Which equation is true when the value of x is - 12 ?F: 1/2x+ 22 = 20G: 15 - 1/2x = 21H: 11 - 2x = 17 J: 3x - 19 = -17

Answers

Answer 1

Substitute x = - 12 in each of the given equation, if the equation satisfy then tha x = -1 2

F) 1/2x + 22 = 20

1/2 ( -12) + 22 = 20

(-6) + 22 = 20

16 is not equal to 22

G) 15 -1/2x = 21

Substitute x = -12 in the expression :

15 - 1/2( -12) = 21

15 + 1/2(12) =21

15 + ( 6) = 21

21 = 21

Thus, The equation 15 - 1/2x = 21 is true for x = -12

H) 11 - 2x = 17

Susbstitute x = ( -12) in the equation :

11 - 2x = 17

11 - 2( -12) = 17

11 + 24 = 17

35 = 17

Since, 35 is not equal to 17

D) 3x - 19 = -17

SUsbtitute x = ( -12)

3( -12) - 19 = -17

-36 - 19 = -17

-36 = -17 + 19

-36 = 2

Since - 36 is not equal 2

Answer : G) 15 - 1/2x = 21


Related Questions

A. The measure of the angle can not be determined B. 70 degreesC. 110 degreesD. 180 degrees

Answers

Okay, here we have this:

Considering the provided graph, we are going to find the measure of the angle "3", so we obtain the following:

Since angle 3 and 4 form a straight angle, that is to say that these two angles are supplementary, then we have:

[tex]\begin{gathered} m\angle3+m\angle4=180 \\ m\angle3+70=180 \\ m\angle3=180-70 \\ m\angle3=110\text{ degre}es \end{gathered}[/tex]

Finally we obtain that the correct answer is the option C.

A line passes through the point (-2,-7) and has a slope of 4

Answers

Answer:

y= 4x +1

Step-by-step explanation:

The equation of a line, in slope-intercept form, is given by y= mx +c, where m is the slope and c is the y-intercept.

Given that the slope is 4, m= 4.

Substitute m= 4 into y= mx +c:

y= 4x +c

To find the value of c, substitute a pair of coordinates the line passes through.

When x= -2, y= -7,

-7= 4(-2) +c

-7= -8 +c

c= -7 +8

c= 1

Substitute the value of c into the equation:

Thus, the equation of the line is y= 4x +1.

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Hi dear how do I get to know you and

Answers

Given the picture, we have:

Enclosed area: A = x*y

Fence Length: F= 2x+y

Josephine bought a bag of garri for
N320.00 and sold it for N400.00.
What was her percentage profit

Answers

The most appropriate choice for profit will be given by-

Profit percent after selling a bag of garri is 25%

What is profit?

If the selling price of an article is more than the cost price of the article, then the difference between selling price and the cost price of the article gives the profit

Profit = SP - CP

Here,

Cost price of a bag of Garri = N320

Selling price of a bag of Garri = N400

Profit = N(400 - 320)

         = N80

Profit Percent = [tex]\frac{80}{320} \times 100[/tex]

                       = 25%

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What is the solution to the following equation?x^2+3x−7=0

Answers

Answer:

Explanation:

Given the equation:

[tex]x^2+3x-7=0[/tex]

On observation, the equation cannot be factorized, so we make use of the quadratic formula.

[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

Comparing with the form ax²+bx+c=0: a=1, b=3, c=-7

Substitute these values into the formula.

[tex]x=\dfrac{-3\pm\sqrt[]{3^2-4(1)(-7)}}{2\times1}[/tex]

We then simplify and solve for x.

