Answer:
The value of the length of the side C is 11.49.
Step-by-step explanation:
Cosine formula is applicable.
c² = a² + b² -2abcos(C)
substitute the values:
c² = (5)² + (12)² -2(5)(12)cos(72)
= 25 + 144 - 2 (60) (0.309)
= 169 - 37.08
c² = 131.92
square root both sides:
c = sqrt(131.92)
C = 11.49
Please Help! Will give Brainlest!
Answer:
amplitude = 2
Step-by-step explanation:
the amplitude is the distance from the x- axis(midline ) to the maximum value , that is
amplitude = 2
[tex]\qquad \qquad \huge \pink {\sf{☁Answer☁}} \\ \\ [/tex]
Option B ( 2 ) ✓
the amount by which the graph of the function travels above and below its midline.OR,
[tex] \sf{amplitude = distance \: from \: undisturbed \: position \div centre \: line \: to \: through \: or \: peak \: }[/tex]
[tex]\purple{\rule{15mm}{2.9pt}} \red{\rule18mm{2.5pt}} \orange{ \rule18mm{2.5pt}}[/tex]
[tex]\sf{\:мѕнαcкεя\: ♪...}[/tex]
There are 49 students had their lunch in the cafeteria. One-
seventh of them brought lunches from home. How many
students brought lunches from home? students
if x=-2 then write the ordered pair that is a solution of 5x-3y=-25
Answer:
(2,11 2/3) or (2,(35/3))
Step-by-step explanation:
5x-3y=-25
For x = 2:
5(2)-3y=-25
10-3y=-25
-3y=-35
y = (35/3) or 11 2/3
(2,11 2/3)
Answer:
X = -2
Y= 5
You use:
5x-3(5)=-25
and
5(-2)-3y=-25
Bruce and his family arrived at the beach at 10:28 a.m. on Saturday morning. They left their house 12 hours and 20 minutes before their arrival at the beach. What time did they leave their house?
Include am or pm in your answer.
help me pls
Answer:
10:48 pm will be your answer
Please help, again. I really need this grade!
Which value is a solution to x <
Answer:
0
Step-by-step explanation:
it less than 4 so u can't pick 4,so it is any number less than 4
Answer:
B) 0
Step-by-step explanation:
The open circle on 4 and the arrow pointing to the left means x < 4
x < 4 means that x is smaller than 4
4 = 4 incorrect as this says 4 is equal to 4
0 < 4 CORRECT as zero is smaller than 4
5 > 4 incorrect as 5 is bigger than 4
4.5 > 4 incorrect as 4.5 is bigger than 4
How do you write a decimal for 30 divided by 8
Answer:
3.75?
Step-by-step explanation:
I dont know if this is what youre looking for but I guess?
Please Help I'm Confused.
Answer:
The last one
Step-by-step explanation:
Look at A and A'
It moved 4 units to the right and 1 unit down
The same with B, B' and C, C'
Unit 10: circles homework 2: central angles & arc measures
The central angle (127 degrees) is the angle at point K
The measures of JL and JML are 127 and 233 degrees, respectively
How to determine the measures of angles JL and JML?From the complete question, we have:
JL = 127 degrees.
The sum of angles at a point is 360 degrees
So, we have:
JML + 127 = 360
Subtract 127 from both sides
JML = 233
Hence, the measures of JL and JML are 127 and 233 degrees, respectively
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Fill in the table using this function rule
y=2x+2
Photo ⬇️
Answer:
Step-by-step explanation:
Put the values of x to the equation y = 2x + 2 and calculate the value of y:
x = 2
y = 2 · 2 + 2 = 4 + 2 = 6
x = 5
y = 2 · 5 + 2 = 10 + 2 = 12
x = 6
y = 2 · 6 + 2 = 12 + 2 = 14
x = 8
y = 2 · 8 + 2 = 16 + 2 = 18
Helpppppp!!!
(Show work)
Answer:
( - y - 3 , - x - 1 )
Step-by-step explanation:
( x , y ) ----> ( - y , x ) ----> ( - y - 3 , x + 1 ) ----> ( - y - 3 , - x - 1 )
At which point would the graphs of the equations below intersect?
{
3
x
−
4
y
=
−
2
−
6
x
+
5
y
=
7
3x-4y = -2 -6x+5y = 7
A.
(
−
2
,
−
1
)
(
-
2
,
-
1
)
B.
(
2
,
−
1
)
(
2
,
-
1
)
C.
(
−
1
,
2
)
(
-
1
,
2
)
D.
(
−
1
,
−
2
)
Answer:
can't explain without you arranging your mathematical expression
Use the linear inequality + 8y 24 for Part A, Part B, and Part C. Part A: Determine the boundary line, and state whether the line will be dashed or solid. Part B: Which half-plane should be shaded? Describe where you should shade using the language "above" or "below" the line. Part C: Show your work for Part B to show how you determined which half-plane to shade.
Answer:
Given inequality: [tex]x+8y\leq 24[/tex]
Part A
Solid line: ≤ or ≥
Dashed line: < or >
Therefore, the line will be solid.
