12) There were about 557 principals in attendance. 13) Option A: The college will have about 480 students who prefer cookies. 14) Option C: bar graph, title favorite sport and the x axis labeled sport and the y axis.
What is proportion?A percentage is a relationship between two values that have the same units and scale and are measured in different amounts. Proportions, which show the relative size or magnitude of one number in comparison to another, are frequently stated as ratios, fractions, or percentages. A class with 8 girls and 12 boys, for instance, has a girl-to-boy ratio of 8:12, or 2:3, which indicates that there are 3 guys for every 2 girls in the class. Numerous branches of mathematics and science, such as statistics, geometry, and physics, use proportions. In statistics, proportions are frequently used to describe how a population or sample is distributed.
12) For the number of principals in conference we set up a proportionality with total people as follows:
We know that, 52 principals out of 70 people thus:
52/70 = x/750
Now,
x = (52/70) * 750
x = 557.14
Hence, we can predict that there were about 557 principals in attendance at the conference.
13) Given that, out of 225 students 27 prefer cookies thus,
27/225 = 0.12
That is 12% students like cookies.
Now, for the total number of students we have:
0.12 * 4000 = 480
Thus, option A: The college will have about 480 students who prefer cookies.
14) For the collected data the best representation is option C: bar graph with the title favorite sport and the x axis labeled sport and the y axis labeled number of students, with the first bar labeled basketball going to a value of 17, the second bar labeled baseball going to a value of 12, the third bar labeled soccer going to a value of 27, and the fourth bar labeled tennis going to a value of 44.
15) For the given description of the line plot the median is:
For Bus 47 = 16
For Bus 18 = 13
The faster bus is Bus 47, with a median of 16.
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Edward has to take a seven-question multiple-choice quiz in his sociology class. Each question has four choices for answers, of which only one is correct. Assuming that Edward guesses on all seven questions, what is the probability that he will answer a) all seven questions correctly, b) exactly three questions correctly, c) at least three questions correctly
a) The probability of him answering all seven questions correctly is [tex](1/4)^7[/tex]or approximately 0.000019%.
b) Therefore, the probability of him answering exactly three questions correctly is [tex]35 * (1/4)^3 * (3/4)^4[/tex]or approximately 19.7%.
c) The probability of him answering at least three questions correctly is the sum of these probabilities, which is approximately 71.5%.
Since each question has four choices and only one is correct, the probability of guessing the correct answer for any one question is 1/4.
a) To answer all seven questions correctly, Edward must guess the correct answer for each question.
Therefore, the probability of him answering all seven questions correctly is [tex](1/4)^7[/tex] or approximately 0.000019%.
b) To answer exactly three questions correctly, Edward must guess the correct answer for three questions and the incorrect answer for the remaining four questions.
The number of ways in which he can do this is given by the binomial coefficient C(7,3) = 35.
The probability of him guessing three questions correctly and four questions incorrectly is [tex](1/4)^3 * (3/4)^4.[/tex]
Therefore, the probability of him answering exactly three questions correctly is [tex]35 * (1/4)^3 * (3/4)^4[/tex]or approximately 19.7%.
c) To answer at least three questions correctly, Edward must either guess three, four, five, six, or seven questions correctly.
We have already calculated the probability of him guessing exactly three questions correctly.
The probability of him guessing exactly four questions correctly is [tex]C(7,4) * (1/4)^4 * (3/4)^3 = 35 * (1/4)^4 * (3/4)^3[/tex]or approximately 34.7%.
The probability of him guessing exactly five questions correctly is [tex]C(7,5) * (1/4)^5 * (3/4)^2 = 21 * (1/4)^5 * (3/4)^2[/tex] or approximately 16.3%.
The probability of him guessing exactly six questions correctly is[tex]C(7,6) * (1/4)^6 * (3/4)^1 = 7 * (1/4)^6 * (3/4)^1[/tex] or approximately 0.82%. Finally, the probability of him guessing all seven questions correctly is (1/4)^7 or approximately 0.000019%.
