a track star runs a 400-m race on a 400-m circular track in 45 s. what is his angular velocity assuming a constant speed?

Answers

Answer 1

The angular velocity assuming a constant speed for a track-star who runs 400 m circular track in 45 s is 0.139 radians/s.

To calculate the angular velocity first the circumference of the track is 400 meters.

This means that the angular displacement of the track star during the race is:

θ = s / r

where θ is the angular displacement,

s is the distance traveled by the track star (which is equal to the circumference of the track), and

r is the radius of the circular track.

2.) Since the radius of the circular track is half of its diameter, we have:

r = 400 m / 2 = 200 m

Plugging this into the equation for angular displacement, we get:

θ = 400 m / 200 m = 2π radians

3.) Next, we can use the formula for angular velocity:

ω = θ / t

where ω is the angular velocity and

t is the time it takes for the track star to complete the race.

4.)Plugging in the values we have:

ω = θ / t

ω = 2π radians / 45 s

Therefore, the angular velocity of the track star is:

ω = 0.139 radians/s (rounded to three significant figures)

Therefore, the track star's angular velocity assuming a constant speed is approximately 0.139 radians/s

The angular displacement of the track star is equal to one complete revolution around the circular track, which is equal to 2π radians.

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Related Questions

what observation can you make that allows you to determine the relative magnitudes of the forces on the upper book?

Answers

Observing the reaction of the book when placed on the table, we can determine the relative magnitudes of the forces on the upper book. If the book stays in place, then the magnitude of the normal force is equal to the gravitational force. If the book slides down, then the gravitational force is greater than the normal force, and if the book slides up, then the normal force is greater than the gravitational force.

To determine the relative magnitudes of the forces on the upper book, we can observe the reaction of the book when placed on the table. If the book stays in place and does not move, then the forces on the upper book are in balance, meaning that the magnitude of the normal force is equal to the gravitational force.

To explain further, the normal force is the force that the table exerts on the book. It opposes the force of gravity, which is the force of attraction between the book and the Earth. When the normal force is equal to the gravitational force, the book is in equilibrium, meaning that it stays in place. When the gravitational force is greater than the normal force, the book slides down, and when the normal force is greater than the gravitational force, the book slides up.

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a 1-kg rock that weighs 10 n is thrown straight upward at 20 m/s. neglecting air resistance, the net force that acts on it when it is half way to the top of its path is

Answers

A net force of 10 N acts on the rock when it is halfway to the top of its path.

The net force acting on the rock can be calculated using the following equation:

Fnet = ma

Where Fnet is the net force, m is the mass, and a is the acceleration.

When the rock is halfway to the top of its path, its velocity is zero since it momentarily stops at the top of its motion. As a result, its acceleration is equal to the acceleration due to gravity, which is -10 m/s² since it is acting in the opposite direction to the upward direction. This is the gravitational force acting on the rock.

We can now calculate the net force acting on the rock at this point in its motion:

Fnet = ma

Fnet = (1 kg)(-10 m/s²)

Fnet = -10 N

Since the acceleration due to gravity is acting downward and the rock is moving upward, the net force is equal to the force of gravity, which is 10 N.

Therefore, the net force that acts on the rock when it is halfway to the top of its path is -10 N or 10 N in the downward direction. This net force is equal in magnitude to the weight of the rock.

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our resistors are connected to a source of emf as shown. Rank the four resistors in order of the current through the resistor, from highest to lowest.A. the 6.00-S2 resistor B. the 8.00-S2 resistor C. the 20.0-2 resistor D. the 25.0-S2 resistor

Answers

the ranking of the resistors in terms of current, from highest to lowest, is A, B, C, D.

To rank the four resistors in order of the current through the resistor from highest to lowest, we need to consider Ohm's Law, which states that the current (I) is equal to the voltage (emf) divided by the resistance (R). Mathematically, this is represented as I = emf / R.

Assuming that all resistors are connected to the same source of emf, the resistor with the lowest resistance will have the highest current, and the resistor with the highest resistance will have the lowest current. Therefore, we can rank the resistors based on their resistance values:

1. A. the 6.00-Ω resistor
2. B. the 8.00-Ω resistor
3. C. the 20.0-Ω resistor
4. D. the 25.0-Ω resistor

So the ranking of the resistors in terms of current, from highest to lowest, is A, B, C, D.

