By definition, in a Geometric sequence the terms are found by multiplying the previous one by a constant. This constant is called "Common ratio".
In this case, you know these values of the set:
[tex]\begin{gathered} .004 \\ .4 \end{gathered}[/tex]Notice that you can set up this set with the value given in the first option:
[tex].004,.04,.4[/tex]Now you can check it there is a Common ratio:
[tex]\begin{gathered} \frac{0.04}{0.004}=10 \\ \\ \frac{.4}{0.04}=10 \end{gathered}[/tex]The Common ratio is:
[tex]r=10[/tex]Therefore, it is a Geometric sequence.
Apply the same procedure with each option given in the exercise:
- Using
[tex].004,.04,-.04,.4[/tex]You can notice that it is not a Geometric sequence, because:
[tex]\begin{gathered} \frac{-.04}{.04}=-1 \\ \\ \frac{.4}{-.04}=-10 \end{gathered}[/tex]- Using
[tex].004,.0004,.4[/tex][tex]\begin{gathered} \frac{.0004}{.004}=0.1 \\ \\ \frac{4}{.0004}=1,000 \end{gathered}[/tex]Since there is no Common ratio, if you use the value given in the third option, you don't get a Geometric sequence.
- Using this set with the values given in the last option:
[tex].004,.0004,-.0004,.4[/tex]You get:
[tex]\begin{gathered} \frac{.0004}{.004}=0.1 \\ \\ \frac{-.0004}{.0004}=-1 \end{gathered}[/tex]It is not a Geometric sequence.
The answer is: First option.
lan is working two summer jobs, making $19 per hour lifeguarding and making $9per hour clearing tables. In a given week, he can work no more than 14 total hoursand must earn a minimum of $180. If x represents the number of hours lifeguardingand y represents the number of hours clearing tables, write and solve a system ofinequalities graphically and determine one possible solution.Inequality 1: y 24plot switch shadeInequality 2: y 24plotswitch shade2019181716151413121110Yes
Given:
Lan is working two jobs:
1) $19 per hour life guarding
2) $9 per hour clearing tables
The total hours per week = 14
He must earn a minimum of $180
Let x represents the number of hours life guarding and y represents the number of hours clearing tables
So, we have the following inequalities
[tex]\begin{gathered} x+y\le14 \\ 19x+9y\ge180 \end{gathered}[/tex]We need to solve the inequalities by graph
So, we will graph the lines: x + y = 14 and 19x + 9y = 180
The shaded area represents the solution of the system of inequalities
The following figure represents the solution of the system of inequalities
I need help with this practice problem solving The subject is trigonometry It asks to graph the functionIf you can, use Desmos to graph… it is recommend
In order to determine the graph of the given function, cosider:
The function f(x) is indetermined when the argument of the cot is 0.
[tex]\begin{gathered} x+\frac{\pi}{6}=0 \\ x=-\frac{\pi}{6} \end{gathered}[/tex]In this case, the period is 2pi. Then, not only for x=-pi/6, but for x=5pi/6 the function is indeterminate.
Then, the graph is:
through: (5,-4), slope = -9/5
The slope intersept form of a line is ,
[tex]y-y_1=m(x-x_1)[/tex]Given the point (x1,y1) is (5,-4) and slope is -9/5 implies,
[tex]undefined[/tex]You have 1/5 of a box of erasers and you need to share them with 3 total people, including yourself. What fraction of the box should each person get?
You have 1/5 of a box of erasers
Number of box of erasers = 1/5.
