the mean weight of an adult is 62 kilograms with a variance of 144 . if 195 adults are randomly selected, what is the probability that the sample mean would be greater than 59.5 kilograms? round your answer to four decimal places.

The statement which  is true for the quadrilateral is B.

To dilate a figure by a scale factor of 2, each point of the original figure is multiplied by 2.

So the coordinates of each vertex of A'B'C'D' are twice the coordinates of the corresponding vertex of ABCD.

The coordinates of A' are (4,10), B' are (4,4), C' are (8,6), and D' are (8,12).

To determine which statements are true, we can compare the angles and side lengths of the two quadrilaterals:

A) None of the answers apply. This may be a valid answer, but we should check the other options before concluding that none of them apply.

B) The angles of Quadrilateral ABCD and Quadrilateral A'B'C'D' are the same. This is true because dilation does not change angles. The corresponding angles of the two quadrilaterals are congruent.

C) The side lengths of Quadrilateral ABCD and Quadrilateral A'B'C'D' are not the same. We can see this by calculating the length of each side of both quadrilaterals.

Therefore, the correct answer is B.

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Answer:

x = 4√5 ≈ 8.94 (2 d.p.)

y = 8√5 ≈ 17.89 (2 d.p.)

Step-by-step explanation:

To find the values of x and y, use the Geometric Mean Theorem (Leg Rule).

The altitude drawn from the vertex of the right angle perpendicular to the hypotenuse separates the hypotenuse into two segments. The ratio of the hypotenuse to one leg is equal to the ratio of the same leg and the segment directly opposite the leg.

[tex]\boxed{\sf \dfrac{Hypotenuse}{Leg\:1}=\dfrac{Leg\:1}{Segment\;1}}\quad \sf and \quad \boxed{\sf \dfrac{Hypotenuse}{Leg\:2}=\dfrac{Leg\:2}{Segment\;2}}[/tex]

From inspection of the given right triangle RST:

Substitute the values into the formulas:

[tex]\boxed{\dfrac{20}{y}=\dfrac{y}{16}}\quad \sf and \quad \boxed{\dfrac{20}{x}=\dfrac{x}{4}}[/tex]

Solve the equation for x:

[tex]\implies \dfrac{20}{x}=\dfrac{x}{4}[/tex]

[tex]\implies 4x \cdot \dfrac{20}{x}=4x \cdot \dfrac{x}{4}[/tex]

[tex]\implies 80=x^2[/tex]

[tex]\implies \sqrt{x^2}=\sqrt{80}[/tex]

[tex]\implies x=\sqrt{80}[/tex]

[tex]\implies x=\sqrt{4^2\cdot 5}[/tex]

[tex]\implies x=\sqrt{4^2}\sqrt{5}[/tex]

[tex]\implies x=4\sqrt{5}[/tex]

Solve the equation for y:

[tex]\implies \dfrac{20}{y}=\dfrac{y}{16}[/tex]

[tex]\implies 16y \cdot \dfrac{20}{y}=16y \cdot \dfrac{y}{16}[/tex]

[tex]\implies 320=y^2[/tex]

[tex]\implies \sqrt{y^2}=\sqrt{320}[/tex]

[tex]\implies y=\sqrt{320}[/tex]

[tex]\implies y=\sqrt{8^2\cdot 5}[/tex]

[tex]\implies y=\sqrt{8^2}\sqrt{5}[/tex]

[tex]\implies y=8\sqrt{5}[/tex]

Answer:

Step-by-step explanation:

Let A be the area of the surface of the cube.

When the side length changes from s to 4s, the new area A' can be calculated as:

A' = 6(4s)^2 = 96s^2

The change in area is then:

ΔA = A' - A = 96s^2 - 6s^2 = 90s^2

To find the integral that quantifies the change in area, we can integrate the expression for ΔA with respect to s, from s to 4s:

∫(90s^2)ds from s to 4s

= [30s^3] from s to 4s

= 30(4s)^3 - 30s^3

= 1920s^3 - 30s^3

= 1890s^3

Therefore, the integral that quantifies the change in area of the surface of a cube when its side length quadruples from s units to 4s units is:

∫(90s^2)ds from s to 4s

= 1890s^3 from s to 4s

= 1890(4s)^3 - 1890s^3

= 477,840s^3 - 1890s^3

The length of the third side between 2.1 inches and 8.3 inches (exclusive) could be a valid length for the third side of the triangle.