Part B
Shading above the line: y > or y ≥
Shading below the line: y < or y ≤
Therefore, shade below the line.
Part C
Make y the subject to determine where to shade.
Given inequality:
[tex]x+8y\leq 24[/tex]
Subtract x from both sides:
[tex]8y\leq 24-x[/tex]
Divide both sides by 8:
[tex]y\leq 3-\dfrac18x[/tex]
[tex]\\ \rm\Rrightarrow x+8y\leqslant 24[/tex]
#Part A
as ≤ is present line will be dashed#Part B
Put (0,0)
0+8(0)≤240≤24Satisfied
Shading below the line and towards origin
#Part C
turn into y=mx+b form
8y≤-x+24y≤-1/8x+3help me please!! will choose brainlyest if you get it right
PLEASE HELP WILL GIVE BRAINLIEST
Answer:
(2, -1)
Step-by-step explanation:
x = 2, y = −1
4.5
3
5
х
Find the length of x
Please help, I'm stuck
Suppose ten distinct, positive integers have a median of $10$. ("Distinct integers" means that no two integers are the same.)
What is the smallest the average of those ten integers could be?
Explain your answer in complete sentences.
Answer:
8 (or 8.4)
Step-by-step explanation:
First, the problem states the words: Distinct and positive.
That means that the smallest number we can use is 0.
We can make 10 blanks for 10 numbers for us to fill in.
_ _ _ _ _ _ _ _ _ _
Since 10 is an even number, and the median is not one single number, it will be the middle of the two numbers.
In this case, our two numbers are the 5th and 6th blank.
Any two numbers can be used, as long as they are the same actual value from 10.
Let us first put in the numbers we can, which are the numbers before the two middle blanks.
0,1,2,3, _ _ _ _ _ _
To find the median between two numbers, we can do:
(a+b) divided by 2 = median
We can use the smallest following number, 4. Then the 6th number will have to be 16 for 10 to be in the middle.
Also try the largest possible number for the 5th blank, 9. Then the 6th number will be 11.
4+16 and 9+11 both equal 20, and 20 divided by 2 is 10. So both of these work.
Now let's place the other numbers in for these two equations.
0,1,2,3,4,16,17,18,19,20
0,1,2,3,9,11,12,13,14,15
If we add the numbers of each together, we get:
0,1,2,3,4,16,17,18,19,20=100
0,1,2,3,9,11,12,13,14,15= 80
If we now divide each sum by 10 (to find the average) we get:
10
8
Since both of these were the most we could go, one with the 5th number as small as possible and one with the 5th number as large as possible.
Since the smaller answer we got was 8, the answer must be 8.
(I believe 0 is a positive integer because it doesn't carry a negative sign. If 0 is not a positive integer, the answer is 8.4. Use the same process
The length of one leg of an isosceles right triangle is 3 ft. What is the perimeter of the triangle? 3 3 StartRoot 2 EndRoot ft 3 3 StartRoot 3 EndRoot ft 6 3 StartRoot 2 EndRoot ft 6 3 StartRoot 3 EndRoot ft.
The perimeter of the isosceles right triangle comes to be 6+3√2.
Given that the length of one leg of an isosceles right triangle = 3 ft
What is an isosceles right triangle?A right-angle triangle having sides other than hypotenuse equal to each other is called an isosceles right triangle.
So, The length of the other leg of an isosceles right triangle = 3 ft
From Pythagoras theorem
Hypotenuse²=Perpendicular²+Base²
So, in the given isosceles right triangle
Hypotenuse²=Leg 1²+Leg2²
Leg 1=Leg2 = 3 feet
Hypotenuse² = 3²+3²
Hypotenuse = 3√2 ft.
So, the perimeter of the triangle = 3+3+ 3√2
The perimeter of the triangle =6+3√2
Therefore, The perimeter of the isosceles right triangle comes to be 6+3√2.
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Answer:
6 + 3 StartRoot 2 EndRoot ft
Step-by-step explanation:
Edge2022
Sketch the graph of y = 5 sin 2x° + 12
Function: y = 5 sin (2(x))+ 12
Find y-intercept:
y = 5 sin 2(0)+ 12
y = 12
[tex]\sf Y\:Intercepts}:\:\left(0,\:12\right)[/tex]
→ Formula for maximum: M = A + |B|
Maximum:
12 + |5|
17
When y = 17
[tex]\rightarrow \sf 17 = 5 sin (2(x))+ 12[/tex]
[tex]\rightarrow \sf \sf 5 sin (2(x)) = 5[/tex]
[tex]\rightarrow \sf sin (2(x)) = 1[/tex]
[tex]\rightarrow \sf 2x = sin^{-1}(1)[/tex]
[tex]\rightarrow \sf 2x = 90^{\circ \:}, \ \ 450^{\circ \:}[/tex]
[tex]\rightarrow \sf x = 45^{\circ \:}, \ \ 225^{\circ \:}[/tex]
maximum: ( 45° , 17 ), (225° , 17), .....