you need to share them with 3 total people, including yourself
Total number of people = 3 + 1( yourself)
Total number of people = 4
Since, we have to distribute the box of erasers to 4 people
So, divide 1/5 by 4:
[tex]\begin{gathered} \frac{1}{5}\text{ }\div4=\frac{\frac{1}{5}}{4} \\ \frac{1}{5}\text{ }\div4=\frac{1}{5}\times\frac{1}{4} \\ \frac{1}{5}\text{ }\div4=\frac{1}{5\times4} \\ \frac{1}{5}\text{ }\div4=\frac{1}{20} \end{gathered}[/tex]The fraction of the box that each person will get is 1/20
Answer: 1/20
3. Which of the following points would produce a negative slope? (A) (B) (C) (D) (-1,2) and (4,2) (-2,-2) and (0,4) (1,3) and (-1,4) (2,4) and (-2,-1)
The sequation to calculate the slope is,
[tex]m=\frac{y2-y1}{x2-x1}[/tex]The solpe of line joining (-1,2) and (4,2) is,
[tex]\begin{gathered} m=\frac{2-2}{4+1} \\ m=0 \end{gathered}[/tex]The slope of the line joining (-2,-2) and (0,4) is,
[tex]\begin{gathered} m=\frac{4+2}{0+2} \\ m=3 \end{gathered}[/tex]The slope of the line joining (1,3) and (-1,4) is,
[tex]\begin{gathered} m=\frac{4-3}{-1-1} \\ m=-\frac{1}{2} \end{gathered}[/tex]Negative slope.
The slope of the line joining (2,4) and (-2,-1) is,
[tex]\begin{gathered} m=\frac{-1-4}{-2-2} \\ m=\frac{5}{4} \end{gathered}[/tex]Positive slope.
CS 18 and 105 calories in each juice box The rules for two horseback riding packages are shown below. Go Galloping Horseback Rides $6 equipment fee plus S10 per hous hours horseback riding and let yepresent the total cost of the package. Write a system of equations to represent this situation let x represent the number of Lucky Horseshoe Stables $12 equipment fee plus hour 259 Calories What is the solution to the system of equations? What does the solution represent?
8A) Let x represent the number of hours of horseback riding.
Let y represent the total cost of the package
If Lucky horseshoe stables is used for x hours, the equation for the total cost would be
y = 7x + 12
If Go galloping horseshoe rides is used for x hours, the equation for the total cost would be
y = 10x + 6
Thus, the equations are
y = 7x + 12
y = 10x + 6
B) To solve the system of equations, we would substitute the first equation into the second equation. It becomes
7x + 12 = 10x + 6
10x - 7x = 12 - 6
3x = 6
x = 6/3
x = 2
y = 7x + 12 = 7 * 2 + 12
y = 14 + 12
y = 26
The solution of the system of equations is (2, 26)
Bobby was making a road trip to visit his parents. He stopped for gas and bought x number of gallons for $2.25 per gallon and a soda for $1.75. How much did he spend at the gas station if her purchased 15 gallons of gas?
Answer:
$35.5
Explanation:
If Bobby purchased 15 gallons of gas and each gallon cost $2.25, the total cost of the gallons of gas is:
15 x $2.25 = $33.75
Adittionally, Bobby bought a soda for $1.75, so he spend a total of:
$33.75 + $1.75 = $35.5
So, he spends $35.5
Andre drew a plan of a courtyard at a scale of 1 to 60. On his drawing, one side of the courtyard is 2.75 inches. What is the actual measurement of that side of the courtyard? Show your work.
Okay, here we have this:
Considering that the scale is of 1 to 60, we obtain the following:
2.75 inches * 60 =165.
Triangle ABC has vertices at A(−4, 3), B(0, 5), and C(−2, 0). Determine the coordinates of the vertices for the image if the preimage is translated 4 units down. A′(−4, −1), B′(0, 1), C′(−2, −4) A′(−4, 7), B′(0, 9), C′(−2, 4) A′(0, 3), B′(4, 4), C′(3, 0) A′(−8, 7), B′(−4, 9), C′(−6, 4)
Given:
The triangle is ABC
Vertices of ABC is
[tex]\begin{gathered} A=(-4,3) \\ \\ B=(0,5) \\ \\ C=(-2,0) \end{gathered}[/tex]Find-:
The vertex after 4 units down
Explanation-:
The triangle is down, which means changing the coordinates of the y-axis
The y axis reduce by 4 units, then coordinates is
[tex]\begin{gathered} A=(-4,3) \\ \\ A\rightarrow A^{\prime} \\ \\ A^{\prime}=(-4,(3-4)) \\ \\ A^{\prime}=(-4,-1) \end{gathered}[/tex]The B' is
[tex]\begin{gathered} B=(0,5) \\ \\ B^{\prime}=(0,(5-4)) \\ \\ B^{\prime}=(0,1) \end{gathered}[/tex]The C' is
[tex]\begin{gathered} C^{\prime}=(-2,(0-4)) \\ \\ C^{\prime}=(-2,-4) \end{gathered}[/tex]So, the new coordinates are
[tex]\begin{gathered} A^{\prime}(-4,-1) \\ \\ B^{\prime}(0,1) \\ \\ C^{\prime}(-2,-4) \end{gathered}[/tex]Find the value of k so that x-1 is a factor of x^2 - 2x^2 + 3x + k
The value of k so that x - 1 is a factor of the polynomial, x² - 2x² + 3x + k is -2.
