Which answer represents a list of UNBALANCED forces?
A group of people playing tug of war, where one side has two small children, and
the other side has two large adults: A motorcycle that is accelerating; A ball that
is decelerating as it rolls.
A skateboard sitting on a sidewalk; A car moving at a constant speed: Two
people pushing on a box with equal force
A person sitting in a chair: A train moving at a constant speed; a wagon being
pulled with 5 N of force from each direction.

Answers

Answer 1

The response that enumerates the unbalanced forces is a bunch of people playing tug-of-war with two young children on one side and two huge adults on the other.

Is the force used in tug of war balanced or unbalanced?

In a tug of war, if both teams are applying the same amount of force on the rope, balanced forces are displayed. The forces pulling on the rope are opposing in direction and of equal magnitude.

What's an illustration of an imbalanced force?

The imbalanced soldiers are acting onto the football if you kick it and it goes from one area to another. After being kicked, the ball goes from one location to another. An illustration of an uneven force is this.

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Related Questions

Use the data in the table to determine the identities of the two gasses that you found could be components of water. Provide evidence to support your claim.

Answers

The two gases that could be components of water are indeed hydrogen and oxygen.

Evidence to support this claim:

1. The chemical formula for water is H2O, which means that it is composed of two hydrogen atoms and one oxygen atom.

2. The table of elements shows that hydrogen (H) and oxygen (O) are both elements that exist in nature.

3. The atomic mass of hydrogen (1.008) and oxygen (15.999) matches the molecular mass of water (18.015).

4. Water is produced when hydrogen gas (H2) is burned in the presence of oxygen gas (O2), according to the following equation: 2H2 + O2 → 2H2O.

Overall, the evidence supports the conclusion that hydrogen and oxygen are the two gases that could be components of water.

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A current of O.S.A flows in a circuit with resistance 60 calculate the potential difference of the circuit

Answers

Therefore, the potential difference of the circuit is 30 volts.

What in electricity is a potential difference?

The external effort required to move a charge from one position to another in an electric field is known as an electric potential difference, or voltage. A test charge that has an electric potential differential of +1 will experience a shift in potential energy.

To calculate the potential difference (V) of the circuit, we can use Ohm's Law, which states that V = IR, where I is the current flowing through the circuit and R is the resistance of the circuit.

In this case, the current (I) is given as 0.5 A and the resistance (R) is given as 60 Ω. Therefore, we can substitute these values into Ohm's Law to find the potential difference:

V = IR

V = 0.5 A × 60 Ω

V = 30 volts

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A uniform electric field makes an angle of 60.0∘ with a flat surface. The area of the surface is 6.66×10−4m2. The resulting electric flux through the surface is 4.44 N⋅m2/C.
Calculate the magnitude of the electric field.(Express your answer with the appropriate units.)

Answers

Answer:

Explanation:

The electric flux through a surface is given by the equation:

Φ = EAcos(θ)

where Φ is the electric flux, E is the electric field, A is the area of the surface, and θ is the angle between the electric field and the surface normal.

We are given Φ = 4.44 N⋅m2/C, A = 6.66×10−4 m2, and θ = 60.0∘. Substituting these values into the equation above and solving for E, we get:

E = Φ / (Acos(θ))

= 4.44 N⋅m2/C / (6.66×10−4 m2cos(60.0∘))

= 1.62×10^4 N/C

Therefore, the magnitude of the electric field is 1.62×10^4 N/C.

The magnitude of the electric field is 13,320 N/C.

What is electric flux?

The electric flux through a surface is defined as the product of the electric field and the area of the surface projected perpendicular to the electric field. Mathematically, we can write:

Φ = EAcos(θ)

where Φ is the electric flux, E is the electric field, A is the area of the surface, and θ is the angle between the electric field and the surface normal.

Here in the Question,

We are given the electric flux Φ = 4.44 N·m^2/C, the area A = 6.66×10^-4 m^2, and the angle θ = 60.0°. We can solve for the magnitude of the electric field E by rearranging the equation as follows:

E = Φ / (A*cos(θ))

Substituting the given values, we get:

E = 4.44 N·m^2/C / (6.66×10^-4 m^2*cos(60.0°))

Simplifying the denominator, we get:

E = 4.44 N·m^2/C / (6.66×10^-4 m^2*0.5)

E = 13,320 N/C

Therefore, 13,320 N/C is the magnitude of the electric field.

