Which choice could be used in proving that the given triangles are similar? A) PO 6 DE 4 II B) PO 4 EF 9 PO 4 DE 6 D) PR 6 DE 6 allo

Which Choice Could Be Used In Proving That The Given Triangles Are Similar? A) PO 6 DE 4 II B) PO 4 EF

Answers

Answer 1
[tex]\frac{PQ}{4}=\frac{DF}{6}[/tex]


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Suppose that $2000 is invested at a rate of 3.9%, compounded monthly. Assuming that no withdrawals are made, find the total amount after six years.Round your answer to the nearest cent.

Answers

Compound interest formula:

[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ \\ A\colon\text{Amount} \\ P\colon\text{ Principal} \\ r\colon\text{ interest rate (in decimals)} \\ n\colon\text{ number of times interest is compounded in a year} \\ t\colon\text{ time (in years} \end{gathered}[/tex]

Given data:

P= $2,000

r= 3,9% =0.039

n=monthly= 12

t= 6 years

[tex]\begin{gathered} A=2000(1+\frac{0.039}{12})^{12(6)} \\ \\ A=2000(1.00325)^{72} \\ \\ A\approx2526.33 \end{gathered}[/tex]

Then, the total amount after six years is $

Apply the product rule to rewrite the product below using a single base and exponent then simplify: 3^2 *3^3 our base is Answerour exponent is Answerthis simplifies to Answer

Answers

[tex]undefined[/tex]

Explanation:

[tex]3^2\text{ }\times3^3[/tex][tex]\begin{gathered} \text{The expression has same base.} \\ \text{Base = 3} \\ We\text{ take one base and bring the exponents together} \\ \text{The sign betw}en\text{ them changes from multiplication to addition} \end{gathered}[/tex][tex]\begin{gathered} 3^2\text{ }\times3^3\text{ = }3^{2\text{ + 3}} \\ \text{Exponent = 2 + 3} \\ \text{Exponent = 5} \end{gathered}[/tex][tex]\begin{gathered} \text{Simplifying:} \\ 3^{2+3}=3^5 \\ 3^5\text{ = 243} \end{gathered}[/tex]

26/w = 5/6 what is w?

Answers

Here, the expression is 26/w=5/6.

Therefore,

[tex]\begin{gathered} \frac{26}{w}=\frac{5}{6} \\ w=\frac{26\times6}{5} \\ w=\frac{156}{5} \\ w=31.2 \end{gathered}[/tex]

So, the value of w is 31.2

Use Part Il of the Fundamental Theorem of Calculus to evaluate the definite integral

Answers

Answer:

[tex]4\ln (2)+\frac{49}{3}\approx19.1059[/tex]

Given:

[tex]\int ^{-1}_{-2}\frac{7x^5-4x^2}{x^3}dx[/tex]

Simplify:

[tex]\int \frac{7x^3-4}{x}dx[/tex]

Expand:

[tex]\int (7x^2-\frac{4}{x})dx[/tex]

Apply linearity:

[tex]7\int x^2dx-4\int \frac{1}{x}dx[/tex]

Apply power rule and the standard integral ln(x)

[tex]7(\frac{x^3}{3})-4\ln (x)[/tex]

Now, applying the Fundamental Theorem of Calculus Part 2

[tex]\int ^{-1}_{-2}\frac{7x^5-4x^2}{x^3}dx=(7(\frac{(-1)^3}{3})-4\ln (-1))-(7(\frac{(-2)^3}{3})-4\ln (-2))[/tex][tex]=4\ln (2)+\frac{49}{3}[/tex]

Or approximately

[tex]\approx19.1059[/tex]

. In a 30°-60-90° triangle, the hypotenuse is 7 yards long.Find the exact lengths of the legs?

Answers

ANSWER

The lengths of the legs of the triangle are 6.06 yards and 3.6 yards.

EXPLANATION

First, let us make a sketch of the problem:

To find the length of the legs, we have to apply trigonometric ratios SOHCAHTOA.