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-4 ≤ x- 4 ≤ 0 graph the conjuntion ?? can someone help
The inequality is simplified as 0 ≤ x ≤ 4
Define inequalityIn mathematics, inequality refers to a mathematical expression that indicates that two values or quantities are unequal. An inequality is represented by the symbols "<" (less than), ">" (greater than), "≤" (less than or equal to), or "≥" (greater than or equal to).
For example, the inequality "x > 5" means that the value of x is greater than 5, and the inequality "y ≤ 10" means that the value of y is less than or equal to 10.
To graph the conjunction, we first need to solve for x:
-4 ≤ x - 4 ≤ 0
Add 4 to all parts of the inequality:
0 ≤ x ≤ 4
Image of graph is attached below.
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A charity needs to report its typical donations received. The following is a list of the donations from one week. A histogram is provided to display the data.
5, 5, 6, 8, 10, 15, 18, 20, 20, 20, 20, 20, 20
A graph titled Donations to Charity in Dollars. The x-axis is labeled 1 to 5, 6 to 10, 11 to 15, and 16 to 20. The y-axis is labeled Frequency. There is a shaded bar up to 2 above 1 to 5, up to 3 above 6 to 10, up to 1 above 11 to 15, and up to 7 above 16 to 20.
Which measure of variability should the charity use to accurately represent the data? Explain your answer.
The range of 13 is the most accurate to use, since the data is skewed.
The IQR of 13 is the most accurate to use, since the data is skewed.
The range of 20 is the most accurate to use to show that they have plenty of money.
The IQR of 20 is the most accurate to use to show that they need more money.
The IQR (Interquartile Range) of 13 is the most accurate measure of variability to use for this data since the data is skewed and contains outliers. The IQR is less sensitive to outliers than the range and provides a better representation of the spread of the middle 50% of the data.
What is variability?Variability refers to the extent to which data points in a dataset differ from each other. It is a measure of how spread out or dispersed a set of data is.
According to given information:In statistics, measures of variability are used to describe how spread out or clustered a set of data is. There are several measures of variability, but the two most common ones are the range and the interquartile range (IQR).
The range is the difference between the maximum and minimum values in a set of data. It is a simple measure of variability that gives an idea of how much the data varies. However, it can be affected by outliers, which are values that are much larger or smaller than the other values in the data set.
The IQR is a more robust measure of variability that is less affected by outliers. It is the difference between the third quartile (the value above which 75% of the data falls) and the first quartile (the value below which 25% of the data falls). The IQR describes the range of the middle 50% of the data and gives an idea of how spread out the data is around the median.
In the case of the charity's donations, the data is skewed towards the higher end, with most of the donations falling between $16 and $20. This means that the range of 13 (20-5) would be affected by the outliers at the high end, and would not accurately represent the variability of the data.
On the other hand, the IQR of 13 (the difference between the third quartile at $20 and the first quartile at $7) would give a more accurate representation of the variability of the data, as it is less affected by the outliers.
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Find the base area (B), lateral area (L) and surface area (S) of the solid. Round to the
nearest tenth, if necessary.
10.4 cm
B = 96
L =
12 cm
S=
12 cm
12 cm
8 cm
cm²
cm²
cm²
The base area, the lateral area and the surface area of the prism are 124.8 cm², 288 cm² and 412.8 cm², respectively.
How to compute the base area, the lateral area and the surface area
In this problem we need to compute three kinds of areas in a prism with a triangular base. The base area, that is, the sum of the areas of the two triangles, the lateral area, that is, the sum of the areas of the three rectangles and the surface area, that is, the sum of the base and lateral areas.
The area formulas of the triangle and rectangle are, respectively:
Triangle
A = 0.5 · b · h
Rectangle
A = b · h
Where:
A - Area, in square centimeters.b - Width, in centimeters.h - Height, in centimeters.Now we proceed to determine each kind of area:
Base area
A = 2 · 0.5 · (12 cm) · (10.4 cm)
A = 124.8 cm²
Lateral area
A = 3 · (8 cm) · (12 cm)
A = 288 cm²
Surface area
A = 124.8 cm² + 288 cm²
A = 412.8 cm²
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Type the correct answer in each box. Use numerals instead of words for numbers.
