a) Xiao is 13 hours short of his sleep goal for the week.
b) After 4 nights, Xiao is 5 hours short of his sleep goal.
a) Given,Xiao's goal is to get 8 hours of sleep per weeknight, which means he aims to get 40 hours of sleep (8 hours per night x 5 weeknights) during the week. To find the difference between the amount of sleep he got and his goal, we need to calculate the total amount of sleep he got during the week and subtract it from his goal:
Total sleep = [tex]6 \frac{1}{2} + 7 \frac{1}{2} + 5 \frac{3}{4} + 8 \frac{1}{4} = 27[/tex]
Difference from goal = 40 - 27
= 13
Therefore, Xiao is 13 hours short of his sleep goal for the week.
b. After 4 nights, Xiao has slept for a total of:
Total sleep = 27
Since he aims to get 8 hours of sleep per weeknight, he would have gotten a total of 32 hours of sleep (8 hours per night x 4 weeknights) if he had met his goal. To find out how much he is ahead or behind in his sleep goal, we need to calculate the difference between the total amount of sleep he got and his goal:
Difference from goal = 32 - 27 = 5
Therefore, after 4 nights, Xiao is 5 hours short of his sleep goal.
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Solve the following quadratic function by utilizing the square root method.
Answer:
x = ±9
Step-by-step explanation:
If x² = k, then x = ±√k.
x² - 81 = 0
x² = 81
x = ±√81
x = ±9
jason flips a coin three times. what is the probability that the coin will land on the same side in all three tosses?
The probability that the coin will land on the same side in all three tosses is 1/8.
There are two possible outcomes for each coin flip: heads or tails. Therefore, there are 2 × 2 × 2 = 8 possible outcomes for flipping a coin three times in a row.To find the probability that the coin will land on the same side in all three tosses, we need to count the number of outcomes that satisfy this condition.
There are only two such outcomes: either all three tosses are heads or all three tosses are tails. Therefore, the probability of this happening is 2/8 or 1/4.But we are asked for the probability that the coin will land on the same side in all three tosses, not just one specific side.
Therefore, we need to divide our previous result by 2 (the number of sides of the coin) to get the final answer: 1/4 ÷ 2 = 1/8. The probability that the coin will land on the same side in all three tosses is 1/8.
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The speed of the ISS is 27,576 kilometres per hour.
The station travels 42,600 in 1 orbit
Work out the number of full orbits the station does in 1 day.
Answer:
15 Full orbits per day
Step-by-step explanation:
To work out the number of full orbits the ISS does in 1 day, we need to know how long it takes for the ISS to complete one orbit around the Earth.
We can use the information given to us to calculate the time it takes for the ISS to complete one orbit:
Distance traveled in one orbit = 42,600 kilometers
Speed of the ISS = 27,576 kilometers per hour
To calculate the time taken for one orbit:
Time taken = Distance traveled / Speed
Time taken = 42,600 kilometers / 27,576 kilometers per hour
Time taken = 1.54 hours (rounded to 2 decimal places)
So, the ISS takes approximately 1.54 hours to complete one orbit around the Earth.
Now, we can calculate the number of orbits the ISS does in one day:
Number of orbits per day = 24 hours / Time taken for one orbit
Number of orbits per day = 24 hours / 1.54 hours
Number of orbits per day = 15.58 (rounded to 2 decimal places)
Therefore, the ISS completes approximately 15 full orbits around the Earth in one day.
How do I work this out?
a.) The mode for the chart is 24.
b.) The probability that the winning score will be 25 = 7/50
C.)The probability that the winning score will be 23 or more = 37/50.
How to calculate the probability of the selected outcomes?The number of times the game is played = 50 times
The number of games that showed the score of 25= 7
The probability of winning a score of 25 = 7/50
The scores that are 23 and above; 10+14+7+4+2= 37
The probability of winning a score of 23 and above = 37/50
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find the sum for
1 12/15 + 1 5/15
let's firstly convert the mixed fractions to improper fractions and then add them up.