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what results when two waves, in phase and with the same wavelength, interact? what results when two waves, in phase and with the same wavelength, interact? a wave with an amplitude that is the difference between the amplitudes of the initial two waves. a wave with an amplitude that is the larger of the amplitudes of the initial two waves. a wave with an amplitude that is the multiplication of the amplitudes of the initial two waves. a wave with an amplitude that is the sum of the amplitudes of the initial two waves.

Answers

When two waves, in phase and with the same wavelength, interact, the result is a wave with an amplitude that is the sum of the amplitudes of the initial two waves.

Thus, the correct answer is a wave with an amplitude that is the sum of the amplitudes of the initial two waves (D).

What is a wave?

А wаve is а disturbаnce thаt trаvels through а medium, trаnsferring energy from one point to аnother without trаnsferring the mаteriаl medium itself. Wаves cаn be of vаrious types, such аs sound wаves, electromаgnetic wаves, аnd more.

When two wаves interаct, there аre three possible results: reinforcement, interference, аnd а combinаtion of the two. When two wаves interfere with one аnother, their displаcements аdd up to form а resultаnt wаve. The crest of one wаve is in line with the crest of the other wаve, resulting in constructive interference, which results in а wаve with аn аmplitude thаt is the sum of the аmplitudes of the initiаl two wаves.

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find the force between charges of +10.0 x 10*C and -50.0 x 10*C located 20>0cm apart

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20 cm apart, the charges of +1.0 x 10⁻⁶ C and –1.0 x 10⁻⁶ C exert a force of 449.5 N on one another. This force is directed from the negative charge to the positive charge.

How can the force between two charges be determined?

According to Coulomb's law, the force F between two point charges, q1 and q2, that are separated by a distance r, is computed as F=k|q1q2|r2.

It is possible to determine the force between two point charges using Coulomb's law:

F = k*(q1*q2)/r²

In this case, we have[tex]q1 = +10.0 x 10^-6 C, q2 = -50.0 x 10^-6 C, and r = 20 cm = 0.2 m.[/tex]

Plugging in these values, we get:

[tex]F = (8.99 x 10^9 N m^2/C^2) * [(+10.0 x 10^-6 C) * (-50.0 x 10^-6 C)] / (0.2 m)^2[/tex]

Simplifying, we get:

F = -449.5 N.

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why do the solar system's many small bodies, such as asteroids, comets, and small moons, seem unlikely as potential homes to life?

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The solar system's many small bodies, such as asteroids, comets, and small moons, are unlikely as potential homes to life due to the fact that these celestial objects have too little gravity to support an atmosphere and most have no liquid water.

This is because their small sizes and masses do not allow for enough gravitational force to retain an atmosphere, and the extreme temperatures make liquid water impossible. Additionally, many small bodies lack the necessary components needed to support life, such as organic compounds or the right amount of radiation.

Asteroids, comets, and small moons typically have a low density, which means they are composed of rocks, dust, or ice, which would not support life. Moreover, these celestial objects have highly variable rotational periods and orbits, which would result in chaotic and extremely variable temperatures, making it difficult for any life forms to survive.

These celestial objects are also very small in comparison to other bodies in the solar system, meaning they receive far less sunlight than larger bodies. This is important for life to thrive because it requires energy from the sun to grow, reproduce, and obtain nutrients. The lack of energy from the sun, combined with the lack of liquid water and a protective atmosphere, makes these small bodies unlikely candidates for supporting life.

Therefore, it is unlikely to consider the celestial objects as potential homes because of the lack of sustainable living conditions like gravity, water, oxygen, and other organic substances.

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bioelectrical impedance analysis is a commercially available method used to estimate body fat percentage. the device applies a small potential between two parts of the patient's body and measures the current that flows through. with an estimate of the resistance individually of the muscle and fat between the two points, the composition of the tissue can be estimated. assume that the muscle and fat tissue can be modeled as resistors in parallel. part a part complete if the resistance of fat is 3 times that of muscle, what is the resistance of fat if a 1 ma m a current is measured when potential difference of 0.5 v v is applied to the patient's arm?

Answers

2000 ohms is the the resistance of fat if a 1 ma m a current is measured when potential difference of 0.5 v v is applied to the patient's arm.

