zero are even "bigger".
The least number is -27/36. It is a negative number.
We can also see that we have some fractions. A fraction is a part of "a whole".
So, as we can see 6 is not a fraction. Therefore, 6 is the greatest number from this list.
So we have the least and the greatest: -27/36 and 6, respectively.
We also need to compare 18/40 and 5/20. What fraction is bigger?
In order to compare them, we need to have two fractions with the same denominator. Then, the fraction with the greatest numerator is "bigger" than the other fraction.
Let us see:
If we divide the numerator and the denominator of 18/40 by 2, we have:
18/2 = 9
40/2 = 20
Then, the equivalent fraction is 9/20 (or 9/20 is equivalent to 18/40). Now, we can compare them:
9/20 and 5/20. So, which one is the greatest? The one with the greatest numerator: 9/20.
Our final list is this way, from least to the greatest as follows:
-27/36, 5/20, 18/40 (9/20), 6.
In the accompanying diagram of circle O, COA is adiameter, O is the origin, OA = 1, and mLBOA = 30. Whatare the coordinates of B?
Given:
COA is a diameter
O is the origin
OA = 1
m< BOA = 30
Re-drawing the diagram to show the coordinates of the B:
Let the coordinates of B be (x,y)
Using trigonometric ratio, we can find the length of side AB
From trigonometric ratio, we have:
[tex]tan\text{ }\theta\text{ = }\frac{opposite}{adjacent}[/tex]Substituting we have:
[tex]\begin{gathered} tan\text{ 30 = }\frac{y}{1} \\ Cross-Multiply \\ y\text{ = tan30 }\times\text{ 1} \\ y\text{ = 0.577} \\ y\text{ }\approx\text{ 0.58} \end{gathered}[/tex]Hence, the coordinates of B is (1, 0.58)
An online bookstore is having a sale. All paperback books are $6.00 with a flat shipping fee of $1.25. you purchase "b" booms and your total is "c". What is the independent variable?$6.00"c" cost"b" books$1.25
Let:
c = total
a = cost of each book
w = flat shipping fee
Therefore, the total is given by:
[tex]c=ab+w[/tex]where:
b = number of books
[tex]c=6x+1.25[/tex]The independent variable is:
"b" books
Compute P(7,4)
From probability and statistics
The resultant answer from computing P(7,4) from probability and statistics is 840.
What is probability?The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true. An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty.The probability is computed by dividing the total number of possible outcomes by the number of possible ways the event could occur.So, P(7,4):
This is a permutation and can be calculated as:
ₙPₓ= n! / (n - x)!Here, n = 7 and x = 4Put the values in the given formula:
P(7, 4) = 7! / (7 - 4)!P(7, 4) = 7! / 3!P(7, 4) = 840Therefore, the resultant answer from computing P(7,4) from probability and statistics is 840.
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a sample size 115 will be drawn from a population with mean 48 and standard deviation 12. find the probability that x will be greater than 45. round the final answer to at least four decimal places
B) find the 90th percentile of x. round to at least two decimal places.
The probability that x will be greater than 45 is 0.1974.
The 90th percentile of x is 63.3786
Given,
The sample size drawn from a population = 115
The mean of the sample size = 48
Standard deviation of the sample size = 12
a) We have to find the probability that x will be greater than 45.
Here,
Subtract 1 from p value of the z score when x = 45
Then,
z = (x - μ) / σ
z = (45 - 48) / 12 = -3/12 = -0.25
The p value of z score -0.25 is 0.8026
1 - 0.8026 = 0.1974
That is,
The probability that x will be greater than 45 is 0.1974.
b) We have to find the 90th percentile of x.
Here,
p value is 0.90
Then, z score will be equal to 1.28155
Now find x.
z = (x - μ) / σ
1.28155 = (x - 48) / 12
15.3786 = x - 48
x = 15.3786 + 48
x = 63.3786
That is,
The 90th percentile of x is 63.3786
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Given the following absolute value function sketch the graph of the function and find the domain and range.