We have that:

[tex]\sin (60)=\frac{\text{opposite}}{\text{hypotenuse}}[/tex]

From the diagram:

[tex]\begin{gathered} \sin (60)=\frac{x}{7} \\ \Rightarrow x=7\cdot\sin (60) \\ x\approx6.06\text{ yds} \end{gathered}[/tex]

We also have that:

[tex]\sin (30)=\frac{\text{opposite}}{\text{hypotenuse}}[/tex]

From the diagram:

[tex]\begin{gathered} \sin (30)=\frac{y}{7} \\ \Rightarrow y=7\cdot\sin (30) \\ y=3.5\text{ yds} \end{gathered}[/tex]

The lengths of the legs of the triangle are 6.06 yards and 3.5 yards.

Solve each of the following equations. Show its set on a number line. |4x-4(x+1)|=4

Answers

Solving this equation, we have:

[tex]\begin{gathered} |4x-4\mleft(x+1\mright)|=4​ \\ |4x-4x-4|=4 \\ |-4|=4 \\ 4=4 \end{gathered}[/tex]

Since the final sentence is always true, the solution set is all real numbers.

Showing it in the number line in blue, we have:

PLEASE HELP! BRAINLIEST

Find (w ∘ w)(−1) for w(x)=3x^2+3x−3.
Answer: (w ∘ w)(−1)=

Answers

Answer:

15

Step-by-step explanation:

wow(-1) means w(w(-1))

so we can find out what w(-1) is

3(-1)^2+3(-1)-3=3-3-3

which is -3

then we can find w(-3)

3(-3)^2+3(-3)-3

which is 15

1)Find the probability of randomly selecting the correct access code on the first try 4 digits (0 through 9)2)find the probability of NOT selecting the correct access code on the first try

Answers

There are 10 digits from 0 to 9.

First digit 10 ways

Second digit 10 ways

Third digit 10 ways

Fourth digit 10 ways

[tex]\text{There are 10}\times10\times10\times10\text{ ways for four digits.}[/tex]

[tex]\text{There are 10}000\text{ ways for four digits.}[/tex]

Hence the total outcomes =10000

Selecting the correct access code on the first try given favorable outcomes =1.

[tex]\text{The probability of randomly selecting the correct access code on the first try=}\frac{favorable\text{ outcome}}{\text{Total outcomes}}[/tex]

[tex]\text{=}\frac{1}{10000}[/tex]

[tex]=0.0001[/tex]

Hence the probability of randomly selecting the correct access code on the first try is 0.0001.

The probability of not selecting the correct access code on the first try=1-The probability of selecting the correct access code on the first try

The probability of not selecting the correct access code on the first try=1-0.0001

Hence the probability of not selecting the correct access code on the first try=0.9999.

3. Express the given integral as the limit of a Riemann sum but do not evaluate:

Answers

Expression of the integral [tex]\int\limits^3_0 {(x^{3}-6x) } \, dx[/tex] as the limit of a Riemann sum without any evaluation will be

Lim(n → ∞) ∑(n = 1 → ∞) [{(27i³/n³) - (18i/n)} * (3i/n)]

As per the question statement, we are provided with an integral [tex]\int\limits^3_0 {(x^{3}-6x) } \, dx[/tex] ,

And we are required to determine the expression of the above mentioned integral as the limit of a Riemann sum without any evaluation.

To start with, we need to know the formula [Δx = {(b - a)/n}]

And here, from our given integral [tex]\int\limits^3_0 {(x^{3}-6x) } \, dx[/tex], we get that, (a = 0) and

(b = 3). Therefore substituting the values of "a" and "b" in the formula to calculate Δx, we get,

[Δx = {(3 - 0)/n} = (3/n)]

Also, [(x[tex]_{i}[/tex]) = {a + (Δx)i} = {0 + (3/n)i) = (3i/n)],

Given, [ρ(x) = (x³ - 6x)], and thus, [ρ(x[tex]_{i}[/tex]) = ρ(3i/n)]

Or, [ρ(x[tex]_{i}[/tex]) = {(3i/n)³ - 6(3i/n)}]

Or, [ρ(x[tex]_{i}[/tex]) = {(27i³/n³) - (18i/n)}]

Then, Lim(n → ∞) ∑(n = 1 → ∞) ρ(x[tex]_{i}[/tex])Δx

= Lim(n → ∞) ∑(n = 1 → ∞) [{(27i³/n³) - (18i/n)} * (3i/n)]

Reimann Sum: In Mathematics, a Riemann sum is a certain kind of approximation method for an integral by a finite sum. Named after renowned German mathematician Bernhard Riemann, one very common application of the Reimann Sum is in approximating the area of functions or lines on a graph, and also the length of curve.