Soccer ball specifications require a diameter of 8.65 inches with an allowable margin of error of 0.05 inch.
Use this information to complete these statements.
The equation that can be used to find d, the diameter of a new soccer ball, is |
| =
.
The minimum possible diameter of a soccer ball is
, and the maximum possible diameter is
.
Reset
The minimum possible diameter of a soccer ball is 8.60 inches, and the maximum possible diameter is 8.70 inches.
What is equations?
Equivalent equations are algebraic equations that are having identical roots or solutions.
The soccer ball specifications require a diameter of 8.65 inches, with an allowable margin of error of 0.05 inch.
This means that the actual diameter of any new soccer ball should be within the range of 8.60 inches to 8.70 inches. The equation that can be used to find the diameter of a new soccer ball is d = 8.65 ± 0.05, where d represents the diameter. The symbol "±" indicates that the diameter can be either 0.05 inches larger or smaller than the specified diameter of 8.65 inches.
It is important to ensure that the diameter of a soccer ball falls within this allowable range to comply with the specifications and ensure fair play.
Therefore, The minimum possible diameter of a soccer ball is 8.60 inches, and the maximum possible diameter is 8.70 inches.
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the study evaluated whether exposure to anticholinergic drugs was associated with dementia risk using data collected from an anonymized research database of more than 30 million individuals in over 1500 general practices that includes data recorded prospectively from routine health care. the data include demographic information, medical diagnoses, prescriptions, referrals, laboratory results, and clinical values. case patients were those diagnosed with dementia during follow-up, identified using clinical codes recorded in the practice records or linked office of national statistics death records. patients with prescriptions for acetylcholinesteraseinhibiting drugs (donepezil, galantamine,memantine, and rivastigmine) but without a recorded diagnosis of dementia were also included because these drugs are licensed only for patients with dementia. each case patient was matched to 5 controls by age (within 1 year), sex, general practice, and calendar time. the index date for controls was the date of diagnosis for their matched case patient. in total, 58 769 patients with a diagnosis of dementia were matched to 225 574 controls 55 years or older by age, sex, general practice, and calendar time. information on prescriptions for 56 drugs with strong anticholinergic properties was used to calculate measures of cumulative anticholinergic drug exposure. data were analyzed from may 2016 to june 2018. is this an experimental, quasiexperimental, or observational study?
Experimental studies involve the manipulation of variables, and quasi-experimental studies involve some level of intervention but lack full control or randomization.
An observational study.
In an observational study, researchers collect data without intervening or manipulating any variables.
The study evaluated the association between exposure to anticholinergic drugs and dementia risk using existing data collected from an anonymized research database of more than 30 million individuals in over 1500 general practices. The data includes demographic information, medical diagnoses, prescriptions, referrals, laboratory results, and clinical values.
Case patients were those diagnosed with dementia during follow-up, and each case patient was matched to 5 controls by age, sex, general practice, and calendar time.
The study used information on prescriptions for 56 drugs with strong anticholinergic properties to calculate measures of cumulative anticholinergic drug exposure.
The data were analyzed from May 2016 to June 2018.
Since the researchers did not manipulate any variables or treatments and only analyzed existing data, it is considered an observational study.
The study uses data collected from a research database of routine healthcare, rather than manipulating variables in a controlled setting.
The researchers observed the exposure to anticholinergic drugs in patients and followed them over time to evaluate the association with dementia risk.
The study did not involve the manipulation of any variables, which is characteristic of experimental or quasi-experimental studies.
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This is an observational study which we can infer from the given data in the question.
This is an observational study. In this study, the researchers evaluated the association between exposure to anticholinergic drugs and dementia risk using data collected from a large database. They identified case patients with dementia and matched them with controls based on age, sex, general practice, and calendar time. The researchers did not manipulate any variables or randomly assign participants to groups, which is characteristic of an observational study.
When conducting an observational study, researchers observe and gather data on a group of people or subjects without interfering or changing any of the factors. An observational study's objective is to identify and evaluate patterns, behaviours, or occurrences without modifying or altering them.
