Which state of matter is being described below?It cannot be squashed easily, will not spread out & is high densityA. GasB. SolidC. LiquidD. Plasma

Answers

Answer 1

There are 3 main states of matter: gas, solid, and liquid.

The solid is characterized by its rigid structure, its high density (it means that's there's a lot of mass per unit of volume). Also, it doesn't take the container's shape as a liquid does.

Then, the description corresponds to the solid state (option B).


Related Questions

When 29.0 g of butane reacts with oxygen, 88.0 g of carbon dioxide and 45.0 g of water are produced. What mass of oxygen reacted with the butane?

Answers

We need to first write the balanced equation:

[tex]2C_4H_{10}+13O_2\rightarrow8CO_2+10H_2O[/tex]

we are given the following:

mass of butane = 29.0 g

mass of carbon = 88.0 g

mass of water = 45.0 g

We want the mass of O2 that reacted.

C4H10 is the limiting reactant, and we know the masses of products produced. We can use that to find out how much oxygen reacted.

We can use CO2:

number of moles of CO2 = 88.0/44.01 = 1.9995 mol

The molar ratio between O2 and CO2 is 13:8

Therefore the number of moles of O2 = 1.9995 x (13/8) = 3.249 mol

Now that we have the number of moles, we can calculate the mass.

m = n x M

m = 3.249 mol x 31.998 g/mol

m = 103.97 g

A photon has a frequency of 3.16 * 10^7 Hz. Calculate its energy

Answers

If the photon has a frequency of   3.16 × 10 ⁷ Hz, then the energy of the the photon as per Planck's law would be 1.978× 10⁻²⁶ Joules

What is Wavelength?

It can be understood in terms of the distance between any two similar successive points across any wave.

C = λν

As given in the problem we have to calculate the energy of the light if the frequency of light is  3.16 × 10 ⁷ Hz

The energy of the photon = h ν

                                           = 6.26 × 10⁻³⁴ × 3.16 × 10 ⁷

                                           = 1.978× 10⁻²⁶ Joules

Thus, If the photon has a frequency of   3.16 × 10 ⁷ Hz, then the energy of the the photon as per Planck's law would be 1.978× 10⁻²⁶ Joules.

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How to balance ____CaCl2 —-> ____Ca+ ____ Cl

Answers

In order to properly balance an equation, we need to make sure that the same amount of elements on the reactants side matches the number of elements on the products side, we can do that by increasing the number in front of each molecule, the so called stoichiometric coefficient. In the reaction from the question we can properly balance by adding the following stoichiometric coefficients

For this question we have:

CaCl2 -> Ca + 2 Cl

The energy released when a nucleus forms is calledQuestion 26 options: enthalpy. atomic mass. a becquerel. binding energy.

Answers

The correct answer in this case is binding energy, which is the energy released when a collection of nucleons form a nucleus.

The correct answer is the last choice.

What is the maximum number of electrons that can occupy the n = 2 shell?

Answers

Explanation:

If n = 2 we have this posibility:

This shell contains 2 subshells: s and p

Subshell 2s can only contain 2 electrons

Subshell 2p can only contain 6 electrons

Answer: In total, we can have 8 electrons in n = 2

How many liters of oxygen gas at STP are required to react with 30.25 g of aluminum in the production of aluminum oxide?

Answers

Answer:

18.82L of oxygen gas are needed.

Explanation:

1st) It is necessary to write and balance the chemical reaction:

[tex]3O_2+4Al\rightarrow2Al_2O_3[/tex]

2nd) From the balanced reaction, we can see that 3 moles of oxygen gas (O2) react with 4 moles of aluminum (Al). To convert moles to grams, it is necessary to use the molar mass of oxygen (32g/mol) and aluminum (27g/mol):

- O2 conversion:

[tex]\begin{gathered} 1mol-32g \\ 3mol-x=\frac{3mol*32g}{1mol} \\ x=96g \end{gathered}[/tex]

- Al conversion:

[tex]\begin{gathered} 1mol-27g \\ 4mol-x=\frac{4mol*27g}{1mol} \\ x=108g \end{gathered}[/tex]

Now we can see that 96g of O2 react with 108g of Al.

