What are the values of x and y? *
Pls help!

The key features of the function are Base = 0.72, Rate = decrement and it decays

Given that

y = 3000 * (0.72)ˣ

The given equation is in the form of exponential decay:

Base: The base of the exponential function is the constant term that is being raised to a power. In this case, the base is 0.72.

Rate of change: The rate of change is the factor by which the function is being multiplied or divided as the input variable increases.

Since the base is less than 1, the function is decreasing as x increases. The rate of decrease is given by the base, which is 0.72.

Growth or decay: As the base is less than 1, the function is decreasing, which means it is a decay function.

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In the given triangle, the value of x = 5.

What is a triangle's definition?

A triangle is a geometrical shape that is defined as a polygon with three sides and three angles. It is a closed figure with three line segments as its sides, and these sides intersect at three points, which are called vertices. When we add all the angles of a triangle then the result will always be 180°.

Now,

As we know the property of a triangle that

sum of all angles of triangle=180°

given angles are (9x-1)°, 74° and 62°

then,

        9x-1+74+62=180°

9x+135=180

9x=45

x=5

Hence,

           the value of x is 5.

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Answer:

The shape of each cut surface is a rectangle. The dimensions of the first cut surface are 8 inches by 10 inches, and the dimensions of the second cut surface are 10 inches by 20 inches.

The area of the first cut surface is 8 inches x 10 inches = 80 square inches. The area of the second cut surface is 10 inches x 20 inches = 200 square inches.

To find the total area Jenny needs to paint, we need to add the area of the first cut surface to the area of the second cut surface.

Total area = Area of first cut surface + Area of second cut surface

Total area = 80 square inches + 200 square inches

Total area = 280 square inches

Therefore, Jenny needs to paint a total area of 280 square inches.

To find the two consecutive odd integers, let's set up an equation using the given information. Let x be the smaller odd integer, then the next consecutive odd integer is x+2.

The problem states that the product of these two integers is 77 more than twice the larger integer. In equation form, this can be written as:

x * (x + 2) = 2(x + 2) + 77

Now, let's solve for x:

x * (x + 2) = 2x + 4 + 77
x^2 + 2x = 2x + 81
x^2 = 81

To find the value of x, take the square root of both sides:

√(x^2) = √81
x = 9

So, the smaller odd integer is 9. The next consecutive odd integer is 9 + 2 = 11.

Therefore, the two consecutive odd integers are 9 and 11.

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The two consecutive odd integers are 9 and 11.

To find the two consecutive odd integers whose product is 77 more than twice the larger, we can set up the following equation:
x * (x + 2) = 2(x + 2) + 77
Here, x represents the first odd integer, and x + 2 represents the second consecutive odd integer. Now, let's solve the equation step by step:
1. Expand the equation: x^2 + 2x = 2x + 4 + 77
2. Simplify the equation: x^2 + 2x = 2x + 81
3. Subtract 2x from both sides: x^2 = 81
4. Take the square root of both sides: x = ±9
Since we're looking for positive integers, x = 9. Therefore, the two consecutive odd integers are 9 and 11.

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Around 0.13% or 0.0013 of children find relief for less than four hours.

The percentage of children who experience relief for less than four hours if the relief time follows a lognormal distribution is determined as follows:

Step 1: Define the parameters of the problem. Assume that relief times are normally distributed with a mean of μ = 5.5 hours and a standard deviation of σ = 0.5 hours. We want to find the percentage of children who experience relief for less than four hours.

Step 2: Convert the normal distribution to the standard normal distribution using the formula: z = (x - μ) / σwhere x is the relief time in hours.

Step 3: Find the z-score corresponding to the value of x = 4:z = (4 - 5.5) / 0.5 = -3

Step 4: Use a standard normal distribution table to find the percentage of the area under the curve to the left of z = -3. This is equivalent to the percentage of children who experience relief for less than four hours.

Using the standard normal distribution table or calculator, we get that the percentage of children who experience relief for less than four hours is approximately 0.13% or 0.0013.


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The LCD of 2/5, 1/2, and 3/4 is equal to 20.

