solve the inequality
`-5x+2<=12`

Tim's fair share is 175 rupees and Tom's fair share is 125 rupees.

To find the fair share of both Tim and Tom depending on the work done, follow these steps:

Step 1: Find the total number of windows cleaned by both Tim and Tom.

Total number of windows cleaned = number of windows on ground floor + number of windows on first floor

Total number of windows cleaned = 7 + 8 = 15

Step 2: Find the ratio of the number of windows cleaned by Tim to the number of windows cleaned by Tom.

Ratio of Tim's work to Tom's work = number of windows cleaned by Tim / number of windows cleaned by Tom

Ratio of Tim's work to Tom's work = 7 / 8 = 0.875

Step 3: Divide the total money paid by the master (300 rupees) in the same ratio as the work done by Tim and Tom.

Tim's share = (0.875 / (0.875 + 1)) * 300 = 175 rupees

Tom's share = (1 / (0.875 + 1)) * 300 = 125 rupees

Step 4: Check the shares to ensure they add up to the total amount paid by the master.

Tim's share + Tom's share = 175 + 125 = 300 rupees

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Answer:

-407/42

Step-by-step explanation:

-8 6/7 - 5/6

-8 6/7 = -62/7

-62/7 - 5/6

= -372/42 - 35/42

= -407/42

(a) The ratio of sin A as a fraction is 63/65, cos A is 16/65 and the tan of angle A is 63/16.

(b) The ratio of sin B as a fraction is 16/65, cos B is 63/65 and the tan of angle B is 16/63.

The missing parts of the right triangle is calculated using the trigonometry principle as shown below.

For angle A:

opposite side = 63

adjacent side = 16

hypothenuse side = 65

sin A = opp/hypo = 63 / 65

cos A = adj/hypo = 16 / 65

tan A = opp/adja = 63/16

For angle B:

opposite side = 16

adjacent side = 63

hypothenuse side = 65

sin B = opp/hypo = 16 / 65

cos B = adj/hypo = 63 / 65

tan A = opp/adja = 16/63

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The prοbability that mοre than 2 animals need tο stay οvernight is apprοximately 0.9124, οr 91.24%.

The binοmial distributiοn is a prοbability distributiοn that describes the number οf successes in a fixed number οf independent trials, each with the same prοbability οf success. The distributiοn is characterized by twο parameters: the number οf trials (n) and the prοbability οf success (p) fοr each trial.

Tο sοlve this prοblem, we need tο use the binοmial distributiοn since we have a fixed number οf trials (25 animals brοught in) and each trial (animal) can either be a success (needs tο stay οvernight) οr a failure (dοesn't need tο stay οvernight).

Let X be the number οf animals that need tο stay οvernight. Then X fοllοws a binοmial distributiοn with n = 25 trials and p = 0.2 prοbability οf success (animal needing tο stay οvernight).

We want tο find the prοbability that mοre than 2 animals need tο stay οvernight, which can be expressed as:

nοw, P(X > 2) = 1 - P(X ≤ 2)

Tο calculate P(X ≤ 2), we can use the binοmial cumulative distributiοn functiοn (CDF) οr simply add up the prοbabilities οf X = 0, X = 1, and X = 2:

similarly, P(X ≤ 2) = P(X = 0) + P(X = 1) + P(X = 2)

[tex]= (0.8)^{25} + 25(0.2)(0.8)^{24} + (25\ \text{choose}\ 2)(0.2)^{2}(0.8)^{23}[/tex]

≈ 0.0876

Therefοre, P(X > 2) = 1 - P(X ≤ 2) ≈ 1 - 0.0876 = 0.9124

Sο the prοbability that mοre than 2 animals need tο stay οvernight is apprοximately 0.9124, οr 91.24%.

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The intersection of two evens a and b is the event that both a and b occur that is option A is correct.

The intersection of two events A and B is defined as the event that occurs when both A and B occur simultaneously. It is denoted by A ∩ B, where the symbol ∩ represents intersection.

For example, if event A is "getting a head when flipping a coin" and event B is "rolling a 6 on a fair die", then the intersection of A and B would be the event "getting a head when flipping a coin and rolling a 6 on a fair die".

For example, suppose A represents the event "rolling an even number on a dice" and B represents the event "rolling a number greater than 3 on a dice". The intersection of A and B is the event that "rolling a number that is both even and greater than 3 on a dice", which consists of the outcomes {4, 6}.

