Answer:
Single atoms of elements are not molecules.
Explanation:
A single oxygen, O, is not a molecule. When oxygen bonds to itself (e.g., O2, O3) or to another element (e.g., carbon dioxide or CO2), molecules are formed
Suppose object A has double the specific heat and triple the mass of object B. If the same amount of heat is applied to both objects, how will the temperature change of A be related to the temperature change of B? Enter your answer to three significant figures.
Taking into account the definition of calorimetry, the temperature change of A will be one sixth of the temperature change of B.
CalorimetryCalorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
So, the equation that allows to calculate heat exchanges is:
Q = c× m× ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
Temperature change of A related to the temperature change of BIn this case, for object A:
QA = cA× mA× (ΔT)A
and for object B:
QB = cB× mB× (ΔT)B
You know:
Object A has double the specific heat of object B. ⇒ cA= 2× cB
Object A has triple the mass of object B. ⇒ mA= 3× mB
If the same amount of heat is applied to both objects ⇒ QA= QB
Then:
cA× mA× (ΔT)A= QB = cB× mB× (ΔT)B
2× cB × 3× mB× (ΔT)A= cB× mB× (ΔT)B
Solving:
6× cB × mB× (ΔT)A= cB× mB× (ΔT)B
(ΔT)A= (cB× mB× (ΔT)B) ÷ (6× cB × mB)
(ΔT)A=[tex]\frac{1}{6}[/tex] (ΔT)B
Finally, the temperature change of A will be one sixth of the temperature change of B.
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The molar mass of sucrose (c12h22o11) is 342.3 g/mol. a chemist has a 0.500-mol sample of sucrose. what is the mass, in grams, of this sample? 171 grams 342 grams 500 grams 684 grams
Mass is the measure of the quantity of the substance present in the sample containing a compound or molecule. The mass of sucrose in the sample is 171 g.
What is mass?The mass of the compound in the sample is the product of the number of moles of the substance and the molar mass of the compound.
Given,
The molar mass of the sucrose compound = 342.3 g/mol
Number of moles of sucrose = 0.500 moles
Mass of sucrose is calculated as:
[tex]\begin{aligned}\rm mass &= \rm moles \times molar \; mass\\\\&= 0.500 \;\rm moles \times 342.3 \;\rm g/mol\\\\&= 171.15 \;\rm gm\end{aligned}[/tex]
Therefore, option A. 171 gm is the mass of sucrose.
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The correct answer is option A: 171 grams
Explanation: Got 90% on the quiz on edge and got this answer right
What do the neural pathways for taste, hearing, sight, and touch have in common
Answer:
All of the signals pass through the thalamus
Explanation:
how many liters of water would it require to 36 grams of the substance?
3 liters
________________
The rusting of iron is represented by the equation 4Fe + 3O2 --> 2Fe2O3. If you have a 3.5-mol sample of iron, how many grams of O2 are needed to rust the iron completely?
34.9 g
84.0 g
16.5 g
48.6 g
Answer:
84.0 g
Balanced equation: 4Fe + 3O2 --> 2Fe2O3
3.5-mol sample of ironFind moles of oxygen:
4Fe : 3O24 : 3(3.5/4)*3 = 2.625 molesFind mass of O2
mass = moles * Mrmass = 2.625 * 32mass = 84 gA mixture of three gases has a total pressure of 94.5 kpa. if the partial pressure of
the 1st gas is 65.4 kpa and the partial pressure of the 2nd gas is 22.4 kpa, what is the
partial pressure of the 3rd gas of the mixture?
Answer: 6.7 kPa
Explanation:
Pressure Total = P(partial 1) + P(partial 2) + P(partial 3) →
94.5 kPa = 65.4 kPa + 22.4 kPa + P(partial 3) →
6.7 = P(partial 3) :)
According to the Dalton's law of partial pressures the total pressure exerted by a mixture of gases is equal to the sum of the partial pressures exerted by each individual gas in the mixture.
