The cumulative infiltration and infiltration rate on a silty clay soil after one hour of rainfall at 1cm/h with initial effective saturation of 20 percent are 252 cm and 4.21 cm/h, respectively.
To calculate the cumulative infiltration and the infiltration rate on a silty clay soil after one hour of rainfall at 1cm/h if the initial effective saturation is 20 percent, we need to first calculate the cumulative infiltration (Icum) and infiltration rate (f). The cumulative infiltration is given by the equation: Icum = h0 + ∫f (dt). Here, h0 is negligible and ∫f (dt) = f x t. So, Icum = f x t.
The infiltration rate can be calculated using the Kostiakov equation: f = K x t1/2. Here, K is the Kostiakov coefficient, which is a function of the initial effective saturation (Si). For a silty clay soil, K = 0.0026 x Si0.5 (cm/min1/2). Thus, in this case, K = 0.0026 x 200.5 = 0.164 cm/min1/2. Since the rainfall intensity is 1 cm/h, t = 1 hour = 60 min. So, the infiltration rate, f = 0.164 x 601/2 = 4.21 cm/h. The cumulative infiltration is Icum = 4.21 x 60 = 252 cm. So, the answers are 252 cm and 4.21 cm/h, respectively.
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3
Biocatalysis helps create flavors and scents through what process?
altering DNA
chemical reactions
purifying components in a formula
aiding with the decomposition process
Answer:
its B. ima keep it short its B
Explanation
how does the sovent drainage and waste system operate without the venting piping used in traditional systems?
The solvent drainage and waste system operates without venting piping by using a combination of air flow and pressure.
Instead of relying on venting piping to exhaust fumes and waste, the system takes in air from the atmosphere and circulates it through the system with a blower or compressor. This creates a pressure difference that drives the solvent out of the system, taking any remaining waste with it. The pressure also keeps odors from escaping and prevents the system from backflowing.
Drainage is the removal of a mass of water either naturally or artificially from the surface or subsurface from a place.
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what is an impact, ballistic or creep ripple? what is the length of these ripples relative to their heights? how does this ratio compare to those for aerodynamic and hydrodynamic ripples?
Impact, ballistic, and creep ripples are all types of surface features that can occur on materials subjected to different types of stresses.
Impact ripples are formed when a material is struck by a projectile or another object. Ballistic ripples are similar but are specifically formed by high-velocity projectiles. Creep ripples, on the other hand, are formed when a material is subjected to a constant stress over a long period of time, causing it to slowly deform.
The length of these ripples relative to their heights can vary depending on the specific material and conditions. However, in general, the ripples tend to have a relatively short wavelength compared to their height.
In comparison, aerodynamic and hydrodynamic ripples are formed by the flow of air or water over a surface. These ripples tend to have a much longer wavelength compared to their height, with the length-to-height ratio typically ranging from several to tens of thousands. This is because the fluid flow over the surface is generally much smoother and less abrupt than the stresses that cause impact, ballistic, and creep ripples.
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what is the purpose of the ground symbol used in electrical circuit diagrams? group of answer choices to show that there is a return path for the current between the source of electrical energy and the load. to show the source of electrical energy for the load. to show that there is common bus for connection of the source of electrical energy to the load.
Answer:
To show that there is a return path for the current between the source of electrical energy and the load.
the equation used to determine the approximate amount of of critical stress to propagate a crack is known as the friffith equation the griffith equation is
The Griffith equation is used to calculate the approximate amount of critical stress necessary to propagate a crack. The formula for the equation is K = √(πE/2Y), where E is Young's modulus, and Y is the geometrical factor, which depends on the shape of the crack.
The equation is based on the energy release rate for crack propagation and was developed by A.A. Griffith in 1921. The equation is used to calculate the stress intensity factor (K) for a crack in an elastic material.
The Griffith equation is important for engineers as it can be used to estimate how much stress a material can withstand before it will fracture. This is important when designing components or structures that will be subject to loading or fatigue. Additionally, the equation can be used to calculate the stress concentration factor (Kt) at a point of crack initiation.
In conclusion, the Griffith equation is an important equation used to calculate the approximate amount of critical stress necessary to propagate a crack. This equation can be used by engineers to ensure that their designs are able to withstand the expected loads, as well as calculate stress concentration factors.
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which safety hazard are firefighters most likely to find in the space between the ceiling and the roof?
Firefighters are most likely to find the following safety hazards in the space between the ceiling and the roof: accumulation of combustible material, poor ventilation, and exposure to hazardous chemicals.
Accumulation of combustible materials such as wood, paper, insulation, and other debris can provide fuel for a fire, which can be difficult to contain in a confined space like the one between a ceiling and a roof.
Poor ventilation in this space can make it difficult for firefighters to breathe, and they can be exposed to hazardous chemicals such as asbestos, lead, and dust. Firefighters have to be careful with that.
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Which is a small plain text file that a website might place on your local drive?
Answer:A cookie
Explanation:To track interests.
Please give a detail explanation, thank you
1) When solving the impact problems, we should always assume that during an impact between two bodies, there is no permanent deformation in the bodies.
True or false
2) If a semi-truck collides head-on with a mini car, which one will exert more force?
Semi-truck on the mini car
Mini car on the semi-truck
There is no force exerted
Both vehicles will exert equal force
The given statement "When solving the impact problems, we should always assume that during an impact between two bodies, there is no permanent deformation in the bodies" is False and there is usually some amount of permanent deformation during an impact when semi-truck collides head-on with a mini car.
The statement is False because In reality, there is usually some amount of permanent deformation that occurs during an impact, especially if the impact is severe. However, in many cases, the amount of deformation may be negligible or can be ignored for simplicity in calculations.Therefore the statement is False.
If a semi-truck collides head-on with a mini car then According to Newton's Third Law of Motion, every action has an equal and opposite reaction. Therefore, both the semi-truck and the mini car will exert equal force on each other during a head-on collision. The force experienced by each vehicle will depend on factors such as their mass, speed, and the duration of the impact. However, it is likely that the semi-truck, being much larger and heavier than the mini car, will experience less of a change in velocity than the mini car and therefore will exert more force on the smaller vehicle.
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