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5) Solve the formula r/m = c for m.

Answers

We have the following:

[tex]\frac{r}{m}=c[/tex]

solving for m:

[tex]\begin{gathered} r=m\cdot c \\ m=\frac{r}{c} \end{gathered}[/tex]

The start of a quadratic
sequence is
8, 18, 30, 44, 60, …
What is the nth term rule for this sequence?

Answers

Answer:

The correct option is D

98

The general term of the sequence is n(n+7)

You can find the general rule in two ways
8 = 1x8, 18 = 2x9, 30 = 3x10, 44 = 4x11, 60 = 5x12 … so in general T(n) = n(n + 7)

Or because the second differences are constant we know it uses squares
8 = 1^2 + 7, 18 = 2^2 + 14, 30 = 3^2 + 21, 44 = 4^2 + 28, 60 = 5^2 + 35 … so in general T(n) = n^2 + 7n

The table shows claims and their
probabilities for an insurance
company.
Amount of claim
(to the nearest $20,000)

$0
$20,000
$40,000
$60,000
$80,000
$100,000

Probability
0.70
0.16
0.09
0.03
0.01
0.01

Answers

Answer:

Step-by-step explanation:

This is an equation! Solutions: x=1.

Graphical form: Equation 3%2Ax-x%2B2=4 was fully solved.

Text form: 3*x-x+2=4 simplifies to 0=0

Cartoon (animation) form: simplify_cartoon%28+3%2Ax-x%2B2=4+%29

For tutors: simplify_cartoon( 3*x-x+2=4 )

If you have a website, here's a link to this solution.

diameter = 10.5in.we are learning something about area of circle.

Answers

Use the formula for the area of a circle:

[tex]A=\pi\cdot r^2[/tex]

First, we need to find the radius r. Since the radius is half the diameter, then:

[tex]\begin{gathered} r=\frac{10.5\text{ in}}{2} \\ \therefore r=5.25in \end{gathered}[/tex]

Substitute the value for r in the formula for the area of the circle:

[tex]\begin{gathered} A=\pi\cdot(5.25in)^2 \\ \approx86.6in^2 \end{gathered}[/tex]

Therefore, the area of a circle of diameter 10.5 in is approximately 86.6 squared inches.

Mike made $120 last week working d days. Express the amount he made each day in terms of d.

Answers

Since he made $120 in d days

To find his earn in eac

I need help with my pre-calculus homework, please show me how to solve them step by step if possible. The image of the problem is attached. The homework was a pdf so the choices can't expand, my teacher told me to just write the transformation of the given function in the format.

Answers

Answer:

• Amplitude: 3

,

• Period: π/2

,

• Phase Shift: 1/8 (to the left)

,

• Vertical Shift: -0.5

Explanation:

Given the trigonometric function:

[tex]y=3\sin (4x+\frac{1}{2})-0.5[/tex]

Comparing with the form below:

[tex]\begin{gathered} y=A\sin (Bx-C)+D\text{ where:} \\ \text{Amplitude}=A \\ Period=\frac{2\pi}{B} \\ Phase\text{ Shift}=\frac{C}{B} \\ \text{Vertical Shift}=D \end{gathered}[/tex]

Thus, we have that:

[tex]\begin{gathered} \text{Amplitude,}A=3 \\ Period,\frac{2\pi}{B}=\frac{2\pi}{4}=\frac{\pi}{2} \\ Phase\text{ Shift,}\frac{C}{B}=-\frac{1}{2}\div4=-\frac{1}{8} \\ \text{Vertical Shift, }D=-0.5 \end{gathered}[/tex]

The phase shift, -1/8 indicates a shift to the left.

