Does a car's odometer and speedometer give an accurate measure of the car's velocity ?

Answers

Answer 1
A car's speedometer shows instantaneous speed of the car at the moment it is moving. Therefore, the speedometer measure speed NOT velocity.

An odometer measure the distance traveled by the car. Therefore, the odometer measures distance NOT velocity

the answer is no.
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Related Questions

PLSSSSSSSS ASAP!!!!!!
If the distance and time of an object are given, and I need to find speed, I will *


1.add the distance and time

2.divide the distance and time

3.multiply the distance and time

Answers

Answer:

2. divide the distance and time

speed=distance÷time

Yodelin has fifty quarters and dimes. Their total value is $9.80. Which of these systems of equations can be used to find the number of quarters (q) and
dimes (d) Yodelin has?

Answers

Answer:

q + d = 50

25q + 10d = 980

Explanation:

The equation that can be employed to determine the number of quarters(q), as well as, dimes(d) that Yodelin has would be:

q + d = 50...(1)

25q + 10d = 980...(2)

Multiplying (1) by 25

25q + 25d = 1250 ...(3)

25q + 10d = 980...(4)

subtracting (4) from (3)

15d = 270

d = 18

q = 50 - 18

    = 32

The system of the equations could be

q + d = 50

25q + 10d = 980

Calculation of the equation and the number of quarters and dimes:

Since Yodelin has fifty quarters and dimes. Their total value is $9.80.

So here the equations be

q + d = 50...(1)

25q + 10d = 980...(2)

Now we have to Multiplying (1) by 25

So,

25q + 25d = 1250 ...(3)

25q + 10d = 980...(4)

Now

subtracting (4) from (3)

15d = 270

d = 18

So,

q = 50 - 18

   = 32

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Hiro walks up a flight of stairs in his apartment building. Later in the day, he runs up the same flight of stairs.

Which statement about work and power describes Hiro’s actions?

He did more work running than walking.
He did more work walking than running.
He had more power running than walking.
He had more power walking than running.

Answers

Answer:

C) he had more power running than walking

Explanation:

saw it on a quizlet. not 100% sure tho

Hiro walks up a flight of stairs in his apartment building. Later in the day, he runs up the same flight of stairs so He had more power running than walking.

What is power?

In physics, power is the amount of energy transferred or converted per unit of time. In the International System of Units, the unit of power is the watt, equal to one joule per second. In older works, power is sometimes called activity. Power is a scalar quantity.

Power is related to other quantities; for example, the power involved in moving a ground vehicle is the product of the traction force on the wheels and the velocity of the vehicle.

The output power of a motor is the product of the torque that the motor generates and the angular velocity of its output shaft

Since we know that Hiro will run on stairs to minimize the time of reaching his home so if time decreases then he has to increase his power as power is the ratio of work and time.

Hence Hiro walks up a flight of stairs in his apartment building. Later in the day, he runs up the same flight of stairs so He had more power running than walking.

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A student is on a skateboard facing a wall. The student and skateboard have a mass of 75 kilograms. The student pushes off of the wall with a force of 100 Newtons. What is the force of the wall pushing back on the student? What is the acceleration of the student as she moves away from the wall?

Answers

Answer:

F=-100N; a=1.3m/s^2

Explanation:

Force is being made by student, so wall counteracts that force by not moving so it is equally opposite.

The force of the wall pushing back on the student would be 100 Newtons, and the acceleration of the student as she moves away from the wall would be 1.33 m/s²

What is Newton's third law of motion?

Newton's third law of motion state that for every action force there exists a complementary reaction force that balances it.

As given in the problem a student is on a skateboard facing a wall. The student and skateboard have a mass of 75 kilograms. The student pushes off of the wall with a force of 100 Newtons,

The force of the wall pushing back the student = 100 Newtons

The acceleration of the student = 100/75

                                                     =1.33 m/s²

Thus, The student would be pushed back against the wall by a force of 100 Newtons, and she would accelerate away from the wall at a rate of 1.33 m/s².