ƒ(x) = |x + 3| - 1
pls show how did u solve it
In order to sketch the graph we need to find the vertex and two more points to connect with the vertex.
To do so set the inside of absolute value to zero:
x + 3 = 0x = - 3The y-coordinate of same is:
f(-3) = 0 - 1 = - 1.So the vertex is (- 3, - 1).
Since the coefficient of the absolute value is positive, the graph opens up, and the vertex is below the x-axis as we found above.
Find the x-intercepts by setting the function equal to zero:
|x + 3| - 1 = 0x + 3 - 1 = 0 or - x - 3 - 1 = 0x + 2 = 0 or - x - 4 = 0x = - 2 or x = - 4We have two x-intercepts (-4, 0) and (-2, 0).
Now plot all three points and connect the vertex with both x-intercepts.
Now, from the graph we see there is no domain restrictions but the range is restricted to y-coordinate of the vertex.
It can be shown as:
Domain: x ∈ ( - ∞, + ∞),Range: y ∈ [ - 1, + ∞)Answer:
Vertex = (-3, -1).y-intercept = (0, 2).x-intercepts = (-2, 0) and (-4, 0).Domain = (-∞, ∞).Range = [-1, ∞).Step-by-step explanation:
Given absolute value function:
[tex]f(x)=|x+3|-1[/tex]
The parent function of the given function is:
[tex]f(x)=|x|[/tex]
Graph of the parent absolute function:
Line |y| = -x where x ≤ 0Line |y| = x where x ≥ 0Vertex at (0, 0)Translations
[tex]f(x+a) \implies f(x) \: \textsf{translated $a$ units left}.[/tex]
[tex]f(x-a) \implies f(x) \: \textsf{translated $a$ units right}.[/tex]
[tex]f(x)+a \implies f(x) \: \textsf{translated $a$ units up}.[/tex]
[tex]f(x)-a \implies f(x) \: \textsf{translated $a$ units down}.[/tex]
Therefore, the given function is the parent function translated 3 units left and 1 unit down.
If the vertex of the parent function is (0, 0) then the vertex of the given function is:
⇒ Vertex = (0 - 3, 0 - 1) = (-3, -1)
To find the y-intercept, substitute x = 0 into the given function:
[tex]\implies \textsf{$y$-intercept}=|0+3|-1=2[/tex]
To find the x-intercepts, set the function to zero and solve for x:
[tex]\implies |x+3|-1=0[/tex]
[tex]\implies |x+3|=1[/tex]
Therefore:
[tex]\implies x+3=1 \implies x=-2[/tex]
[tex]\implies x+3=-1 \implies x=-4[/tex]
Therefore, the x-intercepts are (-2, 0) and (-4, 0).
To sketch the graph:
Plot the found vertex, y-intercept and x-intercepts.Draw a straight line from the vertex through (-2, 0) and the y-intercept.Draw a straight line from the vertex through (-4, 0).Ensure the graph is symmetrical about x = -3.Note: When sketching a graph, be sure to label all points where the line crosses the axes.
The domain of a function is the set of all possible input values (x-values).
The domain of the given function is unrestricted and therefore (-∞, ∞).
The range of a function is the set of all possible output values (y-values).
The minimum of the function is the y-value of the vertex: y = -1.
Therefore, the range of the given function is: [-1, ∞).
a certain number was multiplied by 3. then, this product was divided by 10.2. finally, 12.4 was subtracted from this quotient, resulting in a difference of -8.4. what was this number
Answer:
13.6
Step-by-step explanation:
[tex] \frac{3x}{10.2} - 12.4 = - 8.4[/tex]
[tex] \frac{3x}{10.2} = 4[/tex]
[tex]3x = 40.8[/tex]
[tex]x = 13.6[/tex]
A ball bounces to a height of 6.1 feet on the first bounce. Each subsequent bounce reaches a height that is 82% of the previous bounce. What is the height, in feet, of the fifth bounce? Round your answer to the thousandths place.
