Which is NOT part of the male reproduction system of a flower? stamen pollen anther pistil​

Answer:

Chlorine gas is produced

Explanation:

One of the methods of laboratory preparation of chlorine gas is to heat manganese dioxide with concentrated hydrochloric acid. The acid is oxidized by the manganese dioxide to liberate chlorine gas as follows;

MnO2(s) + 4HCl(aq) -------> MnCl2(aq) + 2H2O(l) + Cl2(g)

Hence, When manganese dioxide is heated with concentrated hydrochloric

acid, chlorine gas is liberated.

Answer:

Iron is limiting reactant

Explanation:

Based on the reaction:

Fe + S → FeS

1 mole of iron reacts per mole of Sulfur

To solve this question we must convert the mass of each reactant to moles using molar masses of each reactant. As the reaction is 1:1, the reactant with the lower amount of moles is limiting reactant.

Moles Fe -Molar mass: 55.845g/mol-

4.68g * (1mol / 55.845g) = 0.0838 moles

Moles S -Molar mass: 32.065g/mol-

2.88g * (1mol / 32.065g) = 0.0898 moles

As the amount of moles of Fe < Moles S,

Iron is limiting reactant

When 4.68 g of iron reacts with 2.88 g of sulfur to produce FeS, iron is the limiting reagent.

If in a chemical reaction two reactants are present and one of them is present in less quantity as compared to other, is known as limiting reagent.

Given chemical reaction is:
Fe + S → FeS

From the stoichiometry of the reaction it is clear that equal moles of both reactant is required for the formation of product, so their mole ratio is 1:1.

Now we calculate the moles by using the formula:

n = W/M, where

W = given mass

M = molar mass

Moles of 4.68g of iron = 4.68g / 55.845g/mole = 0.0838 moles

Moles of 2.88 of sulfur = 2.88g / 32.065g/mole = 0.0898 moles

Moles of iron is less as compare to the sulfur, so it is the limiting reagent.

Hence, iron is the limiting reagent.

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Answer:

Square

Explanation:

A square is a quadrilateral with r sides the same length

Answer:

Explanation:

A- nuclear fusion

Answer:

5.9 × 10² kJ

Explanation:

When carbon disulfide, CS₂, forms from its elements, heat is absorbed. The corresponding value for the standard enthalpy of formation of carbon disulfide is 117.36 kJ/mol. The thermochemical equation that represents this process is:

C(graphite) + 2 S(s, rhombic) ⇒ CS₂(g)   ΔH°f = 117.36 kJ/mol

117.36 kJ of heat are absorbed when 1 mole of CS₂ is formed. The amount of heat absorbed when 5.0 moles of CS₂ are formed is:

5.0 mol × 117.36 kJ/mol = 5.9 × 10² kJ

Answer:

2.059524x10^26 if im not wrong

Explanation:

avogadro's number is 6.022x10^23

Answer: A

Explanation:

The correct structure of the name of the compound given is  CH₃CH₂C=CC (CH₃)₃.

Dimethyl hexyne is an organic compound. Its chemical formula is C8H14. The compound hexyne is used to make a complex compound, agrochemical, and pharmaceutical compounds.

Thus, the correct option is A, CH₃CH₂C=CC (CH₃)₃.

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Answer:

0.188mol

Explanation:

Using the formula;

mole = mass/molar mass

Molar mass of hypomanganous acid. (H3MnO4) = 1(3) + 55 + 16(4)

= 3 + 55 + 64

= 122g/mol

According to this question, there are 22.912g of H3MnO4

mole = 22.912g ÷ 122g/mol

mole = 0.188mol

The statement is true  about the rotational period of the moon " the rotational period of the moon is equal to the revolution period around Earth."

A celestial object's rotation period may relate towards its sidereal rotation period, which is the time it takes for the object to complete one revolution around in its axis of rotation in sidereal seems like to the background stars.

