Determine if the following ordered pairs are solutions to the equation 3x + y = 12.
(2,5)
(4,0)
(0,6)
Is (2,5) a solution to the equation 3x+y=12? Select the correct choice below and fill in the answer box to complete your
choice.
OA. Yes, because when 2 is substituted for x and 5 is substituted for y, simplifying the left side results in.
equals the right side.
OB. No, because when 2 is substituted for x and 5 is substituted for y, simplifying the left side results in
does not equal the right side.
A. Yes, because when 4 is substituted for x and 0 is substituted for y, simplifying the left side results in
equals the right side.
which
Is (4,0) a solution to the equation 3x + y = 12? Select the correct choice below and fill in the answer box to complete your
choice.
OB. No, because when 4 is substituted for x and 0 is substituted for y, simplifying the left side results in
does not equal the right side.
which
which
which
Is (0,6) a solution to the equation 3x+y=12? Select the correct choice below and fill in the answer box to complete your
choice.
OA. Yes, because when 0 is substituted for x and 6 is substituted for y, simplifying the left side results in
which

Determine If The Following Ordered Pairs Are Solutions To The Equation 3x + Y = 12.(2,5)(4,0)(0,6)Is

Answers

Answer 1

We can conclude that (4,0) is the solution of the equation 3x + y = 12 with the correct option (A).

What exactly are equations?The definition of an equation in algebra is a mathematical statement that demonstrates the equality of two mathematical expressions. For instance, the equation 3x + 5 = 14 consists of the two expressions 3x + 5 and 14, which are separated by the 'equal' sign.

So, the ordered pair of the equation 3x + y = 12:

(A) When (2,5):

3x + y = 123(2) + 5 = 126 + 5 = 1211 ≠ 12

(B) When (4,0):

3x + y = 123(4) + 0 = 1212 + 0 = 1212 = 12

(C) When (0,6):

3x + y = 123(0) + 6 = 120 + 6 = 126 ≠ 12

Therefore, we can conclude that (4,0) is the solution of the equation 3x + y = 12 with the correct option (A).

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Determine If The Following Ordered Pairs Are Solutions To The Equation 3x + Y = 12.(2,5)(4,0)(0,6)Is

Related Questions

How do I simplify 5 8/48

Answers

Given:

[tex]5\frac{8}{48}[/tex][tex]5\frac{8}{48}=\frac{248}{48}[/tex][tex]5\frac{8}{48}=\frac{31}{6}[/tex][tex]5\frac{8}{48}=5.1667[/tex]

focus on the fraction
what can divide into 8 and 48
if you need to you can do small numbers like 2
but you can divide 4 and 8
you don’t have to worry about 5 because that a whole number so pretend that’s not that there until you break down the fraction till you can’t anymore
once you can’t break down the fraction anymore and the 5 back
hope this helped

Olivia goes out to lunch. The bill, before tax and tip, was $13.90. A sales tax of 6% was added on. Olivia tipped 23% on the amount after the sales tax was added. How much was the sales tax? Round to the nearest cent.

Answers

According to the information given in the exercise, the bill before the tax and tip was $13.90 and the sales tax of 6% was added to that amount.

By definition, you can write 6% as a Decimal number by dividing it by 100. Then, this is:

[tex]\frac{6}{100}=0.06[/tex]

Let be "t" the amount (in dollars) of the sales tax.

To find the value of "t", you can set up the following equation:

[tex]t=(13.90)(0.06)[/tex]

Finally, evaluating, you get that this is:

[tex]t=0.834[/tex]

Rounded to the nearest cent, this is:

[tex]t\approx0.83[/tex]

The answer is: $0.83

Alberto is saving money to buy a pair of shoes that cost $50 he has already saved $32 he still needs to save D dollars explain how to solve your equation to find how much money Alberto needs to save how much more does he need to save

Answers

[tex]32\text{ + x = 50}[/tex]

This is the formula that represents how much money needs Alberto to buy a pair of shoes.

To solve this equation, first, subtract 32 to both sides of the equation:

[tex]32\text{ - 32 + x = 50 - 32}[/tex][tex]x\text{ = 50 - 32}[/tex]

[tex]x\text{ = 18}[/tex]

Thus, he still needs to save $18 to buy the shoes.

coupon A 60% off of $87 pants coupon B $55 rebate on $87 pants

Answers

We are given two coupons A and B. Coupon A gives a 60% discount on a $87 item. Let's calculate the amount to pay by subtracting 60% of 87. We do that by multiplying 87 by 60/100, like this:

[tex]87(\frac{60}{100})=52.2[/tex]

Now we subtract this from the initial price, like this:

[tex]87-52.2=34.8[/tex]

therefore, using coupon A she must pay $34.8

For coupon B there's a rebate of $55. We calculate the amount to pay by subtracting 55 to the total price of 87, like this:

[tex]87-55=32[/tex]

Therefore, using coupon B she must pay $32.

