Write an equation of the line passing through the points ( -5, -25 ),(0,0), and( 3,15)?




Please help me with this question

Answer:

A. 2086 yd²

Step-by-step explanation:

SA = 2lw + 2wh + 2lh
SA = 2*17*20 + 2*20*19 + 2*17*19
SA = 680 + 760 + 646
SA = 2086
Hope this helps :)

Answer:

(2,11 2/3)  or (2,(35/3))

Step-by-step explanation:

5x-3y=-25

For x = 2:  

5(2)-3y=-25

10-3y=-25

-3y=-35

y = (35/3) or 11 2/3

(2,11 2/3)

Answer:

X = -2

Y= 5

You use:

5x-3(5)=-25

and

5(-2)-3y=-25

Answer:

The last one

Step-by-step explanation:

Look at A and A'

It moved 4 units to the right and 1 unit down

The same with B, B' and C, C'

Answer:

They have more resources and yeah they just do

Step-by-step explanation:

I have no clue why im just guessing

Can you please show me what angle?

The total harvested area is 232 acres .

To determine the number of acres harvested, we simply have to divide the bushels of soybean by the crop yield.

Mathematically we can write it as,

The total land area = bushels of soybean / bushels per acre

Substituting the known values,

[tex]Total land area = 9396 / 40.5 = 232[/tex]

Therefore, 232 acres were harvested.

To learn more about the area visit:

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Answer:The total harvested area is 232 acres

Step-by-step explanation:

Answers:

5.) [tex]\displaystyle \pm{1\frac{2}{3}}[/tex]

4.) [tex]\displaystyle 2[/tex]

3.) [tex]\displaystyle \pm{1\frac{2}{3}}[/tex]

2.) [tex]\displaystyle 2[/tex]

1.) [tex]\displaystyle \pm{2}[/tex]

Step-by-step explanations:

5.) [tex]\displaystyle \frac{\sqrt{75}}{\sqrt{27}} \hookrightarrow \sqrt{2\frac{7}{9}} \hookrightarrow \frac{\pm{5\sqrt{3}}}{\pm{3\sqrt{3}}} \\ \\ \boxed{\pm{1\frac{2}{3}}}[/tex]

4.) [tex]\displaystyle \frac{\sqrt[5]{96}}{\sqrt[5]{3}} \hookrightarrow \sqrt[5]{32} \hookrightarrow \frac{2\sqrt[5]{3}}{\sqrt[5]{3}} \\ \\ \boxed{2}[/tex]

3.) [tex]\displaystyle \frac{\sqrt{125}}{\sqrt{45}} \hookrightarrow \sqrt{2\frac{7}{9}} \hookrightarrow \frac{\pm{5\sqrt{5}}}{\pm{3\sqrt{5}}} \\ \\ \boxed{\pm{1\frac{2}{3}}}[/tex]

2.) [tex]\displaystyle \frac{\sqrt[3]{24}}{\sqrt[3]{3}} \hookrightarrow \sqrt[3]{8} \hookrightarrow \frac{2\sqrt[3]{3}}{\sqrt[3]{3}} \\ \\ \boxed{2}[/tex]

1.) [tex]\displaystyle \frac{\sqrt{8}}{\sqrt{2}} \hookrightarrow \sqrt{4} \hookrightarrow \frac{\pm{2\sqrt{2}}}{\pm{\sqrt{2}}} \\ \\ \boxed{\pm{2}}[/tex]

I am joyous to assist you at any time.

The central angle (127 degrees) is the angle at point K

The measures of JL and JML are 127 and 233 degrees, respectively

From the complete question, we have:

JL = 127 degrees.

The sum of angles at a point is 360 degrees

So, we have:

JML + 127 = 360

Subtract 127 from both sides

JML = 233

Hence, the measures of JL and JML are 127 and 233 degrees, respectively

Read more about circles and arcs at:

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Because we know one point and an axis of symmetry, we know that the point (2, -7) must lie on the graph.

If a function has a line of symmetry at x = x₀, then we know that:

f(x₀ + x) = f(x₀ - x).

So we have symmetry around that line.

Then, if the line of symmetry is at x = 5 and we know that:

f(8) = f(5 + 3) = -7

We also must have:

f(2) = f(5 - 3) = -7

Then the point (2, - 7) must be on the graph.

If you want to learn more about symmetry you can read:

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Answer:

10:48 pm will be your answer

Answer:

Answer is 138

Step-by-step explanation:

I took the test and it was 138

Answer:

19 boxes, but only 18 of them will be completely full

Step-by-step explanation:

Divide 75 by 4 to see how many boxes you can completely fill. You get 18 and 3/4, so there will be 18 boxes of four muffins (completely full), and one box with 3 muffins in it.

