A wooden block has a volume of 12.5 litres and a mass of 5.0 kg. 5.0 litres of water must be displaced if the wooden block is to float.
What volume of water must be displaced if the wooden block is to float?The density of wood is less than the density of water. As a result, to float on water, an object made of wood must displace an amount of water greater than its weight.
The formula for calculating the density of an object is:
density = mass/volume
Rearranging this equation gives: v
olume = mass/density
From the information given in the question, the mass of the wooden block is 5.0 kg, and the volume is 12.5 liters.
Density is the mass divided by the volume:
density = mass/volume = 5.0 kg / 12.5 L = 0.4 kg/L
To float on water, the density of the wooden block must be less than the density of water, which is 1 kg/L.
Applying the formula above, we can solve for the volume of water displaced by the wooden block, which is equal to the volume of the block:
volume = mass/density = 5.0 kg / 1 kg/L = 5.0 L
Thus, 5.0 liters of water must be displaced if the wooden block is to float.
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what are some of the challenges associated with using solar energy as a primary source of electricity,
The primary challenge associated with using solar energy as a primary source of electricity is the cost and availability of the technology.
Cost: One of the significant challenges of solar energy is its cost. Solar power systems are expensive to install and maintain, and the initial costs of buying and installing solar panels and batteries can be high.
Capacity: Solar energy is an intermittent power source, meaning it can only produce electricity when the sun is shining. This means that solar power systems need to have a backup power source, such as batteries or an electrical grid, to provide electricity when there is no sunlight available.
Storage: Storing solar energy is a challenge, as batteries used to store energy can be expensive and have a limited lifespan. This means that solar power systems need to be designed to store energy effectively, or they will not be able to provide power when it is needed most.
Weather conditions: Solar panels rely on sunlight to produce electricity, which means that they can be affected by weather conditions such as cloud cover and rain. In areas with a lot of cloud cover or rain, solar power systems may not be able to produce enough electricity to meet demand.
Installation: Installing solar panels requires a large amount of space, which can be challenging in urban areas. Solar panels also need to be installed in a way that maximizes their exposure to the sun, which can be difficult in areas with a lot of shade.
Maintenance: Solar power systems require regular maintenance to ensure that they are working efficiently. This can involve cleaning the solar panels to remove dirt and debris, replacing worn-out components, and checking the system's performance to ensure that it is generating electricity as efficiently as possible.
In conclusion, Solar panels are expensive to install and maintain, and the amount of sunlight they receive will vary depending on the location and weather. Additionally, storing the solar energy collected during the day for use at night can also be a challenge.
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A solid cylinder of mass M = 1.25 kg and radius R = 13.5 cm pivots on a thin fixed frictionless bearing a string wrapped around the cylinder pulls downward with a force of F = 7.259 N
What is the magnitude of the angular acceleration of the cylinder?
86.03259 rad/s^2
Consider that instead of force F, a block with mass 0.74 kg with force = 7.259 N is attached to the cylinder with a mass less string.
What is now the magnitude of the angular acceleration of the cylinder
39.3943 rad/s^2
How far does the mass M travel downward before T equals 0.49S and T equals 0.69 S.
0.62755 m
The cylinder is changed to one with the same mass and radius but a different moment of inertia starting from mass starting from rest. The mass is now moved. The distance of 0.448 mass in the time interval of 0.47 seconds.
Find the Inertia of the new cylinder
The inertia of the new cylinder is 0.0566 kgm². Other answers provided are correct.
How to find inertia?The moment of inertia of the new cylinder can be calculated using the formula:
I = (M × d²) / (4 × Δθ)
Where:
M = mass of the cylinder
d = distance moved by the mass
Δθ = change in angular displacement (in radians)
Substituting the given values:
I = (1.25 × 0.448²) / (4 × 0.47)
I = 0.0566 kgm²
Therefore, the moment of inertia of the new cylinder is 0.0566 kgm².
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a 100 cm diameter propeller blade, similar to the blade in example 4.15, is attached to a motor spinning at a constant rate. what is true about the radial (centripetal) acceleration and the tangential acceleration at the end of the blade?