In the first bounce, the height is
[tex]6.1\times(0.82)^0=6.1[/tex]In the second bounce, the height is
[tex]6.1\times(0.82)^2=5.002[/tex]Then, we can note that the pattern is
[tex]6.1\times(0.82)^{n-1}[/tex]where n represents the number of bounces of the ball. Then, for n=5 (fifth bounce), we get
[tex]\begin{gathered} 6.1\times(0.82)^{5-1} \\ 6.1\times(0.82)^4 \end{gathered}[/tex]which gives
[tex]6.1\times(0.82)^4=2.7579[/tex]Therefore, by rounding to the nearest thousandths, the answer is 2.758 feet
three more than the difference of five and a number
Answer:
5x+3
Step-by-step explanation:
Three more than means we add 3
The product of 5 and a number means some number multiplied by 5 call it 5x
so three more than 5x is 5x+3.
Given the points (3, -2) and (4, -1) find the slope
Slope is
[tex]\text{slope}=\frac{y2-y1}{x2-x1}[/tex]Then:
[tex]\text{slope}=\frac{-1-(-2)}{4-3}=\frac{-1+2}{1}=\frac{1}{1}=1[/tex]Answer: slope = 1
given the parent function f (x) identify whether g (x) is a reflection about a horizontal line of reflection or vertical line of reflectionf (x) = 6^x and g (x) = - (6^x)
The relation between this two functions is g(x) = -f(x)
This means that g(x) is a reflection of f(x) about the x-axis, that is, a reflection about a horizontal line
write an equation that gives the proportinal relationship of the graph
Answer:
y=5x
Explanation:
The slope-intercept form of the equation of a line is:
[tex]y=mx+b\text{ where }\begin{cases}m=\text{slope} \\ b=y-\text{intercept}\end{cases}[/tex]First, we find the slope of the line by picking two points from the line.
• The points are (0,0) and (3,15).
[tex]\begin{gathered} \text{Slope},m=\frac{Change\text{ in y-axis}}{Change\text{ in x-axis}}=\frac{15-0}{3-0}=\frac{15}{3} \\ \implies m=5 \end{gathered}[/tex]Next, the line crosses the y-axis at y=0.
Therefore, the y-intercept, b=0.
Substitute m=5 and b=0 into the slope-intercept form:
[tex]\begin{gathered} y=5x+0 \\ \implies y=5x \end{gathered}[/tex]The equation that gives the proportional relationship of the graph is y=5x.
Use the sample data and confidence level given below to complete parts (a) through (d). A drug is used to help prevent blood clots in certain patients. In clinical trials, among 4519 patients treated with the drug. 133 developed the adverse reaction of nausea Construct a 90% confidence interval for the proportion of adverse reactions. a) Find the best point estimate of the population proportion p.
We will have the following:
*First: We determine the standard deviation of the statistic, this is:
[tex]\sigma=\sqrt[]{\frac{\sum ^{133}_1(x_i-\mu)^2}{N}}[/tex]So, we will have:
[tex]\mu=\frac{\sum^{133}_1x_i}{N}\Rightarrow\mu=\frac{8911}{133}\Rightarrow\mu=67[/tex]Then:
[tex]\sigma=\sqrt[]{\frac{\sum^{133}_1(x_i-67)^2}{133}}\Rightarrow\sigma=\sqrt[]{\frac{196042}{133}}\Rightarrow\sigma=\sqrt[]{1474}\Rightarrow\sigma=38.39270764\ldots[/tex]And so, we obtain the standar deviation.
