ethyl benzene is treated with (i) br2 and febr3 and (ii) br2 and light or heat separately. do you think the products will be same? justify your answer.

For precipitation to occur, the value of Qsp (the ion product constant) should be greater than the solubility product constant (Ksp).

Precipitation is the conversion of a dissolved substance into a solid, which then settles out of a solution. Precipitation occurs when a liquid solution is cooled or heated, causing it to become super-saturated with one or more solutes. A solution's super-saturation means that it contains more of a solute than it can contain at equilibrium.

A tiny seed crystal of the solute is added to the solution to kick off the precipitation. The seed crystal provides a template for the rest of the solute to nucleate and form a solid. For precipitation to occur, the value of Qsp (the ion product constant) should be greater than the solubility product constant (Ksp). When Qsp is greater than Ksp, the solution is supersaturated and precipitates are formed. If Qsp is less than Ksp, the solution is unsaturated and no precipitation occurs.

Learn more about solution at:

https://brainly.com/question/16159788

#SPJ11

The temperature of helium gas confined in a two Litre flask under a pressure of 2.05 atm is approximately 41.11 °C.

The temperature of helium gas confined in a two Litre flask under a pressure of 2.05 atm can be calculated using the Ideal Gas Law. The Ideal Gas Law is expressed as PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the universal gas constant, and T is temperature.

In this case, we know that the pressure is 2.05 atm and the volume is 2 L. We also know that helium is a monoatomic gas with a molar mass of 4 g/mol. We can use the universal gas constant R = 0.0821 L atm/mol K. Plugging in these values, we get:

2.05 atm × 2 L = n × 0.0821 L atm/mol K × T

Dividing both sides by 0.0821 L atm/mol K gives:

n = (2.05 atm × 2 L) / (0.0821 L atm/mol K × T)

Simplifying, n = 50 T / R. We can now solve for T: n = 50 T / R => T = nR / 50

Substituting in the values we have:

n = (2.05 atm × 2 L) / (0.0821 L atm/mol K × 1 mol / 4 g)

= 24.88 molT = (24.88 mol × 0.0821 L atm/mol K) / 50

= 0.04111 K or 41.11 °C.

Therefore, the temperature of helium gas confined in a two Litre flask under a pressure of 2.05 atm is approximately 41.11 °C.

To learn more about temperature; https://brainly.com/question/25677592

#SPJ11

(a) If the pressure is 10.0 atm, the temperature is 62.0 K.

(b) if the temperature is 225 k, the pressure is 36.3 atm.

a) In order to calculate the temperature, we need to use the ideal gas law, PV = nRT, where P is the pressure, V is the volume of the container, n is the number of moles of argon, R is the ideal gas constant, and T is the temperature.

We can calculate the number of moles, n, by using the molar mass of argon, which is 39.948 g/mol.

We have n = 186 g / 39.948 g/mol = 4.656 mol.

So we can plug in our values and solve for T:

T = (10.0 atm)(2.37 L) / (4.666 mol)(0.08206 L·atm/mol·K) = 62.0 K.

b) To calculate the pressure, we can again use the ideal gas law, PV = nRT. We know the values of n, R, and T from the previous question.

Since the volume of the container is given, we can plug in these values to solve for P:

P = (4.666 mol)(0.08206 L·atm/mol·K)(225 K) / 2.37 L = 36.3 atm.

Learn more about ideal gas law here: https://brainly.com/question/27870704.

#SPJ11

To calculate the density (in grams per milliliter) for a glass marble with a volume of 7.94 ml and a mass of 15.36 g, you must divide the mass by the volume. In this case, the density would be 1.93 g/mL.

To solve this problem mathematically:

Step 1: Identify the mass (m) and volume (v) of the marble.

Mass (m) = 15.36 g
Volume (v) = 7.94 mL

Step 2: Divide the mass by the volume to calculate the density.

Density (d) = m/v
Density (d) = 15.36 g / 7.94 mL
Density (d) = 1.93 g/mL

Therefore, the density of the glass marble is 1.93 g/mL.

For more such questions on density

https://brainly.com/question/26364788

#SPJ11

The pH after the addition of 0.100 mol NaOH to 1.00 L of a buffer that is 0.700 M HF and 0.553 M NaF. The pH  is 7.031.