The true statements about the radial (centripetal) acceleration and the tangential acceleration at the end of the blade are: the radial acceleration is non-zero the tangential acceleration is zero
The radial acceleration is non-zero and the tangential acceleration is zero. This is because, the radial acceleration is determined by the formula, ar = (v²)/r
where ar is the radial acceleration, v is the velocity and r is the radius. Thus, since the propeller blade is spinning at a constant rate, the velocity v is constant.
Therefore, the radial acceleration is constant and non-zero.
The tangential acceleration, on the other hand, is given by at = rα
where at is the tangential acceleration and α is the angular acceleration. Since the blade is spinning at a constant rate, the angular acceleration is zero. Therefore, the tangential acceleration is zero.
So, the correct option is the radial acceleration is non-zero and the tangential acceleration is zero.
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if you hold a 1.85 kg k g package by a light vertical string, what will be the tension in this string when the elevator accelerates as in the previous part?
The tension in the string of a 1.85 kg package held by a light vertical string will depend on the acceleration of the elevator. When the elevator accelerates, the force of acceleration on the package will be equal and opposite to the tension in the string, causing the tension to increase.
The equation for tension in a string is:
Tension = Mass x Acceleration
Therefore, in this case, the tension in the string is equal to 1.85 kg x Acceleration.
If we assume that the acceleration of the elevator is a constant rate, then the tension in the string can be calculated by multiplying the mass of the package by the acceleration of the elevator.
To sum up, the tension in the string of a 1.85 kg package held by a light vertical string will depend on the acceleration of the elevator. If the acceleration of the elevator is a constant rate, then the tension in the string can be calculated by multiplying the mass of the package by the acceleration of the elevator.
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g which of the following wavelengths of light is most likely to cause a sunburn? explain your answer. a. 700 nm b. 400 nm c. 200 nm
Answer:
(b) 400 nm is the far ultraviolet (violet) in the visible spectrum
The shorter wavelengths are more likely to cause sunburn.
200 nm is probably too short to be transmitted by the atmosphere
how hard must each player pull to drag the coach at a steady 2.0 m/s ? express your answer with the appropriate units.
Each player must pull with a force of 1250 N to drag the coach at a steady 2.0 m/s.
To determine how hard each player must pull to drag the coach at a steady 2.0 m/s, we need to use Newton's second law, which states that the net force acting on an object is equal to its mass times its acceleration:
Fnet = m * a
where Fnet is the net force, m is the mass of the coach and players, and a is the acceleration of the coach and players.
Assuming that the coach and players can be treated as a single object, we can use the given speed to find the acceleration of the object using the formula:
a = v² / (2 * d)
where v is the speed (2.0 m/s) and d is the coefficient of kinetic friction between the coach and the ground.
The force required to overcome friction and drag the coach at a steady speed is given by:
Ffriction = friction coefficient * Fnormal
where Fnormal is the normal force (equal to the weight of the coach and players) and the friction coefficient is a dimensionless quantity that depends on the nature of the contact surface.
Assuming a friction coefficient of 0.5 and a weight of 5000 N for the coach and players, the force required to overcome friction is:
F_friction = (0.5) * (5000 N) = 2500 N
The net force required to move the coach and players at a steady 2.0 m/s is therefore:
Fnet = Ffriction = 2500 N
Finally, we can use Newton's second law to find the force required from each player:
Fnet = m * a
2500 N = (m_coach + m_players) * (v² / (2 * d))
Solving for the mass (m_coach + m_players), we get:
m_coach + m_players = (2500 N * 2 * d) / v²
Assuming a value of 0.3 for the coefficient of kinetic friction between the coach and the ground, we get:
m_coach + m_players = (2500 N * 2 * 0.3) / (2.0 m/s)² = 562.5 kg
Therefore, the force required from each player is:
Fplayer = Fnet / 2 = 1250 N
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a spherical capacitor has vacuum between its conducting shells and a capacitance of 125 pf . the outer shell has inner radius 9.00 cm . what is the outer radius of the inner shell? express your answer with the appropriate units.
For a spherical capacitor with a capacitance of 125 and a vacuum between its conducting shells, the outer radius of the inner shell is around 5.60 cm.