*Second: We determine the margin of error:
[tex]me=cv\cdot\sigma[/tex]Here me represents the margin of error, cv represents the critical value and this is multiplied by the standard deviation. We know that the critica value for a 90% confidence interval is of 1.645, so:
[tex]me=1.645\cdot38.39270764\ldots\Rightarrow me=63.15600407\ldots\Rightarrow me\approx63.156[/tex]*Third: We determine the confidence interval as follows:
[tex]ci=ss\pm me[/tex]Here ci is the confidence interval, ss is the saple statistic and me is the margin of error:
[tex]ci\approx133\pm63.156\Rightarrow ci\approx(69.844,196.256)[/tex]And that is the confidence interval,
40. Coach Hesky bought 3 new uniforms for his basketball team. He spent a total of $486. If the same amount was spent on each uniform, how much did he spend per player? .
new uniforms = 3
Total amount spent = $486
Amount spent per player = $486 /3 = $162
Segment AB and segment CD intersect at point E. Segment AC and segment DB are parallel.
To begin we shall sketch a diagram of the line segments as given in the question
As depicted in the diagram, line segment AC is parallel to line segment DB.
This means angle A and angle B are alternate angles. Hence, angle B equals 41 degrees. Similarly, angle C and angle D are alternate angles, which means angle C equals 56.
Therefore, in triangle EAC,
[tex]\begin{gathered} \angle A+\angle C+\angle AEC=180\text{ (angles in a triangle sum up to 180)} \\ 41+56+\angle AEC=180 \\ \angle AEC=180-41-56 \\ \angle AEC=83 \end{gathered}[/tex]The measure of angle AEC is 83 degrees
Identify the graph that has a vertex of (-1,1) and a leading coefficient of a=2.
To determine the vertex form of a parabola has equation:
[tex]f(x)=a(x-h)^2+k[/tex]where V(h,k) is the vertex of the parabola and 'a' is the leading coefficient.
From the question, we have that, the vertex is (-1, 1)
and the leading coefficient is a = 2
We substitute the vertex and the leading coefficient into the vertex form to
get:
[tex]\begin{gathered} f(x)=2(x+1)^2\text{+}1 \\ f(x)=2(x+1)^2+1 \end{gathered}[/tex]The graph of this function is shown in the attachment.
Hence the equation of parabola is
[tex]f(x)=2(x+1)^2+1[/tex]11. Let the supply and demand functions for sugar is given by the following equations. Supply: p = 0.4x Demand: p = 100 - 0.4x (a) Find the equilibrium demand.
SOLUTION:
Step 1:
In this question, we are given the following:
Let the supply and demand functions for sugar be given by the following equations. Bye
Supply: p = 0.4x
Demand: p = 100 - 0.4x
a) Find the equilibrium demand.
Step 2:
At Equilibrium,
[tex]\begin{gathered} \text{Supply}=\text{ Demand} \\ 0.\text{ 4 x = 100 - 0. 4 x} \end{gathered}[/tex]collecting like terms, we have that:
[tex]\begin{gathered} 0.4\text{ x + 0. 4 x = 100} \\ 0.8\text{ x = 100} \end{gathered}[/tex]Divide both sides by 0.8, we have that:
[tex]\begin{gathered} x\text{ = }\frac{100}{0.\text{ 8}} \\ x\text{ = 125} \end{gathered}[/tex]
Step 3:
Recall that:
[tex]\begin{gathered} \text{Equilibrium Demand : p = 100 - 0. 4 x } \\ we\text{ put x = 125, we have that:} \\ p\text{ = 100 - 0. 4 (125)} \\ p\text{ =100 -50} \\ p\text{ = 50} \end{gathered}[/tex]CONCLUSION:
Equilibrium Demand:
[tex]p\text{ = 50 units}[/tex]The initial directions are in the pic below. I’m sending 2 pics now. And the other 2 soon. For a total of 4.
Recall that the rule of transformation of a point reflected over the y-axis is as follows:
[tex](x,y)\rightarrow(-x,y).[/tex]Therefore, the transformed coordinates of the vertices of the triangle are:
[tex]\begin{gathered} N(4,6)\rightarrow N^{\prime}(-4,6), \\ P(1,6)\rightarrow P^{\prime}(-1,6), \\ Q(3,4)\rightarrow Q^{\prime}(-3,4)\text{.} \end{gathered}[/tex]Therefore, the image of the triangle is the triangle with the above vertices.