To calculate the pH after the addition of 0.100 mol NaOH to 1.00 L of a buffer that is 0.700 M HF and 0.553 M NaF, we can use the Henderson-Hasselbalch equation.

The Henderson-Hasselbalch equation is: pH = pKa + log ([A-]/[HA])

Where [A-] is the concentration of the anion (in this case, NaF) and [HA] is the concentration of the acid (in this case, HF).

pKa for HF is 7.1 x 10-4

Before we add the 0.100 mol NaOH, the pH of the buffer is:

pH = 7.1 x 10-4 + log ([0.553 M NaF]/[0.700 M HF])

= 7.1 x 10-4 + log(0.787)

= 7.1 x 10-4 + -0.103

= 6.997

Now, let's calculate the concentration of NaOH after we add 0.100 mol of it to the buffer. We know that 1 mole of NaOH will produce 1 mole of OH- ions, so the concentration of OH- ions is 0.100 M.

Since the buffer already contains HF and NaF, the total concentration of anions is 0.653 M.

We can now calculate the new pH using the Henderson-Hasselbalch equation:

pH = 7.1 x 10-4 + log([0.653 M anions]/[0.700 M HF])

= 7.1 x 10-4 + log(0.933)

= 7.1 x 10-4 + -0.069

= 7.031

Therefore, the pH of the buffer after the addition of 0.100 mol NaOH is 7.031.

For more such questions on Henderson-Hasselbalch equation , Visit:

https://brainly.com/question/13423434

#SPJ11

One molecule of this substance has the molecular formula CH₂ClO, which is methoxychloro. to ascertain how many oxygen atoms there are in 2 molecules of methoxychloro.

To create dioxygen, or oxygen, two oxygen atoms must make a covalent double bond with one another. Typically, oxygen exists as a molecule. It has the name dioxygen.

With an electrical configuration of (2, 6) and an atomic number of 8, oxygen lacks two more electrons to complete an octet. By exchanging two pairs of electrons with another oxygen atom, the oxygen atom becomes stable. A diatomic oxygen molecule is one that contains two oxygen atoms.

To know more about oxygen atoms visit:-

brainly.com/question/14387251

#SPJ1

The molecular equation for the gas evolution reaction between aqueous hydrobromic acid (HBr) and aqueous lithium sulfite (Li2SO3) is as follows:  2 HBr (aq) + [tex]Li_{2} So_{3}[/tex] (aq) → 2 LiBr (aq) + [tex]H_{2} So_{3}[/tex] (aq)

In this reaction, hydrobromic acid (HBr) reacts with lithium sulfite ([tex]Li_{2} So_{3}[/tex]) to form lithium bromide (LiBr) and sulfurous acid ([tex]H_{2} So_{3}[/tex]). The sulfurous acid is unstable and decomposes into water( [tex]H_{2o[/tex]) and sulfur dioxide gas ([tex]So_{2}[/tex]):

[tex]H_{2} So_{3}[/tex] (aq) → [tex]H_{2} 0[/tex]l) + [tex]So_{2}[/tex] (g)

The overall reaction is:

2 HBr (aq) + [tex]Li_{2} So_{3}[/tex] (aq) → 2 LiBr (aq) + [tex]H_{2} o[/tex] (l) + [tex]So_{2}[/tex] (g)

In this gas evolution reaction, the mixing of the two aqueous solutions results in the formation of a new compound, lithium bromide, which remains dissolved in the solution. The other product, sulfurous acid, decomposes into water and sulfur dioxide gas, which is released as bubbles in the solution. This release of gas is the characteristic feature of gas evolution reactions.

Know more about sulfurous acid      here:

https://brainly.com/question/1084323

#SPJ11

Chlorine (Cl) is a nonmetal, meaning it has the tendency to gain electrons to achieve the electron configuration of a noble gas. The noble gas electron configuration of the nearest noble gas, argon (Ar), is 1s2 2s2 2p6 3s2 3p6, with a total of 18 electrons.

Chlorine has 7 valence electrons, meaning it needs 1 more electron to achieve a stable noble gas electron configuration. Therefore, chlorine wants to gain 1 electron to achieve a stable noble gas configuration.

In terms of bonding, chlorine can either gain 1 electron to form an anion with a 1- charge or it can share electrons with another atom to form a covalent bond. Chlorine most commonly forms a single covalent bond with another atom, such as hydrogen, to form hydrogen chloride (HCl). In this case, both atoms share electrons to form a stable molecule.