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(9 •10^9)•(2•10)^-3)

Answers

First, let's distribute the exponent -3 for 2 and ten, like this:

[tex]\begin{gathered} 9\times10^9\times(2\times10)^{-3}^{} \\ 9\times10^9\times2^{-3}\times10^{-3} \end{gathered}[/tex]

Now, we can apply the next property when we have a number raised to a negative power:

[tex]a^{-b}=\frac{1}{a^b}[/tex]

Then:

[tex]\begin{gathered} 9\times10^9\times2^{-3}\times\frac{1}{10^3} \\ 9\times2^{-3}\times\frac{10^9}{10^3} \end{gathered}[/tex]

And when we have a division of the same number raised to different powers we can apply:

[tex]\frac{a^b}{a^c}=a^{b-c}[/tex]

then:

[tex]\begin{gathered} 9\times2^{-3}\times\frac{10^9}{10^3} \\ 9\times2^{-3}\times10^{9-3} \\ 9\times2^{-3}\times10^6 \\ 9\times\frac{1}{2^3}^{}\times10^6 \end{gathered}[/tex]

Now, as we know, having 10 raised to 6 means that we are multiplying ten by ten 6 times, when we do this we get:

[tex]10\times10\times10\times10\times10\times10=1000000[/tex]

And with 2 raised to three we get:

[tex]2\times2\times2=8[/tex]

Then we have:

[tex]\begin{gathered} 9\times\frac{1}{8^{}}^{}\times1000000 \\ \frac{9\times1000000}{8^{}}^{} \\ \frac{9000000}{8^{}}^{} \\ \frac{4500000}{4}^{}=11250000 \end{gathered}[/tex]

Use your knowledge of area and perimeter to complete the following problems. Use 3.14 for  and round to the nearest hundredths place, whenever necessary. Show all work.Part 1:A farmer bought 30 feet of fencing to build a circular pen for his pigs. What is the diameter of the pen he can build with 30 feet of fencing?The farmer also needs to buy a certain type of seed for the grass in the pen. Each bag of seed can cover 50 square feet of land. How many bags of seed will the farmer need to buy?

Answers

[tex]\begin{gathered} \text{Circumfrence of the pen is,} \\ C=2\pi r \\ 30=2\pi\times r \\ r=\frac{30}{2\pi}=4.77\text{ ft} \\ \text{The diameter is}\Rightarrow d=2r \\ d=2\times4.77=9.55\text{ ft} \\ \text{Now, second problem} \\ \end{gathered}[/tex]

Find the distance between the parallel lines. If necessary, round your answer to the nearest tenths.

Answers

The distance between the parallel lines is [tex]\frac{3}{5}}[/tex].

The given parallel lines are

[tex]y= $-$3x+4\\y= $-$3x+1[/tex]

We have to find the distance between the given parallel lines.

The formula is used to solve the distance between two parallel lines [tex]ax+by+c_{1}=0[/tex] and [tex]ax+by+c_{2}=0[/tex] is

[tex]d=|c_{2} $-$c_{1}|\frac{1}{\sqrt{a^{2}+b^{2}}}[/tex]

The first given line is [tex]y= $-$3x+4[/tex]

We can write that line as [tex]3x$-$y $-$4=0[/tex]

The second given line is [tex]y= $-$3x+1[/tex]

We can write that line as [tex]3x$-$y $-$1=0[/tex]

Comparing the both given parallel lines with the standard equation of line.

After comparing we get

[tex]a=3, b= $-$1, c_{1}= $-$4, c_{2}= $-$1[/tex]

Putting the value in the formula

[tex]d=|(-1) -(-4)|\frac{1}{\sqrt{(3)^{2}+(-4)^{2}}}\\d=|-1+4|\frac{1}{\sqrt{9+16}}\\d=|3|\frac{1}{\sqrt{25}}\\d=\frac{3}{5}}[/tex]

Hence, the distance between the parallel lines is [tex]\frac{3}{5}}[/tex].

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A) 14x + 7y > 21 B) 14x + 7y < 21 C) 14x + 7y 5 21 D) 14x + 7y 221match with graph

Answers

As all the options are the same equation

so, we need to know the type of the sign of the inequality

As shown in the graph

The line is shaded so, the sign is < or >

The shaded area which is the solution of the inequaity is below the line

So, the sign is <

So, the answer is option B) 14x + 7y < 21

The sum of 19 and twice a number

Answers

Answer:

2x+19

Step-by-step explanation:

Let x be the number

2x+19

4 Use the sequence below to complete each task. -6, 1, 8, 15, ... a. Identify the common difference (a). b. Write an equation to represent the sequence. C. Find the 12th term (a) our Wilson (All Things Algebral. 2011 Enter your answer(s) here

Answers

we have

-6, 1, 8, 15, ...