[tex]\stackrel{mixed}{1\frac{12}{15}}\implies \cfrac{1\cdot 15+12}{15}\implies \stackrel{improper}{\cfrac{27}{15}}~\hfill \stackrel{mixed}{1\frac{5}{15}} \implies \cfrac{1\cdot 15+5}{15} \implies \stackrel{improper}{\cfrac{20}{15}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{27}{15}~~ + ~~\cfrac{20}{15}\implies \cfrac{27~~ + ~~20}{\underset{\textit{denominator is the same}}{15}}\implies \cfrac{47}{15}\implies 3\frac{2}{15}[/tex]
the fact that the sample averages are not all the same is an illustration of the concept of , and the fact that the sample averages systematically overestimate the true population average is an illustration of the concept of . group of answer choices
The fact that the sample averages are not all the same can be an illustration of the concept of the central limit theorem, while the fact that the sample averages systematically overestimate the true population average can be an illustration of the concept of bias.
The given statement is incomplete, we need additional information in order to provide a solution. It is important to provide the complete statement so that we can help you in the best way possible.
However, based on the given options, we can provide a general explanation of the concepts mentioned, which are the concepts of the central limit theorem and bias.
The central limit theorem states that the distribution of the sample means approaches a normal distribution as the sample size increases. In other words, as the sample size increases, the means of the samples drawn from a population tend to be normally distributed. The central limit theorem has important implications for statistics and hypothesis testing.
Bias, on the other hand, refers to a systematic error in data collection or analysis. Bias can be caused by a variety of factors, such as the selection of participants or the measurement instruments used. A biased sample or analysis can lead to inaccurate conclusions about a population.
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. a student is calculating the surface area of a single sheet of paper. he measures the length to be he measures the width to be the student should record the area of the paper as (a) 602.64 cm2 . (b) 602.6 cm2 . (c) 602 cm2 . (d) 603 cm2 .
The student should record the area of the paper as option (c) 602 cm^2
The student measured the length and width of a single sheet of paper and was asked to calculate its surface area. The surface area of the paper is the product of its length and width, which can be calculated by multiplying the two measurements together.
The surface area of the paper can be calculated as the product of the length and the width
Surface area = length × width
Substituting the given measurements, we get
Surface area = 43 cm × 14 cm
Surface area = 602 cm^2
Therefore, the correct option is (c) 602 cm^2
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The given question is incomplete, the complete question is;
A student is calculating the surface area of a single sheet of paper. he measures the length to be 43 cm he measures the width to be 14cm the student should record the area of the paper as (a) 602.64 cm^2 . (b) 602.6 cm^2 . (c) 602 cm^2 . (d) 603 cm^2 .
A’(10, 5) is the image of A after a translation along the vector 〈−6, 0〉. What are the coordinates of A?
To perform the opposite translation, we add the opposite of the translation vector to the image point A': the coordinates of point A are (16, 5).
what is a vector?
In mathematics, a vector is an object that represents a quantity having both magnitude (or length) and direction. Vectors can be represented geometrically as arrows, where the length of the arrow represents the magnitude of the vector and the direction of the arrow represents the direction of the vector.
To find the coordinates of point A, we need to perform the opposite translation of moving along the vector 〈−6, 0〉 from the image point A'(10, 5). This is because a translation is a rigid motion that preserves the distance between points, so the distance between A and A' is the same as the distance between their respective translations.
To perform the opposite translation, we add the opposite of the translation vector to the image point A':
A = A' - 〈-6, 0〉 = (10, 5) - (-6, 0) = (16, 5)
Therefore, the coordinates of point A are (16, 5).
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Carla asked students at a lunch table what main course they like. Out of those students,
28 like pizza, 15 like chicken nuggets and 8 like both. What is the probability that a
randomly selected student will like pizza but not chicken nuggets?
A. 4/5
B. 4/7
C. 15/28
D.8/35
Answer:
28/51
Step-by-step explanation:
First you add up all the values: 28 + 15 + 8 = 51. That is your denominator because the total is the denominator. Then you put 28 as your numerator because that's how many off all the people that only like pizza.
A factory produces components of which 1% are defective. The components are
packed in boxes of 10. A box is selected at random
the probability that there are at most 2 defective components in the box is approximately 0.9044 and the probability of having at most 3 defective components out of 250 boxes is very close to zero.
a) Let X be the number of defective components in a box of 10 components. Then X follows a binomial distribution with n=10 and p=0.01, since the probability of a component being defective is 0.01. We want to find the probability that there are at most 2 defective components in the box, i.e., P(X ≤ 2).
