Three solid, uniform, cylindrical flywheels with a radius of 1.47 m and a mass of 65.0 kg each rotate. The system's net angular momentum is 297.77 298 kg m2 / s in size.
I is the moment of inertia.
W = angular momentum L = angular velocity
I = 1/2 MR^2
I = 1/2 (65)(1.47^2)
I = 70.23
Moment of Inertia times Angular Velocity equals L.
In the same direction, two of the fly wheels turn.
L = 2I(W1) - I(W2) (W2)
L = 2*70.23(3.83) - 70.23(3.42) (3.42)
L = 297.77 ≈ 298 kg m^2 / s
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an object projected horizontally from a height flies through the air before hitting the ground. the path of the projectile in the air can be described as a
The path of the projectile is parabola projected horizontally from a height flies through the air before hitting the ground.
What is projectile and what is the path of projectile in air before hitting the ground?A projectile is an object that is compelled to move under the influence of external force.And then the projectile moves freely under the influence of gravity as in here too.Here an object is projected horizontally from a height flies through the air before hitting the ground.The path of the projectile before hitting the ground would be parabola in the air .Hence when an object projected horizontally from a height flies through the air before hitting the ground, the path of the projectile in the air is parabola.To know more about projectile visit:
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Force Problem: Four concurrent forces are applied to a 5 Kg mass: 50 N North, 25 N East, 35 N South, and 35 N West.
a. Find the resultant force on the mass.
b. Find the acceleration of the mass.
c. What equilibrium force will sustain equilibrium?
d. What will be the acceleration of the object if it’s mass doubles?
e. Find the equilibrium force if all the initial forces are doubled.
A) Net horizontal force:
Fx= -35 + 25 + -10N
Net vertical force
Fy= 50 - 35 = 15N
Net force
F^2 = fX^2 +Fy^2
F= 18N
B.) Acceleration of system
a=18/5=3.6m/s^2
C). Equilibriant force must be equal to the net force above
F1= 18N
D.) Acceleration becomes half
a1= a/2 =1.8m/s^2
E.) Equilibrant force also doubles
F" = 2F' = 36N
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Which of the following can increase your energy levels?
OA. Getting enough sleep.
OB. Spending plenty of time with your friends and family.
OC. Getting your schoolwork done early in the day.
D. Reading for an hour each day.
the first option, getting enough sleep
write 3500 in units with the appropriate prefixes
If we are to write 3500 in units with the appropriate prefixes, this would be 3.5kg.
What is SI Unit?This refers to the metric system that is used and accepted internationally and is used as a standard for the measurement of items
Hence, when it comes to the use of SI Units, the name of the unit with the prefixes deka, hecto, and kilo are used, meaning, respectively, 10, 100, and 1000.
With this in mind, 1000 units would make one kilo and if we are to write this mathematically this would be 3500 divided by 1000 which is 3500/100, and which would be 3,5.
Therefore, the correct answer is 3.5kg.
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Answer:
3*10^3 g or 0.3*10^4 g
Explanation:
Your community is considering building a dam on a nearby river to reduce flooding. Would you support this proposal? Explain
Yes I would support the proposal of building a dam on a nearby river to reduce flooding.
What is flooding?Flooding is defined as the over spreading of water beyond the banks of a water body or the covering of a large area of land with uncontrolled flow of water.
A dam is a structure that is usually constructed over a flowing water body such as a river, to withhold water which can be diverted for the generation of electricity.
The construction of dam over a water body that usually overflows and floods an area can help control water spread as it's diverts the excess water for other purposes.
Therefore, I would support the proposal that a dam on the nearby river should be constructed.
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PLEASE ANSWERRRRRRRRRRRRRR
Law of Reflection :
The law of reflection states that when light rays strike a smooth surface, the angle of reflection equals the angle of incidence, and the incident ray, reflected ray, and normal to the surface all lie in the same plane.
Here, let us consider, the ray A as the normal , as it is perpendicular to the surface of the plane mirror. When the incident ray hits the plane mirror at an angle say, θ with the normal ( here, incident ray A) , then, θ will be the angle of reflection.