In a triangle, the length of any side must be less than the sum of the lengths of the other two sides and greater than the difference between the lengths of the other two sides.

We can apply this rule to find the possible lengths of the third side of the triangle, given that the lengths of the two sides are 5.2 inches and 3.1 inches.

Here we have

The lengths of two sides of a triangle are 5.2 inches and 3.1 inches

Let's denote the length of the third side as x. Then, we have:

3.1 + 5.2 > x > 5.2 - 3.1

8.3 > x > 2.1

Therefore, the length of the third side x must be greater than 2.1 inches and less than 8.3 inches.

We can write this as an inequality:

2.1 < x < 8.3

Therefore,

The length of the third side between 2.1 inches and 8.3 inches (exclusive) could be a valid length for the third side of the triangle.

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The measure of angle A and B is 29° and 61° respectively

Trigonometric Ratios are defined as the values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

sin(tetha) = opp/hyp

tan(tetha) = opp/adj

cos(tetha) = adj/hyp

The opposite is 6 and the adjascent = 11

Therefore tan (tetha) = 11/6 = 1.833

tetha = tan^-1( 1.833)

= 61°( nearest degree)

The sum of angle in a triangle is 180°

therefore,

angle A = 180-( 61+90)

= 180-151

= 29°

therefore the measure of angle A and B is 29° and 61° respectively.

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To find the inverse of a function, we need to swap the positions of x and y and then solve for y. In other words, we replace f(x) with y and then solve for x.

x = 5y - 6

Next, we'll solve this equation for y:

x + 6 = 5y

y = (x + 6)/5

Answer:

The answer is 3

Step-by-step explanation:

x×108=y

x×2²×3³=y

3×108=324

The 21st term of the sequence 3, 8, 13, 18, .. is 103

To find the indicated term in the sequence, we first need to identify the pattern followed by the sequence. It appears that each term is obtained by adding 5 to the previous term. So, we can write the general formula for the nth term of the arithmetic sequence as

a(n) = a(1) + (n-1)d

where a(1) is the first term of the sequence, d is the common difference, and n is the term number.

In this case, we have:

a(1) = 3 (the first term)

d = 5 (the common difference)

To find the 21st term, we substitute n = 21 in the formula:

a(21) = a(1) + (21-1)d

a(21) = 3 + 20(5)

a(21) = 103

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One machine can produce 600,000 nails in one hour.

Finding the total number of nails produced by the three machines in a minute and dividing that number by three to obtain the number of nails produced by a single machine in a minute are the first two steps in the solution to this problem.

The number of nails produced by a single machine in an hour can then be calculated by multiplying that number by 60.

Now, we add up the total number of nails produced during :

(15 + 16 + 45 + 48 + 55 + 59 + 3) / 7 = 30

To find the number of nails produced by one machine in one hour, we multiply by 60: 10,000 x 60 = 600,000

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Answer:

£12063.57

Step-by-step explanation:

The value of Alfred’s car after 12 years can be calculated using the formula for exponential decay: Final Value = Initial Value * (1 - rate of depreciation)^(number of years). Plugging in the values we get: Final Value = 13960 * (1 - 0.0075)^12. Therefore, after 12 years, Alfred’s car will be worth approximately £12063.57.

Answer:

D. y ≥ x² - 4x - 5

Step-by-step explanation:

We can observe two characteristics of this graphed inequality:

1. its shading is above it, therefore the inequality sign must be greater than

2. its boundary line is continuous, not dotted, so the inequality sign must include or equal to

From these two observations, we can assert that D. x² - 4x - 5 is the correct answer because it is the only one which has a greater than or equal to sign.

