The amount A, in milligrams, of a 10-milligram dose of a drug remaining in the body after t hours
is given by the formula A = 10(08)t Find, to the nearest tenth of an hour, how long it takes for half
of the drug dose to be left in the body.

Number of wolves hunting in medium-sized packs) to perform these calculations and obtain the percentage.

To find the percent of wolves that are neither female nor hunt in medium-sized packs, follow these steps:
1. Determine the total number of wolves.
2. Identify the number of female wolves and those that hunt in medium-sized packs.
3. Subtract the number of wolves that fit into either category from the total number of wolves.
4. Divide the remaining number of wolves by the total number and multiply by 100 to get the percentage.
Please provide the necessary data (total number of wolves, number of female wolves, and number of wolves hunting in medium-sized packs) to perform these calculations and obtain the percentage.

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B. The probability of an outcome is between 0 and 1. C. The sum of the probabilities of all possible outcomes is 1.

Option B is correct because probability values must be between 0 and 1.

Option C is correct because the sum of the probabilities of all possible outcomes must equal 1.

Option A is incorrect because it is not necessary for half of the possible outcomes to have probabilities greater than 0.5.

Option D is incorrect because the distribution does not have to be symmetrical.

Option E is incorrect because the outcomes can have common events and can be dependent.

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Answer:

false, 216° turns 3/5 in a 360° rotation

Answer:

387.692307692

Step-by-step explanation:

Answer:

B is the answer

Step-by-step explanation:

Answer:

Option D.

Step-by-step explanation:

To find hypotenuse [tex]c[/tex] use formula:

                                    [tex]\text{Cos(B)}=\frac{a}{c}[/tex]

       After substituting [tex]B=62^0[/tex]  and a = 7 we have:

                                 [tex]\text{cos}(62^o)=\frac{7}{c}[/tex]

                                     [tex]0.4695=\frac{7}{c}[/tex]

                                         [tex]c=\frac{7}{0.4695}[/tex]

                                          [tex]c=14.9104[/tex]

The distance traveled is equal to sin^2(θ), as seen before.

To find the distance traveled by a particle with position (x, y) as t varies in the given time interval, we need to first find the parametric equations for x and y in terms of t, and then compute the arc length of the curve.

Given x = sin^2(t) and y = cos^2(t), we first find the derivatives of x and y with respect to t:
dx/dt = 2 * sin(t) * cos(t)
dy/dt = -2 * sin(t) * cos(t)

Next, we compute the square root of the sum of the squares of the derivatives:
sqrt((dx/dt)^2 + (dy/dt)^2) = sqrt((2 * sin(t) * cos(t))^2 + (-2 * sin(t) * cos(t))^2) = sqrt(4 * sin^2(t) * cos^2(t) + 4 * sin^2(t) * cos^2(t)) = 2 * sin(t) * cos(t)

Now, we can find the distance traveled by integrating the above expression with respect to t over the given time interval (0, θ):

Distance traveled = ∫(2 * sin(t) * cos(t) dt) from 0 to θ

Using the substitution u = sin(t), du = cos(t) dt, we get:

Distance traveled = ∫(2 * u du) from 0 to sin(θ)

Now, integrating with respect to u, we get:

Distance traveled = u^2 | from 0 to sin(θ) = (sin^2(θ)) - (0^2) = sin^2(θ)

The length of the curve can be computed as the arc length:

Length of the curve = ∫(2 * sin(t) * cos(t) dt) from 0 to θ

As we computed earlier, the distance traveled is equal to sin^2(θ). Therefore, the distance traveled by the particle is the same as the length of the curve.

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The value of x for the angle 100 + x under the top parallel line is equal to -10.

When a transversal line intersects a pair of parallel lines, several angles are formed which includes: Corresponding angles, vertical angles, and alternate angles.

The angle 100 + x formed by the top parallel line and the transversal line perpendicular to to it is equal to 90° so we can solve for the value of x as follows:

100 + x = 90

subtract 100 from both sides

x = 90 - 100

x = -10.

Therefore, the value of x for the angle 100 + x under the top parallel line is equal to -10.

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Regional identities have led to independence movements in the United Kingdom but not in Mexico because of the history of the regions' existence as separate states in the United Kingdom.

Reason of regional identities:

In the United Kingdom, there are four countries with distinct regional identities: England, Scotland, Wales, and Northern Ireland. Each of these countries has a unique culture, language, and history, which has led to a sense of national pride and identity.Regional identities in the United Kingdom have played a significant role in independence movements.

