blue objects absorb most wavelengths but reflect light at about 450 nm. this phenomenon relates to .

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Answer 1

The blue objects absorb most wavelengths but reflect light at about 450 nm. This phenomenon relates to the colors of objects.

When the sunlight falls on an object, some of the light is absorbed, and the rest of the light is reflected. Objects appear to be a certain color because they absorb some colors of light and reflect others. Some objects appear blue because they absorb all colors of light except blue.

Blue light has a shorter wavelength than other colors of light, so it is scattered more in the Earth's atmosphere. The sky appears blue because the shorter blue wavelengths are scattered in all directions and are more likely to reach the observer's eye.

The light that is reflected off blue objects is at a wavelength of around 450 nm. When white light passes through a prism, it splits into the colors of the spectrum.

Violet light has the shortest wavelength, and red light has the longest wavelength. Between violet and green, the colors blend to form blue. So, if blue objects reflect light at around 450 nm, that means they reflect blue light.

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Related Questions

A bar magnet is falling through a loop of wire with constant velocity. The north pole enters first. As the south pole
leaves the loop of wire, the induced current (as viewed from above) will be in which direction?
a) is counterclockwise.
b) is along the length of the magnet
c) is zero
d) is clockwise

Answers

As the south pole leaves the loop of wire, the induced current (as viewed from above) will be in the clockwise direction. 

Whenever a magnet is moved near a closed circuit or wire loop, an emf (electromotive force) is generated in the conductor. When the magnet moves in and out of the coil or loop, the magnitude and direction of this voltage changes, generating an induced current. This is referred to as Faraday's law of electromagnetic induction, which states that an emf is induced in a closed conductor when the magnetic flux through the surface enclosed by the conductor changes over time.

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how many electrons per second enter the positive end of the battery 2? answer in units of electrons/s.

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The number of electrons per second that enter the positive end of a battery can be calculated by the current flowing through the circuit and the time for which it flows.

Therefore, The formula of current is as

I = Q/t

where I is the current,

Q is the charge passing through the circuit, and

t is the time for which the current flows.

Since one electron carries a charge of -1.6 x 10⁻¹⁹Coulombs, we can calculate the number of electrons passing through the circuit using the following formula:

n = Q/e

where n is the number of electrons and

e is the charge on an electron (-1.6 x 10⁻¹⁹ Coulombs).

If we know the current flowing through the circuit and the time for which it flows, we can calculate the number of electrons per second using the following formula:

n/s = I/e

where n/s is the number of electrons per second.

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A skydiver of mass 95kg ,before opening his parachute, falls at t1 with V1= 11m/s and at t2 with t2 v2=27m/s; supposing friction is zero, find the distance covered between t1 and t2

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The skydiver covered a distance of approximately 94.9 meters before opening his parachute between t1 and t2, assuming no air resistance or friction.

v = final velocity = v2 = 27 m/s

u = initial velocity = v1 = 11 m/s

a = acceleration = g = 9.8 m/[tex]s^2[/tex]

s = (v² - u²) / 2a

s = (27² - 11²) / (2 x 9.8) = 94.9 meters

Resistance measures an item's potential to impede the drift of electrical present-day through it. it's far measured in ohms (Ω). Resistance is decided by way of the bodily residences of an item, along with its dimensions, material, and temperature. while electric-powered present-day flows thru a conductor, it encounters resistance that slows down its float. This resistance is as a result of the collisions among electrons and the atoms inside the conductor.

Resistance can be laid low with changes inside the bodily properties of the conductor, such as duration, cross-sectional region, or temperature. an extended or narrower conductor may have higher resistance, even as a much broader conductor could have decreased resistance. understanding resistance is critical for designing and working electrical circuits. with the aid of controlling the resistance of a circuit, engineers can make sure that the appropriate amount of current flows to electricity the devices linked to it.

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josh punches his open left hand with his right hand. which statement is true about the forces his two hands exert on each other?

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Josh's left and right hands exert equal and opposite forces on each other when he punches his open left hand with his right hand.

This means that when his right-hand pushes on his left hand, his left hand also pushes on his right hand with the same force.