____________

Note:

We can also check that the equation for the inequality is correct by converting it to vertex form by completing the square, then graphing it ourselves:

[tex]y \ge (x-2)^2 - 9[/tex]

Answer:

The answer is y≥ x²-4x-5

Step-by-step explanation:

x=a,x=b

where a,b are roots of the equation

a= -1 b=5

x= -1,x=5

x+1=0,x-5=0

(x+1)(x-5)=0

x²-5x+x-5=0

x²-4x-5=0

fraction wise, a whole is always simplified to 1, so

[tex]\cfrac{4}{4}\implies \cfrac{1000}{1000}\implies \cfrac{9999}{9999}\implies \cfrac{17}{17}\implies \text{\LARGE 1} ~~ whole[/tex]

so, we can say the whole of the players, namely all of them, expressed in fourth is well, 4/4, that's the whole lot,  and we also know that 3/4 of that is 12, the guys who chose the bottle of water

[tex]\begin{array}{ccll} fraction&value\\ \cline{1-2} \frac{4}{4}&p\\[1em] \frac{3}{4}&12 \end{array}\implies \cfrac{~~ \frac{4 }{4 } ~~}{\frac{3}{4}}~~ = ~~\cfrac{p}{12}\implies \cfrac{~~ 1 ~~}{\frac{3}{4}} = \cfrac{p}{12}\implies \cfrac{4}{3}=\cfrac{p}{12} \\\\\\ (4)(12)=3p\implies \cfrac{(4)(12)}{3}=p\implies 16=p[/tex]

Step-by-step explanation:

x = -4     ( the value of the x-coordinate of the vertex is the axis of symmetry for normal up or down opening parabolas)

Answer:

mean: 101 (add all the numbers then divide by 7)

mode: 102 (the most frequent number in the set)

median: 102 (the number in the middle of the set)

range: 20 (the difference between the largest and smallest number)

Mean = 101

Mode = 102

Median = 102

Range = 20

MEAN: Add up all the numbers, then divide by how many numbers there are.

102 + 107 + 99 + 102 + 111 + 95 + 91 = 707

707 ÷ 7 = 101

MODE: Arrange all numbers in order from lowest to highest or highest to lowest and then count how many times each number appears in the set. The one that appears the most is the mode.

91,95,99,102,102,107,111

MEDIAN: Arrange the numbers from smallest to largest. If the amount of numbers is odd, the median is the middle number. If it is even, the median is the average of the two middle numbers in the list.

91,95,99,102,102,107,111

RANGE: Subtract the lowest number from the highest number

111 - 91 = 20

The center of gravity is located 96.7 inches aft of the datum.

To determine the location of the center of gravity (CG) of the system, we need to calculate the moment of each weight about the datum, and then divide the sum of the moments by the total weight of the system.

The moment of each weight is equal to its weight multiplied by its distance from the datum. In this case:

Moment of weight a = 140 pounds x 17 inches = 2,380 inch-pounds

Moment of weight b = 120 pounds x 110 inches = 13,200 inch-pounds

Moment of weight c = 85 pounds x 210 inches = 17,850 inch-pounds

The total weight of the system is:

Total weight = weight a + weight b + weight c = 140 + 120 + 85 = 345 pounds

Therefore, the location of the CG can be calculated as follows:

CG location = (Moment of weight a + Moment of weight b + Moment of weight c) / Total weight

CG location = (2,380 + 13,200 + 17,850) / 345

CG location = 33,430 / 345

CG location = 96.7 inches aft of datum

As a result, the center of gravity is 96.7 inches aft of the datum.

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Answer:

5 1/4

Step-by-step explanation:

Answer:

r = 2

center: ( -7,0 )

Step-by-step explanation:

The decimal that represents the fraction of the $30.00 Maggie spent is 0.6.

Now, let's talk about decimals. Decimals are a way of expressing parts of a whole number in a fraction of 10. For example, 0.5 is the same as 1/2. In your situation, Maggie spent $18.00 out of $30.00. To figure out what decimal represents the fraction of the $30.00 Maggie spent, we need to divide the amount she spent by the total amount she had.

So, we can write this as a fraction:

$18.00 / $30.00

To turn this fraction into a decimal, we divide the numerator (top number) by the denominator (bottom number) using long division or a calculator.

$18.00 / $30.00 = 0.6

Another way to say this is that Maggie spent 60% of the money she had in her wallet.

