Why does 50 g of copper require less heat (q) than 50 g of water, in order to raise the temperature by 15 oC? (Hint - the heat capacity may play a role, but how?)

Answers

Answer 1

Answer:

See Explanation

Explanation:

Specific heat capacity is an intensive physical property of matter. It is a measure of the quantity of heat that must be supplied in order to change the temperature of a unit mass of a substance by 1°C.

The specific heat capacity of a substance determines the quantity of heat that must be supplied in order to effect a temperature change of a unit mass of a substance. The higher the specific heat capacity of a substance, the greater the quantity of heat required to effect a temperature change in a given mass of the substance.

The specific heat capacity of water is 4,200 Joules per kilogram while the specific heat capacity of copper is 385 Joules per kilogram. Hence, the heat capacity of water is far greater than that of copper and consequently, 50 g of copper require less heat (q) than 50 g of water, in order to raise the temperature by 15 oC.


Related Questions

Cell membranes are selectively permeable. This means that A. only water can move freely across the cell membrane. B. any substance can move across the cell membrane, but chemical energy will always be required. C. some substances can move freely across the cell membrane, while others must be transported. D. no substances can move freely across the cell membrane.

Answers

Answer:

C. some substances can move freely across the cell membrane, while others must be transported.

Explanation:

PLEASE HELP I HAVE 19 MINUTES LEFT I WILL MARK BRAINLIEST
How much more acidic is a pH of 4 as compared to a pH of 6.5?

Answers

Answer:

316.227766

Explanation:

Answer 3.16 hope it helps

0.41g of neon is held in a 200. mL container at 11 °C. Calculate the pressure in atm.

Answers

Answer:

2.39 atm

Explanation:

We'll begin by calculating the number of mole in 0.41 g of neon (Ne). This can be obtained as follow:

Mass of Ne = 0.41 g

Molar mass of Ne = 20 g/mol

Mole of Ne =.?

Mole = mass / molar mass

Mole of Ne = 0.41 / 20

Mole of Ne = 0.0205 mole

Next we shall convert 200 mL to L.

1000 mL = 1 L

Therefore,

200 mL = 200 mL × 1 L / 1000 mL

200 mL = 0.2 L

Next, we shall convert 11 °C to Kelvin temperature.

T(K) = T(°C) + 273

T(°C) = 11 °C

T(K) = 11 + 273

T (K) = 284 K

Finally, we shall determine the pressure. This can be obtained as follow:

Mole of Ne (n) = 0.0205 mole

Volume (V) = 0.2 L

Temperature (T) = 284 K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =?

PV = nRT

P × 0.2 = 0.0205 × 0.0821 × 284

P × 0.2 = 0.4779862

Divide both side by 0.2

P = 0.4779862 / 0.2

P = 2.49 atm

Therefore, the pressure of the gas is 2.39 atm

given mass of nitrogen is 0.12 dm^3 at 60°C and 1.01*10^5 Nm^2. Find its pressure at the same temperature if its volume is changed to 0.24 dm^3​

Answers

50500Nm^2 or 5.05Nm^2

Explanation:

so bring out the parameters

p1= 0.12dm3, T1= 60c , because temperature is in kelvin add 273= 333k, v1= 0.12dm3 , T2= to the same value because the temperature didn't change = 333k, v2= 0.24dm3,P2= ?

general gas equation p1v1 over T1 = P2V2 over T2, when you input everything or make p2 the subject of the formula first you'll get the answer, pressure can have an s.i unit of mmhg but I'm using the same si unit as the question given and always check your units in the question to convert. please if this question has options please check, I don't want you to fail so verify from others if I made a mistake

when rolling a number cube 500 times, how many times you expect to get a 3?

Answers

Answer:

[tex]\frac{250}{3}[/tex]

Explanation:

you can expect to get a 3 (theoretically) 1 time every 6 times you roll. A 1/6 chance.

Here's the equation:

[tex]\frac{1}{6} =\frac{x}{500}[/tex]

cross multiply (i think that's what it is called)

500=6x

divide by 6 on both sides:

x=[tex]\frac{250}{3}[/tex] or approx 83 times.

Hope this helps! Lmk if u have more questions <3

0.850 moles of N2 originally at 85°C is cooled such that it now occupies 17.55L at 1.25 atm. What is the final temperature of the gas?