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1. Which of the following provides a correct answer for a problem that can be solved using the kinematic equations?
A A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's final
position is 32 m.
B A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's final
velocity is 16 m/s
C A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's travels a
distance of 16 m
A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's final
velocity is 24 m/s
E A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's final
position is 30 m.
1 of 14
2
3
5 6 7 8
9

Answers

Answer:

12

Explanation:

12

The y-axis of a position-time graph represents

Answers

It represents position:)

please help me this is due in 30 minutes. If you can do three that would be so great.

Answers

Answer:

1. 3000 N

Explanation:

you multiply 1000kg and 3

Answer:

2. acceleration will double

The acceleration will increase for example: 4/2=2 m/s^2 and if you double 4 it will be 8/2=4 m/s^2. Which means the acceleration also doubles.

Calculate the TOTAL mechanical energy of pendulum is it swings from his highest point to its lowest point. Pendulum mass is 4 kg. Use your equations for gravitational potential energy and kinetic energy to determine these values based on the data given below. Total energy is the sum of gravitational potential energy and kinetic energy. In this problem, round gravity to: g = 10 m/s^2.

Answers

Answer:

its should be 2.0 and 4.5 on it

Three toy boats with the same mass were in a lake. Two boats were moving and one was stopped. Each boat got bumped by another boat, but not in the same direction. All the boats changed speed as a result of being bumped. Use the information in the diagram to answer. Which toy boat exprienced the strongest force when it was bumped ? How do you know ?

Answers

The answer is " The orange and gray toy boats experienced the strongest force because both gained the same force as they sped up the blue boat lost force so it slow down

Explanation:

Trust me I did this one for an assignment

The boat that will experience the strongest force is the boat that has the highest speed.

According to Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.

F = ma

[tex]F = \frac{mv}{t}[/tex]

where;

F is the force experienced by the objectv is the velocity of the objectt is the time of motion

The force experienced by the boats is directly proportional to the velocity of their motion. Since the boats have the same mass, the force experienced by each boat will depend on the speed with which the boat moves.

Thus, the boat that will experience the strongest force is the boat that has the highest speed.

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What is the term given to telecommunications networks?
a. Telespace
b. Teleport
c. Communications net
d. Cyberspace

Answers

Answer:

c

Explanation:

i think communication net

The term given to telecommunication networks is Cyberspace. The correct option is d.

What is telecommunication network?

Telecommunications network, an electronic network of links and switches, as well as the controls that govern their operation, that enables data transfer and exchange between multiple users. network of communication

A telecommunications network is a collection of nodes linked together by telecommunications links that allow the nodes to exchange messages.

To transmit messages and signals, the links may employ a variety of technologies based on circuit switching, message switching, or packet switching methodologies.

The Internet, telecommunications networks, computer systems, and embedded processors and controllers are all part of a global domain within the information environment. Telecommunication networks are referred to as Cyberspace.

Thus, the correct option is d.

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A wave having a wavelength of 1.5 meters and amplitude of 3.0 meters
travels a distance of 15 meters in 3.0 seconds. Determine the frequency
and the period of the wave. *
Your answer

Answers

Answer:

velocity, v = 15m / 3.0s

= 5 ms^-1

velocity = wavelength × frequency

5 ms^-1 = 1.5m × f

f = 5 ms^-1 / 1.5 m

f = 3.33 Hz

f = 1/T

T = 1/f

= 1/ 3.33 Hz

= 0.3 s

frequency, f = 3.33 Hz

period, T = 0.3 s

Which of the statements below is true?

An object’s weight and mass are equal.
An object’s weight is proportional to its mass.
An object’s weight is inversely proportional to its mass.
An object’s weight is always twice its mass.

Answers

Answer:

An object’s weight is proportional to its mass.

In the 19th century scientists Knew that light was some kind of wave. and every waye science had yet decided needed

Answers

Answer:

The light was the wave

Explanation:

matter makes up all ? and ?

Answers

and All lives matter

True or False? Physical properties can be observed or measured without changing the identity of matter.

Answers

Answer:

true

Explanation:

What is the molar mass of the molecule C8H18, crude oil?

Answers

Answer:

114.23 g/mol

Explanation:

What are the SI units for distance and time?

Answers

Answer:

distance is meters, time is seconds

Answer:

distance is meters(m)

time is seconds (s)

Explanation:

To get employees to work longer hours, employers often offer __________ in the form of extra pay.
A.
costs
B.
benefits
C.
incentives
D.
consequences

Answers

C- Incentives it’s like a reward ~!