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Answer:

Same equation just using the assocaitive property

Step-by-step explanation:

For example, 8 + (2 + 3) = (8 + 2) + 3 = 13

Hope this helps! =D

Answer:

A

Step-by-step explanation:

Equation of a line is:    y = mx + b    where  m = slope    b = y axis intercept

      To find the slope between any two of the given points :

  say   18, 100   and     27, 85

    m = slope =  (y1-y2) / (x1-x2) = (85-100) / ( 27-18)  = -15/12 = -5/3  

so now you have

   y = - 5/3 x   + b       we still need to find the value of b

                                        use any point to calculate b

                              say    15, 106

     106 = - 5/3 (15) + b    

          b = ~ 131

the equation is then     y = - 5/3 x + 131     closest  to answer 'A'

To verify if older adults and middles ages people spend less time on social media, Justin can use the Analysis of variance (ANOVA) test.

ANOVA is used to compare means across two or more groups. Justin can use this test on the different category of younger adults, middle-aged and older adult. This test is done when there is statistically significant difference between the group of samples.

Justin can utilize post-hoc tests (such as Tukey's HSD and Bonferroni) to identify whether particular groups are statistically different from one another if an ANOVA shows a significant difference.

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The balloon payment at the end of 7 years would be $173,819.97, which is option A.

A 7/23 balloon mortgage means that April will make payments on the loan as if it were a 23-year mortgage, but the remaining balance of the loan will be due in full after 7 years.

To find the balloon payment at the end of 7 years, we can first calculate the monthly payment using the loan amount, interest rate, and loan term:

n = 23 * 12 = 276 (total number of payments)

r = 4.15% / 12 = 0.003458 (monthly interest rate)

P = (r * PV) / (1 - (1 + r)^(-n))

where

PV = $197,000

P = (0.003458 * $197,000) / (1 - (1 + 0.003458)^(-276)) = $1,007.14 (monthly payment)

Now we can calculate the remaining balance on the loan after 7 years. Since April is making payments as if it were a 23-year mortgage, she will have made 7 * 12 = 84 payments by the end of the 7th year.

Using the formula for the remaining balance of a loan after t payments:

B = PV * (1 + r)^t - (P / r) * ((1 + r)^t - 1)

Where

t = 84 (number of payments made)

B = $197,000 * (1 + 0.003458)^84 - ($1,007.14 / 0.003458) * ((1 + 0.003458)^84 - 1)

B = $173,819.97

Therefore, the balloon payment at the end of 7 years would be $173,819.97, which is option A.

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Answer:

[tex]f(x) = 500( {.89}^{x} )[/tex]

The sine function that describes the child's apparent distance from the center of the merry-go-round is d(t) = 5.3 sin(2π/15 * t)

To write a sine function that describes the child's apparent distance from the center of the merry-go-round as a function of time t, we can start by finding the amplitude, period, and phase shift of the motion.

Amplitude:

The amplitude of the motion is half the diameter of the merry-go-round, which is 10.6/2 = 5.3 feet. This is because the child moves back and forth across the diameter of the merry-go-round.

Period:

The period of the motion is the time it takes for the child to complete one full cycle of back-and-forth motion, which is equal to the time it takes for the merry-go-round to complete one full rotation.

From the given information, the child completes 8 rotations in 120 seconds, so the period is T = 120/8 = 15 seconds.

Phase shift:

The phase shift of the motion is the amount of time by which the sine function is shifted horizontally (to the right or left).

In this case, the child starts at one end of the diameter and moves to the other end, so the sine function starts at its maximum value when t = 0. Thus, the phase shift is 0.

With these values, we can write the sine function that describes the child's apparent distance from the center of the merry-go-round as:

d(t) = 5.3 sin(2π/15 * t)

where d is the child's distance from the center of the merry-go-round in feet, and t is the time in seconds. The factor 2π/15 is the angular frequency of the motion, which is equal to 2π/T.

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When x is 2, the value of the expression is 9.

An algebraic expression is a mathematical phrase that contains one or more variables, constants, and mathematical operations such as addition, subtraction, multiplication, and division. It can also contain exponents, roots, and trigonometric functions.

Algebraic expressions are used to represent mathematical relationships and solve problems in a wide range of fields, including physics, engineering, finance, and statistics. They can be used to model real-world phenomena and to make predictions based on data.