For what value of x does 32x93x-4?oo 2o 3o 4

Answers

Solution

[tex]3^{2x}=9^{3x-4}[/tex]

We can do the following:

[tex]3^{2x}=3^{2(3x-4)}[/tex]

And we have this:

[tex]2x=6x-8[/tex][tex]4x=8[/tex][tex]x=\frac{8}{4}=2[/tex]

Solve the following system of equations by graphing. Graph the system below and enter the solution set as an ordered pair in the form (x,y).if there are no solutions, enter none and enter all if there are infinite solutions.X - y = 0X + y = - 4

Answers

EXPLANATION

Since we have the system of equations:

(1) x - y = 0

(2) x + y = -4

Isolating x in (1):

x = y

Plugging in x=y into (2):

y + y = -4

Adding like terms:

2y = -4

Dividing both sides by 2:

y = -4/2

Simplifying:

y = -2

Plugging in y=-2 into (1):

x - (-2) = 0

Removing the parentheses:

x + 2 = 0

Subtracting -2 to both sides:

x = -2

The solution of the system of equations is (-2, -2)

Representing the graph:

I need help with this problem, please help

Answers

Answer:

d.

Step-by-step explanation:

the slope is the factor of x.

a perpendicular slope turns the original slope upside-down and flips the sign.

the original slope is -3/7.

the perpendicular slope is then 7/3.

the only answer option with the correct slope is d.

so, d. must be correct.

let's check that (-2, 2) is on this line :

2 = 7/3 × -2 + 20/3 = -14/3 + 20/3 = 6/3 = 2

2 = 2

correct.

so yes, the point (-2, 2) is on this line, and d. is indeed correct.

Determine if the two triangles shown are similar. If so, write the similarity statement.Question options:A) Impossible to determine.B) ΔBCG ∼ ΔEFGC) ΔGCB ∼ ΔGFED) The triangles are not similar.

Answers

ANSWER

Option D: The triangles are not similar

STEP BY STEP EXPLANATION

Now, two (2) triangles are said to be similar if the three (3) angles of triangle A are congruent or equal to the corresponding three (3) angles of triangle B.

If you take a close look at the two (2) triangles, you will notice that the only angle in ∆BCG that is equal to the corresponding angles in ∆EFG is ∆BGC; the two (2) remaining angles in ∆BCG are not congruent with the two (2) corresponding angles in ∆EFG

Hence, it can be concluded that both triangles are not similar.

I need to make 500$ per week after tax in order to pay all my bills. The income tax is 20% What is the smallest pre-tax weekly salary I can earn and still be able to pay my bills after I pay my income tax?

Answers

I must earn at least $625 (or more) per week before tax to pay my bills.

Given,

To make $500 per week after tax in order to pay all my bills.

and, The income tax is 20%

To find the  smallest pre-tax weekly .

Now, According to the question:

Let x be the amount to earn pre - tax.

The income tax is 20% = 20/100 = 0.2

Set up an inequality:

x - 0.2x > = 500

0.8 > = 500

x >= 500/0.8

x >= 625

Hence, I must earn at least $625 (or more) per week before tax to pay my bills.

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A pottery factory purchases a continuous belt conveyor kiln for $68,000. A 6.3% APR loan with monthly payments is taken out to purchase the kiln. If the monthly payments are $765.22, over what term is this loan being paid?

Answers

Based om the cost of the continuous belt conveyor kiln and the monthly payments, as well as the APR of the loan, the term this loan will be paid is 120 months or 10 years.

How to find the term of the loan?

When given the cost of a loan, the APR, and the monthly payments, you can find out the term of the loan by using the NPER function on a spreadsheet.

The Rate would be:

= 6.3% / 12 months in a year

= 0.525%

The Pmt is the payment of $765.22. This amount should be in negatives.

The Present Value or Pv should be the loan amount of $68,000.

The term on the loan would then be 120 months which is 10 years.

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Fiona was playing a game in which she rolled two number cubes. Cube #1 had the integers 1, 2, 3, 4, 5 and 6 on its faces. Cube # 2 has the integers –1, – 2, – 3, –4, –5 and –6 on its faces. She rolled Cube # 1 and got a 2. After she rolled Cube # 2 the sum of the value on the cubes was 0. What number did she roll on Cube # 2?

Answers

When Fiona rolled Cube #2, she got a number -2 as she got 2 while rolling Cube #1 and the sum of the value on the cubes was 0.

As we know Cube #1 has integers 1, 2, 3, 4, 5, 6 on its faces and Cube #2 has -1, -2, -3, -4, -5, -6 on its faces.

It is also given that Fiona got 2 when she rolled cube #1 and the value of the sum on both the cubes is 0.