Answer:

C

Explanation:

I took the test

I would appreciate the help

Two classmates, Aisha and Brandon, want to attend two school activities
over the coming weekend. They have one parking pass between them. The
probabilities that the classmates will attend each event are shown in the
table.
Alsha
Brandon
0.65
0.94
Probability of attending
the Saturday activity
Probability of attending
the Sunday activity
0.80
0.43
They decide to let the person more likely to attend both events have the
parking pass. Assuming that attendance at one activity is independent of
attendance at the other, who is more likely to attend both activities?
A. Brandon. He has a 0.40 probability of attending both activities
O B. Brandon. He has a 0.69 probability of attending both activities
C. Aisha. She has a 0.52 probability of attending both activities.

Answers

Answer:

The answer is D.

Explanation:


Determine the speed of a golf ball that was hit 200meters
in 5 seconds.
a) 1000 m/s b) 40 m/s
c) .025 m/s d) 100 m/s

Answers

Answer:

b

Explanation:

200 divided by 5 is 40

b) 40 m/s

200 divided by 5 equals 40

3. In which direction does Maple Creek flow? a. Northeast b. Southwest Can't tell from information given​

Answers

Answer:

Northeast

Explanation:

I'm not sure if there's some fancy thing you have to do, but if there's no cardinal compass given, I think it's safe to assume that the answer is based off of one. Therefore, up is north, right is east, so Maple Creek flows to the northeast.

However, if they do give you one where, say, north points downwards, the creek would flow to the southwest. But again, from what is shown, there's no compass, so NE is your best guess here.

VR OF SECOND CLASS LEVER

Answers

Answer: Second class lever has mechanical advantage always more than one as load is in between fulcrum and effort making the effort arm longer than the load arm. It multiplies force. ... It does not multiply force but changes the direction of force.

Have a nice day / night! :)

What is the name of the kind of stretch that involves stretching as far as you can and then holding for 10-30 seconds

Question 2 options:

PNF


ballistic


dynamic


static

Answers

Answer:

Static stretching.

Explanation:

It is static stretching because it is a form of stretching which u can do actively for a period of time and you hold position for about 30 to 60 seconds which allow the muscles and connective tissues to lengthen. It is done after work out with out movement in order to loosen up muscles so as to gain flexibility.

The shortest path between two points is:

1) displacement

2) breadth

Answers

Answer:

the shortest path between two points is displacement..

Explanation:

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The shorts path between two points is displacement.

14. Trying to be on time for class, a girl moves at 1.4 m/s down a 52 m-long 7 points
hallway, 1.8 m/s down a much more crowded hallway that is 79 m long, and
the last 25 m to her class at 2.4 m/s. How long does it take her to reach her
class?



88S

Answers

Answer:

Option (2)

Explanation:

To find the time taken by the girl we will use the formula,

Time = [tex]\frac{\text{Distance traveled}}{\text{Speed}}[/tex]

Time taken by a girl who moves down 52 m long and 1.4 m per second,

[tex]t_1=\frac{52}{1.4}[/tex]

[tex]t_1[/tex] = 37.14 sec.

Time taken to move through crowded hallway,

[tex]t_2[/tex] = [tex]\frac{79}{1.8}[/tex]

[tex]t_2=43.89[/tex] sec

Time taken to cover 25 m with speed 2.4 meter per sec,

[tex]t_3=\frac{25}{2.4}[/tex]

[tex]t_3=10.42[/tex] sec

Total time taken by the girl = [tex]t_1+t_2+t_3[/tex]

                                             = 37.14 + 43.89 + 10.42

                                             = 91.45

                                             ≈ 91 seconds

Option (2) will be the answer.

4. Which of the following statements is correct?
A Mass and weight are different names for the same thing
B The mass of an object is different if the object is taken to the Moon
C The weight of a cer is one of the forces acting on the car.
D The weight of a chocolate beris measured in kilograms

Answers

Answer:

Explanation:

A: wrong. Mass and weight are different.

B: Wrong. The mass here and the mass on the moon are the same. The weight, which is Mass * the acceleration  is equal to weight.