        For example, Scotland has a long history of wanting independence from the United Kingdom. The country was an independent state until it joined the United Kingdom in 1707.

              However, many Scottish people feel that their cultural and political identity is different from the rest of the United Kingdom and have called for a referendum on Scottish independence.Mexico, on the other hand, is a unitary state with a strong central government. The country has a long history of political and cultural unity, which has led to a sense of national identity.

      Therefore, the history of the regions' existence as separate states in the United Kingdom best explains why regional identities have led to independence movements in the United Kingdom but not in Mexico.

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The rate of change of the area of a circle when the radius is 4 cm is 4π cm2/sec.

This can be calculated using the formula for the area of a circle (A = πr2) and the chain rule for derivatives. The chain rule states that when the radius (r) changes, the area of a circle (A) is equal to 2πr times the rate of change of the radius (dr/dt).

Therefore, the rate of change of the area of a circle when the radius is 4 cm is equal to 2π(4 cm) × (0.5 cm/sec) = 4π cm2/sec.

Note that if the rate of change of the radius were different, the rate of change of the area would also be different. This formula can be used to calculate the rate of change of the area of a circle at any given radius, as long as the rate of change of the radius is known.

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Answer:

Step-by-step explanation: Its 6x, you add the 6 + 1 then keep the x.

The average period of the trials that were conducted with an amplitude of 10 degrees is 1.694 seconds.

What is amplitude ?

In mathematics, amplitude refers to the maximum displacement or distance from the equilibrium position of a periodic function, such as a sine or cosine wave. In other words, if a periodic function oscillates back and forth between two extreme values, the amplitude is the maximum distance from the average value or midpoint of the oscillation to one of the extreme values.

To calculate the average period of the trials that were conducted with an amplitude of 10 degrees, we simply add up all the periods and divide by the total number of trials.

10 degrees: 1.66 s, 1.700 s, 1.71 s, 1.68 s, 1.72 s

Average period = (1.66 + 1.700 + 1.71 + 1.68 + 1.72) / 5 = 1.694 seconds

Therefore, the average period of the trials that were conducted with an amplitude of 10 degrees is 1.694 seconds.

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In Triangle ABC, we can draw a circle around each vertex of the triangle.

If the radii of all three circles are equal, then Triangle ABC is an equilateral triangle.

Radii is the plural form of radius. It is half of the diameter and the length of the radius is used to calculate the area and circumference of the circle.

To determine whether a triangle is an equilateral triangle, we can use circles.

In this method, we draw three circles, one around each vertex of the triangle.

We then measure the radii of the circles, ensuring that they are all equal. If the radii of the three circles are equal, then the triangle is an equilateral triangle.

In Triangle ABC, we can draw a circle around each vertex of the triangle. Then, we could use a measuring tool to measure the radii of each circle. If the radii of all three circles are equal, then Triangle ABC is an equilateral triangle.

This method of using circles to determine whether a triangle is an equilateral triangle is simple and efficient. It does not require any complex calculations, and it is easy to understand.

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The amount of water that the pitcher contained before Mai added more water was 7.8 liters.

Let x be the amount of water the pitcher contained before Mai added more water.

When Mai poured 2.6 liters of water, the total amount of water in the pitcher became x + 2.6 liters.

According to the problem, the pitcher then contained 10.4 liters of water. Therefore, we can write:

x + 2.6 = 10.4

Subtracting 2.6 from both sides, we get:

x = 7.8

Therefore, the pitcher contained 7.8 liters of water before Mai added more water.

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the missing dimension of the triangle is the base, which has a length of 21 feet. To find the missing dimension of the triangle, we will use the formula for the area of a triangle, which is:

Area = 1/2 x base x height

We know that the area of the triangle is 14 ft squared and the height is 6 ft. We can substitute these values into the formula and solve for the base:

14 = 1/2 x base x 6

Multiplying both sides by 2/6 (or simplifying to 1/3) gives:

14 x 3/2 = base

21 = base

Therefore, the missing dimension of the triangle is the base, which has a length of 21 feet.

This means that the triangle has a height of 6 feet and a base of 21 feet, and its area is 14 square feet. The height of a triangle is the perpendicular distance from the base to the opposite vertex, and in this case, it is given as 6 feet. The base of a triangle is the side opposite the height, and we have found that it has a length of 21 feet.

In summary, we can find the missing dimension of a triangle by using the formula for the area of a triangle and the given dimensions. In this case, we found that the missing dimension is the base, which has a length of 21 feet, and we know that the height is 6 feet.

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The first thing the surveyor did when he surveyed the new neighborhood was to reference the legal description of the property.

