writing equations in slope-intercept form common core algebra 1question 1

Writing Equations In Slope-intercept Form Common Core Algebra 1question 1

Answers

Answer 1

The equation of the line in the slope-intercept form is y = mx + b, where "m" is the slope and "b" is the y-intercept.

"b" is the point (0, yi).

"m" can be found using 2 points P₁ (x₁, y₁) and P₂ (x₂, y₂), according to the formula below:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

So, to solve this question, follow the steps below.

(a) First graph

Step 01: Find the y-intercept and another point in the graph.

To find the points in the graph, choose a x-value and find its corresponding y-value.

Choosing x = 0, y = 2.

P₁ = (0, 2).

Choosing x = -3, y = -2.

P₂ = (-3, -2).

Step 02:


Related Questions

Without needing to graph determined the number of solutions for this system

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Given the system of equations:

[tex]\text{ x + y = 6}[/tex][tex]\text{ y = -x + 6}[/tex]

The two equations appear to be just the same, thus, we are only given one system of equations.

Therefore, the answer is letter B. It has infinite solutions because the two equations are just the same line.

3) There are 24 applicants for three jobs: computer programmer, software tester, and manager. How many ways can this be done?

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this is a combination, so

[tex]24C3=\frac{24\cdot23\cdot22}{3\cdot2\cdot1}=2024[/tex]

answer: 2024 ways

Are the two triangles similar? If so, state the reason and the similarity statement

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Two sides are in same proportion and the included angle is common as per SAS. Therefore, both the triangles are similar.

Triangle:

A triangle is the three-sided polygon, which has three vertices. The three sides are interconnected with each other end to end at a point, which forms the angles of the triangle.

Here there are two triangles KLP and KMN. And the sum of all three angles of the two triangle is equal to 180 degrees.

Given,

Here we have the two triangle and we need to find that they are similar or not.

For that we have to calculate the total length of the sides of the triangle,

That,

KM = KL + LM

KM = 8 + 2 = 10

Similarly,

KN =  KP + PN

KN = 12 + 3 = 15

In triangles KLP & KMN,

KL/KP = 8/12 = 2/3

Similarly, for the triangle KMN,

KM/KN = 2/3

Here the angles have the same values so they are parallel. Which states that, Angle O is common in both the triangles.

Therefore, the two sides are in same proportion and the included angle is common (SAS) . Hence both the triangles are similar.

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Question 19 of 25Which of the following equations is an example of inverse variation betweenthe variables x and y?O A. y -O B. y = 8xO C. y -OD. y=x+8SUBMIT

Answers

Recall: Inverse variation is the relationships between variables that are represented in the form of y = k/x, where x and y are two variables and k is the constant value.[tex]y=\frac{8}{x}[/tex]

Where 8 is the constant

The Final answerOption C

which transformation occurred to create the graph shown below from square root parent function?

Answers

Solution:

Given the function:

[tex]f(x)=\sqrt{x+4}[/tex]

whose graph is shown below:

Suppose that the parent function is expressed as

[tex]f(x)=\sqrt{x}[/tex]

This implies that the parent function is transformed by a horizontal shift to the left by four spaces.

The correct option is

andrew went to the store to buy some walnuts. the price pee walnut is $4 per pound and he has a coupon for $1 off the final amount. with the coupon, how much would andrew have to pay to buy 4 pounds of walnuts? what is the expression for the cost to buy p pounds of walnuts , assuming at least one pound is purchased.

Answers

The amount Andrew have to pay to buy 4 pounds of walnuts = $19

The expression for the cost to buy p pounds of walnuts= 4p - 1

Explanation:

Amount per pound of walnut = $4

Amount of coupon = $1

The cost of 4 pounds of walnuts:

[tex]\text{Cost = 4 }\times5=\text{ \$20}[/tex]

The amount Andrew have to pay to buy 4 pounds of walnuts:

Amount = cost - coupon

Amount = $20 - $1

The amount Andrew have to pay to buy 4 pounds of walnuts = $19

The expression for the cost to buy p pounds of walnuts:

let number of pounds = p

Cost for p pounds of walnut = Amount per walnut * number of walnut

Cost for p pounds of walnut = $4 * p

= $4p

The expression for the cost to buy p pounds of walnuts= cost for p - coupon

= 4p - 1

The number of milligrams D (h) of a certain drug that is in a patients bloodstream h hours after the drug is injected is given by the following function. D (h)=40e ^0.2h When the number of milligrams reaches 9, the drug has to be injected again. How much time is needed between injections? Round your answer to the nearest tenth, and do not round any intermediate computations.