Answer:
Explain the behavior of f(x)= ln (x-a) when x=a. Give values to x and a such that x-a=0
SOLUTION:
Step 1:
In this question, we are given the following:
Explain the behavior of :
[tex]f(x)\text{ = ln\lparen x-a\rparen}[/tex]when x=a.
Give values to x and a such that:
[tex](x-a)\text{ = 0}[/tex]Step 2:
The graph of the function:
[tex]f(x)\text{ = In \lparen x- a \rparen}[/tex]are as follows:
Explanation:
From the graph, we can see that the function:
[tex]f(x)\text{ = ln\lparen x-a\rparen}[/tex]is a horizontal translation, shift to the right of its parent function,
[tex]f(x)\text{ = In x}[/tex]Missed this day of class and have no idea how to solve this last problem on my homework
From the given expression
a) The linear system of a matrix form is
[tex](AX=B)[/tex]The linear system of the given matrix will be
[tex]\begin{gathered} 2x+y+z-4w=3 \\ x+2y+0z-7w=-7 \\ -x+0y+oz+w=10 \\ 0x+0y-z+3w=-9 \end{gathered}[/tex]b) The entries in A of the matrix is
[tex]\begin{gathered} \text{For }a_{22}=2 \\ a_{32}=0 \\ a_{43}=-1 \\ a_{55}\text{ is undefined} \end{gathered}[/tex]c) The dimensions of A, X and B are
[tex]\begin{gathered} A\mathrm{}X=B \\ \begin{bmatrix}{2} & 1 & {1} & -4 \\ {1} & {2} & {0} & {-7} \\ {-1} & {0} & {0} & {1} \\ {0} & {0} & {-1} & {3}\end{bmatrix}\begin{bmatrix}x{} & {} & {} & {} \\ {}y & {} & {} & {} \\ {}z & {} & {} & {} \\ {}w & {} & {} & {}\end{bmatrix}=\begin{bmatrix}3{} & {} & {} & {} \\ {}-7 & {} & {} & {} \\ {}10 & {} & {} & {} \\ {}-9 & {} & {} & {}\end{bmatrix} \end{gathered}[/tex]Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following probability, given the number of trials andthe probability of obtaining a success. Round your answer to four decimal places.P(X= 15), n = 18, p = 0.8TablesKeynad
Recall that the probability of a binomial distribution is given by
[tex]P(X=x)=^^nC_r\cdot p^x\cdot(1-p)^{n-x}[/tex]Where n is the number of trials, p is the probability of success, and x is the variable of interest.
nCr is the number of combinations.
For the given case, we have
n = 18
p = 0.8
x = 15
Let us find the probability P(X=15)
[tex]\begin{gathered} P(X=15)=^{18}C_{15}\cdot0.8^{15}\cdot(1-0.8)^{18-15} \\ P(X=15)=816\cdot0.8^{15}\cdot0.2^3 \\ P(X=15)=0.2297 \end{gathered}[/tex]Therefore, the probability P(X=15) is 0.2297
Sketch the graph of the polynomial function. Use synthetic division and the remainder theorem to find the zeros.
GIVEN:
We are given the following polynomial;
[tex]f(x)=x^4-2x^3-25x^2+2x+24[/tex]Required;
We are required to sketch the graph of the function. Also, to use the synthetic division and the remainder theorem to find the zeros.
Step-by-step solution;
We shall begin by sketching a graph of the polynomial function.
From the graph of this polynomial, we can see that there are four points where the graph crosses the x-axis. These are the zeros of the function. One of the zeros is at the point;
[tex](-1,0)[/tex]That is, where x = -1, and y = 0.
We shall take this factor and divide the polynomial by this factor.
The step by step procedure is shown below;
Now we have the coefficients of the quotient as follows;
[tex]1,-3,-22,24[/tex]That means the quotient is;
[tex]x^3-3x^2-22x+24[/tex]We can also divide this by (x - 1) and we'll have;
We now have the coefficients of the quotient after dividing a second time and these are;
[tex]x^2-2x-24[/tex]The remaining two factors are the factors of the quadratic expression we just arrived at.