In Mathematics, LCD is an abbreviation for least common denominator or lowest common denominator and it can be defined as the smallest number that can act as a common denominator for a given set of fractions.

Next, we would determine the factors of the denominators for the given fraction 5, 2, and 4 as follows;

5 = 5 × 1

2 = 2 × 1

4 = 2 × 2 × 1

Therefore, the least common denominator (LCD) would be calculated as follows:

Least common denominator (LCD) = 5 × 2 × 2 × 1

Least common denominator (LCD) = 20.

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Hence, the population proportion's 95% confidence interval is (0.210, 0.290), rounded to the thousandths place.

A mathematical concept known as proportionality describes the relationship between two quantities that have different sizes but keep the same ratio or proportion. In other words, to preserve the same ratio, if one item changes, the other quantity must also change in proportion. For instance, if an automobile's speed and distance are proportionate, doubling the distance it travels will cause the car to go twice as quickly while retaining the same speed-to-distance ratio. Equations or ratios in mathematics are frequently used to express proportionality.

given

We can use the following formula to determine the lower and upper bounds of the 95% confidence interval for the population proportion:

Lower limit: sqrt((p * q) / n) * p - z

Upper limit: sqrt((p * q) / n) = p + z

With q = 1 - p, z is the z-score corresponding to the level of confidence, and p is the sample proportion.

Here, p = 130/520 = 0.25, q = 1 - p = 0.75, n = 520, and the z-score is 1.96 at a 95% confidence level (from the standard normal distribution).

Lower limit: 0.210 (0.25" * 0.75") - 1.96 * sqrt(0.25" * 0.75")

The maximum is equal to 0.25 + 1.96 * sqrt((0.25 * 0.75) / 520) = 0.290.

Hence, the population proportion's 95% confidence interval is (0.210, 0.290), rounded to the thousandths place.

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The company's total income, expenditure and profit is given respectively as follows:

a.) £180

b.) £146

C.) £34

To calculate the profit of the company the formula such as given below is used.

Profit = total income - total expenditure

The total income = 25+20+35+100 = £180

The total expenditure = 110+20+6+10 = £146

Profit = 180-146 = £34

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Answer:

c

Step-by-step explanation:

fv(40,20) ≈ (f(40.1,20) - f(40,20))/0.1 , ft(40,20) ≈ (f(40,20.05) - f(40,20))/0.05 are the required functional estimations of a given representations.

However, we can estimate the partial derivatives with respect to x (fv) and y (ft) at the point (40,20) using the definition of partial derivatives:

fv = ∂f/∂x ≈ (f(40+h,20) - f(40,20))/h

where h is a small increment in the x direction. Similarly,

ft = ∂f/∂y ≈ (f(40,20+k) - f(40,20))/k

where k is a small increment in the y direction.

To estimate fv(40,20) and ft(40,20), we need to choose small values of h and k and evaluate the function at the corresponding points. Let's say h = 0.1 and k = 0.05:

fv(40,20) ≈ (f(40.1,20) - f(40,20))/0.1

ft(40,20) ≈ (f(40,20.05) - f(40,20))/0.05

We can then use these estimates to approximate the value of f(40.1,20.05) using the first-order Taylor approximation:

f(40.1,20.05) ≈ f(40,20) + fv(40,20)0.1 + ft(40,20)0.05

Note that this is an approximation and may not be very accurate if the function is highly nonlinear or has discontinuities. However, it can give us a rough idea of the value of f(40,20) and how it changes with small variations in x and y.

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If the objective function coefficient for variable 1 decreases by 20, the solution will shift in the direction of the decrease in the objective function coefficient. It means that the optimal solution that was obtained previously will no longer remain optimal, and the new optimal solution will be found with the new objective function coefficient.

In linear programming, the objective function determines the maximum or minimum value that can be attained in the solution, subject to the constraints. The constraints in the problem can be either equalities or inequalities, which limit the range of values that the decision variables can take on.

The change in the objective function coefficient will change the direction of the optimal solution, and it may affect the feasibility of the solution. It means that some constraints may no longer be satisfied, or some variables may become infeasible.

In such cases, it will be necessary to revise the constraints or the variables to ensure the feasibility of the solution.

