What happens to the charges in current electricity?

Answers

Answer 1

Answer:

This is just a quick tip.

Explanation:

An electric current is the movement of particles, starting at the moment when an external voltage is applied at one of the ends of the conductor. That, in turn, generates an electric field on the negatively charged electrons that are attracted to the positive terminal of the external voltage.

Related Questions

if 7.66 g of cuno3 is dissolved in water to make a 0.140 m solution, what is the volume of the solution in milliliters?

Answers

The volume of the solution in milliliters is 547.13 mL.

How to calculate the volume of the solution in milliliters?

The molarity of the solution is given by;

Molarity = Number of moles of solute / Volume of solution in liters

Using the above formula, we can calculate the volume of the solution as;

Volume of solution in liters = Number of moles of solute / Molarity

Number of moles of CuNO3 can be determined as follows:

Number of moles = Given mass of the substance / Molar mass of the substance

= 7.66 g / (Cu: 63.55 g/mol + N: 14.01 g/mol + 3O: 3 x 16 g/mol)

= 0.05 mol

Substituting the values of molarity and number of moles of CuNO3 in the formula of volume of solution, we get:

Volume of solution in liters = Number of moles of solute / Molarity

= 0.05 mol / 0.140 M = 0.357 L

Converting the volume in liters to milliliters;

Volume in milliliters = Volume in liters × 1000

= 0.357 L × 1000= 357 mL

Thus, the volume of the solution in milliliters is 357 mL.

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a sample of metal has a mass of 22.82 g, and a volume of 6.03 ml. what is the density of this metal?

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The density of the metal sample is 3.781 g/mL.

To calculate the density, you need to divide the mass (22.82 g) by the volume (6.03 ml). Thus, 22.82 g / 6.03 ml = 3.781 g/mL.

Density is a measure of the mass per unit volume of a material or object. It is calculated by dividing the mass by the volume. The SI unit of density is kg/m3, but for solids and liquids, g/mL is a commonly used unit of density.

The density of a material or object will change depending on the temperature or pressure, so it is important to consider the temperature and pressure when determining the density of a material or object. For example, the density of water changes from 0.958 g/mL at 4°C to 0.997 g/mL at 25°C.

Therefore, when calculating the density of a metal sample, it is important to ensure that the mass and volume are measured at the same temperature and pressure.

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PLEASE HELP THIS IS URGENT

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The equation for the production of sulfur trioxide gas from sulfur dioxide (57.50 g) and oxygen (20.0 L) using the ideal gas law indicates;

The volume of sulfur trioxide that will be formed at STP is 20.1 L

The volume of sulfur trioxide formed at 15.0°C and 98920 Pa is 21.7 L

What is the ideal gas law?

The ideal gas law is an equation of state that describes an ideal gas behavior. It relates the pressure (P), volume (V), and temperature (T) of a gas to the number of moles (n) of the gas and the universal gas constant. The equation is written as P·V = n·R·T

The balanced chemical equation for the reaction is: 2SO₂ (g) + O₂ (g) --> 2SO₃ (g)

First, we need to convert the given amounts of reactants to moles. We can do this by using the molar mass of SO₂ (64.07 g/mol) and the ideal gas law for O₂ (P·V = n·R·T). At STP (Standard Temperature and Pressure), the temperature is 0°C (273.15 K) and the pressure is 1 atm (101325 Pa). The gas constant R is 8.314 J/Kmol.

The number of moles of SO₂ is: 57.50 g/(64.07 g/mol) = 0.897 moles

The number of moles of O₂ is; (101325 Pa)·(20.0 L)/(8.314 J/K.mol)·(273.15 K) = 0.892 moles

Since the ratio of SO₂ to O₂ in the balanced equation is 2:1, SO₂ is the limiting reactant and will determine the amount of product formed.

The number of moles of SO₃ produced is; (0.897 mol SO₂)·(2 mol SO₃/2 mol SO₂) = 0.897 mol (Which is based on the number of moles of SO₂ in the reactant side of the equation)

At STP, one mole of any gas occupies a volume of 22.4 L, so the volume of SO₃ produced at STP is: (0.897 mol) × (22.4 L/mol) ≈ 20.1 L

To find the volume of SO₃ at 15°C and 98920 Pa, we can use the ideal gas law again; P·V = n·R·T

V = (n·R·T)/P = ((0.897 mol)·(8.314 J/K.mol)·(288.15 K))/(98920 Pa) ≈ 21.7 L

Therefore, the volume of sulfur trioxide formed at STP is 20.1 L and at 15°C and 98920 Pa is 21.7 L

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the sodium atom loses 1 electrons when it reacts with something. the electron configuration of the sodium ion is the same as the electron configuration of

Answers

The sodium atom loses 1 electron when it reacts with something. The electron configuration of the sodium ion is the same as the electron configuration of the noble gas neon.

An electron is a negatively charged subatomic particle that orbits the nucleus of an atom.

The electrons that orbit the nucleus of an atom are arranged in shells, which are concentric circles around the nucleus, in what is known as the electron configuration. Electron configuration is the arrangement of electrons in the orbitals of an atom or molecule in its ground state.

Sodium is a chemical element with the symbol Na and atomic number 11.

Sodium is a soft, silvery-white metal that is extremely reactive.

Sodium readily loses one electron to form a positively charged ion, and it is this characteristic that makes it an important component of many compounds.