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A student uses 800 W microwave for 30 seconds how much energy does a student use

Answers

Answer:

The student used 24000 Joules of energy.

Explanation:

We can use the Energy Power equation to solve this example.

[tex]\sf E=Pt[/tex]

Where

[tex]\sf E[/tex] is the energy in Joules (J)

[tex]\sf P[/tex] is the power in Watts (W)

[tex]\sf t[/tex] is the time in seconds (s)

Numerical Evaluation

In this example we are given

[tex]\sf P=800\\t=30[/tex]

Substituting our given values into the equation yields

[tex]\sf E=800 \cdot 30[/tex]

[tex]\sf E=24000[/tex]

24000 Joules  

[tex]\Large\bold{SOLUTION}[/tex]

To calculate the energy used by the student in this scenario, we can use the formula:

[tex]\sf{Energy\: (in\: Joules) = Power\: (in\: Watts) \times Time\: (in\: seconds)}[/tex]

Given that the student uses an 800 W microwave for 30 seconds, we can plug in these values to the formula:

[tex]\sf Energy = 800\: W \times 30\: s = 24,000\: J[/tex]

Therefore, the student uses 24,000 Joules of energy in this scenario.

[tex]\rule{200pt}{5pt}[/tex]

A student uses 800 W microwave for three seconds how much energy does a student use

Answers

Answer:

The student use 2400 Joules

Explanation:

From the formula E = pt

p = 800W

t = 3 seconds

=> E = 800*3 = 2400J

if an 80 kg person is 5 m away from a 100 kg person, what is the force of gravity between them?

Answers

The force of gravity between the 80 kg person and the 100 kg person, who are 5 meters apart, is approximately 1.07269 × 10^-6 Newtons.

To find the force of gravity between them?

The force of gravity between two objects is given by the formula:

F = G(m1*m2)/r^2

Where

F is the force of gravity G is the gravitational constant (6.67430 × 10^-11 N·(m/kg)^2) m1 and m2 are the masses of the two objectsr is the distance between them

Plugging in the given values, we get:

F = 6.67430 × 10^-11 N·(m/kg)^2 * (80 kg) * (100 kg) / (5 m)^2

Simplifying this expression, we get:

F = 1.07269 × 10^-6 N

Therefore, the force of gravity between the 80 kg person and the 100 kg person, who are 5 meters apart, is approximately 1.07269 × 10^-6 Newtons.

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A Car accelerate Cuniformly from) 13 ms -1 to 31ms-1 while entering the motor way Covering the distance 220m​

Answers

Answer:

3.84 m/s^2.

Explanation:

To solve this problem, we can use the following kinematic equation:

v^2 = u^2 + 2as

where:

v is the final velocity (31 m/s)

u is the initial velocity (13 m/s)

a is the acceleration (which is assumed to be constant)

s is the distance traveled (220 m)

We want to solve for the acceleration, so we can rearrange the equation as follows:

a = (v^2 - u^2) / 2s

Substituting the given values:

a = (31^2 - 13^2) / (2 x 220)

a = 3.84 m/s^2

Therefore, the acceleration of the car is 3.84 m/s^2.

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A body moving at 50m/s decelerates uniformly at 2/ms? until it comes to rest. What distance does it cover from the time it starts to decelerate to the time it comes to rest.​

Answers

Answer:

625

Explanation:

To solve this problem, we can use the following kinematic equation:

v^2 = u^2 + 2as

Where:

v = final velocity (0 m/s since the body comes to rest)

u = initial velocity (50 m/s)

a = acceleration (-2 m/s^2 since the body is decelerating)

s = distance

We want to find the distance (s) that the body covers from the time it starts to decelerate to the time it comes to rest. We can rearrange the equation to solve for s:

s = (v^2 - u^2) / (2a)

Substituting the values we have:

s = (0^2 - 50^2) / (2 x (-2)) = 625 meters

Therefore, the body covers a distance of 625 meters from the time it starts to decelerate until it comes to rest.