This is Newton's Third Law of Motion:

"For every action, there is an equal and opposite reaction."

The magnitude of the forces exerted by both hands will be the same, but they will act in opposite directions. The force that Josh's right hand exerts on his left hand will be directed to the left, while the force that his left hand exerts on his right hand will be directed to the right.

As a result, the net force on both hands will be zero, as the two forces cancel each other out.

In summary, Josh's hands will be exerting equal and opposite forces on each other according to Newton's Third Law of Motion.

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how do air masses contribute to the formation of air fronts?

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Air masses contribute to the formation of air fronts because air masses are large bodies of air that have similar characteristics in terms of temperature, humidity, and stability.

When two air masses with different characteristics come into contact, they form a boundary known as an air front. The characteristics of the two air masses determine the type of air front that forms.

There are four types of air fronts: cold fronts, warm fronts, stationary fronts, and occluded fronts.

Cold fronts occur when a cold air mass displaces a warm air mass, causing the warm air to rise and cool, which leads to cloud formation and precipitation. Warm fronts occur when a warm air mass displaces a cold air mass, causing the warm air to rise gradually over the cold air, leading to gradual cloud formation and precipitation. Stationary fronts occur when two air masses with different characteristics meet but do not move, leading to prolonged periods of precipitation. Occluded fronts occur when a cold front overtakes a warm front and lifts the warm air mass off the ground, leading to cloud formation and precipitation.

Air masses play a significant role in the formation of air fronts because they determine the characteristics of the air mass that will form at the boundary between the two air masses. This, in turn, determines the type of air front that will form and the type of weather that will result. For example, a cold, dry air mass coming into contact with a warm, moist air mass will likely result in a cold front and a period of heavy precipitation.

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Which type of engine has a wheel with several blades mounted on a shaft that rotate a shaft when hit with heated air at a high velocity?

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The type of engine that has a wheel with several blades mounted on a shaft that rotates when hit with heated air at a high velocity is called a gas turbine engine.

What is a gas turbine engine?

The gas turbine engine is also known as a combustion turbine engine. A gas turbine engine is a type of internal combustion engine that converts the chemical energy of fuel into mechanical energy, which can be used to power various machines and equipment. The engine works by compressing air and then mixing it with fuel in a combustion chamber, where it is ignited to produce a high-temperature, high-pressure gas stream. This gas stream then flows through a series of turbine blades, causing them to spin, which drives a shaft that is connected to various machines or equipment. As the shaft rotates, it generates mechanical power that can be used for various applications.

Gas turbine engines are commonly used in aircraft, power plants, and marine propulsion.

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a point charge q is far from all other charges. at a distance of 2 m from q the electric field is 20n/c. what is the force a charge of 5 coulombs feels

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The force a charge of 5 coulombs for a point charge 'q' which is far from all other charges can be calculated by Coulomb's law.

The Coulomb's law states that the force between two point charges is proportional to the product of the charges and inversely proportional to the square of the distance between them:

[tex]F = k * (q_1 * q_2) / r^2[/tex]

where F is the force,

k is Coulomb's constant ([tex]k = 9*10^9[/tex] N m² / C²),

q₁ and q₂ are the charges, and

r is the distance between the charges.

We know that there is only one charge, q, and it is far from all other charges, so we can assume that

q₁ = q and q₂ = 5 C.

We also know that the electric field at a distance of 2 m from q is 20 N/C. The electric field is related to the force per unit charge, so we can use the equation:

[tex]E = F / q_2[/tex]

Therefore To find the force F acting on a charge q₂ at that distance.

Rearranging this equation in terms of F, we get:

[tex]F = E * q_2[/tex]

Substituting the values we have, we get:

F = 20 N/C * 5 C = 100 N

Therefore, a charge of 5 coulombs would feel a force of 100 N due to the point charge q.

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g which of the following wavelengths of light is most likely to cause a sunburn? explain your answer. a. 700 nm b. 400 nm c. 200 nm

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Answer:

(b) 400 nm is the far ultraviolet (violet) in the visible spectrum

The shorter wavelengths are more likely to cause sunburn.

