y=- 8x - 20
How do I graph this

Answer:

26.8

Step-by-step explanation:

Because 33.5 was the average of how many students were in a classroom (if there were 4 classrooms), then 33.5 is can somewhat be the average of how many students were in one classroom; 1/4 of the classrooms can hold an average of 33.5.

Total students that were divided into 4 classrooms :

33.5 × 4 = 134

So if there is 134 students that will be grouped into 5 different classrooms, divide 134 by 5 to find the average amount of students that will be grouped.

134 ÷ 5 = 26.8

So, the average amount of students that will be grouped if they were divided into 5 classrooms would be 26.8 .

Hope this helped !

The figure 1 can be transformed to create figure 2 by reflecting across the y axis.

Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, translation, reflection and dilation.

The figure 1 can be transformed to create figure 2 by reflecting across the y axis.

Find out more on transformation at: https://brainly.com/question/1462871

For zeroes i.e for value(s) of q and s, the given equations must be equal to 0, so let's start with first equation and then 2nd equation ;

[tex]{:\implies \quad \sf 6q^{2}-17q+12=0}[/tex]

[tex]{:\implies \quad \sf 6q^{2}-9q-8q+12=0}[/tex]

[tex]{:\implies \quad \sf 3q(2q-3)-4(2q-3)=0}[/tex]

[tex]{:\implies \quad \sf (3q-4)(2q-3)=0}[/tex]

[tex]{:\implies \quad \sf Either\:\:3q-4=0\:\:\:or\:\:\: 2q-3=0}[/tex]

[tex]{:\implies \quad \sf Either\:\:3q=4\:\:\:or\:\:\:2q=3}[/tex]

[tex]{:\implies \quad \bf q=\dfrac{3}{2},\dfrac43}[/tex]

Now, turning to the second equation ;

[tex]{:\implies \quad \sf 8s^{2}+2s-15=0}[/tex]

[tex]{:\implies \quad \sf 8s^{2}+12s-10s-15=0}[/tex]

[tex]{:\implies \quad \sf 4s(2s+3)-5(2s+3)=0}[/tex]

[tex]{:\implies \quad \sf (4s-5)(2s+3)=0}[/tex]

[tex]{:\implies \quad \sf Either\:\:4s-5=0\:\:\:or\:\:\: 2s+3=0}[/tex]

[tex]{:\implies \quad \sf Either\:\:4s=5\:\:\:or\:\:\:2s=-3}[/tex]

[tex]{:\implies \quad \bf s=\dfrac{5}{4},-\dfrac32}[/tex]

Answer:

Below in bold.

Step-by-step explanation:

I am assuming you want to factor these expressions.

6q^2 - 17q + 12

We need 2 numbers whose product is (6*12) = 72 and whose sum is -17.

Theses are -9 and -8 so we write:

= 6q^2 - 9q - 8q + 12

= 3q(2q - 3) - 4(2q - 3)

= (3q - 4)(2q - 3)

If you want the solution of this expression = zero they are q = 4/3, 3/2.

8s^2 + 2s - 15

8 * -15 = -120.   -120 = -2 * 2 * 2 * 3 * 5 = +12 * -10 ( to give the +2s)

= 8s^2 + 12s - 10s - 15

= 4s(2s + 3) - 5(2s + 3)

= (4s - 5)(2s + 3)

If you want the solution of this expression = zero they are s = 5/4, -3/2.

Answer:

There are 160 books in this section of the library

Step-by-step explanation:

to solve this problem you need to set up a ratio.

since there are 7 times Malay books the number of Tamil books, you can say that

x = # of Tamil books

7x = # of Malay books

next, you know that there are 56 Malay books so you can substitute.

7x = 56

x = 56/7

x = 8

x = # of Tamil books

8 = # of Tamil books

now you know that there are 56 Malay books and 8 Tamil books. Chinese books make up 6/10 of the library so the other languages must add up to 4/10 of the books.

56 + 8 = 4/10 of the total books

64 = 4/10 of total books

if you call the total books T you can make this equation:

64 = 4/10T

64 * 10/4 = T

160 = T

Answer:

a₁₂ = - 4194304

Step-by-step explanation:

the nth term of a geometric sequence is

[tex]a_{n}[/tex] = a₁ [tex](r)^{n-1}[/tex]

where a₁ is the first term and r the common ratio

here a₁ = 1 and r = [tex]\frac{-4}{1}[/tex] = - 4 , then

a₁₂ = 1 × [tex](-4)^{11}[/tex] = - 4194304

Answer:320 cubic cm

Step-by-step explanation:  if you  multiply 16x20m  you get 320  cm

Answer:

4x2=8

Step-by-step explanation:

This equation is simple and easy cause its base sick math

To attempt this algebraic equation we will be multiplying 4 to (3 - x) bracket so as to form the term on L.H.S.