so

a1=-6

a2=1

a3=8

a4=15

a2-a1=1-(-6)=7

a3-a2=8-1=7

a4-a3=15-8=7

so

the common difference is

d=7

Part 2

write an equation

we have that

The equation of a general aritmetic sequence is equal to

an=a1+(n-1)d

we have

d=7

a1=-6

substitute

an=-6+(n-1)7

an=-6+7n-7

an=7n-13

Part 3

Find 12th term

we have

n=12

a12=-7(12)-13

a12=71

Please answer last oneTo graph F using a graphing utility…Either A,B,C, or DLet me know which option

Answers

We have to graph the function F(x) defined as:

[tex]F(x)=\frac{x^2-11x-12}{x+6}[/tex]

We can graph it as:

To see the complete graph we have to show the horizontal axis from x = -30 to x = 30 and the vertical axis from y = -80 to y = 80.

Answer: Option B

Write an equation of variation to represent the situation and solve for the missing information The time needed to travel a certain distance varies inversely with the rate of speed. If ittakes 8 hours to travel a certain distance at 36 miles per hour, how long will it take to travelthe same distance at 60 miles per hour?

Answers

The time needed to travel a certain distance varies inversely with the rate of speed, so:

[tex]\begin{gathered} let\colon \\ t=\text{time} \\ v=\text{rate of speed} \\ t\propto\frac{1}{v} \end{gathered}[/tex]

8hours----------------------------->36mi/h

xhours----------------------------->60mi/h

[tex]\begin{gathered} \frac{8}{x}=\frac{36}{60} \\ \text{ Since the it varies inversely:} \\ \frac{8}{x}=(\frac{36}{60})^{-1} \\ \frac{8}{x}=\frac{5}{3} \\ \text{solve for x:} \\ x=\frac{3\cdot8}{5} \\ x=4.8h \end{gathered}[/tex]

4.8 hours or 4 hours and 48 minutes

17. 19yd. 28in.- 16yd. 31in.18. 61wk. 4da.- 18wk. 6da.21. 8tbsp. 2tsp. * 15

Answers

We need to solve the next expressions:

17. 19yd. 28in.- 16yd. 31in

We need to solve subtract each expression.

Then:

19yd. 28in.- 16yd. 31in =

19yd - 16yd and 28in-31in

3yd -3in

Then, we have the next equivalent.

1 yard = 36 in

So:

36 in - 3 in = 33 in

Therefore

19yd. 28in.- 16yd. 31in = 2 yard 33

18 61wk. 4da.- 18wk. 6da.

We need to subtract both expression:

Then

61wk - 18wk = 43kw

4da-6da = -2da

Where 1 week = 7 days

Then

7 da - 2da = 5 da

Hence, 43kw -1 wk = 42 wk.

The result is:

42 wk 5 da

21. 8tbsp. 2tsp. * 15

We need to convert 2ts into tbsp and then multiply the result by 15.

If

1 tsp ------- 0.333tbsp

Then

2tp ------ 2(0.333tbsp)= 0.66666 tbsp

Now

(8tbsp + 0.6666 ) * 15 = 130 tbsp

Point P is in the interior of

Answers

[tex]\because m\angle OZQ=125[/tex]

∵ m< OZQ = m[tex]\because m\angle OZP=62[/tex]Substitute the measures of the given angles in the equation above

[tex]\therefore125=62+m\angle PZQ[/tex]

Subtract 62 from both sides

[tex]\begin{gathered} \therefore125-62=62-62+m\angle PZQ \\ \therefore63=m\angle PZQ \end{gathered}[/tex]

The measure of angle PZQ is 63 degrees

Suppose that the edge lengths x, y, z of a closed rectangular box are changing at the following rates: dx/dt= 1m/s, dy/dt= -2 m/s, and dz/dt= 0.5 m/s.

At the instant x= 2m, y= 3m, z= 5m, find the rates of change:

a) volume of the box
b) surface area of the box
c) diagonal of the box

Answers

a) The rate of change of the volume of the box is 8m³/s.

b) The rate of change of the surface area of the box is -19m²/s.

c) The rate of change of the diagonal of the box is 1m/s.