200 nm is probably too short to be transmitted by the atmosphere

2. how many times a minute does a boat bob up and down on ocean waves that have a wavelength of 36.0 m and a propagation speed of 4.80 m/s?

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The boat will bob up and down on ocean waves that have a wavelength of 36.0 m and a propagation speed of 4.80 m/s once every 7.50 seconds.

To solve the given question, we must use the formula:

n= v/f

Where: v is the velocity of the wave (in m/s)f is the frequency of the wave (in Hz)n is the number of cycles per second

Therefore, the frequency of the wave (in Hz) can be calculated by using the formula:

f= v/λ

where: v is the velocity of the wave (in m/s)λ is the wavelength of the wave (in m)

The frequency of the wave is 0.1333 Hz (approx).

Now, the number of cycles per second (n) is: n = v/λ

We can solve for n by dividing the velocity of the wave by the wavelength of the wave.

Therefore,

n= v/λ= (4.80 m/s) / (36.0 m)= 0.1333 Hz

So, the boat bob up and down 0.1333 times a minute on ocean waves that have a wavelength of 36.0 m and a propagation speed of 4.80 m/s.

1 Hz = 60 seconds,

0.1333 Hz = 7.50 seconds.

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a pendulum is measured to swing back and forth 15 times in 10 seconds. what is the length of the string?

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The length of the string is 0.48 m.

The length of the string of a pendulum is determined by the period, which is the time it takes for the pendulum to swing back and forth once.

String length = (Gravitational acceleration x (Period)2) / (4π2)

Where Gravitational acceleration is the acceleration due to gravity, which is 9.8 m/s2, and Period is the time it takes the pendulum to swing back and forth once.

The period is 10 seconds divided by 15 swings, or 0.67 seconds.

String length = (9.8 m/s2 x (0.67 s)2) / (4π2) = 0.48 m.

Therefore, the length of the string is 0.48 m.

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two stationary point charges q1 and q2 are shown in the figure along with a sketch of some field linesrepresenting the electric field produced by them. what can you deduce from the sketch?

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From the sketch, we can deduce that the two charges q1 and q2 are of opposite signs, as field lines start at the positive charge q1 and end at the negative charge q2. The field lines also indicate that the magnitude of the electric field produced by q1 is larger than that of q2.

Additionally, the field lines show that the electric field lines near the charges are denser, indicating a stronger electric field intensity near the charges. The direction of the electric field points from q1 to q2, which is consistent with the direction of the force that a positive test charge would experience if placed in the field. The field lines also show that the electric field is radial, i.e., the field lines point directly away from or towards each charge in a straight line, which is a characteristic of the electric field produced by a point charge. Finally, the density of the field lines decreases with distance from the charges, indicating that the electric field strength decreases with distance from the charges, following an inverse-square law.

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when you switch off the lights in your room at night, the walls, ceiling, and floor are at a temperature of about 300 k. why are you not dazzled by the radiation that they emit?

Answers

Answer:

Explanation:

Because by Wien's Law, they emit strongest in infrared and human eyes cannot see infrared radiation

how fast is it moving when it reaches the top of its trajectory if the projectile is fired at a speed of 138 and an upward angle of 65 degrees?

Answers

The projectile will be moving at a speed of 57.21 m/s when it reaches the top of its trajectory.

When a projectile is fired at a speed of 138 and an upward angle of 65 degrees, the speed at the top of the trajectory can be calculated. To solve this problem, you need to understand some basic physics concepts. Here's how you can solve this problem:
1. First, identify the given values and write them down:
Initial velocity (u) = 138 m/s
Angle of projection (θ) = 65 degrees
Acceleration due to gravity (g) = 9.81 m/s²
2. Now, break down the initial velocity into its horizontal and vertical components:
Initial velocity in the horizontal direction = u cos θ
Initial velocity in the vertical direction = u sin θ
3. Use the equation of motion to calculate the time taken by the projectile to reach the top of its trajectory:
u sin θ = gt/2
t = 2u sin θ/g
4. Use the time obtained in step 3 to calculate the velocity at the top of the trajectory:
v = u cos θ
Where,
v = final velocity
u = initial velocity
θ = angle of projection
5. Substitute the given values in the equation to get the final answer:
v = u cos θ
v = 138 cos 65
v = 57.21 m/s
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a rock attached to a string swings in a vertical circle. which free body diagram could correctly describe the force(s) on the rock when the string is in one possible horizontal position?