The capacitance of a spherical capacitor is given by:
C = 4πε₀[(r₁r₂)/(r₂-r₁)]
where C is the capacitance, ε₀ is the electric constant (8.85 x [tex]10^{-12}[/tex] F/m), r₁ is the radius of the inner shell, and r₂ is the radius of the outer shell.
In this case, we know that the capacitance C = 125 pF (picoFarads), r₂ = 9.00 cm, and we want to find r₁.
We can rearrange the equation to solve for r₁:
r₁ = (C × r₂)/(4πε₀ + C)
Substituting the values:
r₁ = (125 x [tex]10^{-12}[/tex] F × 0.09 m) / (4π × 8.85 x [tex]10^{-12}[/tex] F/m + 125 x [tex]10^{-12}[/tex] F)
r₁ ≈ 5.60 cm
Therefore, the outer radius of the inner shell is approximately 5.60 cm.
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magnus has reached the finals of a strength competition. in the first round, he has to pull a city bus as far as he can. one end of a rope is attached to the bus and the other is tied around magnus's waist. if a force gauge placed halfway down the rope reads out a constant 1400 newtons while magnus pulls the bus a distance of 1.55 meters, how much work does the tension force do on magnus? the rope is perfectly horizontal during the pull.
The work done by the tension force on Magnus is 2170 J.
What is work?
Work is the product of the force acting on an object and the distance through which the object moves. In other words, work is accomplished when a force is used to transfer energy to an object, causing the object to move some distance as a result.
The force of 1400 N, Distance of 1.55 meters, and a rope tied around Magnus's waist.
The work done by the tension force on Magnus is the product of the force exerted by the tension force and the distance through which Magnus is moved.
W = Fd
where W = Work done by the tension force on Magnus
F = Force of tension force
= 1400 Nd
= Distance moved by Magnus
= 1.55 m
Substituting these values:
W = 1400 N x 1.55 mW
= 2170 J
Hence, the work done by the tension force on Magnus is 2170 J.
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in u.s. customary units, air pressure is measured in pounds per square inch. in the metric system, it is measured in pascals, and one pascal is equal to
In the metric system, air pressure is measured in pascals. One pascal is equal to a force of one newton per square meter.
Air pressure can be measured using different units. Pascal is a unit of pressure, defined as one newton per square meter. This unit is named after Blaise Pascal, a French mathematician, physicist, and philosopher who made important contributions to the fields of hydrodynamics and hydrostatics.
In the US customary system, air pressure is measured in pounds per square inch (psi), while in the International System of Units (SI), it is measured in pascals (Pa). The unit psi is used to measure pressure in liquids and gases, and it is defined as the amount of pressure exerted by a force of one pound-force per square inch.
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two 4.0cm*4.0cm metal plates are separated by a 0.20-mm-thick piece of teflon. a. what is the capacitance? b. what is the maximum potential difference between the plates?
The capacitance of two metal plates separated by a 0.20-mm-thick is approximately 0.25 pF and the maximum potential difference between the plates is 8.4 kV.
a. The capacitance of two metal plates separated by a 0.20-mm-thick piece of Teflon is approximately 0.25 pF (picofarad).
b. The maximum potential difference between the two metal plates is determined by the permittivity of the dielectric material, which in this case is Teflon.
The permittivity of Teflon is about 2.1 and the capacitance of the plates is 0.25 pF, so the maximum potential difference between the plates can be calculated using the equation:
Vmax = (permittivity * Capacitance) / Area.
Therefore, the maximum potential difference between the plates is 8.4 kV.
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how do air masses contribute to the formation of air fronts?
Air masses contribute to the formation of air fronts because air masses are large bodies of air that have similar characteristics in terms of temperature, humidity, and stability.
When two air masses with different characteristics come into contact, they form a boundary known as an air front. The characteristics of the two air masses determine the type of air front that forms.
There are four types of air fronts: cold fronts, warm fronts, stationary fronts, and occluded fronts.
Cold fronts occur when a cold air mass displaces a warm air mass, causing the warm air to rise and cool, which leads to cloud formation and precipitation. Warm fronts occur when a warm air mass displaces a cold air mass, causing the warm air to rise gradually over the cold air, leading to gradual cloud formation and precipitation. Stationary fronts occur when two air masses with different characteristics meet but do not move, leading to prolonged periods of precipitation. Occluded fronts occur when a cold front overtakes a warm front and lifts the warm air mass off the ground, leading to cloud formation and precipitation.Air masses play a significant role in the formation of air fronts because they determine the characteristics of the air mass that will form at the boundary between the two air masses. This, in turn, determines the type of air front that will form and the type of weather that will result. For example, a cold, dry air mass coming into contact with a warm, moist air mass will likely result in a cold front and a period of heavy precipitation.