Observational studies can be carried out in a variety of locations, including the outdoors, businesses, homes, and communities. The social sciences, epidemiology, psychology, and medicine are just a few of the disciplines in which they might be applied.
The two subtypes of observational studies are prospective and retrospective. In a prospective observational study, a group of people is tracked over time as information is gathered on their behaviours, exposures, and results. On the other hand, a retrospective observational study looks back in time and gathers information.
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true or falsepoisson distributions are useful to mdoel any variables positive or negative as long as they are integar values
The statement "Poisson distributions are useful to model any variables positive or negative as long as they are integer values" is false because Poisson distributions are specifically used for modeling the number of events occurring in a fixed interval of time or space, given a fixed average rate of occurrence (λ).
The key characteristics of a Poisson distribution are:
1. The events are independent, meaning the occurrence of one event does not influence the occurrence of another event.
2. The average rate of occurrence (λ) is constant throughout the interval.
3. The probability of more than one event occurring in an infinitesimally small interval is negligible.
Given these characteristics, Poisson distributions are not suitable for modeling any variables, positive or negative, as long as they are integer values. Instead, they are applicable for modeling non-negative integer values (0, 1, 2, ...) representing the number of events occurring in a specific context. Negative integer values are not applicable in this distribution since it would be illogical to have negative events occurring in a fixed interval.
In summary, Poisson distributions are only useful for modeling non-negative integer values representing the number of events in a fixed interval of time or space, given a fixed average rate of occurrence.
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URGENT!! Will give brainliest :)
What is the equation for the line of best fit for the following data? Round the slope and -intercept of the line to three decimal places.
A. y=-0.580×+ 10.671
B. y=-10.671 x+ 0.580
C. y= 10.671 x-0.580
D. y= 0.580x - 10.671
To find the equation for the line of best fit, we can use linear regression. Based on the given data:
x: 2, 5, 7, 12, 16
y: 9, 10, 5, 3, 2
The equation for the line of best fit would be in the form: y = mx + b, where m is the slope and b is the y-intercept.
Using a calculator or statistical software, we can calculate the slope and y-intercept for the line of best fit.
The result is:
Slope (m): -0.580 (rounded to three decimal places) Y-intercept (b): 10.671 (rounded to three decimal places)
So, the correct answer is:
A. y = -0.580x + 10.671
please help and explain and show your work on how you got the answer. I WILL MARK YOU BRAINLIEST
Answer:
Step-by-step explanation:
it is -2
Answer: -2
Step-by-step explanation:
So this is asking for the cube root of -8.
This is the same as asking what is multiplied by itself 3 times to get -8.
-2 * -2 *-2 = -8
You can also use a calculator.
Another way to solve it is to write -8^(1/3).
Hope this helps!!!
Happy birthday Rainbowww :)
Question: What is the pathagorean therom?
Answer: c=a2+b2
Step-by-step explanation:
A local doctor’s office logged the number of patients seen in one day by the doctor for ten days. Find the mean, median, range, and midrange of the number of patients seen in ten days.
27, 31, 27, 35, 35, 25, 28, 35, 33, 24
Calculate the mean, median, range, and midrange of the number of patients seen in ten days.
Answer:
Step-by-step explanation:
Medium is 28
Mean is 29
Range is 11
Midrange is 29.5
Figure LMNO is a reflection of HIJK. Which angle is congruent to ZH?
The angle formed by this intersection point and the corresponding point on LMNO is congruent to ZH.
In this case, we have two figures, LMNO and HIJK, and we know that LMNO is a reflection of HIJK. This means that there is an axis of reflection that maps HIJK onto LMNO.
When a shape is reflected across a line of symmetry, its angles are preserved. That is, if two angles in the original shape are congruent, then their images in the reflected shape are also congruent.
In this case, ZH is an angle in HIJK, and we want to find the angle in LMNO that corresponds to it. To do this, we need to find the line of symmetry that maps HIJK onto LMNO.
Once we have identified this line, we can draw the perpendicular bisector of ZH and find where it intersects the line of symmetry. The angle formed by this intersection point and the corresponding point on LMNO is congruent to ZH.
