Write the four terms of the sequence f(n) = 12 + 3(n-1)



9,12,15,18,21



12,15,18,21,24



-12,-9,-6,-3,0

Explanation:

The given arithmetic sequence is of the form

a+d(n-1)

where 'a' is the first term and d is the common difference

In the case of

12+3(n-1)

we have a = 12 as our first term and d = 3 as the common difference. This means we start with 12 and add on 3 to each term to get the next one

12+3 = 15

15+3 = 18

18+3 = 21

21+3 = 24

and so on.

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