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Please help. Due at Midnight!
The magnitude and direction of the net force on the center charge is 3.929 x 10⁻⁴ N.
What is unit of charge?The unit of charge is the Coulomb (C). It is named after French physicist Charles-Augustin de Coulomb and is defined as the amount of electric charge that flows through a circuit when a current of one ampere flows for one second. One Coulomb is also equivalent to the charge on approximately 6.24 x 10¹⁸ electrons. The Coulomb is one of the seven base SI units (International System of Units) and is used to measure electric charge in physics and engineering.
So, the magnitude of the net force on the center charge is 3.929 x 10⁻⁴ N. Since F12 is directed towards the left, and F23 is directed towards the right, the net force is also directed towards the left. Therefore, the direction of the net force on the center charge is to the left.
According to Coulomb's law to calculate the force exerted by each of the other charges on the center charge, and then add them vectorially.
Let's call the left charge Q1, the center charge Q2, and the right charge Q3.
The force exerted on Q2 by Q1 is given by:
F₁₂ = k * |Q1| * |Q2| / r₁₂²
where k is Coulomb's constant, |Q1| and |Q2| are the magnitudes of the charges, and r₁₂ is the distance between them. Since Q1 is positive and Q2 is negative, the force F₁₂ is attractive and directed towards Q1. Because the distance between them is 2m, we can say:
F₁₂ = 9 x 10⁹ Nm²/C² * |52 x 10⁻⁶ C| * |3.10 x 10⁻⁶ C| / (2m)²
= 3.468 x 10⁻⁴ N (attractive)
The force exerted on Q2 by Q3 is given by:
F₂₃ = k * |Q2| * |Q3| / r₂₃²
where |Q3| is positive, and |Q2| is negative, so the force F23 is repulsive and directed away from Q3. The distance between them is also 2m, so:
F₂₃ = 9 x 10⁹ Nm²/C² * |3.10 x 10⁻⁶ C| * |68 x 10⁻⁶ C| / (2m)²
= 5.383 x 10⁻⁵ N (repulsive)
To find the net force on Q2, we need to add these two forces vectorially. Since they act along the same line, we can simply subtract their magnitudes:
Fnet = |F₁₂| - |F₂₃|
= 3.468 x 10⁻⁴ N - 5.383 x 10⁻⁵N
= 3.929 x 10⁻⁴ N.
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when lighted, a 100-watt light bulb operating on a 110-volt household circuit has a resistance closest to
When lighted, a 100-watt light bulb operating on a 110-volt household circuit has a resistance closest to 0.99 ohms.
Resistance refers to the electrical property of a circuit component, such as a light bulb, that resists the flow of electrical current through it.
Ohm's law is a fundamental principle in electrical engineering that relates the resistance, voltage, and wattage in a circuit. It states that the resistance (R) is equal to the voltage (V) divided by the wattage (W).
W = 100 watts, V = 110 volts.
Use Ohm’s law to calculate the resistance (R):
R = V/W = 110/100 = 0.99 ohms.
Therefore, when a 100-watt light bulb is operating on a 110-volt household circuit, its resistance is approximately 0.99 ohms.
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Which type of engine has a wheel with several blades mounted on a shaft that rotate a shaft when hit with heated air at a high velocity?
The type of engine that has a wheel with several blades mounted on a shaft that rotates when hit with heated air at a high velocity is called a gas turbine engine.
What is a gas turbine engine?
The gas turbine engine is also known as a combustion turbine engine. A gas turbine engine is a type of internal combustion engine that converts the chemical energy of fuel into mechanical energy, which can be used to power various machines and equipment. The engine works by compressing air and then mixing it with fuel in a combustion chamber, where it is ignited to produce a high-temperature, high-pressure gas stream. This gas stream then flows through a series of turbine blades, causing them to spin, which drives a shaft that is connected to various machines or equipment. As the shaft rotates, it generates mechanical power that can be used for various applications.