3rd) We have to calculate the grams of O2 that will react with 30.25g of Al:

[tex]\begin{gathered} 108gAl-96gO_2 \\ 30.25gAl-x=\frac{30.25gAl*96gO_2}{108gAl} \\ x=26.89gO_2 \end{gathered}[/tex]

Using the molar mass of oxygen, we know that 26.89g represent 0.84 moles of O2.

4th) Finally, a mole of a gas at STP conditions occupies a volume of 22.4L. With this number and the moles of oxygen gas, we can calculate the liters:

[tex]\begin{gathered} 1mol-22.4L \\ 0.84mol-x=\frac{0.84mol*22.4L}{1mol} \\ x=18.82L \end{gathered}[/tex]

So, 18.82L of oxygen gas are needed.

Why is CuSO4 the correct formula for copper (ii) sulfate and not CuSO3?

Answers

The correct formula of copper (II) sulfate is CuSO₄ because Copper ion (Cu²⁺) has +2 charge and sulfate ion SO₄²⁻ has -2 charge, while CuSO₃ is copper(II) sulfite.

What is copper sulfate?

The CuSO₄ molecule contains an ionic bond between the copper cation (Cu²⁺) and the sulfate anion (SO₄²⁻).

The copper sulfate in its pentahydrate form is given by the chemical formula CuSO₄.5H₂O. This form of copper sulfate is characterized by its bright blue color but the anhydrous form of this salt is a white powder.

The oxidation state of the copper atom in a CuSO₄ molecule is +2. The molar mass of the pentahydrate and anhydrous forms of copper sulfate are 249.685 grams/mole and  159.609 grams/mole respectively.

Anhydrous CuSO₄ has a powdery appearance and a grey-white, while the pentahydrate has a bright blue color.

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Monica works in a crime lab. Her supervisor tells her that she needs to better understand Locard’s Exchange Principle. How will she MOST accurately demonstrate her understanding of this concept?

A.
She will always test for the presence of blood at crime scenes.

B.
She will use both fingerprints and bullet matching to solve crimes.

C.
She will keep evidence separated so it doesn’t get contaminated.

D.
She will exchange information openly with other crime investigators.

Answers

She will keep evidence separated so it doesn’t get contaminated demonstrates the understanding of Locard’s Exchange Principle and is denoted as option C.

What is Locard’s Exchange Principle?

This principle states that an individual who commits a crime will bring something into the crime scene and leave with something from it. This also explains that they can be used as evidence during investigation by the appropriate authorities.

Since we are aware that new substances are always brought into and carried away from the crime scene then it is best to keep the evidence separated so it doesn’t get contaminated.

This ensures that the results gotten from the analysis and investigation are accurate and is therefore the reason why option C was chosen as the correct choice.

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A lawyer is presenting a hair sample with its corresponding nuclear DNA that was found at the crime scene. How will this MOST likely affect the criminal case?

A.
The evidence will have a low probability of providing accurate matching results.

B.
The evidence will need to be looked at under a microscope to be admitted.

C.
The evidence will not be admissible in a court case.

D.
The evidence will provide a nearly exact match to the suspect’s hair.

Answers

A sample will likely affect a criminal case because this evidence will provide a nearly exact match to the suspect’s hair (Option D).

What is DNA testing?

DNA testing refers to the techniques used to obtain DNA from samples that can be used to identify an individual in a police case. A sample of hair may be used for DNA testing because it contains cells and therefore also contains DNA.

Therefore, with this data, we can see that DNA testing allow us to identify individuals for which we need to obtain a sample with cells.

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**NEED USEFUL ANSWER ASAP**
How do the masses of the hottest main sequence stars compare to the masses of the coolest main sequence stars?

Answers

Answer:

the more hotter the star, the more brightly it burns

Explanation:

someone just deleted my answer ugh sorry....ill write it again

so, te main sequence is a sequence in mass (and not a sequence in time).

The most massive stars are located at the the top left (since they are the brightest and hottest/bluest). The lowest mass stars are are located at the bottom left ( since they dimmer and cooler/redder).

Following the main sequence from the top left to the bottom right is thus a sequence from high to low mass.