To know more about Chlorine refer here:

https://brainly.com/question/28440406#

#SPJ11

The answer to the question is "e) all molecules will have the same speed." This is because all molecules, regardless of what elements they are made up of, have the same kinetic energy, so they will be moving at the same speed.

To better understand this concept, it is important to note that kinetic energy is the energy of an object due to its motion. Kinetic energy is determined by the mass and speed of the object, with the equation being KE = 1/2 x m x v^2 (where m is the mass and v is the velocity). So, if two objects have the same kinetic energy, they must have the same velocity, regardless of their mass.

As all molecules of hydrogen, nitrogen, oxygen and chlorine have the same kinetic energy, they must also have the same velocity, meaning that all molecules will be moving at the same speed. This is because the molecules' masses differ, but as the kinetic energy is the same, the velocity must be the same as well.

It is also important to note that kinetic energy is not the same as momentum. Momentum is determined by the mass and velocity of an object, but is not dependent on the kinetic energy of the object. So, while all molecules of hydrogen, nitrogen, oxygen and chlorine have the same kinetic energy, they may still have different momentum, due to their different masses.

In conclusion, all molecules of hydrogen, nitrogen, oxygen and chlorine will have the same speed, as they all have the same kinetic energy.

Learn more about Kinetic energy here:

https://brainly.com/question/15764612#

#SPJ11

4.83 x 10^24 atoms are there in 32.10 g of He.

To determine the number of atoms in 32.10 g of He, we first need to convert the mass to moles using the atomic mass of He, which is 4.003 g/mol.

number of moles of He = 32.10 g / 4.003 g/mol = 8.024 mol He

Next, we use Avogadro's number, which is 6.022 x 10^23 atoms/mol, to calculate the number of atoms in 8.024 mol of He:

8.024 mol He x 6.022 x 10^23 atoms/mol = 4.83 x 10^24 atoms

Therefore, there are approximately 4.83 x 10^24 atoms in 32.10 g of He.

Atoms are the fundamental matter units that comprise everything around us, from the air we breathe to the food we consume. They are made up of three different sorts of particles: protons, neutrons, and electrons.

For more such questions on atoms, click on:

https://brainly.com/question/6258301

#SPJ11

The mass gain that happened after the reaction could have been caused due to the matter was created in the reaction .  

What is mass gain?

In physics, mass gain refers to an increase in mass in a chemical or nuclear reaction. It is the difference between the mass of the reactants and the mass of the products after a chemical reaction has occurred.

What happened in the given problem?

According to the given problem, the starting mass of the apparatus and solid was 113.249 g. After the reaction was complete, the apparatus was reweighed. The resulting mass was 113.276 g. The problem asks which of the following could have caused the mass gain.

The mass gain could have been caused by the following:

They forgot to weigh the mass of the gas-generating solid before the reaction

The apparatus picked up extra water droplets between weighing's.

Matter was created in the reaction.

The apparatus picked up extra water droplets between weighings, but they forgot to weigh the mass of the gas-generating solid before the reaction, and matter was created in the reaction.

To know more about the mass https://brainly.com/question/19694949

#SPJ11

The pH at which the ratio of [HA₂⁻] to [H₂A⁻] is 25:1 is 11.1.

Titration is a technique used to determine the concentration of a solution by reacting it with a standardized solution. This process can be used to determine the acidity or basicity of a solution.

Assume that the equilibrium represented around point (A) in the titration can generically be described as:

                         H₃A + OH⁻ → H₂A⁻ + HOH

Ka₁ = 6.76 x 10⁻³

Ka₂ = 9.12 x 10⁻¹⁰

There are three stages to the titration curve. The first stage corresponds to the point at which there is an excess of strong base, and the pH changes rapidly with each addition of base. The second stage corresponds to the buffer region, and the pH changes only slightly with each addition of base. Finally, the third stage corresponds to the point at which the excess base is equal to the amount of acid present in the solution, and the pH changes rapidly once again.

In the equation H₃A + OH⁻ → H₂A⁻ + HOH the first dissociation constant, Ka₁, is equal to

[ H₂A⁻ ][H⁺]/[H₃A]

The second dissociation constant, Ka₂, is equal to

[H₃A⁻ ][OH⁻ ]/[H₂A⁻ ]

Let's assume that the equilibrium is initially set up at pH pKa₁, such that [H₃A] = [H₂A⁻ ].