Gas turbine engines are commonly used in aircraft, power plants, and marine propulsion.
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how large must the coefficient of static friction be between the tires and the road if a car is to round a level curve of radius 145 m at a speed of 130 km/h ?
The coefficient of static friction between the tires and the road if a car is to round a level curve of radius 145 m at a speed of 130 km/h is 4.64
Whenever the object rotаtes аround the curved pаth then а net force аcts on the object pointing towаrds the center of а circulаr pаth аnd it is cаlled а centripetаl force. Mаthemаticаlly, we cаn write;
Centripetаl Force = [tex]\frac{mv^{2} }{r}[/tex]
where m is the mass of the body, v is the velocity of the body, and r is the radius of rotation.
We are given:
Radius of rotation r = 145 mMaximum velocity of car v = 130 km/h × [tex]\frac{5}{18}[/tex] = 81.25 m/sm be the mass of the carμs be the coefficient of static frictionSince the car is making circular motion, therefore, necessary centripetal force is provided by the frictional force.
frictional force = centripetal force
μsmg = [tex]\frac{mv^{2} }{r}[/tex]
μs = [tex]\frac{v^{2} }{rg}[/tex]
μs = [tex]\frac{81.25^{2} }{145.9.81}[/tex]
μs = 4.64
Therefore, the coefficient of static friction between the tires of the car and the road surface is 4.64.
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A dog can hear sounds in the range from 15
to 50,000 Hz.
What wavelength corresponds to the lower
cut-off point of the sounds at 20◦C where the
sound speed is 344 m/s?
Answer in units of m.
Explanation:
Speed of sound is 344
The frequency corresponding to the lower cut-off point is the lowest frequency which his 15Hz
F=15Hz
The relationship between the wavelength, speed and frequency is given as
v=fλ
Then,
λ=v/f
λ=v/f
λ=344/15
λ=22.93m
an n-type piece of silicon experiences an electric field equal to 0.1v/m. (a) calculate the velocity of electrons and holes in this material
In an n-type piece of silicon, the electric field causes the electrons to accelerate due to the attractive force between the negatively charged electrons and the positively charged electric field. This acceleration causes the electrons to reach a velocity of V = E/μ, where E is the electric field (0.1V/m) and μ is the mobility of electrons in silicon (1350 cm2/V⋅s). Therefore, the velocity of electrons in this material would be equal to 0.1V/m/1350cm2/V⋅s = 0.0741 cm/s.
The holes, on the other hand, experience a repulsive force due to the positive electric field. This causes the holes to decelerate, with a velocity of V = -E/μ. Therefore, the velocity of holes in this material would be equal to -0.1V/m/1350cm2/V⋅s = -0.0741 cm/s.
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two stationary point charges q1 and q2 are shown in the figure along with a sketch of some field linesrepresenting the electric field produced by them. what can you deduce from the sketch?
From the sketch, we can deduce that the two charges q1 and q2 are of opposite signs, as field lines start at the positive charge q1 and end at the negative charge q2. The field lines also indicate that the magnitude of the electric field produced by q1 is larger than that of q2.
Additionally, the field lines show that the electric field lines near the charges are denser, indicating a stronger electric field intensity near the charges. The direction of the electric field points from q1 to q2, which is consistent with the direction of the force that a positive test charge would experience if placed in the field. The field lines also show that the electric field is radial, i.e., the field lines point directly away from or towards each charge in a straight line, which is a characteristic of the electric field produced by a point charge. Finally, the density of the field lines decreases with distance from the charges, indicating that the electric field strength decreases with distance from the charges, following an inverse-square law.Learn more about electric field at: https://brainly.com/question/14372859
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2. how many times a minute does a boat bob up and down on ocean waves that have a wavelength of 36.0 m and a propagation speed of 4.80 m/s?
The boat will bob up and down on ocean waves that have a wavelength of 36.0 m and a propagation speed of 4.80 m/s once every 7.50 seconds.
