Answer:
Heat can travel from one place to another in three ways: Conduction, Convection and Radiation. Both conduction and convection require matter to transfer heat. Conduction is the transfer of heat between substances that are in direct contact with each other. Thermal energy is transferred from hot places to cold places by convection. Radiation is a method of heat transfer that does not rely upon any contact between the heat source and the heated object as is the case with conduction and convection. Heat can be transmitted through empty space by thermal radiation often called infrared radiation.
The thermal energy transfer may take place within the iguana’s enclosure through Conduction, Convection, and Radiation.
What are Conduction, Convection, and Radiation?In conduction, heat transfer happens between objects by direct contact. If the heat transfer takes within the fluid then it is In convection. In radiation, heat transfers without involving particles through electromagnetic waves.
In conduction, Heat transfer occurs because of the difference in temperature. In convection, heat transfer occurs due to the difference in density. In radiation, heat transfer occurs with a temperature greater than 0 K in all objects.
In convection, heat transfer in conduction is slow while in convection, heat transfer, in convection is faster and in radiation, the heat transfer in radiation is the fastest.
Conduction and convection heat transfer does not follow the law of refraction and reflection. Radiation heat transfer follows the law of refraction and reflection.
Learn more about Conduction, Convection, and Radiation, here:
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The reaction, C2H6) (l) + 3)2 (g) produces 2CO2 (g) + 3H2) (g), is the combustion of ethanol. What occurs as the reaction proceeds.
Answer:
So as the reaction proceeds we lose energy as the reaction is exothermic due to the delta H being negative, this shows that heat flows from the system to its surroundings.
Explanation:
2H6O (l) + 3O2 (g) = 2CO2 (g) + 3H2O (g)
2CH3CH2OH(l) + 3O2(g) = 2CO2(g) + 3H2O(g) ΔH = -1234.8kJ/mol
I'm pretty sure this is what your equation is supposed to be, seems to be an error where you've pasted it and it's replaced the O's with )
So as the reaction proceeds we lose energy as the reaction is exothermic due to the delta H being negative, this shows that heat flows from the system to its surroundings.
1.46 g H2 is allowed to react with 10.5 g N2, producing 2.72 g NH3. What is the theoretical yield in grams for this reaction under the given conditions?
Express your answer to three significant figures and include the appropriate units.
Answer : The theoretical yield in grams for this reaction under the given conditions is, 8.28 grams.
Explanation : Given,
Mass of [tex]H_2[/tex] = 1.46 g
Mass of [tex]N_2[/tex] = 10.5 g
Molar mass of [tex]H_2[/tex] = 2 g/mol
Molar mass of [tex]N_2[/tex] = 28 g/mol
First we have to calculate the moles of [tex]H_2[/tex] and [tex]N_2[/tex].
[tex]\text{Moles of }H_2=\frac{\text{Given mass }H_2}{\text{Molar mass }H_2}[/tex]
[tex]\text{Moles of }H_2=\frac{1.46g}{2g/mol}=0.73mol[/tex]
and,
[tex]\text{Moles of }N_2=\frac{\text{Given mass }N_2}{\text{Molar mass }N_2}[/tex]
[tex]\text{Moles of }N_2=\frac{10.5g}{28g/mol}=0.375mol[/tex]
Now we have to calculate the limiting and excess reagent.
The balanced chemical equation is:
[tex]3H_2+N_2\rightarrow 2NH_3[/tex]
From the balanced reaction we conclude that
As, 3 mole of [tex]H_2[/tex] react with 1 mole of [tex]N_2[/tex]
So, 0.73 moles of [tex]H_2[/tex] react with [tex]\frac{0.73}{3}=0.243[/tex] moles of [tex]N_2[/tex]
From this we conclude that, [tex]N_2[/tex] is an excess reagent because the given moles are greater than the required moles and [tex]H_2[/tex] is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of [tex]NH_3[/tex]
From the reaction, we conclude that
As, 3 mole of [tex]H_2[/tex] react to give 2 mole of [tex]NH_3[/tex]
So, 0.73 mole of [tex]H_2[/tex] react to give [tex]\frac{2}{3}\times 0.73=0.487[/tex] mole of [tex]NH_3[/tex]
Now we have to calculate the mass of [tex]NH_3[/tex]
[tex]\text{ Mass of }NH_3=\text{ Moles of }NH_3\times \text{ Molar mass of }NH_3[/tex]
Molar mass of [tex]NH_3[/tex] = 17 g/mole
[tex]\text{ Mass of }NH_3=(0.487moles)\times (17g/mole)=8.28g[/tex]
Therefore, the theoretical yield in grams for this reaction under the given conditions is, 8.28 grams.
all but one is a method of passve transport in cells
osmosis
sodium/potassium pump
facilitated transport
Answer:
The answer is Osmosis........
Answer:
osmosis
Explanation:
osmosis is a method of passive transport in cells. osmosis in passive transport cells is of water
How does water's dissolving power support life on Earth?