What is the mass of 9.50 moles of magnesium chloride, MgCl2 ?'

Answers

The actual mass is 904.4g but with correct number of sig figs it’s 904g.

Consider a solution containing 0.100 M fluoride ions and 0.126 M hydrogen fluoride. The concentration of fluoride ions after the addition of 10.00 mL of 0.0100 M HCl to 25.0 mL of this solution is ________ M.

Answers

The concentration of fluoride ions after the addition of 10.00 mL of 0.0100 M HCl to 25.0 mL of this solution is 0.009 M

One of the terms for concentration that is used frequently in solutions would be molarity. It would be explained as the number of moles of solute in one liter of solution.

Molarity can be determined by the formula:

Molarity = moles of solute/ volume of solution

Moles of the HCl can be determined by using the formula:

Moles of solute = molarity × volume of the solution.......(i)

It is given that,

Molarity = 0.0100 M.

Volume = 10.0 mL .

Put the value of given data in above equation:

Moles of solute = (0.0100 M) × (10.0 mL) ×([tex]10^{-3}[/tex]/1 mL)

Moles of solute =  [tex]10^{-7}[/tex] M

Now, determine moles of HF.

Moles of solute = (0.126 M) × (25 mL) ×([tex]10^{-3}[/tex]/1 mL)

Moles of solute = 0.00315 M

Total moles = 0.00315 M + 0.0000001 M =0.0031501 M

Total volume = 10.00 mL + 25 mL = 35 mL.

Molarity can be determined by the formula:

Molarity = moles of solute/ volume of solution

Molarity = 0.0031501 M / 35 (1/[tex]10^{-3}[/tex])

Molarity = 0.009 M

Therefore, molarity will be 0.009 M.

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Part II Dilution Problems: 17. 350.0 mL of water was added to a 2.3 L solution of NaCl. If the final concentration of the solution was 0.967 M, what was the original concentration of the solution?

Answers

ANSWER

The original concentration of the solution is 0.147 mol

EXPLANATION

Given that;

The volume of water is 350.0mL

The volume of NaCl solution is 2.3L

The final concentration of the solution is 0.967M

To find the original concentration of the solution, follow the steps below

Step1: Write the dilution formula

[tex]\text{ M1V1}=M2V2[/tex]

Where

• M1 is the original concentration of the solution

,

• V1 is the original volume of the of the solution

,

• M2 is the final concentration of the solution

,

• V2 is the final volume of the solution

Step 2: Convert the volume of water to L

Recall, that 1mL is equivalent to 0.001L

[tex]\begin{gathered} \text{ The volume can be converted below as} \\ \text{ 1mL }\rightarrow\text{ 0.001L} \\ \text{ 350mL }\rightarrow\text{ vL} \\ \text{ Cross multiply} \\ \text{ vL}\times\text{ 1mL }=\text{ 350mL}\times0.001L \\ \text{ Isolate v} \\ \text{ v }=\text{ }\frac{350\cancel{mL}\times\text{ 0.001L}}{1\cancel{mL}} \\ \text{ v }=\text{ 350}\times\text{ 0.001} \\ \text{ v }=\text{ 0.35L} \end{gathered}[/tex]

Step 3; Find the original concentration of the solution by substituting by the given data into the formula in step 1

[tex]\begin{gathered} \text{ M1}\times2.3\text{ }=\text{ 0.35}\times\text{ 0.967} \\ \text{ 2.3M1 }=\text{ 0.33845} \\ \text{ Divide both sides by 2.3} \\ \text{ }\frac{2.3M1}{2.3}\text{ }=\text{ }\frac{0.33845}{2.3} \\ \text{ M1}=\text{ 0.147 mol} \end{gathered}[/tex]

Hence, the original concentration of the solution is 0.147 mol

7. A given sample of gas is held in a container with the volume of 6.02 L with a temperature of 59.5℃ at a pressure of 1.20 atm. What is the final pressure when the sample of gas is administered to a new volume of 10.0 L at 20.2℃?

Answers

The final pressure of the sample gas based on the new volume and temperature would be 0.245 atm.