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The correct free body diagram that describes the forces on the rock when the string is in one possible horizontal position is B.

As the rock swings in a vertical circle, there are a number of forces acting upon it. These forces are gravity, tension and centrifugal force. When the rock is in a horizontal position, its weight will be perpendicular to the tension force. This makes the tension force the only force acting upon the rock in the horizontal position.

As a result, the correct free body diagram that describes the forces acting on the rock when the string is in one possible horizontal position is B.

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Two aircraft are flying toward each other at the same speed. They each emit a 800 HZ whine. what speed (km/hr) must each aircraft have an order that pitch they both hear is 2 times the emitted frequency. Hint: the speed of sound is 343m/s

Answers

Each aircraft must be moving at a speed of 85.75 km/hr towards each other to hear a pitch that is 2 times the emitted frequency.

What is frequency ?

Frequency is a physical quantity that describes the number of occurrences of a repeating event per unit of time. It is often measured in Hertz (Hz), which represents the number of cycles or vibrations per second.

In the context of waves, such as sound waves or electromagnetic waves, frequency refers to the number of complete cycles of the wave that occur in one second. A high frequency wave has more cycles per second than a low frequency wave.

Frequency is also an important concept in physics, particularly in the study of oscillations and waves. It is used to describe the behavior of systems that oscillate or vibrate, such as a simple pendulum or a guitar string. In these cases, the frequency of the oscillation is related to the natural frequency of the system, which is determined by its mass, stiffness, and other properties.

When two aircraft are moving towards each other, the sound waves from each aircraft are compressed, leading to a higher pitch than the emitted frequency. The pitch heard by the pilots of the aircraft can be calculated using the following formula:

Pitch heard = Emitted frequency * (Speed of sound + Speed of observer) / (Speed of sound - Speed of source)

Since the two aircraft are flying towards each other at the same speed, we can assume that the speed of one aircraft is x km/hr, and the speed of the other aircraft is also x km/hr. Therefore, the relative speed between the two aircraft is 2x km/hr.

Substituting the values given in the formula, we get:

2 * Emitted frequency = Emitted frequency * (343 + 2x) / (343 - x)

Simplifying this equation, we get:

686 - 2x = 343 + 2x

4x = 343

x = 85.75 km/hr

Therefore, each aircraft must be moving at a speed of 85.75 km/hr towards each other to hear a pitch that is 2 times the emitted frequency.

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when lighted, a 100-watt light bulb operating on a 110-volt household circuit has a resistance closest to

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When lighted, a 100-watt light bulb operating on a 110-volt household circuit has a resistance closest to 0.99 ohms.

Resistance refers to the electrical property of a circuit component, such as a light bulb, that resists the flow of electrical current through it.

Ohm's law is a fundamental principle in electrical engineering that relates the resistance, voltage, and wattage in a circuit. It states that the resistance (R) is equal to the voltage (V) divided by the wattage (W).

W = 100 watts, V = 110 volts.

Use Ohm’s law to calculate the resistance (R):

R = V/W = 110/100 = 0.99 ohms.


Therefore, when a 100-watt light bulb is operating on a 110-volt household circuit, its resistance is approximately 0.99 ohms.

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how large must the coefficient of static friction be between the tires and the road if a car is to round a level curve of radius 145 m at a speed of 130 km/h ?

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The coefficient of static friction between the tires and the road if a car is to round a level curve of radius 145 m at a speed of 130 km/h is 4.64

Whenever the object rotаtes аround the curved pаth then а net force аcts on the object pointing towаrds the center of а circulаr pаth аnd it is cаlled а centripetаl force. Mаthemаticаlly, we cаn write;

Centripetаl Force = [tex]\frac{mv^{2} }{r}[/tex]

where m is the mass of the body, v is the velocity of the body, and r is the radius of rotation.

