A hollow ball is made of rubber that is 2 centimeters thick. The ball has a radius to the outside surface of 6 centimeters.

What is the approximate volume of rubber used to make the ball?

Use 3.14 for pi.

Responses

33.5 cm³
33.5 cm³

267.9 cm³
267.9 cm³

636.4 cm³
636.4 cm³

904.3 cm³

Answers

Answer 1

Answer:

636.4 cm³

Step-by-step explanation:

Answer 2
636.4 to the third power

Related Questions

How do you simplify rational expressions

Answers

Answer:

Ok so,

Step-by-step explanation:

Step 1: Factor the numerator and the denominator.

Step 2: List restricted values.

Step 3: Cancel common factors.

Step 4: Reduce to lowest terms and note any restricted values not implied by the expression.

Can someone please help me

Answers

Rate of change= (y2-y1)/(x2-x1), in this case the rate of change is 2
2

the formula for rate of change is
(Y2 - Y1)/(X2-X1).

Plug in any 2 random coordinates.

(6-4)/(5-4)

2/1

2

Find the volume of the pyramid. Round to the nearest tenth if necessary.

Answers

Answer:

410.6 cubic cm

Step-by-step explanation:

Formula V = (l x w x h) / 3

        V =       ( 8 x 14 x 11) / 3

        V =   1232 / 3

        V = 410.6 cubic cm

can someone pls help

Answers

Step-by-step explanation:

A triangle has its interior angle sum as 180°

[tex]{ \tt{ \angle R + \angle S + \angle T = 180 \degree}}[/tex]

[tex]{ \colorbox{silver}{input \: angles}} \\ \\ { \tt{31 \degree + (x + 4) \degree + (3x + 9) \degree = 180 \degree}} \\ \\ { \tt{44 + 4x = 180 \degree}} \\ \\ { \tt{4x = 136}} \\ \\ { \tt{x = 34}} \\ \\ { \colorbox{silver}{for \:R }} \\ \\ { \tt{ m\angle S =x + 4 = 34 + 4}} \\ \\ { \boxed{ \tt{m \angle S = 38 \degree}}} \\ \\ { \colorbox{silver}{for \:T }} \\ \\ { \tt{m \angle T = 3x + 9 = (3 \times 34) + 9}} \\ \\ { \tt{m \angle T = 111 \degree}}[/tex]

(show work pls and ty)

Answers

1. Find the constant of proportionality (K).

K=2.5 because 5 divided by 2 is 2.5. You can even check this by dividing 12.5 by 5 and still get 2.5

2. Write the proportional equation using the table below.

(1 bottle =2.5 liters)
6 bottles X 2.5 liters

3. How many liters of soda can 6 bottles hold?

6 bottles = 15 liters

Answer: 15

Find the volume of the triangular prism; do not round.

Answers

Answer:

[tex]\boxed{\mathtt{Volume=33.55m^{3}}}[/tex]

Step-by-step explanation:

[tex]\textsf{For this problem, we are asked to find the Volume of a Triangular Prism.}[/tex]

[tex]\large\underline{\textsf{What is Volume?}}[/tex]

[tex]\textsf{Volume is the amount of space a figure occupies. Volume is measured in Cubic units.}[/tex]

[tex]\large\underline{\textsf{We are Given;}}[/tex]

[tex]\textsf{The Height is 6.1m. Keep in mind that the Height is the Perpendicular Distance}[/tex]

[tex]\textsf{between 2 bases.}[/tex]

[tex]\textsf{The base is; (4.4 x 2.5).}[/tex]

[tex]\textsf{The Height of the Triangle is 2.5m.}[/tex]

[tex]\large\underline{\textsf{Necessary Formulas;}}[/tex]

[tex]\mathtt{Volume=(Base) \times Height}[/tex]

[tex]\mathtt{Area = \frac{1}{2} (Base \times Height)}[/tex]

[tex]\large\underline{\textsf{For this Problem;}}[/tex]

[tex]\mathtt{Volume=(Triangles' \ Area) \times Height}[/tex]

[tex]\large\underline{\textsf{The area of a Triangle is;}}[/tex]

[tex]\mathtt{Area = \frac{1}{2} (Base \times Height)}[/tex]

[tex]\textsf{Find the area of the base first.}[/tex]

[tex]\large\underline{\textsf{Substitute;}}[/tex]

[tex]\mathtt{Area = \frac{1}{2} (4.4 \times 2.5)}[/tex]

[tex]\boxed{\mathtt{Area = 5.5m^{2}.}}[/tex]

[tex]\textsf{We know the Base, now let's find the volume of the figure.}[/tex]

[tex]\large\underline{\textsf{Substitute;}}[/tex]

[tex]\mathtt{Volume=5.5 \times 6.1}[/tex]

[tex]\boxed{\mathtt{Volume=33.55m^{3}}}[/tex]

[tex]\huge\text{Hey there!}[/tex]


[tex]\huge\textsf{Find the \boxed{\bf volume} of a triangular prism is:}[/tex]

[tex]\mathsf{\dfrac{1}{2}(\boxed{\bf b}ase\times\boxed{\bf h}eight\times\boxed{\bf l}ength) = \boxed{\bf v}olume}[/tex]


[tex]\huge\textsf{Your \boxed{\bf equation} should look like:}[/tex]

[tex]\mathsf{volume = \dfrac{1}{2}(4.4\ m \times 2.5\ m\times 6.1\ m)}[/tex]