Using the binomial probability formula, we get:
P(X ≤ 2) = P(X = 0) + P(X = 1) + P(X = 2)
= (10 choose 0) × 0.01⁰ × 0.99¹⁰ + (10 choose 1) × 0.01¹ × 0.99⁹ + (10 choose 2) × 0.01² × 0.99⁸
= 0.90438222
Therefore, the probability that there are at most 2 defective components in the box is approximately 0.9044 (rounded to four decimal places).
b) We want to find the probability of having at most 3 defective components out of 250 boxes, each containing 10 components. Since np = 100.01 = 0.1 < 5 and n × (1-p)=10 × 0.99=9.9 > 5, we can use the normal approximation to the binomial distribution, with mean μ = np = 2.5 and standard deviation σ = √np(1-p) = 1.577.
Let X be the number of boxes with at most 3 defective components. Then X follows an approximate normal distribution with mean μ' = np=2.5250 = 625 and standard deviation σ' = √np(1-p)) = 12.5 × 1.577 = 19.712.
We want to find P(X ≤ 250), which can be written as P(X < 251) since X is a discrete variable. Using the continuity correction, we can approximate this probability as P(X < 251.5). Then we standardize the variable:
z = (251.5 - μ')/σ' = (251.5 - 625)/19.712 = -18.919
Using a standard normal table or calculator, we find that P(Z < -18.919) is a very small number, practically zero. Therefore, the probability of having at most 3 defective components out of 250 boxes is very close to zero.
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Complete Question
factory produces components of which 1% are defective. The components are packed in boxes of 10. A box is selected by random a) Find the probability that there are at most 2 defective components in the box b) Use a suitable approximation to find the probability of having at most 3 defective (inclusive 3 cases) components out of 250.
please help
At a small animal hospital, there is a 20%
chance that an animal will need to stay
overnight. The hospital only has enough room to
hold animals per night. On a typical day,2 5
animals are brought in.
What is the probability that more than of 2
the animals that are brought in need to
stay overnight?
The prοbability that mοre than 2 animals need tο stay οvernight is apprοximately 0.9124, οr 91.24%.
What is binοmial distributiοn?The binοmial distributiοn is a prοbability distributiοn that describes the number οf successes in a fixed number οf independent trials, each with the same prοbability οf success. The distributiοn is characterized by twο parameters: the number οf trials (n) and the prοbability οf success (p) fοr each trial.
Tο sοlve this prοblem, we need tο use the binοmial distributiοn since we have a fixed number οf trials (25 animals brοught in) and each trial (animal) can either be a success (needs tο stay οvernight) οr a failure (dοesn't need tο stay οvernight).
Let X be the number οf animals that need tο stay οvernight. Then X fοllοws a binοmial distributiοn with n = 25 trials and p = 0.2 prοbability οf success (animal needing tο stay οvernight).
We want tο find the prοbability that mοre than 2 animals need tο stay οvernight, which can be expressed as:
nοw, P(X > 2) = 1 - P(X ≤ 2)
Tο calculate P(X ≤ 2), we can use the binοmial cumulative distributiοn functiοn (CDF) οr simply add up the prοbabilities οf X = 0, X = 1, and X = 2:
similarly, P(X ≤ 2) = P(X = 0) + P(X = 1) + P(X = 2)
[tex]= (0.8)^{25} + 25(0.2)(0.8)^{24} + (25\ \text{choose}\ 2)(0.2)^{2}(0.8)^{23}[/tex]
≈ 0.0876
Therefοre, P(X > 2) = 1 - P(X ≤ 2) ≈ 1 - 0.0876 = 0.9124
Sο the prοbability that mοre than 2 animals need tο stay οvernight is apprοximately 0.9124, οr 91.24%.
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you are placing 11 different pictures on separate pages of a photo album. how many different ways can you order the 11 pictures in the album?
The number of different ways to order 11 different pictures in a photo album is 39,916,800.
To calculate this number, we can use the formula for permutations, which is:
n! / (n - r)!
where n is the total number of items to choose from (in this case, 11 pictures) and r is the number of items to be selected (also 11, since we want to order all the pictures).