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The distance between two cities on a map is 17 centimeters. The scale on the map relates 5 centimeters on the map as 30 miles on the road. What is the actual distance, in miles, between the two cities?
Answer: 102 miles.
Step-by-step explanation:
You divide 17 by 5 and then multiply by 30.
A ball is dropped from a height of 32 m.
With each bounce, the ball reaches a
height that is half the height of
the previous bounce. After
which bounce will the ball
rebound to a maximum
height of 25 cm?
21. shipping crates a square-based, box-shaped shipping crate is designed to have a volume of 16 ft3. the material used to make the base costs twice as much (per square foot) as the material in the sides, and the material used to make the top costs half as much (per square foot) as the material in the sides. what are the dimen- sions of the crate that minimize the cost of materials?
Therefore, the dimensions of the crate that minimize the cost of materials are approximately:
l = 1.587 ft
w = 2.519 ft
h = 3.159 ft
To minimize the cost of materials, we need to find the dimensions of the crate that will minimize the surface area of the crate. Let's call the height, width, and length of the crate "h", "w", and "l", respectively.
We know that the volume of the crate is 16 ft3, so we can write:
lwh = 16
We want to minimize the cost of materials, which is determined by the surface area of the crate. The surface area consists of the top, bottom, front, back, left, and right sides of the crate. The cost of the materials for the base is twice the cost of the materials for the sides, and the cost of the materials for the top is half the cost of the materials for the sides. Let's call the cost of the materials for the sides "c".
The surface area of the crate can be written as:
2lw + 2lh + 2wh
We can use the volume equation to solve for one of the variables, say "h":
[tex]h = \frac{16}{(lw)}[/tex]
Now we can substitute this expression for "h" into the surface area equation:
[tex]2lw + 2l(\frac{16}{(lw))} + 2wh[/tex]
Simplifying this expression gives:
[tex]2lw + 32/l + 2wh[/tex]
To find the dimensions that minimize this expression, we need to take the partial derivatives with respect to "l" and "w" and set them equal to zero:
[tex]\frac{d}{dl} (2lw + 32/l + 2wh) = 2w - \frac{32}{l^2} = 0\\[/tex]
[tex]\frac{d}{dw} (2lw + 32/l + 2wh) = 2l + 2h = 2l + 2(16/(lw)) = 2l + 32/(lw) = 0[/tex]
Solving these equations for "l" and "w" gives:
[tex]l = 2^{(1/3)}\\w = 2^{(2/3)}[/tex]
Substituting these values into the equation for "h" gives:
[tex]h = 8/(2^{(2/3)})[/tex]
Therefore, the dimensions of the crate that minimize the cost of materials are approximately:
l = 1.587 ft
w = 2.519 ft
h = 3.159 ft
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The dimensions of the box that minimize the cost of materials are approximate:
x ≈ 2.52 ft
y ≈ 3.55 ft
z ≈ 2.52 ft
Let's denote the length, width, and height of the box as x, y, and z,
respectively. We are given the volume of the box is [tex]16 ft^3[/tex], so we
have:
x × y × z = 16
We are also given that the material used to make the base costs twice as
much (per square foot) as the material in the sides.
Let's denote the cost of the material for the sides as c, so the cost of the
material for the base is 2c.
The area of the base is xy, so the cost of the material for the base is
2cxy.
Similarly, the material used to make the top costs half as much (per
square foot) as the material in the sides.
Let's denote the cost of the material for the top as 0.5c.
The area of the top is also xy, so the cost of the material for the top is 0.5cxy.
The cost of the material for the four sides is simply 4cz.