How to solve for the resistance

we have r = resistance of the muscle

R = fat resistance

we are given R = 3r

such that the R total would be solved using ohms law:

We would have 3r² / 4r

= 0.75r

when we use the Ohm's law we would have the follwoing calculation

0.5 = 0.001 * 0.75 r

we are to solve for the value of r

0.5 = 0.00075r

divide through by:

r = 0.5 / 0.00075

= 666.667

Remember that R = 3r

R = 3 * 666.667

R = 2000 ohms

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a mass of 500g ball is kicked at angle of 45 degree to the horizontal the ball reaches 12m height what is the initial velocity

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The initial velocity of a 500g ball kicked at a 45-degree angle to the horizontal and reaching a height of 12m can be calculated using the kinematic equation.

What is the kinematic equation?

The equation of kinematics is a set of equations that are used to describe the motion of objects. They relate to displacement, velocity, acceleration, and time. Kinematic equations are divided into two categories, depending on the object's acceleration: zero acceleration and non-zero acceleration.

The kinematic equation for the object in motion with uniform acceleration is as follows:v^2 = u^2 + 2asWhere: v = final velocity u = initial velocity a = acceleration s = displacement. To calculate the initial velocity of the ball, we can rearrange the equation above to obtain:u^2 = v^2 - 2as From the given, a = -9.8 m/s² (negative acceleration indicates that the ball is decelerating or moving upward) s = 12m v = 0 (the final velocity is zero because the ball has stopped rising and is about to start falling). We'll use these values to calculate the initial velocity of the ball.u² = (0)² - 2(-9.8)(12)u² = 235.2u = sqrt(235.2)u = 15.33 m/s.

Therefore, the initial velocity of the ball is approximately 15.33 m/s.

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which term defines the distance from rest to crest, or from rest to trough?responsesamplitudeamplitudefrequencyfrequencyperiodperiodspeed

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Amplitude is not measured from peak to trough, but from rest to peak or rest to trough.

The highest and lowest points on the surface of a wave are called crests and troughs respectively. The vertical distance between the peak and the trough is the height of the waves. The horizontal distance between two successive peaks or troughs is called the wavelength.

The amplitude of a wave is the maximum displacement of a particle on a medium with respect to its position of rest.

The amplitude can be thought of as the distance between rest and the peak. The amplitude from the rest position to the dip position can be measured in a similar manner.

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A billiard ball of mass m = 0.150 kg hits the cushion of a billiard table at an angle of θ1 = 60.0 degrees at a speed of v1 = 2.50 m/s. It bounces off at an angle of θ2 = 47.0 degrees and a speed of v2 = 2.20 m/s.
a) What is the magnitude of the change in the momentum of the billiard ball?
b) In which direction does the change of momentum vector point? (Take the x-axis along the cushion and specify your answer in degrees.)

Answers

The magnitude of the change in the momentum of the billiard ball is 0.268 kg⋅m/s. The direction of the change of momentum vector points at 59.6 degrees, measured counterclockwise from the x-axis along the cushion.

This result can be found by using the equation for conservation of momentum, which states that both the magnitude and the direction of the momentum before and after the collision must be the same.

Since the mass and the speed of the ball changed, the direction of the vector must have changed as well. In this case, the vector changed direction from 60 degrees to 47 degrees, a difference of 13 degrees.

This means that the vector must have rotated counterclockwise by 13 degrees, or in other words, the change of momentum vector points at 59.6 degrees, measured counterclockwise from the x-axis along the cushion.

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an asteroid orbits the sun in a highly elliptical orbit. as the asteroid gets closer to the sun, how are the total mechanical energy and gravitational potential energy of the asteroid-sun system changing, if at all?

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The total mechanical energy and gravitational potential energy of the asteroid-sun system will change.

Asteroid-sun system

As the asteroid gets closer to the sun in its highly elliptical orbit, both the total mechanical energy and gravitational potential energy of the asteroid-sun system will change.

The total mechanical energy of the asteroid-sun system is the sum of its kinetic energy and gravitational potential energy. As the asteroid moves closer to the sun, its kinetic energy will increase due to the increase in speed, but its gravitational potential energy will decrease due to the decrease in distance from the sun. Therefore, the total mechanical energy of the asteroid-sun system will remain constant, according to the law of conservation of energy.

However, if the asteroid encounters any gravitational forces or other external forces, such as a collision with another object or a thrust from a spacecraft, its mechanical energy can change.

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while the general equations for the first and second law are written in terms of how the universe changes, dr. laude's preference is that we quickly rewrite them to reflect changes in what?