So it is clear that on Cube #2, the number must be -2 as in that case only, the sum of the values will be 0.

To prove

2 + (-1) = 1

2 + (-2) = 0

2 + (-3) = -1

Hence, the number she got on Cube #2 is -2.

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The maintenance department at the main campus of a large state university receives daily requests to replace fluorescent lightbulbs. The distribution of the number of daily requests is bell-shaped and has a mean of 42 and a standard deviation of 10. Using the 68-95-99.7 rule, what is the approximate percentage of lightbulb replacement requests numbering between 42 and 62.

Answers

we are given

mean=42

Std=10

if the mean=42 + std =10 42+10=52

if the mean=42 - std=10 42-10=32

Rule -- 68-95-99.7

68% of the measures are within 1 standard deviation of the mean.

42+10=52

95% are within 2.

42+20=62

99.7% are within 3.

42+30=72

The normal distribution is symmetric, which means that 50% of the measures are above the mean and 50% are below.

we are ask for the porcentage of request between 42-62 (between the mean and 2+std)

62 is two standard deviations above the mean.

Of the 50% of the measures below the mean, 95% are between 42 and 62, so

0.95(50)=47.5

The approximate percentage of light bulb replacement requests numbering between 42 and 62 is of 47.5%

Please help me with this problem just wanted to be sure that I am correct in order to help my son to under stand the break down of this problem. I believe that the answer is -3 but I am not sure please help?Solve for x.14x−1/2(4x+6)=3(x−4)−18 Enter your answer in the box.x =

Answers

SOLUTION

We want to solve for x in the equation

[tex]14x-\frac{1}{2}\mleft(4x+6\mright)=3\mleft(x-4\mright)-18[/tex]

First we expand the brackets in both sides of the equation, this becomes

[tex]\begin{gathered} 14x-\frac{1}{2}(4x+6)=3(x-4)-18 \\ 14x-2x-3=3x-12-18 \end{gathered}[/tex]

Note that the minus sign multiplies the items in the brackets too

Now, we collect like terms we have

[tex]\begin{gathered} 14x-2x-3x=-12-18+3 \\ 9x=-27 \\ \text{divide both sides by 9, we have } \\ \frac{9x}{9}=\frac{-27}{9} \\ x=-3 \end{gathered}[/tex]

Hence x = -3

Given the following function, find f(-3), f(0), and f (2) f(x)=5x-2

Answers

The output values of f(-3), f(0) and f(2) of the function f( x ) = 5x - 2 are -17, -2 and 8 respectively.

What are the output values of f(-3), f(0) and f(2) in the given function?

A function is simply a relationship that maps one input to one output.

Given the data in the question;

f( x ) = 5x - 2f( -3 ) = ?f( 0  ) = ?f( 2 ) = ?

For f( - 3 );

To find the output value of f( -3 ), replace all the occurrence of x with -3 in the function and simplify.

f( x ) = 5x - 2

f( -3 ) = 5(-3) - 2

f( -3 ) = -15 - 2

f( -3 ) = -17

For f( 0 );

To find the output value of f( 0 ), replace all the occurrence of x with 0 in the function and simplify.

f( x ) = 5x - 2

f( 0 ) = 5(0) - 2

f( 0 ) = 0 - 2

f( 0 ) = -2

For f( 2 );

To find the output value of f( 2 ), replace all the occurrence of x with 2 in the function and simplify.

f( x ) = 5x - 2

f( 2 ) = 5(2) - 2

f( 2 ) = 10 - 2

f( 2 ) = 8

Therefore, the output value of f( 2 ) is 8, this forms an ordered pair of ( 2, 8 ).

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Hello I'd like some help on my practice question I'd prefer if it's quick because I have other questions I need to solve thank you

Answers

f(x) = -2

the answer is the second option

The horizontal line at y = -2 which is parallel to x-axis

What is the surface area of fish tank in the shape of a cube that has a volume of 90 cubic inches.

Answers

You know that the volume of the fish tank in the shape of a cube:

[tex]V=90in^3[/tex]

By definition, the formula for calculating the volume of a cube is:

[tex]V=a^3[/tex]

Where "a" is the length of each edge of the cube.