Imagine that scientists placed a satellite at the Earth-Moon L1 Lagrangian
point, which is a point between Earth and the Moon where the gravitational
pulls from the two bodies are equal and opposite. What would happen if a
satellite at this position drifted slightly closer to Earth?
O A.
A. The gravitational pull from the Moon would correct the satellite
and bring it back to the Lagrangian point.
OB. The satellite would stop drifting and would remain fixed in this
position because of its tangential velocity.
OC. The satellite would continue to drift toward Earth as Earth's pull
became stronger than that of the Moon.
OD. The gravitational pull from the Sun would eventually pull the
satellite from this point and cause it to directly orbit the Sun.

Answers

Answer:

Explanation:

A. The gravitational pull from the Moon would correct the satellite and bring it back to the Lagrangian point.

At the Earth-Moon L1 Lagrangian point, the gravitational pulls from the Earth and the Moon are balanced, and the satellite is in a stable equilibrium. If the satellite drifted slightly closer to Earth, the gravitational pull from the Earth would become stronger, but the gravitational pull from the Moon would also increase due to its closer distance, and this would correct the satellite's motion and bring it back to the Lagrangian point.

Why do you think the pylon in Figure 24 is designed the way it is, and not in the way shown in Figure 25?

Answers

They are specifically made tο be ideal fοr cοnducting live electrical lines because οf their electrical insulatiοn and mechanical tοughness. A structure called an electric pylοn οf hοt-rοlled steel bevels οr gusset plates.

What kinds οf patterns are used tο create electrical pylοns?

Other materials, such as cοncrete and wοοd, may alsο be utilised in additiοn tο steel. Transmissiοn tοwers can be divided intο fοur main categοries: suspensiοn, terminal, tensiοn, οr transpοsitiοn.

Whο was the electrical pylοn's designer?

This Central Electricity Bοard held a cοmpetitiοn in 1927, and the winning entry was chοsen by the classical designer Sir Reginald Blοοmfield. He settled οn an A-frame structure with latticewοrk that was οffered by the American cοmpany Milliken Brοthers and is still in use tοday.

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Complete question:

Find the density of seawater at a depth where
I the pressure atm
at the
the
surface is 1050 kg/m³. Seawater has a bulk
modulus of 2.3 x 10° N/m². Bulk modulus is
defined to be
B =
Po AP
Ap

Answers

Answer:

To find the density of seawater at a certain depth, we need to use the following equation:

P = P0 + ρgh

where:

P0 = pressure at the surface (given as 1 atm = 101325 Pa)

ρ = density of seawater at the depth we're interested in

g = acceleration due to gravity (9.81 m/s^2)

h = depth below the surface

We also need to use the bulk modulus equation to find the change in pressure with depth:

B = (ρ/ρ0)(P-P0)/P

where:

ρ0 = density of seawater at the surface (given as 1050 kg/m^3)

P = pressure at the depth we're interested in

Combining these two equations, we get:

B = (ρ/ρ0)((P0 + ρgh) - P0)/P

B = ρgh/P

ρ = (BP)/(gh)

Substituting the given values, we get:

ρ = (2.3 x 10^9 N/m^2)(101325 Pa)/(9.81 m/s^2)(1050 kg/m^3)(1 atm)

ρ ≈ 1031.4 kg/m^3

Therefore, the density of seawater at a depth where the pressure is 1 atm and the density at the surface is 1050 kg/m^3 is approximately 1031.4 kg/m^3.

How have astronomers used models to explain galactic evolution through mergers and collisions? Use this model to explain how astronomers might test their understanding of the physical processes of the universe.

Answers

Answer:

Astronomers use computer models to simulate the process of galactic evolution through mergers and collisions. These models are based on our current understanding of the physical laws that govern the behavior of matter and energy in the universe. By running simulations of galactic mergers and collisions, astronomers can test their understanding of how these physical processes work in practice and how they contribute to the formation and evolution of galaxies.

One way that astronomers might test their understanding of the physical processes of the universe is by comparing the predictions of their models to observations of real galaxies. For example, if a model predicts that a particular type of galaxy should have a certain shape, size, or distribution of stars, astronomers can compare these predictions to observations of actual galaxies to see if they match up. If there is a discrepancy between the model's predictions and the observations, this can indicate that there are some physical processes that are not well understood or included in the model.