The pH of the solution at equilibrium will be equal to pKa₁.

Let's suppose that a strong base is added to the solution, and the amount of [OH⁻ ] added is x.

As a result, [H₃A] and [H₂A⁻ ] will be reduced by x, while [HA₂⁻] will be increased by x.

[H₃A] = [HA₂⁻] = [H+];

[OH⁻] = x;

[HA₂⁻] = [OH⁻-];

[H₃A] - x;

[H₂A⁻] - x

We can then calculate the concentration of each species using the expression for the acid dissociation constant:

[H₃A] = [H2A⁻] = [H+];

[OH⁻] = x;

[HA₂⁻] = [OH⁻];

[H₃A] - x;

[H₂A-] - x

Ka₁ = [H₂A⁻][H+]/[H₃A]

Ka₁ = x^2 / ([H+]-x)

Ka₂ = [HA₂⁻][OH⁻]/[H₂A⁻]

Ka₂ = [x][x] / ([H+]-x)

Ka₂= x²/([H+]-x) = 25

Ka₁ is used to calculate [H+]

Ka₂ is used to calculate:

Ka₂ [HA₂⁻] / [H₂A⁻][H+] = 2.06 x 10⁻⁶,

pH = 5.68

[H₂A⁻] / [HA₂⁻] = 0.04,

[HA₂⁻] = [HA₂⁻] * 25 = 1.00 x 10⁻⁴

[OH-] = Ka₂ [H₂A-] / [HA₂⁻] = 9.12 x 10⁻¹⁰ * [H₂A⁻] / [HA₂⁻] = 2.28 x 10⁻¹⁴

pOH = 13.64

pH = 11.1

Therefore, at pH 11.1, the ratio of [HA₂⁻] to [H₂A⁻] is 25:1.

Learn more about titration at https://brainly.com/question/186765

#SPJ11

The electron configuration of valence electrons of carbon before and after sp hybridization are shown below:Before hybridization: 2s2 2p2After hybridization: sp2 2p2The orbital diagram before sp hybridization shows two electrons in the 2s orbital and two electrons in each of the 2p orbitals. After hybridization, the 2s orbital mixes with one of the 2p

orbitals to form two sp hybrid orbitals. These sp hybrid orbitals are oriented at 180° to each other, which allows maximum overlap with two 2p orbitals of the carbon atom. The remaining 2p orbital remains unhybridized and

unchanged. Therefore, the hybridized orbitals contain only one electron each and the unhybridized 2p orbital has two electrons.The boxes with arrows in the orbital diagram represent the orbitals and their electrons. The label "2s" is

dragged to the box representing the 2s orbital before hybridization. Similarly, the labels "2p" and "sp" are dragged to the boxes representing the unhybridized and hybridized orbitals after hybridization, respectively. The label "2p" is also dragged to the unhybridized 2p orbital after hybridization.

For more similar questions on hybridization

brainly.com/question/30902614

#SPJ11

The Rutherford's model lacks an atom's electrical structure and electromagnetic radiation.

According to the idea, an atom has a tiny, compact, positively charged center called a nucleus, where almost all of the mass is concentrated, while light, negatively charged particles called Like planets circle the Sun, electrons also travel a great distance around it. Rutherford discovered that an atom's interior is mostly empty.

Rutherford's alpha scattering experiment did not come to any conclusions on how quickly positively charged particles travel. The nucleus, or core, of the atom contains the positively charged particles.

To know more about Rutherford's model visit:-

https://brainly.com/question/11749615

#SPJ1

The isotope that yields four neutrons and the artificial isotope dubnium-260 when bombarded with nitrogen-15 is curium-244.

Curium-244 is a transuranic element of the actinide series. When bombarded with nitrogen-15, a nucleus of curium-244 splits into two smaller nuclei, releasing four neutrons in the process.

This process is called nuclear fission. The nucleus of nitrogen-15 is then combined with the two smaller nuclei to form dubnium-260, which is an artificially produced isotope.

Nuclear fission of curium-244 is a common process used in nuclear power plants. In nuclear power plants, uranium-235 is bombarded with neutrons, causing a chain reaction that produces energy and more neutrons.