Combined gas law

The combined gas law is expressed as:

[tex]\frac{p_1v_1}{t_1}[/tex] = [tex]\frac{p_2v_2}{t_2}[/tex]

Where

[tex]p_1[/tex]= initial pressure[tex]v_1[/tex]= initial volume[tex]t_1[/tex]= initial temperature[tex]p_2[/tex]= final pressure[tex]v_2[/tex]= final volume[tex]t_2[/tex]= final temperature

In this case, we were given all the variables except the final pressure, [tex]p_2[/tex]:

[tex]p_1[/tex]= 1.20 atm[tex]v_1[/tex]= 6.02 L[tex]t_1[/tex]= 59.5℃[tex]v_2[/tex]= 10.0 L[tex]t_2[/tex]= 20.2℃

Making p2 the subject of the formula in the combined gas equation, we have:

[tex]p_2[/tex]= [tex]p_1v_1t_2/t_1v_2[/tex]

Next, let's substitute the given variables:

[tex]p_2[/tex]= 1.2 x 6.02 x 20.2/59.5 x 10.0

     = 145.9248/595

     = 0.245 atm

In other words, the final pressure when the sample of gas is administered to a new volume of 10.0 L at 20.2℃ is 0.245 atm'

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Chemistry Electromagnetic Radiation HW Help. Pls real answers

Answers

The frequency of the green light from a traffic signal is 5.76 * 10¹⁴ Hz

The frequency of the light is 1.85 * 10¹⁶ Hz

The frequency of the light is 4.84 * 10¹⁴ Hz

The energy of the photons is 1.172 * 10⁻³ J

The energy of the photons is 4.34 * 10⁻² J

What is the frequency of light wave given the wavelength?

The frequency of light can be found given the wavelength from the formula below:

frequency = velocity / wavelength

8. The frequency of the green light from a traffic signal is calculated below:

velocity of light = 3.0 * 10⁸ m/s

wavelength = 5.2 x 10⁻⁷ m

Frequency = 3.0 * 10⁸ / 5.2 x 10⁻⁷

frequency = 5.76 * 10¹⁴ Hz

9. The frequency of the light is calculated below:

velocity of light = 3.0 * 10⁸ m/s

wavelength = 16.23 x 10⁻⁹ m

Frequency = 3.0 * 10⁸ / 16.23 x 10⁻⁹

frequency = 1.85 * 10¹⁶ Hz

10. The frequency of the light is calculated below:

velocity of light = 3.0 * 10⁸ m/s

wavelength = 6.2 x 10⁻⁷ m

Frequency = 3.0 * 10⁸ / 6.2 x 10⁻⁷

frequency = 4.84 * 10¹⁴ Hz

11. The energy of one of the photons will be calculated as follows:

E = hf

E = hc/λ

Energy of the photons =  2.3 x 10¹¹ x hc/λ

h = 6.626 * 10⁻³⁴Js

λ = 3.9 x 10⁻¹² m

c = 3.0 * 10⁸ m/s

E =   2.3 x 10¹¹ x 6.626 * 10⁻³⁴ * 3.0 * 10⁸ / 3.9 x 10⁻¹²

E = 1.172 * 10⁻³ J

12. The energy of one of the photons will be calculated as follows:

E = hf

E = hc/λ

Energy of the photons =  9.4 x 10¹⁶ x hc/λ

h = 6.626 * 10⁻³⁴Js

λ = 4.3 x 10⁻⁷ m

c = 3.0 * 10⁸ m/s

E =   9.4 x 10¹⁶ x 6.626 * 10⁻³⁴ * 3.0 * 10⁸ / 4.3 x 10⁻⁷

E = 4.34 * 10⁻² J

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how does a catalyst increase the rate of a reaction?

Answers

Answer:

Reducing the activation energy and providing an alternative reaction pathway for the reaction to happen

Explanation:

A lower activation energy means that reactants will need less energy to successfully react to make products, meaning that more successful collisions will happen between reactants, increasing the rate of reaction

A catalyst reduces the activation energy of the reaction, speeding it up. By decreasing the activation energy, the energy hurdle that must be cleared for a chemical reaction to take place, catalysts improve the efficiency of this process.

What is catalyst ?