The orbital period is also known as the revolution period. it takes for one astronomical object to complete one cycle around another. It refers to planets and asteroids orbiting the Sun, moons orbiting planets, planetary systems orbiting other stars, or double stars in astronomy.

In the night sky, the moon is just the brightest object. The moon doesn't at all produce its own light. It has no radiance. That is visible because the sun's light bounces off of it.

The rotational period of the moon is equal to the revolution period around Earth because the moon's rate of spin becomes tidally locked to its rate of revolution, it maintains the same face oriented towards the Earth In other words, every time the moon rounds the Earth, it rotates exactly once.

Therefore, the rotational period of the moon is equal to the revolution period around Earth will be correct answer.

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Answer:

See explanation.

Explanation:

Hello there!

In this case, according to the described chemical reaction, we first write the corresponding equation to obtain:

[tex]Cu+2AgNO_3\rightarrow 2Ag+Cu(NO_3)_2[/tex]

Thus, we proceed as follows:

Part 1 of 3: here, since the molar mass of silver and copper (II) nitrate are 107.87 and 187.55 g/mol respectively, and the mole ratio of the former to the latter is 2:1, we can set up the following stoichiometric expression:

[tex]m_{Cu(NO_3)_2}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu(NO_3)_2}{2molAg}*\frac{187.55gCu(NO_3)_2}{1molCu(NO_3)_2} \\\\m_{Cu(NO_3)_2}=1.12gCu(NO_3)_2[/tex]

Part 2 of 3: here, the molar mass of copper is 63.55 g/mol and the mole ratio of silver to copper is 2:1, the mass of the former that was used to start the reaction was:

[tex]m_{Cu}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu}{2molAg}*\frac{63.55gCu)_2}{1molCu} \\\\m_{Cu}=0.380gCu[/tex]

Part 3 of 3: here, the molar mass of silver nitrate is 169.87 g/mol and their mole ratio 2:2, thus, the mass of initial silver nitrate is:

[tex]m_{AgNO_3}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{2molAgNO_3}{2molAg}*\frac{169.87gAgNO_3}{1molAgNO_3} \\\\m_{AgNO_3}=2.03gAgNO_3[/tex]

Best regards!

Answer: C

Explanation: I have the same question, it’s for summit, my teacher helped me with this question :)

Solution :

Molecular mass of NaOH is 23 g/mol .

So, number of moles of NaOH is given by :

[tex]n = \dfrac{10}{40}\ mole[/tex]

Now, we know molarity is given by :

[tex]Molarity = \dfrac{Number \ of \ moles\ of \ salute}{Volume ( in \ Liter ) }[/tex]

[tex]M = \dfrac{10}{40\times 2.4} \ M\\\\M = 0.104 \ M[/tex]

Hence, this is the required solution.

Answer: The answer is A O0.104 M NaOH

Explanation:

Answer:D

Explanation:i did the usa test prep

Answer:answer is D

Explanation:

Answer:

The oxidation state of carbon in CaC204 is 3

Answer:The oxidation number of the carbons + the oxidation numbers of the oxygens must equal -2. Carbons + (-8) = -2 so the oxidation number of the carbons must be +6. Since there are 2 carbon atoms each must contribute +3 each. What is the oxidation number of S in Na2S2O3?

Explanation:

The oxidation state of Oxygen is -2 and that of Calcium is +2. There are four oxygen atoms which amounts to -8 charge. This leaves a charge of +6 on Carbon

Answer:

its b alkyne

Explanation:

brinliest po plsss

Answer:

Alkyne so its b

Answer:

1.13 L

Explanation:

First, we have to write the chemical equation for the reaction between ammonia gas (NH₃) and oxygen gas (O₂) to give nitrogen gas (N₂) and water (H₂O), as follows:

NH₃(g) + O₂(g) → N₂(g) + H₂O(g)