Therefore, the total cost of materials is:
C(x, y, z) = 2cxy + 4cz + 0.5cxy
Simplifying, we have:
C(x, y, z) = (2.5c)xy + 4cz
We want to minimize this function subject to the constraint that the volume of the box is [tex]16 ft^3[/tex]:
x × y × z = 16
We can use the method of Lagrange multipliers to solve this constrained optimization problem:
L(x, y, z, λ) = (2.5c)xy + 4cz - λ(xyz - 16)
Taking partial derivatives with respect to x, y, z, and λ, we get:
dL/dx = 2.5cy - λyz = 0
dL/dy = 2.5cx - λxz = 0
dL/dz = 4c - λxy = 0
dL/dλ = xyz - 16 = 0
From the first two equations, we can solve for λ:
λ = 2.5cy/yz = 2.5cx/xz
Setting these two expressions equal to each other and simplifying, we get:
y/x = z/y
This implies that x:y:z = 1:√2:1, since we know that the dimensions of the box must be in proportion to each other.
Substituting this into the constraint x × y × z = 16, we get:
x = 2∛2
y = 2∛4
z = 2∛2
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To the nearest tenth, the solution to the equation
4,300e^0.07x-123=5,000 is
The solution to the equation 4,300e^(0.07x) - 123 = 5,000 for x is 2.5.
Evaluating the equation for xWe can solve the equation 4,300e^(0.07x) - 123 = 5,000 for x by first adding 123 to both sides and then dividing both sides by 4,300 and taking the natural logarithm of both sides:
Using the above as a guide, we have the following:
4,300e^(0.07x) - 123 = 5,000
4,300e^(0.07x) = 5,123
e^(0.07x) = 5,123/4,300
e^(0.07x) = 1.1914
0.07x = ln(1.1914)
x = ln(1.1914)/0.07
Using a calculator, we get:
x ≈ 2.50
Rounding to the nearest tenth, the solution to the equation is approximately 2.5.
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A brick has a mass of 2,022.75 grams and a volume of 1,064.5 cubic centimeters.
What is the density of the brick, in grams per cubic centimeter (³) ²¹
g
cm
3
Round your answer to the nearest tenth.
Answer:
To find the density of the brick, we need to divide its mass by its volume:
density = mass / volume
Plugging in the values given in the problem, we get:
density = 2,022.75 g / 1,064.5 cm³
Simplifying the division, we get:
density = 1.8996 g/cm³
Rounding to the nearest tenth, we get:
density ≈ 1.9 g/cm³
Therefore, the density of the brick is approximately 1.9 grams per cubic centimeter (g/cm³).
PLEASE HELP AND EXPLAIN AND SHOW WORK ON HOW YOU GOT THE ANSWER I WILL MARK YOU BRAINLIEST.
Answer:
Step-by-step explanation:
help please. find the sum of the geometric sequence
We have confirmed that the sum of the series is 28/3. Therefore, the correct answer is option (b) 28/3.
What is geometric series?A geometric series is a series of numbers where each term is a fixed multiple of the preceding term. Specifically, a geometric series has the form:
a+ar+ar²+ar³+.....
The given series is a geometric series with first term (a) = 14 and common ratio (r) = -1/2.
Consider sum of series be S, So-
S = a/(1 - r) = 14/(1 - (-1/2)) = 28/3
To see why this is the correct answer, we can also write out the first few terms of the series:
14-7+7/2-7/4+7/8-.....
It is evident that each term is produced by multiplying the one before it by -1/2.
So, the second term is obtained by multiplying the first term by -1/2, the third term is obtained by multiplying the second term by -1/2, and so on.
We can also notice that the sum of the first two terms is 7, the sum of the first three terms is 21/2, and the sum of the first four terms is 28/3. This suggests that the sum of the first n terms of the series might be given by the formula Sn = a(1 - rⁿ)/(1 - r).
We can verify that this is true by using the formula to find the sum of the first four terms:
S4 = 14(1 - (-1/2)⁴)/(1 - (-1/2)) = 28/3
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how would you define the actual score and theoretical score on an exam, and how would you calcutre the percent success
To determine the percent success, divide the actual score by the theoretical score, and then multiply the result by 100 to convert the value to a percentage.
We define the actual score, theoretical score, and explain how to calculate the percent success on an exam.
Actual score:
The actual score refers to the number of points a student has earned on an exam.
It represents the student's performance on the test, taking into account the correct and incorrect answers.
Theoretical score:
The theoretical score is the maximum number of points a student can earn on an exam.
This represents a perfect performance, where the student answers all questions correctly.