Answers

we need to find the value of h when D is 9, so we need to replace D by 9 and find h:

Converting between metric units of volume and capacityA water tower has a volume of 874 m³.Find how many liters of water it would take to completely fill thewater tower. Use the table of conversion facts, as needed.LXS?Conversion facts for volume and capacity1 cubic centimeter (cm³) = 1 milliliter (mL)1 cubic decimeter (dm³) = 1 liter (L)1 cubic meter (m³) = 1 kiloliter (KL) I need help with this math problem

Answers

Given: A water tower has a volume of 874 m³

To Determine: How many liters of water it would take to completely fill the

water tower

Solution

Please note that 1 cubic meter (m³) = 1 kiloliter (KL)

Therefore

[tex]\begin{gathered} 1m^3=1KL \\ 874m^3=xKL \\ Cross-multiply \\ x=874KL \end{gathered}[/tex]

Also note that Kilo means 1000

Therefore

[tex]\begin{gathered} 874KL=874\times1000L \\ =874000L \end{gathered}[/tex]

Hence, the water tower will be completely fill with 874000 liters(L)

Find the distance between the pair of points. (16,0) and (1, -7) The distance is. (Round to the nearest thousandth as needed.)

Answers

Solution

For this case we can use the formula for the distance between two points:

[tex]d=\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]

and replacing we got:

[tex]d=\sqrt[]{(-7-0)^2+(1-16)^2}=\sqrt[]{274}[/tex]

And the correct answer after round would be:

16.553

Please help me with this problem so my son can better understand I have attached an image of the problem

Answers

We have to solve for c:

[tex](c+9)^2=64[/tex]

When we have quadratic expressions, we have to take into account that each number has two possible square roots: one positive and one negative.

We can see it in this example: the square root of 4 can be 2 or -2. This is beacuse both (-2)² and 2² are equal to 4.

Then, taking that into account, we can solve this expression as:

[tex]\begin{gathered} (c+9)^2=64 \\ c+9=\pm\sqrt[]{64} \\ c+9=\pm8 \end{gathered}[/tex]

We then calculate the first solution for the negative value -8:

[tex]\begin{gathered} c+9=-8 \\ c=-8-9 \\ c=-17 \end{gathered}[/tex]

And the second solution for the positive value 8:

[tex]\begin{gathered} c+9=8 \\ c=8-9 \\ c=-1 \end{gathered}[/tex]

Then, the two solutions are c = -17 and c = -1.

We can check them replacing c with the corresponding values we have found:

[tex]\begin{gathered} (-17+9)^2=64 \\ (-8)^2=64 \\ 64=64 \end{gathered}[/tex][tex]\begin{gathered} (-1+9)^2=64 \\ (8)^2=64 \\ 64=64 \end{gathered}[/tex]

Both solutions check the equality, so they are valid solutions.

Answer: -17 and -1.

In the figure below, BAC~QPR. Use this information and the diagram below to name the corresponding parts of the similar triangles

Answers

a.

∠A is the right angle of the triangle ABC, so the corresponding angle is ∠P, which is the right angle of the triangle PQR.

b.

BC is the hypotenuse of the triangle ABC, so the corresponding side is QR, which is the hypotenuse of the triangle PQR.

c.

∠C is the smaller angle of the triangle ABC, so the corresponding angle is ∠R.

d.

∠Q is the bigger angle of the triangle PQR, so the corresponding angle is ∠B.

e.

PQ is the smaller leg of the triangle PQR, so the corresponding side is AB.

Which of these steps will eliminate a variable in this system?3x-3y=66x+9y=3OA. Multiply the first equation by 3. Then subtract the second equationfrom the first.B. Multiply the first equation by 2. Then add the equations.C. Multiply the first equation by 2. Then subtract the second equationfrom the first.OD. Multiply the second equation by 2. Then subtract the secondequation from the first.