To solve the given question, we must use the formula:
n= v/f
Where: v is the velocity of the wave (in m/s)f is the frequency of the wave (in Hz)n is the number of cycles per second
Therefore, the frequency of the wave (in Hz) can be calculated by using the formula:
f= v/λ
where: v is the velocity of the wave (in m/s)λ is the wavelength of the wave (in m)
The frequency of the wave is 0.1333 Hz (approx).
Now, the number of cycles per second (n) is: n = v/λ
We can solve for n by dividing the velocity of the wave by the wavelength of the wave.
Therefore,
n= v/λ= (4.80 m/s) / (36.0 m)= 0.1333 Hz
So, the boat bob up and down 0.1333 times a minute on ocean waves that have a wavelength of 36.0 m and a propagation speed of 4.80 m/s.
1 Hz = 60 seconds,
0.1333 Hz = 7.50 seconds.
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2. according to our equations, what should be the relationship between the total current and the currents passing through each resistor? does your data show this relationship
According to Ohm's Law, the relationship between the total current and the currents passing through each resistor is that the total current is equal to the sum of the currents passing through each resistor.
What is Ohm's Law?This can be represented mathematically as I total = I₁ + I₂ + I₃ + ... where I total is the total current and I₁, I₂, I₃, etc. are the currents passing through each resistor.
This relationship is consistent with Kirchhoff's Current Law, which states that the sum of the currents entering and leaving a junction in a circuit must be equal to zero. Therefore, the current flowing through each resistor must add up to the total current in the circuit. Yes, this relationship is observed in data obtained from circuits.
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the cantilevered beam is made of a36 steel and is subjected to the loading shown. determine the displacement at b using the method of superposition. for a36 steel beam, the moment of inertia i
Thus using method of superposition, the total displacement is 0.0276.
A36 steel beam is used Cantilever beam is loaded. The moment of inertia is I. For A36 steel beam, I = 6667 in4 (approx.)As per the method of superposition, the total displacement of the beam at point B is given as follows:δtotal = δP + δWWhere,δP is the displacement of point B due to the point loadδW is the displacement of point B due to the uniformly distributed load.
Considering point load,P = 1500 lb. Distance of the point load from point B = 5 ft. Thus, the moment at point B due to point load can be calculated as follows: MBP = PL = 1500 × 5 = 7500 lb-ft. Similarly, considering uniformly distributed load,W = 200 lb/ft. Thus, the moment at point B due to uniformly distributed load can be calculated as follows:Mbw = (wL2)/12Where,L is the length of the beam= 10 ft
Therefore, Mbw = (200 × 102)/12 = 1667 lb-ft (approx.)Thus, total moment at point B,M = MBP + MBW= 7500 + 1667= 9167 lb-ft. Thus, using the formula for deflection of cantilever beam,δP = (PbL2)/(2EI) = (1500 × 52)/(2 × 29 × 106 × 6667) = 0.0026 inδW = (WbL3)/(3EI) = (200 × 5103)/(3 × 29 × 106 × 6667) = 0.024 in
Therefore, the displacement at point B is 0.0276 in.
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a point charge q is far from all other charges. at a distance of 2 m from q the electric field is 20n/c. what is the force a charge of 5 coulombs feels
The force a charge of 5 coulombs for a point charge 'q' which is far from all other charges can be calculated by Coulomb's law.
The Coulomb's law states that the force between two point charges is proportional to the product of the charges and inversely proportional to the square of the distance between them:
[tex]F = k * (q_1 * q_2) / r^2[/tex]
where F is the force,
k is Coulomb's constant ([tex]k = 9*10^9[/tex] N m² / C²),
q₁ and q₂ are the charges, and
r is the distance between the charges.
We know that there is only one charge, q, and it is far from all other charges, so we can assume that
q₁ = q and q₂ = 5 C.
We also know that the electric field at a distance of 2 m from q is 20 N/C. The electric field is related to the force per unit charge, so we can use the equation:
[tex]E = F / q_2[/tex]
Therefore To find the force F acting on a charge q₂ at that distance.
Rearranging this equation in terms of F, we get:
[tex]F = E * q_2[/tex]
Substituting the values we have, we get:
F = 20 N/C * 5 C = 100 N
Therefore, a charge of 5 coulombs would feel a force of 100 N due to the point charge q.
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josh punches his open left hand with his right hand. which statement is true about the forces his two hands exert on each other?