Let the rate of change of  the edge length x, y, and z of a closed rectangular box are:

dx/dt= 1m/s

dy/dt= -2 m/s

dz/dt= 0.5 m/s

a) The volume of the box

From the formula of the volume,

V=xyz

Then,

differentiate w.r.t t

[tex]\frac{dV}{dt} = xy\frac{dz}{dt} + yz\frac{dx}{dt} +xz\frac{dy}{dt}[/tex]

[tex]\frac{dV}{dt} = xy(0.5)+ yz(1)+xz(-2)[/tex]

put the value of x, y, z , then we get

[tex]\frac{dV}{dt} = 2.3.(0.5)+ 3.5.(1)+2.5.(-2)[/tex]

[tex]\frac{dV}{dt} = 3+ 15 - 10[/tex]

[tex]\frac{dV}{dt} = 8m^3/s[/tex]

The rate of change of the volume of the box is 8m³/s.

b) surface area of the box

surface area of the rectangular box is

s = 2xy + 2yz + 2zx

differentiate w.r.t t

[tex]\frac{ds}{dt} = 2(y + z)\frac{dx}{dt} + 2(z + x)\frac{dy}{dt} +2(x + y)\frac{dz}{dt}[/tex]

[tex]\frac{ds}{dt} = 2(y + z)(1) + 2(z + x)(-2)+2(x + y)(0.5)[/tex]

[tex]\frac{ds}{dt} = 2(3 + 5)(1) + 2(5 + 2)(-2)+2(2 + 3)(0.5)[/tex]

[tex]\frac{ds}{dt} = 16 -40 + 5[/tex]

[tex]\frac{ds}{dt} = -19m^2/s[/tex]

The rate of change of the surface area of the box is -19m²/s.

c) diagonal of the box

lengths of  the boxes for the diagonal is

s = 2x² + y² + z²

differentiate equation w.r.t t

[tex]\frac{ds}{dt} = 4x\frac{dx}{dt} + 2y\frac{dy}{dt} +2z\frac{dz}{dt}[/tex]

[tex]\frac{ds}{dt} = 4.2.1+ 2.3.(-2) +2.5.(0.5)[/tex]

[tex]\frac{ds}{dt} = 8 -12 + 5[/tex]

[tex]\frac{ds}{dt} =1m/s[/tex]

The rate of change of the diagonal of the box is 1m/s.

a) The rate of change of the volume of the box is 8m³/s.

b) The rate of change of the surface area of the box is -19m²/s.

c) The rate of change of the diagonal of the box is 1m/s.

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A store had 896 swimsuits that were marked to sale at $44.95/swimsuit. Each suit was marked down $16.90. Find the reduced price using the formula M = S - N, where M is the markdown, S is the original selling price, and N is the reduced price. The reduced price is ?

Answers

Given:

The original selling price of 1 swimsuit = $44.95

The selling price of 1 marked down swimsuit = $16.90

Using the provided formula:

[tex]M\text{ = S - N}[/tex]

Where,

M is the markdown

S is the original selling price

N is the reduced price

Substituting we have:

[tex]16.90\text{ = 44.95 - N }[/tex]

Solving for N:

[tex]\begin{gathered} \text{Collect like terms} \\ -N\text{ = 16.90 - 44.95} \\ -N\text{ = -28.05} \\ \text{Divide both sides by -1} \\ \frac{-N}{-1}=\text{ }\frac{-28.05}{-1} \\ N\text{ = 28.05} \end{gathered}[/tex]

Hence, the reduced price is $28.05

Answer:

$28.05

The half-life of radium is 1690 years. If 70 grams are present now, how much will be present in 570 years?

Answers

Solution

Given that

Half life is 1690 years.

Let A(t) = amount remaining in t years

[tex]\begin{gathered} A(t)=A_0e^{kt} \\ \\ \text{ where }A_{0\text{ }}\text{ is the initial amount} \\ \\ k\text{ is a constant to be determined.} \\ \end{gathered}[/tex]

SInce A(1690) = (1/2)A0 and A0 = 70

[tex]\begin{gathered} \Rightarrow35=70e^{1690k} \\ \\ \Rightarrow\frac{1}{2}=e^{1690k} \\ \\ \Rightarrow\ln(\frac{1}{2})=1690k \\ \\ \Rightarrow k=\frac{\ln(\frac{1}{2})}{1690} \\ \\ \Rightarrow k=-0.0004 \end{gathered}[/tex]

So,

[tex]A(t)=70e^{-0.0004t}[/tex][tex]\Rightarrow A(570)=70e^{-0.0004(570)}\approx55.407\text{ g}[/tex]

Therefore, the answer is 55.407 g

Consider the following statement:
If Paul is older than Bill and Fred is younger than Bill, then Bill's age is between Paul's and Fred's.
Write the Given statement

Answers

Paul is the oldest and Fred is the youngest of the three.