Answers

The given system of equation is:

[tex]\begin{gathered} 3x-3y=6 \\ 6x+9y=3 \end{gathered}[/tex]

Multiply through the first equation by 2:

[tex]\begin{gathered} 6x-6y=12 \\ 6x+9y=3 \end{gathered}[/tex]

Subtract the second equation from the first equation to get:

[tex]-15y=9[/tex]

Therefore, the steps that will eliminate the variable x are:

Multiply the first equation by 2. Then subtract the second equation from the first.

Choice C

Rounded to three decimal places, the value of the irrational number e is .A.3.142B.3.615C.2.718D.2.947

Answers

REQUIRED:

Round to 3 decimal placed the value of the irrational number e.

Step-by-step solution/explanation;

The letter e in mathematics is also known as the Eular's number and is a mathematical constant used in many calculations especially natural logarithms of numbers.

The value of the Eular's number is approximately;

[tex]e\approx2.71828182846...[/tex]

It can continue till infinity, however approximations of this number is always used to avoid unnecessary complications.

Therefore, rounded to 3 decimal places, the value of e is now;

ANSWER:

[tex]e\approx2.718[/tex]

Note that we take 3 digits aftre the decimal and then if the fourth digit after the decimal is 5 or greater than 5, we make it 1 and add that 1 to the third digit after the decimal. Otherwise we simply make it zero and cancel it along with all other digits after it.

The digit that follows 8 (third digit) is less than 5, therefore, we write it off along with all other digits after it, and we are left with the decimal point and then ...718.

Option C is the correct answer.

Write an explicit formula that represents the sequence defined by the following recursive formula: a1=7 and an=2a_n-1

Answers

Answer:

[tex]a_n=7(2^{n-1})[/tex]

Explanation:

Given the sequence with the recursive formula:

[tex]\begin{gathered} a_1=7 \\ a_n=2a_{n-1} \end{gathered}[/tex]

First, we determine the first three terms in the sequence.

[tex]\begin{gathered} a_2=2a_{2-1}=2a_1=2\times7=14 \\ a_3=2a_{3-1}=2a_2=2\times14=28 \end{gathered}[/tex]

Therefore, the first three terms of the sequence are: 7, 14 and 28.

This is a geometric sequence where:

• The first term, a=7

,

• The common ratio, r =14/7 = 2

We use the formula for the nth term of a GP.

[tex]\begin{gathered} a_n=ar^{n-1} \\ a_n=7\times2^{n-1} \end{gathered}[/tex]

The explicit formula for the sequence is:

[tex]a_n=7(2^{n-1})[/tex]

4. Martin was asked to solve the following system of equations. Hegraphed the two equations below, and decided that the answer was"infinitely many solutions". Do you agree with Martin? Why or why not? Ifyou disagree, what should the answer be?*y=-x-3y=-***+3

Answers

Types of solutions in a system of equations:

Based on this image, we can see that when they are parallel lines (same slope), there is no solution because the lines never touch.

The type of solution Martin was describing is when the lines are the same (letter b in the image) and it looks like one line when graphed.

Answer: We disagree with Martin because the lines never touch, meaning that the system has no solutions.

A company has been forced to reduce its number of employees. Today the company has 29% fewer employees than it did a year ago. If there are currently355 employees, how many employees did the company have a year agoemployees?

Answers

to solve this, question, we would have to convert the percentage to fractions or decimals.

Let x represent the numbers of employees the had a year ago

[tex]\begin{gathered} \frac{29}{100}\times x=355 \\ 0.29x=355 \\ \text{divide both sides by the coefficient of x} \\ \frac{0.29x}{0.29}=\frac{355}{0.29} \\ x=1224.127 \\ x\approx1224 \end{gathered}[/tex]

a year ago, the company had 1224 empolyees

The diagonal of a rectangle is 25 inches. The width is 15 inches. What is the area of the rectangle?

Answers

Answer:

300 in²

Step-by-step explanation:

Hello!