By decreasing the activation energy, the energy hurdle that must be cleared for a chemical reaction to take place, catalysts improve the efficiency of this process.

As a result, catalysts facilitate the formation of chemical bonds between atoms to create novel combinations and new compounds.

A catalyst is a chemical that may be included in a reaction to speed up the process without being consumed. Typically, catalysts shorten the activation energy of a process or alter its mechanism. Proteins called enzymes serve as catalysts in biological processes.

Thus, the catalyst reduces the activation energy of the reaction, speeding it up

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How many grams of MgO are produced when 40.0 grams of O2 react completely with Mg? I picked B but I’m not sure if I’m correct

Answers

Step 1

The reaction provided:

2 Mg (s) + O2 (g) => 2 MgO (s) (completed and balanced)

-----------

Step 2

Information provided:

40.0 g of O2 which react completely

---

Information needed:

The molar masses of:

O2) 32.0 g/mol

MgO) 40.3 g/mol

-----------

Step 3

By stoichiometry,

2 Mg (s) + O2 (g) => 2 MgO (s)

32.0 g O2 ------- 2 x 40.3 g MgO

40.0 g O2 ------- X

X = 40.0 g O2 x 2 x 40.3 g MgO/32.0 g O2

X = 101 g MgO

Answer: C 101 g

Of the elements calcium, Ca, beryllium, Be, barium, Ba, and strontium, Sr, arrange in order of decreasing atomic radii. Explain your answer using the terms electron and energy level.

Answers

Order these elements Ca, Be, Ba, and Sr:

If we take a look at the periodic table trends we will see that the atomic radii increases from left to right and from top to bottom.

So let's look for our elements:

Be: atomic number 4

Ba: atomic number 56

Ca: atomic number 20

Sr: atomic number 38

They are all Alkaline Earth Metals, they are in the same group.

So we said that the atomic radii increases from top to bottom. If we have to arrange them in order of decreasing atomic radii, we have to put first the largest one. The Barium is the one that is in a lower position, then Sr, then Ca and finally Be.

So the order of our problem is Ba, Sr, Ca and Be.

Which is the explanation?

As we move down in the periodic table the number of electrons increases. They all have 2 electrons in the outer shell. But let's look at the electronic configuration of two of them:

Ca:

Ba:

Write formulas or names as appropriate for each of the following hydrates. 1. Magnesium sulfate heptahydrate 6. CoSO4•H2O 2. Copper(I) sulfate pentahydrate 7. Na2CrO4•4H2O 3. Potassium phosphate decahydrate 8. CuF2•2H2O 4. Calcium chloride hexahydrate 9. Sr(NO3)2•6H2O 5. Iron(III) nitrate nonahydrate 10. ZnSO4•7H2O

Answers

Answer:

Explanation:

Here, we want to give the names or formulas of the given hydrates

1) Magnesium sulfate heptahydrate

The first thing we have to do here is write the formula for magnesium sulfate.

Hepta means 7, which is pointing to the fact that there are 7 water molecules

We can have this as:

[tex]\text{MgSO}_4\cdot7H_2O[/tex]

6) Here, we can see that the element involved is cobalt with an oxideation number of 2. We also have just one water of crystallization

So, we have the name of the compound as:

[tex]\text{Cobalt (II) Sulphate hydrate}[/tex]

Given the equation below, how many moles of nitrogen gas (N2) areneeded to react with 7.5 moles of hydrogen gas (H2)?N2+ 3H2 —>2 NH3

Answers

Answer

2.5 moles of N₂ are needed to react with 7.5 moles of hydrogen gas

Explanation

Given:

Equation: N₂ + 3H₂ → 2NH₃

Moles of H₂ = 7.5 moles

What to find:

The moles of nitrogen gas (N₂) needed to react with 7.5 moles of hydrogen gas

Step-by-step solution:

Let the mole of N₂ needed be x.