The neutrons then bombard other uranium-235 nuclei, continuing the process. By bombarding curium-244 with nitrogen-15, a similar chain reaction is created that produces dubnium-260.

The production of dubnium-260 through nuclear fission of curium-244 can be used for various scientific and industrial purposes.

It can be used in the production of nuclear weapons, nuclear fuel, medical isotopes, and in other research activities.

In addition, it can be used as a catalyst for chemical reactions, to produce high energy radiation for sterilization, and for other industrial processes.

In conclusion, curium-244 yields four neutrons and the artificial isotope dubnium-260 when bombarded with nitrogen-15.

This process, known as nuclear fission, can be used in a variety of scientific and industrial applications.

to know more about isotope refer here

https://brainly.com/question/13063428#

#SPJ11

Einstein's famous equation say that all matter is option B. concentrated energy that has condensed into the atoms.

When combined with the speed of light, Einstein's famous equation E=mc2 demonstrates mathematically that energy and matter are one and the same. m stands for mass, c for the speed of light, and E stands for energy. This equation states that all matter is simply concentrated energy that has condensed into atoms.

Einstein's famous equation is E=mc², which expresses the relationship between mass (m) and energy (E), and the constant speed of light (c) in a vacuum. This equation shows that mass and energy are interchangeable, and that a small amount of mass can be converted into a large amount of energy, as demonstrated in nuclear reactions.

Learn more about Einstein at:

https://brainly.com/question/26366397

#SPJ1

Taking into account the definition of Avogadro's Number, 4.83×10²⁴ atoms of He are in 32.10 g of He.

The molar mass of substance is a property defined as the amount of mass that a substance contains in one mole.

Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole.

Its value is 6.023×10²³ particles per mole.

The molar mass of He is 4 g/mole. You can apply the following rule of three: If by definition of molar mass 4 grams of He are contained in 1 mole of He, 32.10 grams of He are contained in how many moles?

moles= (32.10 grams × 1 mole)÷ 4 grams

moles= 8.025 moles

The amount of moles of He in 32.19 grams is 8.025 moles.

You can apply the following rule of three: If by definition of Avogadro's Number 1 mole of He contains 6.023×10²³ atoms, 8.025 moles of He contains how many atoms?

amount of atoms of He= (8.025 moles × 6.023×10²³ atoms)÷ 1 mole

amount of atoms of He= 4.83×10²⁴ atoms

Finally, 4.83×10²⁴ atoms of He are present.

Learn more about Avogadro's Number:

brainly.com/question/11907018

#SPJ1

Answer : To prepare 3 mL of 0.24 M sucrose solution from a stock solution of 0.6 M sucrose, 1.2 mL of the stock solution and 1.8 mL of water should be used.

The amount of 0.6 Molar sucrose needed to prepare 3 mL of 0.24 Molar sucrose solution, as well as the volume of water required, can be calculated using the M1V1 = M2V2 formula. Where M1 is the molarity of the stock solution, V1 is the volume of the stock solution required, M2 is the desired molarity of the solution to be prepared, and V2 is the volume of the solution to be prepared.

Given that the stock solution of sucrose is 0.6 M, and we need to prepare 3 mL of a 0.24 M solution, we can use the formula:
0.6 M x V1 = 0.24 M x 3 mL Solving for V1:
V1 = (0.24 M x 3 mL)/0.6 M
V1 = 1.2 mL

This means that 1.2 mL of the stock solution of 0.6 M sucrose is required to prepare 3 mL of 0.24 M sucrose solution.
The volume of water required can be calculated by subtracting the volume of the stock solution from the total volume of the solution to be prepared: Volume of water = 3 mL - 1.2 mL and Volume of water = 1.8 mL

Know more about sucrose solution here:

https://brainly.com/question/3850162

#SPJ11

There are approximately 7.15 x 10^21 formula units of CaO present in 0.67 grams of CaO.