[tex]:\implies\tt{4(3 - x) = (1 - 2x)}[/tex]

[tex]:\implies\tt{(12 - 4x) = (1 - 2x)}[/tex]

[tex]:\implies\tt{12 - 4x = 1 - 2x}[/tex]

Combining like terms, we get,

[tex]:\implies\tt{12 - 1 = - 2x + 4x}[/tex]

[tex]:\implies\tt{11 = 2x}[/tex]

[tex]:\implies\tt{2x = 11}[/tex]

[tex]:\implies\tt{x = \frac{11}{2} }[/tex]

[tex]:\implies\tt{x = 5.5}[/tex]

Hey there!

4(3 - x) = (1 - 2x)

4(3) + 4(-x) = 1 - 2x

12 - 4x = 1 - 2x

-4x + 12 = -2x + 1

ADD 2x to BOTH SIDES

-4x + 12 + 2x = -2x + 1 + 2x

SIMPLIFY IT!

-2x + 12 = 1

SUBTRACT 12 to BOTH SIDES

-2x + 12 - 12 = 1 - 12

SIMPLIFY IT!
-2x = -11

DIVIDE -2 to BOTH SIDES

-2x/-2 = -11/-2

SIMPLIFY IT!
x = 11/2

Therefore, your answer should be:

x = 11/2

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Answer:

The answer to your problem is x=-1,y=9

Step-by-step explanation:

(-1,9)

Answer:

B and B

Step-by-step explanation:

For the first problem, the range is simply the data set rearranged from smallest to largest.

For the second problem, you just have to cross multiply each variable in order to expand the equation and get an answer.

The answer for that one is [tex]12x^{3} -42x^{2} +8x+55[/tex]

Answer:

top:32

bottom:73.5

Step-by-step explanation:

no need to rate or give brainlyest just wanted to help

there you goo :)) on the chain up on the left from 3 to 48 they keep multiplying by 2, and the other one, they keep subtracting by 7

Answer:  called tthe term of an algebraic expression.

Examples of algebraic expressions and their terms:

(i)  x + 10

We observe that the number of terms used in the expression x + 10 is 2. The terms are x and 10.

(ii)  5m + 2n - 7

We observe that the number of terms used in the expression 5m + 2n – 7 is 3. The terms are 5m, 2n and 7.

(iii)  3a/b

We observe that the number of term used in the expression 3a/b is 1. The term is 3a/b.

(iv) 3xy + 7xz + 2yz - 6

We observe that the number of terms used in the expression 3xy + 7xz + 2yz - 6 is 4. The terms are 3xy, 7xz, 2yz and 6.

)  2abc + 1

We observe that the number of terms used in the expression 2abc + 1 is 2. The terms are 2abc and 1.

Therefore, the algebraic expressions are either simple or compound.

(i) Simple algebraic expressions consist of one term.

(ii) Compound algebraic expressions consist of two or more terms.

Answer:

yes you are correct

Step-by-step explanation:

not sure what you mean but yea

Answer:

Yes

Step-by-step explanation:

To answer this question, we will need to know how many millimeters are in a kilometer.

1 km = 1,000,000 mm

Therefore, 6km is WAY bigger than 54,000 mm

Answer:

54cm²

Step-by-step explanation:

2(3x6) + 2(6x1) + 2(3x1)

= 54cm²

Answer:

man it’s one in the morning and your picture is blurry a f

Step-by-step explanation:

Answer:

x - 7 [tex]\leq[/tex] -28

Step-by-step explanation:

I guarantee you that this is correct. It's pretty simple to understand.

Please mark Brainliest. :)

Answer:

[tex]\boxed{\sf{x=7 \quad y=2}}[/tex]

Step-by-step explanation:

To solve this problem, isolate it on one side of the equation.

x-3y=1: x=1+3y

x=1+3y

Substitute.

x=1+3y= 3(1+3y)-5y=11

Solve.

3+4y=11

Subtract by 3 from both sides.

3+4y-3=11-3

Solve.

11-3=8

Rewrite the problem down.

4y=8

Divide by 4 from both sides.

4y/4=8/4

Solve.

8/4=2

y=2

x=1+3y

x=1+3*2

Solve.

PEMDAS stands for:

1+3*2

Multiply.

3*2=6

Add.

1+6=7

x=7

I hope this helps you! Let me know if my answer is wrong or not.