How to find the factor of a polynomial?The polynomial given is x² - 2x² + 3x + k.
Let's find the value of k so that x - 1 is a factor of the polynomial x² - 2x² + 3x + k.
Factoring of a polynomial is the method of breaking the polynomial into a product of its factors.
Therefore, the value of k that will make x - 1 a factor is when the polynomial is equals to zero when we input the root of x - 1 in the polynomial.
Hence,
x - 1 = 0
x = 1
let's substitute the value of x in the polynomial. The polynomial must be equals to 0 for x - 1 to be a factor of the polynomial.
0 = x² - 2x² + 3x + k
0 = (1)² - 2(1)² + 3(1) + k
0 = 1 - 2 + 3 + k
0 = - 1 + 3 + k
0 = 2 + k
k = - 2
Therefore, the value of k is -2.
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need help with excerise step by step been 20 year's
Given:
Standard deviation
[tex]\sigma=5.18[/tex]Mean
[tex]\mu=129[/tex]Required:
Find the longest braking distance one of these cars could have and still in the bottom.
Explanation:
The z-score formula is given as:
[tex]z=\frac{x-\mu}{\sigma}[/tex]Substitute the given values and find the value of z.
[tex]z=\frac{x-129}{5.18}[/tex]This is the first percentile which is X when Z has a p-value of 0.01, so z = -2.327.
[tex]\begin{gathered} -2.327=\frac{x-129}{5.18} \\ x-129=-2.327(5.18) \\ x-129=-12.054 \\ x=129+12.054 \\ x=116.946\text{ ft} \end{gathered}[/tex]Final answer:
The longest braking distance one of these cars could have and still in the bottom 1% is 116.946 ft.
The triangles below are congruent by SSS, so we can say that < E is congruent to ______ by CPCTC.
The triangles are given to be congruent by the side-side-side (SSS) congruence property.
Hence, the congruent statement is:
[tex]\triangle DEF\cong\triangle HIJ[/tex]It is required to complete the given statement.
Recall that CPCTC means Corresponding Parts of Congruent Triangles are Congruent.
The corresponding part to ∠ E is ∠I. Hence, by CPCTC, the angle congruent to ∠E is ∠I.
The answer is option b.
Can someone please help me on this question, I'm a little stuck? The question should be down below!
We have a right triangle with a missing side.
When we have two sides given sides on the right triangle and we need to find the missing side, we use the Pythagoras theorem:
The formula is given by:
[tex]a^2=b^2+c^2[/tex]Where:
a = Hypotenuse
b= Opposite side
c= Adjacent side
Now, we need to label the sides of the given triangle:
The largest side, represents the hypotenuse, in this case, a=15m.
The adjacent side is between the 90 degrees angle and the hypotenuse, in this case, c = 9m
Therefore, the missing side is the opposite side, let set b for this side:
Replacing these values:
[tex](15m)^2=b^2+(9m)^2[/tex][tex]225=b^2+81[/tex]Solve the equation for b:
[tex]225-81=b^2[/tex][tex]144=b^2[/tex][tex]\sqrt[]{144}=\sqrt[]{b^2}[/tex]Therefore, the missing side:
[tex]12=b[/tex]
Given rectangle BCDE below. If BF = 22, find EF.
Okay, here we have this:
Considering the provided graph, we are going to find the requested measure, so we obtain the following:
Let us remember that a rectangle besides having the properties of a parallelogram also stands out because it has congruent diagonals. So considering this we have:
BD=EC
EF=BF
EF=22
Finally we obtain that EF is equal to 22 units.
