Record the following information below. Be sure to clearly notate which number is which parameter. A.) time of five rotations B.) time of one rotation C.) distance from the shoulder to the elbow D.) distance from the shoulder to the middle of the hand. A. What was the average angular speed (degrees/s and rad/s) of the hand? B. What was the average linear speed (m/s) of the hand? C. Are the answers to A and B the same or different? Explain your answer.

Answers

Answer 1

The average angular speed of the hand is ω = 1800 / t rad/s and 103140 / t degrees/s and the average linear speed of the hand is 5D / t m/s.  The answers to A and B are not the same as they refer to different quantities with different units and different values.

A) To find the average angular speed of the hand, we need to use the formula:

angular speed (ω) = (angular displacement (θ) /time taken(t))

= 5 × 360 / t

Here, t is the time for 5 rotations

So, average angular speed of the hand is ω = 1800 / trad/s

To convert this into degrees/s, we can use the conversion:

1 rad/s = 57.3 degrees/s

Therefore, ω in degrees/s = (ω in rad/s) × 57.3

= (1800 / t) × 57.3

= 103140 / t degrees/s

B) To find the average linear speed of the hand, we need to use the formula:linear speed (v) = distance (d) /time taken(t)

Here, the distance of the hand is the length of the arm.

Distance from shoulder to middle of hand = D

Similarly, the time taken to complete 5 rotations is t

Thus, the total distance covered by the hand in 5 rotations is D × 5

Therefore, average linear speed of the hand = (D × 5) / t

= 5D / t

= 5 × distance of hand / time for 5 rotations

C) No, the answers to A and B are not the same. This is because angular speed and linear speed are different quantities. Angular speed refers to the rate of change of angular displacement with respect to time whereas linear speed refers to the rate of change of linear displacement with respect to time. Therefore, they have different units and different values.

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Jocelyn estimates that a piece of wood measures 5.5 cm. If it actually measures 5.62 cm, what is the percent error of Jocelyn’s estimate?

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