Josh's left and right hands exert equal and opposite forces on each other when he punches his open left hand with his right hand.
This means that when his right-hand pushes on his left hand, his left hand also pushes on his right hand with the same force.
This is Newton's Third Law of Motion:
"For every action, there is an equal and opposite reaction."
The magnitude of the forces exerted by both hands will be the same, but they will act in opposite directions. The force that Josh's right hand exerts on his left hand will be directed to the left, while the force that his left hand exerts on his right hand will be directed to the right.
As a result, the net force on both hands will be zero, as the two forces cancel each other out.
In summary, Josh's hands will be exerting equal and opposite forces on each other according to Newton's Third Law of Motion.
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stop to think 5.5 an elevator suspended by a cable is moving upward and slowing to a stop. which free-body diagram is correct?
When an elevator that is suspended by a cable slows down to a stop and is moving upward, the free-body diagram that is correct is A. shows that the net force acting on the elevator is in the downward direction.
The weight of the elevator, which is the force of gravity acting on it, is pulling it down. The upward force being exerted by the cable is also indicated in the free-body diagram. When the elevator slows down, the tension in the cable decreases, which causes the elevator to slow down. Finally, when the elevator comes to a halt, the tension in the cable equals the weight of the elevator, and the net force acting on the elevator is zero.
A free-body diagram is a diagram that shows all of the forces acting on a body. It can also be referred to as a force diagram. Free-body diagrams are used to visually represent the forces that are acting on an object. They aid in the understanding of an object's motion and are frequently used in physics to analyze and comprehend motion.
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two people are yelling at the same time. one yells with an intensity level of 80.0 db, and the other at 90.0 db. what is the total sound intensity level?
The total sound intensity level is approximately 87 dB.
When two sounds with different intensities are present simultaneously, the total sound intensity level is found by adding the individual sound intensity levels in decibels (dB) using the following equation,
L_total = 10 log10(I_total/I_0)
where L_total is the total sound intensity level, I_total is the total sound intensity, and I_0 is the reference sound intensity (usually taken as 10^-12 W/m^2).
In this case, we have two sounds with intensity levels of 80.0 dB and 90.0 dB. To find the total sound intensity level, we first need to convert each intensity level to sound intensity,
I_1 = I_0 10^(L_1/10) = (10^-12 W/m^2) 10^(80.0/10) = 10^-5 W/m^2
I_2 = I_0 10^(L_2/10) = (10^-12 W/m^2) 10^(90.0/10) = 10^-4 W/m^2
where L_1 and L_2 are the intensity levels of the two sounds in dB.
The total sound intensity is the sum of these two sound intensities,
I_total = I_1 + I_2 = 10^-5 W/m^2 + 10^-4 W/m^2 = 1.1 x 10^-4 W/m^2
L_total = 10 log10(I_total/I_0) = 10 log10(1.1 x 10^-4/10^-12) ≈ 87 dB
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A bar magnet is falling through a loop of wire with constant velocity. The north pole enters first. As the south pole
leaves the loop of wire, the induced current (as viewed from above) will be in which direction?
a) is counterclockwise.
b) is along the length of the magnet
c) is zero
d) is clockwise
As the south pole leaves the loop of wire, the induced current (as viewed from above) will be in the clockwise direction.
Whenever a magnet is moved near a closed circuit or wire loop, an emf (electromotive force) is generated in the conductor. When the magnet moves in and out of the coil or loop, the magnitude and direction of this voltage changes, generating an induced current. This is referred to as Faraday's law of electromagnetic induction, which states that an emf is induced in a closed conductor when the magnetic flux through the surface enclosed by the conductor changes over time.
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A skydiver of mass 95kg ,before opening his parachute, falls at t1 with V1= 11m/s and at t2 with t2 v2=27m/s; supposing friction is zero, find the distance covered between t1 and t2
The skydiver covered a distance of approximately 94.9 meters before opening his parachute between t1 and t2, assuming no air resistance or friction.
v = final velocity = v2 = 27 m/s
u = initial velocity = v1 = 11 m/s
a = acceleration = g = 9.8 m/[tex]s^2[/tex]
s = (v² - u²) / 2a
s = (27² - 11²) / (2 x 9.8) = 94.9 meters
Resistance measures an item's potential to impede the drift of electrical present-day through it. it's far measured in ohms (Ω). Resistance is decided by way of the bodily residences of an item, along with its dimensions, material, and temperature. while electric-powered present-day flows thru a conductor, it encounters resistance that slows down its float. This resistance is as a result of the collisions among electrons and the atoms inside the conductor.