Answers

you know at condition 2
P = 1.25atm
V = 17.55L
T = ?
R = 0.08206 Latm/molK
n = 0.850 mol

so you can use
PV = nRT
to solve for T

T = PV / (nR)
T = (1.25atm) x (17.55L) / (0.850mol x 0.08206 Latm/molK)
T = 314.5K = 41.1°C

The final temperature of the gas is 269.9 K, or -3.25 °C, which was calculated with the help of ideal gas equation.

What is the ideal gas equation?

The ideal gas equation gives the relation between pressure, volume and temperature.

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

To find the initial volume of the gas. We can use the fact that the number of moles of gas does not change during the cooling process:

n = 0.850 moles

We can also use the ideal gas law to find the initial volume of the gas:

PV = nRT

V = nRT/P

where R = 0.08206 L atm/K mol is the gas constant.

Convert the initial temperature from Celsius to Kelvin:

T1 = 85 °C + 273.15 = 358.15 K

Substitute the given values into the equation:

V₁ = (0.850 mol)(0.08206 L atm/K mol)(358.15 K)/(1 atm) = 24.03 L

Now we can use the combined gas law to find the final temperature:

(P₁V₁/T₁) = (P₂V₂/T₂)

Substitute the given values into the equation:

(1.25 atm)(24.03 L)/(358.15 K) = (P₂) (17.55 L)/(T2)

Solve for T₂:

T₂ = (P₂)(17.55 L)(358.15 K)/(1.25 atm)(24.03 L)

T₂ = 269.9 K

Therefore, the final temperature of the gas is 269.9 K, or -3.25 °C.

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Question 6 (4 points)
(08.02 MC)
What is the percentage by mass of solution formed by dissolving 27.0 grams of HCl in 102.0 grams of water? (4 points)
а
26.596
D
20.946
с
18.296
d
16.796

Answers

Answer:

20.9%

Explanation:

I took the test i hope this helps:)

The percentage by mass of solution formed by dissolving 27.0 grams of HCl in 102.0 grams of water is 20.93%. This is calculated using the definition (formula) of percentage by mass of a solution.

What is meant by percentage by mass?

The mass percent of a solution is defined as the ratio of the mass of solute that is present in a solution, relative to the mass of the solution, as a whole.

The formula for percentage by mass is given as

percentage by mass = (mass of the solute/ total mass of the compound solution) × 100

Calculating percentage by mass for the given solution:

The mass of the solute ( the chemical which is going to be dissolved) HCl

= 27.0 grams

The mass of the solvent (the substance in which a solute dissolve) water

= 102.0 grams

So, the total mass of the solution = 27.0 + 102.0 = 129.0 grams

Then, the percentage by mass = [tex]\frac{27.0}{129.0}[/tex] × 100 = 20.93%

Which is approximate equal to 20.946 at option B.

Therefore, the percentage by mass of solution formed by dissolving 27.0 grams of HCl in 102.0 grams of water is 20.93%.

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A balloon is inflated to a volume of 8.0 L on a day when the atmospheric pressure is 1.013 bar . The next day, a storm front arrives, and the atmospheric pressure drops to 0.968 bar . Assuming the temperature remains constant, what is the new volume of the balloon, in liters

Answers

Answer:

[tex]V_2=8.4L[/tex]

Explanation:

Hello there!

In this case, according to the definition of the Boyle's law, which describes de pressure-volume behavior as an inversely proportional relationship, it is possible for us to write:

[tex]P_1V_1=P_2V_2[/tex]

Thus, since we are given the initial pressure and temperature, and the final pressure, we are able to calculate the final volume as shown below:

[tex]baV_2=\frac{P_1V_1}{P_2}\\\\V_2=\frac{8.0L*1.013bar}{ 0.968bar}\\\\V_2=8.4L[/tex]

Regards!

How many grams of oxygen are required to burn 3.01 x 10^23 propane molecules?

Answers

That’s some hard stuff what grade are you in im going to find the answer really fast hold on

What does the cell theory state? Answer F All organisms are composed of a nucleus G All prokaryotes are composed of multiple cells H All prokaryotes are single celled organisms J All organisms are composed of cells

Answers

Answer:

(J) All organisms are composed of cells

A student pours 10.0 g of salt into a container of water and observes the amount of time it takes for the salt to dissolve. She then repeats the process using the same amounts of salt and water but this time she slowly stirs the mixture while it is dissolving. The student performs the experiment one more time but this time she stirs the mixture rapidly.