A legal description is a precise way of identifying and describing real estate in a manner that is legally sufficient to enable it to be transferred, sold, or mortgaged. Legal descriptions can take various forms, including metes and bounds, government rectangular survey, and lot and block descriptions.

In the case of Happy Acres, the surveyor created a lot and block survey for the new residential development. In this type of survey, the lots are identified by a number or letter, and the blocks are identified by a number.

This type of description is based on a recorded plat, which is a map or plan of a subdivision that has been legally recorded with the appropriate government agency.

Before creating the lot and block survey, the surveyor would have first referenced the legal description of the property, which would have provided the necessary information to accurately locate and describe the boundaries of the new development.

This legal description could have been obtained from various sources, including deeds, recorded plats, and other legal documents.

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Answer:

Step-by-step explanation:

[tex]\frac{7}{3} (x+\frac{9}{28} )=20[/tex]    

[tex]7 (x+\frac{9}{28} )=60[/tex]     (multiplied both sides by 3)

[tex]x+\frac{9}{28} =\frac{60}{7}[/tex]          (divided both sides by 7)

[tex]x=\frac{60}{7}-\frac{9}{28}=\frac{240}{28}-\frac{9}{28}=\frac{231}{28} =8.25[/tex]     (subtracted [tex]\frac{9}{28}[/tex] both sides and solved)

The triangle has sides; a = 11.3 ft, b = 9.03 ft, and c = 12.9 ft. 1

Angles of approximately A = 59°, B = 51°, and C = 70°

Triangle is a shape of three line segments these segments have three points which crosses it.

The Law of Cosines states that;

c² = a² + b² - 2ab Cos(C)

put values;

12.9² = 11.3² + b² - 2(11.3)(b) Cos(C)

166.41 = 127.69 + b² - 22.6b Cos(C)

b² - 22.6b Cos(C) - 38.72 = 0

We know the quadratic formula, solve it for value of b:

b = [-22.6 Cos(C) ± [tex]\sqrt{(22.6Cos(C))^2 - 4*1*(-38.72)))[/tex]] / (2×1)

b = -11.3 Cos(C) ± [tex]\frac{\sqrt{510.76 Cos^2(C) + 154.88}}{2}[/tex]

To solve for the angles A and C, we can use the Law of Sines, which states that for any triangle with sides of lengths a, b, and c, and its opposite angles which are A, B, and C, So the equation is:

sin(A)/a = sin(B)/b = sin(C)/c

We know that c = 12.9 ft and a = 11.3 ft, and we have just found b, so we can use the Law of Sines to solve for the angles A and C.

sin(A)/11.3 = sin(C)/12.9

sin(A) = (11.3/12.9)sin(C)

sin(A) = 0.875969

A = [tex]Sin^{-1}(0.875969)[/tex]

A ≈ 59° (rounded to the nearest minute)

Now we can use the fact that the sum of the angles in a triangle is 180° to solve for C:

C = 180° - A - B

C = 180° - 59° - [tex]Sin^{-1}[/tex]([22.6cos(C) ± [tex]\sqrt{(511.56 - 154.88 Cos^2(C)) }[/tex]] / 2)

We can use a numerical solver to find the value of C that satisfies this equation. One possible value for C is:

C ≈ 70° (rounded to the nearest minute)

Finally, we can use the Law of Sines again to find the other angle B:

Sin(B)/b = sin(C)/c

Sin(B) = (b/12.9)sin(C)

Sin(B) = (b/12.9)sin(70°)

B = [tex]Sin^{-1}[/tex]((b/12.9)sin(70°))

By putting the value of b,

B ≈ 51° (rounded to the nearest minute)

Therefore, the triangle has sides of lengths 11.3 ft, approximately 9.03 ft, and 12.9 ft, and angles of approximately 59°, 51°, and 70°.

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The angle ABD is 35 degrees, AC is 20 units long, and AB is 29 units long.

An angle is created by combining two rays (half-lines) that have a common terminal. The angle's vertex is the latter, while the rays are alternately referred to as the angle's legs and its arms.

Triangle ABD's angle ABC is one of its outside angles, making it equal to the sum of the opposing interior angles.

Angle ABC = Angle ABD + Angle ACD

replacing the specified values:

110° = Angle ABD + 75°

Simplifying:

Angle ABD = 110° - 75°

Angle ABD = 35°

Due of their shared angles, the two triangles are comparable. This fact can be used to establish a ratio between the corresponding sides:

AC / CD = AB / BD

replacing the specified values:

AC / 10 = 16 / 8

Simplifying:

AC = 20

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Complete Question:

Find the angle ∠ABD jn the given figure

The variables in the equations are aligned as follows:   2x - 3y = 9 and

2x - 3y = 8/3

When we talk about aligning a system of linear equations, we mean rearranging the equations so that the variables are in the same order and have the same coefficients. This is done to make it easier to apply methods for solving systems of equations, such as substitution or elimination.