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Complete Question:

the intersection of two events a and b is the event that:

a) both a and b occur.

b) the union of ac and bc occurs.

c) the union of a and b does not occur.

d) either a or b or both occur.

e) either a or b, but not both.

f) none of the above.

By the central limit theorem, with a large random sample, the sample histogram will not closely resemble the normal curve but with a large random sample, the probability density function of the sample mean closely resembles the normal curve.

The central limit theorem for samples says that if we keep drawing larger and larger samples and calculating their means, the sample forms their own normal distribution (the sampling distribution). The normal distribution will have the same mean as the original distribution and a variance that equals the original variance divided by the sample size. The variable n is the number of values that are averaged together,and not the number of times the experiment is done.

Hence,with a large random sample, the sample histogram will not resemble the normal curve but with a large random sample, the probability density function of the sample mean will closely resemble the normal curve.

The complete question is-

true or false: (justify/explain your answer) state whether a or b is the true statement below and then explain why the other statement is false. a. with a large random sample, the sample histogram will closely resemble the normal curve. b. with a large random sample, the probability density function of the sample mean will close resemble the normal curve.

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Answer: 12

Step-by-step explanation: Just multiplied them

Answer:

28/51

Step-by-step explanation:

First you add up all the values: 28 + 15 + 8 = 51. That is your denominator because the total is the denominator. Then you put 28 as your numerator because that's how many off all the people that only like pizza.

Based on the boxplot, approximately 25% of these Ayrshire cattle had a butterfat percentage higher than 8.3%.

To determine this, we can look at the boxplot and see that the third quartile (Q3) is at 8.3%. Since 25% of the data is greater than 8.3%, we can infer that 25% of these Ayrshire cattle had a butterfat percentage higher than 8.3%. To further explain, a boxplot is a graphical representation of the five-number summary of a dataset, which consists of the minimum, first quartile (Q1), median (Q2), third quartile (Q3), and maximum.

The boxplot is divided into two parts, the box and the whiskers. The box indicates the interquartile range (IQR) which is the difference between the third and first quartile. The whiskers represent the minimum and maximum of the dataset. The median is shown by a line within the box. In this boxplot, the first quartile (Q1) is 6.7%, the median (Q2) is 7.4%, and the third quartile (Q3) is 8.3%. Therefore, based on the boxplot, about 25% of these Ayrshire cattle had a butterfat percentage that was higher than 8.3%.

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Complete Question : Based on the boxplot, about 25% of these ayrshire cattle had a butterfat percentage that was higher than?

The time necessary for the cell cycle for cancerous cells is significantly shorter compared to normal cells.

This implies that cancerous cells reproduce faster and therefore are able to spread more quickly. Doctors should be aware of this accelerated process so that they can provide more effective treatment options to their patients.

Explanation: In Model 1, the length of the arrow represents the time necessary for a cell to complete its cell cycle. For cancerous cells, the cell cycle is significantly shorter compared to normal cells.

This implies that cancerous cells can reproduce more quickly, and therefore spread more quickly. It is important for doctors to be aware of this so that they can make more informed decisions when it comes to treating cancer patients.

They should have an understanding of the accelerated process of cancerous cells, and use this to create better treatment plans for their patients.

This may include more aggressive methods of treatment such as chemotherapy and radiation, in order to try and stop the rapid spread of cancerous cells.

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The probability that the coin will land on the same side in all three tosses is 1/8.

There are two possible outcomes for each coin flip: heads or tails. Therefore, there are 2 × 2 × 2 = 8 possible outcomes for flipping a coin three times in a row.To find the probability that the coin will land on the same side in all three tosses, we need to count the number of outcomes that satisfy this condition.

There are only two such outcomes: either all three tosses are heads or all three tosses are tails. Therefore, the probability of this happening is 2/8 or 1/4.But we are asked for the probability that the coin will land on the same side in all three tosses, not just one specific side.

Therefore, we need to divide our previous result by 2 (the number of sides of the coin) to get the final answer: 1/4 ÷ 2 = 1/8. The probability that the coin will land on the same side in all three tosses is 1/8.

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answer for number 14 is 1115

you mutliply 27 into 1 ×45 into 100

it is 100 because we are dealing with percentage

so you say (write in fraction form)

27÷1×45÷100

=1215÷100

you get the answer of 1115

so there were 1115 female butterflies

we can subtract the answer from the original number to get the number of male butterflies

1215-1115 =100 male butterflies

Total cost of racquet at Bob's Tennis Racquet Emporium is $192.60 with a 7% sales tax on the original price of $180.00. The price tag on a similar racquet at Tennis Pro, which offers a 10% discount, is $162.00 before tax.