So, P[tex]_o[/tex] = P[tex]_1[/tex]+ P[tex]_2[/tex]+ P[tex]_3[/tex]
[tex]\longrightarrow[/tex]94.5 = 65.4+ 22.4 + P[tex]_3[/tex]
[tex]\longrightarrow[/tex]94.5 = 87.8+ P[tex]_3[/tex]
[tex]\longrightarrow[/tex] P[tex]_3[/tex] = 94.5 - 87.8
[tex]\longrightarrow[/tex]P[tex]_3[/tex] = 6.7 kpa
Therefore, partial pressure of the 3rd gas of the mixture is 6.7 kpa .
How many grams of O2 are made if 2.90 moles of potassium chlorate react based on the same unbalanced equation below
Answer: 139.2 g
Explanation:
2.9 mol KClO3 (3 mol O2 / 2 mol KClO3) (32 g / 1 mol O2) = 139.2 grams :)
What are the key control points within the citric acid cycle?
The citrate synthase, isocitrate dehydrogenase, and the α-ketoglutarate dehydrogenase complex are the three key control points.
What are the key control points within the citric acid cycle?The key control points in citric acid cycle are the reactions catalyzed by citrate synthase, isocitrate dehydrogenase, and the α-ketoglutarate dehydrogenase complex.
So we can conclude that citrate synthase, isocitrate dehydrogenase, and the α-ketoglutarate dehydrogenase complex are the three key control points.
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The citric acid cycle is a chemical cycle that releases stored energy. Citrate synthase, isocitrate dehydrogenase, and alpha-ketoglutarate dehydrogenase are the control point of the cycle.
What is a citric acid cycle?The citric acid cycle or the TCA cycle (tricarboxylic acid cycle) is the chemical series of reactions that releases energy from food sources like fats, carbohydrates, and proteins.
The TCA cycle includes enzymes and many substances that regulate it but three major points are Citrate synthase, isocitrate dehydrogenase, and alpha-ketoglutarate dehydrogenase.
Therefore, they get inhibited, regulated, and limit the rate of the reaction.
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hello people~
Polyethylene terephthalate belongs to which class of synthetic polymer?
A. None of these
B. Polyolefin
C. Nylon
D. Polyester
Answer:
Polyester
Explanation:
Polyethylene terephthalate or shortly known as PET its a clean and strong polyesterIt is used in packagingConsider the combustion reaction for acetylene. 2c2h2(l) 5o2(g) right arrow. 4co2(g) 2h2o(g) if the acetylene tank contains 37.0 mol of c2h2 and the oxygen tank contains 81.0 mol of o2, what is the limiting reactant for this reaction? c2h2 o2 co2 h2o
The limiting reactant for the combustion reaction for acetylene is oxygen.
What is limiting reagent?Limiting reagents are those reagent which is present in less quantity as compared to the other reagent present for the formation of product.
Given chemical reaction is:
2C₂H₂(l) + 5O₂(g) → 4CO₂(g) + 2H₂O(g)
From the stoichiometry of the reaction, it is clear that:
2 moles of C₂H₂ = react with 5 moles of O₂
37 moles of C₂H₂ = react with 5/2×37=92.5 moles of O₂
And given moles of oxygen is 81 moles.
81 moles of O₂ = reacts with 2/5×81=32.4 moles of C₂H₂
And given moles of C₂H₂ = 81 moles.
Hence, O₂ is the limiting reagent.
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Answer:
O2 is the limiting reactant.
What is the molarity of a solution formed when you add 200. Ml of water to 50. Ml of 5. 0 m hcl
The molarity of a solution formed when you add 200 mL of water to 50 mL of 5. 0 M HCl is 1.25M.
How to calculate molarity?The molarity of a solution can be calculated using the following formula:
M1V1 = M2V2
Where;
M1 = molarity of a baseM2 = molarity of acidV1 = volume of baseV2 = volume of acidM1 × 200 = 50 × 5
200M1 = 250
M1 = 250/200
M1 = 1.25M
Therefore, the molarity of a solution formed when you add 200 mL of water to 50 mL of 5. 0 M HCl is 1.25M.