Answers

Answer:

It will go faster each time because she is stirring therefore the water can get to the salt faster than it just sitting at the top

Explanation:

Help plz:)))I’ll mark u Brainliest

Answers

Answer:

[tex]\Delta _{fus}H=205J/g=13.03kJ/mol[/tex]

Explanation:

Hello there!

In this case, since the heat of fusion is a property that allows us to calculate the heat involved during the change from solid to liquid (fusion) and is calculated as shown below:

[tex]Q=m*\Delta _{fus}H[/tex]

In such a way, given the heat involved during this process and the mass of copper, we calculate the heat of fusion as shown below:

[tex]\Delta _{fus}H=\frac{Q}{m}=\frac{41000J}{200.g}\\\\\Delta _{fus}H=205J/g[/tex]

Or in kJ/mol:

[tex]\Delta _{fus}H=205\frac{J}{gCu}*\frac{63.546 gCu}{1molCu}\\\\ \Delta _{fus}H=13026.93J/mol=13.03kJ/mol[/tex]

Regards!

Why is the regression equation not exactly y = 100 • 0.5n?

Answers

Answer:

Radioactive decay is a random event.

Explanation:

on edge

Answer:

Radioactive decay is a random event.

Explanation:

Edge 2020

A common asteroid is in the first photograph. Haley's Comet is in the second photograph. What can be inferred about comets and asteroids? Answer A Both have orbits around the Earth that are ellipses B Both are miniature planets because they orbit the Sun C Both could be planetary fragments from the beginnings of solar system formation D Both are made of rock, ice, and solar dust from the beginning of the solar system

Answers

Answer:

D Both are made of rock ,ice and solar dust from the beginning of the solar system

Answer:

The answer is D

Explanation:

When two substances at room temperature are combined, the product feels HOT. What
kind of reaction is this?

Answers

Answer:

The correct answer is - exothermic reaction.

Explanation:

Exothermic reactions are the reaction that releases energy into the surrounding and does not require energy to take place due to the total energy of the reactants the total energy of the products is more than tthe total energy of the products. It releases energy usually as heat or light with the product.

In the given condition of room temperature mixing two substance produces hot products, fits with the explanation given above, therefore, it is an exothermic reaction.

How many sulphur atoms are there in 0.125 moles of sulphur

Answers

Explanation:

There are 6.022x1023 molecules in 1 mole of SO3 (Avogadro's number) so in 0.25 moles, there are (0.25)(6.022x1023) molecules in the 0.25 moles of SO3. or 1.506x1023 molecules per 0.25 moles of SO3.

There is one atom of sulfur in each molecule of SO3. So there are 1.506x1023 atoms of sulfur in 0.25 moles of SO3.

According to the concept of Avogadro's number there are 0.7525 ×10²³ atoms of sulfur in 0.125 moles of sulfur.

What is Avogadro's number?

Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.

It has a SI unit of reciprocal mole whose numeric value is expressed in reciprocal mole which is a dimensionless number and is called as Avogadro's constant.It relates the volume of a substance with it's average volume occupied by one of it's particles .

According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.

Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number

In the given example, number of atoms of sulfur are calculated as, Avogadro's number×number of moles, that is,6.022×10²³ ×0.125=0.75275×10²³ atoms

Therefore, there are 0.75275×10²³ atoms in 0.125 moles of sulfur.

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There are four stages to the classical demographic transition model Pre-transitional Europe was characterized by high and
fluctuating mortality and a high birth rate. The transition model began to progress into and through stage 2 in the late 18th and early
19th century. All BUT ONE contributed to the decline in mortality.
S- -1]))
A)
Enacting measures to provide clean water supplies.
B)
Public health advances including quarantine of settlements undergoing
epidemics
The development of vaccines to prevent disease and antibiotics to treat
infection.
D)
Widespread acceptance of germ theory resulting in more hygienic
practices, including hand washing and sterilizing medical equipment and
infants' bottles.