What is mean by younger?

Younger is a comparative adjective that generally indicates more youthful.

Similar to old, elder simply indicates older in age. It is a comparative version of old.

Given that x is a natural number, let Bill's age equal x years.

Paul's age is thus calculated as (x + a) Years, where an is any positive integer.

Fred is also younger than Bill.

So, Fred's age is equal to x - k, where k is any positive integer.

As a result, if we arranged Fred, Bill, and Paul's ages, they would be

Bill, Fred, and Paul

x-k < x < x+a

As a result, we can conclude that Paul is the oldest and Fred is the youngest of the three.

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An equation is incorrectly solved below.Equation: 2x+3=-4step 1: 2x+3-3=-4-3step 2: 2x=-1step 3: 2x/2=-1/2step 4: x=-1/2What is the first step that shows an error in the solution of the Equation? A. Step 1B. Step 2C. Step 3D. Step 4

Answers

To find the step where the error was made, we are going to correctly solve the equation:

[tex]2x+3=-4[/tex]

We need to solve for x, first we subtract 3 from each side:

[tex]\begin{gathered} 2x+3-3=-4-3 \\ 2x=-7 \end{gathered}[/tex]

We divide by 2 each side:

[tex]\begin{gathered} \frac{2x}{2}=\frac{-7}{2} \\ x=-\frac{7}{2} \end{gathered}[/tex]

The first step that shows an error in the solution of the equation is the Step 2, because when we have two negative numbers, we add them, we do not subtract them.

Answer: B. Step 2

solve for x. then find the missing piece(s) of the parallelogram for #7

Answers

[tex]\begin{gathered} 2x+30+2x-10=180 \\ 2x+2x+30-10=180 \\ 4x+20=180 \\ 4x=160 \\ x=\frac{160}{4} \\ x=40^0 \end{gathered}[/tex]

Let us find the angles of the parallelogram below

[tex]\begin{gathered} 2x+30 \\ x=40 \\ 2(40)+30 \\ 80+30 \\ 110^0 \end{gathered}[/tex][tex]\begin{gathered} 2x-10 \\ 2(40)-10 \\ 80-10 \\ 70^0 \end{gathered}[/tex]

Theorem+: opposite angles of a parallelogram are the same

Hence the angles of the parallelogram are 110, 70, 110, and 70

Jan is looking at a mapof Roaring River. The map wascreated using the scale 1 inch :25 miles. If the river is 5.5inches long on the map, then itis actuallymiles long.

Answers

The map of Roaring River shows1 inch to be an equivalent of 25 miles. If therefore, the river is shown as 5.5 inches long on the map;

[tex]\begin{gathered} \text{Scale; 1 inch=25 miles} \\ 5.5\text{ inches=25 x 5.5 miles} \\ 5.5\text{ inches=137.5miles} \end{gathered}[/tex]

The river is "actually" 137.5 miles long

Which equation is equivalent to - 2x + 5 - 3x = 5x + 25?A. -5 = -30B. -6x + 5 = 5x + 25C. - 10x = 20D. 20x - 5 = 25

Answers

In order to determine which is the equivalent equation, simplify the given expression:

-2x + 5 - 3x = 5x + 25 simplify like terms left side

-2x - 3x + 5 = 5x + 25

-5x + 5 = 5x + 25 subtract 5x both sides and subtract 5 both sides

-5x - 5x = 25 - 5 simplify both sides

-10x = 20

Hence,the equivalent expression is -10x = 20

1. describe the end behavior. 2. determine whether it represents an odd degree or an even degree function.3. state the number of real zeroes

Answers

1. Quadratic curve

2. Odd degree function

3. TWO REAL ZEROS

What is the length of the dotted line in the diagram below? Round to the
nearest tenth.