C: Correct.

D: Wrong. Weight is not measured in Kg. Mass is.

7. A car is moving at 50.0 mph when the driver applies brakes. Determine the distance it
covers before coming to a halt. Coefficient of static friction between the tires and surface of
the road is 0.514. Mass of the car is 1000 kg.

Answers

Answer:

The distance to come to a halt is approximately 49.53 meters

Explanation:

Thee given parameters are;

The speed of the car, v = 50 mph = 22.35 m/s

The mass of the car, m = 1000 kg

The coefficient of friction,  = 0.514

The force of friction of the brake = Mass × Gravity × Friction = 1000 × 9.81 × 0.514 = 5042.34 N

The initial kinetic energy of the car = 1/2×m×v² = 1/2 × 1000 × 22.35² = 249761.25 J

The work done by the brake = Force of the brake × Distance, d, to come to halt

By conservation of energy, we have;

The work done by the brake = The initial kinetic energy of the car

∴ The initial kinetic energy of the car = Force of the brake × Distance, d, to come to halt

The initial kinetic energy of the car = 249761.25 J = 5042.34 N × Distance, d, to come to halt

∴The distance to come to a halt = 249761.25 J /(5042.34 N) ≈ 49.53 meters

The distance to come to a halt ≈ 49.53 meters.

The car will cover 49.65 m distance before stopping due to application of brake.

Given data:

The mass of car is, M = 1000 kg.

The initial speed of car is, u = 50.0 mph = (50)(0.447 m/s) = 22.35 m/s.

The coefficient of static friction is, [tex]\mu = 0.514[/tex].

The given problem can be solved using the third kinematic equation of motion. Which is,

[tex]v^{2}=u^{2}+2as[/tex] ....................................................(1)

Here, v is the final speed, v = 0 (Because car is finally stopping)

s is the distance covered before stopping and a is the magnitude of acceleration.

Now, since frictional force opposes the motion. Then,

[tex]F = f\\\\ma = \mu \times m \times g\\\\a = 0.514 \times 9.8\\\\a =5.03 \;\rm m/s^{2}[/tex]

Substituting the values in equation (1) as,

[tex]0^{2}=23.35^{2}+2(-5.03)s\\\\s = \dfrac{2500}{2 \times 5.03}\\\\ s=49.65 \;\rm m[/tex]

Thus, the car will cover 49.65 m distance before stopping due to application of brake.

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compare and contrast speed and strength

Answers

Answer:

Down Below

Explanation:

As nouns the difference between speed and strength

is that speed is the state of moving quickly or the capacity for rapid motion; rapidity while strength is the quality or degree of being strong.

Answer:

Explanation:is that speed is the state of moving quickly or the capacity for rapid motion; rapidity while strength is the quality or degree of being strong.

field lines point out from all sides on a object. Some of the lines point into a second object nearby. Which statement best describes the objects? A. both objects are permanent magnets B. both objects are electromagnets C. the first object is negatively charged, and the second object is positively charged D. the first object is positively charged, and the second object is negatively charged

Answers

Answer:

The first object is positively charged, and the second object is negatively charged. (D)

Explanation:

the solubility of sugar is 30 degree Celsius at 220 what does it mean​

Answers

Answer:

So, that if you put 100 mL of 30 degree water in a beaker, you could add up to 220 grams of sugar and it would eventually dissolve. In other words, that mass of sugar should dissolve in 100 mL of water to make a solution that is just saturated.

The solubility of sugar is 30° C at 220. This means 220g of sugar is dissolved in 100g of solvent to make the saturated solution at 30° C. Solutions.

What is the solution?

Most frequently, the solubility is represented in terms of mass per volume of water. Solubilities are frequently stated as g/100 mL, g/100 g, or g/L of water.

The ratio you provided is probably 1 g of sugar to 100 mL of water. In other words, if you put 100 mL of water at 30 degrees in a beaker, you could add up to 220 grams of sugar, and it would finally dissolve.

To generate a solution that is just saturated, the mass of sugar should dissolve in 100 mL of water.

Therefore, at 220 degrees, sugar dissolves at 30 degrees. This indicates that to create the saturated solution at 30° C, 220g of sugar must be dissolved in 100g of solvent.

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