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This is due to the fact that the first and second laws of thermodynamics are universally applicable fundamental principles that can be utilised to examine particular systems and processes.

How do chemical processes relate to the first and second laws of thermodynamics?

The part of thermodynamics that deals with chemical reactions is called chemical thermodynamics. The first law states that energy is conserved and cannot be created or destroyed. Second law: When natural processes in a closed system result in a rise in entropy, they are spontaneous.

The second law of thermodynamics is what?

According to the second rule of thermodynamics, an isolated system that is out of equilibrium over time must increase in entropy until it reaches the ultimate equilibrium value.

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explain the use of air bags and seat belts in terms of momentum and impulse. please provide examples (and calculations) to elaborate your concepts.

Answers

Answer:

Explanation:

A seatbelt is designed to stretch a bit when the car decelerates rapidly. You travel forward a little while being stopped - you do not stop sharply as you would if you hit the dashboard. The seatbelt stretching increases the time over which your momentum is changed, thereby decreasing the force experienced by your body.

Airbags are made from a strong coated fabric. They are stored in a module mounted on the steering wheel and dashboard and side panels of the car. The inflation of them is initiated by crash sensors that activate upon impact at speeds of more than 10-15 miles per hour. They are mounted in several locations on the car body. In a crash, the sensor sends an electrical signal to the airbag which then causes the airbag to deploy. It ignites a chemical propellant which produces nitrogen gas, which then inflates the bag itself.

Explain why the transverse pulse traveling on a rope held by two people reflects in the opposite orientation each time it reaches a person.
Drag the terms on the left to the appropriate blanks on the right to complete the sentences. ANSWER: - greater - oppose - second law - increase - smaller - the same
- third law - first law
When a transverse wave pulse reaches a fixed end of the rope, the displacement of the rope end exerts a force on the object that is keeping the end fixed (in this case, a person). By Newton's ___ the person must exert a force of __ magnitude in ___ direction; otherwise the end of the rope would not remain stationary but would the opposite accelerate in the direction of the force due to the wave disturbance. Because this force acts to ___ the force of the incoming wave pulse, it initiates an outgoing wave pulse that is inverted with respect to the incoming wave pulse.

Answers

To complete the given sentences explaining why the transverse pulse traveling on a rope held by two people reflects in the opposite orientation each time it reaches a person order of the words used is third law, the same, oppose, increase.

When a transverse wave pulse reaches a fixed end of the rope, the displacement of the rope end exerts a force on the object that is keeping the end fixed (in this case, a person). By Newton's third law, the person must exert a force of the same magnitude in oppose direction; otherwise, the end of the rope would not remain stationary but would accelerate in the direction of the force due to the wave disturbance. Because this force acts to increase the force of the incoming wave pulse, it initiates an outgoing wave pulse that is inverted with respect to the incoming wave pulse.

When a transverse pulse traveling on a rope held by two people reaches one of the people, the pulse is reflected in the opposite orientation. This happens because of the interaction between the pulse and the person holding the rope.

By Newton's third law, the displacement of the rope end exerts a force on the person that is equal in magnitude but opposite in direction. If the person did not exert an equal and opposite force, the end of the rope would not remain stationary but would instead accelerate in the direction of the force due to the wave disturbance.

The force exerted by the person opposes the force of the incoming wave pulse, initiating an outgoing wave pulse that is inverted with respect to the incoming wave pulse. This happens due to the conservation of energy and momentum, which are described by Newton's first and second laws. The outgoing pulse has a smaller amplitude than the incoming pulse because some energy is lost in the reflection process.

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determine the limit on the series resistance so the energy remaining after one hour is at least 85 percent of the initial energy.

Answers

The limit on the series resistance so that the energy remaining after one hour is at least 85 percent of the initial energy, is initial energy into 85% by the voltage.

Ohm's Law states that the current in a circuit is directly proportional to the voltage and inversely proportional to the resistance.

Therefore, the total resistance in a circuit can be calculated using the formula: R = V/I

The energy remaining after one hour must be at least 85 percent of the initial energy, we can calculate the resistance by rearranging the formula.

The total resistance can be determined by multiplying the initial energy by 85 percent and dividing it by the voltage. Thus, the limit on the series resistance is [tex]R = (Initial Energy *0.85) / V[/tex].  

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what is the magnitude of the force that the child exerts on the seat at the lowest point if his mass is 18.5 kg in n?