Now if we consider all the incident rays A, B, C and D. Among them, let the ray C make an angle Θ, with the normal ( here, incident ray A).
Therefore, from the image given, clearly, θ = Θ, hence Θ is the angle of reflection, thus ray C best represents the reflected ray.
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What two pieces of information would you need in order to measure the masses of stars in an eclipsing binary system?.
The two pieces of information would you need in order to measure the masses of stars in an eclipsing binary system include the following below:
The time between eclipses.The average distance between the stars.What is Eclipsing binary system?This refers to the different process which occurs in the solar system in which two close stars move in an orbit in space in relation to Earth such that the light of one can at times be hidden behind the other.
The masses of stars can be measured in this system through measuring the time between the eclipses so so to ascertain the accurate differences observed.
The average distance between stars provide more information about mass as a lighter one will most likely be faster which is therefore the reason why it was chosen as the correct choice.
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Answer:
Time between eclipses and the average distance between the stars
Explanation:
Match the engines in the following list with their drawbacks. Place your answer in the blank space given. i. gunpowder engine ii. Savery engine iii. Newcomen engine iv. Watt engine a.____ The boiler could not withstand the steam pressure needed to lift water beyond 6 m. b.____ The engine had no mechanism to move the piston back to complete a cycle. c.____ The continual reheating needed after each cooling of the engine cylinder required a tremendous amount of thermal energy. d.____ This engine was large and massive and less efficient than thought possible.
a. (ii) Savery engine - The boiler could not withstand the steam pressure needed to lift water beyond 6 m.
b. (i) Gun powder engine - The engine had no mechanism to move the piston back to complete a cycle.
c. (iii) Newcomen engine - The continual reheating needed after each cooling of the engine cylinder required a tremendous amount of thermal energy.
d. (iv) Watt engine - This engine was large and massive and less efficient than thought possible.
Explanation:
a. Creating a lower vacuum in Savery engine causes more water to evaporate and limits the pressure differential. Practically, Savery's device was limited to 20-25 feet of suction (20 feet = 6 m).
b. The explosion of gun powder, in the gunpowder engine, forces the piston upwards for the gas to escape from the tube. Gravity and air pressure then pull the piston back. It then lifts another weight when it reaches the bottom, it explodes again and the cycle restarts.
c. The Newcomen engine operates by condensing steam drawn into the cylinder, thereby creating a partial vacuum which requires continual reheating after each cooling and a tremendous amount of thermal energy.
d. Watt's engine was able to convert around 2% of the thermal energy in steam to work. Later, the efficiency of this engine was increased to approximately 17%.
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a cylindrical glass rod is heated with a torch until it conducts enough current to cause a light bulb to glow. the rod has a length , a diameter , and its ends, plated with material of infinite conductivity, are connected to the rest of the circuit. when red hot, the rod's conductivity varies with position measured from the center of the rod as
a)The total resistance of the rod R = 2.1 * 10^(3)Ω
b) current Density when voltage ΔV is applied between two ends is J(x) = [tex]=\frac{12\sigma_o\Delta V}{L}[/tex]
c) Steady-state electric field is E(x) = [tex]\frac{12\Delta V}{L^3} x^2\hat{i}[/tex]
a) Consider a small slice of the rod of thickness dx situated at a distance x from the center of the rod.
L = length of rod = 2cm, d= diameter = 0.5cm,
Given [tex]\sigma(x)=\sigma_oL^2/x^2[/tex] where σ is the rod's conductivity.