We are given:

Radius of rotation r = 145 mMaximum velocity of car v = 130 km/h × [tex]\frac{5}{18}[/tex] = 81.25 m/sm be the mass of the carμs be the coefficient of static friction

Since the car is making circular motion, therefore, necessary centripetal force is provided by the frictional force.

frictional force = centripetal force

μsmg = [tex]\frac{mv^{2} }{r}[/tex]

μs = [tex]\frac{v^{2} }{rg}[/tex]

μs = [tex]\frac{81.25^{2} }{145.9.81}[/tex]

μs = 4.64

Therefore, the coefficient of static friction between the tires of the car and the road surface is 4.64.

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two people are yelling at the same time. one yells with an intensity level of 80.0 db, and the other at 90.0 db. what is the total sound intensity level?

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The total sound intensity level is approximately 87 dB.

When two sounds with different intensities are present simultaneously, the total sound intensity level is found by adding the individual sound intensity levels in decibels (dB) using the following equation,

L_total = 10 log10(I_total/I_0)

where L_total is the total sound intensity level, I_total is the total sound intensity, and I_0 is the reference sound intensity (usually taken as 10^-12 W/m^2).

In this case, we have two sounds with intensity levels of 80.0 dB and 90.0 dB. To find the total sound intensity level, we first need to convert each intensity level to sound intensity,

I_1 = I_0 10^(L_1/10) = (10^-12 W/m^2) 10^(80.0/10) = 10^-5 W/m^2

I_2 = I_0 10^(L_2/10) = (10^-12 W/m^2) 10^(90.0/10) = 10^-4 W/m^2

where L_1 and L_2 are the intensity levels of the two sounds in dB.

The total sound intensity is the sum of these two sound intensities,

I_total = I_1 + I_2 = 10^-5 W/m^2 + 10^-4 W/m^2 = 1.1 x 10^-4 W/m^2

L_total = 10 log10(I_total/I_0) = 10 log10(1.1 x 10^-4/10^-12) ≈ 87 dB

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a weight hanging from a spring will remain hanging until the weight is pulled down and released. when the weight is released the spring will bounce up and down. which of newton's laws explains why the spring will bounce?

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This principle can be observed in other everyday scenarios, such as jumping on a trampoline or the recoil of a gun after firing.  Newton's Third Law of Motion is a fundamental principle in classical mechanics and explains why the spring will bounce when the weight is released.

The bouncing of the weight when released is explained by Newton's Third Law of Motion, which states that for every action there is an equal and opposite reaction. When the weight is released, the spring exerts an equal and opposite force on the weight, propelling it upwards and causing it to bounce. This is because when the weight is pulled down, it compresses the spring, storing potential energy. When the weight is released, the spring decompresses and the potential energy is released, propelling the weight in the opposite direction.

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stop to think 5.5 an elevator suspended by a cable is moving upward and slowing to a stop. which free-body diagram is correct?

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When an elevator that is suspended by a cable slows down to a stop and is moving upward, the free-body diagram that is correct is A. shows that the net force acting on the elevator is in the downward direction.

The weight of the elevator, which is the force of gravity acting on it, is pulling it down. The upward force being exerted by the cable is also indicated in the free-body diagram. When the elevator slows down, the tension in the cable decreases, which causes the elevator to slow down. Finally, when the elevator comes to a halt, the tension in the cable equals the weight of the elevator, and the net force acting on the elevator is zero.

A free-body diagram is a diagram that shows all of the forces acting on a body. It can also be referred to as a force diagram. Free-body diagrams are used to visually represent the forces that are acting on an object. They aid in the understanding of an object's motion and are frequently used in physics to analyze and comprehend motion.

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what are some of the challenges associated with using solar energy as a primary source of electricity,

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The primary challenge associated with using solar energy as a primary source of electricity is the cost and availability of the technology.

Cost: One of the significant challenges of solar energy is its cost. Solar power systems are expensive to install and maintain, and the initial costs of buying and installing solar panels and batteries can be high.

Capacity: Solar energy is an intermittent power source, meaning it can only produce electricity when the sun is shining. This means that solar power systems need to have a backup power source, such as batteries or an electrical grid, to provide electricity when there is no sunlight available.