Then, we have to balance the equation (we write first the coefficient 2 for NH₃ to balance N atoms, then a coefficient of 3 for H₂O to balance H atoms, and finally 1/3 to balance the O atoms):

2 NH₃(g) + 3/2 O₂(g) → N₂(g) + 3 H₂O(g)

In the balanced equation, we can see that 1 mol of N₂ is produced from 2 moles of NH₃. We convert the moles of NH₃ to grams by using its molecular weight (MW):

MW(NH₃) = 14 g/mol N x 1 + (1 g/mol H x 3) = 17 g/mol

grams of NH₃ = 17 g/mol x 2 = 34 g

Thus, we have the stoichiometric ratio:

1 mol of N₂/2 mol NH₃ = 1 mol of N₂/34 g NH₃

To calculate how many moles of N₂ are produced from 4.0 of NH₃, we multiply the mass by the conversion factor:

4.0 g NH₃ x 1 mol of N₂/34 g NH₃ = 0.1176 moles N₂

Finally, we calculate the liters of N₂ gas by using the ideal gas equation:

PV = nRT ⇒ V = nRT/P

We introduce the data in the equation:

T = 32.00°C + 273 = 305 K

P = 2.6 atm

R = 0.082 L.atm/K.mol (is the gas constant)

n= 0.1176 moles

⇒ V = nRT/P = (0.1176 mol x 0.082 L.atm/K.mol x 305 K)/(2.6 atm)

                     = 1.13 L

Answer:

15.5 moles

Explanation:

Applying,

PV = nRT.................. Equation 1

Where P = pressure, V = Volume, n = number of mole, R = molar gas constant, T = Temperature.

Make n the subject of the equation

n = PV/RT............... Equation 2

From the question,

Given: P = 0.899 atm, V = 425 L, T = 24 °C = (273+24) K = 297 K.

Constant: R = 0.083 L.atm/K.mol

Substitute these values into equation 2

n = (0.899×425)/(297×0.083)

n = 15.5 moles

Answer:

Explanation:

A covalent compound is a compound formed by covalent bonds. A covalent bond is formed between two atoms where electrons are shared between the two atoms. This forms a molecule.

What determines whether two elements will form a covalent compound or not is the number of valence electrons present in each of the elements.

Fluorine will form a covalent compound with phosphorous because fluorine has 5 electrons in its outermost shell. It needs 3 more to become stable.

Phosphorous also has 5 valence electrons. It needs 3 more to become stable.

What happens is that 3 atoms of FLuorine combine with one atom of Phosphorus, sharing the valence electrons between themselves. This leads to the formation of the PF3 molecule.

Both the Phosphorous and the Fluorine are now stable.

Answer: Phosphorus

Explanation: since both are non-metals they would both create a covalent bond.

Answer:

it will all fall unless these is air

Explanation:

Answer:

If you do it carefully enough, a small amount of water will pour out of the glass — that's supposed to happen. But try not to let any air bubbles get into the glass. Finally, slowly remove the hand holding the cardboard in place.

Answer:The thermal waters of a spring have a hydronium ion (H3O+) concentration of 2.00 x . 2. Acetic acid (CH3COOH) is one of the simplest carboxylic acids. It is an important chemical reagent and industrial chemical.Have a hydronium ion (H3O+) concentration of 2.00 x 10-6 M. Calculate the pH of the water.

Explanation: The thermal waters of a spring have a hydronium ion (H3O+) concentration of 2.  spring have a hydronium ion (H3O+) concentration of 2.00 x 10-6 M. Calculate the pH of the water. 2. Acetic acid (CH3COOH) is one of the simplest carboxylic acids. It is an important chemical reagent and industrial chemical.