We can factorize this and we'll have;
[tex]\begin{gathered} x^2-2x-24 \\ \\ x^2+4x-6x-24 \\ \\ (x^2+4x)-(6x+24) \\ \\ x(x+4)-6(x+4) \\ \\ (x-6)(x+4) \end{gathered}[/tex]The zeros of this polynomial therefore are;
[tex]\begin{gathered} f(x)=x^4-2x^3-25x^2+2x+24 \\ \\ f(x)=(x+1)(x-1)(x-6)(x+4) \\ \\ Where\text{ }f(x)=0: \\ \\ (x+1)(x-1)(x-6)(x+4)=0 \end{gathered}[/tex]Therefore;
ANSWER:
[tex]\begin{gathered} x+1=0,\text{ }x=-1 \\ \\ x-1=0,\text{ }x=1 \\ \\ x-6=0,\text{ }x=6 \\ \\ x+4=0,\text{ }x=-4 \end{gathered}[/tex]Michael earned some Money doing odd jobs last summer and put it in a savings account that earns 13% interest compounded quarterly after 2 years there is 100.00 in the account how much did Michael earn doing odd jobs
Michael earned some Money doing odd jobs last summer and put it in a savings account that earns 13% interest compounded quarterly after 2 years there is 100.00 in the account How much did Michael earn doing odd jobs?
____________________________________
13% interest compounded quarterly
after 2 years there is 100.00
_________________________________-
interest compounded
A = P(1 + r/n)^nt
A= Final amount
P= Principal Amount
r= interest
n= number of compounding periods (year)
t= time (year)
_____________________
Data
A= 100.00
P= Principal Amount (The question)
r= interest (0.13)
n= number of compounding periods (4)
t= time (2)
_________________
Replacing
A = P(1 + r/n)nt
P = A / ((1 + r/n)^nt)
P = 100.00/ ((1 + 0.13/4)^4*5)
P= 100.00/ (1.0325^20)
P= 52
________________
Michael earns doing odd jobs 52 dollars.
Find the area of the triangle below.9 cm6 cm2 cm
We recall that the area of a triangle is defined by the product of the triangle's base times its height divided by 2.
So we notice that in our image, we know the height (6 cm), and we also know the base of the triangle (2 cm)
Therefore the triangles are is easily estimated via the formula:
[tex]\text{Area}=\frac{base\cdot height}{2}=\frac{2\cdot6}{2}=6\, \, cm^2[/tex]Then the area is 6 square cm.
Determine the transformations that produce the graph of the functions g (T) = 0.2 log(x+14) +10 and h (2) = 5 log(x + 14) – 10 from the parent function f () = log 1. Then compare the similarities and differences between the two functions, including the domain and range. (4 points)
The transformation to get g(x) from f(x) are:
translate 14 units to the left and 10 unit upwards
[tex]h(x)=5\log (x+14)-10[/tex]the transformatio to get h(x) from f(x) are:
translate 14 units to the left and 10 units downwards
х3,2y=x?(x, y)00(0,0)2.4(2, 4)For which value of x is the row in the table of values incorrect?3The function is the quadratic function y = -x?4366를18(3,6)(5,18 )5
Since the given equation is
[tex]y=\frac{3}{4}x^2[/tex]If x = 0, then
[tex]y=\frac{3}{4}(0)^2=0[/tex]Then x = 0 is correct because it gives the same value of y in the table
If x = 2
[tex]\begin{gathered} y=\frac{3}{4}(2)^2 \\ y=\frac{3}{4}(4) \\ y=3 \end{gathered}[/tex]Since the value of y in the table is 4
Then x = 2 is incorrect
what is the slope of the line which goes through the points (-2, -9) and (2, 11) the slope of the line is___
We know the equation of a line is given by:
[tex]y=mx+b[/tex]where m is its slope and b its interpcetion with y - axis.