Another way that astronomers might test their understanding is by looking for patterns or trends in the properties of galaxies that are consistent with the predictions of their models. For example, if a model predicts that galaxies that have undergone a recent merger should have a particular distribution of gas and dust, astronomers can look for evidence of this pattern in observations of real galaxies. If they find that the predicted pattern is consistently observed in a large sample of galaxies, this can provide support for the model's predictions and the physical processes that it includes.

Overall, computer models of galactic evolution through mergers and collisions provide a powerful tool for astronomers to test their understanding of the physical processes of the universe. By comparing the predictions of their models to observations of real galaxies and looking for consistent patterns and trends, astronomers can refine their understanding of how galaxies form and evolve over time.

The voltage of a battery is V and the current is I. If the voltage is doubled to 2V, what is the new current?
O 1/4
O 21
O 1/2
041

Answers

Answer:The current in a lightbulb with a voltage of 35.0 V and a resistance of 175 ohm is 0.2 A.

Find the current in a lightbulb?

Given:

The voltage in a lightbulb is given by the equation V=IR

V is the voltage, I is current, and R is the resistance.

The voltage of the lightbulb is given as 35.0 V.

The resistance of the lightbulb is given as 175 Ohm.

As the equation is given,

V= IR

where I is current, R is resistance and V is the voltage.

Now, I = V/R

As the value of Voltage and resistance of the lightbulb is given, we will put in the above equation, we get;

I = 35.0/ 175 A

I = 0.2 A.

Hence, the current of the lightbulb is 0.2 A.

Therefore, Option C is the correct answer.

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Explanation:

The bigger the spring constant, the more__________the spring is.

Answers

The bigger the spring constant, the more stiff or rigid the spring is.

What does it signify when a spring's spring constant is higher?

The exact amount of force needed to bend a spring depends on the spring constant. Although pounds/inch is a common measurement in North America, the standard international (SI) unit for spring constants is Newtons/meter. A stiffer spring has a greater spring constant, and vice versa.

What does it signify when the spring constant is higher?

The exact amount of force needed to bend a spring depends on the spring constant. Although pounds/inch is a common measurement in North America, the standard international (SI) unit for spring constants is Newtons/meter. A stiffer spring has a greater spring constant, and vice versa.

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Is this statement is correct ?? According to Newton's 4rd law, Action and reaction never start from the same point.
help me...​

Answers

Explanation:

I'm sorry, but the statement you provided is incorrect. There is no such thing as Newton's 4th law. Newton's laws of motion consist of three laws, which are:

An object at rest tends to stay at rest, and an object in motion tends to stay in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

The acceleration of an object is directly proportional to the force applied to it and inversely proportional to its mass.

For every action, there is an equal and opposite reaction.

None of these laws state that action and reaction never start from the same point. However, it is true that the action and reaction forces act on different objects, not necessarily at the same point. This is because Newton's third law states that every action has an equal and opposite reaction, which means that when one object exerts a force on another object, the second object exerts an equal and opposite force back on the first object.

Before a collision, a 200-kg Honda is driving 30 m/s towards a
600-kg Toyota that is not moving. After the crash, the two cars
are stuck together. What is their velocity?
m/s

Answers

As a result, the combined Honda-Toyota system's post-collision speed is 7.5 m/s.

How can you calculate the entire momentum prior to a collision?

The system's center of mass was v/2 before to the collision since one automobile had a velocity of v and the other zero. The total momentum is equal to the entire mass times the velocity of the center of mass, or (2m)(v/2) = mv before and after.

Initial momentum of Honda = m1 * v1

= 200 kg * 30 m/s

= 6000 kg·m/s

Final momentum of combined system = (m1 + m2) * v_final

Setting the two momenta equal to each other, we get:

6000 kg·m/s = 800 kg * v_final

Solving for v_final, we get:

v_final = 6000 kg·m/s / 800 kg

= 7.5 m/s

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What are some examples of conservation of energy?

Answers

Answer:

power plant

collision

Battery

Burning wood

speaker

Beating drum

In deep space, there is very little friction. Once they launch a probe into deep space, where there are no external forces acting on it, scientists shut the probe’s engines off because the scientists want the probe to

stop immediately.
speed up.
slow down.
move at constant velocity.