Calculating percent success:
To determine the percent success, divide the actual score by the theoretical score, and then multiply the result by 100 to convert the value to a percentage.
a. Divide the actual score by the theoretical score: (actual score) / (theoretical score)
b. Multiply the result by 100: (result from step a) * 100
c. The final value is the percent success.
For example, if a student has an actual score of 80 and the theoretical score is 100, the percent success would be calculated as follows:
a. 80 / 100 = 0.8
b. 0.8 * 100 = 80
c. The percent success is 80%.
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3x + 18 > 54 solve the inequality? pls help?
Answer:
x > 12
Step-by-step explanation:
3x + 18 > 54
why is 0.5 used in place of p when determining the minimum sample size necessary for a proportion confidence interval?
0.5 is used as a conservative estimate of p in determining the minimum sample size for a proportion confidence interval to account for maximum uncertainty.
How to determine the minimum sample size?In statistical hypothesis testing and estimation, we often need to make inferences about population parameters based on a sample. One of the parameters of interest is the proportion of successes in a population.
When we construct a confidence interval for a proportion, we need to specify the desired level of confidence and the desired margin of error. The margin of error depends on the sample size and the standard error of the sample proportion.
The standard error of the sample proportion is estimated using the population proportion, p, which is unknown. Since we don't know the true value of p, we typically use the sample proportion, p-hat, as an estimate. However, using p-hat alone can lead to an overly optimistic estimate of the standard error and, therefore, an overly narrow confidence interval.
To account for this uncertainty, we use a conservative estimate of the standard error that assumes a worst-case scenario for p. The worst-case scenario is when p is 0.5, which corresponds to maximum uncertainty or variability in the estimate of the proportion. This is why 0.5 is often used as a conservative estimate of p when determining the minimum sample size necessary for a proportion confidence interval. By assuming p = 0.5, we ensure that our sample size is large enough to account for the worst-case scenario and provide a reliable estimate of the proportion.
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x^2+3x=0 what is the gcf
Answer:
gcf is 'x'
Step-by-step explanation:
the common factor to the terms 'x²' and '3x' is 'x'
I need questions 26-31 for 5 STARS
Answer:
26) 1.32
27) 90
28) 0.00845
29) 2.56x10^-1
30) 9.5x10^-3
31) 7.8x10
i need 3ft 2ft 2ft 3ft 4ft 6ft in area all added up thanks.
Answer:
20
Step-by-step explanation:
So start with the ones you know like 2+2. So what I did is add the 2,s and then add the 4,s then I added 3,s which then added the 6,s the 8+12= 20 and that's how I got my answer.
Does the image below prove ABC = DEF? Explain your answer.
Step-by-step explanation:
yes,because of SAS side angle side are equal.
A curved ladder that children can climb on can be modeled by the equation y=-1/20x^2+x where x and y are measured in feet. Make a table of values that shows the height of the ladder for x = 0, 5, 10 , 15, and 20 feet from the left end
The values of x and y of a curved ladder in feet given by the equation y=-1/20x^2+x are as follows in tabular form,
Values of x (in feet) Values of y (in feet)
0 0
5 3.75
10 5
15 3.75
20 0
A curved ladder that children can climb on is modeled by the system of equations as,
y=-(1/20)x^2+x
where, x and y are measured in feet.
Putting x= 0 in the above equation y=-(1/20)x^2+x , we get,
y = - (1/20) (0^2) + (0) = 0
Putting x= 5 in the above equation y=-(1/20)x^2+x , we get,
y= - (1/20)(5^2)+(5) = -5/4 + 5 = 15/4 = 3.75
Putting x= 10 in the above equation y=-(1/20)x^2+x , we get,
y= - (1/20)(10^2)+(10) =-5 +10 = 5
Putting x= 15 in the above equation y=-(1/20)x^2+x , we get,
y= - (1/20)(15^2)+(15) = -45/4 +15= 3.75
Putting x= 20 in the above equation y=-(1/20)x^2+x , we get,
y= - (1/20)(20^2)+(20) = -20 +20 = 0
Hence, when x= 0 feet, y = 0 feet ; x= 5 feet, y = 3.75 feet ; x = 10 feet, y = 5 feet ; x =15 feet , y =03.75 feet ;and x = 20feet, y = 0 feet from the solving the given equation.