Coupon B gives the lowest price, the price of coupon B compared to coupon A is calculated by subtracting both prices:

[tex]34.8-32=2.8[/tex]

Therefore, with coupon B she pays $2.8 less than the price with coupon A.

Consider the following equation of a parabola.(y- 7)? = -4(x - 3)Step 1 of 3: Find the focus of the parabola.

Answers

Answer

Focus = (2, 7)

Explanation

Given:

The following is the equation of a parabola

[tex](y-7)^2=-4x(x-3)[/tex]

What to find:

To find the focus of the parabola.

Step-by-step solution:

The general equation of a parabola can be given as,

[tex](y-k)^2=4p(x-h)[/tex]

Comparing the general equation of a parabola with the given equation of a parabola, we have

4p = -4

∴ p = -4/4 = -1

Also,

h = 3

k = 7

Since h ± c = F

We have,

3 - 1 = 2

Therefore, the focus will be (h ± c, k) = (2, 7)

f(x) = -5x -4 and g(x) = x^2 + 3 find (g+f)(x)

Answers

f(x) = -5x -4

g(x) = x^2+3

To find (g+f)(x)​ , simply add both equations:

(g+f)(x)​= x^2+3 + (-5x -4 )

(g+f)(x)​= x^2+3 -5x -4

Combine like terms

(g+f)(x)​= x^2-5x+3-4

(g+f)(x)​= x^2-5x-1

In a sourball game, a fizzy is worth 2 points and a X is worth 5 points. K and W recently played for the sourball game. During the game, K scored eight more fizzles than the W, but scored 5 fewer Y than the W. Together the two teams scored 93 pints total. What was the final score?

Answers

Using mathematical operations of addition, multiplication, division, and subtraction, the final score was:

K = 42 pointsW = 51 points.

What are mathematical operations?

The basic mathematical operations for getting mathematical results from numbers, values, and variables include addition, multiplication, division, and subtraction.

In this situation, we apply these four basic mathematical operations.

Fizzy = 2 points

X = 5 points

Total scores = 93 points

The points in 8 Fizzys = 16 points (8 x 2)

The points in 5 Xs = 25 points (5 x 5)

The equation showing the total scores of K = total scores + 16 - 25

= (93 + 16 - 25)/2

= 42 points

The equation showing the total scores of W = total scores - 16 + 25

= (93 - 16 + 25)/2

= 51 points

Final scores are K = 42 and W = 51.

Thus, applying mathematical operations, the final score shows that K scored 42 points while W scored 51 points, totaling 93 points for the two teams.

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The numerator of a certain fraction is five times the denominator. If nine is added to both the numerator and the denominator, the resulting fraction is equivalent to two. What was the original fraction (not written in lowest terms)?

Answers

Explanation

To solve the question,

Let

The numerator = x

The denominator = y

So that the original equation will be

[tex]\frac{x}{y}[/tex]

Next, we are told that the numerator is five times the denominator.

So that

[tex]x=5y[/tex]

Again, we are told that If nine is added to both the numerator and the denominator, the resulting fraction is equivalent to two. so

[tex]\frac{x+9}{y+9}=2[/tex]

Hence

we can substitute x =5y into the above

[tex]\begin{gathered} \frac{5y+9}{y+9}=2 \\ \\ cross\text{ multiplying} \end{gathered}[/tex][tex]\begin{gathered} 5y+9=2(y+9) \\ 5y+9=2y+18 \\ Taking\text{ like terms} \\ 5y-2y=18-9 \\ 3y=9 \\ \\ y=\frac{9}{3} \\ \\ y=3 \end{gathered}[/tex]

Thus, the denominator is 3

The numerator will be

[tex]\begin{gathered} x=5y \\ x=5\times3 \\ x=15 \end{gathered}[/tex]

The numerator is 15

Therefore, the fraction is

[tex]undefined[/tex]

Which graph represents 2x + 3y < 6?Choose 1 answer:

Answers

Given: An inequality

[tex]2x+3y<6[/tex]

Required: To determine the graph of the inequality.

Explanation: The inequality represent an area either inside or outside a line determined by repl

What should you do to finish solving this equation?6y + 4y + 90 = 36010y + 90 = 360Add 90 then divide by 102 subtract 90 then multiply by 10Add 10 then multiply by 904Subtract 90 then divide by 10O 102O 304h

Answers

answer is substract 90 then divide by 10

give two-sided of a triangle, find a range of a possible side length of the third side 24 and 52

Answers

For a triangle to be possible with 3 given lengths, the largest side must be lower than the sum of the two remaining sides.