To calculate the total cost of the tennis racquet at Bob's Tennis Racquet Emporium, we need to add the sales tax to the original price.

Sales tax = 7% of $180.00 = 0.07 x $180.00 = $12.60

Total cost = $180.00 + $12.60 = $192.60

Therefore, the total cost of the tennis racquet at Bob's Tennis Racquet Emporium is $192.60.

If Tennis Pro offers a before-tax price that is 10% less than Bob's store for a similar racquet, we can calculate the price tag as follows:

Price at Bob's store = $180.00

Discounted price at Tennis Pro = 10% less than $180.00 = 0.10 x $180.00 = $18.00 discount

Price at Tennis Pro = $180.00 - $18.00 = $162.00

Therefore, the price tag on the similar racquet at Tennis Pro is $162.00 before tax. The sales tax amount will depend on the applicable tax rate in the area where the store is located.

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There is a 68.26% chance of a value falling between 3 and 7 in the given normal distribution.

This indicates a normal distribution, which is a type of continuous probability distribution. It is characterized by a bell-shaped curve that is symmetric about the mean, with a specific formula given by f(x) = [tex]1/(σ√2π)e^(-(x-μ)^2/2σ^2)[/tex]where μ is the mean, σ is the standard deviation, and x is the random variable.

In terms of calculation, we can use the formula to calculate the probability of a certain event occurring. For example, if we know the mean and standard deviation of a normal distribution, we can calculate the probability of a value between two given points. For example, if the mean is 5 and the standard deviation is 2, then the probability of a value between 3 and 7 is given by the integral of f(x) from 3 to 7, which is equal to 0.6826. This means that there is a 68.26% chance of a value falling between 3 and 7 in the given normal distribution.

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The value 2,649 represents the estimated population of elephants in Northwestern Namibia and Etosha National Park in 1995 and the estimated population was 618.4.

The formula for population growth can be represented as:

P = P0ert

Here, P is the population of elephants, P0 is the initial population, e is the base of the natural logarithm, r is the rate of growth or decay, and t is the time in years.

Now, as per the given data, P = 2,649P0 = initial population r = 1.045 (as per the given expression)b = t - 1995 (as per the given formula)Now, putting these values in the population growth formula,

P = P0ert2,649 = P0e1.045(b-1995)Dividing by P0 on both sides, we get:e1.045(b-1995) = 2649/P0

Taking the natural logarithm on both sides,

ln e1.045(b-1995) = ln (2649/P0)

Applying the property of logarithm,1.045(b-1995) ln e = ln (2649/P0)1.045(b-1995) = ln (2649/P0)

vAs we need to find the value of P0, substitute the value of b = 0,1.045(0-1995) = ln (2649/P0)-1.045*1995 = ln (2649/P0)ln (2649/P0) = -2069.95

Taking anti-logarithm or exponentiation on both sides,2649/P0 = eln (2649/P0) = e^(-2069.95)2649/P0 = 4.29P0 = 2649/4.29P0 = 618.4

Therefore, the estimated population of elephants in Northwestern Namibia and Etosha National Park in 1995 was 618.4.


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To find:-

Answer:-

We are here given that 1 gallon of paint can be used to paint 400 sq ft. of an area .

There are 4 walls in a room and the area of opposite walls are equal.

So let's find out the area of wall ABCD , its area would be equal to the area of the wall EFGH . So ,

Area of wall ABCD and EFGH :-

Area = lb

Area = 18ft * 8ft

Area = 144ft.²

Therefore area of wall EFGH will also be 144ft.² .

===============================================

Again,

Area of wall DAHE and CBGF :-

Here both the areas of the wall would again be equal, as they have same dimensions of 14ft × 8ft .

Area = lb

Area = 14ft * 8ft

Area = 112ft.²

Therefore area of walls DAHE and CBGF is 112ft.²

==============================================

Calculating total area of the four walls :-

Total area = 2( 112ft.² + 144ft.² )= 512ft.²

Hence total area of four walls is 512ft.²

Now since there will be two coats of paints , total area to be painted would become double that is 1024ft.²

Now we may use Unitary Method :-

To paint 400ft.² 1 gallon of paint is needed.

To paint 1ft.² 1/400 gallon of paint is needed.