[tex]\sigma_o = 4 * 10^{-2}(\Omega.m)^{-1}[/tex] (given)
The resistance dR of this small section of the rod is
dR=[tex]\frac{\rho_rdx}{A}=\frac{dx}{\sigma_rA} = \frac{4x^{2} dx}{\sigma_o L^2\pi d^2}[/tex]
The total resistance of the rod can be found by the integral of these smalls sections over the whole rod
[tex]R = \int\limits^{L/2}_{-L/2} \, dR = \int\limits^{L/2}_{-L/2} \,\frac{4x^2dx}{\sigma_oL^2\pi d^2}=\frac{4x^3}{3\sigma_oL^2\pi d^2} |_{-L/2}^{L/2} = \frac{L}{3\sigma_o\pi d^2}[/tex]
⇒R = (2*10^(-2)) / (3 * 4 * 10 ^(-2)* π * 0.5 * 10^(-2))
⇒R = 2.1 * 10^(3) Ω
Thus the total resistance of the rod R = 2.1 * 10^(3) Ω
b)The current density when voltage ΔV is applied between two ends is given by
J(x) [tex]=\frac{I}{A}=\frac{4\Delta V}{R\pi d^2} =\frac{12\sigma_o\Delta V}{L}[/tex]
c) the steady-state electric field is
[tex]E(x) = \frac{J(x)}{\sigma} =\frac{12\sigma_o \Delta V / L}{\sigma_o L^2 / x^2} \hat{i} = \frac{12\Delta V}{L^3} x^2\hat{i}[/tex]
The question is incomplete. The full question is probably " A cylindrical glass rod is heated with a torch until it conducts enough current to cause a light bulb to glow. The rod has a length of L=2.0cm, and a diameter of d= 0.5cm, and its ends, plated with the material of infinite conductivity, are connected to the rest of the circuit. When red hot, the rod’s conductivity varies with position x measured from the center of the rod as [tex]\sigma(x)=\sigma_oL^2/x^2[/tex] with [tex]\sigma_o = 4 * 10^{-2}(\Omega.m)^{-1}[/tex] a)What is the resistance of the glass rod? Express your answer both symbolically and as a value in ohms. b)When a voltage ΔV is applied between the two ends, what is the current density J(x)? c)What is the steady-state electric field E(x)? "
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p3. a double-convex lens is to be made of glass with an index of refraction of 1.5. one surface is to have twice the radius of curvature of the other and the focal length is to be 60 mm. what is the (a) smaller and (b) larger radius?
The magnitude of smaller and larger radius is 45mm and 90mm respectively.
Using lens makers formula:
1/f = (n-1) (1/ [tex]r_{1}[/tex] - 1/ [tex]r_{2}[/tex])
where n is the index of refraction, [tex]r_{1}[/tex] and f is the focal length and the curvature's radius of the first surface the light touches, and [tex]r_{2}[/tex] is the second's radius of curvature. The radius of one surface is two times that of the other, such that one is concave to the incoming light and the other is convex.
Plugging in the values we get:
1/f = (n-1) (1/ [tex]r_{1}[/tex] + 1/ [tex]2r_{1}[/tex]) = 3(n-1) / 2[tex]r_{1[/tex]
(a) For magnitude of smaller radius:
3(n-1)f / 2 = 3(1.5-1)(60) / 2 = 45mm
(b) For larger radius:
[tex]r_{2} = 2r_{1}[/tex] = 90mm
Therefore, the magnitude of smaller and larger radius is 45mm and 90mm respectively.
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In the formula:
M1 M2
r2
r is the distance:
from M₁ to the nearest magnetic body
FM = K
between poles M₁ and M 2
between the magnetic lines of force
from the North Pole
Answer: The answer is between poles M 1 and M 2
Explanation:
Suppose you were a farmer trying to grow plants in a greenhouse. Why would it be important to know what the limiting factor is ?
Limiting factors are those factors which limits the growth in the ecosystem. Examples of limiting factors include temperature, sunlight, soil configuration, precipitation and nutrients. It is important to know what the limiting factor is for the limiting factors greatly affects the growth of the plants. Not considering these limiting factors would result in the failure of growing the plants in a greenhouse.
What is Limiting factors ?
Any element (variable) in the environment that has the potential to restrict a process, such as the expansion, abundance, or distribution of a population of species in an ecosystem, is referred to as a limiting factor. Both density-dependent and density-independent limiting variables are possible. Those that depend on population density have a tendency to restrict population increase, abundance, or dispersal. On the other hand, a limiting factor that is independent of population density can restrict population expansion, abundance, or dispersal.