The solution can also be affected if the constraints of the problem change. The new constraints may limit the range of values that the variables can take on, or they may add new variables to the problem. These changes can affect the feasibility of the solution, and it may require the problem to be solved again to obtain the new optimal solution.


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Answer:  ^4√11^5 = 11^(5/4)

Step-by-step explanation: When we apply a radical, we are asking what number, when raised to a certain power, gives us the number under the radical. For example, ^4√16 is asking what number, when raised to the fourth power, gives us 16. The answer is 2, since 2^4 = 16.

So, ^4√11^5 is asking what number, when raised to the fourth power, gives us 11^5. We can simplify this expression using the exponent laws:

^4√11^5 = (11^5)^(1/4) = 11^(5/4)

Therefore, the simplified expression for ^4√11^5 is 11^(5/4). This expression does not have any radicals, making it easier to work with and manipulate.

Hope this helps, and have a great day!

Answer:

4m^2+15-5m

Step-by-step explanation:

Remove parentheses.

4m^2-5-5m+20

Collect like terms.

4m^2+(-5+20)-5m

Simplify

4m^2+15-5m

Answer:

Area: 81*pi

Circumference: 18*pi

Step-by-step explanation:

Area: 9^2= 81

So it would be 81*pi

Circumference: 9*2= 18

So it would be 18*pi

If you want the full area then it's 81*pi= 254.34

If you want the full circumference it's 18*pi= 56.55

Men will have completed oil changes in hours Therefore, Will and Gabriel will each have done 12 oil changes after 4 hours.

Hours is a unit of time measurement. It is used to measure a specific amount of time and is usually denoted by the symbol “h”. There are 24 hours in a day, 60 minutes in an hour and 60 seconds in a minute. Hours are used to measure both short and long periods of time. Commonly, hours are used to measure the length of a workday, the length of a school day, or the length of a movie. Hours are also used to measure how long a person has been alive, how long an event has been going on, or how long an item has been in use.

Let W be the total number of oil changes Will has completed, and G be the total number of oil changes Gabriel has completed.

System of equations:

W = 8 + 2t

G = 3t

Since they will be tied at some point during the day, W = G.

Substituting W into G's equation:

8 + 2t = 3t

Solving for t:

2t = 8

t = 4

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Answer:

Step-by-step explanation:

A reflection across the line y = x will not carry the square onto itself, since the vertex (0, 2) would be reflected to (2, 0) which is not a vertex of the original square.

A reflection across the line y = -x would also not carry the square onto itself, since the vertex (0, 2) would be reflected to (−2, 0) which is not a vertex of the original square.

However, a reflection across the x-axis would carry the square onto itself since all of the vertices lie in the same quadrant, and reflecting across the x-axis does not change their signs.

A 45° or 90° rotation about the origin would also carry the square onto itself since the square has rotational symmetry of order 4.

Therefore, the correct answers are C, D, and E.

The height of the image after being scaled down by 80% three times is 76.8mm, which is not within the required range for a U.S. passport photo.

Scaling is the process of increasing or decreasing the size of a picture by dividing or multiplying its dimensions. An picture is expanded when it is scaled up, and its size is decreased when it is scaled down. An picture is affected by scaling when its size and, consequently, appearance, are altered. An picture may become pixelated or fuzzy if it is scaled up or down excessively, and information may be lost if it is scaled down too much. The aspect ratio of an image—the proportion of its width to its height—can also be impacted by scaling. The picture could look stretched or squished if the aspect ratio is modified.

Given that the image is 150 mm in height.

Thus, 80% of the image is:

150mm x 0.8 = 120mm

The scaling is performed 3 times, thus:

120mm x 0.8 = 96mm

96mm x 0.8 = 76.8mm

Hence, the height of the image after being scaled down by 80% three times is 76.8mm, which is within the required range for a U.S. passport photo.

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The complete question is:

The best interpretation of the interval is: We are 95% confident that the mean time for response is between 2.8 minutes and 12.3 minutes. Option D is correct

A confidence interval is a measure of how accurately an estimate (such as the sample average) corresponds to the actual population parameter. It is a range of values that the researcher believes is very likely to include the actual value of the population parameter.

Here, a 95 percent confidence interval for the mean time, in minutes, for a volunteer fire company to respond to emergency incidents is determined to be (2.8. 12.3). Thus, we can say that we are 95% confident that the mean time for response is between 2.8 minutes and 12.3 minutes. Therefore, option D is correct.

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The sum of the matrices A and C from the list of options is the matrix B

Given the following matrices

Matrix A

| 0  6  2 |

| 1  5  -2 |

Matrix C

| -2  5  3 |

| -1  -7  3|

To find the sum of matrices A and C, we add the corresponding elements in each matrix:

So, we have: A + C

| 0 - 2  6 + 5  2 + 3 |

| 1 - 1    5 - 7  -2 + 3|

Evaluate the sum

| -2  11  5 |

| 0   -2  1 |

This represents option B

Therefore, the sum of matrices A and C is (B)

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Complete question

What is the sum of A+C?

Matrix A

| 0  6  2 |

| 1  5  -2 |

Matrix C

| -2  5  3 |

| -1  -7  3|

The volume of the snowball is decreasing at a rate of approximately 108π cubic centimeters per minute when the radius is 9 cm.

The volume V of a sphere with radius r is given by the formula V = (4/3)πr^3. To find the rate at which the volume is changing with respect to time, we need to take the derivative of V with respect to time t. Using the chain rule, we get:

dV/dt = (dV/dr) * (dr/dt)

Since the radius is changing at a constant rate, we can calculate dr/dt by dividing the change in radius by the time interval:

dr/dt = (10 cm - 20 cm) / (30 minutes) = -1/3 cm/min

To find dV/dr, we can take the derivative of the volume formula with respect to r:

dV/dr = 4πr^2

Substituting the given radius of 9 cm, we get:

dV/dr = 4π(9)^2 = 324π cm^2

Finally, we can substitute these values into the formula for dV/dt:

dV/dt = (dV/dr) * (dr/dt) = 324π cm^2 * (-1/3 cm/min) = -108π cm^3/min

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The solution of the given problem of equation comes out to be the quadratic function's expression is  [tex]y = -2x² + 8x + 3[/tex]

Variable words are commonly used in complex algorithms to show uniformity between two incompatible claims.

Academic expressions called equations are used to show the equality of various academic numbers. Instead of a unique formula that splits 12 into two parts and can be used to analyse data received from [tex]y + 7[/tex]  , normalization in this case yields b + 7.

Here,

A quadratic function's curve is shown in the provided illustration. The quadratic function's expression is

=> [tex]y = -2x² + 8x + 3[/tex]

We can use the knowledge that a quadratic function's standard form is

=>  [tex]y = ax² + bx + c[/tex]  , where a, b, and c are constants, to see this.

When y =  [tex]-2x² + 8x + 3[/tex] is provided,

we can see that a = -2, b = 8, and c = 3 by comparing it to the standard form.

Therefore, the quadratic function's expression is [tex]y = -2x² + 8x + 3[/tex]

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Hence, the value of  variable in the given expression x is 8

An angle is formed when two straight lines  meet at a common endpoint.

∠1 = 7x - 4

∠2 = 3x + 28

A secant line that crosses two parallel lines produces these angles. After that, these angles were congruent, which means that their measures are equal.

Then, equaling  both given expressions and solving for x,  we get:

Step1: subtract 3x both sides

7x - 4 = 3x + 28

Step2: add 4 both sides

7x - 3x - 4 = 28

Step2: simplify like terms

7x - 3x = 28 + 4  

Step3: divide by 4 both sides

4x = 32  

x = 32/4

x = 8

Hence, the value of x is 8.

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The linear measure of arc KML on OO is approximately 3.33 units, rounded to two decimal places.

Since KM is a diameter, angle KOM is a right angle. Therefore, angle KOL is a straight angle, which means that angle MOL is 180 - 145 = 35 degrees.

Now, we can use the fact that the measure of an arc is proportional to the measure of the angle it subtends. In particular, if the measure of an angle in degrees is θ and the radius of the circle is r, then the length of the arc it subtends is given by:

length of arc = (θ/360) * 2πr

In this case, the radius of the circle is half of the diameter KM, which is 36/2 = 18. So we have:

length of arc KML = (35/360) * 2 * 3.14 * 18

≈ 3.33

Therefore, the linear measure of arc KML on OO is approximately 3.33 units, rounded to two decimal places.

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The probability that when he enters the restaurant today it will be at least 5 minutes until he is served is  0.2676 and probability that average time until he is served in eight randomly selected visits is 0.0409.

The square root of the variance is used to calculate the standard deviation, a statistic that expresses how widely distributed a dataset is in relation to its mean. By calculating the deviation of each data point from the mean, the standard deviation can be calculated as the square root of variance.

Given that mean μ = 4.2 , standard deviation σ = 1.3

1. P(X >= 5) = P((X - μ)/σ >

                    = (5 - 4.2) /1.3

                    = P(Z ≥ 0.6154)

                    = 1 - P(Z < 0.6154)

                    = 1 - 0.7324

                    = 0.2676

The required probability is 0.2676.

2.Given that n = 8 then  [tex]\bar x[/tex] = σ/[tex]\sqrt{(n)[/tex]  = 1.3/√(8) = 0.4596

P(x-bar ≥ 5) = P(([tex]\bar x[/tex] - μ)/σx-bar ≥ (5 - 4.2)/0.4596)

                        = P(Z ≥ 1.7406)

                        = 1 - P(Z < 1.7406)

                        = 1 - 0.9591

                        = 0.0409

The required probability is 0.0409.

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Answer:

  13/32

Step-by-step explanation:

You want the area of the shaded portion of the unit square shown.

Points B, C, E are shown as equidistant from point F, so will lie on a circle centered at F. The center of that circle is at the point of coincidence of the perpendicular bisectors of BE, BC, and CE.

Without loss of generality, we can let line EF lie on the x-axis such that E is at the origin. Chord EB of the circle has a rise of 1/2 for a run of 1, so a slope of 1/2. Its midpoint is (1, 1/2)/2 = (1/2, 1/4). The perpendicular line through this point will have slope -2, so its equation can be written ...

  y -1/4 = -2(x -1/2)

  y = -2x +5/4

Then the x-intercept (point F) will have coordinates (0, 5/8):

  0 = -2x +5/4 . . . . . y=0 on the x-axis

  2x = 5/4

  x = 5/8

Trapezoid EFCD will have upper base 5/8, lower base 1, and height 1/2. Its area is ...

  A = 1/2(b1 +b2)h

  A = (1/2)(5/8 +1)(1/2) = (1/4)(13/8) = 13/32

The shaded area is 13/32.

__

Additional comment

The point-slope equation of a line through (h, k) with slope m is ...

  y -k = m(x -h)

The value of [tex]e^{In 5}[/tex] is equal to 5 which of option B. According to the property of logs and logarithm rules the given equation is done.

The natural log, or log to the base e, is denoted by ln. ln can also be written as [tex]log_{e}[/tex].

So, we can write the given expression as:

[tex]e^{log_{e}^(5) }[/tex]

The property of logs is:

[tex]a^{log_{a}^(x) } = x[/tex]

This means that if the number an is raised to a log whose base is the same as the number a, the answer will be equal to the log's argument, which is x.

The number e and the base of log are the same in the given case. As a result, the answer to the expression will be the log argument, which is 5.

Therefore, the value of [tex]e^{log_{e}^(5) }[/tex] = [tex]e^{In 5}[/tex] = 5. Correct option is option B.

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To calculate the monthly periodic interest rate from an annual percentage rate (APR), we need to divide the APR by 12 (the number of months in a year). We can use the following formula:

Monthly periodic interest rate = APR / 12

In this case, the APR is 16.75%, so we can plug it into the formula and simplify:

Monthly periodic interest rate = 16.75% / 12

Monthly periodic interest rate = 1.395833...%

Rounding to the nearest hundredth of a percent, we get:

Monthly periodic interest rate = 1.40%

Therefore, the monthly periodic interest rate for the primary credit card holder is 1.40%.