Let L be the length of the third side. There are two cases:

If L is the largest side, then:

[tex]\begin{gathered} L<24+52 \\ \Rightarrow L<76 \end{gathered}[/tex]

If L is not the largest side, then the largest side has a measure of 52 and:

[tex]\begin{gathered} 52<24+L \\ \Rightarrow52-24Since both conditions should meet for a triangle to be formed, then:[tex]28Therefore, the range of possible values for L is:[tex]undefined[/tex]

Solve 5x² + 25 = 0Ox= -5x = -5 and x = 5Ox=5No Real Solutions

Answers

[tex]5x^2+25=0[/tex]

Solve for x:

Subtract 25 from both sides:

[tex]\begin{gathered} 5x^2+25-25=-25 \\ 5x^2=-25 \end{gathered}[/tex]

Divide both sides by 5:

[tex]\begin{gathered} \frac{5x^2}{5}=-\frac{25}{5} \\ x^2=-5 \end{gathered}[/tex]

Take the square root of both sides:

[tex]\begin{gathered} x=\pm\sqrt{-5} \\ x=\pm\sqrt{5}i \end{gathered}[/tex]

Therefore, there are no real solutions

Answer:

No Real Solutions

0 Rick has been losing weight at a constant rate since he began his new fitness plan. The table below shows Rick's weight for the first four weeks, 2 3 I 220.2 218.6 221.8 223.4 Weight (lbs) a) Write an equation to represent this sequence. b) Find Rick's weight after 16 weeks. ter your answer(s) here

Answers

To make the equation lets us find the rate of change of the weight

The form of the equation is y = m x + b

where:

m is the rate of change (slope)

b is the y-intercept (value y when x = 0)

To find m use two-point from the table

(1, 223.4) , (2, 221.8)

[tex]m=\frac{221.8-223.4}{2-1}=-\frac{8}{5}=-1.6[/tex]

Substitute it in the form of the equation

[tex]y=-1.6x+b[/tex]

To find b use any point in the table

(1, 223.4)

x = 1 , y = 223.4

[tex]\begin{gathered} 223.4=-1.6(1)+b \\ 223.4=-1.6+b \end{gathered}[/tex]

Add 1.6 for both sides to find b

[tex]\begin{gathered} 223.4+1.6=-1.6+1.6+b \\ 225=b \end{gathered}[/tex]

Substitute value b in the equation

[tex]y=-1.6x+225[/tex]

The equation of the sequence is y = -1.6 x + 225

to find his weight after 16 weeks substitute x by 16

[tex]\begin{gathered} y=-1.6(16)+225 \\ y=-25.6+225 \\ y=199.4 \end{gathered}[/tex]

His weight after 16 weeks is 199.4 Ibs

Susan is flying a kite, which gets caught in the top of a tree. Use the diagram to estimate the height of the tree. a. 87 ft b. 74 ft c. 65 ft d. 63 ft

Answers

Given the information on the picture, we have the following right triangle:

we can use the tangent trigonometric function to find the height of the tree:

[tex]\begin{gathered} tan(44)=\frac{\text{opposite side}}{adjacent\text{ side}}=\frac{h}{90} \\ \Rightarrow\tan (44)=\frac{h}{90} \end{gathered}[/tex]

solving for h, we get:

[tex]\begin{gathered} \frac{h}{90}=\tan (44) \\ \Rightarrow h=90\cdot\tan (44)=86.9\approx87 \\ h=87ft \end{gathered}[/tex]

therefore, the height of the tree is 87 ft

Find how many years it would take for an investment of $4500 to grow to $7900 at an annual interest rate of 4.7% compounded daily.

Answers

To answer this question, we need to use the next formula for compound interest:

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]

From the formula, we have:

• A is the accrued amount. In this case, A = $7900.

,

• P is the principal amount. In this case, $4500.

,

• r is the interest rate. In this case, we have 4.7%. We know that this is equivalent to 4.7/100.

,

• n is the number of times per year compounded. In this case, we have that n = 365, since the amount is compounded daily.