Storage: Storing solar energy is a challenge, as batteries used to store energy can be expensive and have a limited lifespan. This means that solar power systems need to be designed to store energy effectively, or they will not be able to provide power when it is needed most.

Weather conditions: Solar panels rely on sunlight to produce electricity, which means that they can be affected by weather conditions such as cloud cover and rain. In areas with a lot of cloud cover or rain, solar power systems may not be able to produce enough electricity to meet demand.

Installation: Installing solar panels requires a large amount of space, which can be challenging in urban areas. Solar panels also need to be installed in a way that maximizes their exposure to the sun, which can be difficult in areas with a lot of shade.

Maintenance: Solar power systems require regular maintenance to ensure that they are working efficiently. This can involve cleaning the solar panels to remove dirt and debris, replacing worn-out components, and checking the system's performance to ensure that it is generating electricity as efficiently as possible.

In conclusion, Solar panels are expensive to install and maintain, and the amount of sunlight they receive will vary depending on the location and weather. Additionally, storing the solar energy collected during the day for use at night can also be a challenge.

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isaac's body plunges to a depth of 2.5m below the water surface before stopping. determine the average force of water resistance experienced by his body

Answers

Isaac encountered a water resistance force of 24,525 N on average as he dived to a depth of 2.5m beneath the water's surface.

Isaac's body experienced an average force of water resistance due to the water surrounding it. This force is determined by the volume and density of the water, as well as the acceleration of his body while it is moving.

First, we need to calculate the volume of the displaced water. We can use the formula:

V = Ah

where A is the surface area of the object and h is the depth to which it sinks. Since we don't have the surface area of Isaac's body, we can assume it to be 1 square meter for simplicity.

V = 1 * 2.5 = 2.5 cubic meters

To calculate the average force of water resistance experienced by his body, we can use the equation

Force = Volume x Density x Acceleration.

Using this equation, we can calculate the force of water resistance as follows:
Force = 2.5m^3 x 1000kg/m^3 x 9.81m/s^2
Force = 24,525 N.

Therefore, Isaac experienced an average force of water resistance of 24,525 N while his body was plunging to a depth of 2.5m below the water's surface.

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two 4.0cm*4.0cm metal plates are separated by a 0.20-mm-thick piece of teflon. a. what is the capacitance? b. what is the maximum potential difference between the plates?

Answers

The capacitance of two metal plates separated by a 0.20-mm-thick is approximately 0.25 pF  and the maximum potential difference between the plates is 8.4 kV.

a. The capacitance of two metal plates separated by a 0.20-mm-thick piece of Teflon is approximately 0.25 pF (picofarad).

b. The maximum potential difference between the two metal plates is determined by the permittivity of the dielectric material, which in this case is Teflon.

The permittivity of Teflon is about 2.1 and the capacitance of the plates is 0.25 pF, so the maximum potential difference between the plates can be calculated using the equation:

Vmax = (permittivity * Capacitance) / Area.

Therefore, the maximum potential difference between the plates is 8.4 kV.

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according to our textbook, what is the best way to defend ourselves against an asteroid which is on course to collide with the earth in 7 years?

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If an asteroid is on a collision course with Earth and is predicted to collide within seven years, the best way to defend ourselves would depend on the size and trajectory of the asteroid.

What is an asteroid ?

An asteroid is a small, rocky object that orbits the Sun. Most asteroids are found in the asteroid belt, a region between the orbits of Mars and Jupiter. Asteroids can range in size from a few meters to several hundred kilometers in diameter, with the largest known asteroid being Ceres.

Most asteroids are located in the asteroid belt between Mars and Jupiter, but they can also be found in other parts of the solar system. Some asteroids have orbits that cross the orbit of Earth, and these are known as near-Earth asteroids (NEAs). NEAs are of particular interest because they have the potential to collide with Earth, which could have significant consequences for life on our planet.

Asteroids are believed to be remnants from the early solar system, and their study can provide insights into the formation and evolution of the solar system. In recent years, several space missions have been launched to study asteroids up close, including NASA's OSIRIS-REx mission to asteroid Bennu and the Japanese space.