Answers

The answer is D! Explaination:

how many molecules in 400g of acetic acid

Answers

Answer:chemical formula of acetic acid is  or

so, molecular mass of acetic acid = 2 × atomic mass of C + 4 × atomic mass of H + 2 × atomic mass of O

= 2 × 12 + 4 × 1 + 2 × 16

= 24 + 4 + 32

= 60g/mol

given mass of acetic acid = 22g

so, no of moles of acetic acid = given mass/molecular mass

= 22/60 ≈ 0.367

so, number of moles of acetic acid is 0.367mol

number of molecules in 0.367 mol of acetic acid = 6.022 × 10²³ × 0.367

= 2.21 × 10²³

Explanation:

Fu/kushima Daiichi nuclear disaster (Research)
1. When and where did this accident happen?
2. Describe the incident and cause.
3. Who was responsible?
4. How many people were injured or died? (short term and long term)
5. How could the accident have been prevented?
6. What chemicals were involved?
7. What are the chemicals physical and chemical properties? (refer to their safety data sheets)
8. What are the chemicals uses, what products are they used in?
9. What health problems did the accident cause?
10. Relate details from the accident to chemistry topics we have covered so far
11. Compare and contrast the safety protocols used at the time of the accident to current safety practices for the same chemical.

Answers

Answer:

I don't know

Explanation:

give me you research

Calculate the volume of solvent present in a 55.5%
by volume of 10.5 mL alcohol solution.

Answers

Answer:

I dont know

Explanation:

good luck

Can someone please solve this question?? Is an element in group 3 likely to bond with an element from group 2?? Explain using the number of balance electrons from each element and the tot number of balance electrons needed to fill an about shell

Answers

Answer:

An atom with one or two valence electrons more than a closed shell The number of valence electrons of an element can be determined Groups 3-12 (transition metals), 2* (The 4s shell is complete and cannot hold any more electrons)  in explaining the molecular structure of many organic compounds.

Explanation:

Inquiry Extension Consider a reaction that occurs between solid potassium and chlorine gas. If you start with an initial mass of 15.20 g K, and an initial mass of 2.830 g Cl2, calculate which reactant is limiting. Explain how to determine how much more of the limiting reactant would be needed to completely consume the excess reactant. Verify your explanation with an example

Answers

The 3.13 g of K would be needed to completely react with the remaining [tex]Cl_2[/tex].

To determine which reactant is limiting, we need to calculate the amount of product that can be formed from each reactant and compare them. The reactant that produces less product is the limiting reactant, since the reaction cannot proceed further once it is consumed.

The balanced chemical equation for the reaction between solid potassium and chlorine gas is:

2 K(s) + [tex]Cl_2[/tex](g) -> 2 KCl(s)

From the equation, we can see that 2 moles of K react with 1 mole of [tex]Cl_2[/tex] to form 2 moles of KCl.

First, we need to convert the masses of K and [tex]Cl_2[/tex] into moles:

moles of K = 15.20 g / 39.10 g/mol = 0.388 mol

moles of [tex]Cl_2[/tex] = 2.830 g / 70.90 g/mol = 0.040 mol

Now, we can use the mole ratio from the balanced equation to calculate the theoretical yield of KCl from each reactant:

Theoretical yield of KCl from K: 0.388 mol K x (2 mol KCl / 2 mol K) = 0.388 mol KCl

Theoretical yield of KCl from [tex]Cl_2[/tex]: 0.040 mol [tex]Cl_2[/tex] x (2 mol KCl / 1 mol [tex]Cl_2[/tex]) = 0.080 mol KCl

We can see that the theoretical yield of KCl from K is 0.388 mol, while the theoretical yield of KCl from [tex]Cl_2[/tex] is 0.080 mol. Therefore, the limiting reactant is [tex]Cl_2[/tex], since it produces less product.

To determine how much more of the limiting reactant would be needed to completely consume the excess reactant, we can use the stoichiometry of the balanced equation.

We know that 1 mole of [tex]Cl_2[/tex] reacts with 2 moles of K to produce 2 moles of KCl. Therefore, the amount of additional K needed to react with the remaining [tex]Cl_2[/tex] can be calculated as follows:

moles of K needed = 0.040 mol [tex]Cl_2[/tex] x (2 mol K / 1 mol [tex]Cl_2[/tex])

                                = 0.080 mol K

This means that 0.080 moles of K would be needed to completely consume the remaining [tex]Cl_2[/tex]. We can convert this to a mass by multiplying by the molar mass of K:

mass of K needed = 0.080 mol K x 39.10 g/mol

                              = 3.13 g K

Therefore, The 3.13 g of K would be needed to completely react with the remaining.

Example verification:

Suppose we had an additional 0.50 g of [tex]Cl_2[/tex] in the reaction. Would all of the K be consumed, or would there still be excess K?