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predict what happens when lead is added to nitric acid
When Lead reacted with nitric acid, lead(II) nitrate, nitrogen oxide and water are produced.
What products are produced when lead reacts with nitric acid?
Lead(II) nitrate, nitrogen oxide and water are the products which are produced by reacting lead and nitric acid with each other. The nitrogen attach with the lead molecule as well as oxygen which produces Lead(II) nitrate and nitrogen oxide.
So we can conclude that when Lead reacted with nitric acid, lead(II) nitrate, nitrogen oxide and water are produced.
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8) If you apply a force of 50N to an object, but the object doesn't move,
how much WORK has been accomplished? Explain.
0 J
Work = Force * Displacement
Since displacement is 0 m (object isn't moving), work would also be 0.
what happens to a cell placed in an isotonic solution
Answer:
The cell's volume will remain stable.
Explanation:
If a cell is placed in an isotonic solution, there will be no net flow of water into or out of the cell, and the cell's volume will remain stable. If the solute concentration outside the cell is the same as inside the cell, and the solutes cannot cross the membrane, then that solution is isotonic to the cell.
How should you prepare a buret for titration before loading it with titrant?.
The buret should be conditioned before loading it with the titrant.
What is a Buret?This is defined as laboratory apparatus which is used in quantitative chemical analysis to measure the volume of a liquid or a gas.
It should be conditioned with the titrant solution to prevent dilution from occurring as a result of cleaning it with water.
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Please help! How many isotopes are in arsenic?
Answer:
Arsenic (33As) has 33 known isotopes and at least 10 isomers.
A balloon has a volume of 22.4 L at 273 K and 760 mm Hg. What will be the new volume if the pressure is
doubled to 2.00 atm?
The new volume of the gas in the balloon when the pressure is doubled is determined as 11.2 L.
General gas equation
The new volume of the balloon is determined by applying general gas equation as shown below
P₁V₁/T₁ = P₂V₂/T₂
Where;
P₁ is the initial pressure of the gas = 760 mmHg = 1 atmV₁ is the initial volume of the gas = 22.4 LT₁ is the initial temperature of the gas = 273 KP₂ is the final pressure of the gas = 2 atmT₂ is the final temperature of the gas = 273 KV₂ is the final volume of the gas = ?[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} \\\\V_2 = \frac{P_1V_1T_2}{T_1P_2} \\\\V_2 = \frac{1 \times 22.4 \times 273}{273 \times 2} \\\\V_2 = 11.2 \ L[/tex]
Thus, the new volume of the gas in the balloon when the pressure is doubled is determined as 11.2 L.
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what determines the role of an organism in an ecosystem?
Answer:
An organism's role within an ecosystem depends on how it obtains its food. Plants and animals obtain their food in very different ways, so they have very different roles in an ecosystem. The way in which an organism obtains food also affects its interactions with other organisms in the ecosystem.
Explanation:
On the basis of the information below, the dissolution of FeF2(s) in acidic solution is A. thermodynamically favorable, because K2 > 1 B. thermodynamically favorable, because K3 > 1 C. not thermodynamically favorable, because K1<1 D. not thermodynamically favorable, because K3 < 1 hint (Hess's law) FeF2(s) – Fe2+(aq) + 2 F"(aq) F"(aq) + H+ (aq) 2 HF(aq) FeF2(s) + 2 H+ (aq) 2 Fe2+ (aq) + 2 HF(aq) K1 = 2 x 10-6 K2 = 1 * 103 K3 = ?
Since K3 is greater than 1, the reaction is thermodynamically favorable.
Data;
FeF2 is in an acidic solutionK2 > 1 is thermodynamically favorablek3 > 1 is not thermodynamically favorableK1<1 is not thermodynamically favorableHess LawThis states that the heat change in a given chemical reaction is the same irrespective of the number of process in which the reaction is effected.