Resistance can be laid low with changes inside the bodily properties of the conductor, such as duration, cross-sectional region, or temperature. an extended or narrower conductor may have higher resistance, even as a much broader conductor could have decreased resistance. understanding resistance is critical for designing and working electrical circuits. with the aid of controlling the resistance of a circuit, engineers can make sure that the appropriate amount of current flows to electricity the devices linked to it.
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Two aircraft are flying toward each other at the same speed. They each emit a 800 HZ whine. what speed (km/hr) must each aircraft have an order that pitch they both hear is 2 times the emitted frequency. Hint: the speed of sound is 343m/s
Each aircraft must be moving at a speed of 85.75 km/hr towards each other to hear a pitch that is 2 times the emitted frequency.
What is frequency ?
Frequency is a physical quantity that describes the number of occurrences of a repeating event per unit of time. It is often measured in Hertz (Hz), which represents the number of cycles or vibrations per second.
In the context of waves, such as sound waves or electromagnetic waves, frequency refers to the number of complete cycles of the wave that occur in one second. A high frequency wave has more cycles per second than a low frequency wave.
Frequency is also an important concept in physics, particularly in the study of oscillations and waves. It is used to describe the behavior of systems that oscillate or vibrate, such as a simple pendulum or a guitar string. In these cases, the frequency of the oscillation is related to the natural frequency of the system, which is determined by its mass, stiffness, and other properties.
When two aircraft are moving towards each other, the sound waves from each aircraft are compressed, leading to a higher pitch than the emitted frequency. The pitch heard by the pilots of the aircraft can be calculated using the following formula:
Pitch heard = Emitted frequency * (Speed of sound + Speed of observer) / (Speed of sound - Speed of source)
Since the two aircraft are flying towards each other at the same speed, we can assume that the speed of one aircraft is x km/hr, and the speed of the other aircraft is also x km/hr. Therefore, the relative speed between the two aircraft is 2x km/hr.
Substituting the values given in the formula, we get:
2 * Emitted frequency = Emitted frequency * (343 + 2x) / (343 - x)
Simplifying this equation, we get:
686 - 2x = 343 + 2x
4x = 343
x = 85.75 km/hr
Therefore, each aircraft must be moving at a speed of 85.75 km/hr towards each other to hear a pitch that is 2 times the emitted frequency.
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how many electrons per second enter the positive end of the battery 2? answer in units of electrons/s.
The number of electrons per second that enter the positive end of a battery can be calculated by the current flowing through the circuit and the time for which it flows.
Therefore, The formula of current is as
I = Q/t
where I is the current,
Q is the charge passing through the circuit, and
t is the time for which the current flows.
Since one electron carries a charge of -1.6 x 10⁻¹⁹Coulombs, we can calculate the number of electrons passing through the circuit using the following formula:
n = Q/e
where n is the number of electrons and
e is the charge on an electron (-1.6 x 10⁻¹⁹ Coulombs).
If we know the current flowing through the circuit and the time for which it flows, we can calculate the number of electrons per second using the following formula:
n/s = I/e
where n/s is the number of electrons per second.
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a weight hanging from a spring will remain hanging until the weight is pulled down and released. when the weight is released the spring will bounce up and down. which of newton's laws explains why the spring will bounce?
This principle can be observed in other everyday scenarios, such as jumping on a trampoline or the recoil of a gun after firing. Newton's Third Law of Motion is a fundamental principle in classical mechanics and explains why the spring will bounce when the weight is released.
The bouncing of the weight when released is explained by Newton's Third Law of Motion, which states that for every action there is an equal and opposite reaction. When the weight is released, the spring exerts an equal and opposite force on the weight, propelling it upwards and causing it to bounce. This is because when the weight is pulled down, it compresses the spring, storing potential energy. When the weight is released, the spring decompresses and the potential energy is released, propelling the weight in the opposite direction.
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