Answers

Answer:

12.1 units

Step-by-step explanation:

Drag the curve to the correct location on the graph. A small museum opened in 2004 with 80 pieces of art in its collection. In 2005, the number of pieces of art in the collection was 1.2 times the initial number of pieces of art. Then, in 2006, the number of pieces of art in the collection was 1.2 times the size of the previous year's collection. The directors of the museum plan to continue acquiring pieces of art at the same rate. Complete the graph of this relationship. 1207 ces of Art f(x) 3001 240 180 120​

Answers

The most appropriate choice for geometric series will be given by

The equation is [tex]y = 80 (1.2)^x[/tex] and it is a geometric function.

What is geometric series ?

The series in which the ratio between consecutive terms of the series are same is called geometric series

For example, 2, 4, 8, 16, ... is a geometric series in which ratio between two consecutive terms is 2.

Number of pieces of art in 2004 = 80

Number of pieces of art  in 2005 = [tex]80 \times 1.2[/tex]

Number of pieces of art in 2006 =  [tex]80\times (1.2)^2[/tex]

Number of pieces of art after x years from 2004 = [tex]80 \times (1.2)^x[/tex]

The equation is [tex]y = 80 (1.2)^x[/tex]

This is a geometric function

The graph has been attached here.

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I need help with this practice I am new to this subject of mathematics (algebra) Can you show me how to solve this STEP-BY-STEP?

Answers

Given:

[tex]4+x+8=24[/tex]

Required:

To find the correct one.

Explanation:

The given quation is:

4 + x +8 =24

Subtract 8 on both sides

4 + x +8 - 8 = 24 -8

4 + x = 16

Final Answer:

Thus the first option is the correct answer.

a group orders three large veggie pizzas each slice represents eighth of an entire Pizza the group eats 3/4 of a piece of how many slices of pizza are left

Answers

1 pizza contain 8 slices, so we can state a rule of three as:

[tex]\begin{gathered} 1\text{ Pizza ------ 8 slices} \\ \frac{3}{4}\text{ pizza ------ x} \end{gathered}[/tex]

then, x is given by

[tex]x=\frac{(\frac{3}{4})(8)}{1}\text{ slices}[/tex]

which gives

[tex]\begin{gathered} x=\frac{3}{4}\times8 \\ x=\frac{3\times8}{4} \\ x=3\times2 \\ x=6\text{ slices} \end{gathered}[/tex]

that is, 3/4 of pizza is equivalent to 6 slices. So, there are 8 - 6 = 2 slices left of one pizza.

However, they bought 3 large pizzas and ate almost one of them. So, there are 2x8 = 16slices plus 2 slices, that is, 18 slices are left.


Find the domain of the function f(x)=√100x²

Answers

The domain of the function √(100x²) will be (-∞,∞) as the definition of domain states that the set of inputs that a function will accept is known as the domain of the function in mathematics

What is domain?

The range of values that we are permitted to enter into our function is known as the domain of a function. The x values for a function like f make up this set (x). A function's range is the set of values it can take as input.

What is function?

A function in mathematics from a set X to a set Y assigns exactly one element of Y to each element of X. The sets X and Y are collectively referred to as the function's domain and codomain, respectively.

Here,

The function is √(100x²).

The domain would be (-∞,∞).

The set of inputs that a function will accept is known as the domain of the function in mathematics, and the domain of the function √(100x²) will be (-∞,∞), according to the definition of domain.

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Find the length of the third side. If necessary, write in simplest radical form. 9 5 Submit Answer Answer:

Answers

The Pythagorean theorem states:

[tex]c^2=a^2+b^2[/tex]

where a and b are the legs and c is the hypotenuse of a right triangle.

Substituting with c = 9 and a = 5, we get:

[tex]\begin{gathered} 9^2=5^2+b^2 \\ 81=25+b^2 \\ 81-25=b^2 \\ 56=b^2 \\ \sqrt[]{56}=b \\ \sqrt[]{4\cdot14}=b \\ \sqrt[]{4}\cdot\sqrt[]{14}=b \\ 2\sqrt[]{14}=b \end{gathered}[/tex]

Other Questions
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