Because the diagonal forms right triangles, we can use the Pythagorean Theorem to find the missing length of the rectangle.

a² + b² = c²

a = legb = legc = hypotenuse

In this case, 25 is c, and 15 is a. We can solve for b using the formula.

Solve for ba² + b² = c²15² + b² = 25²225 + b² = 625b² = 400b = 20

So the missing length of the rectangle is 20. We can find the area by multiplying 15 and 20

15 * 20 = A300 = A

The area is 300 in².

Write an equation of the line containing the given point and parallel to the given line.
​(9​,−6​); 4x−3y=2

Answers

Answer:

y=4/3x-18

Step-by-step explanation:

4x-2=3y

y=4/3x-2/3

to parallel slope has to be the same

-6=9*(4/3)+b

b=-18

y=4/3x-18

Frankenstein was in charge of bringing punch to the Halloween party. He brought 36 liters of his famous eyeball punch. How many gallons was this?​

Answers

Answer: 9.5112

Step-by-step explanation:

There are 0.2642 gallons in a liter. So, in 36 liters, there are [tex]36(0.2642)=9.5112 \text{ gal }[/tex]

Jack bought 3 slices of cheese pizza and 4 slices of mushroom pizza fora total cost of $12.50. Grace bought 3 slices of cheese pizza and 2 slices of mushroom pizza for a total cost of $8.50. What is the cost of one slice of mushroom pizza?

Answers

c = price of a slice of Cheese pizza

m= price of a slice of mushroom pizza

Jack bought 3 slices of cheese pizza and 4 slices of mushroom pizza fora total cost of $12.50

3c + 4 m = 12.50

Grace bought 3 slices of cheese pizza and 2 slices of mushroom pizza for a total cost of $8.50.

3c + 2m = 8.50

We have the system of equations:

3c + 4 m = 12.50 (a)

3c + 2m = 8.50 (b)

Subtract (b) to (a) to eliminate c

3c + 4m = 12.50

-

3c + 2m = 8.50

_____________

2m = 4

Solve for m:

m = 4/2

m=2

The cost of one slice of mushroom pizza is $2

Please help me on #1 Please show your work so I can follow and understand

Answers

Answer:

Between markers 3 and 4.

Explanation:

We know that each student runs 2 / 11 miles. Given this, how many miles do the first two students run?

The answer is

[tex]\frac{2}{11}\cdot2=\frac{4}{11}\text{miles}[/tex]

Now, we know that the course has markers every 0.1 miles. How many markers are ther in 4 /11 miles?

The answer is

[tex]\frac{2}{11}\text{miles}\times\frac{1\text{marker}}{0.1\; miles}[/tex][tex]=3.6\text{ markers}[/tex]

This is between markers 3 and 4. Meaning that the second student finishes between markers 3 and 4.

1/2+1/9Please help me

Answers

If the fraction whose denominator are equal then they will add up

In the given fraction 1/2 +1/9, the denominator of both the fraction 1/2 & 1/9 is not same

so, to make the base same we take the LCM of the 2 & 9

[tex]\begin{gathered} \text{LCM of 2 \& 9 is 18} \\ Si,\text{ the fraction will be :} \\ \frac{1}{2}+\frac{1}{9}=\frac{9+2}{18} \\ \frac{1}{2}+\frac{1}{9}=\frac{11}{18} \end{gathered}[/tex]

Answer : 11/18

Question 8 Let h(t) = –1612 +64 + 80 represent the height of an object

Answers

To find the time it takes the object to reach the maximum height we need to remember that this happens in the axis of symmetry of the parabola described by the function:

[tex]h(t)=at^2+bt+c[/tex]

The axis of symmetry is given as:

[tex]t=-\frac{b}{2a}[/tex]

in this case we have that a=-16 and b=64, then we have:

[tex]t=-\frac{64}{2(-16)}=\frac{-64}{-32}=2[/tex]

Therefore it takes 2 seconds to the object to reach its maximum height.