Limiting factors are those factors which limits the growth in the ecosystem. Examples of limiting factors include temperature, sunlight, soil configuration, precipitation and nutrients. It is important to know what the limiting factor is for the limiting factors greatly affects the growth of the plants. Not considering these limiting factors would result in the failure of growing the plants in a greenhouse.
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A car starts from rest and reaches a speed of 26 m/s in 8.5 seconds. What is the acceleration of the car? Round to 4 decimal places if necessary
ANSWER
3.0588 m/s²
EXPLANATION
Given:
• The final speed of the car, v = 26 m/s
,• The initial speed of the car, u = 0 m/s - remember that it starts from rest
,• The time it takes the car to reach the final speed, t = 8.5 s
Find:
• The acceleration of the car, a
The speed of an object is given by the equation,
[tex]v=u+at[/tex]In this case, u = 0 m/s, so we have,
[tex]v=at[/tex]Solving for a and replacing the known values,
[tex]a=\frac{v}{t}=\frac{26\text{ }m/s}{8.5\text{ }s}\approx3.0588\text{ }m/s^2[/tex]Hence, the acceleration of the car is 3.0588 m/s², rounded to four decimal places.
Two helium isotopes fuse to form beryllium, as shown below. The mass of beryllium is 2.73 x 107 kg less than the combined mass of the two helium atoms. How much energy was produced during this reaction? The speed of light is 3 x 108 m/s. Show your work. Use E = mc².
3/2He+ 4/2He → 7/4Be
A chemical element with the symbol Be and atomic number 4 is known as beryllium. Beryllium is a solid at room temperature and is categorized as an alkaline earth metal. The molar mass of beryllium (atomic number 4) is 9.012 g/mol. Accordingly, if all 6.22x1023 Beryllium atoms were put together in a mole, they would weigh 9.012g on a triple beam balance.
Explain about the mass of beryllium?
The atomic mass unit serves as the unit of measurement for mass (amu). A mass unit of an atom is 1.66 x 10-24 gram. The mass of one nucleon, which can be either a single proton or neutron, is roughly equal to one unified atomic mass unit, which is numerically equivalent to 1 g/mol.
In the aircraft industry in particular, beryllium is employed in gears and cogs. A silvery-white metal is beryllium. It has a low density and is relatively soft. Gyroscopes, springs, electrical contacts, spot-welding electrodes, and non-sparking tools all use beryllium in alloys with copper or nickel.
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how does the total kinetic energy of a cannon and cannonball system change as the mass of the cannon increases and the energy of the blast remains the same?
When the cannon's mass grows and the blast's energy stays constant, the total kinetic energy also stays constant.
What is kinetic energy?Kinetic energy is the force that propels motion, which can be seen in the movement of a particle, an object, or a group of particles. A person walking, a baseball being thrown, a piece of food falling from a table, and a charged particle in an electric field are all instances of objects in motion that use kinetic energy.
Kinetic energy is the kind of power that an object has as a result of motion. It is known as the effort necessary to move a body.
It is important to keep in mind that when the cannon's mass increases while the blast's energy stays constant, the total kinetic energy will also stay constant.
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you have two solid metal sphere that are identical except thatr one has a radius exactly twice the other(with the same density). what is the ratio of their moment of inertia?
The elasticity and Poisson's ratio for this metal is 0.232.
What is ratio?
The realation between two numbers which shows how much bigger one quantity is than another.
Sol-
As per the given question
P=190KN
d=16 mm
Lo=50mm
X=50.1349-50=0.1349mm
Y=15.99-16=-0.01mm
The formula-
E=ó/€
Ó=P/A
A=r/4 d^2 =π/4(16)^2=201.062 mm
ó={190(1000)}201.062=944.982 Mpa
E=944.982/0.002698=350.253 GPa
€y=-0.000625
v=0.232(answer)
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The velocity-time equation for a golf cart isVA= (1 m/s) + (-0.5 m/s?)t (a) What is the cart's initial velocity? (b) What is the cart's acceleration?