Moles of additional [tex]Cl_2[/tex] = mass of [tex]Cl_2[/tex] / molar mass of [tex]Cl_2[/tex]

Moles of additional [tex]Cl_2[/tex] = 0.50 g / 70.90 g/mol

Moles of additional [tex]Cl_2[/tex] = 0.0070 mol

The theoretical yield of KCl that can be formed from the additional [tex]Cl_2[/tex] is:

0.0070 mol [tex]Cl_2[/tex] x (2 mol KCl / 1 mol [tex]Cl_2[/tex]) x (74.55 g KCl / 1 mol KCl) = 1.04 g KCl

Therefore, the total amount of KCl that can be formed from all of the [tex]Cl_2[/tex] is:

5.95 g + 1.04 g = 6.99 g

The amount of K that would be needed to completely consume all of the [tex]Cl_2[/tex].

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write half-reactions that show how H2O2 can act as either an oxidizing agent or a reducing agent, and describe where each of these situations occurred in your testing.

Answers

Answer:

H2O2 reduces itself to H2O and also oxidizes to O2 simultaneously thereby acting both as an oxidizing and reducing agent .

Explanation:

When

H2O2 acts as an oxidizing agent

H2O2 + 2e- 2H+--->   2H2O

Reducing agent

H2O2 --> O2 + 2e + 2H+

H2O2 reduces itself to H2O and also oxidizes to O2 simultaneously thereby acting both as an oxidizing and reducing agent .

How can heat energy transform from mechanical energy?

A)Burning
B)Friction
C)Light
D)Flames

Answers

Answer:

A

Explanation:

brainliest pls

I think it might be B because the mechanical energy can convert into heat and the heat converts to some mechanical energy. Mechanical is similar to heat. This means that’ one is able to change the internal energy of a system by either physically putting work to the system or adding heat to the system. It seems to me that motion is similar to friction because friction is caused by motion. honestly i’m not sure if this is right but i tried my best. i’m so sorry if i get this wrong


A certain mass of water was heated with 41,840 Joules, raising its temperature from 22.0°C to 28.5 °C. Find the
mass of the water.

Answers

Answer:

1.5 × 10³ g

Explanation:

Step 1: Given and required data

Transferred heat (Q): 41,840 JInitial temperature: 22.0 °CFinal temperature: 28.5 °CSpecific heat capacity of water (c): 4.184 J/g.°C

Step 2: Calculate the temperature change

ΔT = 28.5°C - 22.0 °C = 6.5 °C

Step 3: Calculate the mass (m) of water

We will use the following expression.

Q = c × m × ΔT

m = Q / c × ΔT

m = 41,840 J / (4.184 J/g.°C) × 6.5 °C = 1.5 × 10³ g

An experimental measurement was taken of 10.4mL and the actual measurement was 9.7mL. What is the percent error?

Answers

Answer:

13%

Explanation:

When 12.00 moles of potassium chlorate decomposes, how many dm3 of oxygen are produced at 325K and 188 kPa?
2KClO3 →2KCl + 3O2
show work pls

Answers

Answer:

258.71 dm³

Explanation:

We'll begin by calculating the number of mole of O₂ produced by the decomposition of 12 moles of KClO₃. This can be obtained as follow:

The balanced equation for the reaction is given below:

2KClO₃ —> 2KCl + 3O₂

From the balanced equation above,

2 moles of KClO₃ decomposed to produce 3 moles of O₂.

Therefore, 12 moles of KClO₃ will decompose to produce = (12 × 3)/2 = 18 moles of O₂.

Finally, we shall determine the volume of the O₂. This can be obtained as follow:

Temperature (T) = 325 K

Pressure (P) = 188 KPa

Number of mole (n) = 18 moles

Gas constant (R) = 8.314 KPa.dm³/Kmol

Volume (V) =?

PV = nRT

188 × V = 18 × 8.314 × 325

188 × V = 48636.9

Divide both side by 188

V = 48636.9 / 188

V = 258.71 dm³

Thus, 258.71 dm³ of oxygen were obtained from the reaction.

Which organic compound listed below does not have a carbonyl group ?

A. Aldehyde
B. Ketone
C. Ethers
D. Protein
E. Ester
F. Amides

Answers

I believe the answer is F

A balloon is filled with 3.50 L of water at 24.0°C. What is the volume of the water at 307 K?

Answers

Answer:

what is the volume of the water at 307 k?

What are the missing coefficients for C3H8 + o2 = Co2 +H2O

Answers

Answer: C3H8 + 5O2 = 3Co2 +4H2O

Explanation: Equations must be balanced

You must have the same amount of C

H and O on both sides of the equation

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