Algebraic expressions can be simplified by combining like terms and using mathematical rules and properties. They can also be evaluated by substituting values for the variables and simplifying the expression. Solving equations involving algebraic expressions often involves manipulating the expression to isolate a variable and find its value.

When x is 2, the value of the expression 12/4+3(8−x)-12 can be found by substituting 2 for x and simplifying the expression:

12/4 + 3(8 - 2) - 12

= 3 + 3(6) - 12

= 3 + 18 - 12

= 9

Therefore, when x is 2, the value of the expression is 9.

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The complete question is :

When x is 2, what is the value of the expression 12/4+3(8−x)-12?

Answer: The answer is A.

Step-by-step explanation: Because I am smart don't underestimate me.

Answer:

C

Step-by-step explanation: (look at attachment)

3x + 4 = -2x -2

By looking at the y-intercepts, you automatically know the answer is C.

The y-intercept of the pink line is 4 because of 3x + 4.

The y-intercept of the blue line is -2, because of -2x - 2.

The distance between A and B is approximately 8.06 units.

In order to find the distance, d, of AB, we need to use the distance formula. The distance formula gives us the distance between two points in a coordinate plane. It is given as:$$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$ where (x1, y1) and (x2, y2) are the coordinates of the two points in question.

In this case, A and B are the two points for which we need to find the distance. Let's assume that the coordinates of A are (x1, y1) and the coordinates of B are (x2, y2).

Then the distance formula becomes:

$$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$

$$d = \sqrt{((8 + 4) - 2)^2 + ((5 - 1) - 3)^2}$$

$$d = \sqrt{(10 - 2)^2 + (4 - 3)^2}$$

$$d = \sqrt{(8)^2 + (1)^2}$$

$$d = \sqrt{64 + 1}$$

$$d \approx \sqrt{65}$$

$$d \approx 8.06$$

Therefore, the distance between A and B is approximately 8.06 units.

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Answer:

[tex]c + 15 > 24[/tex]

[tex]c > 9[/tex]

The additional amount will be more than $9.

The x-axis and y-axis are two parallel number lines that meet at (0, 0) to form the shape of the letter t.

Geometric objects and mathematical equations are represented on the coordinate plane, a two-dimensional graph. It is made up of the x-axis and y-axis, two parallel number lines that meet at the starting point (0, 0). The horizontal coordinate is represented by the x-axis, while the vertical coordinate is represented by the y-axis. They combine to create the Cartesian coordinate system.

Positive numbers are labelled to the right of the origin and negative values are labelled to the left of the origin on the x-axis. Positive numbers are written above the origin of the y-axis, and negative numbers are written below it. An ordered pair (x, y), where x denotes the horizontal coordinate and y denotes the vertical coordinate, is used to represent each point on the coordinate plane.

For graphing linear equations, quadratic equations, and other functions, the coordinate plane is a helpful tool. Additionally, it is employed to depict geometric forms like polygons, circles, and lines. The distance between two points, the slope of a line, and other significant features of mathematical objects can be calculated by graphing points on the coordinate plane. With applications in physics, engineering, economics, and computer science, the coordinate plane is a fundamental idea in mathematics.

The graph is shown below when y=1.

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Graph attached below,

The coordinates of the plane is

x       y

1       -3.5

2      -3

4      -2

6      -1.

What is equation?

The definition of an equation in algebra is a mathematical statement that demonstrates the equality of two mathematical expressions. For instance, the equation 3x + 5 = 14 consists of the two equations 3x + 5 and 14, which are separated by the 'equal' sign.

Here the given equation is y = [tex]\frac{1}{2}x-4[/tex].

Now put x= 1 then y = [tex]\frac{1}{2}\times1-4 =\frac{1-8}{2}=\frac{-7}{2}=-3.5[/tex]

Now put x=2 then [tex]y=\frac{1}{2}\times2-4=1-4=-3[/tex]

Now put x=4 then [tex]y=\frac{1}{2}\times4-4=2-4=-2[/tex]

Now put x=6 then [tex]y=\frac{1}{2}\times6-4=3-4=-1[/tex]

Then coordinates of the plane is

x       y

1       -3.5

2      -3

4      -2

6      -1.

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