If you solve for "a", you get this formula:

[tex]a=\sqrt[3]{V}[/tex]

In this case, knowing the volume of the cube, you can substitute it into the second formula and evaluate, in order to find the length of each edge of the cube:

[tex]\begin{gathered} a=\sqrt[3]{90in^3} \\ \\ a\approx4.48in \end{gathered}[/tex]

The surface area of a cube can be found using this formula:

[tex]SA=6a^2[/tex]

Where "a" is the length of each edge of the cube.

Substituting the value of "a" into the formula and evaluating, you get:

[tex]SA=6(4.48in)^2\approx120in^2[/tex]

Hence, the answer is: Second option.

Put these five fractions in order, left to right, from least to greatest. 1 /3 2 /7 3/10 4/13 5/17

Answers

The five fractions can be arranged in order, from the left to right, from least to greatest as : 5/17 , 3/10 , 4/13 , 1 /3.

How can the fraction can be arranged from the  from least to greatest?

The fraction can be arranged from the  from least to greatest by firstly convert the fraction to the decimal numbers so that one c b able to identify the highest and the lowest values.

The given fractions  1 /3 2 /7 3/10 4/13 5/17 can be converted to decimal numbers as 0.33 , 0.67 , 0.30 , 0.31 , 0.29 respectively and this can be arranged as 5/17 , 3/10 , 4/13 , 1 /3.

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f(x) = x2 + 1 g(x) = 5 – x

(f + g)(x) =

x to the power of 2 – x + 6

then (f – g)(x) =??

Answers

The function operation ( f - g )( x ) in the functions f(x) = x² + 1 and g(x) = 5 - x is x² + x - 4.

What is the function operation ( f - g )( x ) in the given functions?

A function is simply a relationship that maps one input to one output. Each x-value can only have one y-value.

Given the data in the question;

f(x) = x² + 1g(x) = 5 - x( f - g )( x ) = ?

To find ( f - g )( x ), replace the function designators in ( f - g ) with the actual functions.

( f - g )( x ) = f( x ) - g( x )

( f - g )( x ) = ( x² + 1 ) - ( 5 - x )

Remove the parenthesis using distributive property

( f - g )( x ) = ( x² + 1 ) - ( 5 - x )

( f - g )( x ) = x² + 1 - 5 + x

Collect and add like terms

( f - g )( x ) = x² + x + 1 - 5

( f - g )( x ) = x² + x - 4

Therefore, the function operation ( f - g )( x ) is x² + x - 4.

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The required function would be (f – g)(x) = x² + x - 4.

What is the function?

A mathematical expression that defines the connection between two variables is considered a function.

The given functions following as

f(x) = x² + 1 and g(x) = 5 - x

We have to determine the function (f – g)(x).

(f – g)(x)  = f(x) - g(x)

Substitute the values of functions f(x) = x² + 1 and g(x) = 5 - x in the function (f - g).

(f – g)(x) = (x² + 1) - (5 - x)

Open the parenthesis and apply the arithmetic operation,

(f – g)(x)  = x² + 1 - 5 + x

Rearrange the terms likewise and combine them,

(f – g)(x) = x² + x + 1 - 5

Apply the subtraction operation to get

(f – g)(x) = x² + x - 4

Therefore, the required function would be (f – g)(x) = x² + x - 4.

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10 ptQuestion 10A can of soup has a volume of 80 in and mass of 10 ounces. A can of tuna has a volume of 56 in and mass of 8ounces. About how much less is the density of the soup than the tuna (give your answer in ounces/square inch).Round your answer to the nearest 1000th.SOUPSTUNA CHUNKSBrineLENTIL0.0179 ounces per per square inches less0.1429 ounces per per square inches less0.1250 ounces per per square inches less0.0099 ounces per per square inches less

Answers

We have that the general formula for the density given the volume and the mass is:

[tex]d=\frac{m}{v}[/tex]

in this case, the densities for the can of soup and the can of tuna are:

[tex]\begin{gathered} d_{soup}=\frac{10}{80}=\frac{1}{8} \\ d_{tuna}=\frac{8}{56}=\frac{1}{7} \end{gathered}[/tex]

the difference between these two densities is:

[tex]\frac{1}{7}-\frac{1}{8}=\frac{1}{56}=0.0179[/tex]

therefore, there is 0.0179 less density of the soup than the tuna

Other Questions
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