Using Hess Law;
[tex]rxn_3 = rxn_1 * 2rxn_2\\k_3 = k_1 * k_2^2\\k_3 = 2*10^-^6 * (1*10^3)^2\\k_3 = 2[/tex]
substituting this using Gibbs law,
[tex]\delta G^0_3 = -RT\ln K_3\\\delta G^0_3 < 0[/tex]
Since K3 is greater than 1, the reaction is thermodynamically favorable.
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Determine the mass of sodium acetate necessary to produce 100 ml of an acetate buffer
Explanation:
Ethanoic acid is a weak acid and dissociates:
C
H
3
C
O
O
H
⇌
C
H
3
C
O
O
−
+
H
+
For which
K
a
=
[
C
H
3
C
O
O
−
]
[
H
+
]
[
C
H
3
C
O
O
H
]
=
1.8
×
10
−
5
Please remember that these are equilibrium concentrations .
p
K
a
=
−
log
K
a
=
−
log
[
1.8
×
10
−
5
]
=
4.74
n
=
c
×
v
∴
n
C
H
3
C
O
O
H
=
0.20
×
200.0
1000
=
0.04
write the name molecular and condensed formula of alkyl groups with the following number of carbons 1,2,3,4,5,6,7,8,9,10,11,12
1)
methyl
CH3 (mol)
CH3- (struc)
2)
ethyl
C2H5
CH3-CH2-
3)
propyl
C3H7
CH3-CH2-CH2-
4)
butyl
C4H9
CH3-CH2-CH2-CH2-
5)
pentyl
C5H11
CH3-CH2-CH2-CH2-CH2-
6)
hexyl
C6H13
CH3-CH2-CH2-CH2-CH2-CH2-
7)
heptyl
C7H15
CH3-CH2-CH2-CH2-CH2-CH2-CH2-
8)
octyl
C8H17
i will stop writing the condensed formula ust add another CH2
9)
nonyl
C9H19
10)
decyl
C10H21
11)
Undecyl
C11H23
12)
dodecyl
C12H25
Explain why Na, Mg, and Al are good conductors of electricity?
A chemist adds 36.0 g of sodium chloride to 200 g of water at STP and all of the sodium chloride dissolves. What is the solute in this scenario?
A. Sodium
B. Sodium Chloride
C. Water
The solute in the scenario where a chemist adds 36.0 g of sodium chloride to 200 g of water at STP and all of the sodium chloride is sodium chloride.
What is a solute?A solute is a substance that forms a solution with another substance called solvent in a process called solubility.
According to this question, a chemist adds 36.0 g of sodium chloride to 200 g of water at STP and all of the sodium chloride dissolves in the water.
This shows that the sodium chloride is the solute added to the water (solvent).
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When two heterozygous parents are crossed (Aa X Aa), what percent of the offspring will have a dominant phenotype?
75% dominant and 25% resistive
how many molecules are required to produce 15.8 moles of no2
✥ So, in 1.25 moles of NO2, you would have 1.25 moles of N and (2 x 1.25) 2.50 moles of O.
0.1 mole = Avogadro's number of particles (approx. 6.022x10^23 particles/mol)
So, #oxygen atoms = 2.50 mol x 6.022x10^23 atoms/mol
6.022x10^23 atoms/molOr, approximately 1.51x10^24 oxygen atoms.
Hope this answer helps you ✨
Suppose a researcher wanted to extract as much zinc ion as possible from solution a without any copper (ii) impurity. How many milliliters of solution b should the researcher add to solution a?
The extraction of metal usually makes use of the method of precipitation in which a reagent is added which is able to precipitate the required metal in its pure form without impurities.
What is extraction?The process of extraction has to do with the removal of a substance from another. It is usually the way that pure substances are obtained in chemistry. The question is incomplete but I will try to give a general idea.
The extraction of metal usually makes use of the method of precipitation in which a reagent is added which is able to precipitate the required metal in its pure form without impurities. We can not make numerica;l calculatiosn as the values are missing.