In a neutral atom, a sodium atom has eleven electrons, with the electron configuration being 1s²2s²2p⁶3s¹.

When a sodium atom loses an electron, it becomes a positively charged sodium ion with a 1+ charge.

When a sodium atom loses an electron, the electron configuration of the sodium ion is the same as that of the noble gas neon. Therefore, the electron configuration of a sodium ion is 1s²2s²2p⁶.

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a sample of neon has a volume of 40.81 m3 at 23.5c. at what temperature, in kelvins, would the gas occupy 50.00 cubic meters? assume pressure is constant. a. 363.27 k b. 230.54 k c. 242.0 k d. 28.79 k

Answers

At the temperatute of 363.27 K the sample of the gas Neon would occupy a volume of 50.00 cubic meters. Therefore option A can be considered correct.

Using the combined gas law in order to solve this problem

(P₁V₁)/T₁ = (P₂V₂)/T₂

( P is the pressure, V is the volume, and T is the temperature)

Since the pressure is constant, we can simplify the equation to:

V₁/T₁ = V₂/T₂

After inserting the values given in the problem equation,

V₁ = 40.81 m³

T₁ = 23.5°C + 273.15 = 296.65 K

V₂ = 50.00 m³

We can solve for T₂= (V₂/V₁) × T₁

T₂ = (50.00/40.81) × 296.65

T₂ = 363.27 K

Hnce, the temperature in kelvins at which the gas would occupy the volume of 50.00 cubic meters is calculated out to be 363.27 K.

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doppelbocks are lagers unified by what characteristic? group of answer choices they have almost no bitterness a low alcohol content a high alcohol content they are very bitter

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Doppelbocks are lagers unified by their high alcohol content.

What are doppelbocks?

Doppelbocks are German lagers that are dark and full-bodied. They are recognized for their rich malt flavors and alcoholic content, which is typically over 7% by volume. The monks of Munich developed the style in the 17th century, and the doppelbock style has been associated with monastic brewing ever since.

Doppelbocks are unified by high alcohol content because they are high in maltose and other fermentable sugars, which make them perfect for long, cold fermentations that yield a rich, complex, and smooth flavor. Lagers are a type of beer typically fermented at low temperatures and for an extended period. They are one of two significant categories of beer, the other being ales. Lagers are usually lighter in color and smoother in flavor than ales. They are also typically lower in alcohol content and have a cleaner, crisper taste than ales.

In conclusion, Doppelbocks are lagers unified by high alcohol content.

Answers

The ratio of moles of water to moles of dry sample can be found by dividing the percentage of water by 100.

The calculation of the number of water molecules in a crystal can be performed by analyzing the molar mass of the unhydrated crystal, which contains no water molecules. The ratio of moles of water to moles of dry sample can then be found by comparing the molar masses of the hydrated and unhydrated crystals.

The formula for calculating the number of water molecules in a crystal is as follows:

Percentage of water in crystal = (Molar mass of water / Molar mass of hydrate) * 100

The percentage of water in a crystal can then be used to determine the ratio of moles of water to moles of dry sample. To calculate the number of water molecules in an unknown sample, you must first determine the molar mass of the unhydrated sample. This can be done by dividing the mass of the sample by the number of moles in the sample. The mass of the sample is the sum of the masses of the dry sample and the water molecules. The molar mass of the water molecules is 18.015 g/mol.

To determine the mass of the water molecules, you must subtract the mass of the dry sample from the mass of the sample. The molar mass of the unhydrated sample can then be determined by dividing the mass of the dry sample by the number of moles in the sample. Once the molar mass of the unhydrated sample is known, the percentage of water in the sample can be calculated using the formula given above.

Finally, the ratio of moles of water to moles of dry sample can be found by dividing the percentage of water by 100.

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How many grams of chlorine gas can be liberated from the decomposition of 169. 0 g. Of AuCl3

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169.0 g of [tex]AuCl _{3}[/tex] can liberate 118.4 g of [tex]Cl_{2}[/tex] gas upon decomposition. The molar mass of [tex]AuCl _{3}[/tex] is 303.33 g/mol, which means that 1 mole of [tex]AuCl _{3}[/tex]contains 3 moles of chlorine (3 atoms of chlorine).

To determine the moles of [tex]AuCl _{3}[/tex]in 169.0 g, we divide the mass by the molar mass:

169.0 g / 303.33 g/mol = 0.557 moles of [tex]AuCl _{3}[/tex]

Since each mole of [tex]AuCl _{3}[/tex] produces 3 moles of chlorine, the total moles of chlorine that can be liberated from the decomposition of 0.557 moles of [tex]AuCl _{3}[/tex]is:

0.557 moles x 3 = 1.671 moles of [tex]Cl_{2}[/tex]

Finally, we use the molar mass of chlorine ([tex]Cl_{2}[/tex]), which is 70.90 g/mol, to convert the moles of [tex]Cl_{2}[/tex]to grams:

1.671 moles x 70.90 g/mol = 118.4 g of [tex]Cl_{2}[/tex]

Therefore, 169.0 g of [tex]AuCl _{3}[/tex]can liberate 118.4 g of [tex]Cl_{2}[/tex]gas upon decomposition.

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which is the best colored indicator to use in the titration of 0.1 m ch3cooh(aq) with naoh(aq)? why? look up ka values in the appendix. indicator pka bromocresol green 4.8 bromothymol blue 6.8 phenolphthalein 9.2 group of answer choices