If the velocity-time equation for a golf cart is v = (1 m/s) + (-0.5 m/s)t , then the initial velocity of the cart would be 1 m / s and the acceleration of the cart would be - 0.5 m / s² .
What is acceleration?The rate of change of the velocity with respect to time is known as the acceleration of the object. Generally, the unit of acceleration is considered as meter/seconds².
As given in the problem the velocity-time equation for a golf cart is
v = (1 m/s) + (-0.5 m/s)t ,
The initial velocity of the cart at t = 0 would be 1 m / s.
By differentiating the given equation of the velocity,
The acceleration of the cart would be -0.5 m / s.
Thus, the initial velocity would be 1 m / s and the acceleration would be -0.5 m / s.
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2. Car A, moving in a straight line at a constant speed of 20. meters per second, is initially 200 meters
behind car B, moving in the same straight line at a constant speed of 15 meters per second. How far
must car A travel from this initial position before it catches up with car B?
A) 800 m
B) 200 m
C) 1000 m
D) 400 m
Answer:
Explanation:
Given:
V₁ = 20 m/s
ΔS = 200 m
V₂ = 15 m/s
___________
S - ?
Car motion equation:
X₁ = V₁*t = 25*t
X₂ = ΔS + V₂*t = 200 + 15*t
Since the second car overtook the first, then:
X₁ = X₂
25*t = 200 + 15*t
5*t = 200
t = 200 / 5 = 40 с
Distance:
S = ΔS + V₂*t = 200 + 15*40 = 200 + 600 = 800 m
Correct answer:
A) 800 m
if instead the same ball is used and the rope is shortened; that is, if rope 3 is half the length of rope 1, what is the tension t1 in the rope compared to the tension t3 in the shorter rope?
The tension in the shorter rope is double the tension in the longer rope T1<T3.
What is tension?
In physics, tension is defined as the pulling force that is transmitted axially by a string, rope, chain, or similar object, or through each end of a rod, truss member, or other comparable three-dimensional object. Tension can also be defined as the activity pair of forces acting at every end of the aforementioned elements. The polar opposite of compression might be tension. When atoms or molecules have been pulled apart from one another at the atomic level and gain potential energy while a restoring force is still present, the restoring force may produce what is also known as tension. When a string or rod is under such tension, each end may pull on the thing it is attached to in an attempt to release the tension and return the string or rod to its relaxed length.
The relation between the tension in the string and the length of the tetherball is,
mol=T The length of the rope 3 is half of the length of the rope 1.
Therefore mw^2l=T T∝l
The length of the rope 3 is half of the length of the rope 1.
Therefore l1=l3/2T1=T3/2T1<T3
Hence, the answer is T1<T3
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an object undergoing simple harmonic motion has an amplitude of if the maximum velocity of the object is what is the object's angular frequency? an object undergoing simple harmonic motion has an amplitude of if the maximum velocity of the object is what is the object's angular frequency? 6.5 rad/s
the acceleration is maximum at the peak position and kinetic energy is connected with the mean position.
the object which is performing a simple harmonic motion because the acceleration is directly proportional to displacement that the direction is opposite side the formula is given by
F= -K X
K is the spring constant
because the amplitude means the maximum displacement
the maximum velocity means that the that is proportional to the angular frequency and the relation is given by
V=rW
V is the velocity
r is the radius
W is the angular frequency that the SI unit is rad/s.
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If an object undergoing simple harmonic motion with amplitude 2.3 m and velocity 15 m/s maximum, then its angular frequency is 6.52 rad/s.