[tex]\huge\textsf{\boxed{\bf Step-by-step} explanation can be:}[/tex]

[tex]\mathsf{volume = \dfrac{1}{2}(4.4\ m \times 2.5\ m\times 6.1\ m)}[/tex]

[tex]\mathsf{volume = \dfrac{1}{2}\times 4.4\ m \times 2.5\ m\times 6.1\ m}[/tex]

[tex]\mathsf{volume = 0.5\times 4.4\ m \times 2.5\ m\times 6.1\ m}[/tex]

[tex]\mathsf{volume = 2.2\ m\times 15.25\ m}[/tex]

[tex]\mathsf{volume = 33.55}[/tex]


[tex]\huge\textsf{Therefore your \boxed{\bf answer} should be:}[/tex]

[tex]\huge\boxed{\mathsf{volume = 33.55m^2}}\huge\checkmark[/tex]


[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]



~[tex]\frak{Amphitrite1040:)}[/tex]

100 POINTS HELP PLEASE IM DESPERATE !!!!!!!!!!!!!!!!!!!!

If AB¯¯¯¯¯¯¯¯
is translated right 5
units and down 2
units, what are the coordinates of A′,
the image of point A?

Line Segment A B with coordinates A negative 5, 2 & B negative 2, 6.

Answers

So basically you gotta go uo down left right up up down agian that ur answer
The coordinates for A’ would be (0,0)

Choose ALL correct answers.
Which of the following tables are non-linear?

Answers

Answer: the tables that are non-linear would be A, B, and F i’m pretty sure.

could someone help me? Please.

Answers

An equation that could be used to determine the number of books that Keiko bought include the following: B. 4b - 5 = 71.

The number of books is equal to 19 books.

How to write an equation to model this situation?

In order to write a linear equation to describe this situation, we would assign a variable to the number of books, and then translate the word problem into a linear equation as follows:

Let the variable b represent the number of books.

Since Keiko bought some books for $4 and received a discount of $5 off of her total purchase, a linear equation that models the situation is given by this mathematical expression:

4b - 5 = 71

Next, we would calculate the number of books (b) as follows;

4b - 5 = 71

4b = 71 + 5

4b = 76

b = 76/4

b = 19 books.

Read more on equation here: brainly.com/question/18912929

#SPJ1

Calculate the volume of a cone with a height of 6 inches and a diameter of 6 inches.
Leave your answer in terms of PI

Answers

Answer: Volume ≈ 56.55

Step-by-step explanation:

56.54867 is the answer, but I rounded it. I hope this helped! :)

Answer:

18π cubic inches

Step-by-step explanation:

First, we need to find the radius of the cone, which is half of the diameter.

radius = diameter/2 = 6/2 = 3 inches

The formula for the volume of a cone is:

V = 1/3 × π × r^2 × h

where r is the radius of the base of the cone, and h is the height of the cone.

Substituting the values we get:

V = 1/3 × π × 3^2 × 6

V = 1/3 × π × 9 × 6

V = π × 18

1.) 25 - 3x = 88
2.) -11 = 7 - x
3.) 95 = -4 + 33x​

Answers

Answer: hope this helps ♡

1.) x = -21

2.) x = 18

3.) x = 3

Step-by-step explanation:

(minus&minus = plus)       (minus&plus = minus)        (plus&minus = minus)

1.) 25 - 3x = 88

25 - 25 - 3x = 88 - 25

-3x = 63

-3x ÷ 3 = 63 ÷ 3

-x = 21 → x = -21

2.) -11 = 7 - x

-11 - 7 = 7 -7 -x

-18 = -x

18 = x → x = 18

3.) 95 = -4 + 33x​

95 + 4 = -4 + 4 + 33x

99 = 33x

99 ÷ 33 = 33x ÷ 33

3 = x → x = 3

[tex] \text{1 ] 25 - 3x = 88 }[/tex]

[tex] \rm{↣25 - 3x = 88} \\ \rm↣- 3x= 88 - 25 \\ \rm↣- 3x = 63 \\ \rm↣x = \cancel \frac{63}{ - 3} \\ \underline{ \underline{\rm ↣\purple{ \: x = -21 \: }}}[/tex]

[tex] \: [/tex]

_________

[tex] \text{2 ] -11 = 7 - x }[/tex]

[tex] \rm \: ↣-11 = 7 - x \\ \rm↣ -11 - 7 = -x \\ \rm↣ \cancel- 18 = \cancel -x\\\underline{ \underline{ \rm↣ \pink{x = 18}}}[/tex]

[tex] \: [/tex]

_________

[tex] \text { 3 ] 95 = -4 + 33x }[/tex]

[tex] \rm \: ↣ 95 = -4 + 33x \\ \rm↣ 95 + 4 = 33x \\ \rm↣ 99 = 33x \\ \rm ↣ \cancel \frac{99}{33} = x \\ \rm ↣3 = x \\ \underline{ \underline{\rm \color{hotpink}↣x = 3}}[/tex]

[tex] \: [/tex]

━━━━━━━━━━━━━━━━━━━━━━━

hope it helps:)

what is this (6x+4)+26=90 ?

Answers

Answer:

x=10

Step-by-step explanation:

(6x+4)+26=90

6x+4+26=90

6x+30-30=90-30

6x÷6=60÷6

x=10

Answer:

the answer is X=10

(6x+4)+26=90

6x +30=90

6x= 90÷30

6x=60

X = 60÷6

X= 10

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