Answers

The magnitude of the force that the child exerts on the seat at the lowest point if his mass is 18.5 kg is 981 N.

To determine the magnitude of the force on the child, we must find the magnitude of the centripetal acceleration of the child at the low point first. We can use the equation:

[tex]a_{c}[/tex] = [tex]\frac{v^{2} }{r}[/tex]

where v = 9 m/s and r = 2 m

thus,

[tex]a_{c}[/tex] = [tex]\frac{9^{2} }{2}[/tex]

[tex]a_{c}[/tex] = 40.5 m/s²

And then, we find out the magnitude of the force that the child exerts on the seat at the lowest point if his mass is 18.5 kg.

∑[tex]f_{y}[/tex] = m × [tex]a_{c}[/tex]

[tex]f_{n}[/tex] - w = m × [tex]a_{c}[/tex]

[tex]f_{n}[/tex] = m × [tex]a_{c}[/tex] + w

[tex]f_{n}[/tex] = (18.5 × 40.5) + 18.5 (9.80)

[tex]f_{n}[/tex] = 981 N

Thus, the magnitude of the force that the child exerts on the seat at the lowest point if his mass is 18.5 kg in N is 981 N.

Your question is incomplete, but most probably your full question was

A mother pushes her child on a swing so that his speed is 9.00 m/s at the lowest point of his path. The swing is suspended 2.00 m above the child’s center of mass.

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if the frequency of the incoming light is decreased, will the energy of the ejected electrons increase, decrease, or stay the same?

Answers

If the frequency of the incoming light is decreased, the energy of the ejected electrons will decrease.

The frequency of the incoming light will affect the energy of the ejected electrons. This is because the energy of the ejected electrons is proportional to the frequency of the incoming light.

The energy of the electrons can be determined using the equation:

E = h * f,

where E is the energy, h is Planck’s constant, and f is the frequency of the incoming light. This equation shows that the energy of the electrons is directly proportional to the frequency of the incoming light.


Therefore, if the frequency of the incoming light is decreased, the energy of the ejected electrons will also decrease.

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how does matter affect your daily lives?

Answers

Matter affects our daily lives in the sense all is composed of matter and energy.

What are matter and energy in the Universe and daily life?

Matter and energy in the Universe and daily life are two basic elements that characterize the physic system and allow us to understand the world. In regard to matter, it is something that occupies space and has mass, while energy can perform work.

Therefore, with this data, we can see that matter and energy in the Universe and daily life are fundamental to understanding the universe.

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what is the si unit of energy and how is it related to units of mass, distance, and time? multiple choice question. joule, 1 j

Answers

The correct option is A, the si unit of energy and how is it related to units of mass, distance, and time is joule.

The joule is a unit of measurement used to express energy or work done. It is named after the English physicist James Prescott Joule, who studied the relationship between heat and mechanical work in the mid-19th century. One joule is equal to the amount of energy needed to perform work of one newton-meter.

This means that if a force of one newton is applied over a distance of one meter, one joule of work is done. The joule is used to measure a wide variety of energies, including potential energy, kinetic energy, and thermal energy. It is also used to express the amount of work done by machines, such as engines and generators.

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Complete Question: -

What is the SI unit of energy and how is it related to units of mass, distance, and time?

a. joule

b. watt

c. kilo

d. Newton

imagine you have a sensitive radio telescope and you would like to look at the sun. is it reasonable to expect that you would see it?

Answers

Yes, it is reasonable to expect that you would see the Sun with a sensitive radio telescope.

Radio waves can penetrate through the clouds and the atmosphere, so with a powerful radio telescope you can observe the Sun even on a cloudy day.

Gather the necessary components of the radio telescope, such as a dish and receiver. Point the radio telescope towards the Sun. Tune the receiver to the proper frequency. Take a look at the results from the telescope and observe the Sun.

Therefore, you can expect that you would see the Sun with a sensitive radio telescope.

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A banjo D string is 0.69 m long and has a fundamental frequency of 294 Hz.
Part A
Determine the speed of a wave or pulse on the string.
Express your answer to two significant figures and include the appropriate units.
v =
Part B
Identify first three other frequencies at which the string can vibrate.
Enter your answers using two significant figures in order of increasing frequencies separated by commas.
f2, f3, f4 =

Answers

Answer:

Part A:

The speed of a wave on the string can be calculated using the formula:

v = fλ

where f is the frequency and λ is the wavelength. In this case, we only know the frequency of the fundamental mode, so we need to use another formula that relates the wavelength and the length of the string:

λn = 2L/n

where n is the mode number (n = 1 for the fundamental mode), and λn is the wavelength of the nth mode. Substituting this expression for λ into the first formula, we get:

v = fn × 2L/n

Substituting the given values, we get:

v = (294 Hz) × 2(0.69 m)/(1)

v = 406 m/s

Therefore, the speed of a wave or pulse on the string is 406 m/s.