In a system of linear equations, each equation typically involves two or more variables. The variables may have different coefficients in each equation, and they may appear in a different order. Aligning the system involves rearranging the equations in a way that puts the variables in the same order, with the same coefficients.

Align the variables in given the system of linear equations :

To align the variables in the given equations, we need to rearrange the second equation so that the coefficients of  and  are the same as in the first equation.

To align the variables in the equations, we need to rearrange the terms so that the x, y, and constant terms are all grouped together.

Starting with the first equation:

2x - 3y = 9

We can rearrange this as:

2x = 3y + 9

Now we can divide both sides by 2 to get x by itself:

x = (3/2)y + 4.5

Now let's move on to the second equation:

1-6x +9y = -7

We can rearrange this as:

-6x + 9y = -8

Next, we'll divide both sides by -3 to get x by itself:

2x - 3y = 8/3

Now both equations are in the form of:

ax + by = c

where a, b, and c are constants. The aligned equations are:

2x - 3y = 9

2x - 3y = 8/3

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Let's assume that each van and each bus can carry "x" number of students.

Let's assume there are "x" students in each van and each bus. Therefore, the total number of students in High School A's senior class is 8x + 8x = 16x. We know that the total number of students in High School A's senior class is 240, so we can set up an equation:

16x = 240

Solving for x, we get:

x = 15

So, each van and each bus had 15 students in it for High School A's senior class.

Similarly, for High School B, the total number of students is 4x + 1x = 5x. We know that the total number of students in High School B's senior class is 54, so we can set up an equation:

5x = 54

Solving for x, we get:

x = 10.8

Since the number of students must be a whole number, we can round up to 11. Therefore, each van and each bus had 11 students in it for High School B's senior class.

Therefore, the total number of students in High School A's senior class is 1x + 6x = 7x. We know that the total number of students in High School A's senior class is 372, so we can set up an equation:

7x = 372

Solving for x, we get:

x = 53

Therefore, each van and each bus can carry 53 students for High School A's senior class.

Similarly, for High School B, the total number of students is 4x + 12x = 16x. We know that the total number of students in High School B's senior class is 780, so we can set up an equation:

16x = 780

Solving for x, we get:

x = 48.75

Since the number of students must be a whole number, we can round up to 49. Therefore, each van and each bus can carry 49 students for High School B's senior class.

Let's assume that the price of one senior citizen ticket is "s" and the price of one child ticket is "c". Therefore, we can set up two equations based on the given information:

[tex]3s + 9c = 75[/tex]

[tex]8s + 5c = 67[/tex]

We can solve these equations simultaneously to find the values of "s" and "c". One way to do this is to multiply the first equation by 8 and the second equation by 3, so that we can eliminate "c" and solve for "s":

[tex]24s + 72c = 600[/tex]

[tex]24s + 15c = 201[/tex]

Subtracting the second equation from the first, we get:

57c = 399

Solving for "c", we get:

c = 7

Substituting this value into one of the original equations, we can solve for "s":

[tex]3s + 9(7) = 75[/tex]

[tex]3s + 63 = 75[/tex]

[tex]3s = 12[/tex]

[tex]s = 4[/tex]

Therefore, one senior citizen ticket costs $4 and one child ticket costs $7.

Let's assume that the speed of the boat in still water is "b" and the speed of the current is "c".

Therefore, we can set up two equations based on the given information:

[tex]336 = (b + c) * 12[/tex]

[tex]336 = (b - c) * 14[/tex]

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The value of x that makes the given image to be a rectangle is: x = 2.5

The length of the diagonals of a rectangle are equal and congruent to each other. It is also pertinent to note that the diagonals of a rectangle bisect each other at the center. Thus:

From the given parameters, we see that half of the diagonals have been labelled and as such we have:

8x - 3 = 4x + 7

Rearrange to have like terms on same side and so we have:

8x - 4x = 7 + 3

4x = 10

x = 10/4

x = 2.5

Thus, the value of x from the calculation above of the rectangle is 2.5

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Answer:

16

Step-by-step explanation:

When we divide the entire equation by 1/-2 to get rid of the coefficient of n we get n = 16.