Plugging in the values, we get:
11! / (11 - 11)! = 11! / 0! = 11!
We can simplify 11! as:
11! = 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1
Using a calculator or by hand, we can find that 11! equals 39,916,800.
Therefore, there are 39,916,800 different ways to order 11 different pictures in a photo album.
Hence, the number of ways to order 11 pictures in a photo album can be calculated using the permutation formula, which gives a total of 39,916,800 possible arrangements.
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what effect does increasing the sample size, n, have on the center of the sampling distribution of sample means?
Increasing the sample size leads to a more accurate estimation of the population mean.
What is Probability ?
Probability can be defined as ratio of number of favourable outcomes and total number outcomes.
As the sample size, n, increases, the center of the sampling distribution of sample means becomes more precise and closer to the true population mean. This is known as the central limit theorem, which states that as the sample size increases, the distribution of sample means becomes approximately normal with a mean equal to the population mean and a standard deviation equal to the population standard deviation divided by the square root of the sample size.
In other words, as we take larger and larger samples, we are more likely to obtain sample means that are closer to the true population mean. This is because larger samples are less affected by random fluctuations and more likely to provide a representative picture of the population as a whole.
Therefore, increasing the sample size leads to a more accurate estimation of the population mean.
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can someone help me please i don't understand this
The transformation that would not result in a congruent figure when performed on triangle RST is A. A dilation by a scale factor of 2 with respect to point R.
The equation that has the same solution as the system of equations is C. 4x + 9y = 10
4x + 6y = 24.
Which transformations changes congruency ?Transformations that change the shape or size of a figure can change its congruency. A dilation is a transformation that changes the size of a figure so this would mean that RST dilated would not result in a congruent figure.
How to find the equation?When the system of equations, 4x + 9y = 10, 2x + 3y = 12 is solved, we find that x = 13 and y = - 14/ 3.
Options A,B, and D cannot have the same value because the numbers are the same and so they should have different values., Only option C can be the same and when the values are slotted in, this is proven.
Option C, 4x + 9y = 10 , 4x + 6y = 24 is therefore correct.
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a playground 98 ft long and 56 ft wide is to be resurfaced at a cost of $3.75 per sq ft what will the resurfacing cost?
Answer:L x b
98ft x 56ft =5488
=5488 / $3.75= $1463.47
Step-by-step explanation: Play ground is more like a rectangle so we use the formula for the rectrectangle to get total area . A=Lxb
Divide the total with the cost since it say each per sqr feet
A=lxb
98x56=5488
5488/3.75= 1463.47
Write the equation of the line that is parallel to y=- 3/2and passes through
point (2,3).
Answer:
[tex]y-3=-\frac{3}{2}(x-2)[/tex]
Step-by-step explanation:
In order to find an equation that is parallel, it must have the same slope. This means the y intercept could literally be anything.
By equation of the line, we can write it in point slope form
[tex]y-y1=m(x-x1)[/tex]
where y1 and x1 are points on the coordinate plane and m is the slope.
We are already given the slope, so we just plug in the numbers.
[tex]y-3=-\frac{3}{2}(x-2)[/tex]
a dance delegation of 4 people must be chosen from 5 pairs of dance partners. if 2 dance partners can never be together on the delegation, how many different ways are there to form the delegation?
There are 120 different ways to form the dance delegation from five pairs of dance partners if two dance partners can never be together on the delegation.
The total number of ways to form the delegation from five pairs of dance partners can be calculated using the combination formula. The combination formula is used to calculate the number of different combinations of n objects taken r at a time without repetition.
In this question, n is the total number of dance partners (5) and r is the number of people on the delegation (4).
Therefore, the calculation is as follows:
total number of ways = nCr
= 5C4
= 5! / 4!(5-4)!
= 5! / 4!1!
= 5 x 4 x 3 x 2 x 1 / 4 x 1 x 1
= 5 x 4 x 3 x 2
= 120
Hence, there are 120 different ways to form the dance delegation from five pairs of dance partners if two dance partners can never be together on the delegation.