Now, to find the maximum height we plug this value of t in the equation, then we have:

[tex]\begin{gathered} h(2)=-16(2)^2+64(2)+80 \\ =-16(4)+128+80 \\ =-64+128+80 \\ =144 \end{gathered}[/tex]

therefore the maximum height is 144 ft.

cuántos cifras tiene el cociente de 900÷25

Answers

Given the expression

I need help with part b, c ii, and d

Answers

Recall that:

[tex]\text{average speed=}\frac{total\text{ distance}}{total\text{ time}}.[/tex]

(b) Since Marcos traveled for 2 hours and 17 minutes a distance of 155 miles, then Marco's average speed for the 155 miles trip is:

[tex]\frac{155mi}{(2+\frac{17}{60})h}=\frac{155mi}{\frac{137}{60}h}=\frac{9300}{137}miles\text{ per hour}\approx67.89miles\text{ per hour.}[/tex]

(c ii) Since Devon also traveled the 155 miles in 2hours and 17 minutes but at a constant speed, then the constant speed at which he traveled is equal to his average speed, which is equal to:

[tex]\frac{155mi}{(2+\frac{17}{60})h}=\frac{155mi}{\frac{137}{60}h}=\frac{9300}{137}miles\text{ per hour}\approx67.89miles\text{ per hour.}[/tex]

(d) Marco needs to drive 2 miles in 5 minutes to be able to complete the 155 miles trip in 2 hours and 17 minutes, then he must drive at a constant speed of:

[tex]\frac{2mi}{5\min }=\frac{2mi}{\frac{5}{60}h}=\frac{120mi}{5h}=24\text{miles per hour.}[/tex]

Answer:

(b) 67.89 miles per hour.

(c ii) 67.89 miles per hour.

(d) 24 miles per hour.

how do I determine the hypotenuse, opposite, and adjacent angles when I'm only given sides and no angles?​

Answers

[tex]\angle J = 90^{\circ}\\\\\cos (\angle K)=\frac{5}{23} \implies \angle K=\arccos(5/23)\\\\\sin (\angle I)=\frac{5}{23} \implies \angle I=\arcsin(5/23)[/tex]

how do I know where which choices below go into the correct blanks for number 1-4?

Answers

For 1, we have the following triangle:

Using the cosine function to get the hypotenuse we get:

[tex]\begin{gathered} \cos (45)=\frac{7}{h} \\ \Rightarrow h=\frac{7}{\cos(45)}=\frac{7}{\frac{1}{\sqrt[]{2}}}=7\cdot\sqrt[]{2} \\ h=7\cdot\sqrt[]{2} \end{gathered}[/tex]

Now that we have the hypotenuse, we can find the remaining side using the pythagorean theorem:

[tex]\begin{gathered} h^2=7^2+x^2 \\ \Rightarrow x^2=h^2-7^2=(7\cdot\sqrt[]{2})^2-7^2=49\cdot2-49=49 \\ \Rightarrow x^2=49 \\ x=7 \end{gathered}[/tex]

Therefore, the value of the remaining side is 7.

estimate 328 divided by 11=?

Answers

Answer:

30

Step-by-step explanation:

27. Ava surveys teachers for how long it takes them to drive to school eachmorning. She records each response in the dot plot shown.5 10 15 20 25 30 35 40 45 50 55 60Length of Drive (minutes)Ava considers drives of 55 minutes or more as not typical. Given this,which measure of the entire data set represents the most typicaldriving time?meanrangemedianmean absolute deviation

Answers

EXPLANATION

The measure that represent the most typical driving time is the mean.

10 Zara writes a sequence of five numbers. The first number is 2. The last number is 18. Her rule is to add the same amount each time. Write the missing numbers. 2,____ ,_____,______, 18​

Answers

If the first number is 2. The last number is 18. The sequence of five numbers will be 2,6,10,14,18.

What is a sequence?

It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.

Divergent sequences are those in which the terms never stabilize; instead, they constantly increase or decrease as n approaches infinity, approaching either infinity or -infinity.

It is given that, the first number is 2 and the last number is 18,

a = 2

L=18

n=5

a₅=5

a₅=a+(5-1)d

18=2+4d
4d = 18-2

4d = 16

d= 16 / 4

d=4

The terms of the sequence are,

a₁=2

a₂=2+4=6

a₃=6+4=10

a₄=10+4=14

a₅=14+4=18

Thus, if the first number is 2. The last number is 18. The sequence of five numbers will be 2,6,10,14,18.

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