Missing data from the question:
- the amplitude is 2.3 m
- the maximum velocity of the object is 15 m/s
The equation for the velocity of a simple harmonic motion is given by:
v = A. ω. cos(ωt)
Where:
ω = angular frequency
A = amplitude
Parameters given:
A = 2.3 m
v = 15 m/s
Let's take t = 0, hence,
v = A. ω. cos(0) = A . ω
15 = 2.3 ω
ω = 15/2.3 = 6.52 rad/s
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Tamara is playing a game of billiards. The white cue ball has a mass of 0.17 kg and all the other balls have a mass of 0.16 kg. The cue ball is moving at a velocity of 6 m/s when it collides with the number seven ball. If the cue ball comes to a complete stop after the collision, then what will the resulting velocity be on the number seven ball?
Tamara is playing a game of billiards. The white cue ball has a mass of 0.17 kg and all the other balls have a mass of 0.16 kg. The cue ball is moving at a velocity of 6 m/s when it collides with the number seven ball. If the cue ball comes to a complete stop after the collision, then the resulting velocity of the number seven ball will be 6.375 m/s
The law of conservation of momentum states that, within some problem domain, the amount of momentum remains constant; momentum is neither created nor destroyed, but only changed through the action of forces as described by Newton's laws of motion.
using law of conservation of momentum
initial momentum of the system = final momentum of the system
m1u1 + m2u2 = m1v1 + m2v2 equation 1
m1 = mass of cue ball
u1 = initial velocity of cue ball
m2 = mass of number seven ball
u2 = initial velocity of number seven ball
v1 = final velocity of cue ball
v2 = final velocity of number seven ball
substituting in equation 1
(0.17 * 6) + ( 0.16 * 0 ) = (0.17 * 0) + ( 0.16 * v2)
v2 = 6.375 m/s
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in real life, is it possible to replicate the experiment newton is performing in the simulation? can you actually swing a ball in a horizontal circle with a perfectly horizontal string? explain your answer
No, it is not possible to replicate the experiment which Sir Newton had performed .
What is circular motion ?
A circular path is followed by an object as it moves along at a constant speed is termed a circular motion
The wire cannot be completely straight or horizontal, as you might expect given its weight. Gravity (mg) and the tension of the rope are the two forces that are constantly exerting pressure on the ball, ignoring the weight of the rope.
These must have a vector total that is mv2/r in the radial direction. The tension force must have an opposing vertical component in order to balance the vertical gravity pull, hence the rope cannot be perfectly horizontal. The angle will be less as the mass is rotated more quickly. Additionally, the mass moves in a perfectly horizontal motion in the absence of resistive losses. The same holds true if the youngster swinging the rope precisely balances the losses.
What is centrifugal acceleration ?
From inside the automobile, it seems as though you are being pushed out of the turn's centre. The centrifugal force is a hypothetical force. This effect is more pronounced the sharper the curve and the faster you are travelling.
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50 N of force is applied to a spring and its length increases by 25 cm. If the spring is obeying Hooke's law, what force would be required to give it an extension of 75 cm?
I think the spring constant is not changing
the most common type of topographic map is created by the USGS is a 7.5-minute by 7.5-minute quadrangle map (figure 3.18). this means that each side of the map is 7 minutes and 30 seconds. each minute of latitude is 1852 meters and each second of latitude is 31 meters. how many meters does this map cover in a north-south direction?
Answer: I think it's 13,000 meters
Explanation:
The concept of inertia forms the basis for Newton's Third Law of Motion True False
Given
The concept of inertia forms the basis for Newton's Third Law of Motion
To find
The given statement is true or false
Explanation
The third law of motion states that every action has a equal and opposite reaction
Inertia is the property by virtue of which an object at rest tends to be at rest and object at motion tends to be at motion
Thus both the concept are not similar
Conclusion
The given statement is false
An atmospheric layer of a specific gas provides shielding from harmful ultraviolet light from the sun, allowing life to thrive on earth. What gas makes up this layer?.
Since stratospheric ozone shields life on Earth from harmful ultraviolet (UV) radiation, it is frequently referred to as "good" ozone.
How does the atmosphere safeguard life on Earth?It not only has the oxygen we require to survive, but it also shields us from dangerous UV sun radiation. It generates the pressure necessary for liquid water to exist on the surface of our planet. Additionally, it heats our planet and maintains conditions that allow life to exist on Earth.