Part B:

The frequencies of the other modes of vibration can be calculated using the formula:

fn = nv/2L

where n is the mode number, v is the speed of the wave on the string (which we found in Part A), and L is the length of the string. Substituting the given values, we get:

f2 = (2 × 406 m/s)/(2 × 0.69 m) = 589 Hz

f3 = (3 × 406 m/s)/(2 × 0.69 m) = 883 Hz

f4 = (4 × 406 m/s)/(2 × 0.69 m) = 1178 Hz

Therefore, the first three other frequencies at which the string can vibrate are 589 Hz, 883 Hz, and 1178 Hz.

an electric eel can generate a 278-v, 0.8-a shock for stunning its prey. what is the eel's power output?

Answers

The electric eel's power output is 222.4 Watts

Given voltage (V) = 278 V

Current (I) = 0.8 A

To find the electric eel's power output, we have to use the formula

P = IV,

Where P is the power output, I is current, and V is the voltage.

So, we can calculate the electric eel's power output as follows:

Power Output (P) = IVP

⇒278 × 0.8

Power Output (P) = 222.4 Watts

Hence, The power output of the electric eel is 222.4 Watts.

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if a test point is marked 5 volts and a sedond test point is marked -3.3 volts. what voltage would you expect to read between the two points if the refernece lead is on the lowest voltage

Answers

The 5-volt reading we can expect between the two test points if the reference lead is on the lowest voltage.

The given data is as follows:

The first test marked voltage = 5 volts

The second test marked voltage = -3.3 volts

Let us assume that the two test points are there is a conductive track between them, the voltage between the two points can be calculated using the voltage difference between the two test points.

The voltage difference between the  two test points is calculated as:

5 volts - (-3.3 volts) = 8.3 volts

If the reference lead is on the lowest voltage, It means that the negative side of the voltmeter is attached to the test point with the lower voltage which is -3.3 volts.

The voltage difference between the  two test points is

8.3 volts - 3.3 volts = 5 volts

Therefore we can conclude that the 5-volt reading we can expect between the two test points.

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if the rate of internal energy dissipation in a battery is 1.0 watt, and the current produced by the battery is 0.50 amps, what is the internal resistance of the battery?

Answers

If the rate of internal energy dissipation in a battery is 1.0 watt, and the current produced by the battery is 0.50 amps, the internal resistance of the battery can be calculated using Ohm's law. Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points. The proportionality constant is called the resistance of the conductor, which is expressed mathematically as V = IR, where V is the voltage, I is the current, and R is the resistance.

The power dissipated by the internal resistance of a battery is given by P = I2R, where P is the power, I is the current, and R is the internal resistance. The rate of internal energy dissipation in the battery is given as 1.0 watt, and the current produced by the battery is given as 0.50 amps.

Using Ohm's law, we can calculate the voltage across the battery as V = IR = 0.50 x R. Therefore, the power dissipated by the internal resistance of the battery is P = I2R = (0.50)2 x R = 0.25R.

Equating the power dissipated by the internal resistance of the battery to the rate of internal energy dissipation, we get:

0.25R = 1.0

Solving for R, we get:

R = 1.0/0.25 = 4 ohms.

Therefore, the internal resistance of the battery is 4 ohms.

Internal energy dissipation is the energy that is lost due to friction or resistance in a system. In the case of a battery, internal energy dissipation refers to the energy that is lost due to the internal resistance of the battery. The internal resistance of a battery is a measure of how much energy is lost due to the resistance of the battery's internal components. The higher the internal resistance of the battery, the more energy is lost as heat, which reduces the battery's efficiency.

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As a boat moves through water, it experiences drag, which is similar to air resistance. Does drag slow the boat down or speed it up?

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Answer:

Whether the object or fluid is moving, drag occurs as long as there is a difference in their velocities. Because it is resistant to motion, drag tends to slow down the object. An effective way to reduce it is to alter the shape of the object and make it streamline. Drag Force Examples of Drag Force

Explanation:

if a bag has a mass of 25 kg, how much force must you apply vertically to lift it off of a baggage cart?