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solve for y: 9=4x+6y
Answer:
[tex]\huge\boxed{\sf y = \frac{9-4x}{6}}[/tex]
Step-by-step explanation:
Given equation:9 = 4x + 6y
Subtract 4x from both sides9 - 4x = 6y
Divide both sides by 6[tex]\displaystyle \frac{9-4x}{6} = y\\\\OR\\\\y = \frac{9-4x}{6} \\\\\rule[225]{225}{2}[/tex]
Answer:
y = (-4x + 9)/6y = (-2x/3) + (3/2)Step-by-step explanation:
Now we have to,
→ Find the required value of y.
The equation is,
→ 9 = 4x + 6y
Then the value of y will be,
→ 9 = 4x + 6y
→ 4x + 6y = 9
→ 6y = 9 - 4x
→ 6y = -4x + 9
→ y = (-4x + 9)/6
→ y = (-4x/6) + (9/6)
→ y = (-2x/3) + (3/2)
Hence, this is the answer.
36. Using the definition in Problem 35, prove that if r1, r2, and r3 are distinct real numbers, then the func- tions e"ıt, eľzt, and eľzt are linearly independent on (-00,00). [Hint: Assume to the contrary that, say, erit: Cje"?! + cze'3' for all t. Divide by e"? to get cze("3=ra) and then differentiate to deduce that eri-ra)t and e("3=r) are linearly depen- (t dent, which is a contradiction. (Why?)] = eri-rot C1 + cze(73–rə) a
To prove that the functions e^(r1*t), e^(r2*t), and e^(r3*t) are linearly independent on (-∞,∞) for distinct real numbers r1, r2, and r3, we will follow the hint provided:
1. Assume to the contrary that e^(r1*t) = C1*e^(r2*t) + C2*e^(r3*t) for all t, where C1 and C2 are constants.
2. Divide both sides of the equation by e^(r1*t) to obtain: 1 = C1*e^((r2-r1)*t) + C2*e^((r3-r1)*t).
3. Differentiate both sides of the equation with respect to t:
0 = C1*(r2-r1)*e^((r2-r1)*t) + C2*(r3-r1)*e^((r3-r1)*t).
4. Now, observe that e^((r2-r1)*t) and e^((r3-r1)*t) are linearly dependent, which is a contradiction, since we know that r1, r2, and r3 are distinct real numbers, and the exponential functions with distinct exponents are linearly independent.Thus, the functions e^(r1*t), e^(r2*t), and e^(r3*t) are linearly independent on (-∞,∞) for distinct real numbers r1, r2, and r3.
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Complete the table below using what you know about trigonometric ratios for right triangles.
Write your ratios as fractions. A message will appear when you are correct.
(a) The ratio of sin A as a fraction is 63/65, cos A is 16/65 and the tan of angle A is 63/16.
(b) The ratio of sin B as a fraction is 16/65, cos B is 63/65 and the tan of angle B is 16/63.
What is the missing part of the right triangle?The missing parts of the right triangle is calculated using the trigonometry principle as shown below.
For angle A:
opposite side = 63
adjacent side = 16
hypothenuse side = 65
sin A = opp/hypo = 63 / 65
cos A = adj/hypo = 16 / 65
tan A = opp/adja = 63/16
For angle B:
opposite side = 16
adjacent side = 63
hypothenuse side = 65
sin B = opp/hypo = 16 / 65
cos B = adj/hypo = 63 / 65
tan A = opp/adja = 16/63
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lisa is on her way home in her car. she has driven 24 miles so far, which is three-fourths of the way home. what is the total length of her drive?
If lisa is on her way home in her car, she has driven 24 miles so far, which is three-fourths of the way home, Lisa's total drive is 32 miles.
Let's represent the total length of Lisa's drive as x. We know that she has driven 24 miles so far, which is three-fourths of the total length. We can write this information as:
24 = (3/4) x
To find x, we need to isolate it on one side of the equation. We can start by multiplying both sides by 4/3 to get rid of the fraction:
24 * (4/3) = x
Simplifying, we get:
32 = x
We can say that Lisa has already driven 24 miles, which is three-fourths of the total distance. To find the total distance, we use the equation 24 = (3/4) x, where x represents the total distance.