To paint 1024ft.² , 1/400*1024 = 2.56 gallons of paint would be needed.

Hence the total paint required is 2.56 gallons.

and we are done!

Answer:

3 one-gallon containers of paint.

Step-by-step explanation:

First, find the total surface area that needs to be painted.

To find the surface area of the walls of a rectangular room, calculate the area of each of the four walls and then add them together.

The area of a rectangle is the product of its width and length.

For the walls of the given room, the "length" is the height of 8 ft, since we want to paint from the floor to the ceiling.

The room has four walls:

Therefore, the total surface area is:

[tex]\begin{aligned}\textsf{Total surface area}&=2(14 \times 8)+2(18 \times 8)\\&=2(112)+2(144)\\&=224+288\\&=512\;\sf ft^2\end{aligned}[/tex]

Since we want to apply two coats of paint, we need to double the surface area:

[tex]\implies 2 \times 512=1024 \; \sf ft^2[/tex]

Now, we can find how many gallons of paint are needed by dividing the total surface area by the coverage per gallon:

[tex]\implies \dfrac{1024}{400}=2.56\; \sf gallons[/tex]

Therefore, we need 2.56 gallons of paint to paint two coats of each wall of the rectangular room.

Since we cannot buy a fraction of a gallon, we need to round up to the nearest gallon. Therefore, we need to buy 3 one-gallon containers of paint.

If lisa is on her way home in her car, she has driven 24 miles so far, which is three-fourths of the way home, Lisa's total drive is 32 miles.

Let's represent the total length of Lisa's drive as x. We know that she has driven 24 miles so far, which is three-fourths of the total length. We can write this information as:

24 = (3/4) x

To find x, we need to isolate it on one side of the equation. We can start by multiplying both sides by 4/3 to get rid of the fraction:

24 * (4/3) = x

Simplifying, we get:

32 = x

We can say that Lisa has already driven 24 miles, which is three-fourths of the total distance. To find the total distance, we use the equation 24 = (3/4) x, where x represents the total distance.

To solve for x, we multiply both sides of the equation by 4/3 to cancel out the fraction, giving us 32 = x. Therefore, Lisa's total drive is 32 miles.

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Increasing the sample size leads to a more accurate estimation of the population mean.

What is Probability ?

Probability can be defined as ratio of number of favourable outcomes and total number outcomes.

As the sample size, n, increases, the center of the sampling distribution of sample means becomes more precise and closer to the true population mean. This is known as the central limit theorem, which states that as the sample size increases, the distribution of sample means becomes approximately normal with a mean equal to the population mean and a standard deviation equal to the population standard deviation divided by the square root of the sample size.

In other words, as we take larger and larger samples, we are more likely to obtain sample means that are closer to the true population mean. This is because larger samples are less affected by random fluctuations and more likely to provide a representative picture of the population as a whole.

Therefore, increasing the sample size leads to a more accurate estimation of the population mean.

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Answer:

[tex]\huge\boxed{\sf y = \frac{9-4x}{6}}[/tex]

Step-by-step explanation:

9 = 4x + 6y

9 - 4x = 6y

[tex]\displaystyle \frac{9-4x}{6} = y\\\\OR\\\\y = \frac{9-4x}{6} \\\\\rule[225]{225}{2}[/tex]

Answer:

Step-by-step explanation:

Now we have to,

→ Find the required value of y.

The equation is,

→ 9 = 4x + 6y

Then the value of y will be,

→ 9 = 4x + 6y

→ 4x + 6y = 9

→ 6y = 9 - 4x

→ 6y = -4x + 9

→ y = (-4x + 9)/6

→ y = (-4x/6) + (9/6)

→ y = (-2x/3) + (3/2)

Hence, this is the answer.

In a rectangle where the length is 3 times the width, and the perimeter is 3 times the width. The perimeter is 96 cm, the length is 36 cm and the width is 12 cm.

Given,

Length of a rectangle is 3 times the width.

Perimeter is 3 times the width.

Perimeter is 96 cm.

Let w be the width of the rectangle.

The length of the rectangle is 3 times the width, so the length l is 3w.

The perimeter of the rectangle is equal to the sum of all its sides, so:

2w + 2(3w) = 96

2w + 6w = 96

8w = 96

w = 12

Therefore, the length is 36 cm and the width is 12 cm.

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The sum of the deviations of the individual data elements from their mean is always equal to zero. Correct option is A.