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how hard must each player pull to drag the coach at a steady 2.0 m/s ? express your answer with the appropriate units.

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Each player must pull with a force of 1250 N to drag the coach at a steady 2.0 m/s.

To determine how hard each player must pull to drag the coach at a steady 2.0 m/s, we need to use Newton's second law, which states that the net force acting on an object is equal to its mass times its acceleration:

Fnet = m * a

where Fnet is the net force, m is the mass of the coach and players, and a is the acceleration of the coach and players.

Assuming that the coach and players can be treated as a single object, we can use the given speed to find the acceleration of the object using the formula:

a = v² / (2 * d)

where v is the speed (2.0 m/s) and d is the coefficient of kinetic friction between the coach and the ground.

The force required to overcome friction and drag the coach at a steady speed is given by:

Ffriction = friction coefficient * Fnormal

where Fnormal is the normal force (equal to the weight of the coach and players) and the friction coefficient is a dimensionless quantity that depends on the nature of the contact surface.

Assuming a friction coefficient of 0.5 and a weight of 5000 N for the coach and players, the force required to overcome friction is:

F_friction = (0.5) * (5000 N) = 2500 N

The net force required to move the coach and players at a steady 2.0 m/s is therefore:

Fnet = Ffriction = 2500 N

Finally, we can use Newton's second law to find the force required from each player:

Fnet = m * a

2500 N = (m_coach + m_players) * (v² / (2 * d))

Solving for the mass (m_coach + m_players), we get:

m_coach + m_players = (2500 N * 2 * d) / v²

Assuming a value of 0.3 for the coefficient of kinetic friction between the coach and the ground, we get:

m_coach + m_players = (2500 N * 2 * 0.3) / (2.0 m/s)² = 562.5 kg

Therefore, the force required from each player is:

Fplayer = Fnet / 2 = 1250 N

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A solid cylinder of mass M = 1.25 kg and radius R = 13.5 cm pivots on a thin fixed frictionless bearing a string wrapped around the cylinder pulls downward with a force of F = 7.259 N

What is the magnitude of the angular acceleration of the cylinder?
86.03259 rad/s^2

Consider that instead of force F, a block with mass 0.74 kg with force = 7.259 N is attached to the cylinder with a mass less string.
What is now the magnitude of the angular acceleration of the cylinder
39.3943 rad/s^2
How far does the mass M travel downward before T equals 0.49S and T equals 0.69 S.
0.62755 m
The cylinder is changed to one with the same mass and radius but a different moment of inertia starting from mass starting from rest. The mass is now moved. The distance of 0.448 mass in the time interval of 0.47 seconds.
Find the Inertia of the new cylinder​

Answers

The inertia of the new cylinder is  0.0566 kgm². Other answers provided are correct.

How to find inertia?

The moment of inertia of the new cylinder can be calculated using the formula:

I = (M × d²) / (4 × Δθ)

Where:

M = mass of the cylinder

d = distance moved by the mass

Δθ = change in angular displacement (in radians)

Substituting the given values:

I = (1.25 × 0.448²) / (4 × 0.47)

I = 0.0566 kgm²

Therefore, the moment of inertia of the new cylinder is 0.0566 kgm².

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You're designing an external defibrillator that discharges a capacitor through the patient's body, providing a pulse that stops ventricular fibrillation. Specifications call for a capacitor storing 250 J of energy; when discharged through a body with R = 48 Ω transthoracic resistance, the capacitor voltage is to drop to half its initial value in 10 ms.
A) Determine the capacitance (to the nearest ) 10 μF).
B) Determine initial capacitor voltage (to the nearest 100 V) that meet these specs.
I need both correct answers to 2 significant figures.

Answers

a..... 1.04 x 10⁻⁴ Vi

b.... 9500 V

A) Determine the capacitance (to the nearest 10 μF).

First, we should identify the formula that we will use to solve the problem.

The formula that relates to capacitance is:

C = 2E / V². Where C is the capacitance in farads, E is the energy stored in joules, and V is the voltage across the capacitor in volts.

Converting the energy to joules, we have: E = 250J.