From the given balanced chemical equation:

3 moles of H₂ react with 1 mole of N₂

Therefore, 7. 5 moles of H₂ will react with x moles of N₂

Cross multiply

[tex]\begin{gathered} x\text{ moles }N_2\times3\text{ moles H}_2=7.5\text{ moles H}_2\times1\text{ mole N}_2 \\ \text{Divide both sides by 3 moles H}_2 \\ \frac{x\text{ moles }N_2\times3\text{ moles H}_2}{3\text{ moles H}_2}=\frac{7.5\text{ moles H}_2\times1\text{ mole N}_{2}}{3\text{ moles H}_2} \\ x\text{ moles }N_2=2.5\text{ moles} \end{gathered}[/tex]

Calculate the frequency and the energy of blue light that has a wavelength of 423 nm (Note => 423 nm = 4.23 * 10^7 m)

Answers

According to the Planck's equation,the energy and frequency of blue light are 4.699×10[tex]^-19[/tex] J and 2.363×10⁶ m[tex]^-1[/tex] respectively.

What is Planck's equation?

Max Planck discovered the theory which stated that energy is transferred in the form of discrete packs which are called quanta and thus proposed an equation called the Planck's equation which relates energy and frequency of a photon and is given as, E=hcυ or in terms of wavelength it is ,E=hc/λ.

The equation makes use of a constant which is called the Planck's constant and it's value is 6.626×10[tex]^-34[/tex] Js.

In the given problem, energy is calculated as,E=6.626×10[tex]^-34[/tex]×3×10⁸/4.23×10[tex]^-7[/tex]=4.699×10[tex]^-19[/tex] J.

The frequency  of light is calculated as follows,4.699×10[tex]^-19[/tex]/19.878×10[tex]^-26[/tex]=2.363×10⁶ m[tex]^-1[/tex].

Thus , the energy and frequency of blue light are  4.699×10[tex]^-19[/tex] J and 2.363×10⁶ m[tex]^-1[/tex] respectively.

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What is the correct name-formula pair for calcium (II) oxide?

Answers

The chemical formula of calcium (II) oxide is CaO, wherein the valency of both oxygen and calcium is two.

What is chemical formula?

Chemical  formula is a way of representing the number of atoms present in a compound or molecule.It is written with the help of symbols  of elements. It also makes use of brackets and subscripts.

Subscripts are used to denote number of atoms of each element and brackets indicate presence of group of atoms. Chemical formula does not contain words. Chemical formula in the simplest form  is called empirical formula.

It is not the same as structural formula and does not have any information regarding structure.It does not provide any information regarding structure of molecule as obtained in structural formula.

There are four types of chemical formula:

1)empirical formula

2) structural formula

3)condensed formula

4)molecular formula

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Write the correct formula for the following compound:

magnesium hydroxide

Answers

The formula of magnesium hydroxide is Mg(OH)2.

How magnesium hydroxide?

Magnesium hydroxide is an inorganic compound having the chemical formula of Mg(OH)2. It is present in nature as mineral brucite. It is a white solid substance with low solubility in water. Magnesium hydroxide is a component of antacids such as milk of magnesia. Extended use or overuse of this medication for constipation results in dependence on laxatives and constipation. Overuse of Magnesium hydroxide also causes diarrhea that does not go away, dehydration, and mineral imbalances. Severe nausea, vomiting, or diarrhea are the symptoms of using a high dose of magnesium hydroxide. After using a medicine such as a laxative, nausea, vomiting or diarrhea can be cured.

So we can conclude that Mg(OH)2 is the correct formula for magnesium hydroxide.

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Which temperature is unattainable?
a)_1k
b)_1°C
c)_1°F
d)All of these

Answers

Answer:

A is the correct answer.

Explanation:

It is possible to reach 1°C and 1°F because they are both units of temperature. But 1k is not a unit of temperature.

After conditions changed to a volume of a sample of helium at 15.56 mL, 138.7°C and 334.6 kPa. What was its initial volyme at 63.2 °C and 57.3 kPa?O a. 74.2O b. 41.4O c. 2.18O d. 111

Answers

Answer

a. 74.2

Explanation

Given that:

The initial temperature, T₁ = 63.2 °C + 273 = 336.2 K

Initial pressure, P₁ = 57.3 kPa

The final volume, V₂ = 15.56 mL

Final temperature, T₂ = 138.7°C + 273 = 411.7 K

Final pressure, P₂ = 334.6 kPa

What to find:

The initial volume, V₁.