This is because the deviation is defined as the difference between each data point and the mean of all the data points.

Since the mean is calculated as the sum of all the data points divided by the total number of data points, the positive deviations from the mean must be balanced out by the negative deviations from the mean. In other words, for every data point that is above the mean, there is a corresponding data point that is below the mean.

When we add up all the deviations from the mean, the positive deviations will cancel out the negative deviations, resulting in a sum of zero. This property of the sum of deviations from the mean is fundamental to many statistical concepts, such as variance and standard deviation.

Therefore, the correct answer to the question is (a) equal to zero, since the sum of the deviations from the mean is always zero.

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To prove that the functions e^(r1*t), e^(r2*t), and e^(r3*t) are linearly independent on (-∞,∞) for distinct real numbers r1, r2, and r3, we will follow the hint provided:

1. Assume to the contrary that e^(r1*t) = C1*e^(r2*t) + C2*e^(r3*t) for all t, where C1 and C2 are constants.
2. Divide both sides of the equation by e^(r1*t) to obtain: 1 = C1*e^((r2-r1)*t) + C2*e^((r3-r1)*t).
3. Differentiate both sides of the equation with respect to t:
  0 = C1*(r2-r1)*e^((r2-r1)*t) + C2*(r3-r1)*e^((r3-r1)*t).
4. Now, observe that e^((r2-r1)*t) and e^((r3-r1)*t) are linearly dependent, which is a contradiction, since we know that r1, r2, and r3 are distinct real numbers, and the exponential functions with distinct exponents are linearly independent.Thus, the functions e^(r1*t), e^(r2*t), and e^(r3*t) are linearly independent on (-∞,∞) for distinct real numbers r1, r2, and r3.

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The expected number of patients who will report symptomatic relief is 20.9. and the probability of exactly 20 patients reporting relief being 0.1977, and the probability of at least 20 patients reporting relief being 0.3832.

(a) The expected number of patients who will report symptomatic relief is 20.9.

The probability of a patient reporting symptomatic relief is 0.95, so the probability of a patient not reporting relief is 0.05. Using the binomial distribution formula, the expected value of the number of patients who will report relief is:

E(X) = n * p = 22 * 0.95 = 20.9

(b) The probability that exactly 20 patients will report symptomatic relief is 0.1977.

Using the binomial distribution formula, we can calculate the probability of exactly 20 patients reporting relief:

P(X = 20) = (22 choose 20) * 0.95^20 * 0.05^2 = 0.1977

(c) The probability that at least 20 patients will report symptomatic relief is 0.3832.

Using the binomial distribution formula, we can calculate the probability of 20 or more patients reporting relief:

P(X >= 20) = P(X = 20) + P(X = 21) + ... + P(X = 22)

P(X >= 20) = 1 - P(X < 20)

P(X >= 20) = 1 - (P(X = 0) + P(X = 1) + ... + P(X = 19))

P(X >= 20) = 1 - 0.6168

P(X >= 20) = 0.3832

Therefore, the probability that at least 20 patients will report symptomatic relief is 0.3832.

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Answer:L x b

              98ft x 56ft =5488

                                  =5488 / $3.75= $1463.47

Step-by-step explanation: Play ground is more like a rectangle so we use the formula for the rectrectangle to get total area . A=Lxb

Divide  the total with the cost since it say each per sqr feet

A=lxb

98x56=5488

5488/3.75= 1463.47

The product of 556 and 16 is therefore 33 1/4 as we express the quotient of 556 and 16 as a mixed number in the simplest form.

A mathematical assertion that two expressions are equal is known as an equation. A typical equation has one or more variables, which are often denoted by letters and have a range of possible values. Equations are frequently used in a variety of fields to describe relationships between distinct numbers or to address issues. For instance, the equation x + 2 = 5 only has one variable, x. It denotes that the product of x and 2 equals 5.

given

We can represent 556 as a rectangle with length 556 and width 1, and 16 as a rectangle with length 16 and width 1 to calculate the quotient of 556 and 16 using an area model.

This is how it goes:

To start, we deduct 16 from 556 to obtain:

556 - 16 = 540

540 = 16 x 33 + 4

Finally, by multiplying the numerator and denominator of the fraction 33 4/16 by 4, we may express the quotient of 556 and 16 as a mixed number in the simplest form, which results in:

556 ÷ 16 = 33 4/16 = 33 1/4

The product of 556 and 16 is therefore 33 1/4 as we express the quotient of 556 and 16 as a mixed number in the simplest form.