Three different transformation are performed on the shaded triangle. Each transformation results in on of three images. Match each image to the transformation applied on the shaded triangle
We are given a triangle and three possible transformations performed on it. The first transformation shows that the triangle has no change in orientation, therefore, this transformation is a translation only.
For image 2 we notice that the orientation of the triangle changes. If we draw a horizontal line in the middle of the shaded triangle and image 2 we notice that these two images are related by a reflection, also after this reflection the image was translated therefore, for image two we have reflection across a horizontal line followed by a translation.
For image 3 we can draw a vertical line in the middle of the shaded triangle and image 3 and we do a reflection across this vertical line since there is a change in the orientation of the figure.
uhh im stuck and im stressed .. and i dont understand area model math..
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
(5x + 6)(2x² + 3x + 8) = ?
Step 02:
Area Model
First, you must multiply the values in the rows by each of the values in the columns.
Then, you must add all the values resulting from the multiplications.
10x³
2x²
+ 12x²
15x²
18x
3x
40x
48
8
--------------------------------------------
10x³ + 29x² + 61x + 56
The answer is:
(5x + 6)(2x² + 3x + 8) = 10x³ + 29x² + 61x + 56
The Jones family took a 12-mile canoe ride down the Indian River in 2 hours. After lunch, the return trip back up the river took 3 hours. Find the rate of the canoe in still water and the rate of the current.
Answer:
Step-by-step explanation:
As per the distance formula, the rate of the canoe in still water is 5 mph; the rate of the current is 1 mph.
Distance formula:
Distance is defined as the total movement of an object without any regard to direction. So, it is defined as the distance that covers how much ground an object despite its starting or ending point.
Distance = Speed x time
Given,
The Jones family took a 12-mile canoe ride down the Indian River in 2 hours. After lunch, the return trip back up the river took 3 hours.
Here we need to find the rate of the canoe in still water and the rate of the current.
According to the given question we know that,
Speed downriver = (12 mi)/(2 h) = 6 mph.
Speed upriver = (12 mi)/(3 h) = 4 mph.
Now, we need to find the canoe's rate in still water is the average of these speeds:
=> (6+4)/2 = 5 miles per hour.
Then the current's rate is calculated as the difference between the actual rate and the canoe's rate:
=> 6 - 5 = 1 miles per hour.
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I tried it and got imaginary numbers in the answer.
Given the following equation:
[tex]\frac{x}{x-4}-\frac{4}{x}=\frac{3}{x-4}[/tex]First, we will identify the zeros of the denominator
So, the zeros are: x = {0,4}
Second, multiply the equation by x(x-4) to eliminate the denominators
[tex]x(x-4)*(\frac{x}{x-4}-\frac{4}{x})=x(x-4)*\frac{3}{x-4}[/tex]Simplify the equation:
[tex]x^2-4(x-4)=3x[/tex]Expand the equation and combine the like terms:
[tex]\begin{gathered} x^2-4x+16=3x \\ x^2-7x+16=0 \end{gathered}[/tex]The last quadratic equation will be solved using the quadratic rule:
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]Substitute a = 1, b = -7, c = 16
[tex]\begin{gathered} x=\frac{7\pm\sqrt{(-7)^2-4(1)(16)}}{2(1)} \\ \\ x=\frac{7\pm\sqrt{-15}}{2}=\frac{7\pm i\sqrt{15}}{2} \\ \\ x=\lbrace\frac{7+i\sqrt{15}}{2};\frac{7-i\sqrt{15}}{2}\rbrace \end{gathered}[/tex]So, the answer will be:
[tex]x=\lbrace\frac{7+i\sqrt{15}}{2};\frac{7-i\sqrt{15}}{2}\rbrace[/tex]help meeeeeeeeeeeeeeeee
For the given function f(x) = x³ +x +1,g(x) =-x, composition of the given function is given by ( fog)(x) = -x³ -x +1 , ( g of)(x) = -(x³ +x +1).