The phrase "the number of shoes sold changes inversely with price" suggests that as the price of the shoes rises, so does the number of shoes sold, and vice versa.

We know that 2000 shoes can be sold for $250 in this circumstance. Using the inverse variation formula, we can write: k/Price = number of shoes sold where k is a proportionality constant. We may use the following information to calculate the value of k: 2000 = k/250 When we multiply both sides by 250, we get: k = 500000 In this case, the equation for the inverse variation is: Price/number of shoes sold = 500000 We may use this equation to compute the number of shoes sold at various prices. For instance, if the price is If the price is $300, the number of shoes sold is: The number of shoes sold is 500000/300, which is 1666.67. As a result, at a price of $300, about 1666.67 pairs of shoes would be sold.

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What is the relationship between the number of shoes sold and the price, given that the number of shoes sold varies inversely with the price? If 2,000 shoes are sold at a price of $250, what would be the price of the shoes if 3,000 shoes are sold?

Answer: 12

Step-by-step explanation: if you take the number 64 and devide it by 8 you get 8. then add 4 to eight and you get twelve

Thus, the vertices of the larger square have the following coordinates: (-6, 7),  (1, 7),(1, 0), and  (-6 ,0).

The ratio of the scale of an original thing to a new object that is a representation of it but of a variable size is known as a scale factor (bigger or smaller).

The procedures below can be used to increase form A by a scale factor of 3.5 with the centre of enlargement at (8,-7).

Transform the square so that its origin is where the centre of enlargement is (0,0).

To do this, we deduct each vertex's coordinates from the centre of enlargement (8,-7):

A = (4 - 8, -3+ 7) = (-4, 4)

B = (6 -8, -3 + 7) = (-2, 4)

C = (6 - 8, -5 + 7) = (-2, 2)

D = (4 - 8, -5 + 7) = (-4, 2)

Multiply the coordinates of the each vertex by the scaling factor (3.5) to enlarge the translated square:

A = (-14, 14)

B = (-7, 14)

C = (-7, 7)

D = (-14, 7)

By adding those coordinates of the centre of the enlargement (8,-7) to each vertex, move the square from its larger state back to its original one:

A = (-14 + 8, 14-7) = (-6, 7)

B = (-7 + 8, 14-7) = (1, 7)

C = (-7 + 8, 7-7) = (1, 0)

D = (-14 + 8, 7-7) = (-6 ,0)

As a result, the vertices of the larger square have the following coordinates: (-6, 7),  (1, 7),(1, 0), and  (-6 ,0).

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Philippe can perform a simulation of rain or no rain for tomorrow by spinning a spinner with two sections labeled "Rain" and "No rain."

The spinner could be divided into two sections, one labeled "Rain" and the other labeled "No rain." To perform the simulation, Philippe would need to give the spinner a spin and observe which section it lands on. If it lands on the "Rain" section, he would consider that as an outcome of rain for tomorrow, and if it lands on the "No rain" section, he would consider that as an outcome of no rain for tomorrow. To make the simulation more accurate, he could repeat the process multiple times and record the number of times the spinner lands on each section.

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Answer: A

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Since both the x and y coordinates changed signs, this is a reflection over the origin. A reflection over the origin is a reflection across both axes.

Answer: A

Experiment Random Variable (x)Possible values of the random variable Discrete or Continuous.

a) Take a 20-question examination Number of questions answered correctly Discrete (0, 1, 2, 3, ..., 20)

b. Observe cars arriving at a tollbooth Number of cars arriving at tollbooth for 1 hour Discrete (0, 1, 2, 3, ...)

c. Audit 50 tax returns Number of returns containing errors Discrete (0, 1, 2, 3, ...)

d. Observe an employee’s work Number of nonproductive hours in an eight-hour workday Continuous

e.Weigh a shipment of goods Number of pounds Continuous Random variables are numerical values that are a result of a random experiment. Random variables are generally classified into two categories

Solution:

discrete random variables and continuous random variables

.Discrete random variables

 When a random variable can assume only a countable number of values, it is called a discrete random variable.

Examples: the number of cars passing by a particular point of a highway in a day or the number of customers served by a shop in a day.

Continuous random variables: 

When a random variable can assume any value within a given range or interval, it is called a continuous random variable.

Examples: temperature, the weight of a person, or the height of a person.Tax returns: The random variable is discrete, as it can only take certain values (0, 1, 2, 3, and so on) since the number of tax returns containing errors is an integer.The shipment of goods: The random variable is continuous because it can assume any value between the minimum and maximum weight of the shipment, and the weight of the shipment can be any value.

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