Answers

Move at constant velocity

How did Newton discovered gravity?​

Answers

Answer:

Isaac Newton, the English physicist, mathematician, and astronomer, discovered the concept of gravity in the late 17th century. The story of his discovery of gravity is one of the most famous in scientific history.

The most well-known anecdote is that Newton was sitting under an apple tree when an apple fell from the tree and hit him on the head. This event, however, is likely to be a myth created to make the story more memorable. Nonetheless, it is true that Newton began to wonder why objects fall to the ground instead of flying off into space.

Newton's curiosity led him to conduct experiments to understand the behavior of falling objects. He reasoned that the same force that caused an apple to fall to the ground was responsible for holding the moon in orbit around the Earth.

Newton's breakthrough came when he realized that the force that causes objects to fall to the ground is the same force that governs the motion of the planets in the solar system. He described this force as "gravity" and formulated his famous law of universal gravitation, which states that every object in the universe attracts every other object with a force that is proportional to the product of their masses and inversely proportional to the square of the distance between them.

Newton's discovery of gravity was a major scientific achievement that revolutionized our understanding of the physical world. It laid the foundation for the development of classical mechanics, and the law of gravitation has since been used to explain a wide range of phenomena in physics, from the motion of planets to the behavior of subatomic particles.

In summary, Newton discovered gravity through a process of curiosity, experimentation, and mathematical reasoning. Although the apple falling on his head is unlikely to be true, his discovery has had a profound impact on our understanding of the universe.

Answer:

Isaac Newton did not "discover" gravity, as it was already known that objects were attracted to each other. However, he did discover the law of universal gravitation, which states that every particle in the universe attracts every other particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of their separation distance.

Select in the ticker-timer a frequency of 25 Hz or 50 Hz. Determine the period of the ticker-timer. ​

Answers

Answer:

The period of a ticker-timer is the time interval between two consecutive dots made by the ticker.

If the frequency of the ticker-timer is 25 Hz, then it makes 25 dots in one second. Therefore, the period of the ticker-timer can be calculated as:

Period = 1/frequency = 1/25 Hz = 0.04 seconds

If the frequency of the ticker-timer is 50 Hz, then it makes 50 dots in one second. Therefore, the period of the ticker-timer can be calculated as:

Period = 1/frequency = 1/50 Hz = 0.02 seconds

So, the period of the ticker-timer is 0.04 seconds for a frequency of 25 Hz and 0.02 seconds for a frequency of 50 Hz

Explanation:

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What factors would create an ideal circuit?

Answers

An ideal circuit is a theoretical representation of an electrical circuit, where all components are perfect and all parameters such as resistance, capacitance, and inductance are zero.

The ideal circuit also has no energy losses, making it an ideal electrical system. To create an ideal circuit, the following factors must be considered:

1. Perfectly Conductive Wires: The wires and other conductors used in the circuit should be perfect conductors, which means the resistance should be zero. This will ensure that no energy is lost in the form of heat.

2. Zero Inductance: Inductance is a property of a circuit which causes a voltage drop when current flows through it. The ideal circuit should have no inductance so that the current can flow freely.

3. Zero Capacitance: Capacitance is a property in which electric charge builds up when current passes through it. To create an ideal circuit, the capacitance should be zero.

4. Zero Impedance: Impedance is the opposition to the flow of current in an electrical circuit. The ideal circuit should have zero impedance so that the current can flow freely.

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An athlete whirls a 7.66 kg hammer tied to the end of a 1.4 m chain in a simple horizontal circle where you should ignore any vertical deviations. The hammer moves at the rate of 0.372 rev/s. What is the tension in the chain? Answer in units of N.

Answers

The hammer's centripetal acceleration is therefore 100.59 m/s².

Using an example, what is acceleration?

An object has positive acceleration when it is going faster than it was previously. Positive acceleration was demonstrated by the moving car in the first scenario. Positive forward motion is being made by the car.

Hammer mass, m, is 6.55 kg. chain length, including the length of the arms, r = 1.3 m, Hammer's angular velocity is given by the formula: = 1.4 rev/s = 8.79646 rad/s (1 rev = 6.28 rad).