Hopefully this helps - let me know if you have any questions!

Explanation:

There are many approaches you can take. Perhaps one of the easiest is to show the sides of the rhombus are all the same length. This can be done several ways. Here are a couple of them.

__

A square has degree 4 rotational symmetry, so will map to itself when rotated by any multiple of 90°. This means the midpoints of adjacent sides will map to themselves, and any segment joining the midpoints of adjacent sides will map to itself. When segments map to themselves, they are congruent, hence the four sides of EFGH are congruent, and the figure is a rhombus.

__

The sides of a square are the same length and all corner angles are right angles. Midpoints of the sides divide the sides into congruent parts, so all of the segments PF, FQ, QG, GR, and so on are congruent. This means all of the triangles PFE, QGF, RHG, and SEH are congruent by the LL postulate. Corresponding sides of congruent triangles are congruent, so the sides of EFGH are congruent, and the figure is a rhombus.

Answer:

please rate and mark as brainlest.

Step-by-step explanation:

(i) 1/20

(ii)

a.708.22

b.8635.4

c.147.392

please rate and mark as brainlest.

Answer:

8 (or 8.4)

Step-by-step explanation:

First, the problem states the words: Distinct and positive.

That means that the smallest number we can use is 0.

We can make 10 blanks for 10 numbers for us to fill in.

_ _ _ _ _ _ _ _ _ _

Since 10 is an even number, and the median is not one single number, it will be the middle of the two numbers.

In this case, our two numbers are the 5th and 6th blank.

Any two numbers can be used, as long as they are the same actual value from 10.

Let us first put in the numbers we can, which are the numbers before the two middle blanks.

0,1,2,3, _ _ _ _ _ _

To find the median between two numbers, we can do:

(a+b) divided by 2 = median

We can use the smallest following number, 4. Then the 6th number will have to be 16 for 10 to be in the middle.

Also try the largest possible number for the 5th blank, 9. Then the 6th number will be 11.

4+16 and 9+11 both equal 20, and 20 divided by 2 is 10. So both of these work.

Now let's place the other numbers in for these two equations.

0,1,2,3,4,16,17,18,19,20

0,1,2,3,9,11,12,13,14,15

If we add the numbers of each together, we get:

0,1,2,3,4,16,17,18,19,20=100

0,1,2,3,9,11,12,13,14,15= 80

If we now divide each sum by 10 (to find the average) we get:

10

8

Since both of these were the most we could go, one with the 5th number as small as possible and one with the 5th number as large as possible.

Since the smaller answer we got was 8, the answer must be 8.

(I believe 0 is a positive integer because it doesn't carry a negative sign. If 0 is not a positive integer, the answer is 8.4. Use the same process

Answer:

The answer is (3).

Step-by-step explanation:

Ron and Harry have ages that are consecutive odd integers. The product of their ages is 783. So, the ron's age r is 27.

A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is  ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.

Ron and harry have ages that are consecutive odd integers. The product of their ages is 783.

r is younger

r + 2 = s

product is 783

783 = rs

s = r +2

783 = r(r+2)

So, the quadratic equation form

783 = r^2 + 2r

0 = r^2 + 2r -783

0 = (r -27)(r +29)

set to zero

r-27 = 0

r = 27

and

r + 29 = 0

r = -29

thus, The age of ron is 27 years old.

Learn more about quadratic equations;

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#SPJ4

Answer:

Add 5 to both sides

Step-by-step explanation:

x-5=16

+5  +5

x=21

Answer:

Addition

Step-by-step explanation:

x - 5 = 16

x - 5 + 5 = 16 + 5

x = 21

The required values are :

[tex]\qquad \sf  \dashrightarrow \:x = 4[/tex]

and

[tex]\qquad \sf  \dashrightarrow \:y = 1[/tex]

Check the attachment for solution ~

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Answer:

A

Step-by-step explanation:

The zeros are the roots or x-intercepts

They are located at coordinate points (0, 0) and (6, 0)

This means the answer is A

Hope it makes sense!

Answer:

A. x = 0 and x = 6

Step-by-step explanation:

So, the zeroes of a quadratic are the parts of it that touch the x-axis. When you find those parts, take their x value and you will get the zero.

So, in this parabola, it touches the x-axis at (0, 0) and (6, 0).

The x-values of these are 0 and 6, respectively.

