Answers
Answer:
SEE BELOW.
Step-by-step explanation:
1) 5/40
gcf = 5
5 ÷ 5 / 40 ÷ 5
= 1/8
2) 2/12
1/6
3) 3/9
= 1/3
4) 4/36
1/9
5) 6/40
3/20
6) 7/49
1/7
7) 6/50
3/25
8) 8/12
4/6
2/3
9) 9/90
1/10
10) 14/32
7/16
11) 25/65
5/13
12) 18/64
9/32
13) 24/54
4/9
14) 8/60
4/30
2/15
15) 22/34
11/17
16) 35/84
5/12
17) 48/104
6/13
18) 16/128
1/8
19)36/108
= 1/3
20) 38/152
1/4
2-.1666
3.333333
4-.11111
5-.15
6-.142857
7-.12
8-.666666
9-.1
10-.43375
11-.3846
12-.28125
13-.44444444
14-.133333
15-.647059
16-.4166666
17-.4615
18-.125
19-.3333333
20-.25
I think it's like that.
Related Questions
You pick a card at random What is P(factor of 48)?
Answers
Answer:
48 = {1,2,3,6,8,48.}
Step-by-step explanation:
These are the factors if 48. if it's correct please let me know.
Find the volume of the triangular prism; do not round.
Answers
Answer:
[tex]\boxed{\mathtt{Volume=33.55m^{3}}}[/tex]
Step-by-step explanation:
[tex]\textsf{For this problem, we are asked to find the Volume of a Triangular Prism.}[/tex]
[tex]\large\underline{\textsf{What is Volume?}}[/tex]
[tex]\textsf{Volume is the amount of space a figure occupies. Volume is measured in Cubic units.}[/tex]
[tex]\large\underline{\textsf{We are Given;}}[/tex]
[tex]\textsf{The Height is 6.1m. Keep in mind that the Height is the Perpendicular Distance}[/tex]
[tex]\textsf{between 2 bases.}[/tex]
[tex]\textsf{The base is; (4.4 x 2.5).}[/tex]
[tex]\textsf{The Height of the Triangle is 2.5m.}[/tex]
[tex]\large\underline{\textsf{Necessary Formulas;}}[/tex]
[tex]\mathtt{Volume=(Base) \times Height}[/tex]
[tex]\mathtt{Area = \frac{1}{2} (Base \times Height)}[/tex]
[tex]\large\underline{\textsf{For this Problem;}}[/tex]
[tex]\mathtt{Volume=(Triangles' \ Area) \times Height}[/tex]
[tex]\large\underline{\textsf{The area of a Triangle is;}}[/tex]
[tex]\mathtt{Area = \frac{1}{2} (Base \times Height)}[/tex]
[tex]\textsf{Find the area of the base first.}[/tex]
[tex]\large\underline{\textsf{Substitute;}}[/tex]
[tex]\mathtt{Area = \frac{1}{2} (4.4 \times 2.5)}[/tex]
[tex]\boxed{\mathtt{Area = 5.5m^{2}.}}[/tex]
[tex]\textsf{We know the Base, now let's find the volume of the figure.}[/tex]
[tex]\large\underline{\textsf{Substitute;}}[/tex]
[tex]\mathtt{Volume=5.5 \times 6.1}[/tex]
[tex]\boxed{\mathtt{Volume=33.55m^{3}}}[/tex]
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\textsf{Find the \boxed{\bf volume} of a triangular prism is:}[/tex]
[tex]\mathsf{\dfrac{1}{2}(\boxed{\bf b}ase\times\boxed{\bf h}eight\times\boxed{\bf l}ength) = \boxed{\bf v}olume}[/tex]
[tex]\huge\textsf{Your \boxed{\bf equation} should look like:}[/tex]
[tex]\mathsf{volume = \dfrac{1}{2}(4.4\ m \times 2.5\ m\times 6.1\ m)}[/tex]
[tex]\huge\textsf{\boxed{\bf Step-by-step} explanation can be:}[/tex]
[tex]\mathsf{volume = \dfrac{1}{2}(4.4\ m \times 2.5\ m\times 6.1\ m)}[/tex]
[tex]\mathsf{volume = \dfrac{1}{2}\times 4.4\ m \times 2.5\ m\times 6.1\ m}[/tex]
[tex]\mathsf{volume = 0.5\times 4.4\ m \times 2.5\ m\times 6.1\ m}[/tex]
[tex]\mathsf{volume = 2.2\ m\times 15.25\ m}[/tex]
[tex]\mathsf{volume = 33.55}[/tex]
[tex]\huge\textsf{Therefore your \boxed{\bf answer} should be:}[/tex]
[tex]\huge\boxed{\mathsf{volume = 33.55m^2}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
Identify the least value, first quartile, median, third quartile, and greatest value of the data.