Answer: 2.5

Explanation:

density= 2.5

mass= 62.5 or 62.50

volume= 25 ( 75-50= 25)

so divide 62.5( or 62.50) by 25 which will led you to 2.5

Answer:

Explanation:

I can’t explain but this is the answer LOL

Answer:

a chemical reaction occured

Explanation:

bubbling and fizzing after adding a substance, most offten means a chemical reaction is happening

Answer:

two hydrogen can bonded with oxygen to form H2O

Answer: The balanced equation is [tex]2FeCl_{3} + 3MgO \rightarrow Fe_{2}O_{3} + 3MgCl_{2}[/tex]

Explanation:

The given reaction equation is as follows.

[tex]FeCl_{3} + MgO \rightarrow Fe_{2}O_{3} + MgCl_{2}[/tex]

Here, number of atoms present on reactant side are as follows.

Number of atoms on product side are as follows.

To balance this equation, multiply [tex]FeCl_{3}[/tex] by 2 and MgO by 3 on reactant side. Also, multiply [tex]MgCl_{2}[/tex] by 3 on product side. Therefore, the equation can be rewritten as follows.

[tex]2FeCl_{3} + 3MgO \rightarrow Fe_{2}O_{3} + 3MgCl_{2}[/tex]

Hence, number of atoms on reactant side are as follows.

Number of atoms on product side are as follows.

Since, this equation contains same number of atoms on both reactant and product side. Therefore, this equation is now balanced equation.

Thus, we can conclude that the balanced equation is [tex]2FeCl_{3} + 3MgO \rightarrow Fe_{2}O_{3} + 3MgCl_{2}[/tex].

Answer:

The solid crystals disappeared

Explanation:

When a soluble solid solute is added to water, the solid solute disappears after a little while. The disappearance of this solute indicates that the solute has been dissolved in water.

In this case, blue copper sulphate crystals are added to water, the blue crystals disappear leaving only a blue solution. The disappearance of these blue copper sulphate crystals indicates that the substance has dissolved in water.

Answer:

The cation is written first in the name; the anion is written second in the name. Rule 2. When the formula unit contains two or more of the same polyatomic ion, that ion is written in parentheses with the subscript written outside the parentheses.

When writing the formula of a compound that contains polyatomic ion, the metal is written first followed by the central atom in the ion and then other atoms that surround the central atom.

A poly atomic ion refers to an ion that comprises of more than one atom. Such ions are common in chemistry. Examples of polyatomic ions include; PO4^3-, BH4^- etc.

When writing the formula of a compound that contains a polyatomic ion, the metal is written first then the central atom in the ion follows before other atoms that surround the central atom in the ion.

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Answer:

The reason why atomic mass is usually not a whole number is because it is a weighted average of the mass numbers of isotopes

Explanation:

Answer: f = 760 Hz

Explanation:  speed = frequency · wavelength  v = fλ.

frequency f = v/ λ = 380 m/s / 0.50 m = 760 Hz

Answer:

The tectonic style and viability of modern plate tectonics in the early Earth is still debated. Field observations and theoretical arguments both in favor and against the uniformitarian view of plate tectonics back until the Archean continue to accumulate. Here, we present the first numerical modeling results that address for a hotter Earth the viability of subduction, one of the main requirements for plate tectonics. A hotter mantle has mainly two effects: 1) viscosity is lower, and 2) more melt is produced, which in a plate tectonic setting will lead to a thicker oceanic crust and harzburgite layer. Although compositional buoyancy resulting from these thick crust and harzburgite might be a serious limitation for subduction initiation, our modeling results show that eclogitization significantly relaxes this limitation for a developed, ongoing subduction process. Furthermore, the lower viscosity leads to more frequent slab breakoff, and sometimes to crustal separation from the mantle lithosphere. Unlike earlier propositions, not compositional buoyancy considerations, but this lithospheric weakness could be the principle limitation to the viability of plate tectonics in a hotter Earth. These results suggest a new explanation for the absence of ultrahigh-pressure metamorphism (UHPM) and blueschists in most of the Precambrian: early slabs were not too buoyant, but too weak to provide a mechanism for UHPM and exhumation.

Explanation: