Answers
The given equation is expressed as
x + 4y = 8
4y = 8 - x
y = 2 - x/4
The first step is to input values for x into the equation and determine the corresponding y values. These values are then plotted on the graph.
For x = 0, y = 2 - 0/4 = 2
For x = 1, y = 2 - 1/4 = 1.75
For x = 2, y = 2 - 2/4 = 1.5
We would plot these points on the graph
Related Questions
2x - 6(x-3) ≥ 5
solve for x.
Answers
Answer:
It’s siu
Step-by-step explanation:
Answer:x≤4.6
Step-by-step explanation: 2x-6(x-3)≥5. 1).combine the like terms. 2x+x=3x & -6+-3=-9. 2). isolate the "x". 3x-9≥5. 3x≥14. 3). divide both sides by your coefficient. 3x≥14/ 3
x≥4.6
4) flip your sign. x≤4.6
How to write slope intercept form
Answers
Answer:
See below
Step-by-step explanation:
If you are given slope (m) and intercept (b) , then write the line equation like this:
y = mx + b
A pound of rice crackers cost 42.88 Jacob purchased a 1/4 pound how much did he pay for the crackers?
Answers
Answer:
10.72
Step-by-step explanation:
The price per pound is 42.88
We are getting 1/4 pound.
Multiply 42.88 by 1/4
42.88 * 1/4 =10.72
Answer:
So you know that a pound of rice crackers cost $42.88. You also know that Matthew bought 1/4 or 25% or 0.25 of a pound. This means that by 42.88 divided 4 will equal the answer.
42.88 ÷ 4 = 10.72
Therefore, Matthew paid or $10.72 for 1/4 pound of rice crackers.
Find the formula for an exponential function that passes through the 2 points given
Answers
The form of the exponential function is
[tex]f(x)=a(b)^x[/tex]a is the initial value (value f(x) at x = 0)
b is the growth/decay factor
Since the function has points (0, 6) and (3, 48), then
Substitute x by 0 and f(x) by 6 to find the value of a
[tex]\begin{gathered} x=0,f(x)=6 \\ 6=a(b)^0 \\ (b)^0=1 \\ 6=a(1) \\ 6=a \end{gathered}[/tex]Substitute the value of a in the equation above
[tex]f(x)=6(b)^x[/tex]Now, we will use the 2nd point
Substitute x by 3 and f(x) by 48
[tex]\begin{gathered} x=3,f(x)=48 \\ 48=6(b)^3 \end{gathered}[/tex]Divide both sides by 6
[tex]\begin{gathered} \frac{48}{6}=\frac{6(b)^3}{6} \\ 8=b^3 \end{gathered}[/tex]Since 8 = 2 x 2 x 2, then
[tex]8=2^3[/tex]Change 8 to 2^3
[tex]2^3=b^3[/tex]Since the powers are equal then the bases must be equal
[tex]2=b[/tex]Substitute the value of b in the function
[tex]f(x)=6(2)^x[/tex]The answer is:
The formula of the exponential function is
[tex]f(x)=6(2)^x[/tex]the length of a rectangle is 13 centimeters less then four times it’s width it’s area is 35 centimeters find the dimensions of the rectangle
Answers
Solution:
The area of a recatngle is expressed as
[tex]\begin{gathered} \text{Area of rectangle = L}\times W \\ \text{where} \\ L\Rightarrow\text{length of the rectangle} \\ W\Rightarrow\text{ width of the rectangle } \end{gathered}[/tex]Given that the length of the rectangle is 13 centimeters less than four times its width, this implies that
[tex]L=4W-13\text{ ---- equation 1}[/tex]Tha area of the rectangle is 35 square centimeters. This implies that
[tex]36=L\times W\text{ --- equation 2}[/tex]Substitute equation 1 into equation 2. Thus,
[tex]\begin{gathered} 36=L\times W \\ \text{where} \\ L=4W-13 \\ \text{thus,} \\ 36=W(4W-13) \\ open\text{ parentheses} \\ 36=4W^2-13W \\ \Rightarrow4W^2-13W-36=0\text{ ---- equation 3} \\ \end{gathered}[/tex]Solve equation 3 by using the quadratic formula expressed as
[tex]\begin{gathered} W=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}_{} \\ \text{where} \\ a=4 \\ b=-13 \\ c=-36 \end{gathered}[/tex]thus, we have
[tex]\begin{gathered} W=\frac{-(-13)\pm\sqrt[]{(-13)^2-(4\times4\times-36)}}{2\times4}_{} \\ =\frac{13\pm\sqrt[]{169+576}}{8} \\ =\frac{13\pm\sqrt[]{745}}{8} \\ =\frac{13}{8}\pm\frac{\sqrt[]{745}}{8} \\ =1.625\pm3.411836016 \\ \text{thus,} \\ W=5.036836016\text{ or W=}-1.786836016 \end{gathered}[/tex]but the width cannot be negative. thus, the width of the recangle is
[tex]W=5.036836016[/tex]From equation 1,
[tex]\begin{gathered} L=4W-13 \\ \end{gathered}[/tex]substitute the obtained value of W into equation 1.
Thus, we have
[tex]\begin{gathered} L=4W-13 \\ =4(5.036836016)-13 \\ =20.14734-13 \\ \Rightarrow L=7.14734 \end{gathered}[/tex]Hence:
The width is
[tex]5.036836016cm[/tex]The length is
[tex]7.14734cm[/tex]help meeeeeeeeee pleaseee !!!!!
Answers
The composition of the function (g o f)(5) is evaluated as: (g o f)(5) = g(f(5)) = 6.
How to Determine the Composition of a Function?To find the composition of a function, we have to first evaluate the inner function for the given value of x that is given as its input. After that, the output of the inner function would then be used as the input for the outer function, which would now be evaluated for the composition of the function.
Given the functions:
f(x) = x² - 6x + 2
g(x) = -2x
We need to find the composition of the function, (g o f)(5), where the inner function is f(x), and the outer function is g(x).
Therefore:
(g o f)(5) = g(f(5))
Find f(5):
f(5) = (5)² - 6(5) + 2
f(5) = -3
Substitute x = -3 into g(x) = -2x:
(g o f)(5) = -2(-3)
(g o f)(5) = 6
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1. Sketch the graph of y = x that is stretched vertically by a factor of 3. (Hint: Write the equation first, then graph) Sketch both y = x and the transformed graph.
Answers
ANSWER and EXPLANATION
We want to stretch the graph of:
y = x
A vertical stretch of a linear function is represented as:
y' = c * y
where c is the factor
The factor from the question is 3.
So, the new equation is:
y' = 3 * x
y' = 3x
Let us plot the functions:
Can someone help with this question?✨
Answers
The equation of the line that is perpendicular with y = 4 · x - 3 and passes through the point (- 12, 7) is y = - (1 / 4) · x + 4.
How to derive the equation of a line
In this problem we find the case of a line that is perpendicular to another line and that passes through a given point. The equation of the line in slope-intercept form is described below:
y = m · x + b
Where:
m - Slopeb - Interceptx - Independent variable.y - Dependent variable.In accordance with analytical geometry, the relationship between the two slopes of the lines are:
m · m' = - 1
Where:
m - Slope of the first line.m' - Slope of the perpendicular line.If we know that m = 4 and (x, y) = (- 12, 7), then the equation of the perpendicular line is:
m' = - 1 / 4
b = 7 - (- 1 / 4) · (- 12)
b = 7 + (1 / 4) · (- 12)
b = 7 - 3
b = 4
And the equation of the line is y = - (1 / 4) · x + 4.
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Don’t get part b of the question. Very confusing any chance you may help me with this please.
Answers
To solve this problem, first, we will solve the given equation for y:
[tex]\begin{gathered} x=3\tan 2y, \\ \tan 2y=\frac{x}{3}, \\ 2y=\arctan (\frac{x}{3}), \\ y=\frac{\arctan(\frac{x}{3})}{2}=\frac{1}{2}\arctan (\frac{x}{3})\text{.} \end{gathered}[/tex]Once we have the above equation, now we compute the derivative. To compute the derivative we will use the following properties of derivatives:
[tex]\begin{gathered} \frac{d}{dx}\arctan (x)=\frac{1}{x^2+1}, \\ \frac{dkf(x)}{dx}=k\frac{df(x)}{dx}. \end{gathered}[/tex]Where k is a constant.
First, we use the second property above, and get that:
[tex]\frac{d\frac{\arctan(\frac{x}{3})}{2}}{dx}=\frac{d\arctan (\frac{x}{3})\times\frac{1}{2}}{dx}=\frac{1}{2}\frac{d\arctan (\frac{x}{3})}{dx}\text{.}[/tex]Now, from the chain rule, we get:
[tex]\frac{dy}{dx}=\frac{1}{2}\frac{d\text{ arctan(}\frac{x}{3})}{dx}=\frac{1}{2}\frac{d\arctan (\frac{x}{3})}{dx}|_{\frac{x}{3}}\frac{d\frac{x}{3}}{dx}\text{.}[/tex]Finally, computing the above derivatives (using the rule for the arctan), we get:
[tex]\frac{dy}{dx}=\frac{1}{2}\frac{\frac{1}{3}}{\frac{x^2}{9}+1}=\frac{1}{6}(\frac{1}{\frac{x^2}{9}+1})=\frac{3}{2(x^2+9)}.[/tex]Answer:
[tex]\frac{3}{2(x^2+9)}.[/tex]Help asp show your work you’ll get brainliest
Answers
The information given in the table on the Value of a Car and the Age of the Car, gives;
First Part;
The dependent variable is; The Value of Car
The independent variable is; The Age of Car
Second part;
The situation is a function given that each Age of Car maps to only one Value of Car.
What is a dependent and a independent variable?A dependent variable is an output variable which is being observed, while an independent variable is the input variable which is known or controlled by the researcher.
First part;
The given information in the table is with regards to how the car's value decreases with time, therefore;
The dependent variable, which is the output variable, or the variable whose value is required is the current Value of the Car (Dollars)The independent variable, which is the input variable, or the variable that determines the value of the output or dependent variable, is the Age of Car (Years)Second part;
A function is a relationship in which each input value has exactly one output.
Given that the Values of the cars are all different, and no two car of a particular age has two values, therefore;
The situation is a functionGiven that the first difference varies depending on the age of the car, the function can be taken as a piecewise function
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a janitor had 2/3 of a cleaning solution. he used 1/4 of the solution in an day. how much of the bottle did he use?
Answers
Answer:
5/12 of the cleaning solution.
Step-by-step explanation:
2/3 – 1/4
------------------------------------------
2 × 4
= 8/12
3 × 4
------------------------------------------
1 x 3
= 3/12
4 x 3
------------------------------------------
8 – 3
12
= 5/12
------------------------------------------
Hopefully this makes sense!
Factor.2n2 + 7n + 5
Answers
The first step to factor this expression is to find its roots (the values of 'n' that makes this expression equals zero)
To find the roots, we can use the quadratic formula:
(Using the coefficients a=2, b=7 and c=5)
[tex]\begin{gathered} n_1=\frac{-b-\sqrt{b^2-4ac}}{2a}=\frac{-7-\sqrt{49-40}}{4}=\frac{-7-3}{4}=\frac{-10}{4}=\frac{-5}{2} \\ n_2=\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{-7+3}{4}=\frac{-4}{4}=-1 \end{gathered}[/tex]So the roots of the expression are -5/2 and -1. Now, we can write the expression in this factored form:
[tex]\begin{gathered} a(n-n_1)(n-n_2) \\ 2(n+\frac{5}{2})(n+1) \\ (2n+5)(n+1) \end{gathered}[/tex]So the factored form is (2n+5)(n+1)
Consider the triangles ADB and EDC. Explain how they are similar.
Answers
Example: Triangles like ABC and EDC are similar by SAS similarity, because angle C is congruent in each triangle, and AC/EC = BC/DC = 2. By the definition of similarity, it follows that AB/DE = BC/EF = AC/DF = 2.
Find the absolute maximum and minimum values of the following function on the given interval. f(x)=3x−6cos(x), [−π,π]
Answers
Answer:
Absolute minimum: x = -π / 6
Absolute maximum: x = π
Explanation:
The candidates for the absolute maximum and minimum are the endpoints and the critical points of the function.
First, we evaluate the function at the endpoints.
At x = -π, we have
[tex]f(-\pi)=3(-\pi)-6\cos (-\pi)[/tex][tex]\Rightarrow\boxed{f(-\pi)\approx-3.425}[/tex]At x = π, we have
[tex]f(\pi)=3(\pi)-6\cos (\pi)[/tex][tex]\Rightarrow\boxed{f(\pi)\approx15.425.}[/tex]Next, we find the critical points and evaluate the function at them.
The critical points = are points where the first derivative of the function are zero.
Taking the first derivative of the function gives
[tex]\frac{df(x)}{dx}=\frac{d}{dx}\lbrack3x-6\cos (x)\rbrack[/tex][tex]\Rightarrow\frac{df(x)}{dx}=3+6\sin (x)[/tex]Now the critical points are where df(x)/dx =0; therefore, we solve
[tex]3+6\sin (x)=0[/tex]solving for x gives
[tex]\begin{gathered} \sin (x)=-\frac{1}{2} \\ x=\sin ^{-1}(-\frac{1}{2}) \end{gathered}[/tex][tex]x=-\frac{\pi}{6},\; x=-\frac{5\pi}{6}[/tex]
on the interval [−π,π].
Now, we evaluate the function at the critical points.
At x = -π/ 6, we have
[tex]f(-\frac{\pi}{6})=3(-\frac{\pi}{6})-6\cos (-\frac{\pi}{6})[/tex][tex]\boxed{f(-\frac{\pi}{6})\approx-6.77.}[/tex]At x = -5π/6, we have
[tex]f(\frac{-5\pi}{6})=3(-\frac{5\pi}{6})-6\cos (-\frac{5\pi}{6})[/tex][tex]\Rightarrow\boxed{f(-\frac{5\pi}{6})\approx-2.66}[/tex]Hence, our candidates for absolute extrema are
[tex]\begin{gathered} f(-\pi)\approx-3.425 \\ f(\pi)\approx15.425 \\ f(-\frac{\pi}{6})\approx-6.77 \\ f(-\frac{5\pi}{6})\approx-2.66 \end{gathered}[/tex]Looking at the above we see that the absolute maximum occurs at x = π and the absolute minimum x = -π/6.
Hence,
Absolute maximum: x = π
Absolute minimum: x = -π / 6
I had $70 and my mother gave me $10 and my father gave me $30 and aunt and uncle gave me $150 and I had another $7 how much do I have
Answers
Initial money = 70
then add
10 + 30 + 150 + 7 = 197
Now add both results
70 + 197 = 267
Answer is
You have $267
If each machine produces nails at the same rate, how many nails can 1 machine produce in 1 hour
Answers
Divide the number of nails by the number of minutes:
16 1/5 ÷ 15 = 1 2/25 per minute
48 3/5 ÷ 45 = 1 2/25 per min
59 2/5 ÷ 55 = 1 2/25 per min
We have the number of nails produced per minute, to calculate the number of nails in an hour multiply it by 60, because 60 minutes= 1 hour:
1 2/25 x 60 = 64 4/5
write the number 1,900 in scientific notation
Answers
Explanation
[tex]1900[/tex]Calculating scientific notation for a positive integer is simple, as it always follows this notation:
[tex]a\cdot10^b[/tex]Step 1
To find a, take the number and move a decimal place to the right one position.
so
[tex]1900\Rightarrow1.900\text{ }[/tex]Step 2
Now, to find b, count how many places to the right of the decimal.
[tex]1900\Rightarrow1.900\text{ ( 3 places)}[/tex]Step 3
finally,
Building upon what we know above,
a= 1.9
b=3 (Since we moved the decimal to the left the exponent b is positive)
replace
[tex]\begin{gathered} a\cdot10^b \\ a\cdot10^b=1.9\cdot10^3 \end{gathered}[/tex]therefore, the answer i
[tex]1.9\cdot10^3[/tex]I hope this helps you
If your distance from the foot of the tower is 20 m and the angle of elevation is 40°, find the height of thetower.
Answers
We have to use the tangent of angle 40 to find the height of the tower.
[tex]\text{tan(angle) = }\frac{opposite\text{ side}}{\text{adjacent side}}[/tex]The adjacent side is 20m, and the angle is 40 degrees, then
[tex]\tan (40)\text{ = }\frac{height\text{ of the tower}}{20m}[/tex][tex]\text{height = 20m }\cdot\text{ tan(40) = 20m }\cdot0.84\text{ = }16.8m[/tex]Therefore, the height of the tower is 16.8m
helppppppppppppppppppp
Answers
Which number is greater in each set?
Answers
We have three set of numbers and we must choose the greater value in each set
1.
[tex]\frac{1}{3}or\frac{1}{4}or\frac{1}{5}[/tex]When the numerator is 1, the greater fraction is the one that has the small denominator.
So, in this case the greater number is
[tex]\frac{1}{3}[/tex]2.
[tex]\frac{1}{4}or\frac{4}{3}or\frac{5}{6}[/tex]In this case we can rewrite the fractions as fractions with the same denominator
[tex]\frac{1}{4}=\frac{3}{12}[/tex][tex]\frac{4}{3}=\frac{16}{12}[/tex][tex]\frac{5}{6}=\frac{10}{12}[/tex]Then, the greater number is the one that has the greater numarator
So, it is
[tex]\frac{16}{12}=\frac{4}{3}[/tex]in this case the greater number is
[tex]\frac{4}{3}[/tex]3.
[tex]\frac{16}{5}or3\frac{2}{5}or3.25[/tex]In this case we can rewrite the numbers as decimal numbers
[tex]\frac{16}{5}=3.2[/tex][tex]3\frac{2}{5}=3.4[/tex][tex]3.25=3.25[/tex]In this case the greater number is
[tex]3\frac{2}{5}[/tex]Angle RQT is a straight angle. What are m angle RQS and m angle TQS? Show your work.
Answers
11x + 5 + 8x + 4 = 180
Simplifying like terms
11x + 8x = 180 - 5 - 4
19x = 171
x = 171/19
x = 9
RQS = 11(9) + 5
= 99 + 5
= 104°
TQS = 8(9) + 4
= 72 + 4
= 76°
If you select one card at random from a standard deck of 52 cards, what is the probability of that card being a 5, 6 OR 7?
Answers
To solve this question we will use the following expression to compute the theoretical probability:
[tex]\frac{\text{favorable cases}}{total\text{ cases}}.[/tex]1) We know that there are 4 fives, 4 sixes, and 4 sevens in a standard deck of 52 cards, then, the probability of selecting a 5, 6, or 7 is:
[tex]\frac{4+4+4}{52}\text{.}[/tex]2) Simplifying the above expression we get:
[tex]\frac{12}{52}=\frac{3}{13}\text{.}[/tex]Answer:
[tex]\frac{3}{13}\text{.}[/tex]A circle has a circumference of 10 inches. Find its approximate radius, diameter and area
Answers
Answer:
Radius = 1.59 in
Diameter = 3.18 in
Area = 7.94 in²
Explanation:
The circumference of a circle can be calculated as:
[tex]C=2\pi r[/tex]Where r is the radius of the circle and π is approximately 3.14. So, replacing C by 10 in and solving for r, we get:
[tex]\begin{gathered} 10\text{ in = 2}\pi r \\ \frac{10\text{ in}}{2\pi}=\frac{2\pi r}{2\pi} \\ 1.59\text{ in = r} \end{gathered}[/tex]Then, the radius is 1.59 in.
Now, the diameter is twice the radius, so the diameter is equal to:
Diameter = 2 x r = 2 x 1.59 in = 3.18 in
On the other hand, the area can be calculated as:
[tex]A=\pi\cdot r^2[/tex]So, replacing r = 1.59 in, we get:
[tex]\begin{gathered} A=3.14\times(1.59)^2 \\ A=3.14\times2.53 \\ A=7.94in^2 \end{gathered}[/tex]Therefore, the answer are:
Radius = 1.59 in
Diameter = 3.18 in
Area = 7.94 in²
Use the remainder theorem to find P(-2) for P(x) = x³ + 3x² +9,Specifically, give the quotient and the remainder for the associated division and the value of P(-2).QuotientRemainder =P(-2)=
Answers
Answer:
Quotient:
[tex]x^2+x-2[/tex]Remainder:
[tex]13[/tex]P(-2):
[tex]13[/tex]Step-by-step explanation:
Remember that the remainder theorem states that the remainder when a polynomial p(x) is divided by (x - a) is p(a).
To calculate the quotient, we'll do the synthetic division as following:
Step one:
Write down the first coefficient without changes
Step two:
Multiply the entry in the left part of the table by the last entry in the result row (under the horizontal line).
Add the obtained result to the next coefficient of the dividend, and write down the sum.
Step 3:
Multiply the entry in the left part of the table by the last entry in the result row (under the horizontal line).
Add the obtained result to the next coefficient of the dividend, and write down the sum.
Step 4:
Multiply the entry in the left part of the table by the last entry in the result row (under the horizontal line).
Add the obtained result to the next coefficient of the dividend, and write down the sum.
Now, we will have completed the division and have obtained the following resulting coefficients:
[tex]1,1,-2,13[/tex]Thus, we can conlcude that the quotient is:
[tex]x^2+x-2[/tex]And the remainder is 13, which is indeed P(-2)
Find the missing rational expression.382x + 6(x-3)(x + 1)X-332x + 6(x-3)(x + 1)(Simplify your answer.)X-3
Answers
Convert do you need to the specified equivalent unit round your answer to the nearest 1 decimal place, if necessary
Answers
Answer:
There are 59251.5 decigrams in 209 ounces.
Step-by-step explanation:
We'll solve this using the rule of three.
We know that there are 28.35 grams in an ounce. This way,
This way,
[tex]\begin{gathered} x=\frac{209\times28.35}{1} \\ \\ \Rightarrow x=5925.15 \end{gathered}[/tex]And since we know there are 10 decigrams in a gram, we'll have that:
This way,
[tex]\begin{gathered} y=\frac{5925.15\times10}{1} \\ \\ \Rightarrow y=59251.5 \end{gathered}[/tex]This way, we can conclude that there are 59251.5 decigrams in 209 ounces.
Ariana is going to invest $62,000 and leave it in an account for 20 years. Assuming
the interest is compounded continuously, what interest rate, to the nearest tenth of a
percent, would be required in order for Ariana to end up with $233,000?
Answers
The rate of interest that Ariana should get in order to end up with a final amount of $233,000 is 0.07%.
What is compound interest and how is it calculated?
The interest that is calculated using both the principal and the interest that has accrued during the previous period is called compound interest. It differs from simple interest in that the principal is not taken into account when determining the interest for the subsequent period with simple interest.
Mathematically, A = P (1 + (R/f))ⁿ ;
where A = amount that the depositor will receive
P = initial amount that the depositor has invested
R = rate of interest offered to the depositor
f = frequency of compounding offered per year
n = number of years.
Given, Amount that Ariana wants to end up receiving = A = $233,00
Principal amount that Ariana can invest = P = $62,000
Frequency of compounding offered per year = f = 1
Number of years = 20
Let the rate of interest offered to the depositor be = R
Following the formula established in the literature, we have:
233000 = 62000(1 + R)²⁰ ⇒ 3.76 = (1 + R)²⁰ ⇒ 1.07 = 1 + R ⇒ R = 0.07%
Thus, the rate of interest that Ariana should get in order to end up with a final amount of $233,000 is 0.07%.
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f(x)A6X-868Which of the given functions could this graph represent?OA. f(t) = (x - 1)(x - 2)(x + 1)(x + 2)O B. f(x) = x(x - 1)(1 + 1)Oc. /(x) = x(x - 1)(x - 2)(x + 1)(x + 2)OD. (r) = x(x - 1)(x - 2)
Answers
The Solution:
Given the graph below:
We are required to determine the function that best describes the above graph.
Step1:
Identify the roots of the function from the given graph.
[tex]\begin{gathered} x=-2 \\ x=-1 \\ x=1 \\ x=2 \end{gathered}[/tex]This means that:
[tex]\begin{gathered} x+2=0 \\ x+1=0 \\ x-1=0 \\ x-2=0 \end{gathered}[/tex]So, the required function becomes:
[tex]f(x)=(x-1)(x-2)(x+1)(x+2)[/tex]Therefore, the correct answer is [option A]
ur answer as a polynomial in standard form.=f(x) = 5x + 1g(x) = x2 – 3x + 12=Find: (fog)(x)
Answers
(fog)(x) = 5x² - 15x + 61
Explanation:The given functions are:
f(x) = 5x + 1
g(x) = x² - 3x + 12
(fog)(x) = f(g(x))
This means that we are substituting g(x) into f(x)
(fog)(x) = 5(x² - 3x + 12) + 1
(fog)(x) = 5x² - 15x + 60 + 1
This can be further simplified as:
(fog)(x) = 5x² - 15x + 61
Subtract. Write fractions in simplest form. 12/7 - (-2/9) =
Answers
You have to subtract the fractions:
[tex]\frac{12}{7}-(-\frac{2}{9})[/tex]You have to subtract a negative number, as you can see in the expression, both negatives values are together. This situation is called a "double negative" when you subtract a negative value, both minus signs cancel each other and turn into a plus sign:
[tex]\frac{12}{7}+\frac{2}{9}[/tex]Now to add both fractions you have to find a common denominator for both of them. The fractions have denominators 7 and 9, the least common dneominator between these two numbers is the product of their multiplication:
7*9=63
Using this value you have to convert both fractions so that they have the same denominator 63,
For the first fraction 12/7 multiply both values by 9:
[tex]\frac{12\cdot9}{7\cdot9}=\frac{108}{63}[/tex]For the second fraction 2/9 multiply both values by 7:
[tex]\frac{2\cdot7}{9\cdot7}=\frac{14}{63}[/tex]Now you can add both fractions:
[tex]\frac{108}{63}+\frac{14}{63}=\frac{108+14}{63}=\frac{122}{63}[/tex]