As given in the question,
Given function :
f(x) = x³ +x +1
g(x) =-x
Composition of the given function is equal to :
(fog)(x) = f(g(x))
= f(-x)
= (-x)³ +(-x) +1
= -x³ -x +1
(g of)(x) = g(f(x))
=g(x³ +x+1)
= -(x³ +x+1)
Therefore, for the given function f(x) = x³ +x +1,g(x) =-x, composition of the given function is given by ( fog)(x) = -x³ -x +1 , ( g of)(x) = -(x³ +x +1).
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Hugo averages 42 words per minute on a typing test with a standard deviation of 5.5 words per minute. Suppose Hugo's words per minute on a typing test are normally distributed. Let X= the number of words per minute on a typing test. Then, X∼N(42,5.5). Suppose Hugo types 60 words per minute in a typing test on Wednesday. The z-score when x=60 is ________. This z-score tells you that x=60 is ________ standard deviations to the ________ (right/left) of the mean, ________. Correctly fill in the blanks in the statement above.
The z score when x = 60 is 3.27.
This z score tells you that x = 60 is 3.27 standard deviations to the right of the mean.
Given,
Consider as a normal distribution:
The mean should be equals to 42 (μ)
The standard deviation (σ) = 5.5
We have to find the z score when x = 60.
That is,
z = (x - μ) / σ = (60 - 42) / 5.5 = 18/5.5 = 3.27
Therefore,
The z score when x = 60 is 3.27.
This z score tells you that x = 60 is 3.27 standard deviations to the right of the mean.
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which numbers are all divisible by 5
Answer:
numbers that end with 0 or 5.
Answer: 5 35 790 55
Step-by-step explanation:
kekera pere
How many solutions does this equation have?-4k + 4k = 0
Let's try so solve this equation:
[tex]\begin{gathered} -4k+4k=0 \\ 0=0 \end{gathered}[/tex]When you have a result of 0 = 0, that means the equation has infinite solutions, that is, any value of k we use would satisfy the equation.
So the equation has infinitely many solutions.
Fill in the missing values to make the equations true.(a) log, 9-log, 11 = log5(b) log45 + log4 = log, 45(c) 5log72 = log7
(a)
[tex]\log _59-\log _511=\log _{5_{}}(\frac{9}{11})\text{ (}\because\log a-\log b=\log (\frac{a}{b})[/tex]Thus, the required value in the blank in 9/11/
(b)
[tex]\log _45+\log _4(9)=\log _445\text{ (}\because\log a+\log b=\log ab)[/tex]Thus, the required value in the blank is 9.
(c)
[tex]\begin{gathered} 5\log _72=\log _72^5(\because a\log b=\log b^a) \\ =\log _732 \end{gathered}[/tex]Thus, the requried value in the blank is 32.
6.724x
Melinda went for a run. She was doing a great job until she got to a hill. She was so tired
running up the hill that she tripped over a rock at the top of the hill. She rolled all the way
down the hill. It took her 90 seconds to reach the bottom of the hill. She rolled for 225
feet. What is Melinda's rate of decent?
The Melinda's rate of decent from the top of the hill is 3.75 ft/sec.
What is termed as the rate of decent/speed?Speed is defined as the proportion of distance traveled to time spent traveling. Because it has only one direction and no magnitude, speed is a scalar quantity. When an object travels the same distance in equal time intervals, it is said to be moving at a uniform speed.For the given question;
The distance covered by the Melinda after she tripped over a rock at the top of the hill is 225 feet.
The time taken by Melinda to reach the bottom of the hill is 90 seconds.
Then, the rate of decent will be the speed at which she will fall.
Speed = distance/ time
Speed = 225/60
Speed = 3.75
Thus, the Melinda's rate of decent from the top of the hill is 3.75 ft/sec.
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Question 5 Multiple Choice Worth 1 points)(05.02 MC)A nurse collected data about the average birth weight of babies in the hospital that month. Her data is shown using the dot plot. Create a box plot to represent the data.Monthly Birth Weight:8.28.3 8.4 8.5 8.6Birth Weight (in pounds)82 83 8.4 85 86 87 8.882 8384 8.5 86 87 60 6.982 83 84 8.5 8.6 8.7 8.0 8.9 98283 84 85 86 87 88 8.998.1816.181$F
Given:
Here we have data about the average birth weight of babies in the hospital that month.