The ozone layer, located higher up in the stratosphere, absorbs solar ultraviolet radiation and modulates the amount of heat that is returned to space from the Sun. Overexposure to UV radiation may cause sunburn, skin cancer, and eye damage. The ozone layer protects humans from these negative consequences.
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thermal energy 1. causes the mass of a body to increase. 2. decreases as the temperature of a body increases. 3. is characterized by the random motion of molecules. 4. is the only form of energy that can be transformed into work with 100% efficiency.
Thermal energy 3. is characterized by the random motion of molecules.
In the field of physics, thermal energy can be described as the internal energy present inside an object or system.
The thermal energy present in the molecules of an object causes the molecules to move randomly. It is the energy that causes random motion in atoms.
If the thermal energy keeps on increasing, the movement of molecules also keeps on increasing.
For example, the molecules in water have lower thermal energy initially due to which they show lesser random motion. As we increase heat, the thermal energy increases causing the random motion to increase and water turns into steam as we keep on increasing the thermal energy.
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Two identical clocks are set to 12 noon time when on the ground at rest relative to the ground. One clock is placed in a spacecraft, sent into space and accelerated to a speed of v = 0.93 x 108 m/s. What will the moving clock read if the first clock reads 6 p.m.? Express your answer as the number of minutes from 6 pm.
First, for this problem, we will need to know the formula for time dilation
[tex]t=\frac{t_0}{\sqrt{1-\frac{v^2}{c^2}}}[/tex]Where t is the time in the reference frame on earth
t0 is the time on the ship
v is the velocity relative to lightspeed
and c is light speed in a vacuum
For this problem, we will need to convert .93x10^8 to a fraction of light speed.
.93x10^8 = .31c
Now, we can plug in the numbers we get from the given
t0 = 6 hours since the ship has been in the air for 6 hours
[tex]t=\frac{6}{\sqrt{1-\frac{(.31c)^2}{c^2}}}[/tex]t = 6.31089
For the answer to be valid, we will convert .31089 to minutes by multiplying it by 60 (60 minutes in a hour)
18.654 minutes
a 90.0-kg man is standing on a scale in an elevator that is accelerating upward at 2.00 m/s2. what will be the scale reading? a. 696 n ob. 788 n oc947 n od. 883 n oe. 1,060
The scale reading of a man standing on a scale in an elevator that is accelerating upward at 2.00 m/s2 is 788 N.
Acceleration is the price of change in the velocity of an object with the recognition of time. Accelerations are vector portions. The orientation of an item's acceleration is given by way of the orientation of the internet pressure acting on that item.
Acceleration is the price at which pace adjustments with time, in phrases of both speed and course. A factor or an object shifting in an immediate line is elevated if it hurries up or slows down. movement on a circle is expanded despite the fact that the rate is constant, due to the fact the path is constantly changing.
f = mg - ma
= 900 - 180
= 788 N
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a rocket accelerates vertically upward from rest with acceleration a. after 4.0 s, a small object falls from the rocket. the object strikes the ground 6.0 s later. determine the acceleration of the rocket in terms of g.
Answer:
(9/4)g
Explanation:
The distance the rocket travels is given by:
D = v*t + 1/2*a*t^2. Where v is the initial velocity, t is time, and a is the acceleration. We don;t have the distance nor the acceleration, so the best we can do is rearrange for distance, D, since we we will be able to calculate that with information about the falling rocket.
D =(1/2)a(4)^2
D = 8a
If we find D, we can calculate a, the acceleration of the rocket.
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We are told the rocket takes 8 seconds to fall from height D, The relationship between distance and time with a falling object with force g (earth;s gravity) is:
D = v*t + 1/2*a*t^2
The initial velocity is 0 (rocket turns), the force is g, gravity, and time is 6 seconds, We can set that to the distance calculated in the first step: 8a
8a = 0*t + 1/2*g*(6)^2
8a = 1/2*g*36
a = (36/16)g
a = (9/4)g
The rocket's acceleration was (9/4)g