Now we know that the voltage needs to drop to half of its initial value in 10 ms. We can use the following formula to calculate the capacitance: C = R x t / ln(Vi / Vf) where R is the resistance in ohms, t is the time in seconds, Vi is the initial voltage, and Vf is the final voltage, which is half of the initial voltage.

B) Plugging in the given values, we get:

C = 48 x 0.01 / ln(Vi / (Vi / 2))Simplifying and solving for capacitance, we get:

C = 1.04 x 10⁻⁴ ViNow we can use the energy formula to solve for Vi:Vi = √(2E / C)

Plugging in the given values, we get:Vi = √(2 x 250 / 1.04 x 10⁻⁴)Simplifying and solving for Vi, we get:Vi = 9469 V

Therefore, the capacitance that meets these specifications is 100 μF and the initial capacitor voltage that meets these specifications is 9500 V, to the nearest 100 V.

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a 100 cm diameter propeller blade, similar to the blade in example 4.15, is attached to a motor spinning at a constant rate. what is true about the radial (centripetal) acceleration and the tangential acceleration at the end of the blade?

Answers

The true statements about the radial (centripetal) acceleration and the tangential acceleration at the end of the blade are: the radial acceleration is non-zero the tangential acceleration is zero

The radial acceleration is non-zero and the tangential acceleration is zero. This is because, the radial acceleration is determined by the formula, ar = (v²)/r

where ar is the radial acceleration, v is the velocity and r is the radius. Thus, since the propeller blade is spinning at a constant rate, the velocity v is constant.

Therefore, the radial acceleration is constant and non-zero.

The tangential acceleration, on the other hand, is given by at = rα

where at is the tangential acceleration and α is the angular acceleration. Since the blade is spinning at a constant rate, the angular acceleration is zero. Therefore, the tangential acceleration is zero.

So, the correct option is the radial acceleration is non-zero and the tangential acceleration is zero.

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you are trying to solve a physics problem and the first thing you try doesnt workyou try another and then another and eventually you figure it out what is this method called

Answers

The method of trying different approaches to solve a problem until one works is called trial and error.

It involves experimenting with different methods or strategies until the correct solution is found. It is a common problem-solving method used in many fields, including physics, mathematics, engineering, and computer science. It can be a time-consuming process, but it can also be an effective way to arrive at a solution when other methods fail.

What is trial and error method?

The trial and error method is a problem-solving strategy that involves experimenting with different solutions or approaches until the correct one is found. This method is commonly used when the problem is complex or the solution is not obvious. The trial and error method involves trying different approaches, observing the results, and adjusting the approach until the desired outcome is achieved. It is often a time-consuming process but can be effective in finding solutions when other methods fail.

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the cantilevered beam is made of a36 steel and is subjected to the loading shown. determine the displacement at b using the method of superposition. for a36 steel beam, the moment of inertia i

Answers

Thus using method of superposition, the total displacement is 0.0276.

A36 steel beam is used Cantilever beam is loaded. The moment of inertia is I. For A36 steel beam, I = 6667 in4 (approx.)As per the method of superposition, the total displacement of the beam at point B is given as follows:δtotal = δP + δWWhere,δP is the displacement of point B due to the point loadδW is the displacement of point B due to the uniformly distributed load.

Considering point load,P = 1500 lb. Distance of the point load from point B = 5 ft. Thus, the moment at point B due to point load can be calculated as follows: MBP = PL = 1500 × 5 = 7500 lb-ft. Similarly, considering uniformly distributed load,W = 200 lb/ft. Thus, the moment at point B due to uniformly distributed load can be calculated as follows:Mbw = (wL2)/12Where,L is the length of the beam= 10 ft

Therefore, Mbw = (200 × 102)/12 = 1667 lb-ft (approx.)Thus, total moment at point B,M = MBP + MBW= 7500 + 1667= 9167 lb-ft. Thus, using the formula for deflection of cantilever beam,δP = (PbL2)/(2EI) = (1500 × 52)/(2 × 29 × 106 × 6667) = 0.0026 inδW = (WbL3)/(3EI) = (200 × 5103)/(3 × 29 × 106 × 6667) = 0.024 in

Therefore, the displacement at point B is 0.0276 in.

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