Answer:

53°

Step-by-step explanation:

The value of the z statistic for the considered data is given by: Option A: -3.87 approximately.

If we're given that:

Then, we get:

[tex]z = \dfrac{\overline{x} - \mu}{s}[/tex]

If the sample standard deviation is not  given, then we can estimate it(in some cases) by:

[tex]s = \dfrac{\sigma}{\sqrt{n}}[/tex]

where [tex]\sigma[/tex]population standard deviation

For this case, we're specified that:

Thus, the value of the z-statistic is evaluated as:

[tex]z = \dfrac{\overline{x} - \mu}{\sigma/\sqrt{n}} = \dfrac{2.3- 2.7}{0.4/\sqrt{15}} \approx -3.87[/tex]

Thus, the value of the z statistic for the considered data is given by: Option A: -3.87 approximately.

Learn more about z statistic here:

https://brainly.com/question/27003351

The required equation f(10) = 13.52 mg remains.

We have given that ,

m is the initial mass and h is the half-life in years. cobalt-60 has a half-life of about 5.3 years. which equation gives the mass of a 50 mg cobalt-60

The amount of a radioactive substance remaining after t years is given by the function  

[tex]f(t)=m(0.5)^{t/h}[/tex]............ (1),

where m = initial mass and h= half-life in years.

Now, for Cobalt-60, h = 5.3 years, m = 50 mg and t = 10 years,

then from equation (1) we get,

[tex]f(10)=50(0.5)^{10/5.3}[/tex]

Therefore  the required equation  f(10) = 13.52 mg .

To learn more about the mass of radioactive substance visit:

https://brainly.com/question/25793075

Answer:

The required equation f(10) = 13.52 mg remains.

We have given that ,

m is the initial mass and h is the half-life in years. cobalt-60 has a half-life of about 5.3 years. which equation gives the mass of a 50 mg cobalt-60

What is the fromula for he amount of a radioactive substance remaining after t years?

The amount of a radioactive substance remaining after t years is given by the function  

............ (1),

where m = initial mass and h= half-life in years.

Now, for Cobalt-60, h = 5.3 years, m = 50 mg and t = 10 years,

then from equation (1) we get,

Therefore  the required equation  f(10) = 13.52 mg .

To learn more about the mass of radioactive substance visit:

brainly.com/question/25793075

Answer: Deshi will have 302 marbles  and Elaheh will have 519.

Step-by-step explanation:

Deshi's Marbles will subtract 125.

427 - 125 = 302.

Elaheh's Marbles will add 125.

394 + 125= 519.

Answer: Angle 3

Step-by-step explanation:

Answer:

60.61

Step-by-step explanation:

the missing angle is 51 degrees

we can say sin74/x = sin51 / 49

now we just solve for x.

x = 60.61

Answer:

I think your adopted and nobody loves you

Step-by-step explanation:

Answer:

right... C.

Step-by-step explanation:

Answer:

3. Not linear

4. Linear

Step-by-step explanation:

3. The equation has an exponent on the x. Since x is squared the graph is a parabola. The graph is a curve, not a line, so it is not linear.

4. Both the x and y have no exponent (which is an exponent of 1) The graph will be a line. This is a linear function.

Answer:

Area of the rectangle = 20 square units

Area of left triangle = 8 square units

Area of right triangle = 6 square units

Area of whole figure = 34 square units

Step-by-step explanation:

Alright, area of a rectangle is Base · Height. The base of the rectangle is 5 units and the height is 4 units. 5 · 4 = 20 square units.

Area of a triangle is (Base · Height)/2. The triangle on the left is 4 units tall and 4 units wide. 4 · 4 ÷ 2 = 8 square units.

The triangle on the right is 4 units tall and 3 units wide. 4 · 3 ÷ 2 = 6 square units.

To get the area of the whole figure, you can just add the area of all three shapes. 20 + 8 + 6 = 34 square units.

Hope this helps! :)

Answer:

Rectangle's area;

Length: 4

Width: 5

Formula for area of rectangle;

A = L*W

Replace values:-

A = 4(5)

A = 20.

Left triangle's area;

Base = 4

Height: 4

Formula for area of triangle;

A = BH x 1/2

Replace values:-

A = 4(4) x 1/2

A = 16 x 1/2

A = 16/2

A = 8.

Right triangle's area;

Base = 3

Height: 4

Formula for area of triangle:

A = BH x 1/2

Replace values:-

A = 3(4) x 1/2

A = 12 x 1/2

A = 12/2

A = 6.

Add all the areas we've found so far to get the figure's total area:

20 + 8 + 6

= 34.