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A force of 245 N must be applied vertically to lift the bag off the baggage cart.

The force that must be applied vertically to lift a bag off a baggage cart, given that the bag has a mass of 25 kg, can be determined using the formula F = m*g

where F is force, m is mass, and g is acceleration due to gravity. The value of g is 9.8 m/s².So, F = 25 kg x 9.8 m/s² = 245 N. Therefore, a force of 245 N must be applied vertically to lift the bag off the baggage cart.

The mass of the bag = 25 kg.The formula used is, F = m*gwhereF = Force required to lift the bagm = Mass of the bagg = Acceleration due to gravityF = 25 kg x 9.8 m/s² = 245 N.

Therefore, a force of 245 N must be applied vertically to lift the bag off the baggage cart.

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in an alternating current circuit that contains a resistor a inductor and a capacitor with 120v how do you find current

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In an alternating current circuit that contains a resistor, an inductor, and a capacitor with 120V, you can find the current by using Ohm's Law.

Ohm's Law states that the current is equal to the voltage divided by the resistance.

To calculate the resistance in an alternating current circuit, you must take into account the resistor, inductor, and capacitor.

For example, if the resistor has a resistance of 10 ohms, the inductor has a resistance of 5 ohms, and the capacitor has a resistance of 20 ohms, then the total resistance would be 35 ohms.

Therefore, the current in the circuit would be 120V/35 ohms = 3.43A.

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how much work is done by a person lifting a 6.7-kg object from the bottom of a well at a constant speed of 2.5 m/s for 9 s? write your answer in joules.

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The amount of work done by a person lifting a 6.7-kg object from the bottom of a well at a constant speed of 2.5 m/s for 9 s is 1517.25 Joules.

The work done is determined using the equation below;

W = FdW = mgd

Where,W = Work done by the person,m = mass of object = 6.7 kg,g = acceleration due to gravity = 9.8 md = distance lifted by the person = ?We know that F = m(g + a) where a is the acceleration of the object that was lifted. The object is lifted at a constant velocity and so the acceleration of the object is zero. Hence,

F = mgF = 6.7 × 9.8F = 65.66 N

We can now determine the distance d that was lifted using the equation below;

d = vt

Where,v = constant velocity = 2.5 m/s.t = time taken = 9 s

Substituting the values; d = 2.5 × 9d = 22.5 m

Now we can determine the work done;

W = FdW = 65.66 × 22.5W = 1472.85 Joules (3 decimal places)

The work done by the person lifting a 6.7-kg object from the bottom of a well at a constant speed of 2.5 m/s for 9 s is 1517.25 Joules (2 decimal places)Answer: 1517.25 Joules.

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horses that move with the fastest linear speed on a merry-go-round are located anywhere, because they all move at the same speed. near the center. near the outside.

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Horses that move with the fastest linear speed on a merry-go-round are located near the outside.

A merry-go-round is an amusement park ride that comprises a rotating circular platform equipped with seats or mounts for people to ride on. When the ride is operating, the circular platform rotates around a fixed central axis at a constant velocity, while the people on it rotate with the platform. Linear speed refers to the velocity of the object in a straight line path, regardless of its direction of movement.

Therefore, the linear speed of the mounts on the merry-go-round depends on the radius of the circular path they move on. The closer the horse is to the center, the shorter the path it has to cover during one rotation of the platform, meaning it has a slower linear speed. Conversely, the farther the horse is from the center, the longer the path it has to cover, hence it has a faster linear speed. As a result, the mounts located near the outside of the merry-go-round move with the fastest linear speed.

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the wavelengths for visible light rays correspond to which of these options? a. about the size of a pen b. about the size of a virus or a large molecule

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The wavelengths for visible light rays correspond to about the size of a pen. Option a is correct.

Visible light consists of electromagnetic waves with wavelengths that range from approximately 400 to 700 nanometers (nm), or billionths of a meter. This corresponds to frequencies ranging from approximately 430 to 750 terahertz (THz). These wavelengths are much larger than the size of a virus or a large molecule, which typically range from a few nanometers to a few micrometers in size. In comparison, the size of a pen is typically several centimeters long, which is much larger than the wavelength of visible light. Hence, option a is correct choice.

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Answer: C.

about the size of an amoeba

Explanation: ed mentum or plato

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