The formula a = V2/r, where V is the transverse velocity of the hammer, yields the centripetal acceleration.

V = r, hence

As a result, a = r²

A = 1.3 x 8.796462, or 100.59 m/s², is obtained by substituting the supplied numbers in the equation above.

The hammer's centripetal acceleration is therefore 100.59 m/s².

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Two asteroids are suspended in space 50 meters apart. The masses of the asteroids are 2000000 kg and
3000000 kg.

Answers

Answer:

Explanation:

What is the gravitational force between them?

To calculate the gravitational force between two objects, we can use the formula:

F = G * (m1 * m2) / r^2

where F is the gravitational force, G is the gravitational constant (6.6743 x 10^-11 N * m^2 / kg^2), m1 and m2 are the masses of the two objects, and r is the distance between them.

Plugging in the given values, we get:

F = (6.6743 x 10^-11 N * m^2 / kg^2) * (2000000 kg) * (3000000 kg) / (50 m)^2

F = 0.8046 N

Therefore, the gravitational force between the two asteroids is approximately 0.8046 N.

10. The energy states of an electron in a hydrogen atom is given by:


=

13.6




2
En=
n
2

−13.6 eV


Which of the following is not a possible energy of an emitted photon of the atom for an electron that is initially at

=
4
n=4?
0.66 eV
1.89 eV
2.55 eV
12.8 eV

Answers

Because it is less than the required minimum energy difference of 1.51 eV, the energy of 0.66 eV is not feasible. Hence, 0.66 eV is the correct answer.

When the hydrogen atom's energy in its ground state is 13.6 eV, what is the energy of the third excited state?

The electron is first assumed to be in the ground state (n=1) in a hydrogen atom. Hence, the electron's energy in its ground state is 13.6 eV. This means that 12.75eV is needed to transfer electrons from the ground state to the third excited state.

The following equation provides the energy levels:

En = -13.6/n² eV

where n is the main quantum number.

An electron can move from the n=4 level to the n=3, n=2, or n=1 level after initialization. For each of these transitions, the relevant photon energies and energy differences are as follows:

n=4 to n=3: ΔE = En=3 - En=4 = (-13.6/3²) - (-13.6/4²) = 1.51 eV

n=4 to n=2: ΔE = En=2 - En=4 = (-13.6/2²) - (-13.6/4²) = 3.40 eV

n=4 to n=1: ΔE = En=1 - En=4 = (-13.6/1²) - (-13.6/4²) = 10.2 eV

As a result, the released photons could have energies of 1.51 eV, 3.40 eV, or 10.2 eV.

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If 10 A of current flows through a 2 ohm resistor, what is the voltage of the battery?
20 V
0.2 V
OS V
12 V

Answers

The voltage of the battery would be 20 volts. Option I.

Voltage calculation

According to Ohm's law, the voltage (V) across a resistor is equal to the current (I) flowing through it multiplied by its resistance (R). Mathematically,

V = I × R

In this case, the current (I) flowing through the resistor is given as 10 A and the resistance (R) of the resistor is given as 2 ohms. Substituting these values into the above formula, we get:

V = 10 A × 2 ohms = 20 volts

Therefore, the voltage of the battery is 20 volts.

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A porter can climb 10 staircase of 30cm each in 10 sec by carrying a 50kg bag. Calculate the power of the porter

Answers

Therefore, the power of the porter is 441,450 J/s, or approximately 441.5 watts.

What is work done?

The work done by the porter in lifting the 50 kg bag up the stairs can be calculated as the product of the force applied and the distance moved.

The force applied is the weight of the bag, which is given by:

F = m * g

where m is the mass of the bag and g is the acceleration due to gravity, which is approximately 9.81 m/s². Substituting the given values, we get:

F = 50 kg * 9.81 m/s²

F = 490.5 N

The distance moved by the porter in lifting the bag up one staircase is 30 cm, and the porter climbs 10 staircases in 10 seconds, which gives a speed of:

v = (10 * 30 cm) / 10 s

v = 30 cm/s

The power of the porter is the rate at which work is done, which can be calculated as:

P = W / t

where W is the work done and t is the time taken. Substituting the values, we get:

P = F * d * v / t

P = 490.5 N * 10 * 30 cm * 30 cm/s / 10 s

P = 441,450 J/s

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Owen hits a baseball with a velocity of 55 m/s. The ballpark fence is 120 m away.
Does the ball reach the fence if it leaves the bat traveling upward at an angle of 30°
to the horizontal?