Answer:

C

Step-by-step explanation:

If we have 5 packages and each contains 80, we are basically doing 80+80+80+80+80 (5 TIMES) which is referred to as 80×5=400

Answer:

1 package contain 80 sheets of paper.

If there is 5 packages, there will be 'x' sheets of paper.

We replace the sheets of paper with 'x', because the value of x is unknown.

Now we set up the equation:

__________   _________ = _________, solve for x;

80/1 = x/5

*5        *5

400 = x

x=37.5

if you need an explanation i can type it in the comments

Answer:

Step-by-step explanation:

2+4(4x49)=4+39(563x7)

2+4x196=4+39x3941

2+784=4+153699

786=153703

This equation is

not possible because

786≠153703

Answer:

To find the surface area of a cuboid, add the areas of all 6 faces.

The approximate decimal value of tan(α) is -3.274, α intersects the unit circle at point (-0.292, 0.956)

A circle is the locus of a point such that its distance from a fixed point (center) is always constant.

A unit circle is a circle with a unit radius.

Given that:

The terminal side of angle α intersects the unit circle at point (-0.292, 0.956).

Hence:

tan(α) = (0.956 / -0.292) = -3.274

The approximate decimal value of tan(α) is -3.274, α intersects the unit circle at point (-0.292, 0.956)

Find out more on unit circle at: https://brainly.com/question/23989157

Answer:

3.75?

Step-by-step explanation:

I dont know if this is what youre looking for but I guess?

Answer:

C: 28 inches

Step-by-step explanation:

Perimeter is when you add the length of each sides together.

Answer:

c

Step-by-step explanation: Because to get the perimeter you need to add all the sides of the figure for example 9+9+5+5=28 :]

Function: y = 5 sin (2(x))+ 12

Find y-intercept:

y = 5 sin 2(0)+ 12

y = 12

​[tex]\sf Y\:Intercepts}:\:\left(0,\:12\right)[/tex]

→ Formula for maximum: M = A + |B|

Maximum:

12 + |5|

17

When y = 17

[tex]\rightarrow \sf 17 = 5 sin (2(x))+ 12[/tex]

[tex]\rightarrow \sf \sf 5 sin (2(x)) = 5[/tex]

[tex]\rightarrow \sf sin (2(x)) = 1[/tex]

[tex]\rightarrow \sf 2x = sin^{-1}(1)[/tex]

[tex]\rightarrow \sf 2x = 90^{\circ \:}, \ \ 450^{\circ \:}[/tex]

[tex]\rightarrow \sf x = 45^{\circ \:}, \ \ 225^{\circ \:}[/tex]

maximum: ( 45° , 17 ), (225° , 17), .....

==========================================================

→  Formula for minimum: m = A ‐ |B|

Minimum:

12 - |5|

7

When y = 7

[tex]\rightarrow \sf 7 = 5 sin (2(x))+ 12[/tex]

[tex]\rightarrow \sf 5 sin (2(x)) = -5[/tex]

[tex]\rightarrow \sf 2(x) = sin^{-1}(-1)[/tex]

[tex]\rightarrow \sf x = -45^{\circ \:} , \ \ 135^{\circ \:}[/tex]

minimum: ( -45°,7), (135°, 7), .....

Repeat the same process for finding more values on the x-axis, or just follow the trend of the curve from the points found and sketch the graph easily.

[tex]\sf Domain\:\left(-\infty \: < x < \infty )[/tex]

[tex]\sf Range : 7\le \:f\left(x\right)\le \:17[/tex]

Sketched below:

Answer:

[tex]\sf \dfrac{x}{8}-22[/tex]

Explanation:

[tex]\rightarrow \sf \left(\dfrac{7}{8}x-4\right)-3\left(\dfrac{1}{4}x+6\right)[/tex]

remove parenthesis

[tex]\sf \rightarrow \dfrac{7}{8}x-4-\dfrac{3x}{4}-18[/tex]

expand

[tex]\rightarrow \sf \dfrac{7x}{8}-\dfrac{3x}{4}-22[/tex]

simplify

[tex]\rightarrow \sf \dfrac{x}{8}-22[/tex]

Answer:

[tex]\frac18x-22[/tex]

Step-by-step explanation:

Given expression:

[tex](\frac78x-4)-3(\frac14x+6)[/tex]

Expand:

[tex]\implies \frac78x-4-\frac34x-18[/tex]

Gather like terms:

[tex]\implies \frac78x-\frac34x-4-18[/tex]

Change 3/4 into eighths:

[tex]\implies \frac78x-\frac68x-4-18[/tex]

Combine like terms:

[tex]\implies \frac18x-22[/tex]