Required:
We need to create a box plot to represent the data.
Explanation:
Here we have monthly birth weight in pounds as
8.2 , 8.2 , 8.3 , 8.3 , 8.4 , 8.4 , 8.5 , 8.5 , 8.5 , 8.7 , 8.9
now by data we get Q2 is 8.4
now for this data
8.2 , 8.2 , 8.3 , 8.3 , 8.4
we get Q1 is 8.3
by this data
8.5 , 8.5 , 8.5 , 8.7 , 8.9
we get Q3 is 8.5
and we have maximum 8.9 and minimum 8.2
now make a box plot
Final answer:
A road sign is in the shape of a regular pentagon. What is the measure of each angle on the sign? Round to the nearest tenth. 540 252 54 Od 108
Internal angles of a polygon
The triangle has n=3 sides, and the sum of its internal angles is 180°
The rectangle has n=4 sides, and the sumo of its internal angles is 360°
There is a general formula to calculate the sum of the internal angles of any polygon of n sides:
Sum = 180° ( n -2 )
For a pentagon (n=5), the sum of angles is:
Sum = 180° ( 5 -2 ) = 180° * 3 = 540°
We are required to find the measure of each internal angle. Since the pentagon is regular, all of its internal angles measure the same, thus:
The measure of each angle = 540° / 5 = 108°
A construction worker dropped a hammer while building the Grand Canyon skywalk, 8100 feetabove the Colorado River. Use the formula t=(square root of h)/4 to find how many seconds it took for thehammer to reach the river.
Given:
[tex]t=\frac{\sqrt[]{h}}{4}[/tex]To find the time when the height h=8100 feet:
Substitute h=8100 in the given function.
[tex]\begin{gathered} t=\frac{\sqrt[]{8100}}{4} \\ t=\frac{90}{4} \\ t=22.5\text{ seconds} \end{gathered}[/tex]Thus, the time required for the hammer to reach the river is 22.5 seconds.
Triangle ABC is shown with exterior ∠z.
Determine m∠z.
49°
97°
131°
146°
Answer:
(c) 131°
Step-by-step explanation:
Given exterior angle z of a triangle with remote interior angles 97° and 34°, you want the measure of angle z.
Remote interior anglesAn exterior angle is equal to the sum of the remote interior angles.
Applicationz = 97° +34°
z = 131°
Please help me and tell me the process I have a test in an hour.Value of x.
Vertical angles are congruent.
From the figure, angle 3 and angle (7x + 3) are vertical angles, therefore angle 3 is (7x + 3)
Angle 1 and 127 degrees are supplementary angles and have a sum of 180 degrees.
That will be :
[tex]\begin{gathered} \angle1+127=180 \\ \angle1=180-127 \\ \angle1=53 \end{gathered}[/tex]Angle 2 and 133 degrees are also supplementary angles and have a sum of 180 degrees.
That will be :
[tex]\begin{gathered} \angle2+133=180 \\ \angle2=180-133 \\ \angle2=47 \end{gathered}[/tex]Now we have angles 1, 2 and 3 which are angles in a triangle, and the sum of interior angles in a triangle is 180 degrees.
[tex]\begin{gathered} \angle1+\angle2+\angle3=180 \\ 53+47+(7x+3)=180 \\ \text{Solve for x :} \\ 100+7x+3=180 \\ 7x+103=180 \\ 7x=180-103 \\ 7x=77 \\ x=\frac{77}{7} \\ x=11 \end{gathered}[/tex]ANSWER :
x = 11
4x + x + 4 = 8x -3x + 4
x can take any real value
Explanation
[tex]4x+x+4=8x-3x+4[/tex]
Step 1
add similar terms in both sides
[tex]\begin{gathered} 4x+x+4=8x-3x+4 \\ 5x+4=5x+4 \end{gathered}[/tex]Step 2
subtract 5x+4 in both sides
[tex]\begin{gathered} 5x+4=5x+4 \\ 5x+4-(5x+4)=5x+4-(5x+4) \\ 0=0 \end{gathered}[/tex]0=00 means that as an equation, its solution is that x can take any real value .
I hope this helps you