We know the slope equation is
[tex]\begin{gathered} m=\frac{\Delta y}{\Delta x} \\ =\frac{y_2-y_1}{x_2-x_1} \end{gathered}[/tex]If (x₁, y₁) = (-2, -9) and (x₂, y₂) = (2, 11) then replacing in the slope equation
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ =\frac{11-(-9)}{2-(-2)} \\ =\frac{11+9}{2+2} \\ =\frac{20}{4}=5 \end{gathered}[/tex]Answer: the slope of the line is 5Given the triangle ABC with the points A = ( 4, 6 ) B = ( 2, 8 ) C = ( 5, 10 ) and it's dilation, triangle A'B'C', with points A' = ( 2, 3 ) B' = ( 1, 4 ) C' = ( 2.5, 5 ) what is the scale factor?
Answer:
Explanation:
Given A = (4, 6) B = (2, 8) C = (5, 10)
[tex]\begin{gathered} AB=\sqrt{(2-4)^2+(8-6)^2} \\ \\ =\sqrt{8} \\ \\ BC=\sqrt{(5-2)^2+(10-8)^2} \\ \\ =\sqrt{8} \end{gathered}[/tex]SImilarly, for A' = (2, 3) B' = (1, 4) C' = (2.5, 5)
[tex]\begin{gathered} A^{\prime}B^{\prime}=\sqrt{(1-2)^2+(4-3)^2} \\ \\ =\sqrt{2} \\ \\ B^{\prime}C^{\prime}=\sqrt{(2.5-1)^2+(5-4)^2} \\ \\ =\sqrt{3.25} \end{gathered}[/tex]
Since it is a dilation, AB/A'B' should be the same as BC/B'C', but that is not the case here.
a store sells gift cards in preset amount. You can purchase gift cards for $20 or $30 . You spent $380 on gift cards. let x be the number of gift cards for $20 And let y be your gift cards for $30 . Write an equation in standards for to represent this situation
ANSWER= 20x+30y=380
but what ab this one
What are three combinations of gift cards you could have purchased?
The equation that represent the situation is as follows:
20x + 30y = 380The three combination of the gift cards you can purchase is as follows:
13 and 410 and 67 and 8How to represent equation in standard form?The store sells gift cards. One can purchase gift cards for $20 or $30 .
You spent $380 on gift cards. let x be the number of gift cards for $20 And let y be your gift cards for $30 .
The equation in standard form to represent the situation is as follows:
The standard form of a linear equation is A x + By = C. A, B, and C are
constants, while x and y are variables.
Therefore,
x = number of gift cards for 20 dollars
y = number of gift card for 30 dollars
Hence,
20x + 30y = 380
The three combination one could have purchased is as follows:
20(13) + 30(4) = 38020(10) + 30(6) = 38020(7) + 30(8) = 380learn more on equation here: https://brainly.com/question/7222455
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Mr. Edmonds is packing school lunches for a field trip for the 6th graders of Apollo Middle school. He has 50 apples and 40 bananas chips. Each group of students will be given one bag containing all of their lunches for the day. Mr. Edmonds wants to put the same number of apples and the same number of bananas in each bag of lunches. What is the greatest number of bags of lunches Mr. Edmonds can make? How many apples and bananas will be in each bag?
The greatest number of bags of lunches Mr. Edmonds can make = 40, And , in each bag there will be one apple and one banana chips bag.
In the above question, the following information is given :
Mr. Edmonds wants to pack lunches for the schools field trip where he wants to put the same number of apples and the same number of bananas in each bag of lunches
We are given that,
Number of available bananas chips packs = 40
Number of available apples = 50
We need to find the greatest number of bags of lunches Mr. Edmonds can make
As the pair should be an even number and we have less number of banana chips bags than apples. So the number of lunches which can be packed with equal number of apples and banana chips bags depend on banana chips bags
Therefore, the greatest number of bags of lunches Mr. Edmonds can make = 40
And , in each bag there will be one apple and one banana chips bag.
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