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Hikers noticed that a sealed bag of potato chips puffs up when taken to the top of a mountain. Suppose that at the valley floor below, the air pressure is 1. 0 atm, the temperature is 25°C, and the volume of the bag is 0. 985 L. At the top of the mountain, the temperature is 22°C and the bag has puffed up to 1. 030 L. What is the air pressure on top of the mountain? Type in your answer using the correct number of significant figures. Formula: P1V1 T1 = P2V2 T2 atm.
The final pressure or the air pressure on the top of the mountain is 0.818.
What is air pressure?Air pressure is the pressure exerted by air in the atmosphere of the earth.
By the Gas law
[tex]\dfrac{P_1V_1}{ T1} =\dfrac{ P_2V_2 }{T_2}[/tex]
Given, the pressure of the valley floor is 1 atm. = P1
The temperature is 25° C = T1
The volume of the bag is 0.985 L. = V1
The temperature at the top of the mountain is ° C = T2
Now, the volume of the bag is 1. 030 L = V2
To find P2
Put the values in the formula
[tex]\dfrac{1 atm \times0.985 L}{ 25} =\dfrac{ P_2 \times 1. 030 L }{22}\\\\0.03832 = 0.0468 \times P_2\\\\P_2= 0.818[/tex]
Thus, the final pressure is 0.818.
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The acid dissociation constant of alloxanic acid is. Calculate the ph of a solution of alloxanic acid. Round your answer to decimal place
Answer:
The pH of a 4.4 M solution of boric acid is 4.3
Explanation:
at t=0 cM 0 0
at eqm
So dissociation constant will be:
Give c= 4.4 M and = ?
Putting in the values we get:
Also
Thus pH of a 4.4 M solution is 4.3
What is the effect on the total pressure inside a closed vessel if... a) More gas is added? b) The container's volume is increased?
(a) When more gas is added, the number of moles of the gas increases, and the total pressure of gas inside same vessel will increase.
(b) When the conatiner's volume is increased, the total pressure of gas inside the vessel will decrease.
Ideal gas lawThe ideal gas law of general gas equation, can be used to describe the behavior of an ideal gas.
The ideal gas law is given as;
PV = nRT
where;
P is pressure of the gasV is the volume of the gasn is the number of gas molesR is ideal gas constantT is temperature of the gasWhen more gas is added, the number of moles of the gas increases, and the total pressure of gas inside same vessel will increase.
When the conatiner's volume is increased, the total pressure of gas inside the vessel will decrease.
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Calculate the kovats retention index for an unknown using the retention times 1. 6 min for ch4, 12. 8 min for octane, 15. 4 min for the unknown, and 19. 6 min for nonane
For an unknown using the retention times 1. 6 min for ch4, 12. 8 min for octane, 15. 4 min for the unknown, and 19. 6 min for nonane, the kovats retention index is mathematically given as
I = 807.857
What is Kovats retention index?Generally, the equation for the Kovats index(i) is mathematically given as
[tex]I= \frac{100[n + (N - n) x (Log tr (unknown) - logtr (n))}{ logtr(N) - logtr(n))]}[/tex]
Therefore
[tex]I= \frac{100[ 1+8*(log(14.7) -log (1.5)}{log (19.8) - log (1.5)) 0]}[/tex]
I = 100[ 1+8*(0.991/1.12)]
I = 807.857
In conclusion, Kovats retention index
I = 807.857
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Kovats retention index is a system that converts the retention time into the independent constants of the system. The Kovats retention index for the unknown is 807.857.
What is the Kovats retention index?The Kovats retention index (I) is the system used in analytical techniques like gas chromatography for the conversion of the retention time. It is given mathematically as:
[tex]\rm I = \rm \dfrac{100[n+(N-n)x(Logtr(unknown)-logtr(n))}{Logtr(N)-Logtr(n)]}[/tex]
Substituting values and solving further,
[tex]\begin{aligned} \rm I &= \rm \dfrac{100[1+8 \times (Log(14.7) - log (1.5))}{(log (19.8) - log (1.5))0}\\\\&= 100 [ 1 + 8 (\dfrac{0.991}{1.12})]\\\\&= 807.857\end{aligned}[/tex]
Therefore, the Kovats retention index for an unknown is 807.857.
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