Step-by-step solution:

The initial volume, V₁ can be calculated using the combined gas law equation.

[tex]\begin{gathered} \frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2} \\ \\ V_1=\frac{P_2V_2T_1}{P_1T_2}=\frac{334.6kPa\times15.56mL\times336.2K}{57.3kPa\times411.7K} \\ \\ V_1=\frac{1750383.611\text{ }mL}{23590.41}=74.2\text{ }mL \end{gathered}[/tex]

Hence, its initial volume at 63.2 °C and 57.3 kPa is 74.2 mL

Consider the reaction between sodium metal and chlorine gas to form sodium chloride (table salt):2 Na(s) + Cl2 (g) > 2 NaCI(s)If 12.5 g of sodium react with sufficient chlorine, how many grams of sodium chloride should form?1. 12.1 grams2. 1.18 x 10^2 grams3. 15.9 grams4. 3.18 x 10^1 grams5. 51.0 grams

Answers

Answer:

[tex]4\text{ : 3.18 }\times\text{ 10}^1\text{ grams}[/tex]

Explanation:

Here, we want to calculate the mass of sodium chloride formed

Firstly, we need to get the number of moles of sodium that reacted

To get this, we divide the mass of sodium by its atomic mass

We have that as:

[tex]\frac{12.5}{23}\text{ = 0.5435 mole}[/tex]

Now, let us get the number of moles of chlorine

From the equation of reaction, 1 mole of sodium produced 1 mole of sodium chloride

Thus, 0.5435 mole of sodium will also produce 0.5435 mole of sodium chloride

To get the mass of sodium chloride formed, we multiply the above number of moles by the molar mass of sodium chloride

The molar mass of sodium chloride is 58.44 g/mol

Thus, the mass of sodium chloride formed will be:

[tex]58.44\text{ }\times\text{ 0.5435 = 31.8 g}[/tex]

A chicken egg has mass 60g. It's shell makes up 10% of the whole egg. The shell is made of Calcium Carbonate; CaCO3. What is the mass of the Ca/ Calcium in the egg shell?​

Answers

60g•0.10=6g This is the mass of the egg shell
CaCO3: 100.09g
Ca: 40.08g
C: 12.01g
O: 16.00g•3=48.00g
Find the percentage of Ca found in Calcium Carbonate
40.08g of Ca/100.09g of CaCO3=0.40
.4•6g of CaCO3=2.4g of Ca

The total number of calcium atoms in the expression 3 cal 2 shown in the equation 3CaCl 2 +2Na 3 PO 4 Ca(PO 4 ) 2 +6 NaCl is:

Answers

Let's write the balanced chemical equation:

[tex]3CaCl_2+2Na_3PO_4\to Ca_3(PO_4)_2+6NaCl.[/tex]

You can see that in the reactants and in the products we have the same number of atoms for each element. This is due to the matter of conservation law.

The total number of calcium atoms that are reacting and produced in the reaction is 3.

Definition: This is a type of element or substance that is not a metal.Example: oxygen, nitrogen, hydrogen

Answers

This elements or substances that are not a metal are called non-metals.

I think that the answer is Non-metal

UESTION 14nsider the compound XF. Which of the following is true about the compound?A. If XF is covalent, X could be a metal.B. If XF is ionic, X could be a nonmetal.C. If XF is covalent, the name uses prefixes.D. If XF is covalent, X has a charge of +1.QUESTION 15What are the values of x and y in the compound Agx(CO3)y?O AX= 1, y = 2B. x = 3, y = 1OC. x = 3, y = 2O D.X = 2, y = 1

Answers

a. If XF is covalent, X couldn't be a metal. Because covalent bonding occurs between nonmetals. So this alternative is False.

b. If XF is ionic, X could be a nonmetal. Also False. Ionic bonding occurs between a metal and a nonmetal. In this case, we already have a nonmetal, which is F.

c. If XF is covalent, the name uses prefixes. True. When we have a covalent compound, the name of the nonmetal on the left has a prefix indicating the number of atoms of it.

d. If XF is covalent, X has a charge of +1. False. This would happen if it was ionic.

Answer: Alternative "C"

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