Now, we can substitute each of the corresponding values into the formula as follows:

[tex]A=P(1+\frac{r}{n})^{nt}\Rightarrow7900=4500(1+\frac{\frac{4.7}{100}}{365})^{365t}[/tex]

And we need to solve for t to find the number of years, as follows:

1. Divide both sides by 4500:

[tex]\frac{7900}{4500}=(1+\frac{0.047}{365})^{365t}[/tex]

2. Applying natural logarithms to both sides (we can also apply common logarithms):

[tex]\ln \frac{7900}{4500}=\ln (1+\frac{0.047}{365})^{365t}\Rightarrow\ln \frac{7900}{4500}=365t\ln (1+\frac{0.047}{365})[/tex]

3. Then, we have:

[tex]\frac{\ln\frac{7900}{4500}}{\ln(1+\frac{0.047}{365})}=365t\Rightarrow4370.84856503=365t[/tex]

4. And now, we have to divide both sides by 365:

[tex]\frac{4370.84856503}{365}=t\Rightarrow t=11.9749275754[/tex]

If we round the answer to two decimals, we have that t is equal to 11.97 years.

many solutions can be found for the system of linear equations represented on the graph?A. no solution B. one solution C. two solution D. Infinity many solutions

Answers

The lines are not intersecting. The system of linear equations has a solution only if the lines corresponding to the equations intersect.

The general linear equation is,

y=mx+c, where m is the slope.

The slopes of lines m=2.

Since the graphs are parallel or have the same slope and will never intersect, the system of linear equations have no solution.

Eric takes classes at both Westside Community College and Pinewood Community College. At Westfield class fees are $98 per credit hour and at Pinewood, class fees are $115 per credit hour. Eric is taking a combined total of 17 credit hours at the two schools. Suppose that he is taking W credit hours at Westside. Write an expression for the combined total dollar amount he paid for class fees. Total paid ( in dollars) =

Answers

Let W = number of credit hours at Westside

Since the total credit hours is 17, the number of credit hours at Pinewood is :

[tex]17-W[/tex]

To find the expression for the combined total dollar amount for both class.

Multiply each hours by the corresponding fees.

The expression will be :

[tex]\begin{gathered} 98(W)+115(17-W) \\ =98W+1955-115W \\ =1955-17W \end{gathered}[/tex]

The correct answer is :

1955 - 17W

Triangle DEF is rotated 60⁰ clockwise about the vertex to obtain triangle LMN. if the m

Answers

EXPLANATION

The measure of the angle LMN is equal to 40 degrees, then the measure of the angle LMN is the same because the rotation does not modify the angle.

PLEASE HELP!!
Write an equation of a quadratic function with the given properties: f(3)=f(-5)=0; f(-6)=-36​

Answers

The equation for a quadratic function with given properties is, f(x) = -201.5 (x² +2x - 15)

Given,

f(3) = f(-5) = 0;

f(-6) = -36​

Here,

The x intercepts of the quadratic equation are;

x₁ = 3 , x₂ = -5

The quadratic equation in factored form is equal to

f(x) = a(x - x₁) (x - x₂)

Substitute x₁ = 3 , x₂ = -5 in f(x)

Then,

f(x) = a(x - 3) (x - -5)

f(x) = a(x - 3) (x + 5)

We have;

f(-6) = -36​

That is, if x = -6 then f(x) = -36

So,

f(x) = a(x - 3) (x + 5)

-6 =  a(-36 - 3) (-36 + 5)

-6 = a x - 39 x - 31

-6 = 1029a

a = -1029/6

a = -201.5

Here,

f(x) = -201.5(x - 3) (x + 5)

Apply distributive property;

f(x) = -201.5(x² +5x - 3x - 15)

f(x) = -201.5 (x² +2x - 15)

That is,

The equation for a quadratic function with given properties is, f(x) = -201.5 (x² +2x - 15)

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hello,Can you please help me with question # 25 in the picture?Thank you

Answers

To find the sum of an arithmetic sequence up to the nth term, we use the sum formula, which is

[tex]S_n=n(\frac{a_1+a_n}{2})[/tex]

where a1 represents the first term, and an the nth term.

The general term of our sequence is

[tex]a_n=3n+2[/tex]

We want to sum up to the 16th term. Evaluanting n = 16 and n = 1 on this expression, we get the terms to plug in our formula

[tex]\begin{gathered} a_1=3(1)+2=3+2=5 \\ a_{16}=3(16)+2=48+2=50 \end{gathered}[/tex]

Then, the sum is equal to

[tex]\sum_{i\mathop{=}1}^{16}(3i+2)=16(\frac{50+5}{2})=8\cdot55=440[/tex]

The result of this sum is 440.

Evaluate 7a - 5b when a = 3 and b = 4 .