To solve for x, we multiply both sides of the equation by 4/3 to cancel out the fraction, giving us 32 = x. Therefore, Lisa's total drive is 32 miles.
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HELP FAST I DONT HAVE TIME ASAP
Answer:772
Step-by-step explanation:
SA=PH+2b
SA=(10+8+10+8)(17)+2(8x10)
SA=772
Answer:
Step-by-step explanatin
multiply all of them
Which statements about this graph are true? Select all that apply.
The graph has a y-intercept at (0, 8).
The graph has a maximum point at (-3, 4).
The graph has an x-intercept at (1,0).
The graph has a line of symmetry at x = -3.
The graph has a minimum value of 4.
The graph has zeros in -5 and -1.
the sum of shannon and john’s ages is 70 shannon is 4 times as old as john
Helppp!!! i’m having a really hard time figuring this out:
Therefore , the solution of the given problem of unitary method comes out to be the composite shape's overall size is 30 square units.
What is a unitary method?Utilizing previously well-known variables, this uniform convenience, or all crucial elements from a prior flexible study that followed a particular methodology event can all be used to achieve the goal. It will be possible to contact the entity again if the anticipated assertion outcome actually happens; if it doesn't, both important systems will surely miss the statement.
Here,
We must divide the composite shape into smaller shapes and sum up their areas in order to determine the area of the composite shape.
We can see that the composite form is made up of a triangle with a base of four and a height of three, and a rectangle with dimensions of six by four.
=> length times breadth equals six by four, or 24 square units, for a rectangle.
Triangle's area is equal to
=> (1/2) x base times height, or (1/2) x 4 times 3, or 6 square units.
As a result, the composite shape's overall size is:
=> 24 + 6 = 30 square units.
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End of unit 4 assessment right triangle trigonometry
End of unit 4 assessment on right triangle trigonometry is an evaluation of a student's understanding of the basic concepts and applications of trigonometry involving right triangles.
This assessment may cover topics such as the trigonometric functions, Pythagorean theorem, special right triangles, and solving right triangles.
Trigonometry is the study of the relationships between the angles and sides of triangles, particularly right triangles. It is a branch of mathematics that has numerous applications in fields such as physics, engineering, and astronomy.
The trigonometric functions are sine, cosine, and tangent, which are ratios of the sides of a right triangle. These functions can be used to solve problems involving angles and sides of right triangles, such as finding the missing side or angle.
The Pythagorean theorem is another fundamental concept in right triangle trigonometry. It states that in a right triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides.
Special right triangles, such as the 30-60-90 triangle and the 45-45-90 triangle, have specific ratios of their side lengths that can be used to solve problems more easily.
Solving right triangles involves finding the measures of all the angles and sides of a right triangle given certain information, such as the length of one side and the measure of one angle.
In conclusion, the end of unit 4 assessment on right triangle trigonometry evaluates a student's understanding of the basic concepts and applications of trigonometry involving right triangles. This assessment is important for students to demonstrate their mastery of the subject and to prepare them for further studies in mathematics and related fields.
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End of unit 4 assessment right triangle trigonometry describe the importance of Side ratios in right triangles as a function of the angles ?
algebra 1a/b opt #1 performance task: task linear regression
Answer:
Step-by-step explanation:
Not sure.
A person runs in a straight line across a field. The velocity of the person, v(t) is a differentiable function and selected values of v(t) are given above on the interval 0
Therefore, the average velocity of the person over the interval 0 ≤ t ≤ 12 can be calculated as follows:Average Velocity = Total distance travelled / Total time taken= 6.6 / 12= 0.55 m/s.
In the given question, we need to find the average velocity of a person running in a straight line across a field, given differentiable function v(t) on the interval [0,12]. Therefore, to calculate the average velocity of a person, we use the following formula:Average Velocity = Total distance travelled / Total time takenWe have a graph with the velocity of the person, which is a differentiable function v(t) given above on the interval 0 ≤ t ≤ 12.