5, 1, 4, 0, 9, 0, −8, 5, 2, 4, −1, 10, 7, −5
Answers
Answer: 10 is the greatest and -8 is the least
Step-by-step explanation:
10 is the biggest number and even though -8 is a big number when you have it in the "-" the bigger the number is the less they are
100 POINTS HELP PLEASE IM DESPERATE !!!!!!!!!!!!!!!!!!!!
If AB¯¯¯¯¯¯¯¯
is translated right 5
units and down 2
units, what are the coordinates of A′,
the image of point A?
Line Segment A B with coordinates A negative 5, 2 & B negative 2, 6.
Answers
A hollow ball is made of rubber that is 2 centimeters thick. The ball has a radius to the outside surface of 6 centimeters.
What is the approximate volume of rubber used to make the ball?
Use 3.14 for pi.
Responses
33.5 cm³
33.5 cm³
267.9 cm³
267.9 cm³
636.4 cm³
636.4 cm³
904.3 cm³
Answers
Answer:
636.4 cm³
Step-by-step explanation:
Find the surface area of the figure below. Round your answer to the nearest whole number.
Answers
Can someone please help me
Answers
the formula for rate of change is
(Y2 - Y1)/(X2-X1).
Plug in any 2 random coordinates.
(6-4)/(5-4)
2/1
2
Please help me I want this done today.
Answers
B is correct. B is rights because at the end of the equation you need to divide by 1 so it all equals out.
Answer:
Choose Choice B
Step-by-step explanation:
45-19 is 26.
All of the other equations don't make sense except B
PLEASE HURRY IM RUNNING LATE WITH THIS!,
Answers
Hope this help!!
Find the measure of ∠YOZ by answering the questions.
1. Find the measure of ∠WOV. Which angle relationship did you use? (3 points)
2. Now find the measure of ∠YOZ. Which angle relationship did you use? (3 points)
3. Check your answer by using another strategy to find the measure of ∠YOZ. Describe your strategy, and show that it gives the same measure for ∠YOZ. (4 points)
Answers
Answer:1. The measure of ∠WOV is 60°. You would use complementary angles that are adjacent (∠WOV, and ∠XOW)
2. The measure of ∠YOZ is 60°. You would use the vertical angles that are non-adjacent (∠WOV, and ∠YOZ). These two angles are congruent so they would have the same measure. These angles combined also create supplementary angles
3. Another way to find the measure of ∠YOZ would be to make/write an equation and solve for x. For example, (3x+30)°=60°. x would equal 10 because 10x3=30+30=60°
Step-by-step explanation:
1. Since a complementary angle would equal 90°, simply subtract 30° from 90° resulting in 60°.
2. Because vertical angles are congruent and (∠WOV, and ∠YOZ) are a pair of them, they equal the same as each other so they're both 60°.
3. You can make any equation with x included as long as it equals 60° mine was just an example you can make your own like 10x+10=60 or 4x+20=60. Also to create your equation you also need to use the angle fact of the vertical angles