Calculate the molar mass of CaO, which is the sum of the atomic masses of calcium and oxygen,

Molar mass of CaO = (1 x atomic mass of Ca) + (1 x atomic mass of O)

Molar mass of CaO = 56.08 g/mol

Convert the given mass of CaO to moles using the molar mass,

Moles of CaO = Mass of CaO / Molar mass of CaO

Moles of CaO = 0.0119 mol

Use Avogadro's number to convert moles of CaO to formula units,

Formula units of CaO = Moles of CaO x Avogadro's number

Formula units of CaO = 0.0119 mol x 6.022 x 10^23 formula units/mol

Formula units of CaO = 7.15 x 10^21 formula units

To know more about formula units, here

brainly.com/question/20704685

#SPJ4

It is important not to dilute the initial sample before loading it onto the chromatography column because this can negatively impact the separation and resolution of the components in the sample.

Dilution can lead to a decrease in the concentration of the components in the sample, which can result in poor separation and overlap of the peaks. Additionally, dilution can cause loss of the target compound or impurities in the sample due to adsorption onto the walls of the container used for dilution.

By keeping the sample concentrated and loading it directly onto the chromatography column, the chances of obtaining a clear separation and good resolution of the components in the sample are increased

To learn more about chromatography column refer to:

brainly.com/question/30296545

#SPJ4

Answer:

yes because temperature is the moles of the initial respectively in the volume torr and 433 torr fixed the temperature heliums gas sample by 153 ml thank you

The energy of a photon with a wavelength of 410 nm is equal to 3.03 eV.

To calculate this, you can use the formula E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength. Plugging in the values, you get E = (6.626x10⁻³⁴J·s)(3.0x10⁸m/s)/(410x10⁻⁹m) = 4.839 × 10-19 J = 3.03 eV.

An atomic transition produces a photon with a wavelength of 410 nm. The energy of this photon is 3.03 eV.

The following formula can be used to calculate the energy of a photon.

Energy = Planck's constant x (speed of light/wavelength).

Here, Planck's constant is (h) = 6.626 × 10⁻³⁴ J s. The speed of light is (c) = 3 × 10⁸m/s (in a vacuum). The wavelength of the photon is (λ) = 410 nm.

So, let's first convert the wavelength to meters (1 nm =10⁻⁹ m).

So, 410 nm = 410 × 10⁻⁹ m = 4.10 × [tex]10^{-7}[/tex]m. Now, we can calculate the energy of the photon using the formula.

Energy = h x (c/λ)

Energy = 6.626 × 10⁻³⁴ J s x (3 × 10⁸ m/s / 4.10 × [tex]10^{-7}[/tex] m)

Energy = 4.839 × [tex]10^{-19}[/tex] J (joules)

One electron volt is equal to 1.6 × [tex]10^{-19}[/tex]J.

So, we can convert the energy from joules to electron volts.

Energy (in eV) = Energy (in J) / (1.6 × [tex]10^{-19}[/tex]J/eV)

Energy (in eV) = 4.839 × [tex]10^{-19}[/tex]J / (1.6 × [tex]10^{-19}[/tex]J/eV)

Energy (in eV) = 3.03 eV

Therefore, the energy of the photon is 3.03 eV.

For more questions related to Planck's constant.

https://brainly.com/question/2289138

#SPJ11

The number of moles of aspirin, C₉H₈O₄, there are in a tablet that contains 325 mg of aspirin 0.00180 moles.

To calculate the number of moles of aspirin, the molar mass must first be determined. The molar mass of aspirin (C₉H₈O₄) is the sum of the atomic masses of each element in the compound, which are carbon (12.0107 g/mol), hydrogen (1.00794 g/mol), and oxygen (15.9994 g/mol). The total molar mass of aspirin is:

(9 x 12.0107) + (8 × 1.00794) + (4 × 15.9994) = 180.15 g/mol.

The number of moles of aspirin in a 325 mg tablet can be calculated by dividing its mass, 325 mg (0.325 g), by the molar mass of aspirin.

moles = mass/molar mass

Plugging in the values, we get:

moles = 325 mg(1 g/1000mg) / (180.15 g/mol) = 0.00180 moles

In conclusion, there are 0.00180 moles of aspirin, C₉H₈O₄, in a tablet that contains 325 mg of aspirin.

Learn more about moles here: https://brainly.com/question/14357742.

#SPJ11

The heat released when 30.0 g of [tex]SO_{2}[/tex](g) reacts with 20.0 g of [tex]O_{2}[/tex](g) is 184.8 kJ.