Answers

Answer:

Explanation:

We can solve this problem using kinematic equations. We know that the initial velocity of the ball is 55 m/s at an angle of 30° to the horizontal. We can break this velocity into its horizontal and vertical components:

vx = v0 cos θ = 55 cos 30° = 47.6 m/s

vy = v0 sin θ = 55 sin 30° = 27.5 m/s

We can now use the vertical motion equation to find the time it takes for the ball to reach its maximum height:

Δy = vy t + 0.5 a t^2

At the maximum height, the vertical velocity of the ball is 0, so we have:

0 = vy + a t_max

Solving for t_max, we get:

t_max = -vy / a = -27.5 / (-9.8) = 2.81 s

The ball will take twice this time to reach the fence, since it needs to come back down to the ground:

t_total = 2 t_max = 5.62 s

The horizontal distance the ball travels during this time is:

Δx = vx t_total = 47.6 × 5.62 = 267.7 m

Since this distance is greater than the distance to the fence (120 m), the ball will reach the fence if it leaves the bat traveling upward at an angle of 30° to the horizontal.

What is a force that acts upon a projectile launched into the air?

1. Centripetal

2. Gravity

3. Trajectory

Answers

The force that acts upon a projectile launched into the air is gravity.

What is gravity?

Gravity is a fundamental force of nature that causes all physical objects to attract each other. It is the force that pulls objects towards each other, and it is the reason why objects with mass are attracted towards the center of the Earth.

When an object is launched into the air, it is subject to the force of gravity, which pulls the object down towards the Earth. As the object moves through the air, the force of gravity causes it to follow a curved path, known as a trajectory, until it eventually hits the ground. While other forces such as air resistance may also act upon the projectile, gravity is the primary force that determines the path of the projectile.

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A rock with a mass of 10.0 kg is balanced on top of a large boulder. Describe the forces acting on the rock, and use the concept of forces to explain why it stays on top of the boulder.

Answers

There are two forces acting on the rock: the force of gravity pulling it downward and the force of the boulder supporting it from underneath.

What is the force of gravity?

The force of gravity is the gravitational attraction between the rock and the Earth. It pulls the rock downward with a force equal to its weight, which is given by the equation Fg = mg, where Fg is the force of gravity, m is the mass of the rock, and g is the acceleration due to gravity (approximately 9.81 m/s^2).

Why do boulder stays on top?

The concept of forces explains why the rock stays on top of the boulder because the forces are balanced. The force of gravity pulling the rock downward is equal and opposite to the force of the boulder supporting it from underneath. As a result, the rock remains in equilibrium, or a state of balance, on top of the boulder. If either force were to change, the equilibrium would be disrupted, and the rock would either fall to the ground or be pushed off the boulder.

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HELP ME!!!!If a researcher is designing an electromagnet for a life-saving medical application, which properties of the magnet will she need to take into account?
Select two answers!!
Wether or not magnetic field is constant.
Number of could of conducting wire.
Wether or not domains are present in iron core.
Metal composition of conducting wire.

Answers

Answer:

Number of coils of conducting wire and whether or not domains are present in iron core are the two properties of the electromagnet that the researcher will need to take into account.

Explanation:

The number of coils of conducting wire affects the strength of the magnetic field produced by the electromagnet. More coils will produce a stronger magnetic field, while fewer coils will produce a weaker magnetic field. The researcher will need to determine the appropriate number of coils to produce the desired strength of the magnetic field for the medical application.

The presence of domains in the iron core is also an important consideration. The iron core of the electromagnet helps to concentrate the magnetic field and increase its strength. The domains in the iron core align with the magnetic field produced by the current flowing through the wire, and this alignment reinforces the magnetic field. If the iron core does not have domains, the magnetic field produced by the electromagnet will be weaker. Therefore, the researcher will need to ensure that the iron core has domains to maximize the strength of the magnetic field for the medical application.

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