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The upper and lower 3-sigma control chart limits for this DNA sample data are UCL = 18.53 and LCL = 0

When we are given data on the DNA samples taken over the past 10 days, we can calculate the upper and lower 3-sigma control chart limits. The sample size is 100, and the defective number of DNA samples is given for each of the ten days.

The 3-sigma control limits for a process control chart can be calculated using the following formula: Upper control limit (UCL) = Mean + (3 × Standard Deviation) and Lower control limit (LCL) = Mean - (3 × Standard Deviation),where the mean is the average value of the data, and the standard deviation is the spread of the data around the mean.

Here, we need to calculate the mean and standard deviation of the defective samples for the past 10 days. The average number of defectives per day (mean) is (7+9+9+11+7+8+0+11+13+2) / 10 = 77 / 10 = 7.7

To calculate the standard deviation, firstly, calculate the variance: variance = sum of the squared differences from the mean divided by the number of samples = [tex][(7-7.7)^2 + (9-7.7)^2 + ... + (2-7.7)^2] / 10[/tex]  ≈ 13.01 2.. Now, take the square root of the variance which gives standard deviation. So, standard deviation = [tex]\sqrt{13.01\\}[/tex] ≈ 3.61

Using the 3-sigma rule UCL = Mean + (3 * Standard Deviation) = 7.7 + (3 * 3.61) ≈ 18.53    and   LCL = Mean - (3 * Standard Deviation) = 7.7 - (3 * 3.61) ≈ -3.13. However, since the LCL cannot be negative, we set it to 0 in this context. So, the upper and lower 3-sigma control chart limits are: UCL = 18.53 LCL = 0

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The bball3 dataset appears to take the form of panel data, which is a type of longitudinal data consisting of multiple observations of the same individuals over time

The bball3 dataset appears to take the form of panel data. Panel data is a type of longitudinal data where observations are made on the same individuals over time. This means that the dataset likely consists of multiple observations of a set of individuals, with the observations collected at different points in time. In a panel data set, each individual can be referred to as a ‘panel unit’.

Cross-sectional data, on the other hand, consists of observations that are collected only once, at a single point in time. This means that each observation consists of a snapshot of the population at a given moment, which is different from panel data where each observation may represent different points in time for the same individuals.

Time series data is a type of data that is collected over a period of time. It captures how a certain variable changes over time, and is often used for forecasting purposes. This is different from panel data, which captures information about the same individuals at different points in time.

In conclusion, the bball3 dataset appears to take the form of panel data, which is a type of longitudinal data consisting of multiple observations of the same individuals over time. It is not cross-sectional or time series data.

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The student should record the area of the paper as option (c) 602 cm^2

The student measured the length and width of a single sheet of paper and was asked to calculate its surface area. The surface area of the paper is the product of its length and width, which can be calculated by multiplying the two measurements together.

The surface area of the paper can be calculated as the product of the length and the width

Surface area = length × width

Substituting the given measurements, we get

Surface area = 43 cm × 14 cm

Surface area = 602 cm^2

Therefore, the correct option is (c) 602 cm^2

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The given question is incomplete, the complete question is;

A student is calculating the surface area of a single sheet of paper. he measures the length to be 43 cm he measures the width to be 14cm the student should record the area of the paper as (a) 602.64 cm^2 . (b) 602.6 cm^2 . (c) 602 cm^2 . (d) 603 cm^2 .

Answer:

a To$4198i0 multiple times a week and prosperity in 44 approximate length of 4X5

The domain and range of the function is (-∞, ∞),  (-∞, 18]

A function is a rule that gives each element from the domain set to a single element from the range set. The range is the set of values that the function can take, whereas the domain is the set of values for which the function is defined.

Consider the function f(x) = x^2, for instance. As the function may be defined for any value of x, the domain of this function includes all real numbers. Nevertheless, as the function may only accept values larger than or equal to zero, the range is limited to non-negative real numbers.

a. The domain and range of the function f(x) = -2x² + 8x + 10 are;

domain = (-∞, ∞)

range = (-∞, 18]

b. The domain and range of the function is;

domain = [0, 12]

range = [0, 18]

c. The domain and range of the function are;

domain = (-∞, ∞)

range = [-7, ∞)

d. The domain and range of the function are;

domain = (-∞, ∞)

range = [1, ∞)

Learn more on domain and range of function here;

https://brainly.com/question/2264373

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