Answers

[tex]\begin{gathered} \text{ When evaluating, just substitute the values given assigned to the variable} \\ a=3,b=4 \\ 7a-5b \\ =7(3)-5(4) \\ =21-20 \\ =1 \end{gathered}[/tex]

9) Write an equation of a line that is steeper than y- 6x + 2

Answers

[tex]\begin{gathered} y=-6x+2 \\ y^{^{\prime}}=-6 \\ \end{gathered}[/tex]

Use the fact that 521•73=38, 033.Enter the exact product of 5.21•7.3

Answers

Answer: 38.033

5.21 x 7.3

= 38.033

A cubic equation has zeros at -2, 1, and 3 a) Write an eqn for a polynomial function that meets the given conditions.b) Draw the graph of a polynomial function that meets the given conditions.

Answers

we know that

A cubic equation has zeros at -2, 1, and 3

so

the factors of the cubic equation are

(x+2), (x-1) and (x-3)

Part a

The equation of a polynomial is

[tex]P(x)=(x+2)\cdot(x-1)\cdot(x-3)[/tex]

Applying distributive property

[tex]\begin{gathered} P(x)=(x^2-x+2x-2)\cdot(x-3) \\ P(x)=(x^2+x-2)\cdot(x-3) \end{gathered}[/tex]

Applying distributive property again

[tex]P(x)=x^3-3x^2+x^2-3x-2x+6[/tex]

Combine like terms

[tex]P(x)=x^3-2x^2^{}-5x+6[/tex]

Part b

using a graphing tool

see the attached figure below

If two lines intersect and one of the angles formed has a measure of 67°, which of the following statements are true? Explain your answers.

Answers

Intersecting Lines

When two lines intersect, four angles are formed at the point of intersection.

Two pairs of angles are vertical, i.e., they have the same measure.

Two pairs of angles are complementary (or linear) therefore their sum adds up to 180°.

We are given one of the angles that has a measure of 67°.

Then, another angle also measures 67° (the vertical peer).

One of the other angles is 180° - 67° = 113°

The other angle also measures 113° (the other vertical peer).

According to the facts found above, the following statements are true:

* Vertical angles are congruent, therefore another angle must equal 67°

* The lines form linear pairs

* The lines form complementary angles

* Two of the angles formed measure 113°

* Two of the angles formed will have a sum of 180°

Note: The last statement should read "Two pairs of angles formed..."

Do you know anything about dilation!?

Answers

[tex]\begin{gathered} T^{\prime}(-6,1) \\ U^{\prime}(0,3) \\ V^{\prime}(-2,-2) \\ W^{\prime}(-5,-3) \end{gathered}[/tex]

100 points!!!!
PLS WRITE IN SLOPE INTERCEPT FORM
–18y + 8 = 12x
SOLVE FOR Y

Answers

Answer: y = (-2/3)x + (4/9)

Step-by-step explanation:

y = mx + b is the form expected

-18y + 8 = 12x

subtract 8 from both sides

-18y = 12x - 8

divide both sides by -18

y = (12x/-18) - (8/-18)

Simplify the negatives and pull x out of the parenthesis (this only works if x is in the numerator).

y = (-12/18)x + 8/18

Simplify the fractions

y = (-2/3)x + 4/9

Answer:

The required value of y is,

y = -(2/3)x + (4/9)

Step-by-step explanation:

Given equation,

→ -18y + 8 = 12x

The slope-intercept form is,

→ y = mx + b

Let's rewrite the equation,

→ y = mx + b

→ -18y + 8 = 12x

→ -18y = 12x - 8

→ -y = (12x - 8)/18

→ -y = (2/3)x - (4/9)

→ y = -(2/3)x + (4/9)

Hence, this is the answer.

I’m stuck on this one need a push in Wright direction

Answers

In the graph it is observed that staright line is drawn between y-axis and x-axis. The graph of a linear function is always a straight line. So function represented in graph is linear.

Answer: Yes function is linear

A committee of eight math instructors and ten science instructors need to select two people from each group to send to a conference. What is the probability of selecting two math instructors and two science instructors?

Answers

Choosing two math instructors out of 8 would be

[tex]P=\frac{2}{8}=\frac{1}{4}[/tex]

Choosing two science instructors out of 10 would be

[tex]P=\frac{2}{10}=\frac{1}{5}[/tex]

Given that they are independent events, we multiply their probabilities

[tex]P=\frac{1}{4}\times\frac{1}{5}=\frac{1}{20}[/tex]

Hence, the probability of selecting two math instructors and two science instructors is 1/20.

What fraction is bigger 25/5 or 24/6?

Answers

[tex]\begin{gathered} \text{fraction }\frac{25}{5}\Rightarrow5 \\ \text{fraction }\frac{24}{6}\Rightarrow4 \\ So,\text{ the }\frac{25}{5}\text{ is the bigger than }\frac{24}{6} \end{gathered}[/tex]

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