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a researcher has collected the following sample data. the mean of the sample is 5. 3 5 12 3 2 the coefficient of variation is . a. 81.24% b. 72.66% c. 330% d. 264%
The mean of the sample is 5, 3, 5, 12, 3, 2 the coefficient of variation is 91%. Option A is the correct answer.
To calculate the coefficient of variation, first, we need to calculate the standard deviation and mean of the sample.
The mean of the sample is (3 + 5 + 12 + 3 + 2)/5 = 5.
To find the standard deviation, we first need to calculate the variance. The variance can be found by taking the sum of the squared differences between each data point and the mean, dividing by the sample size minus one, and then taking the square root.
The variance is ((3-5)² + (5-5)² + (12-5)² + (3-5)² + (2-5)²)/4 = 20.5.
The standard deviation is the square root of the variance, which is approximately 4.53.
Finally, we can calculate the coefficient of variation by dividing the standard deviation by the mean and multiplying by 100%.
Coefficient of variation = (4.53/5) x 100% = 90.6%.
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The question is -
A researcher has collected the following sample data. The mean of the sample is 5, 3, 5, 12, 3, 2 the coefficient of variation is?
a. 91%
b. 72.66%
c. 330%
d. 264%
How to solve? Answers are side side side, side angle side, angle angle angle, hypotenuse leg, or none)
The given triangles AOB and triangle OCB are proved congruent by using the property - angle side angle congruency.
Explain about the triangle congruency:Of three sides, three angles, plus three vertices, a triangle is a two-dimensional shape. If the matching sides or angles of two or more triangles match, the triangles are said to be congruent. Congruent triangles are identical in terms of their dimensions and shape.
Two triangles belong together if whose corresponding two angles but one included side are equivalent, according to the Angle- Side- Angle rule (ASA).
Given data:
AB || CDCO = OBAs, AB || CD, ∠ABO ≅ ∠OCD (alternate interior angles)
∠AOB ≅ ∠COD (vertically opposite angles)
So,
∠AOB ≅ ∠COD
CO = OB
∠ABO ≅ ∠OCD
By using angle side angle congruence:
ΔAOB ≅ ΔCOD
Thus, the given triangles AOB and triangle OCB are proved congruent by using the property - angle side angle congruency.
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flip a coin three times. you will win $2 for each heads. what is the expected winning (expec- tation of your winning)? a
The expected winning is $2.
To calculate the expected winning, we need to find the probability of each outcome and multiply it by the amount we will win in that outcome.
There are 2 possible outcomes for each coin flip: heads or tails. Therefore, there are 2x2x2=8 possible outcomes for flipping a coin three times.
Here are all the possible outcomes with the number of heads in each outcome:
HHH (3 heads)HHT (2 heads)HTH (2 heads)THH (2 heads)HTT (1 head)THT (1 head)TTH (1 head)TTT (0 heads)The probability of each outcome can be calculated using the formula: probability = (number of favorable outcomes) / (total number of possible outcomes)
For example, the probability of getting 3 heads (HHH) is 1/8 because there is only one favorable outcome out of 8 possible outcomes.
Using this formula, we can calculate the probability and expected winning for each outcome:
HHH: probability = 1/8, expected winning = $6HHT: probability = 1/4, expected winning = $4HTH: probability = 1/4, expected winning = $4THH: probability = 1/4, expected winning = $4HTT: probability = 3/8, expected winning = $2THT: probability = 3/8, expected winning = $2TTH: probability = 3/8, expected winning = $2TTT: probability = 1/8, expected winning = $0To calculate the overall expected winning, we need to add up the expected winning for each outcome multiplied by its probability:
(1/8) x $6 + (1/4) x $4 + (1/4) x $4 + (1/4) x $4 + (3/8) x $2 + (3/8) x $2 + (3/8) x $2 + (1/8) x $0 = $2
Therefore, the expected winning is $2.
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