==========================================================
→ Formula for minimum: m = A ‐ |B|
Minimum:
12 - |5|
7
When y = 7
[tex]\rightarrow \sf 7 = 5 sin (2(x))+ 12[/tex]
[tex]\rightarrow \sf 5 sin (2(x)) = -5[/tex]
[tex]\rightarrow \sf 2(x) = sin^{-1}(-1)[/tex]
[tex]\rightarrow \sf x = -45^{\circ \:} , \ \ 135^{\circ \:}[/tex]
minimum: ( -45°,7), (135°, 7), .....
Repeat the same process for finding more values on the x-axis, or just follow the trend of the curve from the points found and sketch the graph easily.
[tex]\sf Domain\:\left(-\infty \: < x < \infty )[/tex]
[tex]\sf Range : 7\le \:f\left(x\right)\le \:17[/tex]
Sketched below:
You can buy jars of the same jam in two sizes.
Step-by-step explanation:
Large Jar 540g for 2.16
540/2.16 = 250
(Always divide by the smallest ratio)
= 250g per 1£
Small Jar 360g for 1.37
360/1.37=262.77g
= 262.77g per 1£
Small Jar is the best value for money, more grams, same price.
What are the zeros of this function?
A. x=0 and x=6
B. x=0 and x= -9
C. x=0 and x= -6
D. x=3 and x= -9
Answer:
A
Step-by-step explanation:
The zeros are the roots or x-intercepts
They are located at coordinate points (0, 0) and (6, 0)
This means the answer is A
Hope it makes sense!
Answer:
A. x = 0 and x = 6
Step-by-step explanation:
So, the zeroes of a quadratic are the parts of it that touch the x-axis. When you find those parts, take their x value and you will get the zero.
So, in this parabola, it touches the x-axis at (0, 0) and (6, 0).
The x-values of these are 0 and 6, respectively.
For the following geometric sequence find the recursive formula: {-1, 3, -9, ...}.
an = (-3) n - 1
an = -3 · an - 1 where a1 = -1
an = -3 · an - 1 where a1 = 1
an = -1 · (-3) n - 1
Answer:
an = -3 · an - 1 where a1 = -1.
Step-by-step explanation:
The first term a1 = -1 and the common ratio is -3 so ecah term is formed form the previous one by multiplying by -3.
Solve the equation . 5x+17=42
Answer:
x = 5
Step-by-step explanation:
5x+17=42
5x + 17 - 17 = 42 - 17
the diameter of a circle is 13.8cm. Find the length of its radius
Hello!
R = D/2
R= 13,8/2 => 6,9cm
The length of the circle's radius is 6.9 cm.
The diameter of a circle is twice the length of its radius. So, to find the length of its radius (r), you can divide the diameter (d) by 2.
Given: Diameter (d) = 13.8 cm
Length of radius (r) = d / 2
r = 13.8 cm / 2
r = 6.9 cm
The length of the circle's radius is 6.9 cm.
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6,402.66 divided by 459438.26
Answer: 0.0139358
Step-by-step explanation: 999,999,999,999,999,999,999,999,999,999,999% sure!
Lines j and k are intersected by line m. At the intersection of lines j and m, the uppercase left angle is 93 degrees. At the intersection of lines k and m, the bottom right angle is 93 degrees.
Given the information in the diagram, which theorem best justifies why lines j and k must be parallel?
alternate interior angles theorem
alternate exterior angles theorem
converse alternate interior angles theorem
converse alternate exterior angles theorem
Answer: converse alternate exterior angles theorem
Step-by-step explanation:
The angles are alternate exterior angles.
The area of a 2/3 cube
Answer:
2 that's what soup calculated says
What are quadratic equations? What are some examples?
Answer:Examples of quadratic equations are: 6x² + 11x – 35 = 0, 2x² – 4x – 2 = 0, 2x² – 64 = 0, x² – 16 = 0, x² – 7x = 0, 2x² + 8x = 0 etc. From these examples, you can note that, some quadratic equations lack the term “c” and “bx.”
Step-by-step explanation:
A quadratic equation in the variable x is an equation of the form ax^2 + b x + c = 0, where a, b, c are real numbers, a ≠ 0.
What are quadratic equations?Quadratics can be defined as a polynomial equation of a second degree, which implies that it comprises a minimum of one term that is squared. It is also called quadratic equations.
The standard form of a quadratic equation is;
Quadratic equations are the polynomial equations of degree 2 in one variable of type f(x) = ax^2 + bx + c where a, b, c, ∈ R and a ≠ 0.
These are the following examples of the quadratic equation;
x^2-2x
x^2+5x+6
x^2-5x
Any equation of the form p (x) = 0, where p (x) is a polynomial of degree 2, is a quadratic equation.
If we write the terms of p (x) in decreasing order of their degrees, then we get the standard form of the equation.
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Can someone please answer & show work? Thanks.
Find the smallest number by which 350
must be multiplied to give a perfect square.
Answer:
the smallest number by which 350 by answer is 15