We need to find the distance travelled by the person. Therefore, we use the following formula:Distance travelled = ∫v(t)dt From the given graph, the velocity of the person is zero when t = 0 and when t = 5. Similarly, the velocity of the person is 0 when t = 10 and when t = 12.So, we have to calculate the distance travelled from 0 to 5, from 5 to 10, and from 10 to 12 to determine the total distance travelled by the person over the given interval .Distance travelled from 0 to 5 can be calculated as follows :
Distance travelled from 0 to 5 = ∫v(t)dt from [tex]0 to 5= 5 x 0.6 = 3[/tex]Distance travelled from 5 to 10 can be calculated as follows :Distance travelled from 5 to 10 = [tex]∫v(t)dt[/tex] from [tex]5 to 10= 5 x 0.4 = 2[/tex]
Distance travelled from 10 to 12 can be calculated as follows: Distance travelled from 10 to 12 = ∫v(t)dt from 10 to 12= 2 x 0.8 = 1.6Total distance travelled = Distance travelled from 0 to 5 + Distance travelled from 5 to 10 + Distance travelled from 10 to [tex]12= 3 + 2 + 1.6= 6.6[/tex]
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draw a quadratic function that only has one root at 3
The quadratic function that only has one root at 3 and passes through the point (0,4) is: f(x) = (4/9)(x - 3)^2
What is quadratic equation?A quadratic equation is a polynomial equation of degree 2, meaning that the highest exponent of the variable is 2. It has the general form:
ax^2 + bx + c = 0
If a quadratic function has only one root at 3, then it must be of the form:
f(x) = a(x - 3)^2
where a is a constant. This is because a quadratic function with only one root must have a double root, meaning that the parabola only touches the x-axis at that point and does not cross it. And a quadratic function with vertex at (3,0) and opening upwards satisfies this condition.
To determine the value of a, we can use any additional information that may be provided, such as the value of the function at another point. For example, if we know that f(0) = 4, then we can substitute these values into the equation to get:
4 = a(0 - 3)^2
4 = 9a
a = 4/9
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The quadratic function that has only one root at 3 and passes through (0,4) is: [tex]f(x)=(\frac{4}{9} )(x-3)^{2}[/tex]
Why is it called a quadratic equation?A quadratic equation is a second-degree algebraic problem in x. In its standard form, the quadratic equation is [tex]ax^2+bx+c=0[/tex], where an as well as b are the coefficients, x is the variable, and c is the value of the constant component. The essential requirement for a formula to be a quadratic equation is that the coefficient of [tex]x^2[/tex] is not zero (a 0). When writing an equation with quadratic equations in conventional format, the [tex]x^2[/tex] term comes first, then the x term, and lastly the constant term.
A quadratic equation is a polynomial expression of degree 2, which means that the variable's greatest exponent is 2. It takes the following basic form:
[tex]ax^2+bx+c=0[/tex]
If the quadratic function has only one root at 3, it must have the following form:
[tex]f(x)=a(x-3)^2[/tex]
This requirement is satisfied by a quadratic function with a vertex at (3,0) and an opening upwards.
We know that f(0) = 4, so we can plug these numbers into the equation to get:
[tex]4=a(0-3)^2[/tex]
simplify the above equation
4 = 9a
The value is,
a = 4/9
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based on the boxplot, about 25% of these ayrshire cattle had a butterfat percentage that was higher than what value ?
Based on the boxplot, approximately 25% of these Ayrshire cattle had a butterfat percentage higher than 8.3%.
To determine this, we can look at the boxplot and see that the third quartile (Q3) is at 8.3%. Since 25% of the data is greater than 8.3%, we can infer that 25% of these Ayrshire cattle had a butterfat percentage higher than 8.3%. To further explain, a boxplot is a graphical representation of the five-number summary of a dataset, which consists of the minimum, first quartile (Q1), median (Q2), third quartile (Q3), and maximum.
The boxplot is divided into two parts, the box and the whiskers. The box indicates the interquartile range (IQR) which is the difference between the third and first quartile. The whiskers represent the minimum and maximum of the dataset. The median is shown by a line within the box. In this boxplot, the first quartile (Q1) is 6.7%, the median (Q2) is 7.4%, and the third quartile (Q3) is 8.3%. Therefore, based on the boxplot, about 25% of these Ayrshire cattle had a butterfat percentage that was higher than 8.3%.
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Complete Question : Based on the boxplot, about 25% of these ayrshire cattle had a butterfat percentage that was higher than?