To calculate the heat released when 30.0 g of [tex]SO_{2}[/tex](g) reacts with 20.0 g of [tex]O_{2}[/tex](g), we first need to determine the balanced chemical equation for the reaction:
[tex]SO_{2} (g) + 1/2 O_{2}(g)[/tex]  →  [tex]SO_{3}(g)[/tex]
Now, we need to find the limiting reactant. First, let's calculate the moles of each reactant:

moles of [tex]SO_{2}[/tex] = mass of [tex]SO_{2}[/tex] / molar mass of [tex]SO_{2}[/tex]
moles of [tex]SO_{2}[/tex] = 30.0 g / (32.1 g/mol + 32.0 g/mol) = 0.468 moles

moles of [tex]O_{2}[/tex] = mass of [tex]O_{2}[/tex] / molar mass of [tex]O_{2}[/tex]
moles of [tex]O_{2}[/tex] = 20.0 g / 32.0 g/mol = 0.625 moles

Now, we'll find the mole ratio:

mole ratio = moles of [tex]O_{2}[/tex] / (1/2 * moles of [tex]SO_{2}[/tex])
mole ratio = 0.625 / (1/2 * 0.468) = 2.67

Since the mole ratio is greater than 1, [tex]SO_{2}[/tex] is the limiting reactant.

Now, we need to find the heat released. The standard enthalpy change of the reaction (ΔH°) for the formation of [tex]SO_{3}[/tex] is -395.2 kJ/mol. Therefore, the heat released can be calculated as follows:

heat released = moles of limiting reactant * ΔH°
heat released = 0.468 moles * -395.2 kJ/mol = -184.8 kJ

So, the heat released when 30.0 g of [tex]SO_{2}[/tex](g) reacts with 20.0 g of [tex]O_{2}[/tex](g) is 184.8 kJ.

To learn more about heat released; https://brainly.com/question/22862842

#SPJ11

The symbol for the oxygen isotope with 9 neutrons is O-16.

The atomic number of oxygen is 8, which means it has 8 protons. The mass number for oxygen-16 is 16, which refers to the total number of particles in the nucleus (8 protons + 8 neutrons). The element symbol for oxygen is O.

Isotopes are atoms that have the same number of protons but different numbers of neutrons.

Oxygen-16 has a total of 9 neutrons, meaning it has one more neutron than the most common isotope of oxygen (oxygen-15, with 8 neutrons).

Due to the difference in neutron numbers, the atomic mass of oxygen-16 is slightly larger than oxygen-15.

Atomic mass is the combined mass of all of the protons and neutrons in an atom's nucleus. In oxygen-16, the protons and neutrons have a combined mass of 16, hence the mass number of 16.

Oxygen-16 is an important isotope because it is present in significant amounts in the Earth's atmosphere and is used in numerous medical and scientific applications.

to know more about isotope refer here:

https://brainly.com/question/11680817#

#SPJ11

To determine the volume of NaOH used to reach the equivalence point of the titration using the titration data, we need to find the point where the acid and base are neutralized.

At this point, the moles of acid and base are equal, and this is called the equivalence point.To find the volume of NaOH used at the equivalence point, we can use the following

Steps:1. Plot the titration data on a graph of pH versus volume of NaOH added.

Steps:2. Identify the point where the pH changes abruptly. This is the equivalence point.

Steps:3. Determine the volume of NaOH added at the equivalence point by reading the volume from the graph.

Steps:4. Compare the volume of NaOH used at the equivalence point of the titration with the predicted volume calculated above.The extent of agreement with the predicted volume can be assessed by calculating the percent error.

The percent error is calculated using the formula:

                                      Percent error = [(experimental value - theoretical value) / theoretical value] x 100

If the percent error is small, then the agreement is good. If the percent error is large, then there is a significant difference between the predicted and experimental values.

Learn more about equivalence point of the titration here, https://brainly.com/question/31181892

#SPJ11

The star is moving by a velocity of 3 *10^{5}.

The formula for the Doppler shift is given by

f2/f1 = (c-v)/c,

where c is the speed of light, v is the velocity of the moving object, and f1 and f2 are the emitted and received frequencies of light, respectively.

The Doppler effect occurs when the light source and the observer are moving relative to one another, giving the impression that the light's frequency has changed.

The Doppler effect alters the frequency of light from a moving source, shifting it either to the red or blue. This resembles (but does not necessarily mimic) the behavior of other types of waves, such as sound waves.

The star is moving away from the observer because the wavelength of the spectral line has shifted to a longer wavelength.

doppler shift

Thus, the velocity is given by the formula

:v/c = (Δλ/λ)

where  is the rest wavelength and  is the change in wavelength.

v/c = (Δλ/λ)v/c = (1000.1 - 1000.0)/1000.0v/c = 0.0001/1000.

0v/c = 1e-7v = (1e-7) × c = 300 × 1e-7 = 3e-5

The star is moving away from the observer at a velocity of[tex]3 *10^{5}[/tex]m/s.

To know more about the doppler effect https://brainly.com/question/15318474

#SPJ11

The temperature of the water when it comes to equilibrium is 69.48°C.

Firstly, the heat lost by ice is equal to the heat gained by water. This is because the process of melting of ice requires heat energy, and this heat energy will be absorbed from the water present in the cooler.

Let us find out the heat lost by ice. The specific heat of ice is 2.05 J/g·°C, and the heat of fusion of ice is 334 J/g. Heat lost by ice can be given as:

q1 = mass of ice × specific heat of ice × (final temperature - initial temperature) + mass of ice × heat of fusion

q1 = 6.00 × 10^3 g × 2.05 J/g·°C × (0 - (-5)) + 6.00 × 10^3 g × 334 J/g

= 6.00 × 10^3 g × 10.25 J/g·°C + 2.00 × 10^6 J

= 6.15 × 10^4 J + 2.00 × 10^6 J

= 2.06 × 10^6 J

Heat gained by water can be given as:

q2 = mass of water × specific heat of water × (final temperature - initial temperature)

q2 = 30.0 kg × 4.18 J/g·°C × (final temperature - 20.0°C) = 1254 J/kg·°C × (final temperature - 20.0°C)

Since q1 = q2,

we have: 6.15 × 10^4 J + 2.00 × 10^6 J

= 1254 J/kg·°C × (final temperature - 20.0°C)6.21 × 10^4 J

= 1254 J/kg·°C × (final temperature - 20.0°C)

final temperature - 20.0°C = 6.21 × 10^4 J / (1254 J/kg·°C)

final temperature - 20.0°C = 49.48°C

final temperature = 49.48°C + 20.0°C = 69.48°C

Hence, the temperature of the water when it comes to equilibrium is 69.48°C.

To know more about equilibrium, refer here:

https://brainly.com/question/30807709#

#SPJ4

In order to determine the pH of the unknown HCl solution, a titration calculation must be performed and the pH is 0.903.

1. Before the titration of the HCl solution with the KOH solution,

Let's calculate the number of moles of KOH using the formula given below:

Number of moles of KOH = concentration of KOH × volume of KOH solution

Number of moles of KOH = 0.890 M × 0.035 L

                                          = 0.03115 mol

We now convert moles of KOH to moles of HCl to find the concentration of HCl using the equation given below:

Moles of KOH = Moles of HCl

0.03115 mol KOH = Moles of HCl

25 mL of HCl = 0.025 L of HCl

Therefore, the concentration of HCl = 0.03115 mol / 0.025 L

                                                            = 1.246 M

We have now found the concentration of the HCl solution to be 1.246 M.

2. To find the pH of HCl, let's first recall that the concentration of H+ ions in a solution of a strong acid is equal to its concentration.

Since HCl is a strong acid, its pH can be found using the formula:

pH = -log[H+]

pH = -log[1.246]

pH = 0.903

Hence, the pH of the unknown HCl solution is 0.903.

Learn more about pH: https://brainly.com/question/172153

#SPJ11

To transform an alkene bonded to a tert-butyl group and three hydrogens to a tert-butyl group bonded to CH2CH2OH, the best reagents are H2SO4 and H2O.

H2SO4 is used to protonate the double bond and form a carbocation, which can then undergo nucleophilic attack by water to form the final product. This reaction is known as hydration of alkenes.To perform the transformation, the alkene is first protonated with H2SO4 to form a carbocation intermediate.

Water acts as a nucleophile and attacks the carbocation to form the alcohol product. This reaction is shown below:Thus, the final product formed is tert-butyl group bonded to CH2CH2OH.Another way to perform this transformation is by using oxymercuration-demercuration.

In this reaction, the alkene is first treated with mercuric acetate and water to form a cyclic intermediate.

Know more about nucleophile here:

https://brainly.com/question/27127109

#SPJ11